Journal of Inequalities in Pure and Applied Mathematics ON AN INEQUALITY RELATED TO THE LEGENDRE TOTIENT FUNCTION volume 3, issue 3, article 37, 2002. PENTTI HAUKKANEN Department of Mathematics, Statistics and Philosophy FIN-33014 University of Tampere, Finland. EMail: mapehau@uta.fi Received 06 February, 2002; accepted 27 February, 2002. Communicated by: J. Sándor Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 017-02 Quit Abstract Let ∆(x, n) = ϕ(x, n) − xϕ(n)/n, where ϕ(x, n) is the Legendre totient function and ϕ(n) is the Euler totient function. An inequality for ∆(x, n) is known. In this paper we give a unitary analogue of this inequality, and more generally we give this inequality in the setting of regular convolutions. 2000 Mathematics Subject Classification: 11A25 Key words: Legendre totient function; Inequality; Regular convolution; Unitary convolution. On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 Preliminaries . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4 3 Generalization of (1.3) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 10 4 Unitary Analogue of (1.3) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 13 References Title Page Contents JJ J II I Go Back Close Quit Page 2 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au 1. Introduction The Legendre totient function ϕ(x, n) is defined as the number of positive integers ≤ x which are prime to n. The Euler totient function ϕ(n) is a special case of ϕ(x, n). Namely, ϕ(n) = ϕ(n, n). It is well known that hxi X (1.1) ϕ(x, n) = µ(d) , d d|n where µ is the Möbius function. A direct consequence of (1.1) is that (1.2) ϕ(x, n) = xϕ(n) + O(θ(n)), n where θ(n) denotes the number of square-free divisors of n with θ(1) = 1. This gives rise to the function ∆(x, n) defined as ∆(x, n) = ϕ(x, n) − xϕ(n) . Suryan narayana [8] obtains two inequalities for the function ∆(x, n). Sivaramasarma [7] establishes an inequality which sharpens the first inequality and contains as a special case the second inequality of Suryanarayana [8]. The inequality of Sivaramasarma [7] states that if x ≥ 1, n ≥ 2 and m = (n, [x]), then ϕ(n) 1 1 θ(n) θ(m) mθ(m)ψ(n) ∆(x, n) + {x} (1.3) − ≤ + − , n 2 m 2 2 nψ(m) where {x} = x − [x] and ψ is the Dedekind totient function. See also [4, §I.32]. In this paper we give (1.3) in the setting of Narkiewicz’s regular convolution and the kth power greatest common divisor. As special cases we obtain (1.3) and its unitary analogue. The proof is adapted from that given by Sivaramasarma [7]. On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Title Page Contents JJ J II I Go Back Close Quit Page 3 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au 2. Preliminaries For each n let A(n) be a subset of the set of positive divisors of n. The elements of A(n) are said to be the A-divisors of n. The A-convolution of two arithmetical functions f and g is defined by n X (f ∗A g)(n) = f (d)g . d d∈A(n) Narkiewicz [5] (see also [3]) defines an A-convolution to be regular if (a) the set of arithmetical functions forms a commutative ring with unity with respect to the ordinary addition and the A-convolution, On an Inequality Related to the Legendre Totient Function Pentti Haukkanen (b) the A-convolution of multiplicative functions is multiplicative, Title Page (c) the constant function 1 has an inverse µA with respect to the A-convolution, and µA (n) = 0 or −1 whenever n is a prime power. Contents It can be proved [5] that an A-convolution is regular if and only if (i) A(mn) = {de : d ∈ A(m), e ∈ A(n)} whenever (m, n) = 1, (ii) for each prime power pa (> 1) there exists a divisor t = τA (pa ) of a such that A(pa ) = 1, pt , p2t , . . . , prt , JJ J II I Go Back Close Quit Page 4 of 14 where rt = a, and A(pit ) = 1, pt , p2t , . . . , pit , 0 ≤ i < r. J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au The positive integer t = τA (pa ) in part (ii) is said to be the A-type of pa . A positive integer n is said to be A-primitive if A(n) = {1, n}. The A-primitive numbers are 1 and pt , where p runs through the primes and t runs through the A-types of the prime powers pa with a ≥ 1. For all n let D(n) denote the set of all positive divisors of n and let U (n) denote the set of all unitary divisors of n, that is, n o n = 1 = {d > 0 : d k n}. U (n) = d > 0 : d n, d, d The D-convolution is the classical Dirichlet convolution and the U -convolution is the unitary convolution [1]. These convolutions are regular with τD (pa ) = 1 and τU (pa ) = a for all prime powers pa (> 1). Let k be a positive integer. We denote Ak (n) = d > 0 : dk ∈ A nk . It is known [6] that the Ak -convolution is regular whenever the A-convolution is regular. The symbol (m, n)A,k denotes the greatest kth power divisor of m which belongs to A(n). In particular, (m, n)D,1 is the usual greatest common divisor (m, n) of m and n, and (m, n)U,1 , usually written as (m, n)∗ , is the greatest unitary divisor of n which is a divisor of m. Throughout the rest of the paper A will be an arbitaray but fixed regular convolution and k is a positive integer. The A-analogue of the Möbius function µA is the multiplicative function given by −1 if pa (> 1) is A-primitive, a µA (p ) = 0 if pa is non-A-primitive. In particular, µD = µ, the classical Möbius function, and µU = µ∗ , the unitary analogue of the Möbius function [1]. On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Title Page Contents JJ J II I Go Back Close Quit Page 5 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au The generalized Legendre totient function ϕA,k (x, n) is defined as the number of positive integers a ≤ x such that (a, nk )A,k = 1. It is known [2] that (2.1) ϕA,k (x, n) = X d∈Ak (n) µAk (d) hxi dk . In particular, ϕA,k (n) = ϕA,k (nk , n). We recall that Y (2.2) ϕA,k (n) = nk 1 − p−tk , On an Inequality Related to the Legendre Totient Function p|n Q where n = p pn(p) is the canonical factorization of n and t = τAk (pn(p) ), and we define the generalized Dedekind totient function ψA,k as Y (2.3) ψA,k (n) = nk 1 + p−tk . p|n Pentti Haukkanen Title Page Contents If A is the Dirichlet convolution and k = 1, then ϕA,k (x, n), ϕA,k (n) and ψA,k (n), respectively, reduce to the Legendre totient function, the Euler totient function and the Dedekind totient function. It follows from (2.1) that x X ϕA,k (x, n) = µAk (d) k + O(1) d d∈Ak (n) X xϕA,k (n) + O µ2Ak (d) = k n JJ J II I Go Back Close Quit Page 6 of 14 d∈Ak (n) = xϕA,k (n) + O(θ(n)). nk J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au This suggests we define ∆A,k (x, n) = ϕA,k (x, n) − (2.4) xϕA,k (n) . nk We next present four lemmas which are needed in the proof of our inequality for the function ∆A,k (x, n). n o Lemma 2.1. If f x, nk = n[x]k and mk = [x], nk A,k , then (i) f x, n (ii) mk nk Proof. k On an Inequality Related to the Legendre Totient Function = 0 if m = n, ≤ f (x, nk ) ≤ 1 − mk nk Pentti Haukkanen if m < n. (i) If m = n, then nk |[x] and thus n [x] nk o = 0. k k k (ii) Let m < n. n Then o n 6 | [x] and thus [x] = an + r, where n 0o< r < n . Therefore n[x]k = nrk , where 0 < r < nk , that is, n1k ≤ n[x]k ≤ 1 − n1k . Now, writing [x] nk = ([x]/mk ) (nk /mk ) we arrive at our result. Title Page Contents JJ J II I Go Back Close Lemma 2.2. For n ≥ 2 X d∈Ak (n) ω(d) is odd µ2Ak (d) = θ(n) , 2 Quit Page 7 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 where ω(d) is the number of distinct prime divisors of d. http://jipam.vu.edu.au Proof. It is clear that X µ2Ak (d) d∈Ak (n) ω(d) is odd = ω(n) ω(n) θ(n) + + · · · = 2ω(n)−1 = . 1 3 2 Lemma 2.3. Let mk = ([x], nk )A,k . Then On an Inequality Related to the Legendre Totient Function X µ2A (d)([x], dk )A,k mk θ(m)ψA,k (n) k = . dk nk ψA,k (m) Pentti Haukkanen d∈Ak (n) Proof. By multiplicativity it is enough to consider the case in which n is a prime power. For the sake of brevity we do not present the details. Title Page Contents Lemma 2.4. We have X ϕA,k (n) ∆A,k (x, n) + {x} = − µAk (d)f (x, dk ). nk d∈Ak (n) JJ J II I Go Back Proof. Clearly Close ϕA,k (x, n) = X µAk (d) d∈Ak (n) = xϕA,k (n) − nk x dk − X d∈Ak (n) n x o Quit dk µAk (d) Page 8 of 14 nxo dk . J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au Thus ∆A,k (x, n) = − X µAk (d) d∈Ak (n) It can be verified that x dk = {x} dk + nxo dk . n o [x] . Thus dk X ϕA,k (n) [x] ∆A,k (x, n) = −{x} − µAk (d) . k n dk d∈Ak (n) This completes the proof. On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Title Page Contents JJ J II I Go Back Close Quit Page 9 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au 3. Generalization of (1.3) Theorem 3.1. Let x ≥ 1, n ≥ 2 and mk = ([x], nk )A,k . Then (3.1) ∆A,k (x, n) + {x} ϕA,k (n) − 1 1 nk 2 m θ(n) θ(m) mk θ(m)ψA,k (n) + − . ≤ 2 2 nk ψA,k (m) On an Inequality Related to the Legendre Totient Function Proof. Firstly, suppose that m = n, that is, nk | [x]. Then Pentti Haukkanen X µA (d)[x] ϕA,k (n) k ϕA,k (x, n) = = [x] . k d nk d∈Ak (n) Title Page Thus {x}ϕA,k (n) ∆A,k (x, n) + = 0. nk Since n ≥ 2, the left-hand side of (3.1) is = 0. Therefore (3.1) holds. Secondly, suppose that 1 ≤ m < n. Then, by Lemma 2.4, {x}ϕA,k (n) ∆A,k (x, n)+ = nk d∈Ak (n) ω(d) is odd µ2Ak (d)f (x, dk )− X d∈Ak (n) ω(d) is even µ2Ak (d)f (x, dk ). JJ J II I Go Back Close Quit Page 10 of 14 By Lemma 2.1, ∆A,k (x, n) + X Contents {x}ϕA,k (n) nk J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au ≤ X µ2Ak (d) d∈Ak (n) ω(d) is odd dk 6 |[x] = X ([x], dk )A,k 1− dk µ2Ak (d) − d∈Ak (n) ω(d) is odd − X X − X d∈Ak (n) ω(d) is even dk 6 |[x] µ2Ak (d) ([x], dk )A,k dk µ2Ak (d) d∈Ak (n) ω(d) is odd dk |[x] µ2Ak (d) d∈Ak (n) X ([x], dk )A,k ([x], dk )A,k 2 + µ (d) . Ak k dk d d∈A (n) k dk |[x] By Lemmas 2.2 and 2.3 and definition of the number m, ∆A,k (x, n)+ {x}ϕA,k (n) θ(n) ≤ − nk 2 X d∈Ak (m) ω(d) is odd µ2Ak (d)− mk θ(m)ψA,k (n) +θ(m). nk ψA,k (m) We distinguish the cases m = 1 and m > 1 and apply Lemma 2.2 in the case m > 1 to obtain θ(n) θ(m) mk θ(m)ψA,k (n) {x}ϕA,k (n) 1 1 − ≤ + − . ∆A,k (x, n) + nk 2 m 2 2 nk ψA,k (m) In a similar way we can show that {x}ϕA,k (n) 1 1 θ(n) θ(m) mk θ(m)ψA,k (n) ∆A,k (x, n) + − ≥ − − + . nk 2 m 2 2 nk ψA,k (m) On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Title Page Contents JJ J II I Go Back Close Quit Page 11 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 This completes the proof. http://jipam.vu.edu.au Remark 3.1. If A is the Dirichlet convolution and k = 1, then (3.1) reduces to (1.3). On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Title Page Contents JJ J II I Go Back Close Quit Page 12 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au 4. Unitary Analogue of (1.3) We recall that a positive integer d is said to be a unitary divisor of n (written as dkn) if d is a divisor of n and d, nd = 1. The unitary analogue of the Legendre totient function ϕ∗ (x, n) is the number of positive integers a ≤ x such that (a, n)∗ = 1. Its arithmetical expression is hxi X µ∗ (d) ϕ∗ (x, n) = . d dkn In particular, the unitary analogue of the Euler totient function is given by ϕ∗ (n) = ϕ∗ (n, n). We define the unitary analogue of the Dedekind totient function as Y ψ ∗ (n) = n (1 + p−e ). pe kn It is easy to see that ψ ∗ (n) = σ ∗ (n), where σ ∗ (n) is the sum of the unitary ∗ divisors of n. The function ∆∗ (x, n) is defined as ∆∗ (x, n) = ϕ∗ (x, n) − xϕn(n) . The unitary analogue of (1.3) is ∗ ∗ ϕ (n) 1 1 θ(n) θ(m) mθ(m)σ ∗ (n) (4.1) ∆ (x, n) + {x} − ≤ + − , n 2 m 2 2 nσ ∗ (m) where m = ([x], n)∗ . In fact, if A is the unitary convolution and k = 1, then (3.1) reduces to (4.1). On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Title Page Contents JJ J II I Go Back Close Quit Page 13 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au References [1] E. COHEN, Arithmetical functions associated with the unitary divisors of an integer, Math. Z. 74 (1960), 66–80. [2] P. HAUKKANEN, Some generalized totient functions, Math. Stud. 56 (1988), 65–74. [3] P.J. McCARTHY, Introduction to Arithmetical Functions, Springer–Verlag, New York, 1986. [4] D.S. MITRINOVIĆ, J. SÁNDOR AND B. CRSTICI, Handbook of Number Theory, Kluwer Academic Publishers, MIA Vol. 351, 1996. [5] W. NARKIEWICZ, On a class of arithmetical convolutions, Colloq. Math., 10 (1963), 81–94. [6] V. SITA RAMAIAH, Arithmetical sums in regular convolutions, J. Reine Angew. Math., 303/304 (1978), 265–283. [7] A. SIVARAMASARMA, On ∆(x, n) = ϕ(x, n) − xϕ(n)/n, Math. Stud., 46 (1978), 160–164. [8] D. SURYANARAYANA, On ∆(x, n) = ϕ(x, n) − xϕ(n)/n, Proc. Amer. Math. Soc., 44 (1974), 17–21. On an Inequality Related to the Legendre Totient Function Pentti Haukkanen Title Page Contents JJ J II I Go Back Close Quit Page 14 of 14 J. Ineq. Pure and Appl. Math. 3(3) Art. 37, 2002 http://jipam.vu.edu.au