Volume 10 (2009), Issue 2, Article 59, 8 pp. ON THE EXISTENCE OF SOLUTIONS TO A CLASS OF p-LAPLACE ELLIPTIC EQUATIONS HUI-MEI HE AND JIAN-QING CHEN F UJIAN N ORMAL U NIVERSITY F UZHOU , 350007 P.R. C HINA hehuimei20060670@163.com jqchen@fjnu.edu.cn Received 19 September, 2008; accepted 07 December, 2008 Communicated by C. Bandle A BSTRACT. We study the equation −∆p u+|x|a |u|p−2 u = |x|b |u|q−2 u with Dirichlet boundary condition on B(0, R) or on RN . We prove the existence of the radial solution and nonradial solutions of this equation. Key words and phrases: p-Laplace elliptic equations, Radial solutions, Nonradial solutions. 2000 Mathematics Subject Classification. 35J20. 1. I NTRODUCTION AND M AIN R ESULT Equations of the form ( −∆t u + g(x)|u|s−2 u = f (x, u) in Ω u = 0, on ∂Ω (1.1) have attracted much attention. Many papers deal with the problem (1.1) in the case of t = 2, Ω = RN , s = 2, g large at infinity and f superlinear, subcritical and bounded in x, see e.g. [1], [2] and [4]. The problem (1.1) with t = 2, Ω = B(0, 1), g(x) = 0 and f (x, u) = |x|b ul−1 was studied in [9]; in particular, it was proved that under some conditions the ground states are not radial symmetric. The case t = 2, Ω = B(0, 1) or on RN , g(x) = 1 and f (x, u) = |x|b |u|l−2 u was studied in [7]. The problem (1.1) with t = s, Ω = RN , g(x) = V (|x|) and f (x, u) = Q(|x|)|u|l−2 u was studied by J. Su., Z.-Q. Wang and M. Willem ([11], [12]). They proved embedding results for functions in the weighted W 1,p (RN ) space of radial symmetry. The results were then used to obtain ground state and bound state solutions of equations with unbounded or decaying radial potentials. 255-08 2 H UI -M EI H E AND J IAN -Q ING C HEN In this paper, we consider the nonlinear elliptic problem −∆p u + |x|a |u|p−2 u = |x|b |u|q−2 u u > 0, u ∈ W 1,p (Ω), (1.2) u = 0, in Ω on ∂Ω and prove the existence of the radial and the nonradial solutions of the problem (1.2). Here, ∆p u = div(|∇u|p−2 ∇u) is the p-Laplacian operator, and 1 < p < N, a ≥ 0, b ≥ 0. We denote by Wr1,p (RN ) the space of radially symmetric functions in W 1,p (RN ) = u ∈ Lp (RN ) : ∇u ∈ Lp (RN ) . 1,p Wr,a (RN ) is denoted by the space of radially symmetric functions in Z N 1,p N a p 1,p |x| |u| < ∞ . Wa (R ) = u ∈ W (R ) : RN We also denote by Dr1,p (RN ) the space of radially symmetric functions in n o Np D1,p (RN ) = u ∈ L N −p RN : ∇u ∈ Lp RN . Our main results are: Theorem 1.1. If a ≥ 0, b ≥ 0, 1 < p < N and Np bp p < q < q̃ = + , N −p N −p (p − 1)(q − p) pb − a p + < (q − p)(N − 1), p then the problem (1.2) has a radial solution. Remark 1. In [8], Sirakov proves that the problem (1.2) with p = 2 has a solution for 4b 2N 2 < q < q# = − . N − 2 a(N − 2) In [6], P. Sintzoff and M. Willem proved the existence of a solution of the problem (1.2) with q p = 2, q ≤ 2∗ , 2b − a 1 + < (N − 1)(q − 2). 2 Theorem 1.1 extends the results of [6] to the general equation with a p−Laplacian operator. Theorem 1.2. Suppose that a ≥ 0, b ≥ 0, 1 < p < N and Np p<q< , N −p (p − 1)(q − p) pb − a p + < (q − p)(N − 1), aq < pb, p then for every R, problem (1.2) with Ω = B(0, R), R large enough has a radial and a nonradial solution. This paper is organized as follows: In Section 2, we study (1.2) in the case of Ω = RN . We prove the existence of a radial least energy solution of (1.2) when (p − 1)(q − p) 1 < p < N, p < q < q̃, pb − a p + < (q − p)(N − 1). p J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp. http://jipam.vu.edu.au/ R ADIAL S OLUTION AND N ONRADIAL S OLUTIONS 3 In Section 3, we consider the existence of nonradial solutions of (1.2) with Ω = B(0, R), R large enough. Finally, in Section 4, we consider necessary conditions for the existence of solutions of (1.2). 2. R ADIAL S OLUTION In this paper, unless stated otherwise, all integrals are understood to be taken over all of RN . Also, throughout the paper, we will often denote various constants by the same letter. Lemma 2.1. Suppose that 1 < p < N. There exist AN > 0, such that, for every u ∈ p 1,p Wr,a (RN ), u ∈ C(RN \{0}), for a ≥ p−1 (1 − N ), we have that Z p−1 Z 12 a(p−1) p2 p N −1 + p a p p2 |x| p |x| |u| |∇u| . |u(x)| ≤ AN Proof. Since p p −1 d p a· p−1 du p−1 N −1 p |u| r r = |u|2 2 · 2u · ra· p rN −1 dr 2 dr p−1 p−1 p + |u| a · + N − 1 ra· p −1 rN −1 , p and p a≥ (1 − N ), p−1 we get that du p−1 d p a· p−1 |u| r p rN −1 ≥ pu|u|p−2 ra· p rN −1 dr dr and obtain Z +∞ du p−1 a· p−1 r p rN −1 |u(r)|p ≤ AN |u|p−1 S N −1 S a· p dS dr r Z du p−1 ≤ AN |u|p−1 |x|a· p dx dr Z p−1 Z p1 p a p p |∇u| . ≤ AN |x| |u| It follows that p N −1+a· p−1 |x| Z p |u(x)| ≤ AN a p p−1 Z p |x| |u| p p1 |∇u| , and we have |x| a(p−1) N −1 + p p2 Z |u(x)| ≤ AN a p p−1 Z 2 |x| |u| p p 12 |∇u| p . Lemma 2.2. If 1 < p < N, p ≤ r < Z r |u| dx ≤ C pN , N −p Z then for any u ∈ W 1,p (RN ), we have that p |∇u| J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp. N (r−p) Z 2 p p |u| ) N p+r(p−N 2 p . http://jipam.vu.edu.au/ 4 H UI -M EI H E AND J IAN -Q ING C HEN Proof. The proof can be adapted directly from the Gagliardo-Nirenberg inequality. The following inequality extends the results of [5] to the general equation with the p−Laplacian operator. Lemma 2.3. For 1 < p < N, p<q< pN + N −p c N −1 p + a(p−1) p2 a≥ , p (1 − N ), p−1 there exist BN,p,c such that for every u ∈ Dr1,p (RN ), we have Z |x|c |u|q dx ≤ BN,p,c Z |∇u|p c p(N −1)+a(p−1) + N2 p 2 cp q−p− p(N −1)+a(p−1) . Proof. Using Lemma 2.1 and Lemma 2.2, we have Z |x|c |u|q dx Z |x| = Z ≤ a(p−1) N −1 + p p2 a p p−1 2 · p |x| |u| Z · Z = |∇u|p · |∇u|p Z ≤ BN,p,c c (N −1)/p+a(p−1)p−2 c (N −1)/p+a(p−1)p−2 N2 (q−p− p |x|a |u|p dx Z c c q− (N −1)/p+a(p−1)p−2 (N −1)/p+a(p−1)p−2 |u| |u| dx Z p c p(N −1)+a(p−1) + N2 p |u|p 12 · p |∇u| c ) (N −1)/p+a(p−1)p−2 c(p−1) p(N −1)+a(p−1) Z |∇u|p Z |u|p N2p + p−N 2 p N2p + p−N 2 p 2 cp q−p− p(N −1)+a(p−1) c p(N −1)+a(p−1) + N2 p 2 c (N −1)/p+a(p−1)p−2 p p 2 q− c (N −1)/p+a(p−1)p−2 cp q− p(N −1)+a(p−1) cp q−p− p(N −1)+a(p−1) . Next, to prove Theorem 1.1, we consider the following minimization problem Z p a p m = m(a, b, p, q) = inf |∇u| + |x| |u| dx. 1,p u∈Wr,a (RN ) R |x|b |u|q dx=1 Theorem 2.4. If a ≥ 0, b ≥ 0, 1 < p < N and Np bp + , N −p N −p (p − 1)(q − p) pb − a p + < (q − p)(N − 1), p p < q < q̃ = then m(a, b, p, q) is achieved. J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp. http://jipam.vu.edu.au/ R ADIAL S OLUTION AND N ONRADIAL S OLUTIONS 5 1,p Proof. Let (un ) ⊂ Wr,a (RN ) be a minimizing sequence for m = m(a, b, p, q) : Z |x|b |un |q dx = 1, Z (|∇un |p + |x|a |un |p ) dx → m. 1,p By going (if necessary) to a subsequence, we can assume that un * u in Wr,a (RN ). Hence, by weak lower semicontinuity, we have Z (|∇u|p + |x|a |u|p ) dx ≤ m, Z |x|b |u|q dx ≤ 1. If c is defined by q = pN N −p + Z pc , N −p then c < b and it follows from Lemma 2.3 that Z b q b−c |x| |un | dx ≤ ε |x|c |un |q dx ≤ Cεb−c . |x|≤ε 1,p Since (un ) is bounded in Wr,a (RN ). We deduce from Lemma 2.1 that Z Z b q |x| |un | dx = |x|b−a |un |q−p |x|a |un |p dx |x|≥ 1ε |x|≥ 1ε b−a−(q−p)( Np−1 + a(p−1) Z ) p2 1 ≤ C |x|a |u|p dx ε ≤ Cε a( q+1 − p (q−p)(N −1) q )−b+ p p2 . So we get that, for every t < 1, there exists ε > 0, such that for every n, Z |x|b |un |q dx ≥ t. ε≤|x|≤ 1ε By the Rellich theorem and Lemma 2.1, Z Z b q 1 ≥ |x| |un | dx ≥ |x|b |un |q dx ≥ t. ε≤|x|≤ 1ε Finally R |x|b |u|q dx = 1 and m = m(a, b, p, q) is achieved at u. Now we will prove Theorem 1.1. Proof. By Theorem 2.4, m is achieved. Then by the Lagrange multiplier rule, the symmetric criticality principle (see e.g. [13]) and the maximum principle, we obtain a solution of −∆p υ + |x|a |υ|p−2 υ = λ|x|b |υ|q−2 υ, υ > 0, υ ∈ W 1,p (RN ). 1 Hence u = λ q−p υ is a radial solution of (1.2), with λ = pq m. J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp. http://jipam.vu.edu.au/ 6 H UI -M EI H E AND J IAN -Q ING C HEN 3. N ONRADIAL S OLUTIONS In this section, we will prove Theorem 1.2. We use the preceding results to construct nonradial solutions of problem (1.2) in the case Ω = B(0, R). Consider Z p a p M = M (a, b, p, q) = inf |∇u| + |x| |u| dx. 1,p N a (R ) Ru∈W |x|b |u|q dx=1 It is clear that M ≤ m, and using our previous results, we prove that M is achieved under some conditions. Theorem 3.1. If a ≥ 0, b ≥ 0, 1 < p < N and p < q < q# = p2 b pN − , N − p a(N − p) then M (a, b, p, q) is achieved. Proof. Let (un ) ⊂ Wa1,p (RN ) be a minimizing sequence for M = M (a, b, p, q) : Z |x|b |un |q dx = 1, Z p a p |∇un | + |x| |un | dx → M. By going (if necessary) to a subsequence, we can assume that un * u in Wa1,p (RN ). Hence, by weak lower semicontinuity, we have Z p a p |∇u| + |x| |u| dx ≤ M, Z |x|b |u|q dx ≤ 1. If c is defined by q = pN N −p − p2 c , a(N −p) then c > b and a r= , c s= aN p N −p aq − pc are conjugate. It follows from the Hölder and Sobolev inequalities that b−c Z Z 1 b q |x| |un | dx ≤ |x|c |un |q dx 1 ε |x|≥ ε b−c Z pc pc 1 = |x|c |un | a |un |q− a dx ε 1s Z r1 Z Np c−b a p |un | N −p dx ≤ε |x| |un | dx ≤ Cεc−b . As in Theorem 2.4, for every t < 1, there exists ε > 0 such that, for every n, Z |x|b |un |q dx ≥ t. |x|≤ 1ε J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp. http://jipam.vu.edu.au/ R ADIAL S OLUTION AND N ONRADIAL S OLUTIONS 7 By the compactness of the Sobolev theorem in the bounded domain, for 1 < p < N, p < q < Np , N −p Z Z b q |x|b |un |q dx ≥ t. 1 ≥ |x| |u| dx ≥ |x|≤ 1ε Hence R |x|b |u|q dx = 1 and M = M (a, b, p, q) is achieved at u. Now we will prove Theorem 1.2. Proof. By Theorem 2.4, m(a, b, p, q) is positive. Since pb > aq, it is easy to verify that M (a, b, p, q) = 0. Let us define Z M (a, b, p, q, R) = inf |∇u|p + |x|a |u|p dx, 1,p R u∈Wa (B(0,R)) b q B(0,R) |x| |u| dx=1 B(0,R) Z m(a, b, p, q, R) = inf 1,p R u∈Wr,a (B(0,R)) |x|b |u|q dx=1 |∇u|p + |x|a |u|p dx. B(0,R) B(0,R) It is clear that, for every R > 0, M (a, b, p, q, R) and m(a, b, p, q, R) are achieved and lim M (a, b, p, q, R) = M (a, b, p, q) = 0, R→∞ lim m(a, b, p, q, R) = m(a, b, p, q) > 0. R→∞ Then from Theorem 1.1, we know that problem (1.2) with B(0, R) has a radial solution. On the other hand, by the Lagrange multiplier rule, the symmetric criticality principle (see e.g.[13]) and the maximum principle, we obtain a solution of a p−2 b q−2 −∆p υ + |x| |υ| υ = λ|x| |υ| υ in B(0, R) υ > 0, u ∈ W 1,p (B(0, R)), υ = 0, on ∂B(0, R). 1 Hence u = λ q−p υ is a solution of (1.2), with λ = pq M (a, b, p, q, R). Thus, Problem (1.2) has a nonradial solution. 4. N ECESSARY C ONDITIONS In this section we obtain a nonexistence result for the solution of problem (1.2) using a Pohozaev-type identity. The Pohozaev identity has been derived for very general problems by H. Egnell [3]. Lemma 4.1. Let u ∈ W 1,p (RN ) be a solution of (1.2), then u satisfies Z Z Z N −p N +a N +b p a p |∇u| dx + |x| |u| dx − |x|b |u|q dx = 0. p p q Theorem 4.2. Suppose that q̃ = Np pb + ≤q N −p N −p or N +a N +b ≤ . p q Then there is no solution for problem (1.2). J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp. http://jipam.vu.edu.au/ 8 H UI -M EI H E AND J IAN -Q ING C HEN Proof. Multiplying (1.2) by u and integrating, we see that Z Z b q |x| |u| dx = |∇u|p + |x|a |u|p dx. On the other hand, using Lemma 4.1, we obtain Z Z N +a N +b N −p N +b p − |∇u| dx + − |x|a |u|p dx = 0. p q p q So, if u is a solution of problem (1.2), we must have N −p N +b N +a N +b < , > . p q p q Remark 2. The second assumption of Theorem 2.4, (q − p)(p − 1) pb − a p + < (q − p)(N − 1) p implies that N +b N +a < . q p R EFERENCES [1] T. BARTSCH AND Z.-Q. 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