Journal of Inequalities in Pure and Applied Mathematics http://jipam.vu.edu.au/ Volume 7, Issue 4, Article 139, 2006 A MULTIPLE HARDY-HILBERT INTEGRAL INEQUALITY WITH THE BEST CONSTANT FACTOR HONG YONG D EPARTMENT OF M ATHEMATICS G UANGDONG U NIVERSITY OF B USINESS S TUDY G UANGZHOU 510320 P EOPLE ’ S R EPUBLIC OF C HINA . hongyong59@sohu.com Received 14 September, 2005; accepted 14 December, 2005 Communicated by B. Yang A BSTRACT. In this paper, by introducing the norm kxkα (x ∈ Rn ), we give a multiple HardyHilbert’s integral inequality with a best constant factor and two parameters α, λ. Key words and phrases: Multiple Hardy-Hilbert integral inequality, the Γ-function, Best constant factor. 2000 Mathematics Subject Classification. 26D15. 1. I NTRODUCTION R∞ R∞ If p > 1, p1 + 1q = 1, f ≥ 0, g ≥ 0, 0 < 0 f p (x)dx < +∞, 0 < 0 g q (x)dx < +∞, then the well known Hardy-Hilbert integral inequality is given by (see [3]): Z ∞ p1 Z ∞ 1q Z ∞Z ∞ f (x)g(x) π p q f (x)dx g (x)dx , (1.1) dxdy < x+y 0 0 0 0 sin πp where the constant factor Z ∞ π sin( π p) ∞ Z (1.2) 0 0 where the constant factor is the best possible. Its equivalent form is: f (x) dx x+y π p p dy < sin π π p Z ∞ f p (x)dx, 0 p sin( π p) is also the best possible. Hardy-Hilbert’s inequality is valuable in harmonic analysis, real analysis and operator theory. In recent years, many valuable results (see [4] – [10]) have been obtained in the form of ISSN (electronic): 1443-5756 c 2006 Victoria University. All rights reserved. 273-05 2 H ONG YONG generalizations and improvements of Hardy-Hilbert’s inequality. In 1999, Kuang [5] gave a generalization with a parameter λ of (1.1) as follows: Z ∞ p1 Z ∞ 1q f (x)g(y) 1−λ p 1−λ q (1.3) dxdy < hλ (p) x f (x)dx x g (x)dx , xλ + y λ 0 0 0 0 n o h 1 i−1 1 π π where max p1 , 1q < λ ≤ 1, hλ (p) = π λ sin p pλ sin q qλ . Because of the constant factor hλ (p) being not the best possible, Yang [8] gave a new generalization of (1.1) in 2002 as follows: Z ∞Z ∞ f (x)g(y) (1.4) dxdy xλ + y λ 0 0 Z ∞ p1 Z ∞ 1q π (1−λ)(p−1) p (1−λ)(q−1) q < x f (x)dx x g (x)dx , 0 0 λ sin πp ∞ Z ∞ Z its equivalent form is: Z ∞ y (1.5) λ−1 ∞ Z 0 0 where the constant factors f (x) dx xλ + y λ π λ sin( π p) p p π dy < λ sin πp in (1.4) and π λ sin( π p) Z ∞ x(1−λ)(p−1) f p (x)dx, 0 p in (1.5) are all the best possible. At present, because of the requirement of higher-dimensional harmonic analysis and higherdimensional operator theory, multiple integral inequalities haveQbeen studied. Pn Hardy-Hilbert n 1 1 Hong [11] obtained: If a > 0, j=1 pj , λ > i=1 pi = 1, pi > 1, fi ≥ 0, ri = pi 1 n − 1 − r1i , i = 1, 2, . . . , n, then a Z ∞ (1.6) α ∞ n Y Γn−2 α1 ··· fi (x)dx1 · · · dxn ≤ n−1 P λ α Γ(λ) [ ni=1 (xi − αi )a ] i=1 α Z ∞ p1 n Y i 1 1 1 1 n−1−αλ pi × Γ 1− Γ λ− n−1− (t − α) fi dt . a r a r i i α i=1 Z 1 Afterwards, Bicheng Yang and Kuang Jichang etc. obtained some multiple Hardy-Hilbert integral inequalities (see [9, 6]). In this paper, by introducing the Γ-function, we generalize (1.3) and (1.4) into multiple Hardy-Hilbert integral inequalities with the best constant factors. 2. S OME L EMMAS First of all, we introduce the signs as: Rn+ = {x = (x1 , . . . , xn ) : x1 , . . . , xn > 0}, 1 kxkα = (xα1 + · · · + xαn ) α , J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 α > 0. http://jipam.vu.edu.au/ M ULTIPLE H ARDY-H ILBERT I NTEGRAL I NEQUALITY 3 Lemma 2.1 (see [1]). If pi > 0, ai > 0, αi > 0, i = 1, 2, . . . , n, Ψ(u) is a measurable function, then α n α1 Z Z xn x1 + ··· + (2.1) ... Ψ α1 α n x1 a1 an n x1 ,...,xn >0; a +···+( x ≤1 an ) 1 × xp11 −1 · · · xpnn −1 dx1 · · · dxn ap11 · · · apnn Γ αp11 · · · Γ αpnn Z 1 p1 pn +···+ α −1 n = Ψ(u)u α1 du. p1 pn 0 α1 · · · αn Γ α1 + · · · + αn where Γ(·) is the Γ-function. Lemma 2.2. If p > 1, p1 + 1q = 1, n ∈ Z+ , α > 0, λ > 0, setting the weight function ωα,λ (x, p, q) as: (n−λ)p 1 λq Z q 1 kxk kxk α α ωα,λ (x, p, q) = dy, 1 λ + kykλ kxk kykα p Rn α α + kykα then kxk(n−λ)(p−1) α ωα,λ (x, p, q) = (2.2) πΓn α1 sin πp λαn−1 Γ n α . Proof. By Lemma 2.1, we have ωα,λ (x, p, q) = (n−λ)(p−1)+ λ q kxkα (n−λ)(p−1)+ λ q = kxkα r α <r α y1 ,...,yn >0;y1α +···+yn y1 α r + ··· + h y1 α r kxkλα + r (n−λ)(p−1)+ λ q = kxkα = −(n−λ+ λ 1 q) kyk dy α λ λ kxkα + kykα Rn + Z Z lim ··· r→+∞ h × Z (n−λ)(p−1)+ λ q kxkα 1 yn α α r r Γ r→+∞ αn Γ lim 1 α αn−1 Γ 1−1 1 yn α α r + ··· + n n Γn i−(n−λ+ λq ) 1 α n α Z 1 r→+∞ 1 ru α 0 · · · yn1−1 dy1 · · · dyn −(n−λ+ λq ) n λ u α 1 −1 du kxkλα + ru α Z lim n iλ y 1 0 r λ 1 uλ− q −1 du λ +u kxkλα α Z ∞ n 1 λ Γ α (n−λ)(p−1)+ q 1 −1 λ− λ q du u = kxkα n λ λ αn−1 Γ α 0 kxkα + u Z ∞ Γn α1 1 1 −1 (n−λ)(p−1) p u = kxkα du n n−1 1 + u λα Γ α 0 Γn α1 1 1 (n−λ)(p−1) Γ = kxkα Γ 1− p p λαn−1 Γ αn J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 http://jipam.vu.edu.au/ 4 H ONG YONG = kxkα(n−λ)(p−1) πΓn α1 sin πp λαn−1 Γ n α , hence (2.2) is valid. Lemma 2.3. If p > 1, p1 + 1q = 1, n ∈ Z+ , α > 0, λ > 0, 0 < ε < λ(q − 1), setting ω̃α,λ (x, q, ε) as: Z (n−λ)(q−1)+n+ε − 1 q dy, ω̃α,λ (x, q, ε) = kyk α λ λ kxkα + kykα Rn + then we have ω̃α,λ (x, q, ε) = (2.3) −λ−ε kxkα q q Γn α1 λαn−1 Γ n α Γ 1 ε − p λq 1 ε Γ + . q λq Proof. Lemma 2.3 can be proved in the same manner as Lemma 2.2. 3. M AIN R ESULTS Theorem 3.1. If p > 1, Z 0< (3.1) Rn + 1 p + 1 q = 1, n ∈ Z+ , α > 0, λ > 0, f ≥ 0, g ≥ 0, and kxk(n−λ)(p−1) f p (x)dx α Z < ∞, 0< Rn + kxk(n−λ)(q−1) g q (x)dx < ∞, α then Z Z (3.2) Rn + Rn + πΓn α1 f (x)g(y) dxdy < kxkλα + kykλα sin πp λαn−1 Γ Z × Rn + Z (3.3) Rn + kykλ−n α where the constant factors Z Rn + n α ! p1 kxk(n−λ)(p−1) f p (x)dx α !p f (x) dx dy kxkλα + kykλα πΓn α1 < sin πp λαn−1 Γ 1 πΓn ( α ) n sin( π λαn−1 Γ( α ) p) J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 and ! 1q Z Rn + kxk(n−λ)(q−1) g q (x)dx α ; p Z n α Rn + 1 πΓn ( α ) n sin( π λαn−1 Γ( α ) p) kxk(n−λ)(p−1) f p (x)dx, α p are all the best possible. http://jipam.vu.edu.au/ M ULTIPLE H ARDY-H ILBERT I NTEGRAL I NEQUALITY 5 Proof. By Hölder’s inequality, we have Z Z f (x)g(y) A := dxdy λ λ n kxk + kyk Rn R α α + + n−λ 1 pqλ Z Z q kxk f (x) kxk α α = 1 1 λ + kykλ ) p n kykα p Rn R (kxk + + kykα α α n−λ 1 λ p kykα pq g(y) kykα dxdy × 1 1 kxkα (kxkλα + kykλα ) q kxkαq p1 (n−λ)p 1 λ Z Z q f p (x) kxkα q kxkα1 ≤ dxdy λ λ kxkα + kykα kykα Rn Rn + + kykαp 1q (n−λ)q 1 λ Z Z g q (x) kykαp kykα p × dxdy 1 λ λ kxkα + kykα kxkα Rn Rn + + kxkαq p1 (n−λ)p 1 λ Z Z q 1 kxkα q kxkα1 f p (x) dy dx = kxkλα + kykλα kykα p Rn Rn + + kykα 1q (n−λ)q 1 λp Z Z p 1 kykα kykα1 × g q (y) dx dy λ λ kxkα + kykα kxkα Rn Rn + + kxkαq ! p1 Z ! 1q Z f p (x)ωα,λ (x, p, q)dx = g q (y)ωα,λ (y, q, p)dy Rn + , Rn + according to the condition of taking equality in Hölder’s inequality, if this inequality takes the form of an equality, then there exist constants C1 and C2 , such that they are not all zero, and p 1 q (n−λ)p C1 f (x) kxkα 1 kxkλα + kykλα kykαp kxkα kykα q λq 1 p (n−λ)q C2 g (y) kykα = 1 kxkλα + kykλα kxkαq kykα kxkα λp , a.e. in Rn+ × Rn+ , C1 kxk(n−λ)(p−1)+n f p (x) = C2 kyk(n−λ)(q−1)+n g q (y) = C (constant), α α a.e. in Rn+ × Rn+ , it follows that which contradicts (3.1), hence we have Z A< ! p1 f p (x)ωα,λ (x, p, q)dx Rn + J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 Z ! 1q g q (y)ωα,λ (y, q, p)dy . Rn + http://jipam.vu.edu.au/ 6 H ONG YONG By Lemma 2.2 and sin π p = sin( πq ), we have p1 ! p1 Z πΓ kxk(n−λ)(p−1) f p (x)dx A< α n π n n−1 R+ sin p λα Γ α # 1q Z ! 1q " πΓn α1 kyk(n−λ)(q−1) g q (y)dy × α π n n−1 sin( q )λα Γ α Rn + ! p1 Z ! 1q Z πΓn α1 = kxk(n−λ)(p−1) f p (x)dx kxk(n−λ)(q−1) g q (x)dx . α α Rn Rn sin πp λαn−1 Γ αn + + 1 α n Hence (3.2) is valid. For 0 < a < b < ∞, setting ga,b (y) = R λ−n kykα Rn + f (x) λ dx kxkλ α +kykα p−1 , a < kykα < b, 0 < kykα ≤ a 0, Z g̃(y) = kykλ−n α Rn + f (x) dx λ kxkα + kykλα or kykα ≥ b, !p−1 , y ∈ Rn+ , by (3.1), for sufficiently small a > 0 and sufficiently large b > 0, we have Z q kyk(n−λ)(q−1) ga,b (y)dy < ∞. α 0< a<kykα <b Hence by (3.2), we have Z kyk(n−λ)(q−1) g̃ q (y)dy α a<kykα <b Z kykλ−n α = a<kykα <b Z kykλ−n α = a<kykα <b Z Z = Rn + Rn + Z Rn + Z Rn + f (x) dx kxkλα + kykλα f (x) dx λ kxkα + kykλα !p dy !p−1 Z Rn + ! f (x) dx dy kxkλα + kykλα f (x)ga,b (y) dxdy kxkλα + kykλα J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 http://jipam.vu.edu.au/ M ULTIPLE H ARDY-H ILBERT I NTEGRAL I NEQUALITY πΓn α1 < sin πp λαn−1 Γ Z × Rn + ! p1 Z n α 7 Rn + kxk(n−λ)(p−1) f p (x)dx α ! 1q q kyk(n−λ)(q−1) ga,b (y)dy α πΓn α1 = sin πp λαn−1 Γ Z × ! p1 Z n α Rn + kxk(n−λ)(p−1) f p (x)dx α kyk(n−λ)(q−1) g̃ q (y)dy α 1q , a<kykα <b it follows that Z g̃ q (y)dy kyk(n−λ)(q−1) α a<kykα <b n 1 α p πΓ < sin πp λαn−1 Γ Z n α Rn + kxk(n−λ)(p−1) f p (x)dx. α For a → 0+ , b → +∞, by (3.1), we obtain Z 0< Rn + ≤ kyk(n−λ)(q−1) g̃ q (y)dy α n 1 α p πΓ sin πp λαn−1 Γ Z n α Rn + kxk(n−λ)(p−1) f p (x)dx < ∞, α hence by (3.2), we have Z Rn + Z kykλ−n α Z Rn + f (x) dx λ kxkα + kykλα !p dy Z f (x)g̃(y) dxdy λ λ n kxk + kyk Rn R α α + + ! p1 Z ! 1q Z πΓn α1 < kxk(n−λ)(p−1) f p (x)dx kyk(n−λ)(q−1) g̃ q (y)dy α α n π n n n−1 R+ R+ sin p λα Γ α ! p1 Z πΓn α1 kxk(n−λ)(p−1) f p (x)dx = α n π Rn sin p λαn−1 Γ α + "Z !p # 1q Z f (x) kykλ−n × dx dy , α n kxkλα + kykλα R+ Rn + = J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 http://jipam.vu.edu.au/ 8 H ONG YONG it follows that Z Z λ−n kykα Rn + Rn + f (x) dx λ kxkα + kykλα < !p dy 1 α n p πΓ sin πp λαn−1 Γ Z n α Rn + kxk(n−λ)(p−1) f p (x)dx. α Hence (3.3) is valid. Remark 3.2. By (3.3), we can also obtain (3.2), hence (3.3) and (3.2) are equivalent. 1 πΓn ( α ) If the constant factor Cn,α (λ, p) := sin π λαn−1 in (3.2) is not the best possible, then n Γ( α (p) ) there exists a positive constant K < Cn,α (λ, p), such that Z Z f (x)g(y) (3.4) dxdy kxkλα + kykλα Rn Rn + + ! p1 Z ! 1q Z <K Rn + kxk(n−λ)(p−1) f p (x)dx α Rn + kyk(n−λ)(q−1) g q (y)dy α . In particular, setting f (x) = − kxkα (n−λ)(p−1)+n+ε p , g(y) = − kykα (n−λ)(q−1)+n+ε q , 0 < ε < λ(q − 1), (3.4) is still true. By the properties of limit, there exists a sufficiently small a > 0, such that Z Z (n−λ)(p−1)+n+ε (n−λ)(q−1)+n+ε − − 1 p q kxk kyk dxdy α α λ λ kxkα + kykα kxkα >a Rn + Z p1 (n−λ)(p−1) −(n−λ)(p−1)−n−ε <K kxkα kxkα dx kxkα >a Z kyk(n−λ)(q−1) kyk−(n−λ)(q−1)−n−ε dy α α × 1q kykα >a Z kxk−n−ε dx. α =K kxkα >a On the other hand, by Lemma 2.3, we have Z Z (n−λ)(p−1)+n+ε (n−λ)(q−1)+n+ε − − 1 p q kxk kyk dxdy α α λ + kykλ n kxk kxkα >a R+ α α Z Z (n−λ)(q−1)+n+ε −n+ λ − pε − 1 q q = kxkα kyk dydx α λ λ kxkα + kykα kxkα >a Rn + Z −n+ λ − ε = kxkα q p ω̃α,λ (x, q, ε)dx kxkα >a Z Γn α1 1 ε 1 ε Γ = − Γ + kxk−n−ε dx, α n n−1 p λq q λq λα Γ α kxkα >a hence we obtain Γn α1 λαn−1 Γ n α Γ J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 1 ε − p λq 1 ε Γ + < K. q λq http://jipam.vu.edu.au/ M ULTIPLE H ARDY-H ILBERT I NTEGRAL I NEQUALITY 9 For ε → 0+ , we have πΓn α1 Cn,α (λ, p) = sin πp λαn−1 Γ n α ≤ K, this contradicts the fact that K < Cn,α (λ, p).Hence the constant factor in (3.2) is the best possible. Since (3.3) and (3.2) are equivalent, the constant factor in (3.3) is also the best possible. Corollary 3.3. If p > 1, 1 p + Z 0< (3.5) 1 q = 1, n ∈ Z+ , α > 0, f ≥ 0, g ≥ 0, and Z p f (x)dx < ∞, 0< g q (x)dx < ∞, Rn + Rn + then Z Z (3.6) Rn + Rn + f (x)g(y) dxdy kxknα + kyknα πΓn α1 < sin πp nαn−1 Γ Z Z (3.7) Rn + Rn + f (x) dx n kxkα + kyknα !p ! p1 Z n f p (x)dx Rn + α ! 1q Z g q (x)dx ; Rn + p πΓn α1 dy < sin πp nαn−1 Γ Z n α f p (x)dx, Rn + where the constant factors in (3.6) and (3.7) are all the best possible. Proof. By taking λ = n in Theorem 3.1, (3.6) and (3.7) can be obtained. Corollary 3.4. If p > 1, 1 p + Z 0< (3.8) 1 q = 1, n ∈ Z+ , f ≥ 0, g ≥ 0, and Z p f (x)dx < ∞, 0< g q (x)dx < ∞, Rn + Rn + then Z Z (3.9) Rn + Rn + f (x)g(y) Pn P n n dxdy ( i=1 xi ) + ( ni=1 yi ) < n! sin Z Z (3.10) Rn + Rn + ! p1 Z π π p f (x) Pn P n n dx ( i=1 xi ) + ( ni=1 yi ) f p (x)dx Rn + !p ! 1q Z g q (x)dx ; Rn + p dy < Z π n! sin π p f p (x)dx, Rn + where the constant factors in (3.9) and (3.10) are all the best possible. Proof. By taking α = 1 in Corollary 3.3, (3.9) and (3.10) can be obtained. J. Inequal. Pure and Appl. Math., 7(4) Art. 139, 2006 http://jipam.vu.edu.au/ 10 H ONG YONG R EFERENCES [1] G.M. FICHTINGOLOZ, A Course in Differential and Integral Calculus, Renmin Jiaoyu Publishers, Beijing, 1957. [2] MINGZHE GAO AND TAN LI, Some improvements on Hilbert’s integral inequality, J. Math. Anal. Appl., 229 (1999), 682–689. [3] G.H. HARDY, J.E. LITTLEWOOD AND G. POLYA, Inequalities, Cambridge Univ. Press, London, 1952. [4] A.E. INGHAM, A note on Hilbert’s inequality, J. London Math. 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