Electronic Journal of Differential Equations, Vol. 2008(2008), No. 64, pp. 1–15. ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu (login: ftp) MATRIX ELEMENTS FOR SUM OF POWER-LAW POTENTIALS IN QUANTUM MECHANIC USING GENERALIZED HYPERGEOMETRIC FUNCTIONS QUTAIBEH D. KATATBEH, MA’ZOOZEH E. ABU-AMRA Abstract. In this paper we derive close form for the matrix elements for Ĥ = −∆ + V , where V is a pure power-law potential. We use trial functions of the form s √ p q 2β γ/2 (γ)n γ−1/2 − β rq ψn (r) = r e 2 βr ), p F1 (−n, a2 , . . . , ap ; γ; n!Γ(γ) for β, q, γ > 0 to obtain the matrix elements for Ĥ. These formulas are then optimized with respect to variational parameters β, q and γ to obtain accurate upper bounds for the given nonsolvable eigenvalue problem in quantum mechanics. Moreover, we write the matrix elements in terms of the generalized hypergeomtric functions. These results are generalization of those found earlier in [2], [8]–[16] for power-law potentials. Applications and comparisons with earlier work are presented. 1. Introduction In 1998 Hall et al [15] found a closed form expressions for the singular-potential integrals hm | r−α | ni that obtained with respect to the Gol’dman and Krivchenkov eigenfunctions for the singular Hamiltonian with ~2 = 2m = 1, d2 A + βr2 + 2 , (β > 0, A ≥ 0). (1.1) dr2 r We present a variational analysis of the generalized spiked harmonic oscillator Hamiltonian [2, 3, 4], [7]–[19] of the form Ĥ = − d2 A λ + βr2 + 2 + α , 0 ≤ r < ∞, (1.2) dr2 r r where α and λ are positive real numbers. By writing Ĥ = H (0) + λV with H (0) standing for the generalized spiked harmonic-oscillator Hamiltonian, and V (r) = r−α , Hall et al [8]–[16] used the basis set s γ √ p − β 2 2β 2 (γ)n ψn (r) = Tn rγ−1/2 e 2 r 1 F1 (−n; γ; βr2 ), Tn = , n!Γ(γ) Ĥ = − 2000 Mathematics Subject Classification. 34L15, 34L16, 81Q10, 35P15. Key words and phrases. Schrödinger equation; variational technique; eigenvalues; upper bounds; analytical computations. c 2008 Texas State University - San Marcos. Submitted February 19, 2008 Published April 28, 2008. 1 2 Q. D. KATATBEH, M. E. ABU-AMRA, EJDE-2008/64 n = 0, 1, 2, 3, . . ., constructed from the normalized solutions of H (0) ψn = En ψn to evaluate the matrix elements of Ĥ. They found that p Hmn = hm | Ĥ | ni = 2 β(2n + γ)δmn + λhm | r−α | ni m, n = 0, 1, 2, . . . , N − 1 where r (γ)n (γ)m Γ(γ − α2 )( α2 )n n!m! (γ)n Γ(γ) α α α ×3 F2 (−m, γ − , 1 − ; γ, 1 − − n; 1). 2 2 2 Now, by considering the problem in a finite dimensional subspace and choosing a suitable trial functions as a linear combination of the form s γ √ p − β q 2β 2 (γ)n γ−1/2 r q 2 βr ), Tn = ψn (r) = Tn r e (1.3) p F1 (−n, a2 , . . . , ap ; γ; n!Γ(γ) hm | r −α m+n | ni = (−1) β α 4 This basis is more general than the basis used in [2] and [14], because the number of variational parameters for the exponential function and the generalized hypergeometric function play an important rule for improving the numerical results for our eigenvalue problem. Herein, p F1 stands for the hypergeometric function defined by p Fq (α1 , α2 , . . . , αp ; β1 , β2 , . . . , βq ; x) = ∞ X Πpi=1 (αi )k xk ; Πqj=1 (βj )k k! (1.4) k=0 where p and q are non-negative integers and βj (j = 1, 2, . . . , q) cannot be a nonpositive integer [1]. The expression (a)n is the Pochhammer symbol defined by the relations Γ(a + n) (a)n = a(a + 1) . . . (a + n − 1) = Γ(a) (a)0 = 1 (a)−n = (−1)n , (1 − a)n where n is an integer (positive, negative or zero). 2. Variational Technique In this section we review the well known variational technique for eigenvalue problem in quantum mechanics [5]. We consider a non solvable eigenvalue problem of the form Ĥ = −4 + V (r) in N -dimensional space over a finite subspace in the domain of its angular momentum subspace. Our variational technique is based on forming trial wave function from a linear combination of some of orthonormal basis function ψn (r), n = 1, 2, . . . , D such that, Ψ(r) = D X cn ψn (r) (2.1) n=1 where the cn are variational parameters. The variational energy EΨ we obtain with this trial function is given by, R R ∗ PD PD c∗n cm ψn∗ Ĥψm dτ Ψ ĤΨdτ n=1 m=1 = PD PD (2.2) EΨ = R ∗ R ∗ ∗ Ψ Ψdτ n=1 m=1 cn cm ψn ψm dτ EJDE-2008/64 MATRIX ELEMENTS Now, defining the matrix element of Ĥ as Z Hnm = ψn∗ Ĥψm dτ and using the orthonormal property of the ψ functions, we obtain that PD PD c∗ cm Hnm EΨ = n=1PDm=1 n 2 n=1 | cn | or D D X D X X EΨ | cn |2 = c∗n cm Hnm n=1 3 (2.3) (2.4) n=1 m=1 We seek the minimum value of EΨ as a function of all the cn . By differentiating with respect to ci , we obtain D D X ∂E X 2 ∗ c∗n Hni | cn | + Eci = ∂ci n=1 n=1 and setting ∂E ∂ci = 0, we have D X c∗n Hni − Ec∗i = 0. (2.5) n=1 We can derive one equation similar to (2.5) for each possible value of i, i = 1, . . . , D, and we may take (2.5) to represent a set of linear equations with each equation characterized by a different value of i. According to the theory of linear algebraic equations, there is a nontrivial solution, if and only if the determinant of the coefficients vanishes or if and only if H11 − E H12 H13 · · · H1D H21 H22 − E H23 · · · H2D =0 .. .. .. .. . . . . HD1 HD2 HD3 · · · HDD − E This determinant is called a secular determinant. If we use a basis set that is not orthonormal, we define the matrix element Snm by Z Snm = ψn ψm dτ , in this case the equation corresponding to (2.5) and the secular determinant are D X cn Hin − ESin cn = 0 n=1 and the secular determinant H11 − ES11 H21 − ES21 .. . HD1 − ESD1 can be written as H12 − ES12 H22 − ES22 .. . ··· ··· HD2 − ESD2 ··· = 0. HDD − ESDD H1D − ES1D H2D − ES2D .. . (2.6) 4 Q. D. KATATBEH, M. E. ABU-AMRA, EJDE-2008/64 3. Derivation of the Matrix Elements We divide the problem of computing the matrix elements for Schrödinger equation into simple parts. In the first lemma we compute the matrix elements for singular potential in three-spatial dimensions, it will be used to compute the matrix elements for the kinetic energy. Lemma 3.1. For the generalized spiked harmonic oscillator Hamiltonian (1.2), the expectation values of the operator V (x) = r−α with respect to a trial basis (1.3) are given by m hψm | r−α | ψn i = α−2γ 1 2γ − α X (−m)k (a2 )k · · · (ap )k ( Tm Tn β 2q Γ( ) q q (γ)k k! 2γ−α q )k k=0 2γ − α ×p+1 F1 (−n, a2 , . . . , ap , + k; γ; 1) q (3.1) Proof. Using (1.3), it follows that hψm | r−α | ψn i = Z ∞ √ r2γ−α−1 e− βr q p F1 (−m, a2 , . . . , ap ; γ; p q βr ) 0 ×p F1 (−n, a2 , . . . , ap ; γ; (3.2) p q βr )dr Using the series representation (1.4) of the hypergeometric function p F1 , yields −α rmn = Tm Tn ×β n m X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l (γ)k (γ)l k!l! k=0 l=0 Z ∞ √ l+k 2γ−α+qk+ql−1 − βr q 2 r e (3.3) dr 0 By restoring to the integral representation of gamma function, we obtain under the condition 2γ−α q + k + l > 0, that −α rmn m = n l+k X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l β 2 1 2γ − α Tm Tn Γ( + k + l) q (γ)k (γ)l k!l! q k=0 l=0 = m hX n i α−2γ X 1 (−n)l (a2 )l · · · (ap )l 2γ − α Tm Tn β 2q Γ( + k + l) q (γ)l l! q k=0 l=0 (−m)k (a2 )k · · · (ap )k × (γ)k k! (3.4) On the other hand, using the definition of the Pochhammer symbols and the series representation of the hypergeometric functions (1.4), the finite sum inside the EJDE-2008/64 MATRIX ELEMENTS 5 bracket collapses to n X (−n)l (a2 )l · · · (ap )l (γ)l l! l=0 = Γ( 2γ − α + k + l) q n X + k)l (−n)l (a2 )l · · · (ap )l ( 2γ−α q (γ)l l! l=0 =p+1 F1 (−n, a2 , . . . , ap , Γ( 2γ − α + k) q (3.5) 2γ − α 2γ − α + k; γ; 1)Γ( + k) q q Consequently, we arrive at −α rmn = m α−2γ X 1 2γ − α (−m)k (a2 )k · · · (ap )k Tm Tn β 2q Γ( + k) q q (γ)k k! k=0 2γ − α + k; γ; 1) q 2γ−α m α−2γ 2γ − α X (−m)k (a2 )k · · · (ap )k ( q )k 1 2q Γ( ) = Tm Tn β q q (γ)k k! ×p+1 F1 (−n, a2 , . . . , ap , k=0 2γ − α ×p+1 F1 (−n, a2 , . . . , ap , + k; γ; 1). q This completes the proof. For the case of γ > 1 and α = 2, we have −2 rmn = m 1−γ X (−m)k (a2 )k · · · (ap )k 2(γ − 1) 1 Tm Tn β q Γ( + k) q (γ)k k! q k=0 (3.6) 2(γ − 1) ×p+1 F1 (−n, a2 , . . . , ap , + k; γ; 1). q 3.1. Matrix Elements for V (r) = rα . We now use the suggested basis (1.3) to compute the matrix elements for the power-law potential operators rα , α > 0. This kind of computation is important for may problems in the literature, such as Kratzer potential [6]. Whose calculation is achieved by means of following lemma. Lemma 3.2. For the generalized spiked harmonic oscillator Hamiltonian (1.2), the expectation values of the operator V (x) = rα with respect to a trial basis (1.3) are given by m hψm | rα | ψn i = α+2γ 1 2γ + α X (−m)k (a2 )k · · · (ap )k ( Tm Tn β − 2q Γ( ) q q (γ)k (k! 2γ+α q )k k=0 2γ + α ×p+1 F1 (−n, a2 , . . . , ap , + k; γ; 1) q (3.7) Proof. Using (1.3), it immediately follows that Z ∞ √ q p hψm | rα | ψn i = r2γ+α−1 e− βr p F1 (−m, a2 , . . . , ap ; γ; βrq ) 0 p ×p F1 (−n, a2 , . . . , ap ; γ; βrq )dr (3.8) 6 Q. D. KATATBEH, M. E. ABU-AMRA, EJDE-2008/64 Using the series representation (1.4) of the hypergeometric function p F1 , yields α rmn = Tm Tn ×β m X n X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l (γ)k (γ)l k!l! k=0 l=0 Z ∞ √ l+k 2γ+α+qk+ql−1 − βr q 2 r e (3.9) dr. 0 Using the integral representation of gamma function, we obtain under the condition 2γ+α q + k + l > 0 that α rmn = Tm Tn β− α+2γ 2q q m X n X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l 1 (γ)k (γ)l k!l! k=0 l=0 2γ + α × Γ( + k + l) q α+2γ m n i β − 2q X h X (−n)l (a2 )l · · · (ap )l 2γ + α = Tm Tn Γ( + k + l) q (γ)l l! q k=0 (3.10) l=0 (−m)k (a2 )k · · · (ap )k × (γ)k k! On the other hand, by using the definition of the Pochhammer symbols and the series representation of the hypergeometric functions (1.4), the finite sum inside the bracket collapses to n X (−n)l (a2 )l · · · (ap )l (γ)l l! l=0 = Γ( 2γ + α + k + l) q n X (−n)l (a2 )l · · · (ap )l ( 2γ+α + k)l q (γ)l l! l=0 =p+1 F1 (−n, a2 , . . . , ap , Γ( 2γ + α + 2 + k) q (3.11) 2γ + α 2γ + α + k; γ; 1)Γ( + k). q q Finally, we arrive at α rmn = Tm Tn β− α+2γ 2q q m X (−m)k (a2 )k · · · (ap )k k=0 (γ)k k! Γ( 2γ + α + k) q 2γ + α + k; γ; 1) q 2γ+α m 2γ + α X (−m)k (a2 )k · · · (ap )k ( q )k Γ( ) q (γ)k k! ×p+1 F1 (−n, a2 , . . . , ap , = Tm Tn β− α+2γ 2q q k=0 2γ + α ×p+1 F1 (−n, a2 , . . . , ap , + k; γ; 1). q The proof is complete. EJDE-2008/64 MATRIX ELEMENTS 7 On the other hand, for the case of γ > 0 and α = 2 > 0, we have that m 1 1+γ X (−m)k (a2 )k · · · (ap )k 2(γ + 1) hψm | r2 | ψn i = Tm Tn β − q Γ( + k) q (γ)k k! q k=0 (3.12) 2(γ + 1) + k; γ; 1). ×p+1 F1 (−n, a2 , . . . , ap , q Lemma 3.3. For γ > 0, and m, n = 0, 1, 2, . . . , Smn = hψm | ψn i 2γ m β − q 2γ X (−m)k (a2 )k · · · (ap )k ( q )k Γ( ) = Tm Tn q q (γ)k k! γ k=0 ×p+1 F1 (−n, a2 , . . . , ap , (3.13) 2γ + k; γ; 1) q Proof. Using (1.3), it follows that Z ∞ √ q p Smn = r2γ−1 e− βr p F1 (−m, a2 , . . . , ap ; γ; βrq ) 0 p ×p F1 (−n, a2 , . . . , ap ; γ; βrq )dr (3.14) By means of the series representation (1.4) of the hypergeometric function p F1 , that Smn = Tm Tn Z × l+k n m X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l β 2 k=0 l=0 ∞ √ 2γ+qk+ql−1 − βr q r e (γ)k (γ)l k!l! (3.15) dr. 0 Further, after restoring the integral representation of the gamma function and a change of variables, we obtain for 2γ q + k + l > 0, that Smn = Tm Tn γ 2γ m n β − q X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l Γ( q + k + l) q (γ)k (γ)l k!l! − γq k=0 l=0 m hX n X i (−m) (a ) · · · (a ) (−n)l (a2 )l · · · (ap )l 2γ k 2 k p k Γ( + k + l) q (γ)l l! q (γ)k k! k=0 l=0 (3.16) On the other hand, by using the definition of the pochhammer symbols and the series representation of the hypergeometric functions (1.4), the finite sum inside the bracket collapses to = Tm Tn β n X (−n)l (a2 )l · · · (ap )l l=0 = (γ)l l! Γ( 2γ + k + l) q n X (−n)l (a2 )l · · · (ap )l ( 2γ q + k)l l=0 (γ)l l! =p+1 F1 (−n, a2 , . . . , ap , Γ( 2γ + k) q 2γ 2γ + k; γ; 1)Γ( + k) q q (3.17) 8 Q. D. KATATBEH, M. E. ABU-AMRA, EJDE-2008/64 Consequently, Smn γ m β − q X 2γ (−m)k (a2 )k · · · (ap )k Γ( = Tm Tn + k) q q (γ)k k! k=0 2γ + k; γ; 1) q γ 2γ m β − q 2γ X (−m)k (a2 )k · · · (ap )k ( q )k = Tm Tn Γ( ) q q (γ)k k! ×p+1 F1 (−n, a2 , . . . , ap , k=0 ×p+1 F1 (−n, a2 , . . . , ap , 2γ + k; γ; 1) q This completes the proof. Lemma 3.4. For γ > 1, and m, n = 1, 2, . . . , the matrix elements of the generalized spiked harmonic oscillator Hamiltonians (1.2) can be written as Hmn = Tm Tn [β 1−γ q m (A − γ 2 + 2γ − 43 ) X (−m)k (a2 )k · · · (ap )k 2γ − 2 Γ( + k) q (γ)k k! q k=0 2γ − 2 + k; γ; 1) ×p+1 F1 (−n, a2 , . . . , ap , q m 1 X (−m)k (a2 )k · · · (ap )k 2γ + 2 − 1+γ q +B Γ( + k) q (γ)k k! q k=0 ×p+1 F1 (−n, a2 , . . . , ap , −β 1−γ q 2γ + 2 + k; γ; 1) q m q X (−m)k (a2 )k · · · (ap )k 2γ − 2 Γ( + 2 + k) 4 (γ)k k! q k=0 ×p+1 F1 (−n, a2 , . . . , ap , +β 1−γ q 2γ − 2 + 2 + k; γ; 1) q m q X (−m)k (a2 )k · · · (ap )k 2γ − 2 (γ − 1 + ) Γ( + 1 + k) 2 (γ)k k! q k=0 2γ − 2 + 1 + k; γ; 1) q m na2 · · · ap X (−m)k (a2 )k · · · (ap )k ×p+1 F1 (−n, a2 , . . . , ap , +β 1−γ q (q + 2(γ − 1)) γ k=0 ×p+1 F1 (1 − n, 1 + a2 , . . . , 1 + ap , −β 1−γ q q (γ)k k! Γ( 2γ − 2 + 1 + k) q 2γ − 2 + 1 + k; 1 + γ; 1) q m na2 · · · ap X (−m)k (a2 )k · · · (ap )k 2γ − 2 Γ( + 2 + k) γ (γ)k k! q k=0 2γ − 2 + 2 + k; 1 + γ; 1) q m 1−γ n(−1 + n)a2 (1 + a2 ) · · · ap (1 + ap ) X (−m)k (a2 )k · · · (ap )k −β q q γ(1 + γ) (γ)k k! ×p+1 F1 (1 − n, 1 + a2 , . . . , 1 + ap , k=0 EJDE-2008/64 MATRIX ELEMENTS 9 2γ − 2 2γ − 2 + 2 + k)p+1 F1 (2 − n, 2 + a2 , . . . , 2 + ap , + 2 + k; 2 + γ; 1) q q 2γ−α m α−2γ 1 2γ − α X (−m)k (a2 )k · · · (ap )k ( q )k ) + λβ 2q Γ( q q (γ)k k! × Γ( k=0 ×p+1 F1 (−n, a2 , . . . , ap , 2γ − α + k; γ; 1) q (3.18) Proof. By writing the Hamiltonian H in compactified form as d2 2 −2 −α | ψn +βrmn + Armn + λrmn dr2 Hmn =≺ ψm | − 2 −2 −α where rmn is given by (3.12) rmn is given by (3.6), and rmn is given by (3.1). By using (1.3) it is follows that Z ∞ √ √ B q 1 Hmn = − rγ− 2 e− 2 r p F1 (−m, a2 , . . . , ap ; γ; Brq ) 0 √ √ B q 1 d2 × 2 (rγ− 2 e− 2 r p F1 (−n, a2 , . . . , ap ; γ; Brq ))dr dr 2 −2 −α + βrmn + Armn + λrmn (3.19) We denote the first term on the right-hand side of (3.19) by Imn and have by means of the series representation (1.4) of the hypergeometric function p F1 , that m n l+k 3 X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l B 2 Imn = (−γ 2 + 2γ − ) 4 (γ)k (γ)l k!l! k=0 l=0 Z ∞ √ q × r2γ−3+qk+ql e− Br dr 0 −B l+k m n q 2 X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l B 2 4 (γ)k (γ)l k!l! k=0 l=0 ∞ Z √ r2γ−3+2q+qk+ql e− × Br q dr 0 m n l+k √ q X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l B 2 Bq(γ − 1 + ) 2 (γ)k (γ)l k!l! Z ∞ + k=0 l=0 × 0 n X √ r2γ−3+q+qk+ql e− Br q √ dr + Bq(2(γ − 1) + q) m na2 · · · ap X γ k=0 (−m)k (a2 )k · · · (ap )k (1 − n)l (1 + a2 )l · · · (1 + ap )l (γ)k (1 + γ)l l=0 l+k Z ∞ √ q B 2 × r2γ−3+q+qk+ql e− Br dr k!l! 0 m n na2 · · · ap X X (−m)k (a2 )k · · · (ap )k (1 − n)l (1 + a2 )l · · · (1 + ap )l − Bq 2 γ (γ)k (1 + γ)l k=0 l=0 l+k Z ∞ √ q B 2 × r2γ−3+2q+qk+ql e− Br dr k!l! 0 × 10 Q. D. KATATBEH, M. E. ABU-AMRA, EJDE-2008/64 n(−1 + n)a2 (1 + a2 ) · · · ap (1 + ap ) γ(1 + γ) m X n X (−m)k (a2 )k · · · (ap )k (2 − n)l (2 + a2 )l · · · (2 + ap )l − Bq 2 × (γ)k (2 + γ)l k=0 l=0 l+k × B 2 k!l! ∞ Z √ r2γ−3+2q+qk+ql e− Br q dr 0 Further, after restoring the integral representation of the gamma function and a change of variables, we obtain for 2(γ−1) + k + l > 0, 2(γ−1) + 1 + k + l > 0 and q q 2(γ−1) + q 2 + k + l > 0 that Imn =B 1−γ q m n (−γ 2 + 2γ − 34 ) X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l q (γ)k (γ)l k=0 l=0 × Γ( 2(γ−1) q −B +B l−γ q k!l! 2(γ−1) m n q X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l Γ( q + 2 + k + l) 4 l−γ q + k + l) (γ)k (γ)l k=0 l=0 m k!l! n q X X (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l (γ − 1 + ) 2 (γ)k (γ)l k=0 l=0 × × + 1 + k + l) Γ( 2(γ−1) q k!l! +B 1−γ q m na2 · · · ap X (2(γ − 1) + q) γ k=0 2(γ−1) n X (−m)k (a2 )k · · · (ap )k (1 − n)l (1 + a2 )l · · · (1 + ap )l Γ( q + 1 + k + l) (γ)k (1 + γ)l l=0 −B 1−γ q q k!l! m n na2 · · · ap X X (−m)k (a2 )k · · · (ap )k (1 − n)l (1 + a2 )l · · · (1 + ap )l γ (γ)k (1 + γ)l k=0 l=0 × × × Γ( 2(γ−1) q + 2 + k + l) k!l! −B 1−γ q q n(−1 + n)a2 (1 + a2 ) · · · ap (1 + ap ) γ(1 + γ) m X n X (−m)k (a2 )k · · · (ap )k (2 − n)l (2 + a2 )l · · · (2 + ap )l k=0 l=0 Γ( 2(γ−1) q = −B (γ)k (2 + γ)l + 2 + k + l) k!l! 1−γ q m n k=0 l=0 (−γ 2 + 2γ − 34 ) X h X (−n)l (a2 )l · · · (ap )l Γ( q (γ)k (γ)l 2(γ−1) q l! (−m)k (a2 )k · · · (ap )k k! 2(γ−1) n m hX X l−γ q (−n)l (a2 )l · · · (ap )l Γ( q + 2 + k + l) i q −B 4 (γ)k (γ)l l! × k=0 l=0 + k + l) i EJDE-2008/64 MATRIX ELEMENTS 11 m × l−γ (−m)k (a2 )k · · · (ap )k q X + B q (γ − 1 + ) k! 2 k=0 2(γ−1) n hX (−m)k (a2 )k · · · (ap )k (−n)l (a2 )l · · · (ap )l Γ( q + 1 + k + l) i × (γ)k (γ)l l! l=0 (−m)k (a2 )k · · · (ap )k × k! m n 1−γ na2 · · · ap X h X (1 − n)l (1 + a2 )l · · · (1 + ap )l + B q (2(γ − 1) + q) γ (γ)k (1 + γ)l k=0 × −B × × 1−γ q q + 1 + k + l) i (−m)k (a2 )k · · · (ap )k k! k! 2(γ−1) m hX n X na2 · · · ap (1 − n)l (1 + a2 )l · · · (1 + ap )l Γ( q + 2 + k + l) i γ k=0 (γ)k (1 + γ)l l=0 l! 1−γ (−m)k (a2 )k · · · (ap )k n(−1 + n)a2 (1 + a2 ) · · · ap (1 + ap ) −B q q k! γ(1 + γ) 2(γ−1) m n X h X (2 − n) (2 + a ) · · · (2 + a ) Γ( + 2 + k + l) i l k=0 × l=0 Γ( 2(γ−1) q 2 l p l q (γ)k (2 + γ)l l=0 l! (−m)k (a2 )k · · · (ap )k k! (3.20) We denote the finite sum inside the brackets in the expression above as I1mn , I2mn , . . . , I6mn . On the other hand, by using of the definition of the pochhammer symbols and the series representation of the hypergeometric functions (1.4), the finite sum inside the bracket collapses to I1mn = n X (−n)l (a2 )l · · · (ap )l l=0 = (γ)l l! (γ)l l! =p+1 F1 (−n, a2 , . . . , ap , n X (−n)l (a2 )l · · · (ap )l l=0 = 2(γ − 1) + k + l) q n X (−n)l (a2 )l · · · (ap )l ( 2(γ−1) + k)l q l=0 I2mn = Γ( (γ)l l! Γ( l=0 =p+1 F1 (−n, a2 , . . . , ap , 2(γ − 1) + k) q (3.21) 2(γ − 1) 2(γ − 1) + k; γ; 1)Γ( + k) q q 2(γ − 1) + 1 + k + l) q n X (−n)l (a2 )l · · · (ap )l ( 2(γ−1) + 1 + k)l q (γ)l l! Γ( Γ( 2(γ − 1) + 1 + k) q 2(γ − 1) 2(γ − 1) + 1 + k; γ; 1)Γ( + 1 + k) q q (3.22) 12 Q. D. KATATBEH, M. E. ABU-AMRA, I3mn = n X (−n)l (a2 )l · · · (ap )l l=0 = (γ)l l! (γ)l l! =p+1 F1 (−n, a2 , . . . , ap , Γ( 2(γ − 1) + 2 + k) q (1 + γ)l l! Γ( 2(γ − 1) + 1 + k + l) q n X + 1 + k)l (1 − n)l (1 + a2 )l · · · (1 + ap )l ( 2(γ−1) q (1 + γ)l l! l=0 =p+1 F1 (1 − n, 1 + a2 , . . . , 1 + ap , × Γ( (3.23) 2(γ − 1) 2(γ − 1) + 2 + k; γ; 1)Γ( + 2 + k) q q n X (1 − n)l (1 + a2 )l · · · (1 + ap )l l=0 = 2(γ − 1) + 2 + k + l) q n X + 2 + k)l (−n)l (a2 )l · · · (ap )l ( 2(γ−1) q l=0 I4mn = Γ( EJDE-2008/64 Γ( 2(γ − 1) + 1 + k) q 2(γ − 1) + 1 + k; 1 + γ; 1) q 2(γ − 1) + 1 + k) q (3.24) I5mn = n X (1 − n)l (1 + a2 )l · · · (1 + ap )l l=0 = (1 + γ)l l! Γ( 2(γ − 1) + 2 + k + l) q n X (1 − n)l (1 + a2 )l · · · (1 + ap )l ( 2(γ−1) + 2 + k)l q (1 + γ)l l! l=0 =p+1 F1 (1 − n, 1 + a2 , . . . , 1 + ap , × Γ( Γ( 2(γ − 1) + 2 + k) q 2(γ − 1) + 2 + k; 1 + γ; 1) q 2(γ − 1) + 2 + k) q (3.25) I6mn = 2(γ−1) n X (2 − n)l (2 + a2 )l · · · (2 + ap )l Γ( q + 2 + k + l) l=0 = (2 + γ)l l! n X + 2 + k)l (2 − n)l (2 + a2 )l · · · (2 + ap )l ( 2(γ−1) q (2 + γ)l l! l=0 =p+1 F1 (2 − n, 2 + a2 , . . . , 2 + ap , × Γ( Γ( 2(γ − 1) + 2 + k) q 2γ − 2 + 2 + k; 2 + γ; 1) q 2(γ − 1) + 2 + k) q (3.26) Substituting (3.21), (3.22), (3.23), (3.24), (3.25) and (3.26) into (3.20) we obtain m 3 X 2 1−γ (γ − 2γ + (−m)k (a2 )k · · · (ap )k 4) Imn = −B q I1mn q (γ)k k! k=0 EJDE-2008/64 −B MATRIX ELEMENTS 13 m q X (−m)k (a2 )k · · · (ap )k I2mn 4 (γ)k k! 1−γ q k=0 +B 1−γ q m q X (−m)k (a2 )k · · · (ap )k (γ − 1 + ) I3mn 2 (γ)k k! k=0 +B 1−γ q (q + 2(γ − 1)) m na2 · · · ap X (−m)k (a2 )k · · · (ap )k I4mn γ (γ)k k! k=0 m 1−γ na2 · · · ap X (−m)k (a2 )k · · · (ap )k I5mn −B q q γ (γ)k k! k=0 −B 1−γ q m n(−1 + n)a2 (1 + a2 ) · · · ap (1 + ap ) X (−m)k (a2 )k · · · (ap )k q I6mn γ(1 + γ) (γ)k k! k=0 This completes the proof. In the following tables, we used the derived formulas to compute upper bounds for many problems of interest in the literature. We compare our results with other authors who analyze the spectrum for this kind of problems. One of the advantage and the purpose of such formulas is to provide the researcher with simple method to compute the spectrum for sum of power-law potentials in the literature other than the saving in the time in these computations. d2 λ 2 Table 1 shows the eigenvalues of H = − dr + r2.5 2 + V (r), where V (r) = r anharmonic oscillator potential for different values of λ using s γ p 2β 2 (γ)n γ− 1 − √βrq r 2 e 2 3 F1 (−n, 0.2, 0.07; γ; βrq ) ψn (r) = n!Γ(γ) obtained using the computed matrix elements (3.18) and minimizing with respect to q, γ, andβ. The exponent (n) refer to the dimensions of the matrix used for the variational computations. λ 100 10 1 0.5 0.01 0.001 q 1.824 1.811 1.801 1.807 1.95 1.993 γ 11.117 4.797 2.553 2.229 1.55 1.506 β 2.4115 2.154 1.917 1.8169 1.132 1.017 E (3) 17.541 916 7.735 317 4.318 485 3.850 244 3.037 422 3.004 046 2 E (4) 17.541 912 7.735 256 4.318 181 3.850 028 3.037 421 3.004 046 2 E (5) 17.541 912 7.735 254 4.318 180 3.849 862 3.037 415 3.004 046 1 E 17.541 890 7.735 111 4.317 312 3.848 553 3.036 665 3.004 014 Table 1. Table 2 Shows a comparison between the results ofE HS and the results of the present workE U using s γ p 2β 2 (γ)n γ− 1 − √βrq ψn (r) = r 2 e 2 3 F1 (−n, 0.2, 0.07; γ; βrq ) n!Γ(γ) 2 λ d 2 and H = − dr + r2.5 anharmonic oscillator potential 2 + V (r) where V (r) = r for different values of λ, obtained using the computed matrix elements (3.18) and minimizing with respect to q, γ, andβ. The exponent (n) refer to the dimensions of the matrix used for the variational computations. 14 λ 100 10 1 0.5 0.01 0.001 Q. D. KATATBEH, M. E. ABU-AMRA, q 1.824 1.811 1.801 1.807 1.95 1.993 γ 11.117 4.797 2.553 2.229 1.55 1.506 β 2.4115 2.154 1.917 1.8169 1.132 1.017 E HS 17.541 890(30) 7.735 637(30) 4.323 263(30) 3.869 547(30) 3.039 244(30) 3.004 074(30) HS Em 17.542 040(5) 7.735 596(5) 4.318 963(5) 3.850 823(5) 3.037 474(5) 3.004 047(5) EJDE-2008/64 EU 17.541 912(5) 7.735 254(5) 4.318 141(7) 3.849 759(7) 3.037 399(8) 3.004 046(8) E 17.541 890 7.735 111 4.317 312 3.848 553 3.036 665 3.004 014 HS Table 2. E HS from [14]. Em from [14] after minimizing with respect to one parameter. Table 3 shows a comparison between the results of E B and the results of the present work E U using s γ p 2β 2 (γ)n γ− 1 − √βrq r 2 e 2 3 F1 (−n, 0.2, 0.07; γ; βrq ) ψn (r) = n!Γ(γ) 2 d 4 2 and H = − dr anharmonic oscillator potential for 2 + V (r)where V (r) = r − λr different values of λ, obtained using the computed matrix elements (3.18) and minimizing with respect to q, γ, and β. The exponent (n) refer to the dimensions of the matrix used for the variational computations. λ 2.0 1.0 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 q 2.928 2.023 2.616 2.595 2.574 2.536 2.536 2.518 2.500 2.484 2.468 γ 1.472 1.469 1.469 1.470 1.470 1.740 1.470 1.471 1.471 1.472 1.472 β 0.425 0.927 0.989 1.052 1.117 1.184 1.253 1.323 1.394 1.467 1.542 EB 1.726 29(10) 2.838 91(10) 2.941 23(10) 3.042 10(10) 3.141 55(10) 3.239 62(10) 3.336 36(10) 3.431 79(10) 3.525 96(10) 3.618 90(10) 3.710 64(10) EU 1.713 36(9) 2.835 34(8) 2.937 73(9) 3.039 06(8) 3.138 86(8) 3.237 24(9) 3.334 12(9) 3.429 94(9) 3.524 02(9) 3.617 47(8) 3.709 39(8) E 1.713 2.834 2.937 3.038 3.138 3.236 3.333 3.429 3.523 3.617 3.708 03 54 30 56 37 76 78 47 87 01 93 Table 3. E B from [4]. Conclusion. In this paper we compute closed formula for the matrix elements for Schrödinger equation using generalized hypergeometric function. We used general basis using special kind of functions obtained from the exact solutions of the Gol’dman and Krivchenkov eigenvalue problem [19]. In fact, for specific values of the constants p and q in (1.3) we retrieve to the old results found in the literature [8, 12, 13, 14, 15]. One of the advantages of our results is to obtain analytical formulas that provide us with accurate bounds for the non-solvable singular eigenvalues problems as well as saves time of the computations using the derived formulas. References [1] M. Abramowitz, I. A. Stegun. Handbook of Mathmatical Functions with Formulas, Graphs, and Mathematical Tables. New York: Dover; 1972: 555-566. EJDE-2008/64 MATRIX ELEMENTS 15 [2] V. C. Aguilera-Navarro, R. Guardiola. Nonsingular spiked harmonic oscillator. J. Math. Phys. 1991; 31: 2135. [3] V. C. Aguilera-Navarro, R. Guardiola. Variational and perturbative schemes for a spiked harmonic oscillator. J. Math. Phys. 1990; 31: 99. [4] G. R. P. 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The force V (r) = ar 2 + br −4 + cr −6 . J. Math. Phys. 1990; 31: 108. Qutaibeh D. Katatbeh Department of Mathematics and Statistics, Faculty of Science and Arts, Jordan University of Science and Technology, Irbid 22110, Jordan E-mail address: qutaibeh@yahoo.com Ma’zoozeh E. Abu-Amra Department of Mathematics and Statistics, Faculty of Science and Arts, Jordan University of Science and Technology, Irbid 22110, Jordan