Journal of Inequalities in Pure and Applied Mathematics http://jipam.vu.edu.au/ Volume 6, Issue 1, Article 4, 2005 ON THE APPROXIMATION OF LOCALLY BOUNDED FUNCTIONS BY OPERATORS OF BLEIMANN, BUTZER AND HAHN JESÚS DE LA CAL AND VIJAY GUPTA D EPARTAMENTO DE M ATEMÁTICA A PLICADA Y E STADÍSTICA E I NVESTIGACIÓN O PERATIVA FACULTAD DE C IENCIAS U NIVERSIDAD DEL PAÍS VASCO A PARTADO 644, 48080 B ILBAO , S PAIN mepcaagj@lg.ehu.es S CHOOL OF A PPLIED S CIENCES N ETAJI S UBHAS I NSTITUTE OF T ECHNOLOGY S ECTOR 3 DWARKA , N EW D ELHI -110045, I NDIA vijay@nsit.ac.in Received 25 November, 2004; accepted 29 December, 2004 Communicated by A. Lupaş A BSTRACT. We estimate the rate of the pointwise approximation by operators of Bleimann, Butzer and Hahn of locally bounded functions, and of functions having a locally bounded derivative. Key words and phrases: Operators of Bleimann, Butzer and Hahn, Locally bounded function, Function of bounded variation, Total variation, Rate of convergence, Binomial distribution. 2000 Mathematics Subject Classification. 41A20, 41A25, 41A36. 1. I NTRODUCTION AND M AIN R ESULTS Bleimann, Butzer and Hahn [1] introduced the Bernstein type operator Ln over the interval [0, ∞) given by n X k Ln (f, x) := f bn,k (x), x ≥ 0, n = 1, 2, . . . , n−k+1 k=0 where f is a real function on [0, ∞), and n k n−k x (1.1) bn,k (x) := p x qx , px := , k 1+x qx := 1 − px = ISSN (electronic): 1443-5756 c 2005 Victoria University. All rights reserved. J. de la Cal was supported by the Spanish MCYT, Proyecto BFM2002-04163-C02-02, and by FEDER.. 228-04 1 . 1+x 2 J ESÚS DE LA C AL AND V IJAY G UPTA The approximation of uniformly continuous functions by these operators has been considered in [1] – [4]. For other properties of Ln (preservation of global smoothness, preservation of φvariation, behavior of the iterates, etc.) we refer, for instance, to [4] – [10]. In some of the mentioned works, the results are achieved by using probabilistic methods. This comes from the fact that Ln is an operator of probabilistic type. We can actually write Ln (f, x) = Ef (Zn,x ), where E denotes mathematical expectation, and Zn,x is the random variable given by Zn,x := (1.2) Sn,x , n − Sn,x + 1 Sn,x := ξ1,x + · · · + ξn,x , where ξ1,x , ξ2,x , . . . are independent random variables having the same Bernoulli distribution with parameter px , i.e., P (ξk,x = 1) = px = 1 − P (ξk,x = 0) (so that Sn,x has the binomial distribution with parameters n, px ). This probabilistic representation also plays a significant role in the present paper (for a more refined representation useful for other purposes, see [5, 6]). Here, we discuss the approximation of real functions f on the semi axis which are locally bounded, i.e., bounded on each finite subinterval of [0, ∞). In such a case, we set, for x > 0 and h ≥ 0, ωx+ (f ; h) := sup |f (t) − f (x)|, x≤t≤x+h ωx− (f ; h) := sup |f (t) − f (x)|, (x−h)+ ≤t≤x ωx (f ; h) := ωx+ (f ; h) + ωx− (f ; h), where (x − h)+ := max(x − h, 0), and we observe that these functions are (nonnegative and) nondecreasing on [0, ∞). In particular, every continuous function is locally bounded. Also, if f is locally of bounded variation, i.e., such that b _ (f ) < ∞, 0 ≤ a < b < ∞, a Wb where a (f ) stands for the total variation of f on the interval [a, b], then f is locally bounded, and we obviously have x+h _ (f ), 0 ≤ h ≤ x. ωx (f ; h) ≤ x−h This kind of problem has been already considered for other Bernstein-type operators (see, for instance, [11] – [14] and the references therein). Our main results are stated as follows. Theorem 1.1. Let g be a real locally bounded function on [0, ∞) such that g(t) = O(tr ) (t → ∞), for some r = 1, 2, . . . . If g is continuous at x > 0, then, for n large enough, we have n 7(1 + x)2 X 1 x (1.3) |Ln (g, x) − g(x)| ≤ + Or,x . ωx g; √ n (n + 2)x k=1 k In the following statements (and throughout the paper), we use the notations: f ∗ (x) := f (x+) − f (x−) f (x+) + f (x−) f˜(x) := , 2 J. Inequal. Pure and Appl. Math., 6(1) Art. 4, 2005 http://jipam.vu.edu.au/ A PPROXIMATION O F L OCALLY B OUNDED F UNCTIONS B Y O PERATORS 3 fx := (f − f (x−))1[0,x) + (f − f (x+))1(x,∞) (1A being the indicator function of the set A), provided that the lateral limits f (x+) and f (x−) exist (such a condition is fulfilled when f is locally of bounded variation). We also use the symbol bac to indicate the integral part of the real number a. Theorem 1.2. Let f be a real locally bounded function on [0, ∞) such that f (t) = O(tr ) (t → ∞), for some r = 1, 2, . . . . If x > 0, and f (x+) and f (x−) exist, then we have for n large enough Ln (f, x) − f˜(x) ≤ ∆n,x (fx ) + 1.6 + x + 2.6 x2 |f ∗ (x)| n,x (1 + x) √ · + √ |f (x) − f (x−)|, 2 nx(1 + x) 2enx where ∆n,x (fx ) is the right-hand side of (1.3) with g replaced by fx , and ( 1 if (n + 1)px ∈ {1, 2, . . . , n} n,x := 0 otherwise. Theorem 1.3. Let g be a real function on [0, ∞) such that g(t) = O(tr ) r = 1, 2, . . . , and having the form Z t g(t) = c + f (u) du, t ≥ 0, (t → ∞), for some 0 where c is a constant and f is measurable and locally bounded on [0, ∞). If x > 0, and f (x+) and f (x−) exist, then we have for n large enough √ + x) ∗ Ln (g, x) − g(x) − x(1 √ f (x) 2πn √ nc x 2 bX 5(1 + x) ≤ ωx fx ; +|f ∗ (x)| ox n−1/2 +Or,x (n−1 ). n + 2 k=1 k The proofs of the preceding theorems are given in Sections 3 – 5. In Section 2, we collect the necessary auxiliary results. Some remarks on moments close the paper. 2. AUXILIARY R ESULTS ∗ In the following lemma, Φ denotes the standard normal distribution function, and Fn,x stands √ ∗ npx qx ,, where Sn,x is the same as in for the distribution function of Sn,x := (Sn,x − npx ) (1.2). Such a lemma is nothing but the application of the well-known Berry-Esseen theorem (cf. [15]) to the situation at hand. Lemma 2.1. We have, for x > 0 and n ≥ 1, sup −∞<t<∞ ∗ |Fn,x (t) − Φ(t)| ≤ 0.8(1 + x2 ) 0.8(p3x qx + px qx3 ) √ √ = . n(px qx )3/2 nx(1 + x) Lemma 2.2. Let x > 0 and n ≥ 1. Then, we have: (a) Ln ((· − x)2 , x) = E(Zn,x − x)2 ≤ J. Inequal. Pure and Appl. Math., 6(1) Art. 4, 2005 3x(1 + x)2 . n+2 http://jipam.vu.edu.au/ 4 J ESÚS DE LA C AL AND V IJAY G UPTA (b) P (Zn,x ≤ x − h) + P (Zn,x ≥ x + h) ≤ 3x(1 + x)2 , (n + 2)h2 h > 0. (c) r |P (Zn,x > x) − P (Zn,x ≤ x)| ≤ 1.6(1 + x2 ) x . +√ n nx(1 + x) (d) Ln ((· − x), x) = E(Zn,x − x) = −xpnx = ox (n−1 ), (n → ∞). (e) √ Ln (| · −x|, x) = E|Zn,x − x| = 2x(1 + x) √ + ox (n−1/2 ), πn (n → ∞). Proof. Part (a) was shown in [10]. Part (b) follows from (a) and the fact that, by Markov’s inequality, P (Zn,x ≤ x − h) + P (Zn,x E(Zn,x − x)2 ≥ x + h) = P (|Zn,x − x| ≥ h) ≤ . h2 To show (c), observe that |P (Zn,x > x) − P (Zn,x ≤ x)|= |1 − 2P (Zn,x ≤ x)| = |1 − 2P (Sn,x ≤ (n + 1)px )| r x ∗ = 1 − 2Fn,x n r r r x x x ∗ + 1 − 2Φ ≤ 2 Φ − Fn,x . n n n Thus, the conclusion in part (c) follows from Lemma 2.1 and the fact that (cf. [16]) 2 1/2 0 < 2Φ(t) − 1 ≤ 1 − e−t ≤ t, (t > 0). Part (d) is immediate. Finally, to show (e), let m := b(n + 1)px c. We have m X k Ln (| · −x|, x) − Ln ((· − x), x)= 2 x− bn,k (x) n−k+1 k=0 = 2x m X k=0 = 2x m X k=0 bn,k (x) − 2 m X k=1 bn,k (x) − 2x n! pkx qxn−k (k − 1)!(n − k + 1)! m−1 X bn,k (x) k=0 = 2x bn,m (x) √ 2x(1 + x) √ + ox (n−1/2 ), = πn (n → ∞), the last equality by [13, Lemma 1], and the conclusion follows from (d). J. Inequal. Pure and Appl. Math., 6(1) Art. 4, 2005 http://jipam.vu.edu.au/ A PPROXIMATION O F L OCALLY B OUNDED F UNCTIONS B Y O PERATORS 5 Lemma 2.3. Let x > 0 and r = 1, 2, . . . . Then, we have for all integers n such that (n + 1)(p2x − p3x/2 ) ≥ r, X k∈K r n o s−1 X kr r x (1 + x)r−s+2 n! b (x)≤ 12 r! · n,k (n − k + 1)r s n + r − s + 2 (n + r − s)! s=1 = Or,x (n−1 ), (n → ∞), r where the s are the Stirling numbers of the second kind, and K is the set of all integers k such that n ≥ k > (n − k + 1)2x (i.e., n ≥ k > (n + 1)p2x ). Proof. Using the well known identity r n o X r a(a − 1) · · · (a − s + 1), ar = s s=1 we can write r (2.1) X k∈K X nro kr b (x) = As , n,k (n − k + 1)r s s=1 where As := X k(k − 1) · · · (k − s + 1) (n − k + 1)r k∈K = X k∈K bn,k (x) 1 n! · pk q n−k . r (n − k + 1) (k − s)!(n − k)! x x Since r Y 1 n−k+i 1 = (n − k + 1)r i=1 n − k + i n − k + 1 r Y 1 i−1 = 1+ n−k+i n−k+1 i=1 ≤ r Y i=1 i r!(n − k)! = , n−k+i (n − k + r)! we have As ≤ r! X k∈K n! pkx qxn−k (k − s)!(n − k + r)! n! n−l−s pl+s x qx l!(n + r − s − l)! l∈Ks r!n!psx qx−r X n + r − s xl = (n + r − s)! l∈K l (1 + x)n+r−s s r!n!psx qx−r X n + r − s xl ≤ , (n + r − s)! l∈K 0 l (1 + x)n+r−s = r! X where Ks := {k − s : k ∈ K}, and K 0 stands for the set of all integers l such that n ≥ l > (n − l + 1)(3x/2) (observe that, by the assumption on n, we have Ks ⊂ K 0 ). The probabilistic J. Inequal. Pure and Appl. Math., 6(1) Art. 4, 2005 http://jipam.vu.edu.au/ 6 J ESÚS DE LA C AL AND V IJAY G UPTA interpretation of the last sum together with Lemma 2.2(b) yield r!n!xs (1 + x)r−s 3x As ≤ P Zn+r−s,x > (n + r − s)! 2 s−1 r−s+2 12 r!n!x (1 + x) (2.2) ≤ , (n + r − s)!(n + r − s + 2) and the conclusion follows from (2.1) and (2.2). Remark 2.4. The same procedure as in the preceding proof leads to the following upper bound for the integral moments of Ln (or Zn,x ): Ln (tr , x) = E(Zn,x )r n X kr b (x) = r n,k (n − k + 1) k=0 r n o X r n!xs (1 + x)r−s ≤ r! . s (n + r − s)! s=1 3. P ROOF OF T HEOREM 1.1 Without loss of generality, we assume that g(x) = 0. Denote by Kn,x the distribution function of Zn,x , i.e., X Kn,x (t) := P (Zn,x ≤ t) = bn,k (x) t ≥ 0. k≤(n−k+1)t We can write Ln (g, x) as the Lebesgue-Stieltjes integral Z Ln (g, x) = Eg(Zn,x ) = g(t) dKn,x (t) = 4 Z X [0,∞) j=1 g(t) dKn,x (t), Ij where x I1 := 0, x − √ , n x I3 := x + √ , 2x n I2 := and x x x − √ ,x + √ , n n I4 := (2x, ∞). We obviously have Z x |g(t)| dKn,x (t)≤ ωx g; √ dKn,x (t) n I2 I2 x ≤ ωx g; √ n n 1X x ≤ ωx g; √ . n k=1 k Z (3.1) On the other hand, from the asymptotic assumption on g, we have |g(t)| ≤ M tr , J. Inequal. Pure and Appl. Math., 6(1) Art. 4, 2005 t ≥ α, http://jipam.vu.edu.au/ A PPROXIMATION O F L OCALLY B OUNDED F UNCTIONS B Y O PERATORS 7 for some constants M > 0 and α ≥ 2x. Therefore, Z Z Z |g(t)| dKn,x (t)= + |g(t)| dKn,x (t) I4 (2x,α] (α,∞) X ≤ ωx+ (g; α − x)P (Zn,x > 2x) + M k>(n−k+1)α By Lemma 2.2(b) and Lemma 2.3, this shows that Z (3.2) |g(t)| dKn,x (t) = Or,x (n−1 ) kr bn,k (x). (n − k + 1)r (n → ∞). I4 Finally, using Lemma 2.2(b) and integration by parts (follow the same procedure as in the proof of Theorem 1 in [13]), we obtain Z Z |g(t)| dKn,x (t)≤ ωx− (g; x − t) dKn,x (t) I1 I1 # " Z x−x/√n − ωx (g; x − t) 3x(1 + x)2 ωx− (g; x) dt ≤ +2 (x − t)3 (n + 2) x2 0 n 6(1 + x)2 X − x ≤ ω g; √ (3.3) , (n + 2)x k=1 x k and, analogously, n 6(1 + x)2 X + x ω g; √ |g(t)| dKn,x (t) ≤ . (n + 2)x k=1 x k I3 Z (3.4) The conclusion follows from (3.1) – (3.4). 4. P ROOF OF T HEOREM 1.2 We can write, for t ≥ 0, f ∗ (x) f (t) − f˜(x) = fx (t) + σx (t) + (f (x) − f˜(x))δx (t), 2 where σx := −1[0,x) + 1(x,∞) , and δx := 1{x} is Dirac’s delta at x (this is the so called BojanicVuilleumier-Cheng decomposition). By Theorem 1.1, we have (4.1) |Ln (fx , x)| ≤ ∆n,x (fx ), (4.2) where ∆n,x (fx ) is the right-hand side of (1.2) with g replaced by fx . Moreover, Ln (σx , x)= P (Zn,x > x) − P (Zn,x < x) (4.3) = (P (Zn,x > x) − P (Zn,x ≤ x)) + P (Zn,x = x), and (4.4) Ln (δx , x) = P (Zn,x = x). Using Lemma 2.2(c) and the fact that (cf. [17, Theorem 1]) ( n k n−k if (n + 1)px = k ∈ {1, 2, . . . , n} p q ≤ √(1+x) k x x 2enx P (Zn,x = x) = 0 otherwise, the conclusion readily follows from (4.1) – (4.4). J. Inequal. Pure and Appl. Math., 6(1) Art. 4, 2005 http://jipam.vu.edu.au/ 8 J ESÚS DE LA C AL AND V IJAY G UPTA 5. P ROOF OF T HEOREM 1.3 Using the decomposition (4.1), it is easily checked that Ln (g, x) − g(x) = (5.1) 4 X Ai (n, x), i=1 where f ∗ (x) A1 (n, x) := f˜(x)Ln ((· − x), x) + Ln (| · −x|, x), 2 Z x Z A2 (n, x) := fx (u) du dKn,x (t), [0,x] Z t t Z A3 (n, x) := fx (u) du dKn,x (t), (x,2x] Z x Z A4 (n, x) := t fx (u) du dKn,x (t), (2x,∞) x and Kn,x (t) is the same as in the preceding proofs. From Lemma 2.2(d,e), we have √ x(1 + x) ∗ f (x) + f ∗ (x) ox (n−1/2 ) + ox (n−1 ), (n → ∞). (5.2) A1 (n, x) = √ 2πn Next, we estimate A2 (n, x). By Fubini’s theorem, ! Z x Z x−x/√n Z x A2 (n, x) = Kn,x (u) fx (u) du = + Kn,x (u) fx (u) du. √ 0 0 x−x/ n It is clear that Z x ≤ K (u) f (u) du |fx (u)| du n,x x √ √ x−x/ n x−x/ n Z x ≤ ωx− (fx ; x − u) du √ x−x/ n x x − ≤ √ ωx fx ; √ n n √ b nc 2x X − x ≤ ω fx ; , n k=1 x k Z x and, using Lemma 2.2(b), Z x−x/√n 3x(1 + x)2 Z x−x/√n |f (u)| x Kn,x (u) fx (u) du≤ du 0 (n + 2) (x − u)2 0 √ Z 3x(1 + x)2 x−x/ n ωx− (fx ; x − u) ≤ du (n + 2) (x − u)2 0 Z √n x 3(1 + x)2 ≤ ωx− fx ; dt (n + 2) 1 t √ nc x 2 bX 3(1 + x) ≤ ωx− fx ; . n + 2 k=1 k J. Inequal. Pure and Appl. Math., 6(1) Art. 4, 2005 http://jipam.vu.edu.au/ A PPROXIMATION O F L OCALLY B OUNDED F UNCTIONS B Y O PERATORS 9 We therefore conclude that √ nc 2 bX 5(1 + x) |A2 (n, x)| ≤ n+2 (5.3) x fx ; . k ωx− ωx+ k=1 Similarly, √ nc 2 bX 5(1 + x) |A3 (n, x)| ≤ n+2 (5.4) k=1 x fx ; . k Finally, Z Z g(t) dKn,x (t) − A4 (n, x) = (2x,∞) [g(x) + f (x+)(t − x)] dKn,x (t), (2x,∞) and, by the asymptotic assumption on g, Lemma 2.2(b) and Lemma 2.3, we obtain (5.5) |A4 (n, x)| = Or,x (n−1 ), (n → ∞). The conclusion follows from (5.1) – (5.5). 6. R EMARKS ON M OMENTS Fix x > 0, and let g(·) := | · −x|β , with β > 2. Since ωx (g, h) = 2 hβ , and n X 0 ≤ h ≤ x, k −β/2 = O(1), (n → ∞), k=1 we conclude from Theorem 1.1 that Ln (| · −x|β , x) = Or,x (n−1 ), (n → ∞). In the case that 0 < β ≤ 2, we have, by Jensen’s inequality (or Hölder’s inequality) and Lemma 2.2(a), β2 2 3x(1 + x) β/2 Ln (| · −x|β , x) = E|Zn,x − x|β ≤ E(Zn,x − x)2 ≤ , n+2 for all n ≥ 1. R EFERENCES [1] G. BLEIMANN, P.L. BUTZER AND L. 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