Journal of Inequalities in Pure and Applied Mathematics ON A HYBRID FAMILY OF SUMMATION INTEGRAL TYPE OPERATORS volume 7, issue 1, article 23, 2006. VIJAY GUPTA AND ESRA ERKUŞ School of Applied Sciences Netaji Subhas Institute of Technology Sector-3, Dwarka New Delhi - 110075, India. EMail: vijaygupta2001@hotmail.com Çanakkale Onsekiz Mart University Faculty of Sciences and Arts Department of Mathematics Terzioğlu Kampüsü 17020, Çanakkale, TURKEY. EMail: erkus@comu.edu.tr Received 21 November, 2005; accepted 01 December, 2005. Communicated by: A. Lupaş Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 343-05 Quit Abstract The present paper deals with the study of the mixed summation integral type operators having Szász and Baskakov basis functions in summation and integration respectively. Here we obtain the rate of point wise convergence, a Voronovskaja type asymptotic formula, an error estimate in simultaneous approximation. We also study some local direct results in terms of modulus of smoothness and modulus of continuity in ordinary and simultaneous approximation. 2000 Mathematics Subject Classification: 41A25; 41A30. Key words: Linear positive operators, Summation-integral type operators, Rate of convergence, Asymptotic formula, Error estimate, Local direct results, K-functional, Modulus of smoothness, Simultaneous approximation. Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 Auxiliary Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5 3 Direct Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7 4 Local Approximation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17 References On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Close Quit Page 2 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au 1. Introduction The mixed summation-integral type operators discussed in this paper are defined as Z ∞ Sn (f, x) = (1.1) Wn (x, t)f (t)dt 0 = (n − 1) ∞ X Z sn,ν (x) ν=1 −nx +e ∞ bn,ν−1 (t)f (t)dt 0 f (0), x ∈ [0, ∞), On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş where Wn (x, t) = (n − 1) ∞ X sn,ν (x)bn,ν−1 (t) + e−nx δ(t), Title Page ν=1 δ(t) being Dirac delta function, Contents sn,ν (x) = e−nx and bn,ν (t) = (nx)ν ν! n+ν−1 ν t (1 + t)−n−ν ν are respectively Szász and Baskakov basis functions. It is easily verified that the operators (1.1) are linear positive operators, these operators were recently proposed by Gupta and Gupta in [3]. The behavior of these operators is very similar to the operators studied by Gupta and Srivastava [5], but the approximation JJ J II I Go Back Close Quit Page 3 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au properties of the operators Sn are different in comparison to the operators studied in [5]. The main difference is that the operators (1.1) are discretely defined at the point zero. Recently Srivastava and Gupta [8] proposed a general family of summation-integral type operators Gn,c (f, x) which include some well known operators (see e.g. [4], [7]) as special cases. The rate of convergence for bounded variation functions was estimated in [8], Ispir and Yuksel [6] considered the Bézier variant of the operators Gn,c (f, x) and studied the rate of convergence for bounded variation functions. We also note here that the results analogous to [6] and [8] cannot be obtained for the mixed operators Sn (f, x) because it is not easier to write the integration of Baskakov basis functions in the summation form of Szász basis functions, which is necessary in the analysis for obtaining the rate of convergence at the point of discontinuity. We propose this as an open problem for the readers. In the present paper we study some direct results, for the class of unbounded functions with growth of order tγ , γ > 0, for the operators Sn we obtain a point wise rate of convergence, asymptotic formula of Voronovskaja type, and an error estimate in simultaneous approximation. We also estimate local direct results in terms of modulus of smoothness and modulus of continuity in ordinary and simultaneous approximation. On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Close Quit Page 4 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au 2. Auxiliary Results We will subsequently need the following lemmas: Lemma 2.1. For m ∈ N0 = N ∪ {0}, if the m-th order moment is defined as Un,m (x) = ∞ X sn,ν (x) ν=0 ν n −x m , then Un,0 (x) = 1, Un,1 (x) = 0 and (1) nUn,m+1 (x) = x Un,m (x) + mUn,m−1 (x) . On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Consequently Un,m (x) = O n −[(m+1)/2] . Lemma 2.2. Let the function µn,m (x), m ∈ N0 , be defined as Z ∞ ∞ X µn,m (x) = (n − 1) sn,ν (x) bn,ν−1 (t)(t − x)m dt + (−x)m e−nx . ν=1 0 Then µn,0 (x) = 1, 2x , µn,1 (x) = n−2 nx(x + 2) + 6x2 µn,2 (x) = , (n − 2)(n − 3) Contents JJ J II I Go Back Close Quit also we have the recurrence relation: (n − m − 2)µn,m+1 (x) = x µ(1) n,m (x) + m(x + 2)µn,m−1 (x) + [m + 2x(m + 1)] µn,m (x); Title Page Page 5 of 23 n > m + 2. J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au Consequently for each x ∈ [0, ∞) we have from this recurrence relation that µn,m (x) = O n−[(m+1)/2] . Remark 1. It is easily verified from Lemma 2.2 that for each x ∈ (0, ∞) (2.1) Sn (ti , x) = (n − i − 2)! (n − i − 2)! (nx)i + i(i − 1) (nx)i−1 + O(n−2 ). (n − 2)! (n − 2)! Lemma 2.3. [5]. There exist the polynomials Qi,j,r (x) independent of n and ν such that X xr Dr [sn,ν (x)] = ni (ν − nx)j Qi,j,r (x)sn,ν (x), On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş 2i+j≤r i,j≥0 Title Page where D ≡ d . dx Lemma 2.4. Let n > r ≥ 1 and f Section 3). Then Contents (i) ∈ CB [0, ∞) for i ∈ {0, 1, 2, . . . , r} (cf. ∞ Sn(r) (f, x) X nr sn,ν (x) = (n − 2) · · · (n − r − 1) ν=0 Z 0 JJ J II I ∞ bn−r,ν+r−1 (t)f (r) (t)dt. Go Back Close Quit Page 6 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au 3. Direct Results In this section we consider the class Cγ [0, ∞) of continuous unbounded functions, defined as f ∈ Cγ [0, ∞) ≡ {f ∈ C[0, ∞) : |f (t)| ≤ M tγ , for some M > 0, γ > 0} . We prove the following direct estimates: Theorem 3.1. Let f ∈ Cγ [0, ∞), γ > 0 and f (r) exists at a point x ∈ (0, ∞), then lim Sn(r) (f (t), x) = f (r) (x). (3.1) n→∞ On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Proof. By Taylor’s expansion of f , we have f (t) = r X f (i) (x) i=0 i! (t − x)i + ε(t, x)(t − x)r , where ε(t, x) → 0 as t → x. Thus, using the above, we have Z ∞ (r) Sn (f, x) = Wn(r) (t, x)f (t)dt 0 = Z r X f (i) (x) i=0 i! Z + ∞ Wn(r) (t, x)(t − x)i dt 0 ∞ Title Page Contents JJ J II I Go Back Close Quit Wn(r) (t, x)ε(t, x)(t − x)r dt Page 7 of 23 0 = R1 + R2 , say. J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au First to estimate R1 , using a binomial expansion of (t − x)m and applying (2.1), we have R1 = r i X f (i) (x) X i i=0 (r) i! ν=0 ν i−ν (−x) ∂r ∂xr ∞ Z Wn (t, x)tν dt 0 (x) d (n − r − 2)!nr r = x + terms containing lower powers of x r! dxr (n − 2)! (n − r − 2)!nr (r) = f (x) → f (r) (x) as n → ∞. (n − 2)! f r Next using Lemma 2.3, we obtain |R2 | ≤ (n − 1) X 2i+j≤r i,j≥0 ∞ X × ν=1 ni On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş |Qi,j,r (x)| xr Title Page Contents |ν − nx|j sn,ν (x) Z ∞ bn,ν−1 (t) |ε(t, x)| (t − x)r dt 0 + (−n)r e−nx |ε(0, x)| (−x)r = R3 + R4 , say. JJ J II I Go Back Close Since ε(t, x) → 0 as t → x for a given ε > 0 there exists a δ > 0 such that |ε(t, x)| < ε whenever 0 < |t − x| < δ. Further if s ≥ max {γ, r}, where s is any integer, then we can find a constant M1 > 0 such that |ε(t, x)(t − x)r | ≤ Quit Page 8 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au M1 |t − x|s , for |t − x| ≥ δ. Thus ∞ X X R3 ≤ M2 (n − 1) ni sn,ν (x) 2i+j≤r ν=1 i,j≥0 Z j × |ν − nx| ε bn,ν−1 (t) |t − x|r dt |t−x|<δ Z s + bn,ν−1 (t)M1 |t − x| dt |t−x|≥δ = R5 + R6 , say. Applying the Schwarz inequality for integration and summation respectively, and using Lemma 2.1 and Lemma 2.2, we obtain ∞ X X i R5 ≤ εM2 (n − 1) n sn,ν (x) ν=1 2i+j≤r i,j≥0 × |ν − nx|j 12 Z ∞ bn,ν−1 (t)dt Z 0 ≤ εM2 X 2i+j≤r ni ∞ X 12 ∞ 2r bn,ν−1 (t)(t − x) dt 0 On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back ! 21 Close sn,ν (x)(ν − nx)2j Quit ν=1 i,j≥0 × (n − 1) ∞ X ν=1 Z ! 21 ∞ bn,ν−1 (t)(t − x) dt sn,ν (x) 0 Page 9 of 23 2r J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au X ≤ εM2 ni O nj/2 O n−r/2 = εO(1). 2i+j≤r i,j≥0 Again using the Schwarz inequality, Lemma 2.1 and Lemma 2.2, we get X R6 ≤ M3 (n − 1) n i ∞ X j sn,ν (x) |ν − nx| bn,ν−1 (t) |t − x|s dt |t−x|≥δ ν=1 2i+j≤r Z i,j≥0 X ≤ M3 2i+j≤r ni ∞ X ! 12 On a Hybrid Family of Summation Integral Type Operators sn,ν (x)(ν − nx)2j ν=1 Vijay Gupta and Esra Erkuş i,j≥0 × (n − 1) ∞ X Z sn,ν (x) ν=1 = X ∞ ! 21 bn,ν−1 (t)(t − x)2s dt Title Page 0 ni O nj/2 O n−s/2 2i+j≤r i,j≥0 = O n(r−s)/2 = o(1). Thus due to the arbitrariness of ε > 0 it follows that R3 = o(1). Also R4 → 0 as n → ∞ and therefore R2 = o(1). Collecting the estimates of R1 and R2 , we get (3.1). Theorem 3.2. Let f ∈ Cγ [0, ∞), γ > 0. If f (r+2) exists at a point x ∈ (0, ∞), Contents JJ J II I Go Back Close Quit Page 10 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au then lim n Sn(r) (f, x) − f (r) (x) n→∞ r(r + 3) (r) x f (x) + [x(2 + r) + r] f (r+1) (x) + (2 + x)f (r+2) (x). 2 2 Proof. By Taylor’s expansion of f , we have = f (t) = r+2 (i) X f (x) i! i=0 (t − x)i + ε(t, x)(t − x)r+2 where ε(t, x) → 0 as t → x. Applying Lemma 2.2 and the above Taylor’s expansion, we have " r+2 # X f (i) (x) Z ∞ (r) n Sn (f (t), x) − f (r) (x) = n Wn(r) (t, x)(t − x)i dt − f (r) (x) i! 0 i=0 Z ∞ (r) r+2 + n Wn (t, x)ε(t, x)(t − x) dt 0 = E1 + E2 , say. E1 = n r+2 (i) i X f (x) X i i=0 = i! j=0 j i−j Z (−x) On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back ∞ Wn(r) (t, x)tj dt − nf (r) (x) 0 f (r) (x) (r) r n Sn (t , x) − r! r! f (r+1) (x) n (r + 1)(−x)Sn(r) (tr , x) + Sn(r) (tr+1 , x) + (r + 1)! Close Quit Page 11 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au f (r+2) (x) (r + 2)(r + 1) 2 (r) r + n x Sn (t , x) (r + 2)! 2 (r) r+1 (r) r+2 + (r + 2)(−x)Sn (t , x) + Sn (t , x) . Therefore, using (2.1) we have r n (n − r − 2)! (r) E1 = nf (x) −1 (n − 2)! r n (n − r − 2)! f (r+1) (x) +n (r + 1)(−x)r! (r + 1)! (n − 2)! r+1 n (n − r − 3)! nr (n − r − 3)! + (r + 1)!x + r(r + 1) r! (n − 2)! (n − 2)! f (r+2) (x) (r + 2)(r + 1)x2 nr (n − r − 2)! + (r!) (r + 2)! 2 (n − 2)! r+1 n (n − r − 3)! nr (n − r − 3)! + (r + 2)(−x) (r + 1)!x + r(r + 1) r! (n − 2)! (n − 2)! r+2 n (n − r − 4)! (r + 2)! 2 + x (n − 2)! 2 nr+1 (n − r − 4)! −2 +(r + 1)(r + 2) (r + 1)!x + O n . (n − 2)! In order to complete the proof of the theorem it is sufficient to show that E2 → 0 as n → ∞, which can easily be proved along the lines of the proof of Theorem 3.1 and by using Lemma 2.1, Lemma 2.2 and Lemma 2.3. On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Close Quit Page 12 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au Theorem 3.3. Let f ∈ Cγ [0, ∞), γ > 0 and r ≤ m ≤ r + 2. If f (m) exists and is continuous on (a − η, b + η) ⊂ (0, ∞), η > 0, then for n sufficiently large Sn(r) (f, x) −f (r) ≤ M4 n −1 m X f (i) +M5 n−1/2 w f (r+1) , n−1/2 +O n−2 , i=1 where the constants M4 and M5 are independent of f and n, w(f, δ) is the modulus of continuity of f on (a − η, b + η) and k·k denotes the sup-norm on the interval [a, b] . Proof. By Taylor’s expansion of f , we have f (t) = m X On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş if (t − x) i=0 (x) f m (ξ) − f m (x) + (t − x)m ζ(t) + h(t, x) (1 − ζ(t)) , i! m! (i) where ζ lies between t and x and ζ(t) is the characteristic function on the interval (a − η, b + η). For t ∈ (a − η, b + η), x ∈ [a, b] , we have f (t) = m X i=0 (t − x)i f (i) (x) f m (ξ) − f m (x) + (t − x)m . i! m! h(t, x) = f (t) − i=0 Contents JJ J II I Go Back Close For t ∈ [0, ∞) \ (a − η, b + η), x ∈ [a, b] , we define m X Title Page Quit if (t − x) (i) (x) . i! Page 13 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au Thus Sn(r) (f, x) − f (r) (x) = ( m X f (i) (x) Z i! i=0 ∞ ) ∞ Wn(r) (t, x)(t − x)i dt − f (r) (x) 0 (ξ) − f m (x) m + (t − x) ζ(t)dt m! 0 Z ∞ (r) + Wn (t, x)h(t, x)(1 − ζ(t))dt Z f Wn(r) (t, x) m 0 = ∆1 + ∆2 + ∆3 , say. Using (3.1), we obtain i m X f (i) (x) X i r Z ∞ i−j ∂ ∆1 = (−x) Wn (t, x)tj dt − f (r) (x) r i! j ∂x 0 i=0 j=0 m i X f (i) (x) X i ∂ r (n − j − 2)! = (−x)i−j r (nx)j i! j ∂x (n − 2)! i=0 j=0 (n − j − 2)! j−1 −2 (nx) + O n − f (r) (x). +j(j − 1) (n − 2)! On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Hence k∆1 k ≤ M4 n−1 m X f (i) + O n−2 , i=r uniformly in x ∈ [a, b]. Next Z ∞ |f m (ξ) − f m (x)| |∆2 | ≤ Wn(r) (t, x) |t − x|m ζ(t)dt m! 0 Close Quit Page 14 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au w f (m) , δ ≤ m! ∞ Z Wn(r) (t, x) 0 |t − x| 1+ δ |t − x|m dt. Next, we shall show that for q = 0, 1, 2, ... (n − 1) ∞ X j Z sn,ν (x) |ν − nx| ∞ bn,ν−1 (t) |t − x|q dt = O n(j−q)/2 . 0 ν=1 Now by using Lemma 2.1 and Lemma 2.2, we have (n − 1) ∞ X j Z sn,ν (x) |ν − nx| ≤ bn,ν−1 (t) |t − x|q dt ! 1 2 2j (n − 1) sn,ν (x)(ν − nx) ν=1 j/2 =O n ∞ Vijay Gupta and Esra Erkuş 0 ν=1 ∞ X On a Hybrid Family of Summation Integral Type Operators ∞ X ! ∞ Z 2q bn,ν−1 (t) (t − x) dt sn,ν (x) Contents O n−q/2 = O n(j−q)/2 , JJ J uniformly in x. Thus by Lemma 2.3, we obtain (n − 1) s(r) n,ν (x) Z ∞ " ≤ M6 X ni (n − 1) 2i+j≤r II I Go Back bn,ν−1 (t) |t − x|q dt 0 ν=1 Title Page 0 ν=1 ∞ X 1 2 Close ∞ X ν=1 sn,ν (x) |ν − nx|j Z 0 ∞ # bn,ν−1 (t) |t − x|q dt Quit Page 15 of 23 i,j≥0 = O n(r−q)/2 , J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au uniformly in x, where M6 = sup sup |Qi,j,r (x)| x−r . Choosing δ = n−1/2 , 2i+j≤r i,j≥0 x∈[a,b] we get for any s > 0, w f (m) , n−1/2 k∆2 k ≤ O(n(r−m)/2 ) + n1/2 O n(r−m−1)/2 + O n−s m! ≤ M5 w f (m) , n−1/2 n−(m−r)/2 . Since t ∈ [0, ∞) \ (a − η, b + η) , we can choose a δ > 0 in such a way that |t − x| ≥ δ for all x ∈ [a, b] . Applying Lemma 2.3, we obtain k∆3 k ≤ (n − 1) ∞ X X ν=1 ni |ν − nx|j 2i+j≤r On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş |Qi,j,r (x)| sn,ν (x) xr i,j≥0 Title Page Z × r −nx bn,ν−1 (t) |h(t, x)| dt + n e |h(0, x)| . |t−x|≥δ If β is any integer greater than or equal to {γ, m}, then we can find a constant M7 such that |h(t, x)| ≤ M7 |t − x|β for |t − x| ≥ δ. Now applying Lemma 2.1 and Lemma 2.2, it is easily verified that ∆3 = O (n−q ) for any q > 0 uniformly on [a, b]. Combining the estimates ∆1 − ∆3 , we get the required result. Contents JJ J II I Go Back Close Quit Page 16 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au 4. Local Approximation In this section we establish direct local approximation theorems for the operators (1.1). Let CB [0, ∞) be the space of all real valued continuous bounded functions f on [0, ∞) endowed with the norm kf k = sup |f (x)|. The Kx≥0 functionals are defined as 2 K(f, δ) = inf kf − gk + δ kg 00 k : g ∈ W∞ , 2 where W∞ = {g ∈ CB [0, ∞) : g 0 , g 00 ∈ CB [0, ∞)}.By [1,pp 177, Th. 2.4], ∼ ∼ √ there exists a constant M such that K(f, δ) ≤ M w2 f, δ , where δ > 0 and the second order modulus of smoothness is defined as √ w2 f, δ = sup√ sup |f (x + 2h) − 2f (x + h) + f (x)| , 0<h≤ δ x∈[0,∞) where f ∈ CB [0, ∞). Furthermore, let w (f, δ) = sup sup |f (x + h) − f (x)| 0<h≤δ x∈[0,∞) be the usual modulus of continuity of f ∈ CB [0, ∞). Our first theorem in this section is in ordinary approximation which involves second order and ordinary moduli of smoothness: Theorem 4.1. Let f ∈ CB [0, ∞). Then there exists an absolute constant M8 > 0 such that ! r x(1 + x) x |Sn (f, x) − f (x)| ≤ M8 w2 f, + w f, , n−2 n−2 On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Close Quit Page 17 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au for every x ∈ [0, ∞) and n = 3, 4, ... . ∧ Proof. We define a new operator S n : CB [0, ∞) → CB [0, ∞) as follows ∧ nx (4.1) S n (f, x) = Sn (f, x) − f (x) + f . n−2 ∧ Then by Lemma 2.2, we obtain S n (t − x, x) = 0. Now, let x ∈ [0, ∞) and 2 g ∈ W∞ . From Taylor’s formula Z t 0 g(t) = g(x) + g (x)(t − x) + (t − u)g 00 (u)du, t ∈ [0, ∞) On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş x we get Title Page ∧ (4.2) ∧ Z t (t − u)g 00 (u)du, x Z xt 00 = Sn (t − u)g (u)du, x x Z nx/(n−2) n + x − u g 00 (u)du. n − 2 x S n (g, x) − g(x) = S n Contents JJ J II I Go Back Close Quit On the other hand, Z (4.3) x Page 18 of 23 t (t − u)g 00 (u)du ≤ (t − x)2 kg 00 k J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au and Z nx/(n−2) (4.4) x 2 nx n 00 x − u g (u)du ≤ − x kg 00 k n−2 n−2 4x2 00 2 kg k (n − 2) 4x(1 + x) 00 ≤ kg k . (n − 2)2 ≤ Thus by (4.2), (4.3), (4.4) and by the positivity of Sn , we obtain ∧ 4x(1 + x) 00 kg k . S n (g, x) − g(x) ≤ Sn (t − x)2 , x kg 00 k + (n − 2)2 Hence in view of Lemma 2.2, we have ∧ 2nx + (n + 6)x2 4x(1 + x) + (4.5) S n (g, x) − g(x) ≤ kg 00 k (n − 2)(n − 3) (n − 2)2 n 1 4x(1 + x) 00 ≤ + kg k n−3 n−2 n−2 18 ≤ x(1 + x) kg 00 k . n−2 |Sn (f, x)| ≤ (n − 1) ν=1 Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Close Quit Again applying Lemma 2.2 ∞ X On a Hybrid Family of Summation Integral Type Operators Z Page 19 of 23 ∞ −nx bn,ν−1 (t) |f (t)| dt + e sn,ν (x) 0 |f (0)| ≤ kf k . J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au This means that Sn is a contraction, i.e. kSn f k ≤ kf k , f ∈ CB [0, ∞). Thus by (4.2) ∧ (4.6) Sn f ≤ kSn f k + 2 kf k ≤ 3 kf k , f ∈ CB [0, ∞). Using (4.1), (4.5) and (4.6), we obtain ∧ |Sn (f, x) − f (x)| ≤ Sn (f − g, x) − (f − g)(x) ∧ nx n−2 18 nx 00 ≤ 4 kf − gk + x(1 + x) kg k + f (x) − f n−2 n−2 x(1 + x) 00 x ≤ 18 kf − gk + kg k + w f, . n−2 n−2 + Sn (g, x) − g(x) + f (x) − f 2 and using (4.1) Now taking the infimum on the right hand side over all g ∈ W∞ we arrive at the assertion of the theorem. The following error estimation is in terms of ordinary modulus of continuity in simultaneous approximation: (i) Theorem 4.2. Let n > r + 3 ≥ 4 and f ∈ CB [0, ∞) for i ∈ {0, 1, 2, ..., r}. Then r n (n − r − 2)! nr (n − r − 2)! (r) (r) (r) Sn (f, x) − f (x) ≤ −1 f + (n − 2)! (n − 2)! On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Close Quit Page 20 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au r × 1+ [n + (r + 1)(r + 2)] x2 + 2 [n + r(r + 2)] x + r(r + 1) n−r−3 ! × w f (r) , (n − r − 2)−1/2 where x ∈ [0, ∞). Proof. Using Lemma 2.4 and taking into account the well known property w f (r) , λδ ≤ (1 + λ)w f (r) , δ , λ ≥ 0, we obtain On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş (4.7) Sn(r) (f, x) −f (r) (x) Z ∞ ∞ n (n − r − 1)! X ≤ sn,ν (x) bn−r,ν+r−1 (t) f (r) (t) − f (r) (x) dt (n − 2)! 0 r ν=0 n (n − r − 2)! + − 1 f (r) (x) (n − 2)! ∞ r n (n − r − 1)! X ≤ sn,ν (x) (n − 2)! Z ∞ ν=0 × bn−r,ν+r−1 (t) 1 + δ −1 |t − x| w f (r) , δ dt 0 r n (n − r − 1)! + − 1 f (r) . (n − 2)! r Title Page Contents JJ J II I Go Back Close Quit Page 21 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au Further, using Cauchy’s inequality, we have (4.8) (n − r − 1) ∞ X Z bn−r,ν+r−1 (t) |t − x| dt sn,ν (x) 0 ν=0 ( ≤ ∞ (n − r − 1) ∞ X ν=0 Z sn,ν (x) ) 12 ∞ bn−r,ν+r−1 (t) (t − x)2 dt . 0 By direct computation (4.9) (n − r − 1) ∞ X ν=0 Z sn,ν (x) On a Hybrid Family of Summation Integral Type Operators ∞ bn−r,ν+r−1 (t) (t − x)2 dt 2n + 2r(r + 2) n + (r + 1)(r + 2) x2 + x (n − r − 3)(n − r − 2) (n − r − 3)(n − r − 2) r(r + 1) . + (n − r − 3)(n − r − 2) √ Thus by combining (4.7), (4.8) and (4.9) and choosing δ −1 = n − r − 2, we obtain the desired result. = Vijay Gupta and Esra Erkuş 0 Title Page Contents JJ J II I Go Back Close Quit Page 22 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au References [1] R.A. DEVORE AND G.G. LORENTZ, Constructive Approximation, Springer-Verlag, Berlin Heidelberg, New York, 1993. [2] Z. FINTA AND V. GUPTA, Direct and inverse estimates for Phillips type operators, J. Math Anal Appl., 303(2) (2005), 627–642. [3] V. GUPTA AND M.K. GUPTA, Rate of convergence for certain families of summation-integral type operators, J. Math. Anal. Appl., 296 (2004), 608– 618. [4] V. GUPTA, M.K. GUPTA AND V. VASISHTHA, Simultaneous approximation by summation integral type operators, J. Nonlinear Functional Analysis and Applications, 8(3) (2003), 399–412. [5] V. GUPTA AND G.S. SRIVASTAVA, On convergence of derivatives by Szász-Mirakyan-Baskakov type operators, The Math Student, 64 (1-4) (1995), 195–205. [6] N. ISPIR AND I. YUKSEL, On the Bezier variant of Srivastava-Gupta operators, Applied Mathematics E Notes, 5 (2005), 129–137. [7] C.P. MAY, On Phillips operators, J. Approx. Theory, 20 (1977), 315–322. [8] H.M. SRIVASTAVA AND V. GUPTA, A certain family of summation integral type operators, Math. Comput. Modelling, 37 (2003), 1307–1315. On a Hybrid Family of Summation Integral Type Operators Vijay Gupta and Esra Erkuş Title Page Contents JJ J II I Go Back Close Quit Page 23 of 23 J. Ineq. Pure and Appl. Math. 7(1) Art. 23, 2006 http://jipam.vu.edu.au