Volume 9 (2008), Issue 1, Article 30, 6 pp. UNIFORMLY STARLIKE AND UNIFORMLY CONVEX FUNCTIONS PERTAINING TO SPECIAL FUNCTIONS V.B.L. CHAURASIA AND AMBER SRIVASTAVA D EPARTMENT OF M ATHEMATICS U NIVERSITY OF R AJASTHAN , JAIPUR -302004, I NDIA D EPARTMENT OF M ATHEMATICS S WAMI K ESHVANAND I NSTITUTE OF T ECHNOLOGY, M ANAGEMENT AND G RAMOTHAN JAGATPURA , JAIPUR -302025, I NDIA amber@skit.ac.in Received 04 September, 2006; accepted 14 July, 2007 Communicated by H.M. Srivastava A BSTRACT. The main object of this paper is to derive the sufficient conditions for the function z{p ψq (z)} to be in the classes of uniformly starlike and uniformly convex functions. Similar results using integral operator are also obtained. Key words and phrases: Analytic functions, Univalent functions, Starlike functions, Convex functions, Integral operator, FoxWright function. 2000 Mathematics Subject Classification. 30C45. 1. I NTRODUCTION Let A denote the class of functions of the form ∞ X (1.1) f (z) = z + an z n , n=2 that are analytic in the open unit disk ∆ = {z : |z| < 1}. Also let S denote the subclass of A consisting of all functions f (z) of the form (1.2) f (z) = z − ∞ X an z n , an ≥ 0. n=2 0 (z) A function f ∈ A is said to be starlike of order α, 0 ≤ α < 1, if and only if Re zff (z) > α, f (z)−f (ξ) z ∈ ∆. Also f of the form (1.1) is uniformly starlike, whenever (z−ξ)f ≥ 0, (z,ξ) ∈ 0 (z) The authors are grateful to Professor H.M. Srivastava, University of Victoria, Canada for his kind help and valuable suggestions in the preparation of this paper. 230-06 2 V.B.L. C HAURASIA AND A MBER S RIVASTAVA ∆ × ∆. This class of all uniformly starlike functions is denoted by U ST [4] (see also [5], [10] and [14]). 00 (z) The function f of the form (1.1) is uniformly convex in ∆ whenever Re 1 + (z − ξ) ff 0 (z) ≥ 0, (z,ξ) ∈ ∆ × ∆. This class of all uniformly convex functions is denoted by U CV [3] (also 00and [13]). Further it is said to be in the class U CV (α), α ≥ 0 if refer 0[2], [6], [9] (z) zf (z) Re 1 + f (z) ≥ α zff 0 (z) . A functionf of the form (1.2) is said to be in the class U ST N (α), 0 ≤ α ≤ 1, if f (z)−f (ξ) Re (z−ξ)f ≥ α, (z,ξ) ∈ ∆ × ∆. 0 (z) In the present paper, we shall use analogues of the lemmas in [8] and [7] respectively in the following form. Lemma 1.1. A function f of the form (1.1) is in the class U ST (α), if ∞ X [(3 − α)n − 2] |an | ≤ (1 − α)M1 , n=2 where M1 > 0 is a suitable constant. In particular, f ∈ U ST whenever ∞ X (3n − 2) |an | ≤ M1 . n=2 LemmaP1.2. A sufficient condition for a function f of the form (1.1) to be in the class U CV (α) is that ∞ 1)n − α] an ≤ M2 , where M2 > 0 is a suitable constant. In particular, n=2 n[(α + P 2 f ∈ U CV whenever ∞ n=2 n an ≤ M2 . The Fox-Wright function [12, p. 50, equation 1.5] appearing in the present paper is defined by X ∞ Qp n (aj , αj )1,p ; j=1 Γ(aj + αj n)z Q (1.3) ψ (z) = ψ z = , p q p q q (bj , βj )1,q ; Γ(b + β n)n! j j j=1 n=0 P P where αj (j = 1, . . . , p) and βj (j = 1, . . . , q) are real and positive and 1+ qj=1 βj > pj=1 αj . 2. M AIN R ESULTS Theorem 2.1. If q X j=1 |bj | > p X |aj | + 1, aj > 0 j=1 and 1+ q X j=1 βj > p X αj , j=1 then a sufficient condition for the function z{ p ψq (z)} to be in the class U ST (α), 0 ≤ α < 1, is Qp 3−α (|aj + αj |, αj )1,p ; (|aj |, αj )1,p ; j=1 Γaj (2.1) 1 + p ψq 1 ≤ M1 + Q q . p ψq (|bj + βj |, βj )1,q ; (|bj |, βj )1,q ; 1−α j=1 Γbj Proof. Since Qp Qp ∞ X Γ[aj + αj (n − 1)]z n j=1 Γaj Qq j=1 z{p ψq (z)} = Qq z+ j=1 Γbj j=1 Γ[bj + βj (n − 1)](n − 1)! n=2 so by virtue of Lemma 1.1, we need only to show that Qp ∞ X Q j=1 Γ[aj + αj (n − 1)] (2.2) [(3 − α)n − 2] q ≤ (1 − α)M1 . j=1 Γ[bj + βj (n − 1)](n − 1)! n=2 J. Inequal. Pure and Appl. Math., 9(1) (2008), Art. 30, 6 pp. http://jipam.vu.edu.au/ U NIFORMLY S TARLIKE AND U NIFORMLY C ONVEX F UNCTIONS 3 Now, we have Qp Γ[a + α (n − 1)] j j Q j=1 [(3 − α)n − 2] q Γ[b + β (n − 1)](n − 1)! j j j=1 n=2 Qp ∞ X Γ[a + α (n + 1)] j j j=1 = [(3 − α)(n + 2) − 2] Qq Γ[b + β (n + 1)](n + 1)! j j j=1 n=0 Qp ∞ X Q j=1 Γ[(aj + αj ) + nαj ] = (3 − α) q Γ[(b + β ) + nβ ]n! j j j j=1 n=0 " ∞ Qp # Qp X j=1 Γ(aj + αj n) 1 Γa j j=1 + (1 − α) Qq − Qq Γ(b + β n) n! j j j=1 j=1 Γbj n=0 (|aj + αj |, αj )1,p ; = (3 − α) p ψq 1 (|bj + βj |, βj )1,q ; Qp (|aj |, αj )1,p ; j=1 Γaj + (1 − α) p ψq 1 − (1 − α) Qq (|bj |, βj )1,q ; j=1 Γbj ∞ X ≤ (1 − α)M1 which in view of Lemma 1.1 gives the desired result. Theorem 2.2. If q X bj > j=1 p X aj + 1, aj > 0 and 1+ j=1 q X βj > j=1 p X αj , j=1 then a sufficient condition for the function z{p ψq (z)} to be in the class U ST N (α), 0 ≤ α < 1, is: Qp 3−α (aj + αj , αj )1,p ; (aj , αj )1,p ; j=1 Γaj 1 + p ψq 1 ≤ M1 + Q q . p ψq (bj + βj , βj )1,q ; (bj , βj )1,q ; 1−α j=1 Γbj Proof. The proof of Theorem 2.2 is a direct consequence of Theorem 2.1. Theorem 2.3. If q X bj > j=1 p X aj + 2, aj > 0 j=1 and 1+ q X j=1 βj > p X αj , j=1 then a sufficient condition for the function z{p ψq (z)} to be in the class U CV (α), 0 ≤ α < 1, is (2.3) (1 + α) p ψq (aj + 2αj , αj )1,p ; 1 (bj + 2βj , βj )1,q ; Qp (aj + αj , αj )1,p ; j=1 Γaj + (2α + 3) p ψq 1 + p ψq (1) ≤ M2 + Qq . (bj + βj , βj )1,q ; j=1 Γbj Proof. By virtue of Lemma 1.2, it suffices to prove that Qp ∞ X j=1 Γ[aj + αj (n − 1)] (2.4) n[(α + 1)n − α] Qq ≤ M2 . j=1 Γ[bj + βj (n − 1)](n − 1)! n=2 J. Inequal. Pure and Appl. Math., 9(1) (2008), Art. 30, 6 pp. http://jipam.vu.edu.au/ 4 V.B.L. C HAURASIA AND A MBER S RIVASTAVA Now, we have (2.5) ∞ X Qp Γ[aj + αj (n − 1)] j=1 Γ[bj + βj (n − 1)](n − 1)! n=2 Qp Qp ∞ ∞ X X j=1 Γ(aj + αj n) j=1 Γ(aj + αj n) 2 = (1 + α) (n + 1) Qq −α (n + 1) Qq . Γ[(b + β n)n! Γ(b + β n)n! j j j j j=1 j=1 n=1 n=1 n[(α + 1)n − α] Qq j=1 Using (n + 1)2 = n(n + 1) + (n + 1), (2.5) may be expressed as Qp Qp ∞ ∞ X X j=1 Γ(aj + αj n) j=1 Γ(aj + αj n) (n + 1) Qq (2.6) (1 + α) + (n + 1) Qq j=1 Γ(bj + βj n)(n − 1)! j=1 Γ(bj + βj n)n! n=1 n=1 Q Q p p ∞ ∞ X X Γ[(aj + αj ) + αj n] j=1 Γ(aj + αj n) Qq Qqj=1 = (1 + α) + (2α + 3) j=1 Γ(bj + βj n)(n − 2)! j=1 Γ[(bj + βj ) + βj n]n! n=0 n=2 Q p ∞ X Γ(aj + αj n) Qqj=1 + j=1 Γ(bj + βj n)n! n=1 (aj + αj , αj )1,p ; (aj + 2αj , αj )1,p ; 1 = (1 + α) p ψq 1 + (2α + 3) p ψq (bj + 2βj , βj )1,q ; (bj + βj , βj )1,q ; Qp j=1 Γaj + p ψq (1) − Qq , j=1 Γbj which is bounded above by M2 if and only if (2.3) holds. Hence the theorem is proved. 3. A N I NTEGRAL O PERATOR In this section we obtain sufficient conditions for the function Z z (aj , αj )1,p ; z = p φq p ψq (x)dx (bj , βj )1,q ; 0 to be in the classes U ST and U CV . Theorem 3.1. If q X bj > j=1 p X aj , aj > 0 j=1 q X βj > j=1 p X αj , j=1 Rz to be in the class U ST is Qp Qp Γ(a − α ) j j (aj − αj , αj )1,p ; j=1 j=1 Γaj 3 p ψq (1) − 2 p ψq 1 + 2 Qq ≤ M1 + Q q . (bj − βj , βj )1,q ; j=1 Γ(bj − βj ) j=1 Γbj then a sufficient condition for the function p φq (z) = (3.1) 1+ and ψ (x)dx 0 p q Proof. Since Z (3.2) p φq (z) = 0 z Qp ∞ Qp X Γ[(aj − αj ) + αj n] z n j=1 Γaj Qj=1 z+ , p ψq (x)dx = Qq q j=1 Γbj j=1 Γ[(bj − βj ) + βj n] n! n=2 J. Inequal. Pure and Appl. Math., 9(1) (2008), Art. 30, 6 pp. http://jipam.vu.edu.au/ U NIFORMLY S TARLIKE AND U NIFORMLY C ONVEX F UNCTIONS 5 we have (3.3) Qp j=1 Γ[(aj − αj ) + αj n] (3n − 2) Qq j=1 Γ[(bj − βj ) + βj n]n! n=2 " ∞ Qp ∞ Qp X X Γ(a + α n) Γ[(aj − αj ) + αj n] j j Qqj=1 Qqj=1 =3 −2 j=1 Γ(bj + βj n)n! j=1 Γ[(bj − βj ) + βj n]n! n=1 n=0 # Qp Qp Γ(a − α ) Γa j j j j=1 j=1 − Qq − Qq j=1 Γ(bj − βj ) j=1 Γbj Qp Qp Γ(a − α ) j j (aj − αj , αj )1,p ; j=1 j=1 Γaj = 3 p ψq (1) − 2 p ψq 1 + 2 Qq − Qq . (bj − βj , βj )1,q ; j=1 Γ(bj − βj ) j=1 Γbj ∞ X In view of Lemma 1.1, (3.3) leads to the result (3.1). Theorem 3.2. If q X j=1 bj > p X aj , aj > 0 1+ and j=1 q X j=1 βj > p X αj , j=1 Rz then a sufficient condition for the function p φq (z) = 0 p ψq (x)dx to be in the class U CV is Qp (aj + αj , αj )1,p ; j=1 Γaj (3.4) 1 + p ψq (1) ≤ M2 + Qq . p ψq (bj + βj , βj )1,q ; j=1 Γbj Proof. Since p φq (z) has the form (3.2), then Qp ∞ X j=1 Γ[(aj − αj ) + αj n] 2 (3.5) n Qq j=1 Γ[(bj − βj ) + βj n]n! n=2 Qp ∞ X j=1 Γ(aj + αj n) = (n + 1) Qq j=1 Γ(bj + βj n)n! n=1 Q Qp p ∞ ∞ Qp X X j=1 Γ[(aj + αj ) + αj n] j=1 Γ(aj + αj n) j=1 Γaj Qq Qq = + − Qq j=1 Γ[(bj + βj ) + βj n]n! j=1 Γ(bj + βj n)n! j=1 Γbj n=0 n=0 Qp (aj + αj , αj )1,p ; j=1 Γaj = p ψq 1 + p ψq (1) − Qq , (bj + βj , βj )1,q ; j=1 Γbj which in view of Lemma 1.2 gives the desired result (3.4). 4. PARTICULAR C ASES 4.1. By setting α1 = α2 = · · · = αp = 1; β1 = β2 = · · · = βq = 1 and Qp j=1 Γaj M1 = M2 = M3 = Q q , j=1 Γbj Theorems 2.1, 2.3, 3.1 and 3.2 reduce to the results recently obtained by Shanmugam, Ramachandran, Sivasubramanian and Gangadharan [11]. 4.2. By specifying the parameters suitably, the results of this paper readily yield the results due to Dixit and Verma [1]. J. Inequal. Pure and Appl. Math., 9(1) (2008), Art. 30, 6 pp. http://jipam.vu.edu.au/ 6 V.B.L. 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