CERTAIN SUBCLASSES OF p-VALENT MEROMORPHIC FUNCTIONS INVOLVING CERTAIN OPERATOR p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 M.K. AOUF AND A.O. MOSTAFA Department of Mathematics Faculty of Science Mansoura University Mansoura 35516, Egypt. EMail: mkaouf127@yahoo.com Title Page Contents adelaeg254@yahoo.com JJ II I Received: 25 March, 2008 J Accepted: 20 May, 2008 Page 1 of 16 Communicated by: N.K. Govil 2000 AMS Sub. Class.: 30C45. Key words: Analytic, p−valent, Meromorphic, Integral operator. Abstract: P In this paper, a new subclass α p,β (η, δ, µ, λ) of p−valent meromorphic functions defined by certain integral operator is introduced. Some interesting properties of this class are obtained. Acknowledgements: The authors would like to thank the referees of the paper for their helpful suggestions. Go Back Full Screen Close Contents 1 Introduction 3 2 Main Results 6 p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 Title Page Contents JJ II J I Page 2 of 16 Go Back Full Screen Close 1. Introduction Let P p be the class of functions f of the form: f (z) = z (1.1) −p + ∞ X ak−p z k−p (p ∈ N = {1, 2, ...}), k=1 which are analytic and p−valent in the punctured unit disc U ∗ = {z : z ∈ C and 0 < |z| < 1} = U \{0}. P Similar to [1], we define the following family of integral operators Qαβ,p : p → P p (α ≥ 0, β > −1; p ∈ N) as follows: (1.2) Qαβ,p f (z) (1.3) vol. 9, iss. 2, art. 45, 2008 Z z α+β−1 t −(p+β) = αz (1 − )α−1 tβ+p−1 f (t)dt β−1 z 0 (α > 0; β > −1; p ∈ N; f ∈ Σp ); Contents and JJ II J I Page 3 of 16 (ii) Go Back (1.4) Q0β,p f (z) = f (z) (for α = 0; β > −1; p ∈ N; f ∈ Σp ). ∞ Qαβ,p f (z) =z −p Full Screen Close From (1.2) and (1.4), we have (1.6) M.K. Aouf and A.O. Mostafa Title Page (i) (1.5) p-Valent Meromorphic Functions Γ(α + β) X Γ(k + β) + ak−p z k−p Γ(β) k=1 Γ(k + β + α) (α ≥ 0; β > −1; p ∈ N; f ∈ Σp ). Using the relation (1.5), it is easy to show that α z(Qαβ,p f (z))0 = (α + β − 1)Qα−1 β,p f (z) − (α + β + p − 1)Qβ,p f (z). P Pα Definition 1.1. Let p,β (η, δ, µ, λ) be the class of functions f ∈ p which satisfy: (1.7) (1.8) Re (1 − λ) Qαβ,p f (z) Qαβ,p g(z) !µ +λ Qα−1 β,p f (z) Qα−1 β,p g(z) Qαβ,p f (z) Qαβ,p g(z) !µ−1 > η, p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 where g ∈ (1.9) P p satisfies the following condition: ( ) Qαβ,p g(z) Re > δ (0 ≤ δ < 1; z ∈ U ), Qα−1 β,p g(z) and η and µ are real numbers such that 0 ≤ η < 1, µ > 0 and λ ∈ C with Re{λ} > 0. To establish our main results we need the following lemmas. Lemma 1.2 ([2]). Let Ω be a set in the complex plane C and let the function ψ : 1+r 2 C2 → C satisfy the condition ψ(ir2 , s1 ) ∈ / Ω for all real r2 , s1 ≤ − 2 2 . If q is analytic in U with q(0) = 1 and ψ(q(z), zq 0 (z)) ∈ Ω, z ∈ U, then Re{q(z)} > 0 (z ∈ U ). Lemma 1.3 ([3]). If q is analytic in U with q(0) = 1, and if λ ∈ C\{0} with Re{λ} ≥ 0, then Re{q(z) + λzq 0 (z)} > α (0 ≤ α < 1) implies Re{q(z)} > α + (1 − α)(2γ − 1), where γ is given by Z 1 γ = γ(Re λ) = (1 + tRe{λ} )−1 dt 0 Title Page Contents JJ II J I Page 4 of 16 Go Back Full Screen Close which is increasing function of Re{λ} and sense that the bound cannot be improved. 1 2 ≤ γ < 1. The estimate is sharp in the For real or complex numbers a, b and c (c 6= 0, −1, −2, . . . ), the Gauss hypergeometric function is defined by (1.10) 2 F1 (a, b; c; z) = 1 + a·b z a(a + 1) · b(b + 1) z 2 + + ··· . c 1! c(c + 1) 2! We note that the series (1.10) converges absolutely for z ∈ U and hence represents an analytic function in U (see, for details, [4, Ch. 14]). Each of the identities (asserted by Lemma 1.4 below) is fairly well known (cf., e.g., [4, Ch. 14]). Lemma 1.4 ([4]). For real or complex numbers a, b and c (c 6= 0, −1, −2, . . . ), Z 1 Γ(b)Γ(c − b) (1.11) tb−1 (1 − t)c−b−1 (1 − tz)−a dt = 2 F1 (a, b; c; z) Γ(c) 0 (Re(c) > Re(b) > 0); p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 Title Page Contents JJ II J I Page 5 of 16 (1.12) 2 F1 (a, b; c; z) = (1 − z)−a 2 F1 z a, c − b; c; z−1 ; Go Back Full Screen (1.13) 2 F1 (a, b; c; z) =2 F1 (b, a; c; z); and (1.14) 2 F1 1 1, 1; 2; 2 = 2 ln 2. Close 2. Main Results Unless otherwise mentioned, we assume throughout this paper that α ≥ 0; β > −1; α + β 6= 1; µ > 0; 0 ≤ η < 1; p ∈ N and λ ≥ 0. P Theorem 2.1. Let f ∈ αp,β (η, δ, µ, λ). Then !µ Qαβ,p f (z) 2µη(α + β − 1) + λδ (2.1) Re > , (z ∈ U ), α Qβ,p g(z) 2µ(α + β − 1) + λδ P where the function g ∈ p satisfies the condition (1.9). Proof. Let γ = (2.2) 2µη(α+β−1)+λδ , 2µ(α+β−1)+λδ and we define the function q by " !µ # Qαβ,p f (z) 1 q(z) = −γ . 1−γ Qαβ,p g(z) Then q is analytic in U and q(0) = 1. If we set (2.3) h(z) = Qαβ,p g(z) M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 Title Page Contents JJ II J I Page 6 of 16 , Qα−1 β,p g(z) Go Back then by the hypothesis (1.9), Re{h(z)} > δ. Differentiating (2.2) with respect to z and using the identity (1.7), we have !µ !µ−1 α Qα−1 f (z) Qαβ,p f (z) Q f (z) β,p β,p + λ α−1 (2.4) (1 − λ) α Qβ,p g(z) Qβ,p g(z) Qαβ,p g(z) = [(1 − γ)q(z) + γ] + p-Valent Meromorphic Functions λ(1 − γ) zq 0 (z)h(z). µ(α + β − 1) Full Screen Close Let us define the function ψ(r, s) by (2.5) ψ(r, s) = [(1 − γ)r + γ] + Using (2.5) and the fact that f ∈ Pα λ(1 − γ) sh(z). µ(α + β − 1) p,β (η, δ, µ, λ), we obtain {ψ(q(z), zq 0 (z)); z ∈ U )} ⊂ Ω = {w ∈ C : Re(w) > η}. Now for all real r2 , s1 ≤ − 1+r22 , 2 p-Valent Meromorphic Functions we have M.K. Aouf and A.O. Mostafa λ(1 − γ)s1 Re h(z) µ(α + β − 1) λ(1 − γ)δ(1 + r22 ) ≤γ− 2µ(α + β − 1) λ(1 − γ)δ ≤γ− = η. 2µ(α + β − 1) vol. 9, iss. 2, art. 45, 2008 Re{ψ(ir2 , s1 )} = γ + Hence for each z ∈ U, ψ(ir2 , s1 ) ∈ / Ω. Thus by Lemma 1.2, we have Re{q(z)} > 0 (z ∈ U ) and hence !µ Qαβ,p f (z) > γ (z ∈ U ). Re Qαβ,p g(z) This proves Theorem 2.1. Title Page Contents JJ II J I Page 7 of 16 Go Back Full Screen Close P Corollary 2.2. Let the functions f and g be in p and let g satisfy the condition (1.9). If λ ≥ 1 and ( ) Qα−1 Qαβ,p f (z) β,p f (z) (2.6) Re (1 − λ) α + λ α−1 > η (0 ≤ η < 1; z ∈ U ), Qβ,p g(z) Qβ,p g(z) then ( (2.7) Re Qα−1 β,p f (z) ) Qα−1 β,p g(z) >γ= η[2(α + β − 1) + δ] + δ(λ − 1) 2(α + β − 1) + δλ (z ∈ U ). Proof. We have ( ) Qα−1 Qα−1 Qαβ,p f (z) Qαβ,p f (z) β,p f (z) β,p f (z) = (1 − λ) α + λ α−1 + (λ − 1) α λ α−1 Qβ,p g(z) Qβ,p g(z) Qβ,p g(z) Qβ,p g(z) p-Valent Meromorphic Functions (z ∈ U ). Since λ ≥ 1, making use of (2.6) and (2.1) (for µ = 1), we deduce that ( α−1 ) Qβ,p f (z) η[2(α + β − 1) + δ] + δ(λ − 1) Re >γ= (z ∈ U ). α−1 2(α + β − 1) + δλ Qβ,p g(z) Corollary 2.3. Let λ ∈ C\{0} with Re{λ} ≥ 0. If f ∈ condition: P p satisfies the following (z ∈ U ), Title Page Contents JJ II J I Go Back Full Screen then Re{(z p Qαβ,p f (z))µ } > Further, if λ ≥ 1 and f ∈ (2.9) vol. 9, iss. 2, art. 45, 2008 Page 8 of 16 p α µ−1 Re{(1 − λ)(z p Qαβ,p f (z))µ + λz p Qα−1 }>η β,p f (z)(z Qβ,p f (z)) (2.8) M.K. Aouf and A.O. Mostafa P p 2µη(α + β − 1) + Re{λ} 2µ(α + β − 1) + Re{λ} (z ∈ U ). satisfies Re{(1 − λ)z p Qαβ,p f (z) + λz p Qα−1 β,p f (z)} > η (z ∈ U ), Close then (2.10) Re{z p Qα−1 β,p f (z)} > 2η(α + β − 1) + λ − 1 2(α + β − 1) + λ (z ∈ U ). Proof. The results (2.8) and (2.10) follow by putting g(z) = z −p in Theorem 2.1 and Corollary 2.2, respectively. Remark 1. Choosing α, λ and µ appropriately in Corollary 2.3, we have, p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa (i) For α = 0, β 6= 1 and λ = 1 in Corollary 2.3, we have: 1 zf 0 (z) µ p Re β+p−1+ (z f (z)) > η β−1 f (z) vol. 9, iss. 2, art. 45, 2008 (z ∈ U ), Title Page Contents which implies that 2µη(β − 1) + 1 Re {z f (z)} > 2µ(β − 1) + 1 p µ (z ∈ U ). (ii) For α = 0, β 6= 1, µ = 1 and λ ∈ C\{0} with Re{λ} ≥ 0 in Corollary 2.3, we have λp λ p+1 0 p Re (1 + )z f (z) + z f (z) > η, β−1 β−1 which implies that Re {z p f (z)} > JJ II J I Page 9 of 16 Go Back Full Screen Close 2η(β − 1) + Re{λ} 2(β − 1) + Re{λ} (z ∈ U ). 0 (iii) Replacing f by − zfp in the result (ii), we have: h i z p+1 f 0 (z) p+1 00 λ λ − Re 1 + β−1 (p + 1) + p(β−1) z f (z) > η p (0 ≤ η < 1; z ∈ U ), which implies that p+1 0 z f (z) 2η(β − 1) + Re{λ} > (z ∈ U ). − Re p 2(β − 1) + Re{λ} P Theorem 2.4. Let λ ∈ C with Re{λ} > 0. If f ∈ p satisfies the following condition: p α µ−1 (2.11) Re{(1−λ)(z p Qαβ,p f (z))µ +λz p Qα−1 }>η β,p f (z)(z Qβ,p f (z)) (z ∈ U ), p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 Title Page then (2.12) Contents Re{(z p Qαβ,p f (z))µ } > η + (1 − η)(2ρ − 1), where (2.13) 1 µ(α + β − 1) 1 ρ = 2 F1 1, 1; + 1; . 2 Re{λ} 2 JJ II J I Page 10 of 16 Go Back Proof. Let q(z) = (z p Qαβ,p f (z))µ . Full Screen Then q is analytic with q(0) = 1. Differentiating (2.14) with respect to z and using the identity (1.7), we have Close (2.14) p α µ−1 (1 − λ)(z p Qαβ,p f (z))µ + λz p Qα−1 β,p f (z)(z Qβ,p f (z)) = q(z) + λ zq 0 (z), µ(α + β − 1) so that by the hypothesis (2.11), we have λ 0 Re q(z) + zq (z) > η µ(α + β − 1) (z ∈ U ). In view of Lemma 1.3, this implies that Re{q(z)} > η + (1 − η)(2ρ − 1), p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa where Z 1 ρ = ρ(Re{λ}) = 1+t Re{λ} µ(α+β−1) −1 vol. 9, iss. 2, art. 45, 2008 dt. 0 Putting Re{λ} = λ1 > 0, we have Z 1 Z −1 λ1 µ(α+β−1) µ(α + β − 1) 1 −1 µ(α+β−1)) ρ= 1+t dt = (1 + u)−1 u λ1 du λ1 0 0 Using (1.11), (1.12), (1.13) and (1.14), we obtain 1 µ(α + β − 1) 1 ρ= + 1; . 2 F1 1, 1; 2 λ1 2 Re{z II J I Full Screen Corollary 2.5. Let λ ∈ R with λ ≥ 1. If f ∈ p satisfies (2.15) Re (1 − λ)z p Qαβ,p f (z) + λz p Qα−1 f (z) >η β,p Qα−1 β,p f (z)} JJ Go Back P p Contents Page 11 of 16 This completes the proof of Theorem 2.1. then Title Page 1 > η + (1 − η)(2ρ1 − 1) 1 − λ Close (z ∈ U ), (z ∈ U ), where 1 ρ1 = 2 2 F1 (α + β − 1) 1 1, 1; + 1; λ 2 . Proof. The result follows by using the identity p α p α−1 p α (2.16) λz p Qα−1 β,p f (z) = (1 − λ)z Qβ,p f (z) + λz Qβ,p f (z) + (λ − 1)z Qβ,p f (z). p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa Remark 2. We note that, for α = 0, β = 2 and λ = µ > 0 in Corollary 2.3, that is, if (2.17) Re (1 − λ)(z p f (z))λ + λ(z p+1 f (z))0 (z p f (z))λ−1 > η (z ∈ U ), vol. 9, iss. 2, art. 45, 2008 Title Page Contents then (2.8) implies that Re{(z p f (z))λ } > (2.18) 2η + 1 3 (z ∈ U ), P whereas, if f ∈ p satisfies the condition (2.17) then by using Theorem 2.4, we have Re{(z p f (z))λ } > 2(1 − ln 2)η + (2 ln 2 − 1) (z ∈ U ), which is better than (2.18). JJ II J I Page 12 of 16 Go Back Full Screen P Theorem 2.6. Suppose that the functions f and g are in p and g satisfies the condition (1.9). If ( α−1 ) Qβ,p f (z) Qαβ,p f (z) (1 − η)δ >− (z ∈ U ), (2.19) Re − α α−1 Qβ,p g(z) 2(α + β − 1) Qβ,p g(z) Close for some η (0 ≤ η < 1), then ( Re (2.20) Qαβ,p f (z) Qαβ,p g(z) ) >η (z ∈ U ) and ( (2.21) Re Qα−1 β,p f (z) Qα−1 β,p g(z) ) > η[2(α + β − 1) + δ] − δ 2(α + β − 1) (z ∈ U ). p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 Proof. Let (2.22) " # Qαβ,p f (z) 1 q(z) = −η . 1 − η Qαβ,p g(z) Then q is analytic in U with q(0) = 1. Setting (2.23) φ(z) = Qαβ,p g(z) Qα−1 β,p g(z) (z ∈ U ), we observe that from (1.9), we have Re{φ(z)} > δ (0 ≤ δ < 1) in U . A simple computation shows that Qα−1 Qαβ,p f (z) (1 − η)zq 0 (z) β,p f (z) φ(z) = α−1 − α α+β−1 Qβ,p g(z) Qβ,p g(z) = ψ(q(z), zq 0 (z)), where ψ(r, s) = (1 − η)sφ(z) . α+β−1 Title Page Contents JJ II J I Page 13 of 16 Go Back Full Screen Close Using the hypothesis (2.19), we obtain {ψ(q(z), zq (z)); z ∈ U } ⊂ Ω = w ∈ C : Re w > − 0 Now, for all real r2 , s1 ≤ − 1+r22 , 2 (1 − η)δ 2(α + β − 1) . we have s1 (1 − η) Re{φ(z)} α+β−1 −(1 − η)δ(1 + r22 ) ≤ 2(α + β − 1) −(1 − η)δ ≤ . 2(α + β − 1) p-Valent Meromorphic Functions Re {ψ(ir2 , s1 )} = M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 Title Page Contents This shows that ψ(ir2 , s1 ) ∈ / Ω for each z ∈ U. Hence by Lemma 1.2, we have Re{q(z)} > 0 (z ∈ U ). This proves (2.20). The proof of (2.21) follows by using (2.20) and (2.21) in the identity: ( α−1 ) ( α−1 ) ( ) Qβ,p f (z) Qβ,p f (z) Qαβ,p f (z) Qαβ,p f (z) Re = Re − α − Re . Qβ,p g(z) Qαβ,p g(z) Qα−1 Qα−1 β,p g(z) β,p g(z) JJ II J I Page 14 of 16 Go Back Full Screen This completes the proof of Theorem 2.6. Close Remark 3. (i) For α = 0 and g(z) = z −p in Theorem 2.6, we have −(1 − η)δ Re z p+1 f 0 (z) + pz p f (z) > 2 (z ∈ U ), which implies that Re {z p f (z)} > η (z ∈ U ) and η[2(β − 1) + δ] − δ Re z p+1 f 0 (z) + (p + β − 1)z p f (z) > 2 (ii) Putting α = 0, β = 2 in Theorem 2.6, we get that, if 0 zf (z) + (p + 1)f (z) f (z) −(1 − η)δ Re − > 0 zg (z) + (p + 1)g(z) g(z) 2 (z ∈ U ). p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa (z ∈ U ), vol. 9, iss. 2, art. 45, 2008 Title Page then Re and Re f (z) g(z) zf 0 (z) + (p + 1)f (z) zg 0 (z) + (p + 1)g(z) >η (z ∈ U ) η(2 + δ) − δ > 2 Contents (z ∈ U ). JJ II J I Page 15 of 16 Go Back Full Screen Close References [1] E. AQLAN, J.M. JAHANGIRI AND S.R. KULKARNI, Certain integral operators applied to meromorphic p-valent functions, J. of Nat. Geom., 24 (2003), 111–120. [2] S.S. MILLER AND P.T. MOCANU, Second order differential equations in the complex plane, J. Math. Anal. Appl., 65 (1978), 289–305. [3] S. PONNUSAMY, Differential subordination and Bazilevic functions, Proc. Indian Acad. Sci. (Math. Sci.), 105 (1995), 169–186. [4] E.T. WHITTAKER AND G.N. WATSON, A Course of Modern Analysis: An Introduction to the General Theory of Infinite Processes and of Analytic Functions; With an Account of the Principal Transcendental Functions, Fourth Edition, Cambridge University Press, Cambridge, 1927. p-Valent Meromorphic Functions M.K. Aouf and A.O. Mostafa vol. 9, iss. 2, art. 45, 2008 Title Page Contents JJ II J I Page 16 of 16 Go Back Full Screen Close