Journal of Inequalities in Pure and Applied Mathematics SOME RESULTS ON L1 APPROXIMATION OF THE r-TH DERIVATE OF FOURIER SERIES volume 3, issue 1, article 10, 2002. Z. TOMOVSKI Faculty of Mathematical and Natural Sciences P.O. Box 162 91000 Skopje MACEDONIA EMail: tomovski@iunona.pmf.ukim.edu.mk Received 22 September, 1999; received in final form 17 October, 2001; accepted 18 October, 2001. Communicated by: A.G. Babenko Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 005-99 Quit Abstract In this paper we obtain the conditions for L1 -convergence of the r-th derivatives of the cosine and sine trigonometric series. These results are extensions of corresponding Sidon’s and Telyakovskii’s theorems for trigonometric series (case: r = 0). 2000 Mathematics Subject Classification: 26D15, 42A20. Key words: L1 -approximation, Fourier series, Sidon-Telyakovskii class, Telyakovskii inequality Some Results on L1 -Approximation of the r-th Derivate of Fourier Series The author would like to thank the referee for his suggestions and encouragement. Živorad Tomovski Contents Title Page Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8 3 Lemmas . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 10 4 Proofs of the Main Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 16 References JJ J II I Go Back Close Quit Page 2 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au 1. Introduction Let ∞ a0 X f (x) = + an cos nx , 2 n=1 (1.1) g(x) = (1.2) ∞ X an sin nx n=1 be the cosine and sine trigonometric series with real coefficients. Let ∆an = an − an+1 , n ∈ {0, 1, 2, 3, . . .}. The Dirichlet’s kernel, conjugate Dirichlet’s kernel and modified Dirichlet’s kernel are denoted respectively by n sin n + 12 t 1 X Dn (t) = + cos kt = , 2 k=1 2 sin 2t n X cos 2t − cos n + D̃n (t) = sin kt = 2 sin 2t k=1 1 2 t , cos n + 12 t 1 t Dn (t) = − ctg + D̃n (t) = − . 2 2 2 sin 2t Let En (t) = n X n X 1 1 + eikt and E−n (t) = + e−ikt . 2 k=1 2 k=1 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 3 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au (r) (r) Then the r-th derivatives Dn (t) and D̃n (t) can be written as (r) (1.3) 2Dn(r) (t) = En(r) (t) + E−n (t) , (1.4) 2iD̃n(r) (t) = En(r) (t) − E−n (t) . (r) In [2], Sidon proved the following theorem. ∞ ∞ Theorem 1.1. Let P∞{αn }n=1 and {pn }n=1 be sequences such that |αn | ≤ 1, for every n and let n=1 |pn | converge. If (1.5) an = ∞ k X pk X k=n k αl , n ∈ N Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski l=n then the cosine series (1.1) is the Fourier series of its sum f. Title Page Several authors have studied the problem of L1 −convergence of the series (1.1) and (1.2). In [4] Telyakovskii defined the following class of L1 -convergence of Fourier series. A sequence {ak }∞ k=0 belongs to the class S, or {ak } ∈ S if ak → 0 as k →P∞ and there exists a monotonically decreasing sequence {Ak }∞ k=0 such that ∞ A < ∞ and |∆a | ≤ A for all k. k k k=0 k The importance of Telyakovskii’s contributions are twofold. Firstly, he expressed Sidon’s conditions (1.5) in a succinct equivalent form, and secondly, he showed that the class S is also a class of L1 -convergence. Thus, the class S is usually called the Sidon–Telyakovskii class. In the same paper, Telyakovskii proved the following two theorems. Contents JJ J II I Go Back Close Quit Page 4 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Theorem 1.2. [4]. Let the coefficients of the series f (x) belong to the class S. Then the series is a Fourier series and the following inequality holds: Z π ∞ X |f (x)| dx ≤ M An , 0 n=0 where M is a positive constant, independent on f . Theorem 1.3. [4]. Let the coefficients of the series g (x) belong to the class S. Then the following inequality holds for p = 1, 2, 3, . . . ! Z π p ∞ X X |an | |g (x)| dx = +O An . n π/(p+1) n=1 n=1 In particular, g (x) is a Fourier series iff P∞ n=1 |an | n < ∞. In [5], we extended the Sidon–Telyakovskii class S = S0 , i.e., we defined the class Sr , r = 1, 2, 3, . . . as follows: {ak }∞ k=1 ∈ Sr if ak → 0 as k → ∞ and there exists a monotonically decreasing sequence {Ak }∞ k=1 such that P∞ r Ak for all k. k=1 k Ak < ∞ and |∆ak | ≤ P r We note that by Ak ↓ 0 and ∞ k=1 k Ak < ∞, we get (1.6) k r+1 Ak = o (1) , k → ∞. It is trivially to see that Sr+1 ⊂ Sr for all r = 1, 2, 3, .... Now, let {an }∞ n=1 ∈ ∞ S1 . For arbitrary real number a0 , we shall prove that sequence {an }n=0 belongs to S0 . We define A0 = max(|∆a0 |, A1 ). Then |∆a0 | ≤ A0 , i.e. |∆an | ≤ An , for all n ∈ {0, 1, 2, ...} and {An }∞ n=0 is monotonically decreasing sequence. Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 5 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au On the other hand, ∞ X An ≤ A0 + n=0 ∞ X nAn < ∞ . n=1 Thus, {an }∞ n=0 ∈ S0 , i.e. Sr+1 ⊂ Sr , for all r = 0, 1, 2, . . .. The next example verifies that the implication {an } ∈ Sr+1 ⇒ {an } ∈ Sr , r = 0, 1, 2, . . . is not reversible. P 1 Example 1.1. For n = 0, 1, 2, 3, ... define an = ∞ k=n+1 k2 . Then an → 0 as 1 n → ∞ and for n = 0, 1, 2, 3, . . ., ∆an = (n+1)2 . Firstly we shall show that {an }∞ / S1 . n=1 ∈ Let {An }∞ positive such that A ↓ 0 and ∆an = n=1 is an arbitrary P∞ P∞sequence n |∆an | ≤ An . However, n=1 nAn ≥ n=1 (n+1)2 is divergent, i.e. {an } ∈ / S1 . 1 Now, for all n = 0, 1, 2, . . . let An = (n+1)2 . Then An ↓ 0, |∆an | ≤ An and P∞ P∞ 1 ∞ n=0 An = n=1 n2 < ∞, i.e. {an }n=0 ∈ S0 . Our next example will show that there exists a sequence {an }∞ n=1 such that ∞ ∞ {an }n=1 ∈ Sr but {an }n=1 ∈ / Sr+1 , for all r = 1, 2, 3, . . .. P 1 Namely, for all n = 1, 2, 3, . . . let an = ∞ k=n kr+2 . Then an → 0 as n → ∞ 1 and for n = 1, 2, 3, . . . , ∆an = nr+2 . Let {An }∞ n=1 is an arbitrary positive sequence such that An ↓ 0 and ∆an = |∆an | ≤ An . However, ∞ X n=1 nr+1 An ≥ ∞ X n=1 nr+1 1 nr+2 ∞ X 1 = n n=1 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 6 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au is divergent, i.e. {an } ∈ / Sr+1 . On the other for all = 1, 2, . . . let P∞hand, Pn ∞ 1 r An = nr+2 . Then An ↓ 0, |∆an | ≤ An and n=1 n An = n=1 n12 < ∞, i.e. {an } ∈ Sr . In the same paper [5] we proved the following theorem. Theorem 1.4. [5]. Let the coefficients of the series (1.1) belong to the class Sr , r = 0, 1, 2, .... Then the r−th derivative of the series (1.1) is a Fourier series of some f (r) ∈ L1 (0, π) and the following inequality holds: Z π ∞ X (r) f (x) dx ≤ M n r An , 0 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series n=1 Živorad Tomovski where 0 < M = M (r) < ∞. This is an extension of the Telyakovskii Theorem 1.2. Title Page Contents JJ J II I Go Back Close Quit Page 7 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au 2. Results In this paper, we shall prove the following main results. Theorem 2.1. A null sequence {an } belongs to the class Sr , r = 0, 1, 2, . . . if and only if it can be represented as an = (2.1) ∞ k X pk X k=n k αl , n ∈ N l=n ∞ where {αn }∞ n=1 and {pn }n=1 are sequences such that |αn | ≤ 1, for all n and ∞ X nr |pn | < ∞. Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski n=1 Corollary 2.2. every n and let ∞ Let {αn }∞ n=1 and {pn }n=1 be sequences P ∞ r n=1 n |pn | < ∞, r = 0, 1, 2, . . . . If an = ∞ k X pk X k=n k such that |αn | ≤ 1, for Title Page Contents JJ J αl , n ∈ N l=n II I then the r−th derivate of the series (1.1) is a Fourier series of some f (r) ∈ L1 . Go Back Theorem 2.3. Let the coefficients of the series g (x) belong to the class Sr , r = 0, 1, 2, . . . Then the r-th derivate of the series (1.2) converges to a function and for m = 1, 2, 3, . . . the following inequality holds: ! Z π m ∞ X X (r) r−1 r g (x) dx ≤ M (∗) |an | · n + n An , Close π/(m+1) n=1 n=1 Quit Page 8 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au where 0 < M = M (r) < ∞ . P∞ Moreover, if n=1 nr−1 |an | < ∞, then the r-th derivate of the series (1.2) is a Fourier series of some g (r) ∈ L1 (0, π) and ! Z π ∞ ∞ X X (r) r−1 r g (x) dx ≤ M |an | · n + n An 0 n=1 n=1 Corollary 2.4. Let the coefficients of the series g (x) belong to the class Sr , r ≥ 1. Then the following inequality holds: Z π ∞ X (r) g (x) dx ≤ M n r An , 0 where 0 < M = M (r) < ∞. n=1 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 9 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au 3. Lemmas For the proof of our new theorems we need the following lemmas. The following lemma proved by Sheng, can be reformulated in the following way. Lemma 3.1. [1] Let r be a nonnegative integer and x ∈ (0, π], where n ≥ 1. Then r kπ 1 k 1 X n + sin n + x + 2 2 2 ϕk (x), Dn(r) (x) = r+1−k x sin 2 k=0 where ϕr ≡ 12 and ϕk , k = 0, 1, 2, . . . , r − 1 denotes various entire 4π – periodic functions of x, independent of n. More precisely, ϕk , k = 0, 1, 2, . . . , r are trigonometric polynomials of x2 . Lemma 3.2. Let {αj }kj=0 be a sequence of real numbers. Then the following relation holds for ν = 0, 1, 2, . . . , r and r = 0, 1, 2, . . . Z π k X 1 ν 1 ν+3 j + sin j + x + π 2 2 2 Uk = αj dx r+1−ν x π/(k+1) j=0 sin 2 !1/2 k X 1 . = O (k + 1)r−ν+ 2 αj2 (j + 1)2ν j=0 Proof. Applying first Cauchy–Buniakowski inequality, yields "Z #1/2 π dx Uk ≤ 2(r+1−ν) π/(k+1) sin x 2 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 10 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au × Z " π π/(k+1) k X αj j + j=0 1 2 ν #2 1/2 1 (ν + 3)π sin j + x+ dx . 2 2 Since Z π π/(k+1) sin dx ≤ π 2(r+1−ν) 2(r+1−ν) x 2 Z π π/(k+1) dx x2(r+1−ν) π(k + 1)2(r+1−ν)−1 2(r + 1 − ν) − 1 ≤ π(k + 1)2(r+1−ν)−1 , ≤ we have 1/2 Uk ≤ π(k + 1)2(r+1−ν)−1 " k ν #2 1/2 Z π X 1 1 ν+3 × αj j + sin j + x+ π dx 0 2 2 2 j=0 1/2 ≤ 2π(k + 1)2(r+1−ν)−1 " k ν #2 1/2 Z 2π X ν+3 1 × sin (2j + 1)t + π dt . αj j + 0 2 2 j=0 Then, applying Parseval’s equality, we obtain: " k #1/2 h i1/2 X Uk ≤ 2π (k + 1)2(r+1−ν)−1 |αj |2 (j + 1)2ν . j=0 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 11 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Finally, 1 Uk = O (k + 1)r−ν+ 2 k X !1/2 αj2 (j + 1)2ν . j=0 Lemma 3.3. Let r ∈ {0, 1, 2, 3, . . . } and {αk }nk=0 be a sequence of real numbers such that |αk | ≤ 1, for all k. Then there exists a finite constant M = M (r) > 0 such that for any n ≥ 0 n Z π X (r) (∗∗) αk Dk (x) dx ≤ M · (n + 1)r+1 . π/(n+1) k=0 Proof. Similar to Lemma 3.1 it is not difficult to proof the following equality r X n + 12 k sin n + 12 x + k+3 π (r) 2 Dn (x) = ϕk (x), r+1−k sin x2 k=0 where ϕk denotes the same various 4π-periodic functions of x, independent of n. Now, we have: n Z π X (r) αk Dk (x) dx π/(n+1) k=0 ! Z π n r X X π j + 12 ν sin j + 12 x + ν+3 2 ≤ αj ϕ (x) dx. ν r+1−ν π/(n+1) j=0 sin x2 ν=0 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 12 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Since ϕν are bounded, we have: ν Z π n X j+ 12 sin j + 21 x + αj r+1−ν π/(n+1) sin x j=0 ν+3 π 2 2 ϕν (x) dx ≤ K Un , where Un is the integral as in Lemma 3.2, and K = K(r) is a positive constant. Applying Lemma 3.2, to the last integral, we obtain: Z π n X 1 ν+3 1 ν j + 2 sin j + 2 x + 2 π αj ϕν (x) dx r+1−ν x π/(n+1) j=0 sin 2 !1/2 n X 1 = O (n + 1)r−ν+ 2 αj2 (j + 1)2ν j=0 = O (n + 1) r−ν+ 12 (n + 1) ν+ 12 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page = O (n + 1) r+1 . Finally the inequality (∗∗) is satisfied. Remark 3.1. For r = 0, we obtain the Telyakovskii type inequality, proved in [4]. Lemma 3.4. Let r be a non-negative integer. Then for all 0 < |t| ≤ π and all n ≥ 1 the following estimates hold: (r) 4nr π (i) E−n (t) ≤ |t| , r (r) (ii) D̃n (t) ≤ 4n|t|π , Contents JJ J II I Go Back Close Quit Page 13 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au (r) (iii) Dn (t) ≤ 4nr π |t| +O 1 |t| r+1 . Proof. (i) The case r = 0 is trivial. Really, |En (t)| ≤ |Dn (t)| + |D̃n (t)| ≤ π π 3π 4π + = < , 2|t| |t| 2|t| |t| |E−n (t)| = |En (−t)| < 4π . |t| Let r ≥ 1. Applying the Abel’s transformation, we have: " n−1 # n X X 1 1 En(r) (t) = ir k r eikt = ir ∆(k r ) Ek (t) − + nr En (t) − 2 2 k=1 k=1 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page n−1 X 1 1 (r) r r r |En (t)| ≤ [(k + 1) − k ] + |Ek (t)| + n + |En (t)| 2 2 k=1 ) (X n−1 3π 4πnr π + [(k + 1)r − k r ] + nr = . ≤ 2|t| 2|t| |t| k=1 (r) 4nr π (r) (r) Since E−n (t) = En (−t), we obtain E−n (t) ≤ |t| . (ii) Applying the inequality (i), we obtain (r) (r) 1 (r) 1 (r) 4nr π D̃ (t) = i D̃ (t) ≤ E (t) + E (t) . n n ≤ 2 n 2 −n |t| Contents JJ J II I Go Back Close Quit Page 14 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au (r) 1 (iii) We note that ctg 2t . Applying the inequality (ii), we = O |t|r+1 obtain (r) 1 t 1 (r) 4nr π (r) |Dn (t)| ≤ |D̃n (t)| + ctg +O . ≤ 2 2 |t| |t|r+1 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 15 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au 4. Proofs of the Main Results Proof of Theorem 2.1. Let (2.1) hold. Then ∞ X pm ∆ak = αk , m m=k and we denote ∞ X |pm | Ak = . m m=k Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Since |αk | ≤ 1, we get Živorad Tomovski |∆ak | ≤ |αk | ∞ X |pm | ≤ Ak , for all k . m m=k Contents However, ∞ X Title Page ∞ ∞ m ∞ X |pm | X |pm | X r X r k Ak = k = k ≤ m |pm | < ∞ , m m k=1 m=1 m=1 k=1 k=1 m=k r ∞ X r and Ak ↓ 0 i.e. {ak } ∈ Sr . k Now, if {ak } ∈ Sr , we put αk = ∆a and pk = k (Ak − Ak+1 ) . Ak Hence |αk | ≤ 1, and by (1.6) we get: ∞ X k=1 k r |pk | = ∞ X k=1 k r+1 (Ak − Ak+1 ) ≤ ∞ X k=1 JJ J II I Go Back Close Quit Page 16 of 23 (r + 1) k r Ak < ∞ . J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Finally, ak = = ∞ X i=k ∞ X ∆ai = ∞ X αi Ai = i=k ∞ X pm αi m=i i=k m = ∞ X ∞ X αi ∞ X ∆Am m=i i=k m pm X αi , m=k m i=k i.e. (2.1) holds. Proof of Corollary 2.2. The proof of this corollary follows from Theorems 1.4 and 2.1. Proof of Theorem 2.3. We suppose that a0 = 0 and A0 = max (|a1 | , A1 ) . Applying the Abel’s transformation, we have: (4.1) g(x) = ∞ X ∆ak Dk (x) , x ∈ (0, π] . P (r) Applying Lemma 3.4 (iii), we have that the series ∞ k=1 ∆ak D k (x) is uniformly convergent on any compact subset of [ε, π], where ε > 0. Thus, representation (4.1) implies that g Živorad Tomovski Title Page Contents k=0 (r) Some Results on L1 -Approximation of the r-th Derivate of Fourier Series (x) = ∞ X JJ J II I Go Back Close Quit (r) ∆ak Dk (x) . Page 17 of 23 k=0 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Then, Zπ |g (r) (x)|dx ≤ j=1 π/(m+1) j−1 X (r) ∆ak Dk (x) dx π/(j+1) k=0 ! m Z π/j ∞ X X (r) +O ∆ak Dk (x) dx . π/(j+1) m Z X π/j j=1 k=j Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Let j−1 X (r) I1 = ∆ak Dk (x) dx , j=1 π/(j+1) k=0 m Z π/j ∞ X X (r) D (x) I2 = ∆a dx . k k π/(j+1) m Z X π/j j=1 Since ctg x2 = ing estimate 2 x k=j + P∞ x (r) 2(−1)r r! ctg = + O(1), x ∈ (0, π] . 2 xr+1 4x n=1 x2 −4n2 π 2 (see [3]) it is not difficult to proof the follow- Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Thus (r) Dn (x) = r+1 (−1) r! + O (n + 1)r+1 , x ∈ (0, π] r+1 x Page 18 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Hence, j−1 Z m X π/j X dx I1 = r! ∆ak π/(j+1) xr+1 j=1 k=0 #Z " j−1 m X X +O |∆ak |(k + 1)r+1 j=1 = Or m X |aj |j r−1 +O j=1 dx π/(j+1) k=0 ! ! π/j j−1 m X X (k + 1)r+1 |∆ak | j(j + 1) j=1 k=0 ! , Živorad Tomovski where Or depends on r. However, j−1 m X X (k + 1)r+1 |∆ak | j=1 k=0 j(j + 1) = ≤ m X j=1 ∞ X j−1 X 1 (k + 1)r+1 |∆ak | j(j + 1) k=0 (k + 1)r+1 |∆ak | k=0 = Some Results on L1 -Approximation of the r-th Derivate of Fourier Series ∞ X ∞ X 1 j(j + 1) j=k+1 (k + 1)r |∆ak | k=0 = |∆a0 | + ≤ |a1 | + 2r ∞ X Title Page Contents JJ J II I Go Back Close (k + 1)r |∆ak | k=1 ∞ X k=1 Quit Page 19 of 23 k r |∆ak | J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au ≤ ∞ X |∆ak | + 2r ∞ X k r Ak ≤ (1 + 2r ) k=1 k=1 ∞ X k r Ak . k=1 Thus, j−1 m X X |∆ak |(k + 1)r+1 j(j + 1) j=1 k=0 = Or ∞ X ! k r Ak , k=1 where Or depends on r. Therefore, m X I1 = Or ! |aj |j r−1 + Or j=1 ∞ X Some Results on L1 -Approximation of the r-th Derivate of Fourier Series ! k r Ak . Živorad Tomovski k=1 Application of Abel’s transformation, yields ∞ X (r) ∆ak Dk (x) = ∞ X k=j k=j ∆Ak k X ∆ai i=0 Ai (r) Di (x) Title Page − Aj j−1 X ∆ai i=0 Ai (r) Di (x) . Let us estimate the second integral: Contents JJ J II I Go Back k m ∞ X ∆a π X X i (r) D (x) I2 ≤ (∆Ak ) i A i π/(j+1) i=0 j=1 k=j " Z # Z π/j X j−1 ∆ai (r) +Aj Di (x) dx . π/(j+1) i=0 Ai Close Quit Page 20 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Applying the Lemma 3.3, we have: k Z π X ∆a (r) i (4.2) Jk = Di (x) dx = Or (k + 1)r+1 , π/(j+1) i=0 Ai where Or depends on r. Then, by Lemma 3.4(iii), Z π/j X j−1 ∆a i (r) D (x) dx| i A i π/(j+1) i=0 !! ! Z Z j−1 j−1 X X |∆ai | π/j dx |∆ai | π/j dx r =O j +O Ai π/(j+1) x Ai π/(j+1) xr+1 i=0 i=0 (4.3) = O(j r ) + Or (j r ) = Or (j r ) j=1 = Or (1) ∞ X (∆Ak )(k + 1)r+1 + Or = Or ∞ X ! j r Aj ∞ X j=1 k=1 Živorad Tomovski Title Page where Or depends on r. However, by (4.2), (4.3) and (1.6), we have ! ∞ ∞ X X I2 ≤ (∆Ak ) Jk + Or j r Aj k=1 Some Results on L1 -Approximation of the r-th Derivate of Fourier Series ! j r Aj Contents JJ J II I Go Back Close Quit . j=1 Finally, the inequality (∗) is satisfied. Page 21 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au Proof of Corollary 2.4. By the inequalities m X |an | · n r−1 ≤ n=1 ≤ ∞ X n=1 ∞ X n r−1 nr−1 n=1 = ∞ X Ak k=1 ∞ X |∆ak | k=n ∞ X k=n k X n Ak r−1 ≤ n=1 ∞ X k=1 and Theorem 2.3, we obtain: Z π (r) |g (x)|dx ≤ M 0 where 0 < M = M (r) < ∞. k r Ak , Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski ∞ X n=1 ! n r An , Title Page Contents JJ J II I Go Back Close Quit Page 22 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au References [1] SHENG SHUYUN, The extensions of the theorem of C. V. Stanojevic and V.B. Stanojevic, Proc. Amer. Math. Soc., 110 (1990), 895–904. [2] S. SIDON, Hinrehichende Bedingungen fur den Fourier-Charakter einer trigonometrischen Reihe, J. London Math. Soc., 72 (1939), 158–160. [3] M.R. SPIEGEL, Theory and Problems of Complex Variables, Singapore (1988), p.175, 192. [4] S.A. TELYAKOVSKII, On a sufficient condition of Sidon for the integrability of trigonometric series, Math. Notes, 14 (1973), 742–748. [5] Ž. TOMOVSKI, An extension of the Sidon–Fomin inequality and applications, Math. Ineq. & Appl., 4(2) (2001), 231–238. [6] Ž. TOMOVSKI, Some results on L1 -approximation of the r-th derivate of Fourier series, RGMIA Research Report Collection, 2(5) (1999), 709–717. ONLINE: http://rgmia.vu.edu.au/v2n5.html Some Results on L1 -Approximation of the r-th Derivate of Fourier Series Živorad Tomovski Title Page Contents JJ J II I Go Back Close Quit Page 23 of 23 J. Ineq. Pure and Appl. Math. 3(1) Art. 10, 2002 http://jipam.vu.edu.au