ON Lp-ESTIMATES FOR THE TIME DEPENDENT SCHRÖDINGER OPERATOR ON L2 Lp -Estimates for the Schrödinger Operator MOHAMMED HICHEM MORTAD Département de Mathématiques Université d’Oran (Es-senia) B.P. 1524, El Menouar, Oran. Algeria. EMail: mortad@univ-oran.dz Received: 07 July, 2007 Accepted: 29 August, 2007 Communicated by: S.S. Dragomir 2000 AMS Sub. Class.: Primary 35B45; Secondary 35L10. Key words: Schrödinger Equation, Strichartz Estimates and Self-adjointness. Abstract: Let L denote the time-dependent Schrödinger operator in n space variables. We consider a variety of Lebesgue norms for functions u on Rn+1 , and prove or disprove estimates for such norms of u in terms of the L2 norms of u and Lu. The results have implications for self-adjointness of operators of the form L + V where V is a multiplication operator. The proofs are based mainly on Strichartztype inequalities. Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 1 of 18 Go Back Acknowledgements: I would like to express all my gratitude to my ex-Ph.D.-supervisor Professor Alexander M. Davie for his helpful comments, especially in the counterexamples section. Full Screen Close Contents 1 Introduction 3 2 2 L∞ t (Lx ) Estimates. 6 3 Lqt (Lrx ) Estimates. 10 4 Counterexamples 14 5 Question 16 Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 2 of 18 Go Back Full Screen Close 1. Introduction Let (x, t) ∈ Rn+1 where n ≥ 1. The Schrödinger equation ∂u = i4x u has been ∂t much studied using spectral properties of the self-adjoint operator 4x . When a multiplication operator (potential) V is added, it becomes important to determine whether 4x + V is a self-adjoint operator, and there is a vast literature on this question (see e.g. [9]). ∂ One can also, however, regard the operator L = −i ∂t − 4x as a self-adjoint operator on L2 (Rn+1 ), and that is the point of view taken in this paper. We ask what can be said about the domain of L, more specifically, we ask which Lq spaces, and more generally mixed Lqt (Lrx ) space, a function u must belong to, given that u is in the domain of L (i.e. u and Lu both belong to L2 (Rn+1 )). We answer this question and, using the Kato-Rellich theorem, deduce sufficient conditions on V for L + V to be self-adjoint. Our approach is based on the fact that any sufficiently well-behaved function u on Rn+1 can be regarded as a solution of the initial value problem (IVP) ( −iut − 4x u = g(x, t), (1.1) u(x, α) = f (x) Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 3 of 18 Go Back where α ∈ R, f (x) = u(x, α) and g = Lu. To apply this, we will use estimates for u based on given bounds for f and g. A number of such estimates are known and generally called Strichartz inequalities, after [12] which obtained such an Lq bound for u. This has since been generalized to give inequalities for mixed norms [13, 4]. The specific inequalities we use concern the case g = 0 of (1.1) and give bounds for u in terms of kf kL2 (Rn ) - see (3.2) below. The precise range of mixed Lqt (Lrx ) norms for which the bound (3.2) holds is known as a result of [13, 4] and the counterexample in [6]. Full Screen Close In Section 2 we prove a special case of our main theorem, namely a bound for u 2 in L∞ t (Lx ), which does not require Strichartz estimates, only elementary arguments using the Fourier transform. The main theorem, giving Lqt (Lrx ) bounds for the largest possible set of (q, r) pairs, is proved in Section 3. In fact, we prove a somewhat stronger bound, in a smaller space L2,q,r defined below. The fact that the set of pairs (q, r) covered by Theorem 3.1 is the largest possible is shown in Section 4. Some results on a similar question for the wave operator can be found in [7]. For Strichartz-type inequalities for the wave operator, see e.g. [11, 12, 2, 3, 4]. We assume notions and definitions about the Fourier Transform and unbounded operators and for a reference one may consult [8], [5] or [10]. We also use on several occasions the well-known Duhamel principle for the Schrödinger equation (see e.g. [1]). Notation. The symbol û stands for the Fourier transform of u in the space (x) variable while the inverse Fourier transform will be denoted either by F −1 u or ǔ. We denote by C0∞ (Rn+1 ) the space of infinitely differentiable functions with compact support. We denote by R+ the set of all positive real numbers together with +∞. For 1 ≤ p ≤ ∞, k · kp is the usual Lp -norm whereas k · kLpt (Lqx ) stands for the mixed spacetime Lebesgue norm defined as follows 1q q ku(t)kLrx dt . Z kukLqt (Lrx ) = kukLqt,k (Lrx ) = k vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 4 of 18 Go Back Close We also define some modified mixed norms. First we define, for any integer k, k+1 Mohammed Hichem Mortad Full Screen R Z Lp -Estimates for the Schrödinger Operator 1q ku(t)kqLrx dt , and then ! p1 kukLp,q,r = X kukpLq r t,k (Lx ) . k∈Z We note that kukLp,q1 ,r ≥ kukLp,q2 ,r if q1 ≥ q2 , and that kukLqt (Lrx ) ≤ kukLp,q,r if q ≥ p. Finally we define MLn = {f ∈ L2 (Rn+1 ) : Lf ∈ L2 (Rn+1 )}, Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 where L is defined as in the abstract and where the derivative is taken in the distributional sense. We note that MLn = D(L), the domain of L, and also that C0∞ (Rn+1 ) is dense in MLn in the graph norm kukL2 (Rn+1 ) + kLukL2 (Rn+1 ) . Title Page Contents JJ II J I Page 5 of 18 Go Back Full Screen Close 2. 2 L∞ t (Lx ) Estimates. Before stating the first result, we are going to prepare the ground for it. Take the Fourier transform of the IVP (1.1) in the space variable to get ( −iût + η 2 û = ĝ(η, t), Lp -Estimates for the Schrödinger Operator û(η, α) = fˆ(η) which has the following solution (valid for all t ∈ R): Z t 2 −iη 2 t ˆ (2.1) û(η, t) = f (η)e +i e−iη (t−s) ĝ(η, s)ds, vol. 8, iss. 3, art. 80, 2007 Title Page α where η ∈ Rn . Duhamel’s principle gives an alternative way of writing the part of the solution depending on g. Taking the case f = 0, the solution of (1.1) can be written as Z t (2.2) u(x, t) = i us (x, t)ds, α where us is the solution of ( Mohammed Hichem Mortad Contents JJ II J I Page 6 of 18 Go Back Lus = 0, t > s, us (x, s) = g(x, s). Now we state a result which we can prove using (2.1). In the next section we prove a more general result using Strichartz inequalities and Duhamel’s principle (2.2). Full Screen Close Proposition 2.1. For all a > 0, there exists b > 0 such that kukL2,∞,2 ≤ akLuk2L2 (Rn+1 ) + bkuk2L2 (Rn+1 ) for all u ∈ MLn . Proof. We prove the result for u ∈ C0∞ (Rn+1 ) and a density argument allows us to deduce it for u ∈ MLn . We use the fact that any such u is, for any α ∈ R, the unique solution of (1.1), where f (x) = u(x, α) and g = Lu, and therefore satisfies (2.1). Let k ∈ Z and let t and α be such that k ≤ t ≤ k + 1 and k ≤ α ≤ k + 1. Squaring (2.1), integrating with respect to η in Rn , and using Cauchy-Schwarz (and the fact that |t − α| ≤ 1), we obtain Z Z Z t 2 2 (2.3) kû(·, t)kL2 (Rn ) ≤ 2 |û(η, α)| dη + 2 |ĝ(η, s)|2 dsdη. Rn Rn Rn k=−∞ vol. 8, iss. 3, art. 80, 2007 Title Page Contents k |ĝ(η, s)| dηds. Rn ess sup ku(·, t)k2L2 (Rn ) ≤ 2kLuk2L2 (Rn+1 ) + 2kuk2L2 (Rn+1 ) . k≤t≤k+1 Finally to get an arbitrarily small constant in the Lu term we use a scaling argument: let m be a positive integer and let v(x, t) = u(mx, m2 t). Then we find kvkL2 (Rn+1 ) = m−1−n/2 kukL2 (Rn+1 ) JJ II J I 2 Now take the essential supremum of both sides in t over [k, k + 1], then sum in k over Z to get (recalling that g = Lu) ∞ X Mohammed Hichem Mortad α Now integrating against α in [k, k + 1] allows us to say that Z k+1 Z Z k+1 Z 2 2 ku(·, t)kL2 (Rn ) ≤ 2 |û(η, α)| dηdα + 2 k Lp -Estimates for the Schrödinger Operator Page 7 of 18 Go Back Full Screen Close and kLvkL2 (Rn+1 ) = m1−n/2 kLukL2 (Rn+1 ) . Also, kv(·, t)kL2 (Rn ) = m−n/2 ku(·, m2 t)kL2 (Rn ) and so sup kv(·, t)k2L2 (Rn ) = m−n k≤t≤k+1 sup m2 k≤t≤m2 (k+1) ku(·, t)k2L2 (Rn ) Mohammed Hichem Mortad m2 (k+1)−1 ≤ m−n Lp -Estimates for the Schrödinger Operator vol. 8, iss. 3, art. 80, 2007 X sup ku(·, t)k2L2 (Rn ) . j=m2 k j≤t≤j+1 Title Page Summing over k gives kvk2L2,∞,2 Contents ≤m −n kuk2L2,∞,2 ≤m −n ≤ 2m −2 2kLuk2L2 (Rn+1 ) kLvk2L2 (Rn+1 ) + 2kuk2L2 (Rn+1 ) + 2m 2 kvk2L2 (Rn+1 ) and choosing m so that 2m−2 < a completes the proof. Now we recall the Kato-Rellich theorem which states that if L is a self-adjoint operator on a Hilbert space and V is a symmetric operator defined on D(L), and if there are positive constants a < 1 and b such that kV uk ≤ akLuk + bkuk for all u ∈ D(L), then L + V is self-adjoint on D(L) (see [9]). Corollary 2.2. Let V be a real-valued function in L∞,2,∞ . Then L+V is self-adjoint on D(L) = MLn . JJ II J I Page 8 of 18 Go Back Full Screen Close Proof. One can easily check that kV ukL2 (Rn+1 ) ≤ kV kL∞,2,∞ kukL2,∞,2 . Choose a < kV k−1 L∞,2,∞ and then Proposition 2.1 shows that L + V satisfies the hypothesis of the Kato-Rellich theorem. In particular, it follows that L + V is self-adjoint whenever V ∈ L2t (L∞ x ). Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 9 of 18 Go Back Full Screen Close 3. Lqt (Lrx ) Estimates. Now we come to the main theorem in this paper, which depends on the following Strichartz-type inequality. Suppose n ≥ 1 and q and r are positive real numbers (possibly infinite) such that q ≥ 2 and 2 n n (3.1) + = . q r 2 When n = 2 we exclude the case q = 2, r = ∞. Then there is a constant C such that if f ∈ L2 (Rn ) and g = 0, the solution u of (1.1) satisfies (3.2) kukLqt (Lrx ) ≤ Ckf kL2 (Rn ) . This result can be found in [13] for q > 2; the more difficult ‘end-point’ case where q = 2, n ≥ 3 is treated in [4]. That (3.2) fails in the exceptional case n = 2, q = 2, r = ∞ is shown in [6]. For n ≥ 1 we define a region Ωn ∈ R+ × R+ as follows: for n 6= 2, 2 n n + + (3.3) Ωn = (q, r) ∈ R × R : + ≥ , q ≥ 2, r ≥ 2 q r 2 and for n = 2, Ω2 is defined by the same expression, with the omission of the point (2, ∞). The sets Ωn are probably most easily visualized in the ( 1q , 1r )-plane. Then Ω1 is a quadrilateral with vertices ( 41 , 0), ( 12 , 0), (0, 12 ), ( 12 , 12 ) and for n ≥ 2, Ωn is a triangle with vertices ( 12 , n−2 ), (0, 12 ), ( 12 , 12 ), the point ( 12 , 0) being excluded in the 2n case n = 2. Theorem 3.1. Let n ≥ 1, and let (q, r) ∈ Ωn . Then for all a > 0, there exists b > 0 such that (3.4) kukL2,q,r ≤ akLukL2 (Rn+1 ) + bkukL2 (Rn+1 ) n for all u ∈ ML . Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 10 of 18 Go Back Full Screen Close Proof. By the inclusion L2,q1 ,r ⊆ L2,q2 ,r , when q1 ≥ q2 it suffices to treat the case where 2q + nr = n2 , for which (3.2) holds. Let k ∈ Z and let α ∈ [k, k + 1]. As in the proof of Proposition 2.1 we use the fact that u is the solution of (1.1) with f = u(·, α) and g = Lu. Now we split u into two parts u = u1 + u2 , where u1 , u2 are the solutions of ( ( Lu1 = g, Lu2 = 0, u1 (x, α) = 0, u2 (x, α) = f. Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 The estimate for u2 is deduced from (3.2): (3.5) Lp -Estimates for the Schrödinger Operator ku2 kLqt (Lrx ) ≤ Ckf kL2 (Rn ) ≤ Cku(·, α)kL2 (Rn ) . Title Page For u1 we apply (2.2) to obtain Contents Z t u1 (x, t) = i (3.6) us (x, t)ds, JJ II J I α from which we deduce Z Page 11 of 18 k+1 kus (·, t)kLr (Rn ) ds ku1 (·, t)kLr (Rn ) ≤ k for t ∈ [k, k + 1], and hence Full Screen Z ku1 k Lqt,k (Lrx ) Go Back k+1 ≤ kus kLqt (Lrx ) ds k Z ≤C k+1 kg(·, s)kL2 (Rn ) ds k ≤ CkgkL2 (Rn ×[k,k+1]) . Close Combining this with (3.5) we have kuk2Lq r t,k (Lx ) ≤ 2C 2 ku(·, α)k2L2 (Rn ) + 2C 2 kLuk2L2 (Rn ×[k,k+1]) . Integrating w.r.t. α from k to k + 1 gives kuk2Lq r t,k (Lx ) ≤ 2C 2 kuk2L2 (Rn ×[k,k+1]) + 2C 2 kLuk2L2 (Rn ×[k,k+1]) . Lp -Estimates for the Schrödinger Operator Summing over k, we obtain kuk2L2,q,r ≤ 2C 2 kukL2 (Rn+1 ) + 2C 2 kLukL2 (Rn+1 ) , and the proof is completed by a similar scaling argument to that used in Proposition 2.1. Using the inclusion L2,q,r ⊆ Lqt (Lrx ) for all u ∈ vol. 8, iss. 3, art. 80, 2007 Title Page for q ≥ 2 we deduce Corollary 3.2. Let n ≥ 1, and let (q, r) ∈ Ωn . Then for all a > 0, there exists b > 0 such that kukLqt (Lrx ) ≤ akLukL2 (Rn+1 ) + bkukL2 (Rn+1 ) (3.7) Mohammed Hichem Mortad MLn . In particular, we get such a bound for kukLq (Rn+1 ) whenever 2 ≤ q ≤ (2n + 4)/n. By applying the Kato-Rellich theorem we can deduce a generalization of Corollary 2.2 from Theorem 3.1. We first define 2 n ∗ + + (3.8) Ωn = (p, s) ∈ R × R : + ≤ 1, p ≥ 2, s ≥ 2 p s for n 6= 2, and for n = 2, Ω2 is defined by the same expression, with the omission of the point (2, ∞). Contents JJ II J I Page 12 of 18 Go Back Full Screen Close Corollary 3.3. Let n ≥ 1 and let (p, s) ∈ Ω∗n . Let V be a real-valued function belonging to L∞,p,s . Then L + V is self-adjoint on MLn . 2p 2s Proof. Let q = p−2 and r = s−2 . Then (q, r) ∈ Ωn and the conclusion (3.4) of Theorem 3.1 applies. Now we have Z k+1 Z k+1 2 kV u(·, t)kL2 (Rn ) ≤ ku(·, t)k2Lr (Rn ) kV (·, t)k2Ls (Rn ) k k ≤ kuk2Lq r t,k (Lx ) kV k2Lp s t,k (Lx ) Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 and summation over k gives kV ukL2 (Rn+1 ) ≤ kukL2,q,r kV kL∞,p,s . Title Page Contents Then, using (3.4), the result follows in the same way as Corollary 2.2. It follows from Corollary 3.3 that L + V is self-adjoint whenever V ∈ Lpt (Lsx ) for (p, s) ∈ Ω∗n . Taking the case s = p, we find that L + V is self-adjoint if V ∈ Lp (Rn+1 ) for some p ≥ n + 2. JJ II J I Page 13 of 18 Go Back Full Screen Close 4. Counterexamples Now we show that Theorem 3.1 is sharp, as far as the allowed set of q, r is concerned. Proposition 4.1. Let n ≥ 1 and let q and r be positive real numbers, possibly infinite, such that (q, r) ∈ / Ωn . Then there are no constants a and b such that (3.7) holds for n all u ∈ ML . Proof. For (q, r) to fail to be in Ωn one of the following three possibilities must occur: (i) q < 2 or r < 2; (ii) 2q + nr < n2 ; (iii) n = 2, q = 2 and r = ∞. We consider these cases in turn. (i) If q < 2, choose a sequence (βk )k∈Z which is in l2 but not in lq . Let φ(x, t) be a n+1 smooth function which vanishes for t outside [0, 1], and P of compact support on R let u(x, t) = k∈Z βk φ(x, t − k). Then u ∈ MLn , but u ∈ / Lqt (Lrx ) for any r. The case r < 2 can be treated similarly. We chose a sequence βk which is in l2 r but set u(x, t) = P not l , and a smooth φ which vanishes for x1 outside [0, 1], then n β φ(x − ke , t), where e is the unit vector (1, 0, . . . , 0) in R . Then u ∈ MLn , 1 1 k∈Z k but u ∈ / Lqt (Lrx ) for any q. (ii) In this case we use the scaling argument which shows that the Strichartz estimates fail, together with a cutoff to ensure u and Lu are in L2 . We start with a non-zero f ∈ L2 (Rn ), and let u be the solution of (1.1) with 2 α = 0 and g = 0. (An explicit example would be f (x) = e−|x| and then u(x, t) = 2 (1 + 4it)−n/2 e−|x| /(1+4it) ). Choose a smooth function φ on R such that φ(0) 6= 0 and such that φ and φ0 are in L2 . Then for λ > 0 define vλ (x, t) = λn/2 u(λx, λ2 t)φ(t). Then (using Lu = 0) we find Lv(x, t) = −iλn/2 u(λx, λ2 t)φ0 (t). We calculate Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 14 of 18 Go Back Full Screen Close kvλ kL2 (Rn+1 ) = kf kL2 (Rn ) kφkL2 and kLvλ kL2 (Rn+1 ) = kf kL2 (Rn ) kφ0 kL2 . Also kvλ kLqt (Lrx ) = λ β 1q Z ku(·, t)kqLr (Rn ) |φ(λ−2 t)|q dt , R where β = n2 − nr − 2q > 0. So λ−β kvλ kLqt (Lrx ) → |φ(0)|kukLqt (Lrx ) (note that the norm on the right may be infinite) and hence kvλ kLqt (Lrx ) tends to ∞ as λ → ∞, completing the proof. Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad (iii) This exceptional case we treat in a similar fashion to (ii), but we need the result from [6], that the Strichartz inequality fails in this case. We start by fixing a smooth function φ on R such that φ = 1 on [−1, 1] and φ and φ0 are in L2 . Now let M > 0 be given and we use [6] to find f ∈ L2 (R2 ) with kf kL2 (R2 ) = 1 such that the solution u of (1.1) with α = 0 and g = 0 satisfies kukL2t (L∞ > M. x ) RR 2 2 1/2 Then we can find R > 0 so that −R ku(·, t)kL∞ (R2 ) dt > M . Let λ = R and define v(x, t) = λn/2 u(λx, λ2 t)φ(t). Then kvkL2 (R3 ) = kφkL2 , kLvkL2 (R3 ) = kφ0 kL2 and Z 1 2 kvkL2t (L∞ ≥ kv(·, t)k2L∞ (R2 ) dt > M 2 , x ) vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 15 of 18 −1 which completes the proof, since M is arbitrary. We remark that [6] also gives an example of f ∈ L2 (R2 ) such that u ∈ / L2t (BM Ox ) and the argument of part (iii) can then be applied to show that no inequality kukL2t (BM Ox ) ≤ akLukL2 (R3 ) + bkukL2 (R3 ) can hold. Go Back Full Screen Close 5. Question We saw as a result of Corollary 3.3 that if (p, s) ∈ Ω∗ , then L + V is self-adjoint on MLn whenever V ∈ Lpt (Lsx ). One can ask whether this can be extended to a larger range of (p, s) with p, s ≥ 2. If one asks whether L + V is defined on MLn , then we would require a bound kV ukL2 (Rn+1 ) ≤ akLukL2 (Rn+1 ) +bkuk to hold for all u ∈ MLn . If such a bound is to hold for all V ∈ Lpt (Lsx ), then, in fact, we require (3.7) 2p 2s to hold for q = p−2 and r = s−2 , which we know cannot hold unless (p, s) ∈ Ω∗ . One can instead ask for L + V , defined on say C0∞ (Rn+1 ), to be essentially selfadjoint. This is equivalent to saying that the only (distribution) solution in L2 (Rn+1 ) of the PDE −iut − 4x u + V u = ±iu is u = 0 (see e.g. [8]). We do not know if there are any values of (p, s) not in Ω∗n such that this holds for all V ∈ Lpt (Lsx ). The analogous question for the Laplacian is extensively discussed in [9]. Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 16 of 18 Go Back Full Screen Close References [1] L.C. EVANS, Partial Differential Equations, American Mathematical Society (G.S.M. Vol. 19), 1998. [2] J. GINIBRE AND G. VELO, Generalized Strichartz inequalities for the wave equation, J. of Functional Analysis, 133 (1995), 50–68. [3] J. HARMSE, On Lebesgue space estimates for the wave equation, Indiana Univ. Math. J., 39(1) (1990) 229–248. Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 [4] M. KEEL AND T. TAO, Endpoint Strichartz estimates, Amer. J. of Math., 120 (1998), 955–980. Title Page [5] E.H. LIEB AND M. LOSS, Analysis, American Mathematical Society (G.S.M. Vol. 14), Second Edition 2001. [6] S.J. MONTGOMERY-SMITH, Time decay for the bounded mean oscillation of solutions of the Schrödinger and wave equations, Duke Math. J., 91(2) (1998), 393–408. 2 Contents JJ II J I Page 17 of 18 n [7] M.H. MORTAD, Self-adjointness of the perturbed wave operator on L (R ), Proc. Amer. Math. Soc., 133(2) (2005), 455–464. [8] M. REED AND B. SIMON, Methods of Modern Mathematical Physics, Vol. 1, “Functional Analysis,” Academic Press, 1972. [9] M. REED AND B. SIMON, Methods of Modern Mathematical Physics, Vol.2, “Fourier Analysis, Self-Adjointness,” Academic Press, 1975. [10] E.M. STEIN AND G. WEISS, Introduction to Fourier Analysis on Euclidean Spaces, (PMS; 32) Princeton University Press, 1971. Go Back Full Screen Close [11] R.S. STRICHARTZ, A priori estimates for the wave equation and some applications, J. of Functional Analysis, 5 (1970), 218–235. [12] R.S. STRICHARTZ, Restrictions of Fourier transforms to quadratic surfaces and decay of solutions of wave equations, Duke Mathematical Journal, 44(3) (1977), 705–714. [13] K. YAJIMA, Existence of solutions for Schrödinger evolution equations, Comm. Math. Phys., 110 (1987), 415–426. Lp -Estimates for the Schrödinger Operator Mohammed Hichem Mortad vol. 8, iss. 3, art. 80, 2007 Title Page Contents JJ II J I Page 18 of 18 Go Back Full Screen Close