Journal of Inequalities in Pure and Applied Mathematics ON SOME APPROXIMATE FUNCTIONAL RELATIONS STEMMING FROM ORTHOGONALITY PRESERVING PROPERTY volume 7, issue 3, article 85, 2006. JACEK CHMIELIŃSKI Instytut Matematyki, Akademia Pedagogiczna w Krakowie Podchora̧żych 2, 30-084 Kraków, Poland Received 17 January, 2006; accepted 24 February, 2006. Communicated by: K. Nikodem EMail: jacek@ap.krakow.pl Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 015-06 Quit Abstract Referring to previous papers on orthogonality preserving mappings we deal with some relations, connected with orthogonality, which are preserved exactly or approximately. In particular, we investigate the class of mappings approximately preserving the right-angle. We show some properties similar to those characterizing mappings which exactly preserve the right-angle. Besides, some kind of stability of the considered property is established. We study also the property that a particular value c of the inner product is preserved. We compare the case c 6= 0 with c = 0, i.e., with orthogonality preserving property. Also here some stability results are given. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński 2000 Mathematics Subject Classification: 39B52, 39B82, 47H14. Key words: Orthogonality preserving mappings, Right-angle preserving mappings, Preservation of the inner product, Stability of functional equations. Contents 1 2 Prerequisites . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 Additivity of Approximately Right-angle Preserving Mappings . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7 3 Approximate Right-angle Preserving Mappings are Approximate Similarities . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 18 4 Some Stability Problems . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 23 5 On Mappings Preserving a Particular Value of the Inner Product . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 27 References Title Page Contents JJ J II I Go Back Close Quit Page 2 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au 1. Prerequisites Let X and Y be real inner product spaces with the standard orthogonality relation ⊥. For a mapping f : X → Y it is natural to consider the orthogonality preserving property: ∀x, y ∈ X : x⊥y ⇒ f (x)⊥f (y). (OP) The class of solutions of (OP) contains also very irregular mappings (cf. [1, Examples 1 and 2]). On the other hand, a linear solution f of (OP) has to be a linear similarity, i.e., it satisfies (cf. [1, Theorem 1]) kf (x)k = γkxk, (1.1) x∈X On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński or, equivalently, (1.2) hf (x)|f (y)i = γ 2 hx|yi , x, y ∈ X with some γ ≥ 0 (γ > 0 for f 6= 0). (More generally, a linear mapping between real normed spaces which preserves the Birkhoff-James orthogonality has to satisfy (1.1) – see [5].) Therefore, linear orthogonality preserving mappings are not far from inner product preserving mappings (linear isometries), i.e., solutions of the functional equation: Title Page Contents JJ J II I Go Back ∀x, y ∈ X : hf (x)|f (y)i = hx|yi . Close A property similar to (OP) was introduced by Kestelman and Tissier (see [6]). One says that f has the right-angle preserving property iff: Quit (1.3) (RAP) ∀x, y, z ∈ X : x − z⊥y − z ⇒ f (x) − f (z)⊥f (y) − f (z). Page 3 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au For the solutions of (RAP) it is known (see [6]) that they must be affine, continuous similarities (with respect to some point). It is easily seen that if f satisfies (RAP) then, for an arbitrary y0 ∈ Y , the mapping f + y0 satisfies (RAP) as well. In particular, f0 := f − f (0) satisfies (RAP) and f0 (0) = 0. Summing up we have: Theorem 1.1. The following conditions are equivalent: (i) f satisfies (RAP) and f (0) = 0; (ii) f satisfies (OP) and f is continuous and linear; (iii) f satisfies (OP) and f is linear; (iv) f is linear and satisfies (1.1) for some constant γ ≥ 0; (v) f satisfies (1.2) for some constant γ ≥ 0; (vi) f satisfies (OP) and f is additive. Proof. (i)⇒(ii) follows from [6] (see above); (ii)⇒(iii) is trivial; (iii)⇒(iv) follows from [1] (see above); (iv)⇒(v) by use of the polarization formula and (v)⇒(vi)⇒(i) is trivial. In particular, one can consider a real vector space X with two inner products h·|·i1 and h·|·i2 and f = id|X a linear and continuous mapping between (X, h·|·i1 ) and (X, h·|·i2 ). Then we obtain from Theorem 1.1: On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 4 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Corollary 1.2. Let X be a real vector space equipped with two inner products h·|·i1 and h·|·i2 generating the norms k · k1 , k · k2 and orthogonality relations ⊥1 , ⊥2 , respectively. Then the following conditions are equivalent: (i) ∀x, y, z ∈ X : x − z⊥1 y − z ⇒ x − z⊥2 y − z; (ii) ∀x, y ∈ X : x⊥1 y ⇒ x⊥2 y; (iii) kxk2 = γkxk1 for x ∈ X with some constant γ > 0; (iv) hx|yi2 = γ 2 hx|yi1 for x, y ∈ X with some constant γ > 0; (v) ∀x, y, z ∈ X : x − z⊥1 y − z ⇔ x − z⊥2 y − z; (vi) ∀x, y ∈ X : x⊥1 y ⇔ x⊥2 y. For ε ∈ [0, 1) we define an ε-orthogonality by ε u⊥ v :⇔ | hu|vi | ≤ εkukkvk. (Some remarks on how to extend this definition to normed or semi-inner product spaces can be found in [2].) Then, it is natural to consider an approximate orthogonality preserving (a.o.p.) property: (ε-OP) ∀x, y ∈ X : x⊥y ⇒ f (x)⊥ε f (y) and the approximate right-angle preserving (a.r.a.p.) property: (ε-RAP) ∀x, y, z ∈ X : x − z⊥y − z ⇒ f (x) − f (z)⊥ε f (y) − f (z). On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 5 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au The class of linear mappings satisfying (ε-OP) has been considered by the author (cf. [1, 3]). In the present paper we are going to deal with mappings satisfying (ε-RAP) and, in the last section, with mappings which preserve (exactly or approximately) a given value of the inner product. We will deal also with some stability problems. (For basic facts concerning the background and main results in the theory of stability of functional equations we refer to [4].) The following result establishing the stability of equation (1.3) has been proved in [3] and will be used later on. Theorem 1.3 ([3], Theorem 2). Let X and Y be inner product spaces and let X be finite-dimensional. Then, there exists a continuous mapping δ : R+ → R+ such that limε→0+ δ(ε) = 0 which satisfies the following property: For each mapping f : X → Y (not necessarily linear) satisfying (1.4) | hf (x)|f (y)i − hx|yi | ≤ εkxkkyk, x, y ∈ X there exists a linear isometry I : X → Y such that kf (x) − I(x)k ≤ δ(ε)kxk, On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents x ∈ X. JJ J II I Go Back Close Quit Page 6 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au 2. Additivity of Approximately Right-angle Preserving Mappings Tissier [6] showed that a mapping f satisfying the (RAP) property has to be additive up to a constant f (0). Following his idea we will show that a.r.a.p. mappings are, in some sense, quasi-additive. We start with the following lemma. Lemma 2.1. Let X be a real inner product space. Let a set of points a, b, c, d, e ∈ X satisfies the following relations, with ε ∈ [0, 18 ), (2.1) a − b⊥ε c − b, b − c⊥ε d − c, c − d⊥ε a − d, d − a⊥ε b − a; On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński (2.2) a − e⊥ε b − e, b − e⊥ε c − e, c − e⊥ε d − e, d − e⊥ε a − e. Title Page Then, with δ := a + c ≤ δka − ck e − 2 q 3ε . 1−4ε Proof. We have Contents JJ J II I Go Back Close kc − ek2 = ke − a + a − ck2 = ke − ak2 + ka − ck2 + 2 he − a|a − ci whence kc − ek2 − ka − ek2 − ka − ck2 he − a|a − ci = . 2 Quit Page 7 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Thus 2 2 e − a + c = e − a + a − c 2 2 1 = ke − ak2 + ka − ck2 + he − a|a − ci 4 1 1 1 1 = ke − ak2 + ka − ck2 + kc − ek2 − ka − ek2 − ka − ck2 4 2 2 2 1 1 1 = ka − ek2 + kc − ek2 − ka − ck2 . 2 2 4 Finally, (2.3) 2 a + c = 1 2ka − ek2 + 2kc − ek2 − ka − ck2 e − 2 4 and, analogously, 2 b + d e − = 1 2kb − ek2 + 2kd − ek2 − kb − dk2 . (2.4) 2 4 Adding the equalities: ka − bk2 kb − ck2 kc − dk2 kd − ak2 = ka − e + e − bk2 = ka − ek2 + ke − bk2 + 2 ha − e|e − bi , = kb − e + e − ck2 = kb − ek2 + ke − ck2 + 2 hb − e|e − ci , = kc − e + e − dk2 = kc − ek2 + ke − dk2 + 2 hc − e|e − di , = kd − e + e − ak2 = kd − ek2 + ke − ak2 + 2 hd − e|e − ai On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 8 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au one gets (2.5) ka − bk2 + kb − ck2 + kc − dk2 + kd − ak2 = 2ka − ek2 + 2kb − ek2 + 2kc − ek2 + 2kd − ek2 + 2 ha − e|e − bi + 2 hb − e|e − ci + 2 hc − e|e − di + 2 hd − e|e − ai . Similarly, adding ka − ck2 ka − ck2 kb − dk2 kb − dk2 = ka − b + b − ck2 = ka − bk2 + kb − ck2 + 2 ha − b|b − ci , = ka − d + d − ck2 = ka − dk2 + kd − ck2 + 2 ha − d|d − ci , = kb − a + a − dk2 = kb − ak2 + ka − dk2 + 2 hb − a|a − di , = kb − c + c − dk2 = kb − ck2 + kc − dk2 + 2 hb − c|c − di On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page one gets (2.6) ka − ck2 + kb − dk2 = ka − bk2 + ka − dk2 + kc − bk2 + kc − dk2 + ha − b|b − ci + ha − d|d − ci + hb − a|a − di + hb − c|c − di . Using (2.3) – (2.6) we derive 2 2 a + c b + d e − + e − 2 2 Contents JJ J II I Go Back Close Quit Page 9 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au (2.3),(2.4) = 2ka − ek2 + 2kc − ek2 + 2kb − ek2 + 2kd − ek2 − ka − ck2 − kb − dk2 4 1 kb − ck2 + kc − dk2 + kd − ak2 + ka − bk2 4 − 2 hb − e|e − ci − 2 hc − e|e − di − 2 hd − e|e − ai − 2 ha − e|e − bi − ka − ck2 − kb − dk2 1 (2.6) = − ha − b|b − ci + ha − d|d − ci + hb − a|a − di + hb − c|c − di 4 + 2 hb − e|e − ci + 2 hc − e|e − di + 2 hd − e|e − ai + 2 ha − e|e − bi . (2.5) = Thus 2 2 e − a + c + e − b + d 2 2 1 ≤ | ha − b|b − ci | + | ha − d|d − ci | + | hb − a|a − di | 4 + | hb − c|c − di | + 2| hb − e|e − ci | + 2| hc − e|e − di | + 2| hd − e|e − ai | + 2| ha − e|e − bi | . Using the assumptions (2.1) and (2.2), we obtain 2 2 a + c b + d + e − e − (2.7) 2 2 1 ≤ ε ka − bkkb − ck + ka − dkkd − ck + kb − akka − dk 4 + kb − ckkc − dk + 2kb − ekke − ck + 2kc − ekke − dk On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 10 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au + 2kd − ekke − ak + 2ka − ekke − bk 1 = ε (kb − ck + ka − dk)(ka − bk + kc − dk) 4 + 2(kb − ek + kd − ek)(ka − ek + kc − ek) . Notice, that for ε = 0, (2.7) yields e = Let a+c 2 = b+d . 2 % := max{ka − bk, kb − ck, kc − dk, kd − ak, ka − ek, kb − ek, kc − ek, kd − ek}. It follows from (2.7) that 2 2 e − a + c + e − b + d ≤ 1 ε(2% · 2% + 2 · 2% · 2%) = 3ε%2 . 2 2 4 Jacek Chmieliński Title Page Contents Then, in particular (2.8) On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property 2 e − a + c ≤ 3ε%2 . 2 JJ J II I Go Back Since we do not know for which distance the value % is attained, we are going to consider a few cases. 1. % ∈ {ka − bk, kb − ck, kc − dk, kd − ak}. Close Quit Page 11 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Suppose that % = ka−bk (other possibilities in this case are similar). Then ka − ck2 = ka − b + b − ck2 = ka − bk2 + kb − ck2 + 2 ha − b|b − ci ≥ %2 + 0 − 2εka − bkkb − ck ≥ %2 − 2ε%2 = (1 − 2ε)%2 . Assuming ε < 21 , %2 ≤ 1 ka − ck2 . 1 − 2ε On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Using (2.8) we have Jacek Chmieliński 2 a + c e − ≤ 3ε ka − ck2 2 1 − 2ε whence (2.9) Title Page Contents r a + c 3ε e − ≤ ka − ck. 2 1 − 2ε II I Go Back 2. % ∈ {ka − ek, kc − ek}. Suppose that % = ka − ek (the other possibility (2.3), we have 2 1 a + c = 1 ka − ek2 + ka − ck2 + e − 4 2 2 JJ J is similar). Then, from Close Quit 1 1 kc − ek2 ≥ %2 , 2 2 Page 12 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au whence 2 1 a + c 2 . % ≤ ka − ck + 2 e − 2 2 2 From it and (2.8) we get 2 2 a + c 3ε a + c 2 2 e − ≤ 3ε% ≤ ka − ck + 6ε e − 2 2 2 whence (assuming ε < 16 ) (2.10) s 3ε a + c e − ≤ ka − ck. 2(1 − 6ε) 2 3. % ∈ {kb − ek, kd − ek}. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Suppose that % = kb − ek (the other possibility is similar). We have then kb − ak2 = kb − e + e − ak2 = kb − ek2 + ke − ak2 + 2 hb − e|e − ai ≥ %2 + 0 − 2εkb − ekke − ak ≥ %2 − 2ε%2 = (1 − 2ε)%2 , whence kb − ak2 ≥ (1 − 2ε)%2 . Contents JJ J II I Go Back Close Quit Page 13 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Using this estimation we have ka − ck2 = ka − b + b − ck2 = ka − bk2 + kb − ck2 + 2 ha − b|b − ci ≥ (1 − 2ε)%2 + 0 − 2εka − bkkb − ck ≥ (1 − 2ε)%2 − 2ε%2 = (1 − 4ε)%2 , whence (for ε < 41 ) %2 ≤ On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property 1 ka − ck2 . 1 − 4ε Using (2.8) we get 2 a + c ≤ 3ε%2 ≤ 3ε ka − ck2 e − 2 1 − 4ε Jacek Chmieliński and JJ J Title Page Contents r a + c 3ε e − ≤ ka − ck. 2 1 − 4ε (2.11) Finally, assuming ε < (r max 1 , 8 Go Back we have 3ε , 1 − 2ε s 3ε , 2(1 − 6ε) II I Close r 3ε 1 − 4ε ) r = Quit 3ε 1 − 4ε Page 14 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au and it follows from (2.9) – (2.11) r a + c 3ε ≤ e − ka − ck, 2 1 − 4ε which completes the proof. Theorem 2.2. Let X and Y be real inner product spaces and let f : X → Y satisfy (ε-RAP) with ε < 18 . Then f satisfies x+y f (x) + f (y) ≤ δkf (x) − f (y)k for x, y ∈ X (2.12) f − 2 2 q 3ε . with δ = 1−4ε for Jacek Chmieliński Title Page Contents Moreover, if additionally f (0) = 0, then f satisfies (ε-OP) and (2.13) kf (x + y) − f (x) − f (y)k ≤ 2δ(kf (x + y)k + kf (x) − f (y)k), On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property x, y ∈ X. JJ J II I Go Back Proof. Fix arbitrarily x, y ∈ X. The case x = y is obvious. Assume x 6= y. Choose u, v ∈ X such that x, u, y, v are consecutive vertices of a square with the center at x+y . Denote 2 x+y a := f (x), b := f (u), c := f (y), d := f (v), e := f . 2 Close Quit Page 15 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Since x−u⊥y −u, u−y⊥v −y, y −v⊥x−v, v −x⊥u−x and x− x+y ⊥u− x+y , 2 2 x+y x+y x+y x+y x+y x+y u − 2 ⊥y − 2 , y − 2 ⊥v − 2 , v − 2 ⊥x − 2 , it follows from (ε-RAP) that the conditions (2.1) and (2.2) are satisfied. The assertion of Lemma 2.1 yields (2.12). For the second assertion, it is obvious that f satisfies (ε-OP). Inequality (2.13) follows from (2.12). Indeed, putting y = 0 we get x f (x) f ≤ δkf (x)k, − x ∈ X. 2 2 Now, for x, y ∈ X kf (x+y) − f (x) − f (y)k f (x + y) x + y x + y f (x) + f (y) = 2 − f + f − 2 2 2 2 f (x + y) x+y x+y f (x) + f (y) ≤ 2 −f − + 2 f 2 2 2 2 ≤ 2δkf (x + y)k + 2δkf (x) − f (y)k. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back For ε = 0 we obtain that if f satisfies (RAP) and f (0) = 0, then f is additive. The following, reverse in a sense, statement is easily seen. Lemma 2.3. If f satisfies (ε-OP) and f is additive, then f satisfies (ε-RAP) and f (0) = 0. Close Quit Page 16 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Example 2 in [1] shows that it is not possible to omit completely the additivity assumption in the above lemma. However, the problem arises if additivity can be replaced by a weaker condition (e.g. by (2.13)). This problem remains open. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 17 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au 3. Approximate Right-angle Preserving Mappings are Approximate Similarities As we know from [6], a right-angle preserving mappings are similarities. Our aim is to show that a.r.a.p. mappings behave similarly. We start with a technical lemma. Lemma 3.1. Let a, x ∈ X and ε ∈ [0, 1). Then (a − x)⊥ε (−a − x) (3.1) if and only if q 2ε 2 2 (3.2) kxk − kak ≤ √ kak2 kxk2 − ha|xi2 . 2 1−ε Moreover, it follows from (3.1) that r r 1−ε 1+ε (3.3) kak ≤ kxk ≤ kak. 1+ε 1−ε Proof. The condition (3.1) is equivalent to: | ha + x|a − xi | ≤ εka + xkka − xk, p p kak2 − kxk2 ≤ ε kak2 + 2 ha|xi + kxk2 kak2 − 2 ha|xi + kxk2 , kak2 − kxk2 2 ≤ ε2 (kak2 + kxk2 + 2 ha|xi)(kak2 + kxk2 − 2 ha|xi) = ε2 (kak2 + kxk2 )2 − 4 ha|xi2 = ε2 (kak2 − kxk2 )2 + 4kak2 kxk2 − 4 ha|xi2 , On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 18 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au and finally (1 − ε2 )(kak2 − kxk2 )2 ≤ 4ε2 kak2 kxk2 − ha|xi2 which is equivalent to (3.2). Inequality (3.2) implies kxk2 − kak2 ≤ √ 2ε kakkxk, 1 − ε2 which yields kxk kak 2ε kak − kxk ≤ √1 − ε2 (3.4) (we assume x 6= 0 and a 6= 0, otherwise the assertion of the lemma is trivial). 2ε Denoting t := kxk > 0 and α := √1−ε 2 , the inequality (3.4) can be written in kak the form |t − t−1 | ≤ α with a solution −α + √ 2 α2 + 4 ≤t≤ α+ √ α2 + 4 . 2 On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Therefore, r 1−ε kxk ≤ ≤ 1+ε kak r 1+ε 1−ε Quit Page 19 of 33 whence (3.3) is satisfied. J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Theorem 3.2. If f : X → Y is homogeneous and satisfies (ε-RAP), then with some k ≥ 0: 3 3 1−ε 2 1+ε 2 (3.5) k· kxk ≤ kf (x)k ≤ k · kxk, x ∈ X. 1+ε 1−ε Proof. 1. For arbitrary x, y ∈ X we have kxk = kyk ⇔ x − y⊥ − x − y. It follows from (ε-RAP) and the oddness of f that kxk = kyk ⇒ f (x) − f (y)⊥ε − f (x) − f (y). On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Lemma 3.1 yields r 1−ε kf (x)k ≤ kf (y)k ≤ 1+ε r 1+ε kf (x)k. 1−ε 2. Fix arbitrarily x0 = 6 0 and define for r ≥ 0, ϕ(r) := f kxr0 k x0 . Using (3.6) we have r r 1−ε 1+ε kxk = r ⇒ ϕ(r) ≤ kf (x)k ≤ ϕ(r), 1+ε 1−ε (3.6) kxk = kyk ⇒ Contents JJ J II I Go Back Close Quit whence r (3.7) Title Page 1−ε ϕ(kxk) ≤ kf (x)k ≤ 1+ε r 1+ε ϕ(kxk), 1−ε Page 20 of 33 x ∈ X. J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au 3. For t ≥ 0 and kxk = r we have # "r r 1−ε 1+ε kf (tx)k ∈ ϕ(tr), ϕ(tr) 1+ε 1−ε and "r tkf (x)k ∈ 1−ε tϕ(r), 1+ε r # 1+ε tϕ(r) . 1−ε Since kf (tx)k = tkf (x)k (homogeneity of f ), # # "r "r r r 1+ε 1−ε 1+ε 1−ε tϕ(r) 6= ∅. tϕ(r), ϕ(tr) ∩ ϕ(tr), 1−ε 1+ε 1−ε 1+ε Thus there exist λ, µ ∈ hq 1−ε , 1+ε q 1+ε 1−ε i such that λϕ(tr) = µtϕ(r), whence 1−ε 1+ε tϕ(r) ≤ ϕ(tr) ≤ tϕ(r). 1+ε 1−ε In particular, for r = 1 and k := ϕ(1) we get (3.8) 1−ε 1+ε kt ≤ ϕ(t) ≤ kt, 1+ε 1−ε On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back t ≥ 0. 4. Using (3.7) and (3.8), we get r r 1+ε 1+ε 1+ε kf (x)k ≤ ϕ(kxk) ≤ · kkxk 1−ε 1−ε 1−ε Close Quit Page 21 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au and r kf (x)k ≥ 1−ε ϕ(kxk) ≥ 1+ε r 1−ε 1−ε · kkxk 1+ε 1+ε whence (3.5) is proved. For ε = 0 we get kf (x)k = kkxk for x ∈ X and, from (2.13), f is additive hence linear. Thus f is a similarity. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 22 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au 4. Some Stability Problems The stability of the orthogonality preserving property has been studied in [3]. We present the main result from that paper which will be used in this section. Theorem 4.1 ([3, Theorem 4]). Let X, Y be inner product spaces and let X be finite-dimensional. Then, there exists a continuous function δ : [0, 1) → [0, +∞) with the property limε→0+ δ(ε) = 0 such that for each linear mapping f : X → Y satisfying (ε-OP) one finds a linear, orthogonality preserving one T : X → Y such that kf − T k ≤ δ(ε) min{kf k, kT k}. The mapping δ depends, actually, only on the dimension of X. Immediately, we have from the above theorem: Corollary 4.2. Let X, Y be inner product spaces and let X be finite-dimensional. Then, for each δ > 0 there exists ε > 0 such that for each linear mapping f : X → Y satisfying ( ε-OP) one finds a linear, orthogonality preserving one T : X → Y such that kf − T k ≤ δ min{kf k, kT k}. We start our considerations with the following observation. Proposition 4.3. Let f : X → Y satisfy (RAP) and f (0) = 0. Suppose that g : X → Y satisfies kf (x) − g(x)k ≤ M kf (x)k, x∈X On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 23 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au (M +2) with some constant M < 14 . Then g satisfies (ε-OP) with ε := M(1−M and )2 √ (4.1) kg(x + y) − g(x) − g(y)k ≤ 2 ε(kg(x)k + kg(y)k), x, y ∈ X; √ (4.2) kg(λx) − λg(x)k ≤ 2 ε|λ|kg(x)k, x ∈ X, λ ∈ R. Proof. It follows from Theorem 1.1 that for some γ ≥ 0, f satisfies (1.2) and (1.1). Thus we have for arbitrary x, y ∈ X: | hg(x)|g(y)i − γ 2 hx|yi | = | hg(x) − f (x)|g(y) − f (y)i + hg(x) − f (x)|f (y)i + hf (x)|g(y) − f (y)i | ≤ kg(x) − f (x)kkg(y) − f (y)k + kg(x) − f (x)kkf (y)k + kf (x)kkg(y) − f (y)k 2 ≤ M kf (x)kkf (y)k + M kf (x)kkf (y)k + M kf (x)kkf (y)k = M (M + 2)γ 2 kxkkyk. Using [1, Lemma 2], we get, for arbitrary x, y ∈ X, λ ∈ R: p kg(x + y) − g(x) − g(y)k ≤ 2 M (M + 2)γ(kxk + kyk) p = 2 M (M + 2)(kf (x)k + kf (y)k); p kg(λx) − λg(x)k ≤ 2 M (M + 2)γ|λ|kxk p = 2 M (M + 2)|λ|kf (x)k. Since kf (x)k − kg(x)k ≤ M kf (x)k, kg(x)k kf (x)k ≤ . 1−M On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 24 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Therefore | hg(x)|g(y)i − γ 2 hx|yi | ≤ Putting ε := M (M + 2) kg(x)kkg(y)k. (1 − M )2 M (M +2) (1−M )2 we have x⊥y ⇒ g(x)⊥ε g(y) and √ kg(x + y) − g(x) − g(y)k ≤ 2 ε(kg(x)k + kg(y)k) √ kg(λx) − λg(x)k ≤ 2 ε|λ|kg(x)k. Corollary 4.4. If f satisfies (RAP), f (0) = 0 (whence f is linear) and g : X → Y is a linear mapping satisfying, with M < 14 , (4.3) On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński kf − gk ≤ M kf k, then g is (ε-OP) (and linear) whence (ε-RAP). Title Page The above result yields a natural question if the reverse statement is true. Namely, we may ask if for a linear mapping g : X → Y satisfying (ε-RAP) (with some ε > 0) there exists a (linear) mapping f satisfying (RAP) such that an estimation of the (4.3) type holds. A particular solution to this problem follows easily from Theorem 4.1. Contents Theorem 4.5. Let X be a finite-dimensional inner product space and Y an arbitrary one. There exists a mapping δ : [0, 1) → R+ satisfying limε→0+ δ(ε) = 0 and such that for each linear mapping satisfying (ε-RAP) g : X → Y there exists f : X → Y satisfying (RAP) and such that (4.4) JJ J II I Go Back Close Quit Page 25 of 33 kf − gk ≤ δ(ε) min{kf k, kgk}. J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Proof. If g is linear and satisfies (ε-RAP), then g is linear and satisfies (ε-OP). It follows then from Theorem 4.1 that there exists f linear and satisfying (OP), whence (RAP), such that (4.4) holds. Corollary 4.6. Let X be a finite-dimensional inner product space and Y an arbitrary one. Then, for each δ > 0 there exists ε > 0 such that for each linear and satisfying (ε-RAP) mapping g : X → Y there exists f : X → Y satisfying (RAP) and such that kf − gk ≤ δ min{kf k, kgk}. It is an open problem to verify if the above result remains true in the infinite dimensional case or without the linearity assumption. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 26 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au 5. On Mappings Preserving a Particular Value of the Inner Product The following considerations have been inspired by a question of L. Reich during the 43rd ISFE. In this section X and Y are inner product spaces over the field K of real or complex numbers. Let f : X → Y and suppose that, for a fixed number c ∈ K, f preserves this particular value of the inner product, i.e., (5.1) ∀x, y ∈ X : hx|yi = c ⇒ hf (x)|f (y)i = c. If c = 0, the condition (5.1) simply means that f preserves orthogonality, i.e., that f satisfies (OP). We will show that the solutions of (5.1) behave differently for c = 0 and for c 6= 0. Obviously, if f satisfies (1.3) then f also satisfies (5.1), with an arbitrary c. The converse is not true, neither with c = 0 (cf. examples mentioned in the Introduction) nor with c 6= 0. Indeed, if c > 0, then fixing x0 ∈ X such that kx0 k2 = c, a constant mapping f (x) = x0 , x ∈ X satisfies (5.1) but not (1.3). Another example: let X = Y = C and let 0 6= c ∈ C. Define c f (z) := , z z ∈ C \ {0}; f (0) := 0. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Then, for z, w ∈ C \ {0} Quit hf (z)|f (w)i = |c|2 Page 27 of 33 hz|wi J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au and, in particular, if hz|wi = c, then hf (z)|f (w)i = c. Thus f satisfies (5.1) but not (1.3). Let us restrict our investigations to the class of linear mappings. As we will see below (Corollary 5.2), a linear solution of (5.1), with c 6= 0, satisfies (1.3). Let us discuss a stability problem. For fixed 0 6= c ∈ K and ε ≥ 0 we consider the condition (5.2) ∀x, y ∈ X : hx|yi = c ⇒ | hf (x)|f (y)i − c| ≤ ε. Theorem 5.1. For a finite-dimensional inner product space X and an arbitrary inner product space Y there exists a continuous mapping δ : R+ → R+ satisfying limε→0+ δ(ε) = 0 and such that for each linear mapping f : X → Y satisfying (5.2) there exists a linear isometry I : X → Y such that kf − Ik ≤ δ(ε). Proof. Let 0 6= d ∈ K. If hx|yi = d, then dc x|y = c and hence, using (5.2) |c| and homogeneity of f , |d| | hf (x)|f (y)i − d| ≤ ε. Therefore we have (for d 6= 0) (5.3) hx|yi = d ⇒ | hf (x)|f (y)i − d| ≤ |d| ε. |c| Now, let d = 0. Let 0 D 6= dn ∈ K and E limn→∞ dn = 0. Suppose that hx|yi = dn y d = 0 and y 6= 0. Then x + kyk2 |y = dn and thus, from (5.3) and linearity of f, |dn | d n f (x) + ≤ f (y)|f (y) − d ε. n kyk2 |c| On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 28 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Letting n → ∞ we obtain hf (x)|f (y)i = 0. For y = 0 the latter equality is obvious. Summing up, we obtain that | hf (x)|f (y)i − hx|yi | ≤ | hx|yi | ε |c| whence also (5.4) | hf (x)|f (y)i − hx|yi | ≤ ε kxkkyk. |c| Let δ 0 : R+ → R+ be a mapping from the assertion of Theorem 1.3. Define δ(ε) := δ 0 (ε/|c|) and notice that limε→0+ δ(ε) = 0. Then it follows from (5.4) that there exists a linear isometry I : X → Y such that ε 0 kf − Ik ≤ δ = δ(ε). |c| For ε = 0 we obtain from the above result (we can omit the assumption concerning the dimension of X in this case, considering a subspace spanned on given vectors x, y ∈ X): Corollary 5.2. Let f : X → Y be linear and satisfy (5.1), with some 0 6= c ∈ K. Then f satisfies (1.3). On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back Close Quit Page 29 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Notice that for c = 0, the condition (5.2) has the form hx|yi = 0 ⇒ | hf (x)|f (y)i | ≤ ε. If hx|yi = 0, then also hnx|yi = 0 for all n ∈ N. Thus | hf (nx)|f (y)i | ≤ ε, whence | hf (x)|f (y)i | ≤ nε for n ∈ N. Letting n → ∞ one gets ∀x, y ∈ X : hx|yi = 0 ⇒ hf (x)|f (y)i = 0, i.e, f is a linear, orthogonality preserving mapping. Now, let us replace the condition (5.2) by (5.5) ∀x, y ∈ X : hx|yi = c ⇒ | hf (x)|f (y)i − c| ≤ εkf (x)kkf (y)k. For c = 0, (5.5) states that f satisfies (ε-OP). Let us consider the class of linear mappings satisfying (5.5) with c 6= 0. We proceed similarly as in the proof of Theorem 5.1. Let 0 6= d ∈ K. If hx|yi = d, then dc x|y = c and hence, using (5.5) and homogeneity of f , we obtain |c| |c| | hf (x)|f (y)i − d| ≤ ε kf (x)kkf (y)k. |d| |d| Therefore we have (for d 6= 0) On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I hx|yi = d ⇒ | hf (x)|f (y)i − d| ≤ εkf (x)kkf (y)k. Go Back Now, suppose D E that hx|yi = d = 0. Let 0 6= dn ∈ K and limn→∞ dn = 0. Then dn y x + kyk2 |y = dn and thus, from (5.6) and linearity of f , d d n n ≤ ε f (x) + kf (y)k. f (x) + f (y)|f (y) − d f (y) n kyk2 kyk2 Close (5.6) Quit Page 30 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au Letting n → ∞ we obtain | hf (x)|f (y)i | ≤ εkf (x)kkf (y)k. So we have hx|yi = 0 ⇒ | hf (x)|f (y)i | ≤ εkf (x)kkf (y)k. Summing up, we obtain that (5.7) | hf (x)|f (y)i − hx|yi | ≤ εkf (x)kkf (y)k, Putting in the above inequality x = y we get kf (x)k ≤ gives ε | hf (x)|f (y)i − hx|yi | ≤ kxkkyk, 1−ε ε i.e., f satisfies (1.4) with the constant 1−ε . Therefore, applying Theorem 1.3, we get x, y ∈ X. kxk √ 1−ε for x ∈ X, which x, y ∈ X, Theorem 5.3. If X is a finite-dimensional inner product space and Y an arbitrary inner product space, then there exists a continuous mapping δ : R+ → R+ with limε→0+ δ(ε) = 0 such that for a linear mapping f : X → Y satisfying (5.5), with c 6= 0, there exists a linear isometry I : X → Y such that kf − Ik ≤ δ(ε). On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents JJ J II I Go Back A converse theorem is also true, even with no restrictions concerning the dimension of X. Let I : X → Y be a linear isometry and f : X → Y a mapping, not necessarily linear, such that Close Quit Page 31 of 33 kf (x) − I(x)k ≤ δkxk, x∈X J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au q with δ = 1+2ε − 1 (for a given ε ≥ 0). Reasoning similarly as in the proof of 1+ε Proposition 4.3 one can show that | hf (x)|f (y)i − hx|yi | ≤ δ(δ + 2)kxkkyk, which implies 1 kxk ≤ p 1 − δ(δ + 2) kf (x)k and finally δ(δ + 2) kf (x)kkf (y)k 1 − δ(δ + 2) = εkf (x)kkf (y)k. |hf (x)|f (y)i − hx|yi| ≤ Thus f satisfies (5.5) with an arbitrary c. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents Remark 1. From Theorems 5.1 and 5.3 one can derive immediately the stability results formulated as in Corollaries 4.2 and 4.6. JJ J II I Go Back Close Quit Page 32 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au References [1] J. CHMIELIŃSKI, Linear mappings approximately preserving orthogonality, J. Math. Anal. Appl., 304 (2005), 158–169. [2] J. CHMIELIŃSKI, On an ε-Birkhoff orthogonality, J. Inequal. Pure Appl. Math., 6(3) (2005), Art. 79, 7pp. [ONLINE: http://jipam.vu.edu. au/article.php?sid=552]. [3] J. CHMIELIŃSKI, Stability of the orthogonality preserving property in finite-dimensional inner product spaces, J. Math. Anal. Appl., 318 (2006), 433–443. [4] D.H. HYERS, G. ISAC AND Th.M. RASSIAS, Stability of Functional Equations in Several Variables, Progress in Nonlinear Differential Equations and Their Applications vol. 34, Birkhäuser, Boston-Basel-Berlin, 1998. On Some Approximate Functional Relations Stemming from Orthogonality Preserving Property Jacek Chmieliński Title Page Contents [5] A. KOLDOBSKY, Operators preserving orthogonality are isometries, Proc. Roy. Soc. Edinburgh Sect. A, 123 (1993), 835–837. [6] A. TISSIER, A right-angle preserving mapping (a solution of a problem proposed in 1983 by H. Kestelman), Advanced Problem 6436, Amer. Math. Monthly, 92 (1985), 291–292. JJ J II I Go Back Close Quit Page 33 of 33 J. Ineq. Pure and Appl. Math. 7(3) Art. 85, 2006 http://jipam.vu.edu.au