GENERAL SYSTEM OF STRONGLY PSEUDOMONOTONE NONLINEAR VARIATIONAL INEQUALITIES BASED ON PROJECTION SYSTEMS Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma R. U. VERMA Department of Mathematics, University of Toledo Toledo, Ohio 43606, USA EMail: verma99@msn.com Received: 26 February, 2006 Accepted: 11 December, 2006 Communicated by: R.N. Mohapatra 2000 AMS Sub. Class.: 49J40, 65B05, 47H20. Key words: Strongly pseudomonotone mappings, Approximation solvability, Projection methods, System of nonlinear variational inequalities. Abstract: Let K1 and K2 , respectively, be non empty closed convex subsets of real Hilbert spaces H1 and H2 . The Approximation − solvability of a generalized system of nonlinear variational inequality (SN V I) problems based on the convergence of projection methods is discussed. The SNVI problem is stated as follows: find an element (x∗ , y ∗ ) ∈ K1 × K2 such that hρS(x∗ , y ∗ ), x − x∗ i ≥ 0, ∀x ∈ K1 and for ρ > 0, hηT (x∗ , y ∗ ), y − y ∗ i ≥ 0, ∀y ∈ K2 and for η > 0, where S : K1 × K2 → H1 and T : K1 × K2 → H2 are nonlinear mappings. vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 1 of 19 Go Back Full Screen Close Contents 1 Introduction 3 2 General Projection Methods 7 Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 2 of 19 Go Back Full Screen Close 1. Introduction Projection-like methods in general have been one of the most fundamental techniques for establishing the convergence analysis for solutions of problems arising from several fields, such as complementarity theory, convex quadratic programming, and variational problems. There exists a vast literature on approximation-solvability of several classes of variational/hemivariational inequalities in different space settings. The author [6, 7] introduced and studied a new system of nonlinear variational inequalities in Hilbert space settings. This class encompasses several classes of nonlinear variational inequality problems. In this paper we intend to explore, based on a general system of projection-like methods, the approximation-solvability of a system of nonlinear strongly pseudomonotone variational inequalities in Hilbert spaces. The obtained results extend/generalize the results in [1], [5] – [7] to the case of strongly pseudomonotone system of nonlinear variational inequalities. Approximation solvability of this system can also be established using the resolvent operator technique but in the more relaxed setting of Hilbert spaces. For more details, we refer the reader to [1] – [10]. Let H1 and H2 be two real Hilbert spaces with the inner product h·, ·i and norm k · k. Let S : K1 × K2 → H1 and T : K1 × K2 → H2 be any mappings on K1 × K2 , where K1 and K2 are nonempty closed convex subsets of H1 and H2 , respectively. We consider a system of nonlinear variational inequality (abbreviated as SNVI) problems: determine an element (x∗ , y ∗ ) ∈ K1 × K2 such that (1.1) hρS(x∗ , y ∗ ), x − x∗ i ≥ 0 ∀x ∈ K1 (1.2) hηT (x∗ , y ∗ ), y − y ∗ i ≥ 0 ∀y ∈ K2 , where ρ, η > 0. Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 3 of 19 Go Back Full Screen Close The SNVI (1.1)−(1.2) problem is equivalent to the following projection formulas x∗ = Pk [x∗ − ρS(x∗ , y ∗ )] for ρ > 0 y ∗ = Qk [y ∗ − ηT (x∗ , y ∗ )] for η > 0, where Pk is the projection of H1 onto K1 and QK is the projection of H2 onto K2 . We note that the SNVI (1.1)−(1.2) problem extends the NVI problem: determine an element x∗ ∈ K1 such that Strongly Pseudomonotone Nonlinear Variational Inequalities hS(x∗ ), x − x∗ i ≥ 0, ∀x ∈ K1 . (1.3) R. U. Verma vol. 8, iss. 1, art. 6, 2007 Also, we note that the SNVI (1.1) − (1.2) problem is equivalent to a system of nonlinear complementarities (abbreviated as SNC): find an element (x∗ , y ∗ ) ∈ K1 × K2 such that S(x∗ , y ∗ ) ∈ K1∗ , T (x∗ , y ∗ ) ∈ K2∗ , and hρS(x∗ , y ∗ ), x∗ i = 0 for (1.4) ∗ ∗ ∗ hηT (x , y ), y i = 0 for (1.5) Contents ρ > 0, η > 0, II J I Go Back K1∗ = {f ∈ H1 : hf, xi ≥ 0, ∀x ∈ K1 }. Full Screen K2∗ = {g ∈ H2 : hg, yi ≥ 0, ∀g ∈ K2 }. Close Now, we recall some auxiliary results and notions crucial to the problem on hand. Lemma 1.1. For an element z ∈ H, we have and JJ Page 4 of 19 where K1∗ and K2∗ , respectively, are polar cones to K1 and K2 defined by x∈K Title Page hx − z, y − xi ≥ 0, ∀y ∈ K if and only if x = Pk (z). Lemma 1.2 ([3]). Let {αk }, {β k }, and {γ k } be three nonnegative sequences such that αk+1 ≤ (1 − tk )αk + β k + γ k for k = 0, 1, 2, ..., P P∞ k k k k k where tk ∈ [0, 1], ∞ k=0 t = ∞, β = o(t ), and k=0 γ < ∞. Then α → 0 as k → ∞. A mapping T : H → H from a Hilbert space H into H is called monotone if hT (x)−T (y), x−yi ≥ 0 for all x, y ∈ H. The mapping T is (r)−strongly monotone if for each x, y ∈ H, we have hT (x) − T (y), x − yi ≥ r||x − y||2 for a constant r > 0. This implies that kT (x) − T (y)k ≥ rkx − yk, that is, T is (r)-expansive, and when r = 1, it is expansive. The mapping T is called (s)-Lipschitz continuous (or Lipschitzian) if there exists a constant s ≥ 0 such that kT (x) − T (y)k ≤ skx − yk, ∀ x, y ∈ H. T is called (µ)-cocoercive if for each x, y ∈ H, we have hT (x) − T (y), x − yi ≥ µ||T (x) − T (y)||2 for a constant µ > 0. Clearly, every (µ)-cocoercive mapping T is ( µ1 )-Lipschitz continuous. We can easily see that the following implications on monotonicity, strong monotonicity and expansiveness hold: Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 5 of 19 Go Back Full Screen strong monotonicity ⇒ expansiveness ⇓ monotonicity Close T is called relaxed (γ)-cocoercive if there exists a constant γ > 0 such that hT (x) − T (y), x − yi ≥ (−γ)kT (x) − T (y)k2 , ∀x, y ∈ H. T is said to be (r)-strongly pseudomonotone if there exists a positive constant r such that hT (y), x − yi ≥ 0 ⇒ hT (x), x − yi ≥ r kx − yk2 , ∀x, y ∈ H. T is said to be relaxed (γ, r)-cocoercive if there exist constants γ,r > 0 such that hT (x) − T (y), x − yi ≥ (−γ) kT (x) − T (y)k2 + r kx − yk2 . Strongly Pseudomonotone Nonlinear Variational Inequalities Clearly, it implies that hT (x) − T (y), x − yi ≥ (−γ) kT (x) − T (y)k2 , R. U. Verma vol. 8, iss. 1, art. 6, 2007 that is, T is relaxed (γ)-cocoercive. T is said to be relaxed (γ, r)-pseudococoercive if there exist positive constants γ and r such that hT (y), x − yi ≥ 0 ⇒ hT (x), x − yi ≥ (−γ) kT (x) − T (y)k2 +r kx − yk2 , Thus, we have following implications: ⇒ strong (r)-pseudomonotonicity (r)-strong monotonicity ⇓ relaxed (γ, r)-cocoercivity ⇓ relaxed (γ, r)-pseudococoercivity Title Page Contents ∀x, y ∈ H. JJ II J I Page 6 of 19 Go Back Full Screen Close 2. General Projection Methods This section deals with the convergence of projection methods in the context of the approximation-solvability of the SNVI (1.1) − (1.2) problem. Algorithm 1. For an arbitrarily chosen initial point (x0 , y 0 ) ∈ K1 × K2 , compute the sequences {xk } and {y k } such that x k+1 k k k k k k k k k = (1 − a − b )x + a Pk [x − ρS(x , y )] + b u y k+1 = (1 − αk − β k )y k + αk QK [y k − ηT (xk , y k )] + β k v k , where PK is the projection of H1 onto K1 , QK is the projection of H2 onto K2 , ρ, η > 0 are constants, S : K1 × K2 → H1 and T : K1 × K2 → H2 are any two mappings, and uk and v k , respectively, are bounded sequences in K1 and K2 . The sequences {ak }, {bk }, {αk }, and {β k } are in [0, 1] with (k ≥ 0) 0 ≤ ak + bk ≤ 1, 0 ≤ αk + β k ≤ 1. Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Algorithm 2. For an arbitrarily chosen initial point (x0 , y 0 ) ∈ K1 × K2 , compute the sequences {xk } and {y k } such that Page 7 of 19 xk+1 = (1 − ak − bk )xk + ak Pk [xk − ρS(xk , y k )] + bk uk Go Back y k+1 = (1 − ak − bk )y k + ak QK [y k − ηT (xk , y k )] + bk v k , Full Screen where PK is the projection of H1 onto K1 , QK is the projection of H2 onto K2 , ρ, η > 0 are constants, S : K1 × K2 → H1 and T : K1 × K2 → H2 are any two mappings, and uk and v k , respectively, are bounded sequences in K1 and K2 . The sequences {ak } and {bk }, are in [0, 1] with (k ≥ 0) Close 0 ≤ ak + bk ≤ 1. Algorithm 3. For an arbitrarily chosen initial point (x0 , y 0 ) ∈ K1 × K2 , compute the sequences {xk } and {y k } such that xk+1 = (1 − ak )xk + ak Pk [xk − ρS(xk , y k )] y k+1 = (1 − ak )y k + ak QK [y k − ηT (xk , y k )], where PK is the projection of H1 onto K1 , QK is the projection of H2 onto K2 , ρ, η > 0 are constants, S : K1 × K2 → H1 and T : K1 × K2 → H2 are any two mappings. The sequence {ak } ∈ [0, 1] for k ≥ 0. We consider, based on Algorithm 2, the approximation solvability of the SNVI (1.1) − (1.2) problem involving strongly pseudomonotone and Lipschitz continuous mappings in Hilbert space settings. Theorem 2.1. Let H1 and H2 be two real Hilbert spaces and, K1 and K2 , respectively, be nonempty closed convex subsets of H1 and H2 . Let S : K1 × K2 → H1 be strongly (r)− pseudomonotone and (µ)−Lipschitz continuous in the first variable and let S be (ν)−Lipschitz continuous in the second variable. Let T : K1 × K2 → H2 be strongly (s)−pseudomonotone and (β)−Lipschitz continuous in the second variable and let T be (τ )−Lipschitz continuous in the first variable. Let k · k∗ denote the norm on H1 × H2 defined by k(x, y)k∗ = (kxk + kyk) ∀(x, y) ∈ H1 × H2 . Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 8 of 19 Go Back Full Screen In addition, let s 1 − 2ρr + ρ + θ= s σ= 1 − 2ηr + η + ρµ2 2 ηβ 2 2 Close + ρ2 µ 2 + ητ < 1 + η 2 β 2 + ρν < 1, let (x∗ , y ∗ ) ∈ K1 × K2 form a solution to the SNVI (1.1) − (1.2) problem, and let sequences {xk }, and {y k } be generated by Algorithm 2. Furthermore, let (i) hS(x∗ , y k ), xk − x∗ i ≥ 0; (ii) hT (xk , y ∗ ), y k − y ∗ i ≥ 0; (iii) 0 ≤ ak + bk ≤ 1; P P∞ k k (iv) ∞ k=0 a = ∞, and k=0 b < ∞; (v) 0 < ρ < 2r µ2 and 0 < η < Strongly Pseudomonotone Nonlinear Variational Inequalities 2s . β2 R. U. Verma vol. 8, iss. 1, art. 6, 2007 Then the sequence {xk , y k } converges to (x∗ , y ∗ ). Proof. Since (x∗ , y ∗ ) ∈ K1 ×K2 forms a solution to the SNVI (1.1)−(1.2) problem, it follows that x∗ = PK [x∗ − ρS(x∗ , y ∗ )] and y ∗ = QK [x∗ − ηT (x∗ , y ∗ )]. Contents Applying Algorithm 2, we have (2.1) kxk+1 − x∗ k k k k k k k k ∗ k k k k k = k(1 − a − b )x + a PK [x − ρS(x , y )] + b u ∗ ∗ k ∗ k k II J I k ∗ Go Back ≤ (1 − a − b )kx − x k k JJ Page 9 of 19 ∗ − (1 − a − b )x − a PK [x − ρS(x , y )] − b x k k Title Page Full Screen k k ∗ ∗ ∗ + a kPK [x − ρS(x , y )] − PK [x − ρS(x , y )]k + M b ≤ (1 − a )kxk − x∗ k + ak kxk − x∗ − ρ[S(xk , y k ) − S(x∗ , y k ) k + S(x∗ , y k ) − S(x∗ , y ∗ )]k + M bk ≤ (1 − ak )kxk − x∗ k + ak kxk − x∗ − ρ[S(xk , y k ) − S(x∗ , y k )]k + ρk[S(x∗ , y k ) − S(x∗ , y ∗ )]k + M bk , k Close where M = max{sup kuk − x∗ k, sup kv k − y ∗ k} < ∞. Since S is strongly (r)− pseudomonotone and (µ)−Lipschitz continuous in the first variable, and S is (ν)−Lipschitz continuous in the second variable, we have in light of (i) that (2.2) kxk − x∗ − ρ[S(xk , y k ) − S(x∗ , y k )]k2 Strongly Pseudomonotone Nonlinear Variational Inequalities = kxk − x∗ k2 − 2ρhS(xk , y k ) − S(x∗ , y k ), xk − x∗ i R. U. Verma + ρ2 kS(xk , y k ) − S(x∗ , y k )k2 vol. 8, iss. 1, art. 6, 2007 = kxk − x∗ k2 − 2ρhS(xk , y k ), xk − x∗ i + 2ρhS(x∗ , y k ), xk − x∗ i + ρ2 kS(xk , y k ) − S(x∗ , y k )k2 Title Page ≤ kxk − x∗ k2 − 2ρrkxk − x∗ k2 + ρ2 µ2 kxk − x∗ k2 Contents + 2ρhS(x∗ , y k ), xk − x∗ i ≤ kxk − x∗ k2 − 2ρrkxk − x∗ k2 + ρ2 µ2 kxk − x∗ k2 + 2ρhS(x∗ , y k ), xk − x∗ i = [1 − 2ρr + ρ2 µ2 ]kxk − x∗ k2 + 2ρhS(x∗ , y k ), xk − x∗ i. JJ II J I Page 10 of 19 Go Back On the other hand, we have Full Screen ∗ k k ∗ ∗ k 2 k ∗ 2 2ρhS(x , y ), x − x i ≤ ρ[kS(x , y )k + kx − x k ] and (2.3) kS(x∗ , y k )k2 1 = kS(x∗ , y k ) − S(xk , y k )k2 − 2[kS(xk , y k )k2 2 Close 1 − kS(xk , y k ) + S(x∗ , y k )k2 2 1 ≤ kS(x∗ , y k ) − S(xk , y k )k2 − 2[kS(xk , y k )k2 2 1 k k ∗ k 2 − | kS(x , y ) − S(x , y )k | ] 2 1 ≤ kS(x∗ , y k ) − S(xk , y k )k2 2 µ2 k ≤ kx − x∗ k2 , 2 where kS(xk , y k )k2 − 1 | kS(xk , y k ) − S(x∗ , y k )k |2 > 0. 2 Therefore, we get 2 ρµ ∗ k k ∗ 2ρhS(x , y ), x − x i ≤ ρ + kxk − x∗ k2 . 2 It follows that 2 ρµ k ∗ k k ∗ k 2 2 kx −x −ρ[S(x , y )−S(x , y )]k ≤ 1 − 2ρr + ρ + + (ρµ) kxk −x∗ k2 . 2 Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 11 of 19 Go Back Full Screen Close As a result, we have (2.4) kxk+1 − x∗ k ≤ (1 − ak )kxk − x∗ k + ak θkxk − x∗ k + ak ρνky k − y ∗ k + M bk , r 2 where θ = 1 − 2ρr + ρ + ρµ2 + ρ2 µ2 . Similarly, we have (2.5) y k+1 − y ∗ ≤ (1 − ak )ky k − y ∗ k + ak σky k − y ∗ k + ak ητ kxk − x∗ k + M bk , r where σ = 1 − 2ηr + η + ηβ 2 2 + η2β 2. It follows from (2.4) and (2.5) that (2.6) kx k+1 ∗ − x k + ky k+1 Strongly Pseudomonotone Nonlinear Variational Inequalities ∗ −y k ≤ (1 − ak )kxk − x∗ k + ak θkxk − x∗ k + ak ητ kxk − x∗ k + M bk + (1 − ak )ky k − y ∗ k + ak σky k − y ∗ k + ak ρνky k − y ∗ k + M bk = [1 − (1 − δ)ak ](kxk − x∗ k + ky k − y ∗ k) + 2M bk , where δ = max{θ + ητ , σ + ρν} and H1 × H2 is a Banach space under the norm k · k∗ . If we set αk = kxk − x∗ k + ky k − y ∗ k, β k = 2M bk tk = (1 − δ)ak , for k = 0, 1, 2, ..., in Lemma 1.2, and apply (iii) and (iv), we conclude that kxk − x∗ k + ky k − y ∗ k → 0 R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 12 of 19 Go Back Full Screen Close as k → ∞. Hence, kxk+1 − x∗ k + ky k+1 − y ∗ k → 0. Consequently, the sequence {(xk , y k )} converges strongly to (x∗ , y ∗ ), a solution to the SNVI (1.1) − (1.2) problem. This completes the proof. Note that the proof of the following theorem follows rather directly without using Lemma 1.2. Theorem 2.2. Let H1 and H2 be two real Hilbert spaces and, K1 and K2 , respectively, be nonempty closed convex subsets of H1 and H2 . Let S : K1 × K2 → H1 be strongly (r)− pseudomonotone and (µ)−Lipschitz continuous in the first variable and let S be (ν)−Lipschitz continuous in the second variable. Let T : K1 × K2 → H2 be strongly (s)−pseudomonotone and (β)−Lipschitz continuous in the second variable and let T be (τ )−Lipschitz continuous in the first variable. Let k · k∗ denote the norm on H1 × H2 defined by k(x, y)k∗ = (kxk + kyk) Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 ∀(x, y) ∈ H1 × H2 . Title Page In addition, let s θ= 1 − 2ρr + ρ + s σ= 1 − 2ηr + η + ρµ2 2 ηβ 2 Contents 2 + ρ2 µ 2 + ητ < 1, + η 2 β 2 + ρν < 1, let (x∗ , y ∗ ) ∈ K1 × K2 form a solution to the SNVI (1.1) − (1.2) problem, and let sequences {xk }, and {y k } be generated by Algorithm 3. Furthermore, let (i) hS(x∗ , y k ), xk − x∗ i ≥ 0 (ii) hT (xk , y ∗ ), y k − y ∗ i ≥ 0 (iii) 0 ≤ ak ≤ 1 P k (iv) ∞ k=0 a = ∞ JJ II J I Page 13 of 19 Go Back Full Screen Close (v) 0 < ρ < 2r µ2 and 0 < η < 2s . β2 Then the sequence {xk , y k )} converges strongly to (x∗ , y ∗ ). Proof. Since (x∗ , y ∗ ) ∈ K1 ×K2 forms a solution to the SNVI (1.1)−(1.2) problem, it follows that x∗ = PK [x∗ − ρS(x∗ , y ∗ )] and y ∗ = QK [x∗ − ηT (x∗ , y ∗ )]. Applying Algorithm 3, we have Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma (2.7) kxk+1 − x∗ k vol. 8, iss. 1, art. 6, 2007 = k(1 − ak )xk + ak PK [xk − ρS(xk , y k )] − (1 − ak )x∗ − ak PK [x∗ − ρS(x∗ , y ∗ )]k Title Page ≤ (1 − ak )kxk − x∗ k + ak kPK [xk − ρS(xk , y k )] − PK [x∗ − ρS(x∗ , y ∗ )]k ≤ (1 − ak )kxk − x∗ k + ak kxk − x∗ − ρ[S(xk , y k ) − S(x∗ , y k ) + S(x∗ , y k ) − S(x∗ , y ∗ )]k ≤ (1 − ak )kxk − x∗ k + ak kxk − x∗ − ρ[S(xk , y k ) − S(x∗ , y k )]k + ρk[S(x∗ , y k ) − S(x∗ , y ∗ )]k. Since S is strongly (r)− pseudomonotone and (µ)−Lipschitz continuous in the first variable, and S is (ν)−Lipschitz continuous in the second variable, we have in light of (i) that (2.8) kxk − x∗ − ρ[S(xk , y k ) − S(x∗ , y k )]k2 = kx − x∗ k2 − 2ρhS(xk , y k ) − S(x∗ , y k ), xk − x∗ i + ρ2 kS(xk , y k ) − S(x∗ , y k )k2 = kx − x∗ k2 − 2ρhS(xk , y k ), xk − x∗ i + 2ρhS(x∗ , y k ), xk − x∗ i Contents JJ II J I Page 14 of 19 Go Back Full Screen Close + ρ2 kS(xk , y k ) − S(x∗ , y k )k2 ≤ kxk − x∗ k2 − 2ρrkxk − x∗ k2 + ρ2 µ2 kxk − x∗ k2 + 2ρhS(x∗ , y k ), xk − x∗ i ≤ kxk − x∗ k2 − 2ρrkxk − x∗ k2 + ρ2 µ2 kxk − x∗ k2 + 2ρhS(x∗ , y k ), xk − x∗ i = [1 − 2ρr + ρ2 µ2 ]kxk − x∗ k2 + 2ρhS(x∗ , y k ), xk − x∗ i. Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma On the other hand, we have 2ρhS(x∗ , y k ), xk − x∗ i ≤ ρ[kS(x∗ , y k )k2 + kxk − x∗ k2 ] and (2.9) vol. 8, iss. 1, art. 6, 2007 Title Page kS(x∗ , y k )k2 ( 1 = kS(x∗ , y k ) − S(xk , y k )k2 2 ) 1 − 2 kS(xk , y k )k2 − kS(xk , y k ) + S(x∗ , y k )k2 2 ( 1 kS(x∗ , y k ) − S(xk , y k )k2 ≤ 2 ) 1 − 2 kS(xk , y k )k2 − | kS(xk , y k ) − S(x∗ , y k )k |2 2 µ2 1 ≤ kS(x∗ , y k ) − S(xk , y k )k2 ≤ kxk − x∗ k2 , 2 2 Contents JJ II J I Page 15 of 19 Go Back Full Screen Close where kS(xk , y k )k2 − 1 S(xk , y k ) − S(x∗ , y k )2 > 0. 2 Therefore, we get 2 ρµ 2ρhS(x , y ), x − x i ≤ ρ + kxk − x∗ k2 . 2 ∗ k ∗ k Strongly Pseudomonotone Nonlinear Variational Inequalities It follows that 2 ρµ 2 kx −x −ρ[S(x , y )−S(x , y )]k ≤ 1 − 2ρr + ρ + + (ρµ) kxk −x∗ k2 . 2 k ∗ k k ∗ k 2 As a result, we have R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page kxk+1 − x∗ || ≤ (1 − ak )kxk − x∗ k + ak θkxk − x∗ k + ak ρνky k − y ∗ k, r 2 where θ = 1 − 2ρr + ρ + ρµ2 + ρ2 µ2 . (2.10) Similarly, we have k+1 ∗ k ∗ k k ∗ k k It follows from (2.9) and (2.10) that (2.12) JJ II J I Page 16 of 19 k ∗ ky − y k ≤ (1 − a )ky − y k + a σky − y k + a ητ kx − x k, r 2 where σ = 1 − 2ηr + η + ηβ2 + η 2 β 2 . (2.11) Contents kxk+1 − x∗ k + ky k+1 − y ∗ k ≤ (1 − ak )kxk − x∗ k + ak θkxk − x∗ k + ak ητ kxk − x∗ k + (1 − ak )ky k − y ∗ k + ak σky k − y ∗ k + ak ρνky k − y ∗ k Go Back Full Screen Close = [1 − (1 − δ)ak ](kxk − x∗ k + ky k − y ∗ k) k Y ≤ [1 − (1 − δ)aj ](kx0 − x∗ k + ky 0 − y ∗ k), j=0 where δ = max{θ + ητ , σ + ρν} and H1 × H2 is a Banach space under the norm k · k∗ . P k Since δ < 1 and ∞ k=0 a is divergent, it follows that k Y lim [1 − (1 − δ)aj ] = 0 k→∞ Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma as k → ∞. vol. 8, iss. 1, art. 6, 2007 j=0 Title Page Therefore, kx k+1 ∗ − x k + ky k k k+1 ∗ − y k → 0, Contents ∗ ∗ and consequently, the sequence {(x , y )} converges strongly to (x , y ), a solution to the SN V I (1.1) − (1.2) problem. This completes the proof. JJ II J I Page 17 of 19 Go Back Full Screen Close References [1] S.S. CHANG, Y.J. CHO, AND J.K. KIM, On the two-step projection methods and applications to variational inequalities, Mathematical Inequalities and Applications, accepted. [2] Z. LIU, J.S. UME, AND S.M. KANG, Generalized nonlinear variational-like inequalities in reflexive Banach spaces, Journal of Optimization Theory and Applications, 126(1) (2005), 157–174. Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma [3] L. S. 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WITTMANN, Approximation of fixed points of nonexpansive mappings, Archiv der Mathematik, 58 (1992), 486–491. Contents JJ II J I Page 18 of 19 Go Back Full Screen Close [9] E. ZEIDLER, Nonlinear Functional Analysis and its Applications I, SpringerVerlag, New York, New York, 1986. [10] E. ZEIDLER, Nonlinear Functional Analysis and its Applications II/B, Springer-Verlag, New York, New York, 1990. Strongly Pseudomonotone Nonlinear Variational Inequalities R. U. Verma vol. 8, iss. 1, art. 6, 2007 Title Page Contents JJ II J I Page 19 of 19 Go Back Full Screen Close