Journal of Inequalities in Pure and Applied Mathematics APPLICATIONS OF NUNOKAWA’S THEOREM A.Y. LASHIN Department of Mathematics Faculty of Science Mansoura University, Mansoura 35516, EGYPT. volume 5, issue 4, article 111, 2004. Received 29 August, 2004; accepted 13 December, 2004. Communicated by: H.M. Srivastava EMail: aylashin@yahoo.com Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 162-04 Quit Abstract The object of the present paper is to give applications of the Nunokawa Theorem [Proc. Japan Acad. Ser. A Math. Sci. 69 (1993), 234-237]. Our results have some interesting examples as special cases . 2000 Mathematics Subject Classification: 30C45 Key words: Analytic functions, Univalent functions, Subordination Applications of Nunokawa’s Theorem The author thank the referee for his helpful suggestion. A.Y. Lashin Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 Main Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . References Title Page 3 5 Contents JJ J II I Go Back Close Quit Page 2 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au 1. Introduction Let A be the class of functions of the form (1.1) f (z) = z + ∞ X an z n n=2 which are analytic in the open unit disk U = {z : |z| < 1}. It is known that the class ) ( ( µ−1 ) f (z) > 0, µ > 0, z ∈ U (1.2) B(µ) = f (z) ∈ A : Re f 0 (z) z is the class of univalent functions in U ([3]). To derive our main theorem, we need the following lemma due to Nunokawa [2]. Lemma 1.1. Let p(z) be analytic in U , with p(0) = 1 and p(z) 6= 0 (z ∈ U ). If there exists a point z0 ∈ U, such that π |arg p(z)| < α for |z| < |z0 | 2 and |arg p(z0 )| = then we have π α (α > 0), 2 z0 p0 (z0 ) = ikα, p(z0 ) where k ≥ 1 when arg p(z0 ) = π2 α and k ≤ −1 when arg p(z0 ) = − π2 α Applications of Nunokawa’s Theorem A.Y. Lashin Title Page Contents JJ J II I Go Back Close Quit Page 3 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au In [1] , Miller and Mocanu proved the following theorem. Theorem A. Let β0 = 1.21872..., be the solution of 3 βπ = π − tan−1 β 2 and let α = α(β) = β + 2 tan−1 β π Applications of Nunokawa’s Theorem for 0 < β < β0 . If p(z) is analytic in U , with p(0) = 1, then 0 p(z) + zp (z) ≺ or 1+z 1−z α A.Y. Lashin ⇒ p(z) ≺ 1+z 1−z β Title Page Contents π π |arg (p(z) + zp0 (z))| < α ⇒ |arg p(z)| < β. 2 2 Corresponding to Theorem A, we will obtain a result which is useful in obtaining applications of analytic function theory. JJ J II I Go Back Close Quit Page 4 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au 2. Main Results Now we derive: Theorem 2.1. Let p(z) be analytic in U , with p(0) = 1 and p(z) 6= 0 (z ∈ U ) and suppose that π 2 0 −1 |arg (p(z) + βzp (z))| < α + tan βα (α > 0, β > 0), 2 π then we have π α for z ∈ U. 2 Proof. If there exists a point z0 ∈ U, such that |arg p(z)| < |arg p(z)| < π α for |z| < |z0 | 2 and π |arg p(z0 )| = α (α > 0), 2 then from Lemma 1.1, we have (i) for the case arg p(z0 ) = π2 α, z0 p0 (z0 ) 0 arg (p(z) + βz0 p (z0 )) = arg p(z0 ) 1 + β p(z0 ) π π = α + arg (1 + iβαk) ≥ α + tan−1 βα. 2 2 Applications of Nunokawa’s Theorem A.Y. Lashin Title Page Contents JJ J II I Go Back Close Quit Page 5 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 This contradicts our condition in the theorem. http://jipam.vu.edu.au (ii) for the case arg p(z0 ) = − π2 α, the application of the same method as in (i) shows that π 0 −1 arg (p(z) + βz0 p (z0 )) ≤ − α + tan βα . 2 This also contradicts the assumption of the theorem, hence the theorem is proved. Making p(z) = f 0 (z) for f (z) ∈ A in Theorem 2.1, we have Applications of Nunokawa’s Theorem Example 2.1. If f (z) ∈ A satisfies π |arg (f (z) + βzf (z))| < 2 0 00 2 α + tan−1 βα π then we have π |arg f (z)| < α , 2 where α > 0, β > 0 and z ∈ U . 0 Further, taking p(z) = f (z) z for f (z) ∈ A in Theorem 2.1, we have Example 2.2. If f (z) ∈ A satisfies π f (z) 2 0 −1 arg{(1 − β) + βf (z)} < α + tan βα , z 2 π then we have π f (z) < α, arg z 2 where α > 0, 0 < β ≤ 1 and z ∈ U . A.Y. Lashin Title Page Contents JJ J II I Go Back Close Quit Page 6 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au Theorem 2.2. If f (z) ∈ A satisfies µ−1 f (z) 2 π 0 −1 α α + tan , < arg f (z) 2 z π µ then we have µ arg f (z) < π α, 2 z where α > 0, µ > 0 and z ∈ U . n oµ Proof. Let p(z) = f (z) , µ > 0, then we have z 1 p(z) + zp0 (z) = f 0 (z) µ f (z) z Applications of Nunokawa’s Theorem A.Y. Lashin µ−1 and the statements of the theorem directly follow from Theorem 2.1. Theorem 2.3. Let µ > 0 , c + µ > 0 and α > 0. If f (z) ∈ A satisfies µ−1 f (z) 2 α π 0 −1 α + tan , (z ∈ U ) arg f (z) < 2 z π µ+c Title Page Contents JJ J II I Go Back Close Quit then F (z) = [Iµ,c (f )](z) defined by Iµ,c f (z) = µ+c zc Z 0 µ1 z f µ (t)tc−1 dt , Page 7 of 11 ([Iµ,c (f )](z)/z 6= 0 in U ) J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au satisfies µ−1 F (z) π arg F 0 (z) < α. 2 z Proof. Consider the function p defined by 0 p(z) = F (z) F (z) z µ−1 (z ∈ U ). Applications of Nunokawa’s Theorem Then we easily see that 1 p(z) + zp0 (z) = f 0 (z) µ+c f (z) z A.Y. Lashin µ−1 , Title Page and the statements of the theorem directly follow from Theorem 2.1. Theorem 2.4. Let a function f (z) ∈ A satisfy the following inequalities µ+1 z 2 π 0 −1 α (2.1) −α + tan , (z ∈ U ) arg f (z) < 2 f (z) π µ for some α (0 < α ≤ 1), (0 < µ < 1). Then µ π f (z) arg < α. 2 z Contents JJ J II I Go Back Close Quit Page 8 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au µ Proof. Let us define the function p(z) by p(z) = f (z) , (0 < µ < 1). Then z p(z) satisfies µ+1 z 1 1 zp0 (z) 0 f (z) = 1+ . f (z) p(z) µ p(z) If there exists a point z0 ∈ U, such that π |arg p(z)| < α for |z| < |z0 | 2 and π |arg p(z0 )| = α, 2 then from Lemma 1.1, we have: (i) for the case arg p(z0 ) = π2 α, µ+1 1 1 zp0 (z0 ) z 0 arg f (z0 ) = arg 1+ f (z0 ) p(z0 ) µ p(z0 ) π iαk = − α + arg 1 + 2 µ π α ≥ − α + tan−1 . 2 µ This contradicts our condition in the theorem. (ii) for the case arg p(z0 ) = − π2 α, the application of the same method as in (i) shows that µ+1 π z 0 −1 α ≤ − − α + tan . arg f (z0 ) f (z0 ) 2 µ Applications of Nunokawa’s Theorem A.Y. Lashin Title Page Contents JJ J II I Go Back Close Quit Page 9 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au This also contradicts the assumption of the theorem, hence the theorem is proved. Theorem 2.5. Let f (z) ∈ A satisfy the condition (2.1) and let (2.2) c−µ F (z) = z c−µ Z z 0 t f (t) µ − µ1 dt , where c − µ > 0. Then Applications of Nunokawa’s Theorem µ+1 z π < α. arg F 0 (z) 2 F (z) A.Y. Lashin Proof. If we put Title Page p(z) = F 0 (z) z F (z) µ+1 Contents , JJ J then from (2.2) we have 1 p(z) + zp0 (z) = f 0 (z) c−µ z f (z) µ+1 . II I Go Back Close The statements of the theorem then directly follow from Theorem 2.1. Quit Page 10 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au References [1] S.S. MILLER AND P.T. MOCANU, Differential Subordinations, Marcel Dekker, INC., New York, Basel, 2000. [2] M. NUNOKAWA, On the order of strongly convex functions, Proc. Japan Acad. Ser. A Math. Sci., 69 (1993), 234–237. [3] M. OBRADOVIĆ, A class of univalent functions, Hokkaido Math. J., 27 (1988), 329–335. Applications of Nunokawa’s Theorem A.Y. Lashin Title Page Contents JJ J II I Go Back Close Quit Page 11 of 11 J. Ineq. Pure and Appl. Math. 5(4) Art. 111, 2004 http://jipam.vu.edu.au