Journal of Inequalities in Pure and Applied Mathematics CERTAIN SECOND ORDER LINEAR DIFFERENTIAL SUBORDINATIONS volume 5, issue 3, article 59, 2004. V. RAVICHANDRAN Department of Computer Applications Sri Venkateswara College of Engineering Pennalur, Sriperumbudur 602 105, India Received 29 December, 2003; accepted 03 April, 2004. Communicated by: N.E. Cho EMail: vravi@svce.ac.in URL: http://www.svce.ac.in/∼vravi Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 003-04 Quit Abstract In this present investigation, we obtain some results for certain second order linear differential subordination. We also discuss some applications of our results. 2000 Mathematics Subject Classification: Primary 30C80, Secondary 30C45. Key words: Analytic functions, Hadamard product (or convolution), differential subordination, Ruscheweyh derivatives, univalent functions, convex functions. The author is thankful to the referee for his comments. Contents 1 2 3 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 Differential Subordination with Convex Functions of Order α 8 Differential Subordination with Caratheodory Functions of Order α . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 14 4 Applications . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 18 References Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page Contents JJ J II I Go Back Close Quit Page 2 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au 1. Introduction Let H denote the class of all analytic functions in ∆ := {z ∈ C : |z| < 1}. For a positive integer n and a ∈ C, let ) ( ∞ X H[a, n] := f ∈ H : f (z) = a + ak z k (n ∈ N := {1, 2, 3, . . .}) k=n and ( A(p, n) := f ∈ H : f (z) = z p + ∞ X ) ak z k (n, p ∈ N) . Certain Second Order Linear Differential Subordinations V. Ravichandran k=n+p Title Page Set Ap := A(p, 1), A := A1 . Contents For two functions f, g ∈ H, we say that the function f (z) is subordinate to g(z) in ∆ and write f ≺g f (z) ≺ g(z), or and |w(z)| < 1 II I Go Back Close if there exists a Schwarz function w(z) ∈ H with w(0) = 0 JJ J (z ∈ ∆), Quit Page 3 of 25 such that J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 (1.1) f (z) = g(w(z)) (z ∈ ∆). http://jipam.vu.edu.au In particular, if the function g is univalent in ∆, the above subordination (1.1) is equivalent to f (0) = g(0) and f (∆) ⊂ g(∆). Miller and Mocanu [2] considered the second order linear differential subordination A(z)z 2 p00 (z) + B(z)zp0 (z) + C(z)p(z) + D(z) ≺ h(z), where A, B, C and D are complex-valued functions defined on ∆ and h(z) is any convex function and in particular h(z) = (1 + z)/(1 − z). In fact, they have proved the following: Theorem 1.1 (Miller and Mocanu [2, Theorem 4.1a, p.188]). Let n be a positive integer and A(z) = A ≥ 0. Suppose that the functions B(z), C(z), D(z) : ∆ → C satisfy <B(z) ≥ A and (1.2) [=C(z)]2 ≤ n[<B(z) − A]<(nB(z) − nA − 2D(z)). If p ∈ H[1, n] and if Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page Contents JJ J II I Go Back (1.3) <{Az 2 p00 (z) + B(z)zp0 (z) + C(z)p(z) + D(z)} > 0, Close Quit then <p(z) > 0. Page 4 of 25 Also Miller and Mocanu [2] have proved the following: J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au Theorem 1.2 (Miller and Mocanu [2, Theorem 4.1e, p.195]). Let h be convex univalent in ∆ with h(0) = 0 and let A ≥ 0. Suppose that k > 4/|h0 (0)| and that B(z), C(z) and D(z) are analytic in ∆ and satisfy < B(z) ≥ A + |C(z) − 1| − <(C(z) − 1) + k|D(z)|. If p ∈ H[0, 1] satisfies the differential subordination Az 2 p00 (z) + B(z)zp0 (z) + C(z)p(z) + D(z) ≺ h(z) then p ≺ h. Certain Second Order Linear Differential Subordinations In this paper, we extend Theorem 1.1 by assuming 2 00 0 <{Az p (z) + B(z)zp (z) + C(z)p(z) + D(z)} > α, V. Ravichandran (0 ≤ α < 1) and Theorem 1.2 by assuming that the function h(z) is convex of order α. Certain results of Karunakaran and Ponnusamy [6], Juneja and Ponnusamy [7] and Owa and Srivastava [8] are obtained as special cases. Also we give application of our results to certain functions defined by the familiar Ruscheweyh derivatives. For two functions f (z) and g(z) given by f (z) = z p + ∞ X ak z k , g(z) = z p + k=n+p ∞ X bk z k (n, p ∈ N) , k=n+p the Hadamard product (or convolution) of f and g is defined by (f ∗ g)(z) := z p + ∞ X k=n+p ak bk z k =: (g ∗ f )(z). Title Page Contents JJ J II I Go Back Close Quit Page 5 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au The Ruscheweyh derivative of f (z) of order δ + p − 1 is defined by (1.4) Dδ+p−1 f (z) := zp (1 − z)δ+p ∗f (z) (f ∈ A (p, n) ; δ ∈ R\ (−∞, −p]) or, equivalently, by (1.5) D δ+p−1 ∞ X δ+k−1 f (z) := z + ak z k k − p k=p+1 p (f ∈ A (p, n) ; δ ∈ R\ (−∞, −p]) . Certain Second Order Linear Differential Subordinations V. Ravichandran In particular, if δ = l (l + p ∈ N), we find from the definition (1.4) or (1.5) that dl+p−1 l−1 zp z f (z) (l + p − 1)! dz l+p−1 (f ∈ A (p, n) ; l + p ∈ N) . Dl+p−1 f (z) = In our present investigation of the second order linear differential subordination, we need the following definitions and results: Definition 1.1 (Miller and Mocanu [2, Definition 2.2b, p. 21]). Let Q be the set of functions q that are analytic and univalent on ∆ \ E(q), where Title Page Contents JJ J II I Go Back Close Quit E(q) = {ζ ∈ ∂∆ : lim q(z) = ∞} z→ζ and are such that q 0 (ζ) 6= 0 for ζ ∈ ∂∆\E(q), where ∂∆ := {z ∈ C : |z| = 1}, ∆ := ∆ ∪ ∂∆. Page 6 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au Theorem 1.3 (Miller and Mocanu [2, Lemma 2.2d, p. 24]). Let q ∈ Q, with q(0) = a. Let p(z) = a + pn z n + · · · be analytic in ∆ with p(z) 6≡ a and n ≥ 1. If p(z) is not subordinate to q(z), then there exist points z0 = r0 eθ0 ∈ ∆ and ζ0 ∈ ∂∆ − E(q), and an m ≥ n ≥ 1 for which p(∆r0 ) ⊂ q(∆), (1.6) (i) (ii) (iii) p(z0 ) = q(ζ0 ) z0 p0 (z0 ) = mζ0 q 0 (ζ0 ), and <[z0 p00 (z0 )/p0 (z0 ) + 1] ≥ m<[z0 q 00 (z0 )/q 0 (z0 ) + 1], where ∆r := {z ∈ C : |z| < r}. Theorem 1.4 (cf. Miller and Mocanu [2, Theorem 2.3i (i), p. 35]). Let Ω be a simply connected domain and ψ : C3 × ∆ → C satisfies the condition Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page ψ(iσ, ζ, µ + iη; z) 6∈ Ω for z ∈ ∆ and for real σ, ζ, µ, η satisfying ζ ≤ −n(1 + σ 2 )/2 and ζ + µ ≤ 0. Let p(z) = 1 + pn z n + pn+1 z n+1 + · · · be analytic in ∆. If ψ(p(z), zp0 (z), z 2 p00 (z); z) ∈ Ω, then <p(z) > 0. Contents JJ J II I Go Back Close Quit Page 7 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au 2. Differential Subordination with Convex Functions of Order α By appealing to Theorem 1.3, we first prove the following: Theorem 2.1. Let h be a convex univalent function of order α, 0 ≤ α < 1, in ∆ with h(0) = 0 and let A ≥ 0. Suppose that k > 22(1−α) |h0 (0)| and that B(z), C(z) and D(z) are analytic in ∆ and satisfy Certain Second Order Linear Differential Subordinations V. Ravichandran (2.1) n<B(z) ≥ n(1 − αn)A + 1 [|C(z) − 1| − <(C(z) − 1)] + k|D(z)|, 2β(α) where Title Page Contents α 4 (1 − 2α) α 6= 4 − 22α+1 β(α) := (log 4)−1 α= (2.2) 1 2 1 . 2 If p ∈ H[0, n] satisfies the differential subordination JJ J II I Go Back Close Quit (2.3) then p ≺ h. 2 00 0 Az p (z) + B(z)zp (z) + C(z)p(z) + D(z) ≺ h(z), Page 8 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au Proof. Our proof of Theorem 2.1 is essentially similar to Theorem 1.2 of Miller and Mocanu [2]. Let the subordination in (2.3) be satisfied so that D(0) = 0. Since k|h0 (0)| > 22(1−α) , there is an r0 , 0 < r0 < 1 such that (1 + r0 )2(1−α) (1 + r)2(1−α) = k|h0 (0)| and 22(1−α) < < k|h0 (0)| r0 r for r0 < r < 1. Since h is convex of order α in ∆, the function hr (z) = h(rz) is convex of order α in ∆ (r0 < r < 1). By setting pr (z) = p(rz) for r0 < r < 1, we see that the subordination (2.3) becomes (2.4) ur (z) := Az 2 p00r (z) + B(rz)zp0r (z) + C(rz)pr (z) + D(rz) ≺ hr (z) (z ∈ ∆; r0 < r < 1). Assume that pr is not subordinate to hr , for some r in (r0 , 1). Then by Theorem 1.3 there exist points z0 ∈ ∆, w0 ∈ ∂∆ and an m ≥ n ≥ 1 such that pr (z0 ) = hr (w0 ), z0 p0r (z0 ) = mw0 h0r (w0 ), (2.5) (2.6) < z0 p00 (z0 ) 1+ 0r pr (z0 ) ≥ m< w0 h00 (w0 ) 1+ 0 r hr (w0 ) V. Ravichandran Title Page Contents JJ J II I Go Back Close . Quit Page 9 of 25 Therefore we have (2.7) Certain Second Order Linear Differential Subordinations < z02 p00r (z0 ) 1+ mw0 h0 (w0 ) ≥ mα. J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au From Equations (2.5), (2.6) and (2.7), it follows that 2 00 z0 pr (z0 ) (2.8) < ≥ m(mα − 1). w0 h0r (w0 ) Since hr (z) is convex of order α or equivalently zh00r (z) < 1+ 0 > α (z ∈ ∆), hr (z) by [2, Theorem 3.3f, p.115], we have zh0 (z) < r > β(α) (z ∈ ∆) hr (z) where β(α) is given by Equation (2.2) and this condition is equivalent to hr (z) 1 1 zh0 (z) − 2β(α) ≤ 2β(α) (z ∈ ∆). r Therefore, 1 hr (w0 ) ≥ {<[C(rz0 ) − 1] − |C(rz0 ) − 1|}. (2.9) < (C(rz0 ) − 1) w0 h0r (w0 ) 2β Since h is convex of order α, we have the following well-known estimate: |h0 (z)| ≥ |h0 (0)| (1 + r)2(1−α) (|z| = r < 1). Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page Contents JJ J II I Go Back Close Quit Page 10 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au By setting z = rw0 , we see that (2.10) |w0 h0r (w0 )| ≥ r|h0 (0)| (1 + r)2(1−α) (|w0 | = 1). By setting (2.11) V := Az02 p00r (z0 ) B(rz0 )z0 p0r (z0 ) + w0 h0r (w0 ) w0 h0r (w0 ) + (C(rz0 ) − 1) pr (z0 ) D(rz0 ) + , w0 h0r (w0 ) w0 h0r (w0 ) V. Ravichandran we see that (2.12) Certain Second Order Linear Differential Subordinations ur (z0 ) = hr (w0 ) + V w0 h0r (w0 ). From (2.8), (2.9), (2.10) and (2.11), we have 1 <V ≥ m(mα − 1)A + m<B(rz0 ) + [<(C(rz0 ) − 1) − |C(rz0 ) − 1|] 2β(α) (1 + r)2(1−α) − |D(rz0 )| r|h0 (0)| ≥ m[(nα − 1)A + <B(rz0 )] 1 [<(C(rz0 ) − 1) − |C(rz0 ) − 1|] − k|D(rz0 )| + 2β(α) ≥ n[(nα − 1)A + <B(rz0 )] 1 − [|C(rz0 ) − 1| − <(C(rz0 ) − 1)] − k|D(rz0 )| ≥ 0, 2β(α) Title Page Contents JJ J II I Go Back Close Quit Page 11 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au it follows that ur (z0 ) 6∈ hr (∆), a contradiction. Therefore, pr ≺ hr for r ∈ (r0 , 1). By letting r → 1− , we obtain the desired conclusion p ≺ h. Remark 2.1. When α = 0, n = 1, Theorem 2.1 reduces to Theorem 1.2 of Miller and Mocanu [2]. From the proof of Theorem 2.1, it is clear that the condition h(0) = 0 in not necessary when C(z) = 1 and hence the following: Corollary 2.2. Let h be a convex univalent function of order α, 0 ≤ α < 1, in ∆, h(0) = a and let A ≥ 0. Suppose that Certain Second Order Linear Differential Subordinations k > 22(1−α) /|h0 (0)| V. Ravichandran and that B(z) and D(z) are analytic in ∆ with D(0) = 0 and Title Page (2.13) n < B(z) ≥ n(1 − αn)A + k|D(z)| for all z ∈ ∆. If p ∈ H[a, n], p(0) = h(0), satisfies the differential subordination (2.14) Az 2 p00 (z) + B(z)zp0 (z) + p(z) + D(z) ≺ h(z), Contents JJ J II I Go Back then p ≺ h. Close By taking A = 0 and D(z) = 0 in Theorem 2.1, we obtain the following: Corollary 2.3. Let h be a convex univalent function of order α, 0 ≤ α < 1, in ∆ with h(0) = 0. Let B(z) and C(z) be analytic functions on ∆ satisfying <B(z) ≥ 1 [|C(z) − 1| − <(C(z) − 1)], 2nβ(α) Quit Page 12 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au where β(α) is as given in Theorem 2.1. If p ∈ H[0, n] satisfies the subordination B(z)zp0 (z) + C(z)p(z) ≺ h(z), then p(z) ≺ h(z). By taking B(z) = 1, α = 0, n = 1, in Corollary 2.3, we have the following: Corollary 2.4. Let h be a convex univalent function in ∆ with h(0) = 0. Let C(z) be analytic functions on ∆ satisfying <C(z) > |C(z) − 1|. Certain Second Order Linear Differential Subordinations V. Ravichandran If the analytic function p(z) satisfies the subordination Title Page zp0 (z) + C(z)p(z) ≺ h(z), then p(z) ≺ h(z). Contents JJ J II I Go Back Close Quit Page 13 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au 3. Differential Subordination with Caratheodory Functions of Order α By appealing to Theorem 1.4, we now prove the following: Theorem 3.1. Let n be a positive integer and A(z) = A ≥ 0. Suppose that the functions B(z), C(z), D(z) : ∆ → C satisfy <B(z) ≥ A and (3.1) [= C(z)]2 ≤ n [<B(z) − A] 2+δ δ + 2α × n(<B(z) − A) − < C(z) − <(D(z) − α) . 1−α 1−α If p ∈ H[1, n] and (3.2) then 2 00 Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page 0 <{Az p (z) + B(z)zp (z) + C(z)p(z) + D(z)} > α δ + 2α <p(z) > . δ+2 (α < 1), Contents JJ J II I Go Back Proof. Define the function P (z) by Close p(z) − γ P (z) := 1−γ where δ + 2α γ := . δ+2 Quit Page 14 of 25 Then inequality (3.2) can be written as <{ψ(P (z), zP 0 (z), z 2 P 00 (z); z)} > 0, J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au where ψ(r, s, t; z) = At + B(z)s + C(z)r + γC(z) + D(z) − α . 1−γ In view of Theorem 1.4, it is enough to show that <ψ(iσ, ζ, µ + iη; z) ≤ 0 for all real numbers σ, ζ, µ and η with ζ ≤ z ∈ ∆. Now, −n(1+σ 2 ) , 2 ζ + µ ≤ 0 and for all Certain Second Order Linear Differential Subordinations V. Ravichandran <ψ(iσ, ζ, µ + iη; z) γC(z) + D(z) − α = µA + ζ<B(z) − σ=C(z) + < 1−γ γC(z) + D(z) − α ≤ ζ(<B(z) − A) − σ=C(z) + < 1−γ 1 ≤ − n[<B(z) − A]σ 2 + 2=C(z)σ 2 γC(z) + D(z) − α +n[<B(z) − A] − 2< ≤ 0, 1−γ provided (3.1) holds. This completes the proof of our Theorem 3.1. For α = δ = 0, Theorem 3.1 reduces to Theorem 1.1. By taking D = 0 and C(z) = 1 in Theorem 3.1, we have the following: Title Page Contents JJ J II I Go Back Close Quit Page 15 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au Corollary 3.2. Let A ≥ 0 and <B(z) − A > δ > 0. If p ∈ H[1, n] satisfies <{Az 2 p00 (z) + B(z)zp0 (z) + p(z)} > α (α < 1) then nδ + 2α . nδ + 2 Corollary 3.3. Let λ(z) and R(z) be functions defined on ∆ and <p(z) > <λ(z) > δ + 2+δ <R(z) ≥ 0. (1 − α)n If p ∈ H[1, n] satisfies Certain Second Order Linear Differential Subordinations V. Ravichandran <{λ(z)zp0 (z) + p(z) + R(z)} > α (α < 1), then 2α + δn . 2 + δn A special case of Corollary 3.3 is obtained by Owa and Srivastava [8, Lemma 2, p. 254]. The proof of the following theorem is similar and hence it is omitted. <p(z) > Theorem 3.4. Let n be a positive integer and A(z) = A ≥ 0. Suppose that the functions B(z), C(z), D(z) : ∆ → C satisfy <B(z) ≥ A and (3.3) [=C(z)]2 δ + 2α 2+δ ≤ n[<B(z)−A] n(<B(z) − A) − < C(z) − <(D(z) − α) . 1−α 1−α Title Page Contents JJ J II I Go Back Close Quit Page 16 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au If p ∈ H[1, n] satisfies (3.4) <{Az 2 p00 (z) + B(z)zp0 (z) + C(z)p(z) + D(z)} < α then <p(z) < (α > 1), δ + 2α . δ+2 Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page Contents JJ J II I Go Back Close Quit Page 17 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au 4. Applications We now give certain applications of our results obtained in Section 2 and 3. Theorem 4.1. Let γ ∈ C with γ 6= −1, −2, −3, . . . and let φ, Φ be analytic functions on ∆ with φ(z)Φ(z) 6= 0 for z ∈ ∆. If <C(z) − |C(z) − 1| > 1 − 2nβ(α)<B(z), where γΦ(z) + zΦ0 (z) Φ(z) and C(z) := , φ(z) φ(z) then the integral operator defined by Z z 1 I(f )(z) := γ tγ−1 f (t)φ(t)dt z Φ(z) 0 B(z) := satisfies I(f )(z) ≺ h(z) for every function f (z) ≺ h(z) where h(z) is a convex function of order α. Proof. The result follows immediately from Corollary 2.3. Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page Contents JJ J II I Go Back Theorem 4.2. Let h be a convex univalent function of order α in ∆, 0 ≤ α < 1 and h(0) = 1. Let M, N, R be analytic in ∆ with R(0) = 0 and M (z) = z n + . . . , and N (z) = z n + . . . . Let βN (z) < 0 > k|R(z)| zN (z) 22(1−α) k> 0 |h (0)| . Close Quit Page 18 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au If (4.1) β M 0 (z) M (z) + (1 − β) + R(z) ≺ h(z), 0 N (z) N (z) then M (z) ≺ h(z). N (z) Proof. Let the function p(z) be defined by Certain Second Order Linear Differential Subordinations p(z) = M (z)/N (z). V. Ravichandran Then p(0) = 1 = h(0) and it follows that M 0 (z) N (z) 0 p(z) + zp (z) = . zN 0 (z) N 0 (z) Also, a computation shows that the subordination in (4.1) is equivalent to p(z) + βN (z) 0 zp (z) + R(z) ≺ h(z). zN 0 (z) The result now follows by an application of Corollary 2.2 Remark 4.1. When β = 1, α = 0, Theorem 4.2 reduces to [2, Theorem 4.1h, p. 199] of Miller and Mocanu. If α = 0 and R(z) = 0, then Theorem 4.2 reduces to a result of Juneja and Ponnusamy [7, Corollary 1, p. 290]. Title Page Contents JJ J II I Go Back Close Quit Page 19 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 More generally, we have the following: http://jipam.vu.edu.au Theorem 4.3. Let δ > −p be any real number, λ ∈ C with <λ ≥ 0. Let R(z) be a function defined on ∆ with R(0) = 0 and h(z) a convex function of order α, 0 ≤ α < 1, h(0) = 1. Let g ∈ Ap satisfy Dδ+p−1 g(z) 22(1−α) < λ δ+p ≥ µ(δ + p)|R(z)|, k> 0 . D g(z) |h (0)| If f ∈ Ap satisfies δ+p−1 µ µ−1 Dδ+p f (z) Dδ+p−1 f (z) D f (z) + λ δ+p + R(z) ≺ h(z), (1 − λ) Dδ+p−1 g(z) D g(z) Dδ+p−1 g(z) Certain Second Order Linear Differential Subordinations V. Ravichandran then Dδ+p−1 f (z) Dδ+p−1 g(z) µ ≺ h(z). Proof. Let the function p(z) be defined by δ+p−1 µ D f (z) p(z) := . Dδ+p−1 g(z) Then a computation shows that the following subordination holds: B(z)zp0 (z) + p(z) + R(z) ≺ h(z), where Dδ+p−1 g(z) λ B(z) := . µ(δ + p) Dδ+p g(z) The result follows by an application of Corollary 2.2. Title Page Contents JJ J II I Go Back Close Quit Page 20 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au When R(z) = 0 and µ = 1, the Theorem 4.3 reduces to Juneja and Ponnusamy [7, Theorem 1, p. 289]. Theorem 4.4. Let α be a complex number <α > 0 and β < 1. Let M, N, R be analytic in ∆ with R(0) = 0 and M (z) := z n + c1 z n+k + · · · , Let < N (z) := z n + d1 z n+k + · · · . αN (z) 2 + δk >δ+ <R(z). 0 zN (z) (1 − β)k If Certain Second Order Linear Differential Subordinations V. Ravichandran (4.2) then <[α M (z) M 0 (z) + (1 − α) + R(z)] > β, 0 N (z) N (z) Contents M (z) 2β + kδ < > . N (z) 2 + kδ Proof. Let p(z) := M (z)/N (z). Then p(0) = 1 = h(0). It follows that N (z) 0 M 0 (z) zp (z) = 0 . p(z) + zN 0 (z) N (z) JJ J II I Go Back Close Quit Then <p(z) + Title Page αN (z) 0 M 0 (z) M (z) zp (z) + R(z) = <[α + (1 − α) + R(z)] 0 0 zN (z) N (z) N (z) > β. Page 21 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au If B(z) is defined by B(z) := αN (z)/[zN 0 (z)], then it follows that <B(z) > δ + 2 + δk <R(z). (1 − β)k The result now follows by an application of Corollary 3.3 Remark 4.2. For R(z) = 0, β = 0, Theorem 4.4 is due to Karunakaran and Ponnusamy [6, Theorem B, p. 562]. Theorem 4.5. Let δ > −p be any real number, λ ∈ C with <λ ≥ 0. Let R(z) be a function defined on ∆ with R(0) = 0, 0 ≤ α < 1. Let g ∈ Ap satisfies Dδ+p−1 g(z) µ(δ + p)(2 + δ) > µ(δ + p)δ + <R(z) ≥ 0. < λ δ+p D g(z) 1−α If f ∈ Ap satisfies ( ) δ+p−1 µ µ−1 D f (z) Dδ+p f (z) Dδ+p−1 f (z) < (1 − λ) + λ δ+p + R(z) > α, Dδ+p−1 g(z) D g(z) Dδ+p−1 g(z) Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page Contents JJ J II I Go Back then Dδ+p−1 f (z) Dδ+p−1 g(z) µ ≥ 2α + δ . 2+δ Close Quit Page 22 of 25 Proof. Let p(z) := δ+p−1 D f (z) δ+p−1 D g(z) µ . J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au Then a computation shows that <{B(z)zp0 (z) + p(z) + R(z)} > α, where B(z) := λ Dδ+p−1 g(z) . µ(δ + p) Dδ+p g(z) The result follows easily. Certain Second Order Linear Differential Subordinations V. Ravichandran Title Page Contents JJ J II I Go Back Close Quit Page 23 of 25 J. Ineq. Pure and Appl. Math. 5(3) Art. 59, 2004 http://jipam.vu.edu.au References [1] B.C. CARLSON AND S.B. SHAFFER, Starlike and prestarlike hypergeometric functions, SIAM J. Math. Anal., 15 (1984), 737–745. [2] S.S. MILLER AND P.T. MOCANU, Differential Subordinations: Theory and Applications, Series in Pure and Applied Mathematics, No. 225, Marcel Dekker, New York, (2000). [3] S.S. MILLER, P.T. MOCANU AND M.O. READE, Differential subordinations and univalent functions, Michigan Math. J., 28 (1981), 157–171. Certain Second Order Linear Differential Subordinations [4] S.S. MILLER AND P.T. MOCANU, The theory and applications of second order differential subordinations, Studia Univ. Babes-Bolyai, Math., 34(4) (1989), 3–33. V. Ravichandran [5] S.S. MILLER AND P.T. MOCANU, Classes of univalent integral operators, J. Math. Anal. Appl., 157 (1991), 147–165. Contents [6] V. KARUNAKARAN AND S. 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