Journal of Inequalities in Pure and Applied Mathematics http://jipam.vu.edu.au/ Volume 4, Issue 1, Article 16, 2003 HILBERT-PACHPATTE TYPE INTEGRAL INEQUALITIES AND THEIR IMPROVEMENT S.S. DRAGOMIR AND YOUNG-HO KIM S CHOOL OF C OMPUTER S CIENCE AND M ATHEMATICS V ICTORIA U NIVERSITY OF T ECHNOLOGY PO B OX 14428 , M ELBOURNE C ITY MC V ICTORIA 8001, AUSTRALIA . sever.dragomir@vu.edu.au URL: http://rgmia.vu.edu.au/SSDragomirWeb.html D EPARTMENT OF A PPLIED M ATHEMATICS C HANGWON NATIONAL U NIVERSITY C HANGWON 641-773, KOREA . yhkim@sarim.changwon.ac.kr Received 31 October, 2002; accepted 8 January, 2003 Communicated by P.S. Bullen A BSTRACT. In this paper, we obtain an extension of multivariable integral inequality of HilbertPachpatte type. By specializing the upper estimate functions in the hypothesis and the parameters, we obtain many special cases. Key words and phrases: Hilbert’s inequality, Hilbert-Pachpatte type inequality, Hölder’s inequality, Jensen inequality. 2000 Mathematics Subject Classification. 26D15. 1. I NTODUCTION Hilbert’s double series theorem [3, p. 226] was proved first by Hilbert in his lectures on integral equations. The determination of the constant, the integral analogue, the extension, other proofs of the whole or of parts of the theorems and generalizations in different directions have been given by several authors (cf. [3, Chap. 9]). Specifically, in [10] – [14] the author has established some new inequalities similar to Hilbert’s double-series inequality and its integral analogue which we believe will serve as a model for further investigation. Recently, G.D. Handley, J.J. Koliha and J.E. Pečarić [2] established a new class of related integral inequalities from which the results of Pachpatte [12] – [14] are obtained by specializing the parameters and the functions Φi . A representative sample is the following. ISSN (electronic): 1443-5756 c 2003 Victoria University. All rights reserved. The authors would like to thank Professor P.S. Bullen, University of British Columbia, Canada, for the careful reading of the manuscript which led to a considerable improvement in the presentation of this paper. 114-02 2 S.S. D RAGOMIR AND YOUNG -H O K IM Theorem 1.1 (Handley, Koliha and Pečarić [2, Theorem 3.1]). Let ui ∈ C mi ([0, xi ]) for i ∈ I. If Z si (ki ) (si − τi )mi −ki −1 Φi (τi ) dτi , si ∈ [0, xi ], i ∈ I, ui (si ) ≤ 0 then Z x1 xn Z ··· 0 0 Qn (ki ) u (s ) i i i=1 ds1 · · · dsn Pn (αi +1)/(qi ωi ) ω s i i i=1 n Z n 1 Y Y qi ≤U xi i=1 where U = 1 .Q n i=1 [(αi 1 qi i=1 xi βi +1 (xi − si ) pi Φi (si ) dsi p1 i , 0 1 pi + 1) (βi + 1) ] . The purpose of the present paper is to derive an extension of the inequality given in Theorem 1.1. In addition, we obtain some new inequalities as Hilbert-Pachpatte type inequalities, these inequalities improve the results obtained by Handley, Koliha and Pečarić [2]. 2. M AIN R ESULTS In what follows we denote by R the set of real numbers; R+ denotes the interval [0, ∞). The symbols N, Z have their usual meaning. The following notation and hypotheses will be used throughout the paper: I = {1, ..., n} n∈N mi , i ∈ I mi ∈ N ki , i ∈ I ki ∈ {0, 1, . . . , mi − 1} xi , i ∈ I xi ∈ R, xi > 0 pi , qi , i ∈ I pi , qi ∈ R, pi , qi > 0, p1i + q1i = 1 Pn 1 1 Pn 1 1 = i=1 pi , q = i=1 qi p p, q ai , bi , i ∈ I ωi , i ∈ I ai , bi ∈ R+ , ai + bi = 1 Pn ωi ∈ R, ωi > 0, i=1 ωi = Ωn αi , i ∈ I αi = (ai + bi qi )(mi − ki − 1) βi , i ∈ I βi = ai (mi − ki − 1) ui , i ∈ I ui ∈ C mi ([0, xi ]) for some m0i ≥ mi Φi , i ∈ I Φi ∈ C 1 ([0, xi ]), Φi ≥ mi . 0 Here the ui are given functions of sufficient smoothness, and the Φi are subject to choice. The coefficients pi , qi are conjugate Hölder exponents to be used in applications of Hölder’s inequality, and the coefficients ai , bi will be used in exponents to factorize integrands. The coefficients ωi will act as weights in applications of the geometric-arithmetic mean inequality. J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 http://jipam.vu.edu.au/ H ILBERT-PACHPATTE T YPE I NTEGRAL I NEQUALITIES 3 The coefficients αi and βi arise naturally in the derivation of the inequalities. Our main results are given in the following theorems. Theorem 2.1. Let ui ∈ C mi ([0, xi ]) for i ∈ I. If Z si (ki ) (2.1) (si − τi )mi −ki −1 Φi (τi ) dτi , si ∈ [0, xi ], i ∈ I, ui (si ) ≤ 0 then Z x1 Z xn ··· (2.2) 0 0 h 1 Ωn Qn (ki ) u (s ) i i=1 i iΩn ds1 · · · dsn Pn (αi +1)/(qi ωi ) i=1 ωi si p1 n n Z xi 1 Y Y i qi βi +1 pi ≤V xi (xi − si ) Φi (si ) dsi , i=1 0 i=1 where V =Q h n (2.3) i=1 1 1 qi (αi + 1) (βi + 1) 1 pi i. Proof. Factorize the integrand on the right side of (2.1) as (si − τi )(ai /qi +bi )(mi −ki −1) × (si − τi )(ai /pi )(mi −ki −1) Φi (τi ) and apply Hölder’s inequality [9, p.106]. Then q1 Z si i (ki ) (ai +bi qi )(mi −ki −1) (si − τi ) dτi ui (si ) ≤ 0 Z si × ai (mi −ki −1) (si − τi ) p1 pi Φi (τi ) dτi i 0 = (α +1)/qi si i (αi + 1) si Z 1 qi βi pi (si − τi ) Φi (τi ) dτi p1 i . 0 Using the inequality of means [9, p. 15] ! Ω1 n n Y wi si ≤ i=1 n 1 X wi sri Ωn i=1 ! r1 for r > 0, we deduce that n Y i=1 " ir sw i n 1 X ≤ wi sri Ωn i=1 # Ωn for r > 0. According to above inequality, we have " # Ωn n n Y X 1 1 (ki ) (α +1)/(qi ωi ) ωi si i ui (si ) ≤ Qn 1 Ωn i=1 qi i=1 i=1 (αi + 1) p1 n Z s i Y i βi pi × (si − τi ) Φi (τi ) dτi i=1 J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 0 http://jipam.vu.edu.au/ 4 S.S. D RAGOMIR AND YOUNG -H O K IM for r = (αi + 1)/qi ωi . In the following estimate we apply Hölder’s inequality and, at the end, change the order of integration: Qn (ki ) Z x1 Z xn i=1 ui si ··· h P iΩn ds1 · · · dsn (αi +1)/(qi ωi ) n 1 0 0 i=1 ωi si Ωn " Z Z # p1 n xi si Y i 1 ≤Q (si − τi )βi Φi (τi )pi dτi , dsi 1 n qi 0 0 (α + 1) i=1 i i=1 Z xi Z si p1 n 1 Y i 1 qi βi pi ≤Q xi (si − τi ) Φi (τi ) dτi , dsi 1 n qi 0 0 i=1 i=1 (αi + 1) p1 n n Z xi 1 Y Y i 1 qi =Q xi (xi − si )βi +1 Φi (si )pi dsi . 1 1 n qi pi 0 [(α + 1) (β + 1) ] i=1 i=1 i i i=1 This proves the theorem. Remark 2.2. In Theorem 2.1, setting Ωn = 1, we have Theorem 1.1. Corollary 2.3. Under the assumptions of Theorem 2.1, if r > 0, we have Z x1 Z ··· 0 0 Qn (ki ) i=1 ui si xn h 1 Ωn (αi +1)/(qi ωi ) i=1 ωi si Pn ≤p 1 r·p V iΩn ds1 · · · dsn n Y 1 qi xi i=1 " 1 Z xi r # r·p n X 1 (xi − si )βi +1 Φi spi i dsi , p i 0 i=1 where V is defined by (2.3). Proof. By the inequality of means, for any Ai ≥ 0 and r > 0, we obtain n Y 1 pi Ai i=1 " n X 1 r Ai ≤ p p i i=1 1 # r·p . The corollary then follows from the preceding theorem. Pn Lemma 2.4. Let γ1 > 0 and γ2 < −1. Let ωi > 0, i=1 ωi = Ωn and let si > 0, i = 1, . . . , n be real numbers. Then " #−γ1 Ωn n n Y 1 X ωi γ1 γ2 −γ2 si ≥ ωi si . Ωn i=1 i=1 Proof. By the inequality of means, for any γ1 > 0 and γ2 < −1, we have n Y " sωi i γ1 γ2 i=1 J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 n 1 X ≥ ωi si Ωn i=1 # γ1 γ2 Ωn . http://jipam.vu.edu.au/ H ILBERT-PACHPATTE T YPE I NTEGRAL I NEQUALITIES 5 − γ1 Using the fact that x " is concave and using the Jensen inequality, we have that # γ1 γ2 Ωn " # γ 1 γ2 Ω n n n 1 X 1 X −γ2 ωi si = ωi f (si ) Ωn i=1 Ωn i=1 !#γ1 γ2 Ωn " n X 1 2 ωi s−γ ≥ f i Ωn i=1 !− γ1 γ1 γ2 Ωn n 2 X 1 2 = ωi s−γ i Ωn i=1 " #−γ1 Ωn n 1 X −γ2 = ωi si . Ωn i=1 2 The proof of the lemma is complete. Theorem 2.5. Under the assumptions of Theorem 2.1, if γ2 < −1, then Qn (ki ) Z x1 Z xn i=1 ui (si ) ··· i−(αi +1)Ωn /γ2 qi ωi ds1 · · · dsn h P n −γ2 1 0 0 ω s i=1 i i Ωn p1 n n Z xi 1 Y Y i qi βi +1 pi ≤V xi (xi − si ) Φi (si ) dsi , i=1 0 i=1 where V is given by (2.3). Proof. Using the inequality of Lemma 2.4, for any γ1 > 0 and γ2 < −1, we get " #− γ1γΩn n n 2 Y X 1 2 sωi i γ1 ≤ ωi s−γ . i Ωn i=1 i=1 According to above inequality, we deduce that #−W1 " n n Y 1 1 X (ki ) 2 ωi s−γ ui (si ) ≤ Qn 1 i Ω qi n i=1 i=1 i=1 (αi + 1) "Z # p1 n (si ) i Y × (si − τi )βi Φi (τi )pi dτi , i=1 0 where W1 = (αi + 1)Ωn /γ2 qi ωi . The proof of the theorem then follows from the preceding Theorem 2.1. Corollary 2.6. Under the assumptions of Theorem 2.5, if r > 0, we have Qn (ki ) Z x1 Z xn i=1 ui (si ) ··· h P i−(αi +1)Ωn /γ2 qi ωi ds1 · · · dsn n −γ2 1 0 0 i=1 ωi si Ωn 1 " n r # r·p n 1 Y X 1 Z xi 1 qi (xi − si )βi +1 Φi (si )pi dsi ≤ p r·p V xi , p i 0 i=1 i=1 J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 http://jipam.vu.edu.au/ 6 S.S. D RAGOMIR AND YOUNG -H O K IM where V is given by (2.3). Proof. By the inequality of means, for any Ai ≥ 0 and r > 0, we obtain 1 " n # r·p n 1 Y X 1 r p . Ai i ≤ p A p i i=1 i=1 i The corollary then follows from the preceding Theorem 2.5. In the following section we discuss some choice of the functions Φi . 3. T HE VARIOUS I NEQUALITIES (j) Theorem 3.1. Let ui ∈ C mi ([0, xi ]) be such that ui (0) = 0 for j ∈ {0, . . . , mi − 1}, i ∈ I. Then Qn (ki ) Z x1 Z xn i=1 ui (si ) (3.1) ··· iΩn ds1 · · · dsn h P (αi +1)/(qi ωi ) n 1 0 0 i=1 ωi si Ωn p1 n n Z xi pi 1 Y Y i qi βi +1 (mi ) ≤ V1 xi (xi − si ) , ui (si ) dsi i=1 i=1 0 where (3.2) V1 = Q h n i=1 1 1 1 (mi − ki − 1)!(αi + 1) qi (βi + 1) pi i. Proof. Inequality (3.1) is proved when we set Φi (si ) = (mi ) u (s ) i i (mi − ki − 1)! in Theorem 2.1. Corollary 3.2. Under the assumptions of Theorem 3.1, if r > 0, we have Qn (ki ) Z x1 Z xn u (s ) i i=1 i ··· iΩn ds1 · · · dsn h P (αi +1)/(qi ωi ) n 1 0 0 ω s i=1 i i Ωn 1 " n Z xi r # r·p n pi 1 Y X 1 1 (m ) q xi i (xi − si )βi +1 ui i (si ) dsi , ≤ p r·p V1 p 0 i=1 i i=1 where V1 is given by (3.2). Theorem 3.3. Under the assumptions of Theorem 3.1, if γ2 < −1, then Qn (ki ) Z x1 Z xn u (s ) i i=1 i (3.3) ··· i−(αi +1)Ωn /γ2 qi ωi ds1 · · · dsn h P n −γ2 1 0 0 ω s i=1 i i Ωn p1 n n Z xi pi 1 Y Y i (m ) qi , ≤ V1 xi (xi − si )βi +1 ui i (si ) dsi i=1 i=1 0 where V1 is given by (3.2). J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 http://jipam.vu.edu.au/ H ILBERT-PACHPATTE T YPE I NTEGRAL I NEQUALITIES 7 Proof. Inequality (3.3) is proved when we set Φi (si ) = (mi ) ui (si ) (mi − ki − 1)! in Theorem 2.5. Corollary 3.4. Under the assumptions of Theorem 3.3, if r > 0, we have Z x1 Z xn ··· 0 h 0 1 Ωn Qn (ki ) (s ) u i i i=1 i−(αi +1)Ωn /γ2 qi ωi ds1 · · · dsn Pn −γ2 i=1 ωi si 1 " n Z xi r # r·p n pi 1 Y X 1 1 (m ) q ≤ p r·p V1 xi i (xi − si )βi +1 ui i (si ) dsi . p i 0 i=1 i=1 We discuss a number of special cases of Theorem 3.1. Similar examples apply also to Corollary 3.2, Theorem 3.3 and Corollary 3.4. Example 3.1. If ai = 0 and bi = 1 for i ∈ I, then Theorem 3.1 becomes Z x1 Z xn ··· 0 Qn (ki ) i=1 ui (si ) h 0 1 Ωn (qi mi −qi ki −qi +1)/(qi ωi ) i=1 ωi si Pn ≤ V2 n Y iΩn ds1 · · · dsn 1 qi xi i=1 n Z Y xi 0 i=1 p1 pi i (mi ) , (xi − si ) ui (si ) dsi where V2 = Q h n i=1 1 1 (mi − ki − 1)!(qi mi − qi ki − qi + 1) qi i. Example 3.2. If ai = 0, bi = 1, qi = n, pi = n/(n − 1), mi = m and ki = k for i ∈ I, then Z x1 Z ··· 0 0 Qn (ki ) i=1 ui (si ) xn h 1 Ωn Pn (nm−nk−n+1)/(nωi ) i=1 ωi si iΩn ds1 · · · dsn √ n x1 · · · xn n ≤ (m − k − 1)! (nm − nk − n + 1) n−1 n Z xi n Y n (m) n−1 . × (xi − si ) ui (si ) dsi i=1 0 For q = p = n = 2 and ωi = n1 this is [12, Theorem 1]. Setting q = p = 2, k = 0, n = 1 and ωi = n1 , we recover the result of [14]. J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 http://jipam.vu.edu.au/ 8 S.S. D RAGOMIR AND YOUNG -H O K IM Example 3.3. If ai = 0 and bi = 1 for i ∈ I, then Theorem 3.1 becomes Qn (ki ) Z x1 Z xn (s ) u i i i=1 ··· iΩn ds1 · · · dsn h P (mi −ki )/(qi ωi ) n 1 0 0 i=1 ωi si Ωn p1 n n Z xi pi 1 Y Y i qi mi −ki (mi ) ≤ V3 xi (xi − si ) , ui (si ) dsi i=1 i=1 0 where 1 . V3 = Qn i=1 (mi − ki )! Example 3.4. If ai = 1, bi = 0, qi = n, pi = n/(n − 1), mi = m and ki = k for i ∈ I. Then (3.1) becomes Qn (ki ) Z x1 Z xn i=1 ui (si ) ··· iΩn ds1 · · · dsn h P (m−k)/(nωi ) n 1 0 0 ω s i=1 i i Ωn (n−1) √ n Z xi n/(n−1) n n x1 · · · xn Y m−k (m) n ≤ (xi − si ) dsi . ui (si ) (m − k)! i=1 0 Example 3.5. Let p1 , p2 ∈ R+ . If we set n = 2, ω1 = p11 , ω2 = p12 , mi = 1 and ki = 0 for i = 1, 2 in Theorem 3.1, then by our assumptions q1 = p1 /(p1 − 1), q2 = p2 /(p2 − 1), and we obtain Z x1 Z x2 |u1 (s1 )| |u2 (s2 )| h iΩ2 ds1 ds2 (p1 −1) (p2 −1) 1 0 0 p 2 s1 + p 1 s2 p1 p2 Ω2 p1 Z x1 1 p1 (p1 −1)/p1 (p2 −1)/p2 0 ≤ x1 x2 (x1 − s1 ) |u1 (s1 )| ds1 0 Z × x2 (x2 − p s2 ) |u02 (s2 )| 2 p1 ds2 2 . 0 If we set ω1 + ω2 = 1 in Example 3.5, then we have [13, Theorem 2]. (The values of ai and bi are irrelevant.) R EFERENCES [1] BICHENG YANG, On Hilbert’s integral inequality, J. Math. Anal. Appl., 220 (1988), 778–785. [2] G.D. HANDLEY, J.J. KOLIHA AND PEČARIĆ, New Hilbert-Pachpatte type integral inequalities, J. Math. Anal. Appl., 257 (2001), 238–250. [3] G.H. HARDY, J.E. LITTLEWOOD AND G. POLYA, Inequalities, Cambridge Univ. Press, London, 1952. [4] YOUNG-HO KIM, Refinements and Extensions of an inequality, J. Math. Anal. Appl., 245 (2000), 628–632. [5] V. LEVIN, On the two-parameter extension and analogue of Hilbert’s inequality, J. London Math. Soc., 11 (1936), 119–124. J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 http://jipam.vu.edu.au/ H ILBERT-PACHPATTE T YPE I NTEGRAL I NEQUALITIES 9 [6] G. MINGZE, On Hilbert’s inequality and its applications, J. Math. Anal. Appl., 212 (1997), 316– 323. [7] D.S. MITRINOVIĆ, Analytic inequalities, Springer-Verlag, Berlin, New York, 1970. [8] D.S. MITRINOVIĆ AND J.E. PEČARIĆ, On inequalities of Hilbert and Widder, Proc. Edinburgh Math. Soc., 34 (1991), 411–414. [9] D.S. MITRINOVIĆ, J.E. PEČARIĆ AND A.M. FINK, Classical and New Inequalities in Analysis, Kluwer Academic, Dordrecht, 1993. [10] B.G. PACHPATTE, A note on Hilbert type inequality, Tamkang J. Math., 29 (1998), 293–298. [11] B.G. PACHPATTE, On some new inequalities similar to Hilbert’s inequality, J. Math. Anal. Appl., 226 (1998), 166–179. [12] B.G. PACHPATTE, Inequalities similar to the integral analogue of Hilbert’s Inequality, Tamkang J. Math., 30 (1999), 139–146. [13] B.G. PACHPATTE, Inequalities similar to certain extensions of Hilbert’s inequality, J. Math. Anal. Appl., 243 (2000), 217–227. [14] B.G. PACHPATTE, A note on inequality of Hilbert type, Demonstratio Math., in press. [15] D.V. WIDDER, An inequality related to one of Hilbert’s, J. London Math. Soc., 4 (1929), 194–198. J. Inequal. Pure and Appl. Math., 4(1) Art. 16, 2003 http://jipam.vu.edu.au/