ON CERTAIN SUBCLASS OF BAZILEVIČ FUNCTIONS Subclass of Bazilevič Functions DONG GUO AND MING-SHENG LIU School of Mathematical Sciences, South China Normal University, Guangzhou 510631, Guangdong, China. EMail: liumsh@scnu.edu.cn Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents Received: 22 September, 2006 Accepted: 26 February, 2007 Communicated by: H.M. Srivastava 2000 AMS Sub. Class.: Primary 30C45; Secondary 26A33, 33C05. Key words: Starlike function, Bazilevič Function, Subordination relationships, Inclusion relationship, Coefficient estimates, Integral operator, Covering theorem, FeketeSzegö inequalities. JJ II J I Page 1 of 23 Go Back Full Screen Close Abstract: P∞ Let H be the class of functions f (z) of the form f (z) = z + n=2 an z n , which are analytic in the unit disk U = {z : |z| < 1}. In this paper, the authors introduce a subclass M (α, λ, ρ) of H and study its some properties. The subordination relationships, inclusion relationships, coefficient estimates, the integral operator and covering theorem are proven here for each of the function classes. Furthermore, some interesting Fekete-Szegö inequalities are obtained. Some of the results, presented in this paper, generalize the corresponding results of earlier authors. Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Acknowledgements: This research is partly supported by the Doctoral Foundation of the Education committee of China (No. 20050574002). Title Page Contents JJ II J I Page 2 of 23 Go Back Full Screen Close Contents 1 Introduction 4 2 Preliminaries 7 3 Main Results and Their Proofs 9 Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 3 of 23 Go Back Full Screen Close 1. Introduction Let H denote the class of functions f of the form (1.1) f (z) = z + ∞ X an z n , n=2 which are analytic in the open unit disk U = {z : |z| < 1}, and let S denote the class of all functions in H which are univalent in the disk U . Suppose also that S ∗ , K and α − K denote the familiar subclasses of H consisting of functions which are, respectively, starlike in U, convex in U and α− convex in U. Thus we have 0 zf (z) ∗ S = f : f ∈ H and R > 0, z ∈ U , f (z) zf 00 (z) K = f : f ∈ H and R 1 + 0 > 0, z ∈ U f (z) and zf 0 (z) zf 00 (z) α−K = f : f ∈ H and R α 1 + 0 + (1 − α) > 0, f (z) f (z) Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 4 of 23 z∈U Subclass of Bazilevič Functions . Let f (z) and F (z) be analytic in U . Then we say that the function f (z) is subordinate to F (z) in U , if there exists an analytic function ω(z) in U such that |ω(z)| ≤ |z| and f (z) = F (ω(z)), denoted f ≺ F or f (z) ≺ F (z). If F (z) is univalent in U , then the subordination is equivalent to f (0) = F (0) and f (U ) ⊂ F (U ) (see [18]). Assuming that α > 0, λ ≥ 0, ρ < 1, a function p(z) = 1 + p1 z + p2 z 2 + · · · is said to be in the class Pρ if and only if p(z) is analytic in the unit disk U and Go Back Full Screen Close Rp(z) > ρ, z ∈ U . A function f (z) ∈ H is said to be in the class B(λ, α, ρ) if and only if it satisfies α α 0 f (z) zf (z) f (z) (1.2) R(1 − λ) +λ > ρ, z ∈ U, z f (z) z α α f (z) such that = 1. It is where we choose the branch of the power f (z) z z z=0 obvious that the subclass B(1, α, 0) is the subclass of Bazilevič functions, which is the subclass of univalent functions S, we set B(α, ρ) ≡ B(1, α, ρ). The function class B(λ, α, ρ) was introduced and studied by Liu [10]. Some special cases of the function class B(λ, α, ρ) had been studied by Bazilevič [1], Chichra [2], Ding, Ling and Bao [3], Liu [9] and Singh [19], respectively. Liu [11] introduced the following class B(λ, α, A, B, g(z)) of analytic functions, and studied its some properties. B(λ, α, A, B, g(z)) α α 0 f (z) zf (z) f (z) 1 + Az zg 0 (z) = f ∈H: 1−λ +λ ≺ , g(z) g(z) f (z) g(z) 1 + Bz where α > 0, λ ≥ 0, −1 ≤ B < A ≤ 1, g(z) ∈ S ∗ . Fekete and Szegö [4] showed that for f ∈ S given by (1.1), 3 − 4u, if µ ≤ 0, |a3 − µa22 | ≤ 1 + 2e−2/(1−µ) , if 0 ≤ µ < 1, 4 − 3µ, if µ ≥ 1. As a result, many authors studied similar problems for some subclasses of H or S (see [6, 7, 8, 13, 14, 15, 20]), which is popularly referred to as the Fekete-Szegö Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 5 of 23 Go Back Full Screen Close inequality or the Fekete-Szegö problem. Li and Liu [12] obtained the Fekete-Szegö inequality for the function class B(λ, α, ρ). Recently, Patel [17] introduced the following subclass Mp (λ, µ, A, B) of p−valent Bazilevič functions, and studied some its properties. Pof ∞ p An analytic function f (z) = z + n=p+1 an z n is said to be in the class Mp (λ, µ, A, B) P n if and only if there exists a p−valent starlike function g(z) = z p + ∞ n=p+1 bn z such that µ 0 zf 0 (z) f (z) zf 00 (z) zf 0 (z) zf (z) zg 0 (z) 1 + Az +λ 1 + 0 − +µ − ≺p , f (z) g(z) f (z) f (z) f (z) g(z) 1 + Bz where µ ≥ 0, λ > 0, −1 ≤ B < A ≤ 1. In the present paper, we introduce the following subclass of analytic functions, and obtain some interesting results. Definition 1.1. Assume that α ≥ 0, λ ≥ 0, 0 ≤ ρ < 1, f ∈ H. We say that f (z) ∈ M (α, λ, ρ) if and only if f (z) satisfies the following inequality: 0 α 0 zf (z) f (z) zf 00 (z) zf 0 (z) zf (z) R +λ 1+ 0 − +α −1 > ρ, z ∈ U. f (z) z f (z) f (z) f (z) It is evident that M (α, 0, ρ) = B(α, ρ)(α ≥ 0) and M (0, α, 0) = α −K(α ≥ 0). Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 6 of 23 Go Back Full Screen Close 2. Preliminaries To derive our main results, we shall require the following lemmas. Lemma 2.1 ([16]). If −1 ≤ B < A ≤ 1, β > 0 and the complex number γ satisfies R(λ) ≥ −β(1−A) , then the differential equation 1−B q(z) + 1 + Az zq 0 (z) = , βq(z) + γ 1 + Bz z ∈ U, Dong Guo and Ming-Sheng Liu has a univalent solution in U given by z β+γ (1 + Bz)β(A−B)/B Rz − βγ , B = 6 0, β+γ−1 β(A−B)/B (1 + Bt) dt β 0 t (2.1) q(z) = z β+γ exp(βAz) R z β+γ−1 − γ, B = 0. β 0 t exp(βAt)dt β If φ(z) = 1 + c1 z + c2 z 2 + · · · is analytic in U and satisfies (2.2) zφ0 (z) 1 + Az ≺ , φ(z) + βφ(z) + γ 1 + Bz then φ(z) ≺ q(z) ≺ 1 + Az , 1 + Bz Subclass of Bazilevič Functions (z ∈ U), vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 7 of 23 Go Back Full Screen (z ∈ U), and q(z) is the best dominant of (2.2). Lemma 2.2 ([11]). Suppose that F (z) is analytic and convex in U, and 0 ≤ λ ≤ 1, f (z) ∈ H, g(z) ∈ H. If f (z) ≺ F (z) and g(z) ≺ F (z). Then λf (z) + (1 − λ)g(z) ≺ F (z). Close P n Lemma 2.3 ([18]). Let p(z) = 1 + ∞ n=1 pn z ∈ P0 . Then 1 2 p2 − p1 ≤ 2 − 1 |p21 | 2 2 and |pn | ≤ 2 for all n ∈ N+ . Lemma 2.4 ([1]). Let α ≥ 0, f ∈ H and for |z| < R ≤ 1, 0 α zf (z) f (z) R > 0, f (z) z Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 then f (z) is univalent in |z| < R. Title Page Contents JJ II J I Page 8 of 23 Go Back Full Screen Close 3. Main Results and Their Proofs Theorem 3.1. Let α ≥ 0 and λ > 0. If f (z) ∈ M (α, λ, ρ). Then α 1 + (1 − 2ρ)z zf 0 (z) f (z) ≺ q(z) ≺ , (z ∈ U), (3.1) f (z) z 1−z where λz 1/λ (1 − z)−2(1−ρ)/λ q(z) = R z (1−λ)/λ , −2(1−ρ)/λ dt t (1 − t) 0 and q(z) is the best dominant of (3.1). Proof. By applying the method of the proof of Theorem 3.1 in [17] mutatis mutandis, we can prove this theorem. Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents With the aid of Lemma 2.4, from Theorem 3.1, we have the following inclusion relation. JJ II Corollary 3.2. Let α ≥ 0, 0 ≤ ρ < 1 and λ ≥ 0, then J I M (α, λ, ρ) ⊂ M (α, 0, ρ) ⊂ M (α, 0, 0) ⊂ S. Theorem 3.3. Let α ≥ 0 and λ2 > λ1 ≥ 0, 1 > ρ2 ≥ ρ1 ≥ 0, then M (α, λ2 , ρ2 ) ⊂ M (α, λ1 , ρ1 ). Proof. Suppose that f (z) ∈ M (α, λ2 , ρ2 ). Then, by the definition of M (α, λ2 , ρ2 ), we have 0 α 0 zf (z) f (z) zf 00 (z) zf 0 (z) zf (z) (3.2) R + λ2 1 + 0 − +α −1 f (z) z f (z) f (z) f (z) > ρ2 (z ∈ U). Page 9 of 23 Go Back Full Screen Close Since α ≥ 0 and λ2 > λ1 ≥ 0, by Theorem 3.1, we obtain 0 α zf (z) f (z) (3.3) R > ρ2 (z ∈ U). f (z) z Setting λ = λ1 , λ2 so that 0 ≤ λ < 1, we find from (3.2) and (3.3) that α 0 zf 00 (z) zf 0 (z) zf (z) zf 0 (z) f (z) R + λ1 1 + 0 − +α −1 f (z) z f (z) f (z) f (z) 0 α 0 zf 00 (z) zf 0 (z) zf (z) zf (z) f (z) = λR + λ2 [1 + 0 − +α −1 f (z) z f (z) f (z) f (z) α zf 0 (z) f (z) + (1 − λ)R > ρ2 ≥ ρ1 (z ∈ U), f (z) z Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents that is, f (z) ∈ M (α, λ1 , ρ1 ). Hence, we have M (α, λ2 , ρ2 ) ⊂ M (α, λ1 , ρ1 ), and the proof of Theorem 3.3 is complete. JJ II J I Remark 1. Theorem 3.3 obviously provides a refinement of Corollary 3.2. Setting α = 0, ρ2 = ρ1 = 0 in Theorem 3.3, we get Theorem 9.4 of [5]. Page 10 of 23 With the aid of Lemma 2.2, by using the method of our proof of Theorem 3.3, we can prove the following inclusion relation. Theorem 3.4. Let µ ≥ 0, −1 ≤ B < A ≤ 1 and λ2 > λ1 ≥ 0, then Mp (λ2 , µ, A, B) ⊂ Mp (λ1 , µ, A, B). By applying the method of the proof of Theorem 3.13, Theorem 3.6 and Theorem 3.11 in [17] mutatis mutandis, we can prove the following three results. Go Back Full Screen Close Theorem 3.5. Let α ≥ 0, λ > 0 and γ > 0. If f (z) ∈ H satisfies 0 α 0 zf (z) f (z) zf (z) zf 00 (z) zf 0 (z) γ +λ 1 + 0 − +α −1 6= it, f (z) z f (z) f (z) f (z) p where t is a real number satisfying |t| > λ(λ + 2γ), then α 0 zf (z) f (z) R > 0, (z ∈ U). f (z) z Theorem 3.6. Suppose that α > 0 and 0 ≤ ρ < 1. If f (z) ∈ H satisfies 0 α zf (z) f (z) Re > ρ, (z ∈ U), f (z) z (z ∈ U), Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents then f (z) ∈ M (α, λ, ρ) for |z| < R(λ, ρ), where λ > 0, and √ (1+λ−ρ)− (1+λ−ρ)2 −(1−2ρ) , ρ 6= 1 , 1−2ρ 2 R(λ, ρ) = 1 , ρ = 12 . 1+2λ The bound R(λ, ρ) is the best possible. (3.4) Fα,δ (f ) = Fα,δ (f )(z) = α+δ zδ II J I Page 11 of 23 Go Back Full Screen For a function f ∈ H, we define the integral operator Fα,δ as follows: JJ Z α1 z δ−1 α t f (t) dt 0 where α and δ are real numbers with α > 0, δ > −α. (z ∈ U), Close Theorem 3.7. Let α and δ be real numbers with α > 0, 0 ≤ ρ < 1, δ > max{−α, −αρ} and let f (z) ∈ H. If 0 α π zf (z) f (z) arg − ρ ≤ β (0 ≤ ρ < 1; 0 < β ≤ 1), f (z) z 2 then 0 π zFα,δ (f ) Fα,δ (f ) α arg − ρ ≤ β, Fα,δ (f ) z 2 where Fα,δ (f ) is the operator given by (3.4). Now we derive the Fekete-Szegö inequality for the function class M (α, λ, ρ). P n Theorem 3.8. Suppose that f (z) = z + ∞ n=2 an z ∈ M (α, λ, ρ). Then |a2 | ≤ 2(1 − ρ) , (1 + λ)(1 + α) and for each µ ∈ C, the following bound is sharp 2(1 − ρ) |a3 − µa22 | ≤ (1 + 2λ)(2 + α) (1 − ρ)[2λ(3 + α) − (2 + α)(α − 1 + 2µ + 4µλ)] . × max 1, 1 + (1 + λ)2 (1 + α)2 Proof. Since f (z) ∈ M (α, λ, ρ), by Definition 1.1, there exists a function p(z) = P+∞ 1 + k=1 pk z k ∈ P0 , such that α 0 zf 00 (z) zf 0 (z) zf (z) zf 0 (z) f (z) +λ 1+ 0 − +α −1 f (z) z f (z) f (z) f (z) = (1 − ρ)p(z) + ρ, z ∈ U. Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 12 of 23 Go Back Full Screen Close Equating coefficients, we obtain 1−ρ p1 , (1 + λ)(1 + α) h i (α+2)(α−1) 2 (1 − ρ) λ(3 + α) − 2 1−ρ a3 = p2 + p2 . 2 2 (1 + 2λ)(2 + α) (1 + λ) (1 + α) (1 + 2λ)(2 + α) 1 Thus, we have 1−ρ 1 2 2 a3 − µa2 = p2 − p1 (1 + 2λ)(2 + α) 2 2 (1−ρ) [2λ(3+α)−(2+α)(α−1)−2µ(1+2λ)(2+α)]+(1−ρ)(1+λ)2 (1+α)2 2 + p1 . 2(1+λ)2 (1+α)2 (1+2λ)(2+α) a2 = By Lemma 2.3, we obtain that |a2 | = 1−ρ |p | (1+λ)(1+α) 1 |a3 − µa22 | ≤ H(x) = A + ≤ 2(1−ρ) , (1+λ)(1+α) Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents and ABx2 , 4 where x = |p1 | ≤ 2, A= Subclass of Bazilevič Functions JJ II J I Page 13 of 23 2(1 − ρ) , (1 + 2λ)(2 + α) 2 B= 2 |C| − (1 + λ) (1 + α) , (1 + λ)2 (1 + α)2 Go Back Full Screen and C = (1 + λ)2 (1 + α)2 + (1 − ρ)[2λ(3 + α) − (2 + α)(α − 1 + 2µ + 4µλ)]. So, we have |a3 − µa22 | ≤ H(0) = A, H(2) = A|C| , (1+λ)2 (1+α)2 |c| ≤ (1 + λ)2 (1 + α)2 , |c| ≥ (1 + λ)2 (1 + α)2 . Close Here equality is attained for the function given by α zf 0 (z) f (z) (3.5) f (z) z λz 1/λ (1 − z 2 )(ρ−1)/λ R , λ > 0, z (1−λ)/λ 2 )(ρ−1)/λ dt t (1 − t 0 1 + (1 − 2ρ)z 2 , λ = 0, 1 − z2 = λz 1/λ (1 − z)2(ρ−1)/λ Rz , λ > 0, t(1−λ)/λ (1 − t)2(ρ−1)/λ dt 0 1 + (1 − 2ρ)z , λ = 0, 1−z |c| ≤ (1 + λ)2 (1 + α)2 , |c| ≤ (1 + λ)2 (1 + α)2 Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 |c| ≥ (1 + λ)2 (1 + α)2 , Title Page |c| ≥ (1 + λ)2 (1 + α)2 . Setting λ = 0 in Theorem 3.8, we have the following corollary. Corollary 3.9. If f (z) ∈ B(α, ρ) given by (1.1), then |a2 | ≤ Subclass of Bazilevič Functions 2(1 − ρ) , 1+α and for each µ ∈ C, the following bound is sharp 2(1 − ρ) (1 − ρ)(2 + α)(1 − 2µ − α) 2 |a3 − µa2 | ≤ max 1, 1 + . 2+α (1 + α)2 Notice that M (0, α, 0) ≡ α − K, and from Theorem 3.8, we have the following corollary. Contents JJ II J I Page 14 of 23 Go Back Full Screen Close Corollary 3.10. Let α ≥ 0. If f (z) ∈ α − K given by (1.1). Then |a2 | ≤ 2 , 1+α and for each µ ∈ C, the following bound is sharp 1 6α + 2 − 4µ − 8µα 2 . |a3 − µa2 | ≤ max 1, 1 + 1 + 2α (1 + α)2 Theorem 3.11 (Covering Theorem). Let α ≥ 0, λ ≥ 0 and f (z) ∈ M (α, λ, ρ), then the unit disk U is mapped by f (z) on a domain that contains the disk |ω| < r1 , where (1 + α)(1 + λ) r1 = . 2(1 + α)(1 + λ) + 2(1 − ρ) Proof. Let ω 0 be any complex number such that f (z) 6= ω 0 (z ∈ U), then ω 0 6= 0 and (by Corollary 3.2) the function 1 ω 0 f (z) = z + a2 + z2 + · · · , ω 0 − f (z) ω0 is univalent in U, so that Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 15 of 23 Go Back a2 + 1 ≤ 2, ω0 Therefore, according to Theorem 3.8, we obtain |ω 0 | ≥ Subclass of Bazilevič Functions (1 + α)(1 + λ) = r1 . 2(1 + α)(1 + λ) + 2(1 − ρ) Thus we have completed the proof of Theorem 3.11. Full Screen Close Remark 2. Setting α = λ = ρ = 0 in Theorem 3.11, we get the well-known 14 − covering theorem for the familiar class S ∗ of starlike functions. If 0 ≤ µ ≤ µ1 and µ is a real number, Theorem 3.8 can be improved as follows. P n Theorem 3.12. Suppose that f (z) = z + ∞ n=2 an z ∈ M (λ, α, ρ) and µ ∈ R. Then (3.6) |a3 − µa22 | + µ|a2 |2 2(1 − ρ) (1 − ρ)[2λ(3 + α) − (2 + α)(α − 1)] ≤ 1+ , (1 + 2λ)(2 + α) (1 + λ)2 (1 + α)2 0 ≤ µ ≤ µ0 , Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page (3.7) |a3 − µa22 | + (µ1 − µ)|a2 |2 ≤ 2(1 − ρ) , (1 + 2λ)(2 + α) Contents µ0 ≤ µ ≤ µ1 , and these inequalities are sharp, where 1 2λ − α(2 + α) (1 + λ)2 (1 + α)2 µ0 = + + , 2 2(1 + 2λ)(2 + α) 2(1 + 2λ)(2 + α)(1 − ρ) 1 2λ − α(2 + α) (1 + λ)2 (1 + α)2 + + . 2 2(1 + 2λ)(2 + α) (1 + 2λ)(2 + α)(1 − ρ) Proof. From Theorem 3.8, we get µ1 = 2(1 − ρ) 2(1 − ρ) (3.8) |a3 − µa22 | ≤ + (1 + 2λ)(2 + α) (1 + 2λ)(2 + α) |(1 − ρ)[2λ(3 + α) − (2 + α) [(α − 1) + 2µ(1 + 2λ)]] + (1 + λ)2 (1 + α)2 | 1 − |p1 |2 . · 2 2 4(1 + λ) (1 + α) 4 JJ II J I Page 16 of 23 Go Back Full Screen Close Using (3.8) and a2 = 1−ρ p, (1+λ)(1+α) 1 if 0 ≤ µ ≤ µ0 , we obtain 2(1 − ρ) 2(1 − ρ) + (1 + 2λ)(2 + α) (1 + 2λ)(2 + α) (1 − ρ)[2λ(3 + α) − (2 + α)(α − 1) − 2µ(1 + 2λ)(2 + α)] × |p1 |2 4(1 + λ)2 (1 + α)2 2(1 − ρ)2 [2λ(3 + α) − (2 + α)(α − 1)] 2(1 − ρ) = + |p1 |2 − µ|a2 |2 . 2 2 (1 + 2λ)(2 + α) 4(1 + 2λ)(2 + α)(1 + λ) (1 + α) |a3 − µa22 | ≤ Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Hence |a3 − µa22 | + µ|a2 |2 2(1 − ρ) 2(1 − ρ)2 [2λ(3 + α) − (2 + α)(α − 1)] + |p1 |2 ≤ (1 + 2λ)(2 + α) 4(1 + 2λ)(2 + α)(1 + λ)2 (1 + α)2 2(1 − ρ) (1 − ρ)[2λ(3 + α) − (2 + α)(α − 1)] ≤ 1+ , (1 + 2λ)(2 + α) (1 + λ)2 (1 + α)2 Subclass of Bazilevič Functions Title Page Contents 0 ≤ µ ≤ µ0 . If µ0 ≤ µ ≤ µ1 , from (3.8), we obtain |a3 − µa22 | 2(1 − ρ) 2(1 − ρ) ≤ + (1 + 2λ)(2 + α) (1 + 2λ)(2 + α) −2(1 + λ)2 (1 + α)2 − (1 − ρ)[2λ(3 + α) − (2 + α)(α − 1 + 2µ + 4µλ)] × |p1 |2 2 2 4(1 + λ) (1 + α) 2(1 − ρ) = − (µ1 − µ)|a2 |2 . (1 + 2λ)(2 + α) JJ II J I Page 17 of 23 Go Back Full Screen Close Therefore 2(1 − ρ) , µ0 ≤ µ ≤ µ1 . (1 + 2λ)(2 + α) Here equality is attained for the function given by (3.5), and the proof of Theorem 3.12 is complete. |a3 − µa22 | + (µ1 − µ)|a2 |2 ≤ Theorem 3.13. Let f (z) ∈ H, α ≥ 0, λ ≥ 0 and 0 < k ≤ 1. If 0 zf (z) f (z) α (3.9) f (z) z 0 zf 00 (z) zf 0 (z) zf (z) +λ 1 + 0 − +α −1 − 1 < k, f (z) f (z) f (z) then k |a2 | ≤ , (1 + λ)(1 + α) and for each µ ∈ C, the following bound is sharp |a3 − Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 z ∈ U, Title Page Contents µa22 | α k(1 + 2λ)(2 + α) + 1 − 2µ − 1+2λ k ≤ max 1, (1 + 2λ)(2 + α) 2(1 + λ)2 (1 + α)2 JJ II J I Page 18 of 23 2λ (1+2λ)(2+α) Proof. By (3.9), there exists a function p(z) ∈ P0 such that for all z ∈ U α 0 zf 0 (z) f (z) zf 00 (z) zf 0 (z) zf (z) +λ 1+ 0 − +α −1 f (z) z f (z) f (z) f (z) 2k + 1 − k. = 1 + p(z) . Go Back Full Screen Close Equating the coefficients, we obtain k p1 , 2(1 + λ)(1 + α) h i k 2 λ(3 + α) − (2+α)(α−1) 2 k 1 (1 + 2λ)(2 + α)a3 = − p2 − p21 + p21 . 2 2 2 4(1 + λ) (1 + α)2 a2 = − Thus, we have a3 − µa22 Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu 1 2 k =− p2 − p1 2(1 + 2λ)(2 + α) 2 i h k 2 λ(3 + α) − (2+α)(α−1) − µ(1 + 2λ)(2 + α) 2 + p21 , 4(1 + λ)2 (1 + α)2 (1 + 2λ)(2 + α) so that, by Lemma 2.3, we get that |a2 | = k |p | 2(1+λ)(1+α) 1 ≤ k , (1+λ)(1+α) and vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I 2 |a3 − µa22 | ≤ H(x) = A + Bx , 4 Page 19 of 23 Go Back where x = |p1 | ≤ 2, Full Screen k A= , (1 + 2λ)(2 + α) and C= k 2 |C| k B= − 2 2 [(1 + λ) (1 + α) ] [(1 + 2λ)(2 + α)] 1 − 2µ α λ − + . 2 2(1 + 2λ) (1 + 2λ)(2 + α) Close Therefore |a3 − µa22 | ≤ H(0) = A, H(2) = Ak(1+2λ)(2+α)|C| , (1+λ)2 (1+α)2 Here equality is attained for the function given by 2 λz 1/λ exp(−kz )/(2λ) R z t(1−λ)/λ , 2 )/(2λ) (−kt exp dt 0 α 1 − kz 2 , zf 0 (z) f (z) = 1/λ exp−kz/λ f (z) z R z λz (1−λ)/λ exp−kt/λ dt , t 0 1 − kz, |c| ≤ (1+λ)2 (1+α)2 , k(1+2λ)(2+α) |c| ≥ (1+λ)2 (1+α)2 . k(1+2λ)(2+α) λ > 0, |c| ≤ (1+λ)2 (1+α)2 , k(1+2λ)(2+α) λ = 0, |c| ≤ (1+λ)2 (1+α)2 , k(1+2λ)(2+α) λ > 0, |c| ≥ (1+λ)2 (1+α)2 , k(1+2λ)(2+α) λ = 0, |c| ≥ (1+λ)2 (1+α)2 . k(1+2λ)(2+α) Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu This completes the proof of Theorem 3.13. Setting λ = 0, we get the following corollary. Corollary 3.14. Let f (z) ∈ H, α ≥ 0 and 0 < k ≤ 1. If 0 zf (z) f (z) α < k, z ∈ U, − 1 f (z) z vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 20 of 23 Go Back Full Screen then k , (1 + α) and for each µ ∈ C, the following bound is sharp k(2 + α) k 2 max 1, |1 − 2µ − α| . |a3 − µa2 | ≤ 2+α 2(1 + α)2 |a2 | ≤ Close Corollary 3.15. Let f (z) ∈ H, α ≥ 0 and 0 < k ≤ 1. If 0 00 zf (z) zf (z) (1 − α) < k, z ∈ U, + α 1 + − 1 f (z) f 0 (z) then k , 1+α and for each µ ∈ C the following bound is sharp ( 1 − 2µ + k(1 + 2α) k |a3 − µa22 | ≤ max 1, 2(1 + 2α) (1 + α)2 |a2 | ≤ Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu α 1+2α ) vol. 8, iss. 1, art. 12, 2007 . Title Page Setting α = 1 in Corollary 3.15, we have the following corollary. Corollary 3.16. Let f (z) ∈ H and 0 < k ≤ 1. If 00 zf (z) f 0 (z) < k, z ∈ U, then k , 2 and for each µ ∈ C the following bound is sharp k|4 − 6µ| k 2 . |a3 − µa2 | ≤ max 1, 6 4 |a2 | ≤ Contents JJ II J I Page 21 of 23 Go Back Full Screen Close References [1] I.E. BAZILEVIĆ, On a case of integrability in quadratures of the LoewnerKuarev equation, Mat. Sb., 37 (1955), 471–476. [2] P.N. CHICHRA, New subclass of the class of close-to-convex functions, Proc. Amer. Math. Soc., 62(1) (1977), 37–43. [3] S.S. DING, Y. LING AND G.J. BAO, Some properties of a class of analytic functions, J. of Math. Anal. Appl., 195 (1995), 71–81. [4] M. FEKETE AND G. SZEGÖ, Eine Bermerkung über ungerade schlichte Functionen, J. London Math. Soc., 8 (1933), 85–89. [5] A.W. GOODMAN, Univalent Functions, Vol. 1, Florida, Mariner Publishing Co., 1983. [6] CHUNYI GAO, Fekete-Szegö problem for strongly Bazilevic̆ functions, Northeast Math. J., 12(4) (1996), 469–474. [7] F.R. KEOGH AND E.P. MERKS, A coefficient inequality for certain classes of analytic functions, Proc. Amer. Math. Soc., 20(1) (1969), 8–12. [8] W. KOEPF, On the Fekete-Szegö problem for close-to-convex functions, Proc. Amer. Math. Soc., 101 (1987), 89–95. [9] M.S. LIU, The Radius of univalence for certain class of analytic functions, In: Lu Jianke and Wen Guochun eds, Boundary Value Problems, Integral Equations and Related Problems, Singapore: World Scientific Publishing, 2000, 122–128. [10] M.S. LIU, Properties for some subclasses of analytic functions, Bulletin of the Institute of Math. Acdaemia Sinica, 30(1) (2002), 9–26. Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 22 of 23 Go Back Full Screen Close [11] M.S. LIU, On certain subclass of analytic functions, J. of South China Normal Univ., 4 (2002), 15–20 (Chinese). [12] Z.T. LI AND M.S. LIU, The functional of coefficients for a class of analytic functions, J. of South China Normal Univ., (3) (2005), 86–91 (Chinese). [13] M.S. LIU, The Fekete-Szegö inequality for certain class of analytic functions, Acta Math. Scientia, 22A(1) (2002), 8–14 (Chinese). [14] R.R. LONDON, Fekete-Szegö inequalities for close-to-convex functions, Proc. Amer. Math. Soc., 117(4) (1993), 947–950. [15] M. DARUS, The Fekete-Szegö theorem for close-to-convex functions of the class KSH (α, β)[J], Acta Math. Academiae Paedagogicae Nyíregyháziensis, 18 (2002), 13–18. [16] S.S. MILLER AND P.T. MOCANU, Univalent solutions of Briot-Bouquet differential subordination, J. Differential Eqns., 58 (1985), 297–309. [17] J. PATEL, On certain subclass of p−valently Bazilevic functions, J. of Inequalities in Pure and Applied Math., 6(1) (2005), Art. 16. [18] C. POMMERENK, Univalent Functions. With a chapter on quadratic differentials by Gerd Jensen. Studia Mathematica/Mathematische Lehrbücher. Band XXV. Göttingen: Vandenhoeck & Ruprecht,1975. [19] R. SINGH, On Bazilevic functions, Proc. Amer. Math. Sci., 38 (1973), 261– 267. [20] H.M. SRIVASTAVA, A.K. MISHRA AND M.K. DAS, The Fekete-Szegö problem for a subclass of close-to-convex functions, Complex Variables Theory Appl., 44 (2001), 145–163 Subclass of Bazilevič Functions Dong Guo and Ming-Sheng Liu vol. 8, iss. 1, art. 12, 2007 Title Page Contents JJ II J I Page 23 of 23 Go Back Full Screen Close