Journal of Inequalities in Pure and Applied Mathematics SOME INEQUALITIES BETWEEN MOMENTS OF PROBABILITY DISTRIBUTIONS volume 5, issue 4, article 86, 2004. R. SHARMA, R.G. SHANDIL, S. DEVI AND M. DUTTA Department of Mathematics Himachal Pradesh University Summer Hill, Shimla -171005, India EMail: shandil_rg1@rediffmail.com Received 23 February, 2004; accepted 19 July, 2004. Communicated by: T. Mills Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 040-04 Quit Abstract In this paper inequalities between univariate moments are obtained when the random variate, discrete or continuous, takes values on a finite interval. Further some inequalities are given for the moments of bivariate distributions. 2000 Mathematics Subject Classification: 60E15, 26D15. Key words: Random variate, Finite interval, Power means, Moments. Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 Some Elementary Inequalities . . . . . . . . . . . . . . . . . . . . . . . . . . 5 3 Inequalities Between Moments . . . . . . . . . . . . . . . . . . . . . . . . . 9 4 Inequalities Between Moments of Bivariate Distributions . . . 14 5 Applications of Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 18 References Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 2 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au 1. Introduction The rth order moment µ0r of a continuous random variate which takes values on the interval [a, b] with pdf φ(x) is defined as Z b 0 (1.1) µr = xr φ(x)dx. a For a random variate which takes a discrete set of finite values xi (i = 1, 2,. . ., n) with corresponding probabilities pi (i = 1, 2,. . ., n), we define n X µ0r = (1.2) pi xri . Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta i=1 The power mean of order r is defined as 1/r Mr = (µ0r ) (1.3) for r 6= 0, Contents and 1/r Mr = lim (µ0r ) (1.4) r→0 for r = 0. It may be noted here that M−1 , M0 and M1 respectively define harmonic mean, geometric mean and arithmetic mean. Kapur [1] has reported the following bound for µ0r when µ0s is prescribed, r > s, and the random variate, discrete or continuous, takes values in the interval [a, b] with a ≥ 0, (1.5) Title Page r/s (µ0s ) (br − ar ) µ0s + ar bs − as br ≤ µ0r ≤ . b s − as JJ J II I Go Back Close Quit Page 3 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au Inequality (1.5) gives the condition which the given moment values must necessarily satisfy in order to be the moments of a probability distribution in the given range [a, b]. Kapur [1] was motivated by the consideration of maximizing the entropy function subject to certain constraints. But before maximizing the entropy function one has to see whether the given moment values are consistent or not i.e whether there is any probability distribution which corresponds to the given values of moments. If there is no such distribution then the efforts of finding out the maximum entropy probability distribution will not produce any result and hence we should not proceed to apply Lagrange’s or any other method to find the maximum entropy probability distribution, [2]. Here we try to obtain a generalization of inequality (1.5) for the case where r and s can assume any real value. This shall help us in deducing bounds between power means. This will also provide us with an alternate proof of inequality (1.5) and enable us to tighten it when the random variate takes a finite set of discrete values x1 , x2 ,. . ., xn . In addition some inequalities between the moments of bivariate distributions are also obtained. Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 4 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au 2. Some Elementary Inequalities We prove the following theorems: Theorem 2.1. If r is a positive real number and s is any non zero real number with r > s then for a ≤ x ≤ b; with a > 0, we have (2.1) xr ≤ (br − ar ) xs + ar bs − as br , bs − as and for x lying outside (a, b) we have (2.2) xr ≥ (br − ar ) xs + ar bs − as br . bs − as If r is a negative real number with r > s then inequality (2.1) holds for x lying outside (a, b) and inequality (2.2) holds for a ≤ x ≤ b. Proof. Consider the following function f (x) for positive real values of x: (2.3) b r − ar s as b r − ar b s x + , f (x) = x − s b − as b s − as r where r and s are real numbers such that r > s and s 6= 0. The function f (x) is continuous in the interval [a, b] with a > 0. Then f 0 (x) is given by r b − ar 0 s−1 r−s (2.4) f (x) = x rx − s s . b − as Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 5 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au f 0 (x) vanishes at x = 0 and c, where 1 r r−s s b − ar (2.5) c= . r b s − as By Rolle’s theorem we have that c lies in the interval (a, b). If r is a positive real number and s is a negative real number with r > s then 0 f (x) ≤ 0 iff x ≤ c. This means that f (x) decreases in the interval (0, c) and increases in the interval (c, ∞). Further, since c lies in the interval (a, b) and f (a) = f (b) = 0, it follows that (2.6) f (x) ≤ 0 for a ≤ x ≤ b, R. Sharma, R.G. Shandil, S. Devi and M. Dutta and for x lying outside (a, b) (2.7) f (x) ≥ 0. On substituting the value of f (x) from equation (2.3) in inequalities (2.6) and (2.7), we obtain inequalities (2.1) and (2.2) respectively. If r is a negative real number with r > s then f 0 (x) ≤ 0 iff x ≥ c. This means that f (x) increases in the interval (0, c) and decreases in the interval (c, ∞). Since c lies in the interval (a, b) and f (a) = f (b) = 0 it follows that inequality (2.7) holds for a ≤ x ≤ b while inequality (2.6) holds for x lying outside (a, b) and thus we get inequalities for the case when r is negative real number. Theorem 2.2. For a ≤ x ≤ b with a > 0, we have (2.8) Some Inequalities Between Moments of Probability Distributions (br − ar ) log x + ar log b − br log a xr ≤ , log b − log a Title Page Contents JJ J II I Go Back Close Quit Page 6 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au and for x lying outside (a, b), we have (2.9) xr ≥ (br − ar ) log x + ar log b − br log a , log b − log a where r is a real number. Proof. Consider the following function f (x) defined for positive real values of x, (br − ar ) br log a − ar log b f (x) = x − log x + . log b − log a log b − log a Some Inequalities Between Moments of Probability Distributions The function f (x) is continuous in the interval [a, b] where a > 0. Then f 0 (x) is given by 1 b r − ar 0 r (2.11) f (x) = rx − , x log b − log a R. Sharma, R.G. Shandil, S. Devi and M. Dutta (2.10) r and we have f 0 (x) = 0 at x = c where r1 b r − ar . (2.12) c= r (log b − log a) By Rolle’s Theorem we have that c lies in the interval (a, b). Also f 0 (x) ≤ 0 iff x ≤ c. This means that f (x) decreases in the interval (0, c) and increases in the interval (c, ∞). Further, since c lies in the interval (a, b) and f (a) = f (b) = 0 it follows that (2.13) f (x) ≤ 0 for a ≤ x ≤ b, Title Page Contents JJ J II I Go Back Close Quit Page 7 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au and for x lying outside (a, b) we have (2.14) f (x) ≥ 0. On substituting the value of f (x) from equation (2.10) in inequalities (2.13) and (2.14), we obtain inequalities (2.8) and (2.9) respectively. Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 8 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au 3. Inequalities Between Moments Theorem 3.1. Let r be a positive real number and s be any non zero real number with r > s. If a positive random variate takes values xi (i = 1, 2,. . ., n) in the interval [a, b], with a > 0, then we have (3.1) µ0r ≤ (br − ar ) µ0s + ar bs − as br , b s − as and xrj − xrj−1 µ0s + xrj−1 xsj − xsj−1 xrj , xsj − xsj−1 (3.2) µ0r ≥ where j = 2, 3,. . ., n. If a continuous random variate takes values in the interval [a, b], with a > 0, then the upper bound for µ0r is given by the inequality (3.1) whereas the lower bound is given by following inequality (3.3) r/s µ0r ≥ (µ0s ) . Proof. It is seen that µ0r can be expressed in terms of µ0s in the following form : ! r r x − x xsβ xrα − xsα xrβ α β 0 (3.4) µ0r = µ + s xsβ − xsα xsβ − xsα " # n r r r s r s X x − x x x − x x α s α β β β α + x + , pi xri − s s s i s x − x x − x α α β β i=1 Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 9 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au where α and β take one of the values among 1, 2,. . ., n with α 6= β. Without loss of generality we can arrange values of the variate such that a = x1 ≤ x2 ≤ · · · ≤ xn = b. If we take α = 1 and β = n then x1 ≤ xi ≤ xn for i = 1, 2, ,. . ., n. It follows from (2.1) that the last term in equation (3.4) is negative and we conclude that the upper bound for µ0r is given by inequality (3.1). Further if xα = xj−1 and xβ = xj , j = 2, 3,. . ., n then each xi lies outside (xj−1 , xj ) and it follows from (2.2) that the last term in equation (3.4) is positive and we conclude that the lower bound for µ0r is given by inequality (3.2). It is also clear that equality in the inequalities (3.1) and (3.2) holds iff n = 2. If the value of µ0s coincides with one of xsj−1 or xsj , then from inequality (3.2) we have µ0r (3.5) ≥ r/s (µ0s ) . Also if xj−1 approaches xj we get inequality (3.5) and we conclude that for a continuous random variate the lower bound for µ0r is given by inequality (3.5). The upper bound for µ0r can be deduced from Theorem 2.1. Multiplying both sides of inequality (2.1) by pdf φ(x) we get, on using the properties of definite integrals, inequality (3.1). Theorem 3.2. Let r and s be negative real numbers with r > s. If a positive random variate takes values xi (i = 1, 2,. . ., n) in the interval [a, b], with a > 0, we have (3.6) µ0r (br − ar ) µ0s + ar bs − as br , ≥ b s − as Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 10 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au and (3.7) 0 r r x µs + xrj−1 xsj − xsj−1 xrj − x j j−1 0 , µr ≤ xsj − xsj−1 where j = 2, 3,. . ., n. If a continuous random variate takes values in the interval [a, b], with a > 0, the lower bound for µ0r is given by inequality (3.6) whereas the upper bound for µ0r is given by following inequality: (3.8) µ0r ≤ r/s (µ0s ) . Proof. We again consider equation (3.4). If we take α = 1 and β = n then x1 ≤ xi ≤ xn for i = 1, 2,. . ., n. It follows from Theorem 2.1 that the last term in equation (3.4) is positive and we conclude that the lower bound for µ0r is given by inequality (3.6). Also if xα = xj−1 and xβ = xj , j = 2, 3,. . ., n then each xi lies outside (xj−1 , xj ). It follows from Theorem 2.1 that the last term in equation (3.4) is negative and we conclude that the upper bound for µ0r is given by inequality (3.7). Also if xj−1 approaches xj we get inequality (3.8). The lower bound for µ0r can be deduced from Theorem 2.1. Multiplying both sides of inequality (2.2) by pdf φ(x) we get, on using the properties of definite integrals, inequality (3.6). Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Theorem 3.3. For a random variate which takes values xi (i = 1, 2,. . ., n) in the interval [a, b], with a > 0, we have (3.9) (br − ar ) log M0 + ar log b − br log a , µ0r ≤ log b − log a Quit Page 11 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au and (3.10) r r r r x − x j j−1 log M0 + xj−1 log xj − xj log xj−1 µ0r ≥ , log xj − log xj−1 where j = 2, 3,. . .n, r is a real number and M0 = xP1 1 xP2 2 · · · xPnn . (3.11) For a continuous random variate which takes values in the interval [a, b] with a > 0 the upper bound for µ0r is given by inequality (3.9) whereas the lower bound for µ0r is given by the following inequality µ0r (3.12) r ≥ (M0 ) . Proof. It is seen that µ0r can be expressed in terms of log M0 in the following form: xrβ − xrα xrα log xβ − xrβ log xα log M0 + log xβ − log xα log xβ − log xα n r r X xrβ log xα − xrα log xβ xβ − xα r log xi + . + Pi x i − log xβ − log xα log xβ − log xα i=1 (3.13) µ0r = Without loss of generality we can arrange values of the variate such that a = x1 < x2 < · · · < xn = b. If we take α = 1and β = n then x1 ≤ xi ≤ xn for i = 1, 2,. . ., n. It follows from Theorem 2.2 that last term in equation (3.13) is negative and we conclude that the upper bound for µ0r is given by inequality Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 12 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au (3.9). Also if xα = xj−1 and xβ = xj , j = 2, 3,. . ., n then each xi lies outside (xj−1 , xj ). It follows from Theorem 2.2 that the last term in equation (3.13) is positive and we conclude that the lower bound for µ0r is given by inequality (3.10). If the value of M0 coincides with one of xj−1 or xj then from inequality (3.10) we have (3.14) µ0r ≥ (M0 )r . Also if xj−1 approaches xj we get inequality (3.14) and we conclude that for the continuous random variate the lower bound for µ0r is given by inequality (3.14). The upper bound for µ0r can be deduced from Theorem 2.2. Multiplying both sides of inequality (2.8) by pdf φ(x) we get, on using the properties of definite integrals, inequality (3.9). Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 13 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au 4. Inequalities Between Moments of Bivariate Distributions The moments of a bivariate probability distribution are the generalizations of those of univariate one and are equally important in the theory of mathematical statistics. For a discrete probability distribution, if pi is the probability of the occurrence of the pair of values (xi , yi ) i = 1, 2,. . ., n, the moment µ0rs about the origin is given by µ0rs (4.1) = n X Pi xri yis . i=1 We obtain a bound on µ0rs in the following theorem: Theorem 4.1. Let µ0rs be the moment of order r in x and of order s in y, about the origin (0, 0), of a discrete bivariate probability distribution. The random variates x and y vary respectively over the finite positive real intervals [a, b] and [c, d]. If µ0k m is the corresponding moment of order k in x and m in y such that r ≥ k, s ≥ m and rm = ks then we must have by necessity, r+s (4.2) (µ0k m ) k+m ≤ µ0r s ≤ (br ds − ar cs ) µ0k m + ar cs bk dm − ak cm br ds . bk dm − ak cm Proof. If u, v, α and β are positive real numbers with α + β = 1 then from Hölder’s inequality [3], !α !β n n n X X X α β (4.3) ui v i ≤ ui vi . i=1 i=1 i=1 Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 14 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au We make the following substitutions, (4.4) ui = pi xri yis , vi = pi and α = k+m . r+s This gives, uαi viβ = pi xki yim . (4.5) Also, (4.6) n X !α ui = n X i=1 Some Inequalities Between Moments of Probability Distributions ! k+m r+s pi xri yis , i=1 R. Sharma, R.G. Shandil, S. Devi and M. Dutta and (4.7) n X Title Page !β vi Contents = 1. i=1 JJ J From (4.3), (4.5), (4.6) and (4.7), we get (4.8) µ0r s ≥ (µ0k m ) r+s k+m . For a ≤ x ≤ b, c ≤ y ≤ d, r ≥ k, s ≥ m and rm = ks, inequality (4.3) will remain valid if we substitute n = 2, u1 = p1 ar cs , u2 = p2 br ds , v1 = p1 , v2 = p2 , α = k+m , r+s bk dm − xk y m p1 = k m , b d − ak c m II I Go Back Close Quit Page 15 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au and p2 = x k y m − ak c m . bk dm − ak cm These substitutions give (4.9) xr y s ≤ (br ds − ar cs ) xk y m + ar cs bk dm − ak cm br ds . bk dm − ak cm Without loss of generality we can have that the random variate take values a = x1 < x2 < · · · < xn = b and c = y1 < y2 < · · · < yn = d therefore a ≤ xi ≤ b and c ≤ yi ≤ d, i = 1, 2,. . ., n. From inequality (4.9), it follows that xri yis ≤ or n X Pi xri yis ≤ (br ds − ar cs ) xki yim + ar cs bk dm − ak cm br ds , bk dm − ak cm (br ds − ar cs ) i=1 Pn r s k m k m r s k m i=1 Pi xi yi + a c b d − a c b d bk dm − ak cm or R. Sharma, R.G. Shandil, S. Devi and M. Dutta Pn i=1 Pi Title Page , (br ds − ar cs ) µ0k m + ar cs bk dm − ak cm br ds . µ0r s ≤ bk dm − ak cm Inequality (4.2) also holds for the continuous bivariate distributions. The upper bound in inequality (4.2) is a consequence of inequality (4.9). Multiplying both sides of inequality (4.9) by joint pdf φ(x, y) and integrating over the corresponding limits, we get the maximum value of µ0rs where Z bZ d Z bZ d 0 r s µrs = x y φ(x, y)dxdy and φ(x, y)dxdy = 1. a c a c Some Inequalities Between Moments of Probability Distributions Contents JJ J II I Go Back Close Quit Page 16 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au Now consider, RbRd f α g β dxdy α R R β b d f dxdy g dxdy a c a R R b d a c c Z bZ d = a ≤ a RbRd c Z bZ c a d !α f " c !β g RbRd f dxdy a c dxdy g dxdy # αf βg + RbRd dx dy RbRd f dxdy g dxdy a c a c Some Inequalities Between Moments of Probability Distributions = 1, R. Sharma, R.G. Shandil, S. Devi and M. Dutta where α + β = 1 and f and g are positive functions. We therefore have Z bZ d α β Z b Z f g dx dy ≤ (4.10) a c α Z b Z d f dxdy a c g dxdy a φ(x, y), g = φ(x, y) , Contents c JJ J and make the following substitutions, f = xr y s Title Page β d and Inequality (4.10) then yields the minimum value of µ0rs . α= k+m . r+s II I Go Back Close Quit Page 17 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au 5. Applications of Results On using the results derived in Section 3 and giving particular values to r and s it is possible to derive a host of results connecting the Harmonic mean (H), Geometric mean (G), Arithmetic mean (A) and Root mean square (R) when one of the means is given and the random variate takes the prescribed set of positive values x1 , x2 , . . . , xn . If we put r = +1 and s = −1 we get inequalities between A and H, if we put r = 0 and s = −1 we get inequalities between G and H, and so on. Root mean square R corresponds to r = 2. In particular the following inequalities are obtained from the general result, 1 1 (5.1) [(xj−1 + xj ) A − xj−1 xj ] 2 ≤ R ≤ [(a + b) A − ab] 2 , (5.2) ab xj−1 xj ≤H≤ , a+b−A xj−1 + xj − A (5.3) bA−a ab−A 1 b−a A−xj−1 xj −A xj−1 ≤ G ≤ xj 1 j −xj−1 x Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents , JJ J II I Go Back (5.4) 1 xj−1 xj (xj−1 + xj ) 2 2 2 xj−1 + xj−1 xj + xj − H 1 ab (a + b) 2 2 2 ≤ R ≤ a + ab + b − , H Close Quit Page 18 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au (xj−1 + xj ) − (5.5) (5.6) h x (H−xj−1 ) xj−1 (xj −H) xj j xj−1 log (5.7) (5.8) G xj−1 x ab log ab a b b log Ga G G xj xj−1 log 1 j −xj−1 ) i H(x xj x2j−1 G j log xj−1 log (5.9) x2j ab xj−1 xj ≤A≤a+b− , H H xj xj−1 1 ≤ G ≤ bb(H−a) aa(b−H) H(b−a) , log ≤ R2 ≤ 2 G b a 2 b a G log ab xj−1 xj xj log xj−1 xj−1 xj xj G log xj−1 G xj xj−1 G ≤A≤ log G b a log ab b a G , R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page ≤H≤ Some Inequalities Between Moments of Probability Distributions , Contents JJ J II I Go Back , Close Quit (5.10) R2 + ab R2 + xj−1 xj ≤A≤ , a+b xj−1 + xj Page 19 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au (5.11) a2 ab (a + b) xj−1 xj (xj−1 + xj ) ≤H≤ 2 , 2 2 + ab + b − R xj−1 + xj−1 xj + x2j − R2 and (5.12) b R2 −a2 b2 −a2 a b2 −R2 b2 −a2 R2 −x2 j−1 x2 −x2 j j−1 ≤ G ≤ xj 2 x2 j −R 2 2 x −x j j−1 xj−1 , where j = 2, 3,. . ., n. We now deduce the result that the power mean Mr is an increasing function of r. If r is positive and s is any real number with r > s then from inequality (3.3) we have 1 (5.13) 1 (µ0r ) r ≥ (µ0s ) s , or Mr ≥ Ms. If r is a negative real number with r > s we again get inequality (5.13) from inequality (3.8). From inequality (3.12) we have Mr ≥ M0 for r > 0, and Mr ≤ M0 for r < 0. Hence we conclude that the power mean of order r is an increasing function of r. In particular, we get that Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close M−1 ≤ M0 ≤ M1 ≤ M2 . Quit Page 20 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au References [1] J.N. KAPUR AND A. RANI, Testing the consistency of given values of a set of moments of a probability distribution, J. Bihar Math. Soc., 16 (1995), 51–63. [2] J.N. KAPUR, Maximum Entropy Models in Science and Engineering, Wiley Eastern and John Wiley, 2nd Edition, 1993. [3] G.H. HARDY, J.E. LITTLEWOOD AND G. POLYA, Inequalities, Cambridge University Press, 2nd Edition, 1952. Some Inequalities Between Moments of Probability Distributions R. Sharma, R.G. Shandil, S. Devi and M. Dutta Title Page Contents JJ J II I Go Back Close Quit Page 21 of 21 J. Ineq. Pure and Appl. Math. 5(4) Art. 86, 2004 http://jipam.vu.edu.au