NEW RESULT IN THE ULTIMATE BOUNDEDNESS OF SOLUTIONS OF A THIRD-ORDER NONLINEAR ORDINARY DIFFERENTIAL EQUATION Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 M.O. OMEIKE Department of Mathematics University of Agriculture Abeokuta, Nigeria. Title Page Contents EMail: moomeike@yahoo.com Received: 26 March, 2007 Accepted: 15 January, 2008 Communicated by: S.S. Dragomir 2000 AMS Sub. Class.: Primary: 34C11; Secondary: 34B15. Key words: Differential equations of third order, Boundedness. Abstract: Sufficient conditions are established for the ultimate boundedness of solutions of certain third-order nonlinear differential equations. Our result improves on Tunc’s [C. Tunc, Boundedness of solutions of a third-order nonlinear differential equation, J. Inequal. Pure and Appl. Math., 6(1) Art. 3,2005,1-6]. Acknowledgements: The author would like to express sincere thanks to the anonymous referees for their invaluable corrections, comments and suggestions. JJ II J I Page 1 of 15 Go Back Full Screen Close Contents 1 Introduction 3 2 Preliminaries 6 3 Proof of Theorem 1.1 13 Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 Title Page Contents JJ II J I Page 2 of 15 Go Back Full Screen Close 1. Introduction We consider the third-order nonlinear ordinary differential equation, ... x + f (x, ẋ, ẍ)ẍ + g(x, ẋ) + h(x, ẋ, ẍ) = p(t, x, ẋ, ẍ) (1.1) or its equivalent system (1.2) ẋ = y, ẏ = z, ż = −f (x, y, z)z − g(x, y) − h(x, y, z) + p(t, x, y, z), Ultimate Boundedness of Solutions M.O. Omeike where f, g, h and p are continuous in their respective arguments, and the dots denote differentiation with respect to t. The derivatives ∂f (x, y, z) ≡ fx (x, y, z), ∂x ∂h(x, y, z) ≡ hy (x, y, z), ∂y ∂f (x, y, z) ∂h(x, y, z) ≡ fz (x, y, z), ≡ hx (x, y, z), ∂z ∂x ∂h(x, y, z) ∂g(x, y) ≡ hz (x, y, z) and ≡ gx (x, y) ∂z ∂x exist and are continuous. Moreover, the existence and the uniqueness of solutions of (1.1) will be assumed. It is well known that the ultimate boundedness is a very important problem in the theory and applications of differential equations, and an effective method for studying the ultimate boundedness of nonlinear differential equations is still the Lyapunov’s direct method (see [1] – [8]). Recently, Tunc [7] discussed the ultimate boundedness results of Eq. (1.1) and the following result was proved. Theorem A (Tunc [7]). Further to the assumptions on the functions f, g, h and p assume the following conditions are satisfied (a, b, c, l, m and A− some positive constants): (i) f (x, y, z) ≥ a and ab − c > 0 for all x, y, z; vol. 9, iss. 1, art. 15, 2008 Title Page Contents JJ II J I Page 3 of 15 Go Back Full Screen Close (ii) (iii) g(x,y) y ≥ b for all x, y 6= 0; h(x,0,0) x ≥ c for all x 6= 0; (iv) 0 < hx (x, y, 0) < c, for all x, y; (v) hy (x, y, 0) ≥ 0 for all x, y; Ultimate Boundedness of Solutions (vi) hz (x, y, 0) ≥ m for all x, y; (vii) yfx (x, y, z) ≤ 0, yfz (x, y, z) ≥ 0 and gx (x, y) ≤ 0 for all x, y, z; M.O. Omeike vol. 9, iss. 1, art. 15, 2008 (viii) yzhy (x, y, 0) + ayzhz (x, y, z) ≥ 0 for all x, y, z; (ix) |p(t, x, y, z)| ≤ e(t) for all t ≥ 0, x, y, z, Rt where 0 e(s)ds ≤ A < ∞. Title Page Contents Then, given any finite numbers x0 , y0 , z0 there is a finite constant D = D(x0 , y0 , z0 ) such that the unique solution (x(t), y(t), z(t)) of (1.2) which is determined by the initial conditions JJ II J I Page 4 of 15 x(0) = x0 , y(0) = y0 , z(0) = z0 |x(t)| ≤ D, |y(t)| ≤ D, |z(t)| ≤ D satisfies for all t ≥ 0. Theoretically, this is a very interesting result since (1.1) is a rather general thirdorder nonlinear differential equation. For example, many third order differential equations which have been discussed in [5] are special cases of Eq. (1.1), and some known results can be obtained by using this theorem. However, it is not easy to apply Go Back Full Screen Close Theorem A to these special cases to obtain new or better results since Theorem A has some hypotheses which are not necessary for the stability of many nonlinear equations. The Lyapunov function used in the proof of Theorem A is not complete (see [2]). Furthermore, the boundedness result considered in [7] is of the type in which the bounding constant depends on the solution in question. Our aim in this paper is to further study the boundedness of solutions of Eq. (1.1). In the next section, we establish a criterion for the ultimate boundedness of solutions of Eq. (1.1), which extends and improves Theorem A. Our main result is the following theorem. Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 Theorem 1.1. Further to the basic assumptions on the functions f, g, h and p assume that the following conditions are satisfied (a, b, c, ν and A− some positive constants): Title Page Contents (i) f (x, y, z) > a and ab − c > 0 for all x, y, z; (ii) (iii) g(x,y) y ≥ b for all x, y 6= 0; h(x,y,z) x ≥ ν for all x 6= 0; (v) yfx (x, y, z) ≤ 0, yfz (x, y, z) ≥ 0 and gx (x, y) ≤ 0 for all x, y, z; (vi) |p(t, x, y, z)| ≤ A < ∞ for all t ≥ 0. J I |ẋ(t)| ≤ D, Go Back Full Screen Close Then every solution x(t) of (1.1) satisfies |x(t)| ≤ D, II Page 5 of 15 (iv) hx (x, 0, 0) ≤ c, hy (x, y, 0) ≥ 0 and hz (x, 0, z) ≥ 0 for all x, y, z; (1.3) JJ |ẍ(t)| ≤ D for all sufficiently large t, where D is a constant depending only on a, b, c, A and ν. 2. Preliminaries It is convenient here to consider, in place of the equation (1.1), the system (1.2). It is to be shown then, in order to prove the theorem, that, under the conditions stated in the theorem, every solution (x(t), y(t), z(t)) of (1.2) satisfies |x(t)| ≤ D, (2.1) |y(t)| ≤ D, |z(t)| ≤ D for all sufficiently large t, where D is the constant in (1.3). Our proof of (2.1) rests entirely on two properties (stated in the lemma below) of the function V = V (x, y, z) defined by Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 V = V1 + V2 , (2.2) where V1 , V2 are given by Z x Z h(ξ, 0, 0)dξ + 2 (2.3a) 2V1 = 2 0 Title Page y Z ηf (x, η, 0)dη + 2δ 0 Contents y g(x, η)dη 0 2 2 + δz + 2yz + 2δyh(x, 0, 0) − αβy , 2 Z x Z y (2.3b) 2V2 = αβbx + 2a h(ξ, 0, 0)dξ + 2a ηf (x, η, 0)dη 0 0 Z y +2 g(x, η)dη + z 2 + 2aαβxy + 2αβxz + 2ayz + 2yh(x, 0, 0), JJ II J I Page 6 of 15 Go Back Full Screen 0 where 1 a < δ < cb , and α, β are some positive constants such that ab − c 1 aδ − 1 ν(aδ − 1) α < min 2 ; a ; abδ ; β[f (x, y, z) − a]2 β a + ν −1 g(x,y) −b y Close and β will be fixed to advantage later. Lemma 2.1. Subject to the conditions of Theorem 1.1, V (0, 0, 0) = 0 and there is a positive constant D1 depending only on a, b, c, α and δ such that V (x, y, z) ≥ D1 (x2 + y 2 + z 2 ) (2.4) for all x, y, z. Furthermore, there are finite constants D2 > 0, D3 > 0 dependent only on a, b, c, A, ν, δ, and α such that for any solution (x(t), y(t), z(t)) of (1.2), M.O. Omeike d V̇ ≡ V (x(t), y(t), z(t)) ≤ −D2 , dt (2.5) Ultimate Boundedness of Solutions vol. 9, iss. 1, art. 15, 2008 provided that x2 + y 2 + z 2 ≥ D3 . Title Page Proof of Lemma 2.1. To verify (2.4) observe first that the expressions (2.3) defining 2V1 , 2V2 may be rewritten in the forms Z x 2 δ 2 h(x, 0, 0) 2V1 = 2 h(ξ, 0, 0)dξ − h (x, 0, 0) + δb y + b b 0 Z y + 2 ηf (x, η, 0)dη − δ −1 y 2 − αβy 2 + δ(z + δ −1 y)2 0 Z y 2 +δ 2 g(x, η)dη − by 0 Contents JJ II J I Page 7 of 15 Go Back Full Screen Close and Z 2V2 = αβ(b − αβ)x + a 2 x h (x, 0, 0) −1 2 2 h(ξ, 0, 0)dξ − β n 1 o2 Z y −2 −1 12 −1 2 + β a y + β a h(x, 0, 0) + 2 g(x, η)dη − βa y 0 0 Z +a 2 y ηf (x, η, 0)dη − ay 2 + (αβx + ay + z)2 . 0 The term 2 equal to Rx 0 h(ξ, 0, 0)dξ − δb h2 (x, 0, 0) in the rearrangement for 2V1 is evidently Z 2 0 x δ δ 1 − hξ (ξ, 0, 0) h(ξ, 0, 0)dξ − h2 (0, 0, 0). b b By conditions (iii) and (iv) of Theorem 1.1 and h(0, 0, 0) = 0, we have Z x δ 2 δ δ 2 1 − hξ (ξ, 0, 0) h(ξ, 0, 0)dξ − h (0, 0, 0) ≥ 1 − c νx2 . b b b 0 In the same way, using (iii) and (iv), it can be shown that the term Z x −1 2 2 h(ξ, 0, 0)dξ − β h (x, 0, 0) 0 appearing in the rearrangement for 2V2 satisfies Z x c −1 2 2 h(ξ, 0, 0)dξ − β h (x, 0, 0) ≥ 1 − νx2 , β 0 for all x. Since h(x,y,z) ≥ ν (x 6= 0), g(x,y) ≥ b, (y 6= 0) and f (x, y, z) > a, and x y combining all these with (2.2), we have δ c x2 2V ≥ ν 1 − c + αβ(b − αβ) + aν 1 − b β 2 β 1 1 2 + a − − αβ + b − y + δ z + y + (αβx + ay + z)2 δ a δ Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 Title Page Contents JJ II J I Page 8 of 15 Go Back Full Screen Close for all x, y and z. Hence if we choose β = ab the constants 1 − δb c, b − αβ, 1 − βc , a − 1δ − αβ and b − βa are either zero or positive. This implies that there exists a constant D1 small enough such that (2.4) holds. To deal with the other half of the lemma, let (x(t), y(t), z(t)) be any solution of (1.2) and consider the function V (t) ≡ V (x(t), y(t), z(t)) . By an elementary calculation using (1.2), (2.2) and (2.3), we have that Z y Z y (2.6) V̇ = (1 + δ)y gx (x, η)dη + (1 + a)y ηfx (x, η, 0)dη 0 By (v), we get y Z gx (x, η)dη ≤ 0, y 0 M.O. Omeike vol. 9, iss. 1, art. 15, 2008 0 {f (x, y, z) − f (x, y, 0)} 2 {h(x, y, z) − h(x, 0, 0)} 2 yz − (1 + a) y − (1 + a) z y h(x, y, z) 2 g(x, y) 2 {h(x, y, z) − h(x, 0, 0)} 2 − (1 + δ) z − αβ x − y z x y g(x, y) 2 −a y + δhx (x, 0, 0)y 2 + hx (x, 0, 0)y 2 + aαβy 2 y g(x, y) 2 2 2 − δf (x, y, z)z − [f (x, y, z) − a]z + z − αβ − b xy y − αβ{f (x, y, z) − a}xz + {αβx + (1 + a)y + (1 + δ)z}p(t, x, y, z). Z Ultimate Boundedness of Solutions Contents JJ II J I Page 9 of 15 Go Back Full Screen Close y fx (x, η, 0)ηdη ≤ 0. y Title Page 0 It follows from (v), for z 6= 0 that {f (x, y, z) − f (x, y, 0)} 2 W1 = a yz = afz (x, y, θ1 z)yz 2 ≥ 0, z 0 ≤ θ1 ≤ 1 but W1 = 0 when z = 0. Hence W1 ≥ 0 for all x, y, z. Similarly, it is clear that W2 = {h(x, y, z) − h(x, 0, 0)} 2 y = hy (x, θ2 y, 0)y 2 ≥ 0, y 0 ≤ θ2 ≤ 1 but W2 = 0 when y = 0. Hence Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 W2 ≥ 0 f or all x, y. Also, {h(x, y, z) − h(x, 0, 0)} 2 W3 = z = hz (x, 0, θ3 z)z 2 ≥ 0, z 0 ≤ θ3 ≤ 1 but W3 = 0 when z = 0. Hence W3 ≥ 0 for all x, z. Then, combining the estimates W1 , W2 , W3 and (iii) with (2.6) we obtain V̇ ≤ −αβνx2 − (ab − c − αβa)y 2 − (b − δc)y 2 − (aδ − 1)z 2 g(x, y) 2 − az − αβ − b xy − αβ{f (x, y, z) − a}xz y + {αβx + (1 + a)y + (1 + δ)z}p(t, x, y, z) ( " 2 #) 1 g(x, y) −b y2 = − αβνx2 − ab − c − αβ a + ν −1 2 y − (b − δc)y 2 − aδ − 1 − αβν −1 [f (x, y, z) − a]2 z 2 − az 2 Title Page Contents JJ II J I Page 10 of 15 Go Back Full Screen Close 1 − αβν 4 ( ) 2 g(x, y) 2 x + 2ν −1 − b y + x + 2ν −1 (f (x, y, z) − a)z y + {αβx + (1 + a)y + (1 + δ)z}p(t, x, y, z). If we choose α < min ab − c ν(aδ − 1) 1 aδ − 1 ; ; , ; 2 a abδ β[f (x, y, z) − a]2 g(x,y) −1 β a + ν −b y it follows that Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 Title Page 1 V̇ ≤ − αβνx2 − (b − δc)y 2 − az 2 + {αβx + (1 + a)y + (1 + δ)z}p(t, x, y, z) 2 ≤ −D4 (x2 + y 2 + z 2 ) + D5 (|x| + |y| + |z|), where D4 = min 1 αβν; b − δc; a , 2 Contents JJ II J I Page 11 of 15 D5 = A max{αβ; 1 + a; 1 + δ}. Go Back Moreover, Full Screen 1 2 V̇ ≤ −D4 (x2 + y 2 + z 2 ) + D6 (x2 + y 2 + z 2 ) , (2.7) 1 where D6 = 3 2 D5 . 1 If we choose (x2 + y 2 + z 2 ) 2 ≥ D7 = 2D6 D4−1 , inequality (2.7) implies that 1 V̇ ≤ − D4 (x2 + y 2 + z 2 ). 2 Close We see at once that V̇ ≤ −D8 , provided that x2 + y 2 + z 2 ≥ 2D8 D4−1 ; and this completes the verification of (2.5). Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 Title Page Contents JJ II J I Page 12 of 15 Go Back Full Screen Close 3. Proof of Theorem 1.1 Let (x(t), y(t), z(t)) be any solution of (1.2). Then there is evidently a t0 ≥ 0 such that x2 (t0 ) + y 2 (t0 ) + z 2 (t0 ) < D3 , where D3 is the constant in the lemma; for otherwise, that is if 2 2 2 x (t) + y (t) + z (t) ≥ D3 , t ≥ 0, Ultimate Boundedness of Solutions M.O. Omeike then, by (2.5), vol. 9, iss. 1, art. 15, 2008 V̇ (t) ≤ −D2 < 0, t ≥ 0, and this in turn implies that V (t) → −∞ as t → ∞, which contradicts (2.4). Hence to prove (1.3) it will suffice to show that if (3.1) 2 2 2 x (t) + y (t) + z (t) < D9 for t = T, where D9 ≥ D3 is a finite constant, then there is a constant D10 > 0, depending on a, b, c, δ, α and D9 , such that Title Page Contents JJ II J I Page 13 of 15 (3.2) 2 2 2 x (t) + y (t) + z (t) ≤ D10 for t ≥ T. Our proof of (3.2) is based essentially on an extension of an argument in the proof of [8, Lemma 1]. For any given constant d > 0 let S(d) denote the surface: x2 +y 2 + z 2 = d. Because V is continuous in x, y, z and tends to +∞ as x2 + y 2 + z 2 → ∞, there is evidently a constant D11 > 0, depending on D9 as well as on a, b, c, δ and α, such that (3.3) min (x,y,z)∈S(D11 ) V (x, y, z) > max (x,y,z)∈S(D9 ) V (x, y, z). Go Back Full Screen Close It is easy to see from (3.1) and (3.3) that (3.4) x2 (t) + y 2 (t) + z 2 (t) < D11 t ≥ T. for For suppose on the contrary that there is a t > T such that x2 (t) + y 2 (t) + z 2 (t) ≥ D11 . Then, by (3.1) and by the continuity of the quantities x(t), y(t), z(t) in the argument displayed, there exist t1 , t2 , T < t1 < t2 such that (3.5a) x2 (t1 ) + y 2 (t1 ) + z 2 (t1 ) = D9 , Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 (3.5b) x2 (t2 ) + y 2 (t2 ) + z 2 (t2 ) = D11 Title Page and such that (3.6) D9 ≤ x2 (t) + y 2 (t) + z 2 (t) ≤ D11 , Contents t1 ≤ t ≤ t2 . But, writing V (t) ≡ V (x(t), y(t), z(t)) , since D9 ≥ D3 , (3.6) obviously implies [in view of (2.5)] that V (t2 ) < V (t1 ) and this contradicts the conclusion [from (3.3) and (3.5)]: JJ II J I Page 14 of 15 V (t2 ) > V (t1 ). Go Back Hence (3.4) holds. This completes the proof of (1.3), and the theorem now follows. Remark 1. Clearly, our theorem is an improvement and extension of Theorem A. In particular, from our theorem we see that (viii) assumed in Theorem A is not necessary, and (iv) and (ix) can be replaced by hx (x, 0, 0) ≤ c and (vi) of Theorem 1.1 respectively, for the ultimate boundedness of the solutions of Eq. (1.1). Remark 2. Clearly, unlike in [7], the bounding constant D in Theorem 1.1 does not depend on the solution of (1.1). Full Screen Close References [1] H. BEREKETOGLU AND I. GYORI, On the boundedness of the solutions of a third-order nonlinear differential equation, Dynam. Systems Appl., 6(2) (1997), 263–270. [2] E.N. CHUKWU, On the boundedness of solutions of third order differential equations, Ann. Mat. Pur. Appl., 104(4) (1975), 123–149. [3] J.O.C. EZEILO, An elementary proof of a boundedness theorem for a certain third order differential equation, J. Lond. Math. Soc., 38 (1963), 11–16. [4] J.O.C. EZEILO, A further result on the existence of periodic solutions of the ... equation x + Ψ(ẋ)ẍ + φ(x)ẋ + v(x, ẋ, ẍ) = p(t) with a bound ν, Atti. Accad. Naz. Lincei Rend. Cl. Sci. Fis. Mat. Natur., 55 (1978), 51–57. [5] R. REISSSIG, G. SANSONE AND R. CONTI, Nonlinear Differential Equations of Higher Order, Noordhoff, Groningen, 1974. [6] K.E. SWICK, Boundedness and stability for a nonlinear third order differential equation, Atti. Accad. Naz. Lincei Rend. Cl. Sci. Fis. Mat. Natur., 56(6) (1974), 859–865. [7] C. TUNC, Boundedness of solutions of a third-order nonlinear differential equation, J. Inequal. Pure and Appl. Math., 6(1) (2005), Art. 3. [ONLINE: http://jipam.vu.edu.au/article.php?sid=472]. [8] T. YOSHIZAWA, On the evaluation of the derivatives of solutions of y” = f (x, y, x0 ), Mem. Coll. Sci., Univ. Kyoto Ser. A. Math., 28 (1953), 27–32. (1953), 133–141. Ultimate Boundedness of Solutions M.O. Omeike vol. 9, iss. 1, art. 15, 2008 Title Page Contents JJ II J I Page 15 of 15 Go Back Full Screen Close