Journal of Inequalities in Pure and Applied Mathematics http://jipam.vu.edu.au/ Volume 4, Issue 4, Article 66, 2003 INCLUSION THEOREMS FOR ABSOLUTE SUMMABILITY METHODS H. S. ÖZARSLAN D EPARTMENT OF M ATHEMATICS , E RCIYES U NIVERSITY, 38039 K AYSERI , T URKEY. seyhan@erciyes.edu.tr Received 07 April, 2003; accepted 30 April, 2003 Communicated by L. Leindler A BSTRACT. In this paper we have proved two theorems concerning an inclusion between two absolute summability methods by using any absolute summability factor. Key words and phrases: Absolute summability, Summability factors, Infinite series. 2000 Mathematics Subject Classification. 40D15, 40F05, 40G99. 1. I NTRODUCTION P Let an be a given infinite series with partial sums (sn ), and rn = nan . By un and Ptn we denote the n-th (C, 1) means of the sequences (sn ) and (rn ), respectively. The series an is said to be summable |C, 1|k , k ≥ 1, if (see [4]) ∞ X (1.1) nk−1 |un − un−1 |k < ∞. n=1 But since tn = n(un − un−1 ) (see [7]), the condition (1.1) can also be written as ∞ X 1 |tn |k < ∞. n n=1 (1.2) The series P an is said to be summable |C, 1; δ|k k ≥ 1 and δ ≥ 0, if (see [5]) (1.3) ∞ X nδk−1 |tn |k < ∞. n=1 If we take δ = 0, then |C, 1; δ|k summability is the same as |C, 1|k summability. ISSN (electronic): 1443-5756 c 2003 Victoria University. All rights reserved. 046-03 2 H. S. Ö ZARSLAN Let (pn ) be a sequence of positive numbers such that Pn = (1.4) n X pv → ∞ as n → ∞, (P−i = p−i = 0, i ≥ 1). v=0 The sequence-to-sequence transformation Tn = (1.5) n 1 X p v sv Pn v=0 defines the sequence (Tn ) of the (N̄ , pn ) mean of the sequence (sn ), generated by the sequence of coefficientsP(pn ) (see [6]). The series an is said to be summable N̄ , pn k , k ≥ 1, if (see [1]) k−1 ∞ X Pn (1.6) |∆Tn−1 |k < ∞ pn n=1 and it is said to be summable N̄ , pn ; δ k , k ≥ 1 and δ ≥ 0, if (see [3]) δk+k−1 ∞ X Pn (1.7) |∆Tn−1 |k < ∞, pn n=1 where ∆Tn−1 = − (1.8) n pn X Pv−1 av , Pn Pn−1 v=1 n ≥ 1. N̄ , pn ; δ summability is the In the special case when δ = 0 (resp. p = 1 for all values of n) n k same as N̄ , pn k (resp. |C, 1; δ|k ) summability. Concerning inclusion relations between |C, 1|k and N̄ , pn k summabilities, the following theorems are known. Theorem 1.1. ([1]).Let k ≥ 1 and let (pn ) be a sequence of positive numbers such that as n→∞ (i) Pn = O(npn ), (1.9) If the series P (ii) npn = O(Pn ). an is summable |C, 1|k , then it is also summable N̄ , pn k . Theorem 1.2. ([2]). Let k ≥ 1 and let (pn ) be a sequence of positive numbers such that P condition (1.9) of Theorem 1.1 is satisfied. If the series an is summable N̄ , pn k , then it is also summable |C, 1|k . 2. T HE M AIN R ESULT The aim of this paper is to generalize the above theorems for |C, 1; δ|k and N̄ , pn ; δ k summabilities, by using a summability factors. Now, we shall prove the following theorems. Theorem 2.1. Let k ≥ 1 and 0 ≤ δk < 1. Let (pn ) be a sequence of positive numbers such that Pn = O(npn ) and ( ) δk−1 ∞ δk X Pn 1 Pv 1 (2.1) =O . pn Pn−1 pv Pv n=v+1 J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 http://jipam.vu.edu.au/ I NCLUSION T HEOREMS FOR A BSOLUTE S UMMABILITY M ETHODS 3 P P Let an be summable |C, 1; δ|k . Then an λn is summable N̄ , pn ; δ k , if (λn ) satisfies the following conditions: 1−δk k Pn (2.2) n∆λn = O , npn λn = O (2.3) Pn npn k1 . Theorem 2.2. Let k ≥ 1 and 0 ≤ δk < 1. Let (pn ) be P a sequence of positive numbers such . Then that np = O(P ) and satisfies the condition (2.1). Let a be summable N̄ , p ; δ n n n n k P an λn is summable |C, 1; δ|k , if (λn ) satisfies the following conditions: 1−δk k npn (2.4) n∆λn = O Pn λn = O (2.5) npn Pn k1 . Remark 2.3. It may be noted that, if we take λn = 1 and δ = 0 in Theorem 2.1 and Theorem 2.2, then we get Theorem 1.1 and Theorem 1.2, respectively. In this case condition (2.1) reduces to m+1 m+1 X X 1 pn 1 1 = − =O as m → ∞, P P Pn−1 Pn Pv n=v+1 n n−1 n=v+1 which always holds. Proof of Theorem 2.1. Since n 1 X tn = vav n + 1 v=1 we have that n+1 tn − tn−1 . n P Let (Tn ) denote the (N̄ , pn ) mean of the series an λn . Then, by definition and changing the order of summation, we have n v n 1 X X 1 X Tn = pv ai λ i = (Pn − Pv−1 )av λv . Pn v=0 i=0 Pn v=0 an = Then, for n ≥ 1, we have Tn − Tn−1 n pn X Pv−1 av λv . = Pn Pn−1 v=1 By Abel’s transformation, we have Tn − Tn−1 = n−1 n−1 pn X v+1 pn X v+1 Pv ∆λv tv − p v λv tv Pn Pn−1 v=1 v Pn Pn−1 v=1 v n−1 p n X Pv pn n + 1 + λv+1 tv + λn tn Pn Pn−1 v=1 v Pn n = Tn,1 + Tn,2 + Tn,3 + Tn,4 , J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 say. http://jipam.vu.edu.au/ 4 H. S. Ö ZARSLAN Since |Tn,1 + Tn,2 + Tn,3 + Tn,4 |k ≤ 4k (|Tn,1 |k + |Tn,2 |k + |Tn,3 |k + |Tn,4 |k ), to complete the proof of the theorem, it is enough to show that δk+k−1 ∞ X Pn (2.6) pn n=1 |Tn,r |k < ∞ for r = 1, 2, 3, 4. Now, when k > 1, applying Hölder’s inequality with indices k and k 0 , where get m+1 X n=2 ≤ Pn pn δk+k−1 m+1 X n=2 = O(1) Pn pn n=2 = O(1) m+1 X n=2 = O(1) m+1 X n=2 = O(1) = O(1) m X v=1 m X = O(1) 1 k0 = 1, we Pn pn !k v+1 Pv |tv | |∆λv | v v=1 n−1 X 1 k Pn−1 δk−1 n−1 X Pv |tv | |v∆λv | pv vpv v=1 !k n−1 X |tv | |v∆λv | pv 1 k Pn−1 Pn pn δk−1 Pn pn δk−1 1 k Pn−1 Pn−1 |tv |k |v∆λv |k pv |tv |k |v∆λv |k pv v=1 m+1 X n=v+1 k k |tv | |v∆λv | !k v=1 n−1 X 1 v=1 m X + |Tn,1 |k δk−1 m+1 X 1 k Pv pv Pn pn δk−1 1 n−1 X Pn−1 v=1 1 n−1 X Pn−1 v=1 !k−1 pv 1 Pn−1 δk−1 v δk−1 |tv |k = O(1) m → ∞. as v=1 by virtue of the hypotheses of Theorem 2.1. Again using Hölder’s inequality, m+1 X n=2 Pn pn δk+k−1 = O(1) m+1 X n=2 = O(1) |Tn,2 |k m X Pn pn 1 n−1 X Pn−1 v=1 δk−1 k k pv |tv | |λv | v=1 J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 m+1 X n=v+1 pv |tv |k |λv |k Pn pn δk−1 !k−1 pv 1 Pn−1 http://jipam.vu.edu.au/ I NCLUSION T HEOREMS FOR A BSOLUTE S UMMABILITY M ETHODS = O(1) = O(1) δk−1 m X Pv v=1 m X pv 5 |tv |k |λv |k v δk−1 |tv |k |λv |k v=1 = O(1) m X v δk−1 |tv |k = O(1) as m → ∞, v=1 by virtue of the hypotheses of Theorem 2.1. Also m+1 X Pn δk+k−1 |Tn,3 |k pn n=2 ≤ m+1 X n=2 = O(1) Pn pn δk−1 m+1 X n=2 = O(1) m+1 X n=2 = O(1) = O(1) = O(1) m X v=1 m X v=1 m X Pn pn Pn pn !k |λv+1 | |tv | Pv v v=1 n−1 X 1 k Pn−1 δk−1 !k |λv+1 | |tv | vpv v v=1 n−1 X 1 k Pn−1 1 n−1 X Pn−1 v=1 δk−1 k m+1 X k pv |λv+1 | |tv | |tv | Pv pv δk−1 Pn pn δk−1 1 n X Pn−1 v=1 k pv |λv+1 | |tv | n=v+1 k k !k−1 pv 1 Pn−1 |λv+1 |k v δk−1 |tv |k = O(1) as m → ∞, v=1 by virtue of the hypotheses of Theorem 2.1. Lastly δk+k−1 δk−1 m m X X Pn Pn k |Tn,4 | = O(1) |λn |k |tn |k p p n n n=1 n=1 m X Pn δk−1 = O(1) |λn |k |tn |k nδk−1 np n n=1 = O(1) m X nδk−1 |tn |k = O(1) as m → ∞, n=1 by virtue of the hypotheses of Theorem 2.1. This completes the proof of Theorem 2.1. Proof of Theorem 2.2. Let (Tn ) denotes the (N̄ , pn ) mean of the series P an . We have n n 1 X 1 X Tn = p v sv = (Pn − Pv−1 )av . Pn v=0 Pn v=0 J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 http://jipam.vu.edu.au/ 6 H. S. Ö ZARSLAN Since Tn − Tn−1 = n pn X Pv−1 av , Pn Pn−1 v=0 we have that an = (2.7) −Pn Pn−2 ∆Tn−1 + ∆Tn−2 . pn pn−1 Let n 1 X tn = vav λv . n + 1 v=1 By using (2.7) we get n 1 X −Pv Pv−2 tn = v ∆Tv−1 + ∆Tv−2 λv n + 1 v=1 pv pv−1 n−1 n 1 X Pv nPn λn 1 X Pv−2 = (−v) ∆Tv−1 λv − ∆Tn−1 + v ∆Tv−2 λv n + 1 v=1 pv (n + 1)pn n + 1 v=1 pv−1 n−1 n−1 1 X Pv 1 X Pv−1 nPn λn (−v) ∆Tv−1 λv + (v + 1) ∆Tv−1 λv+1 − ∆Tn−1 = n + 1 v=1 pv n + 1 v=1 pv (n + 1)pn n−1 nPn λn 1 X ∆Tv−1 {−vλv Pv + (v + 1)λv+1 Pv−1 } − ∆Tn−1 = n + 1 v=1 pv (n + 1)pn n−1 = nPn λn 1 X ∆Tv−1 {−vλv Pv + (v + 1)λv+1 (Pv − pv )} − ∆Tn−1 n + 1 v=1 pv (n + 1)pn n−1 nPn λn 1 X ∆Tv−1 {−vλv Pv + (v + 1)λv+1 Pv − (v + 1)λv+1 pv } − ∆Tn−1 = n + 1 v=1 pv (n + 1)pn n−1 1 X ∆Tv−1 nPn λn = {−(∆vλv )Pv − (v + 1)λv+1 pv } − ∆Tn−1 n + 1 v=1 pv (n + 1)pn n−1 n−1 1 X −Pv 1 X = ∆Tv−1 {v∆λv − λv+1 } − ∆Tv−1 (v + 1)λv+1 n + 1 v=1 pv n + 1 v=1 nPn λn ∆Tn−1 (n + 1)pn n−1 n−1 1 X vPv 1 X Pv =− ∆λv ∆Tv−1 + ∆Tv−1 λv+1 n + 1 v=1 pv n + 1 v=1 pv − n−1 1 X nPn λn − (v + 1)λv+1 ∆Tv−1 − ∆Tn−1 n + 1 v=1 (n + 1)pn = tn,1 + tn,2 + tn,3 + tn,4 , say. Since |tn,1 + tn,2 + tn,3 + tn,4 |k ≤ 4k (|tn,1 |k + |tn,2 |k + | |tn,3 |k + |t4|k ), J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 http://jipam.vu.edu.au/ I NCLUSION T HEOREMS FOR A BSOLUTE S UMMABILITY M ETHODS 7 to complete the proof of Theorem 2.2, it is enough to show that ∞ X nδk−1 |tn,r |k < ∞ f or r = 1, 2, 3, 4. n=1 Now, when k > 1 applying Hölder’s inequality with indices k and k 0 , where have that m+1 X n−1 X Pv m+1 X 1 nδk−1 |tn,1 |k ≤ nδk−1 k n n=2 n=2 ≤ m+1 X n=2 ≤ n=2 n2−δk v=1 n2−δk v=1 m X v=1 = O(1) = O(1) Pv pv Pv pv k k = O(1) as k |∆λv | v k |∆Tv−1 | = 1, we k k m+1 X n=v+1 |∆λv |k v k |∆Tv−1 |k pv !k−1 n−1 1X 1 n v=1 |∆λv |k v k |∆Tv−1 |k k pv v=1 δk+k−1 m X Pv v=1 k |∆λv | v |∆Tv−1 | k m X Pv 1 k0 v |∆λv | |∆Tv−1 | pv n−1 X 1 = O(1) pv + !k k n−1 X Pv 1 m+1 X v=1 1 k 1 n2−δk 1 v 1−δk |∆Tv−1 |k m → ∞, by virtue of the hypotheses of Theorem 2.2. Again using Hölder’s inequality, m+1 X k nδk−1 |tn,2 | ≤ n=2 m+1 X !k Pv |λv+1 | |∆Tv−1 | pv v=1 n−1 X nδk−1−k n=2 ≤ m+1 X 1 n2−δk k n−1 X Pv |λv+1 |k |∆Tv−1 |k !k−1 n−1 1X 1 n v=1 pv k m+1 X Pv 1 k k = O(1) |λv+1 | |∆Tv−1 | 2−δk pv n v=1 n=v+1 m k X Pv 1 = O(1) |λv+1 |k |∆Tv−1 |k 1−δk pv v v=1 m X Pv δk+k−1 = O(1) ) |∆Tv−1 |k p v v=1 n=2 v=1 m X = O(1) J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 as m → ∞, http://jipam.vu.edu.au/ 8 H. S. Ö ZARSLAN Also, we have that m+1 X nδk−1 |tn,3 |k ≤ n=2 m+1 X n−1 X nδk−1−k n=2 !k (v + 1) |λv+1 | |∆Tv−1 | v=1 = O(1) m+1 X n−1 X nδk−1−k n=2 = O(1) = O(1) = O(1) = O(1) m X v=1 m X n−1 X 1 n2−δk m+1 X n=2 v |λv+1 | |∆Tv−1 | v=1 m+1 X n=2 !k v=1 n−1 X 1 n2−δk v k |λv+1 |k |∆Tv−1 |k !k−1 n−1 1X 1 n v=1 v k |λv+1 |k |∆Tv−1 |k v=1 v k |λv+1 |k |∆Tv−1 |k m+1 X n=v+1 1 n2−δk v δk+k−1 |∆Tv−1 |k v=1 = O(1) δk+k−1 m X Pv pv v=1 |∆Tv−1 |k as m → ∞, = O(1) by virtue of the hypotheses of Theorem 2.2. Finally, we have that m X n δk−1 k |tn,4 | = O(1) n=1 = O(1) k m X Pn nδk−1 |λn |k |∆Tn−1 |k pn n=1 δk+k−1 m X Pn n=1 = O(1) as pn |∆Tn−1 |k m → ∞, by virtue of the hypotheses of Theorem 2.2. Therefore, we get that m X nδk−1 |tn,r |k = O(1) as m → ∞, for r = 1, 2, 3, 4. n=1 This completes the proof of Theorem 2.2. R EFERENCES [1] H. BOR, On two summability methods, Math. Proc. Cambridge Phil. Soc., 97 (1985), 147–149. [2] H. BOR, A note on two summability methods, Proc. Amer. Math. Soc., 98 (1986), 81–84. [3] H. BOR, On the local property of N̄ , pn ; δ k summability of factored Fourier series, J. Math. Anal. Appl., 179 (1993), 646–649. [4] T.M. FLETT, On an extension of absolute summability and some theorems of Littlewood and Paley, Proc. London Math. Soc., 7 (1957), 113–141. J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 http://jipam.vu.edu.au/ I NCLUSION T HEOREMS FOR A BSOLUTE S UMMABILITY M ETHODS 9 [5] T.M. FLETT, Some more theorems concerning the absolute summability of Fourier series, Proc. London Math. Soc., 8 (1958), 357–387. [6] G.H. HARDY, Divergent Series, Oxford University Press., Oxford, (1949). [7] E. KOGBETLIANTZ, Sur les series absolument sommables par la methode des moyannes aritmetiques, Bull. Sci. Math., 49(2) (1925), 234–256. J. Inequal. Pure and Appl. Math., 4(4) Art. 66, 2003 http://jipam.vu.edu.au/