Journal of Inequalities in Pure and Applied Mathematics http://jipam.vu.edu.au/ Volume 7, Issue 3, Article 87, 2006 AN INEQUALITY FOR THE CLASS NUMBER OLIVIER BORDELLÈS 2 ALLÉE DE LA COMBE , LA B ORIETTE 43000 AIGUILHE FRANCE borde43@wanadoo.fr Received 05 October, 2005; accepted 10 March, 2006 Communicated by J. Sándor A BSTRACT. We prove in an elementary way a new inequality for the average order of the Piltz divisor function with application to class number of number fields. Key words and phrases: Piltz divisor function, Class number. 2000 Mathematics Subject Classification. 11N99, 11R29. 1. I NTRODUCTION It could be interesting to use tools from analytic number theory to solve problems of algebraic number theory. For example, let K be a number field of degree n, signature (r1 , r2 ), class number hK , regulator RK , and wK is the number of roots of unity in K, ζK the Dedekind zeta 1/2 function, AK := 2−r2 π −n/2 dK where dK is the absolute value of the discriminant of K. The following formula, valid for any real number σ > 1, σ (1.1) AσK Γr1 Γr2 (σ) ζK (σ) 2 n o XZ 1−σ 2r1 hK RK dy = + kykσ/2 + kyk 2 e−g(a,y) , σ (σ − 1) wK a6=0 kyk≥1 y where g (a, y) is a certain function depending on a nonzero integral ideal a and vector y := (y1 , . . . , yr1 +r2 ) ∈ (R+ )r1 +r2 (here kyk := max |yi |), is the generalization of the well-known formula ∞ Z ∞n σ o X 1−σ 1 2 dy −σ/2 σ/2 2 π Γ ζ (σ) = + y +y e−πn y 2 σ (σ − 1) n=1 1 y for the classical Riemann zeta function. Since the integrand in (1.1) is positive, we get σ (1.2) hK RK ≤ σ (σ − 1) wK 2−r1 AσK Γr1 Γr2 (σ) ζK (σ) 2 ISSN (electronic): 1443-5756 c 2006 Victoria University. All rights reserved. I would like to thank my wife Véronique for her help. 307-05 2 O LIVIER B ORDELLÈS for any real number σ > 1. The study of the function on the right-hand side of (1.2) provides upper bounds for hK RK (see [3] for example) . In a more elementary way, one can connect the class number hK with the Piltz divisor function τn by using the following result ([1]): Lemma 1.1. Let bK > 0 be a real number such that every class of ideals of K contains a nonzero integral ideal with norm ≤ bK . If τn is the Piltz divisor function, then: X hK ≤ τn (m) . m≤bK P Recall that τn is defined by the relations τ1 (m) = m and τn (m) = d|m τn−1 (d) (n ≥ 2). This function has been studied by many authors (see [6] for a good survey of its properties). A standard argument from analytic number theory gives if n ≥ 4 n−1 X τn (m) = xPn−1 (log x) + Oε x n+2 +ε , m≤x 1 where Pn−1 is a polynomial of degree n − 1 and leading coefficient (n−1)! . For some improvements of the error term and related results, see [4]. Note that the Lindelöf Hypothesis is equivalent to αn = (n − 1) / (2n) for any n = 2, 3, . . . where αn is the least number such that X τn (m) − xPn−1 (log x) = Oε xαn +ε . m≤x If we are interested in finding upper bounds of the form X τn (m) n x (log x)n−1 , m≤x one mostly uses arguments based upon induction and the following inequality: P Lemma 1.2. We set Sn (x) := m≤x τn (m) . Then: Z x Sn+1 (x) ≤ Sn (x) + x t−2 Sn (t) dt. 1 Proof. It suffices to use the definition above, interchange the summations and integrate by parts. Using this lemma, it is easy to show by induction the following bound: X x (log x + n − 1)n−1 τn (m) ≤ (n − 1)! m≤x which enables us to obtain Lenstra’s bound again (see [2]), namely: (1.3) hK ≤ bK (log bK + n − 1)n−1 . (n − 1)! In what follows, n is a positive integer and we set X Sn (x) := τn (m) m≤x for any real number x ≥ 1. bK is a positive real number always satisfying the hypothesis of Lemma 1.1. K is a number field of degree n and class number hK . dK is the absolute value of J. Inequal. Pure and Appl. Math., 7(3) Art. 87, 2006 http://jipam.vu.edu.au/ A N I NEQUALITY FOR THE C LASS N UMBER 3 the discriminant of K. For some tables giving values of bK , see [7]. The functions ψ and ψ2 are defined by 1 ψ (t) = t − [t] − , 2 Z t 1 ψ 2 (t) ψ2 (t) = ψ (u) du + = , 8 2 0 where [t] denotes the integral part of t. Recall that we have for all real numbers t : 1 |ψ (t)| ≤ , 2 1 0 ≤ ψ2 (t) ≤ . 8 We denote by γ and γ1 the Euler-Mascheroni constant and the first Stieltjes constant, defined respectively by: ! n X 1 γ = lim − log n , n→∞ k k=1 ! n X log k (log n)2 − . γ1 = lim n→∞ k 2 k=1 The following results are well-known (see [5] for example): 0.577215 < γ < 0.577216, −0.072816 < γ1 < −0.072815, and 1 γ = −2 2 (1.4) Z 1 ∞ ψ2 (t) dt t3 and ∞ Z (1.5) γ1 = − 1 2 log t − 3 ψ2 (t) dt. t3 2. R ESULTS Theorem 2.1. Let n ≥ 3 be an integer. For any real number x ≥ 13, we have: X x τn (m) ≤ (log x + n − 2)n−1 . (n − 1)! m≤x Applying this result with Lemma 1.1 allows us to improve upon (1.3) : Theorem 2.2. Let K be a number field of degree n ≥ 3. If bK ≥ 13 satisfies the hypothesis of Lemma 1.1, then: bK hK ≤ (log bK + n − 2)n−1 . (n − 1)! J. Inequal. Pure and Appl. Math., 7(3) Art. 87, 2006 http://jipam.vu.edu.au/ 4 O LIVIER B ORDELLÈS 3. T HE C ASE n = 3 The aim of this section is to show that the result of Theorem 2.1 is true for n = 3. Hence we will prove the following inequality for S3 : Lemma 3.1. For any real number x ≥ 13, we have: S3 (x) ≤ x (log x + 1)2 . 2 We first check this result for 13 ≤ x ≤ 670 with the PARI/GP system [8], and then suppose x > 670. The lemma will be a direct consequence of the following estimation: Lemma 3.2. For any real number x > 670, we have: ) ( (log x)2 2 + (3γ − 1) log x + 3γ − 3γ − 3γ1 + 1 + R (x) S3 (x) = x 2 where: |R (x)| ≤ 2.36 x2/3 log x. The proof of this lemma needs some technical results: Lemma 3.3. Let x, y ≥ 1 be real numbers. (i) If e3/2 ≤ y ≤ x, then we have: X1 k≤y k log x k (log y)2 = log x log y − + γ log x − γ1 + R1 (x, y) 2 with: |R1 (x, y)| ≤ log (x/y) log x + . 2y 4y 2 (ii) S2 (y) = y log y + (2γ − 1) y + R2 (y) with: 1 |R2 (y)| ≤ y 1/2 + . 2 (iii) X τ (n) n≤y n = (log y)2 + 2γ log y + γ 2 − 2γ1 + R3 (y) 2 with: |R3 (y)| ≤ J. Inequal. Pure and Appl. Math., 7(3) Art. 87, 2006 1 y 1/2 1 + . y http://jipam.vu.edu.au/ A N I NEQUALITY FOR THE C LASS N UMBER 5 Proof. (i) By the Euler-MacLaurin summation formula, we get: x X1 log k k k≤y Z y x log x 1 ψ (y) x = + log dt − log 2 t y y 1 t Z y x ψ2 (y) 2 log (x/t) + 3 − log + 1 − ψ2 (t) dt y2 y t3 1 Z ∞ (log y)2 1 ψ2 (t) = log x log y − + −2 dt log x 2 2 t3 1 Z ∞ 2 log t − 3 ψ (y) x ψ2 (y) x + ψ2 (t) dt − log − log +1 t3 y y y2 y 1 Z ∞ Z ∞ ψ2 (t) 2 log t − 3 + 2 log x dt − ψ2 (t) dt 3 t t3 y y and using (1.4) and (1.5) we get: x X1 (log y)2 log = log x log y − + γ log x − γ1 + R1 (x, y) k k 2 k≤y and since e3/2 ≤ y ≤ x, we have: log (x/y) log (x/y) + 1 log x log y − 1 + + + 2y 8y 2 8y 2 8y 2 log (x/y) log x = + . 2y 4y 2 (ii) This result is well-known (see [1] for example). (iii) Using a result from [5], we have for any real number y ≥ 1 : 3 1 y −3/2 y −2 1 1 −1/2 −1 −1/2 −y − + y − − ≤ R3 (y) ≤ y + + y −1 4 8e3 8 64 2 8e3 |R1 (x, y)| ≤ which concludes the proof of Lemma 3.3. Proof of Lemmas 3.1 and 3.2. The Dirichlet hyperbola principle and the estimations of Lemma 3.3 give, for any real number e3/2 ≤ T < x: hxi x X x X S3 (x) = S2 + τ (n) − [T ] S2 n n T n≤T n≤x/T x X x X τ (n) 1 x x = log + (2γ − 1) + R4 (x, n) + x − S2 n n n n 2 T n≤T n≤x/T x x 1 x x X − τ (n) ψ − T S2 + S2 + ψ (T ) S2 n T 2 T T n≤x/T X x x x = log + (2γ − 1) + R4 (x, n) n n n n≤T x X τ (n) +x − T S2 + R5 (x, T ) n T n≤x/T J. Inequal. Pure and Appl. Math., 7(3) Art. 87, 2006 http://jipam.vu.edu.au/ 6 O LIVIER B ORDELLÈS with r x 1 + n 2 r x x x x x 1 + |R5 (x, T )| ≤ S2 ≤ log + (2γ − 1) + T 2 T T T T |R4 (x, n)| ≤ and hence: ( S3 (x) = x log x log T − (log T )2 + γ log x 2 o − γ1 + R6 (x, T ) + (2γ − 1) (log T + γ + R7 (T )) ) ( x X (log (x/T ))2 2 + R4 (x, n) + x + 2γ log + γ − 2γ1 + R8 (x, T ) 2 T n≤T x + R5 (x, T ) − x log − (2γ − 1) x − T R9 (x, T ) T with, if e3/2 ≤ T < x : log (x/T ) log x + 2T 4T 2 1 |R7 (T )| ≤ T r T T |R8 (x, T )| ≤ + x x r x 1 |R9 (x, T )| ≤ + T 2 |R6 (x, T )| ≤ and thus: ( S3 (x) = x ) (log x)2 + (3γ − 1) log x + 3γ 2 − 3γ − 3γ1 + 1 2 + xR6 (x, T ) + (2γ − 1) xR7 (T ) + R10 (x, T ) + xR8 (x, T ) + R5 (x, T ) − T R9 (x, T ) with |R10 (x, T )| ≤ X |R4 (x, n)| n≤T √ X 1 T √ + ≤ x 2 n n≤T √ √ T ≤ 2 xT − x + 2 and therefore: ( S3 (x) = x ) (log x)2 + (3γ − 1) log x + 3γ 2 − 3γ − 3γ1 + 1 + R11 (x, T ) 2 J. Inequal. Pure and Appl. Math., 7(3) Art. 87, 2006 http://jipam.vu.edu.au/ A N I NEQUALITY FOR THE C LASS N UMBER 7 with: |R11 (x, T )| ≤ √ √ x log (x/T ) x log x + + 4 xT − x 2 2T 4T r x x 1 2x x + log + 2 (2γ − 1) + + 2T + . T T T T 2 We choose: T = x1/3 , which gives: ( S3 (x) = x ) (log x)2 + (3γ − 1) log x + 3γ 2 − 3γ − 3γ1 + 1 + R12 (x) , 2 where: 5 1 1 |R12 (x)| ≤ x2/3 log x + 2 (2γ + 1) x2/3 − x1/2 + x1/3 log x + 3x1/3 + 3 4 2 2/3 ≤ 2.36 x log x since x > 670. This concludes the proof of Lemma 3.2, and then of Lemma 3.1. 4. P ROOF OF T HEOREM 2.1 We first need the following simple bounds: Lemma 4.1. For any integer n ≥ 3, we have: n Z 13 n3 1 1 −2 t Sn (t) dt < ≤ n+ . 4 n! 2 1 Proof. This follows from straightforward computations which give: Z 13 7 3 2281 2 90283 1 t−2 Sn (t) dt = n + n + n+1− 624 9360 90090 13 1 3 n < 4 since n ≥ 3. The second inequality follows from studying the sequence (un ) defined by un = n3 × n! . 4 (n + 1/2)n We get: n un+1 2 (n + 1)4 2n + 1 = 3 un n (2n + 3) 2n + 3 n 512 2 512e−1 ≤ 1− ≤ <1 243 2n + 3 243 and hence (un ) is decreasing, and thus: un ≤ u3 = which concludes the proof of Lemma 4.1. J. Inequal. Pure and Appl. Math., 7(3) Art. 87, 2006 324 ≤ 1, 343 http://jipam.vu.edu.au/ 8 O LIVIER B ORDELLÈS Proof of Theorem 2.1. We use induction, the result being true for n = 3 by Lemma 3.1. Now suppose the inequality is true for some integer n ≥ 3. By Lemmas 1.2, 4.1 and the induction hypothesis, we get: Sn+1 (x) Z 13 −2 Z x t Sn (t) dt + x t−2 Sn (t) dt ≤ Sn (x) + x 1 13 ( ) n Z x n−1 (log x + n − 2) 1 1 1 (log t + n − 2)n−1 ≤x + n+ + dt (n − 1)! n! 2 (n − 1)! 13 t ( n ) (log x + n − 2)n (log x + n − 2)n−1 1 1 n + + n+ − n + log 13e−2 =x n! (n − 1)! n! 2 x ≤ (log x + n − 2)n + (n − 1) (log x + n − 2)n−1 n! x (log x + n − 1)n . ≤ n! The proof of Theorem 2.1 is now complete. 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[8] PARI/GP, Available by anonymous ftp from: ftp://megrez.math.u-bordeaux.fr/pub/ pari. J. Inequal. Pure and Appl. Math., 7(3) Art. 87, 2006 http://jipam.vu.edu.au/