Journal of Inequalities in Pure and Applied Mathematics REFINEMENTS OF THE HERMITE-HADAMARD INEQUALITY FOR CONVEX FUNCTIONS volume 6, issue 5, article 140, 2005. S.S. DRAGOMIR AND A. McANDREW School of Computer Science and Mathematics Victoria University PO Box 14428, MCMC 8001 VIC, Australia. EMail: sever@csm.vu.edu.au URL: http://rgmia.vu.edu.au/dragomir/ EMail: Alasdair.Mcandrew@vu.edu.au URL: http://sci.vu.edu.au/˜amca/ Received 06 April, 2005; accepted 20 September, 2005. Communicated by: A. Lupaş Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 106-05 Quit Abstract New refinements for the celebrated Hermite-Hadamard inequality for convex functions are obtained. Applications for special means are pointed out as well. 2000 Mathematics Subject Classification: Primary 26D15; Secondary 26D10. Key words: Hermite-Hadamard Inequality. This paper is based on the talk given by the second author within the “International Conference of Mathematical Inequalities and their Applications, I”, December 0608, 2004, Victoria University, Melbourne, Australia [http://rgmia.vu.edu.au/ conference] Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 The Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6 3 Applications for Special Means . . . . . . . . . . . . . . . . . . . . . . . . . 12 References Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 2 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au 1. Introduction The following result is well known in the literature as the Hermite-Hadamard integral inequality: Z b a+b 1 f (a) + f (b) (1.1) f ≤ f (t) dt ≤ , 2 b−a a 2 provided that f : [a, b] → R is a convex function on [a, b] . The following refinements of the H· − H· inequality were obtained in [2] 1 (1.2) b−a b a+b f (x) dx − f 2 a Z b f (x) + f (a + b − x) 1 a + b ≥ dx − f ≥ 0. b−a a 2 2 Z and b f (a) + f (b) 1 − f (t) dt 2 b−a a Rb 1 |f (a)| − |f (x)| dx if f (a) = f (b) b−a a ≥ R f (b) Rb 1 1 |x| dx − |f (x)| dx if f (a) 6= f (b) f (b)−f (a) f (a) b−a a Z (1.3) Refinements of the Hermite-Hadamard Inequality for Convex Functions for the general case of convex functions f : [a, b] → R. S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 3 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au If one would assume differentiability of f on (a, b) , then the following bounds in terms of its derivative holds (see [3, pp. 30-31]) Z b f (a) + f (b) 1 (1.4) − f (t) dt ≥ max {|A| , |B| , |C|} ≥ 0 2 b−a a where Z b Z b x − a + b |f 0 (x)| dx − 1 |f 0 (x)| dx, 2 4 a a "Z a+b # Z b 2 1 f (b) − f (a) f (x) dx − f (x) dx − B := a+b 4 b−a a 2 1 A := b−a and 1 C := b−a Z b a a+b x− 2 S.S. Dragomir and A. McAndrew Title Page |f 0 (x)| dx. Contents A different approach considered in [1] led to the following lower bounds Z b f (a) + f (b) 1 − f (t) dt ≥ max {|D| , |E| , |F |} ≥ 0, (1.5) 2 b−a a where JJ J II I Go Back Close Z b Z b Z b 1 1 1 |xf 0 (x)| dx − |f 0 (x)| dx · |x| dx, b−a a b−a a b−a a Z b Z b 1 a+b 1 0 E := · x |f (x)| dx − |f 0 (x)| xdx b−a a 2 b−a a D := Refinements of the Hermite-Hadamard Inequality for Convex Functions Quit Page 4 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au and 1 F := b−a Z a b 1 f (b) − f (a) |x| f (x) dx − · b−a b−a 0 Z b |x| dx. a For other results connected to the H· − H· inequality see the recent monograph on line [3]. In the present paper, we use a different method to obtain other refinements of the H· − H· inequality. Applications for special means are pointed out as well. Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 5 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au 2. The Results The following refinement of the Hermite-Hadamard inequality for differentiable convex functions holds. Theorem 2.1. Assume that f : [a, b] → R is differentiable convex on (a, b) . Then one has the inequality: Z b a+b 1 (2.1) f (t) dt − f b−a a 2 Z b 1 0 a + b a + b b − a f (x) − f dx − ≥ 0. ≥ · f b−a a 2 4 2 Refinements of the Hermite-Hadamard Inequality for Convex Functions Proof. Since f is differentiable convex on (a, b) , then for each x, y ∈ (a, b) one has the inequality S.S. Dragomir and A. McAndrew f (x) − f (y) ≥ (x − y) f 0 (y) . Title Page (2.2) Using the properties of modulus, we have (2.3) f (x) − f (y) − (x − y) f 0 (y) = |f (x) − f (y) − (x − y) f 0 (y)| ≥ ||f (x) − f (y)| − |x − y| |f 0 (y)|| for each x, y ∈ (a, b) . If we choose y = a+b in (2.3) we get 2 a+b a+b a+b 0 (2.4) f (x) − f − x− f 2 2 2 0 a + b a + b a + b − x − f ≥ f (x) − f 2 2 2 Contents JJ J II I Go Back Close Quit Page 6 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au for any x ∈ (a, b) . Integrating (2.4) on [a, b] , dividing by (b − a) and using the properties of modulus, we have Z b Z b a+b 1 a+b 1 a+b 0 f (x) dx − f −f · x− dx b−a a 2 2 b−a a 2 Z b 0 a + b a + b a + b 1 f (x) − f − x − f dx ≥ b − a a 2 2 2 Z b 1 a + b ≥ f (x) − f dx b−a a 2 Z b 0 a+b 1 a + b x − dx − f 2 b−a a 2 Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page and since Z b (2.5) a a+b x− 2 Z b 2 a + b x − dx = (b − a) , dx = 0, 2 4 a we deduce by (2.5) the desired result (2.1). Contents JJ J II I Go Back The second result is embodied in the following theorem. Theorem 2.2. Assume that f : [a, b] → R is differentiable convex on (a, b) . Close Quit Page 7 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au Then one has the inequality Z b 1 f (a) + f (b) a+b 1 (2.6) +f − f (x) dx 2 2 2 b−a a Z b a + b 1 1 f (x) − f dx ≥ 2 b−a a 2 Z b 1 a + b 0 ≥ 0. − x − |f (x)| dx b−a a 2 Proof. We choose x = (2.7) f a+b 2 a+b 2 in (2.3) to get a+b − f (y) − − y f 0 (y) 2 a + b 0 a+b ≥ f − f (y) − − y |f (y)| . 2 2 Integrating (2.7) over y, dividing by (b − a) and using the modulus properties, we get (2.8) f a+b 2 Z b Z b 1 a+b − f (y) dy − − y f 0 (y) dy b−a a 2 a Z b 1 a + b f dy ≥ − f (y) b−a a 2 Z b a + b 0 1 − − y |f (y)| dy . b−a a 2 Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 8 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au Since Z b a a+b y− 2 f (a) + f (b) f (y) dy = (b − a) − 2 0 Z b f (t) dt, a then by (2.8) we deduce f a+b 2 Z b f (a) + f (b) 2 + − f (y) dy 2 b−a a Z b 1 a + b f (y) − f ≥ dy b−a a 2 Z b 0 a + b 1 y − |f (y)| dy − b−a a 2 Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page which is clearly equivalent to (2.6). The following result holding for the subclass of monotonic and convex functions is whort to mention. Theorem 2.3. Assume that f : [a, b] → R is monotonic and convex on (a, b) . Then we have: Z b 1 f (a) + f (b) a+b 1 (2.9) +f − f (x) dx 2 2 2 b−a a Z b 1 1 a + b ≥ [f (b) − f (a)] + sgn − x f (x) dx . 4 b−a a 2 Contents JJ J II I Go Back Close Quit Page 9 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au Proof. Since the class of differentiable convex functions in (a, b) is dense in uniform topology in the class of all convex functions defined on (a, b) , we may assume, without loss of generality, that f is differentiable convex and monotonic on (a, b) . Firstly, assume that f is monotonic nondecreasing on [a, b] . Then Z b Z f (x) − f a + b dx = 2 a a+b 2 a Z b = a+b f − f (x) dx 2 Z b a+b dx + f (x) − f a+b 2 2 Z a+b 2 f (x) dx − f (x) dx, a+b 2 Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew a Title Page Z b 0 a + b x − |f (x)| dx 2 a Z a+b Z b 2 a+b a+b 0 = − x f (x) dx + x− f 0 (x) dx a+b 2 2 a 2 a+b Z a+b 2 2 a+b = − x f (x) + f (x) dx 2 a a b Z b a+b f (x) − + x− f (x) dx a+b 2 a+b 2 Contents JJ J II I Go Back Close Quit Page 10 of 15 2 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au b−a =− f (a) + 2 Z a a+b 2 b−a f (x) dx + f (b) − 2 Z b f (x) dx. a+b 2 Using (2.6) we have Z b 1 f (a) + f (b) a+b 1 +f − f (x) dx 2 2 2 b−a a Z Z a+b b 2 1 f (x) dx − f (x) dx ≥ 2 (b − a) a+b a 2 # " Z b Z a+b 2 b−a b−a f (x) dx − f (x) dx − f (b) − f (a) + a+b 2 2 a 2 Z Z a+b b 2 b−a 1 f (x) dx − 2 f (x) dx − [f (b) − f (a)] , = 2 2 2 (b − a) a+b a 2 which is clearly equivalent to (2.9). A similar argument may be done if f is monotonic nonincreasing and we omit the details. Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 11 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au 3. Applications for Special Means Let us recall the following means: a) The arithmetic mean A (a, b) := b) The geometric mean a+b , a, b > 0, 2 √ G (a, b) := ab; a, b ≥ 0, c) The harmonic mean Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew H (a, b) := 1 a 2 ; a, b > 0, + 1b d) The identric mean Contents 1 1 bb b−a if b 6= a e aa I (a, b) := ; a, b > 0 a if b = a JJ J II I Go Back Close e) The logarithmic mean L (a, b) := Title Page b−a if b 6= a ln b − ln a ; a, b > 0 a if b = a Quit Page 12 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au f) The p−logarithmic mean 1 bp+1 −ap+1 p (p+1)(b−a) if b 6= a, p ∈ R\ {−1, 0} Lp (a, b) := ; a, b > 0. a if b = a It is well known that, if, on denoting L−1 (a, b) := L (a, b) and L0 (a, b) := I (a, b) , then the function R 3 p → Lp (a, b) is strictly monotonic increasing and, in particular, the following classical inequalities are valid (3.1) min {a, b} ≤ H (a, b) ≤ G (a, b) ≤ L (a, b) ≤ I (a, b) ≤ A (a, b) ≤ max {a, b} for any a, b > 0. The following proposition holds: Proposition 3.1. Let 0 < a < b < ∞. Then we have the following refinement for the inequality A ≥ L : " # 2 2 AL G G (3.2) A−L≥ − ln − 1 ≥ 0. b−a A A The proof follows by Theorem 2.1 on choosing f : [a, b] → (0, ∞), f (t) = 1/t and we omit the details. The following proposition contains a refinementof the following well known inequality 1 −1 A + H −1 ≥ L−1 . 2 Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 13 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au Proposition 3.2. With the above assumption for a and b we have " # 2 2 1 −1 A A 1 (3.3) A + H −1 − L−1 ≥ − ln − 1 ≥ 0. 2 b−a G G The proof follows by Theorem 2.3 for the same funcion f : [a, b] → (0, ∞), f (t) = 1/t, which is monotonic and convex on [a, b] , and the details are omitted. One may state other similar results that improve classical inequalities for means by choosing appropriate convex functions f. However, they will not be stated below. Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 14 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au References [1] S.S. DRAGOMIR AND S. MABZELA, Some error estimates in the trapezoidal quadrature rule, Tamsui Oxford J. of Math. Sci., 16(2) (2000), 259– 272. [2] S.S. DRAGOMIR, Refinements of the Hermite-Hadamard inequality for convex functions, Tamsui Oxford J. of Math. Sci., 17(2) (2001), 131–137. [3] S.S. DRAGOMIR AND C.E.M. PEARCE, Selected Topics on HermiteHadamard Type Inequalities and Applications, RGMIA, Monographs, 2000. [ONLINE: http://rgmia.vu.edu.au/monographs. html]. Refinements of the Hermite-Hadamard Inequality for Convex Functions S.S. Dragomir and A. McAndrew Title Page Contents JJ J II I Go Back Close Quit Page 15 of 15 J. Ineq. Pure and Appl. Math. 6(5) Art. 140, 2005 http://jipam.vu.edu.au