ON THE EXISTENCE OF SOLUTIONS TO A CLASS OF EQUATIONS

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Volume 10 (2009), Issue 2, Article 59, 8 pp.
ON THE EXISTENCE OF SOLUTIONS TO A CLASS OF p-LAPLACE ELLIPTIC
EQUATIONS
HUI-MEI HE AND JIAN-QING CHEN
F UJIAN N ORMAL U NIVERSITY
F UZHOU , 350007 P.R. C HINA
hehuimei20060670@163.com
jqchen@fjnu.edu.cn
Received 19 September, 2008; accepted 07 December, 2008
Communicated by C. Bandle
A BSTRACT. We study the equation −∆p u+|x|a |u|p−2 u = |x|b |u|q−2 u with Dirichlet boundary
condition on B(0, R) or on RN . We prove the existence of the radial solution and nonradial
solutions of this equation.
Key words and phrases: p-Laplace elliptic equations, Radial solutions, Nonradial solutions.
2000 Mathematics Subject Classification. 35J20.
1. I NTRODUCTION AND M AIN R ESULT
Equations of the form
(
−∆t u + g(x)|u|s−2 u = f (x, u)
in Ω
u = 0,
on ∂Ω
(1.1)
have attracted much attention. Many papers deal with the problem (1.1) in the case of t =
2, Ω = RN , s = 2, g large at infinity and f superlinear, subcritical and bounded in x, see e.g.
[1], [2] and [4]. The problem (1.1) with t = 2, Ω = B(0, 1), g(x) = 0 and f (x, u) = |x|b ul−1
was studied in [9]; in particular, it was proved that under some conditions the ground states
are not radial symmetric. The case t = 2, Ω = B(0, 1) or on RN , g(x) = 1 and f (x, u) =
|x|b |u|l−2 u was studied in [7]. The problem (1.1) with t = s, Ω = RN , g(x) = V (|x|) and
f (x, u) = Q(|x|)|u|l−2 u was studied by J. Su., Z.-Q. Wang and M. Willem ([11], [12]). They
proved embedding results for functions in the weighted W 1,p (RN ) space of radial symmetry.
The results were then used to obtain ground state and bound state solutions of equations with
unbounded or decaying radial potentials.
255-08
2
H UI -M EI H E AND J IAN -Q ING C HEN
In this paper, we consider the nonlinear elliptic problem

−∆p u + |x|a |u|p−2 u = |x|b |u|q−2 u


u > 0, u ∈ W 1,p (Ω),
(1.2)


u = 0,
in Ω
on ∂Ω
and prove the existence of the radial and the nonradial solutions of the problem (1.2). Here,
∆p u = div(|∇u|p−2 ∇u) is the p-Laplacian operator, and 1 < p < N, a ≥ 0, b ≥ 0.
We denote by Wr1,p (RN ) the space of radially symmetric functions in
W 1,p (RN ) = u ∈ Lp (RN ) : ∇u ∈ Lp (RN ) .
1,p
Wr,a
(RN ) is denoted by the space of radially symmetric functions in
Z
N
1,p
N
a
p
1,p
|x| |u| < ∞ .
Wa (R ) = u ∈ W (R ) :
RN
We also denote by Dr1,p (RN ) the space of radially symmetric functions in
n
o
Np
D1,p (RN ) = u ∈ L N −p RN : ∇u ∈ Lp RN .
Our main results are:
Theorem 1.1. If a ≥ 0, b ≥ 0, 1 < p < N and
Np
bp
p < q < q̃ =
+
,
N −p N −p
(p − 1)(q − p)
pb − a p +
< (q − p)(N − 1),
p
then the problem (1.2) has a radial solution.
Remark 1. In [8], Sirakov proves that the problem (1.2) with p = 2 has a solution for
4b
2N
2 < q < q# =
−
.
N − 2 a(N − 2)
In [6], P. Sintzoff and M. Willem proved the existence of a solution of the problem (1.2) with
q
p = 2, q ≤ 2∗ , 2b − a 1 +
< (N − 1)(q − 2).
2
Theorem 1.1 extends the results of [6] to the general equation with a p−Laplacian operator.
Theorem 1.2. Suppose that a ≥ 0, b ≥ 0, 1 < p < N and
Np
p<q<
,
N −p
(p − 1)(q − p)
pb − a p +
< (q − p)(N − 1), aq < pb,
p
then for every R, problem (1.2) with Ω = B(0, R), R large enough has a radial and a nonradial
solution.
This paper is organized as follows: In Section 2, we study (1.2) in the case of Ω = RN . We
prove the existence of a radial least energy solution of (1.2) when
(p − 1)(q − p)
1 < p < N, p < q < q̃, pb − a p +
< (q − p)(N − 1).
p
J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp.
http://jipam.vu.edu.au/
R ADIAL S OLUTION AND N ONRADIAL S OLUTIONS
3
In Section 3, we consider the existence of nonradial solutions of (1.2) with Ω = B(0, R), R
large enough. Finally, in Section 4, we consider necessary conditions for the existence of solutions of (1.2).
2. R ADIAL S OLUTION
In this paper, unless stated otherwise, all integrals are understood to be taken over all of RN .
Also, throughout the paper, we will often denote various constants by the same letter.
Lemma 2.1. Suppose that 1 < p < N. There exist AN > 0, such that, for every u ∈
p
1,p
Wr,a
(RN ), u ∈ C(RN \{0}), for a ≥ p−1
(1 − N ), we have that
Z
p−1
Z
12
a(p−1)
p2
p
N −1
+
p
a
p
p2
|x| p
|x| |u|
|∇u|
.
|u(x)| ≤ AN
Proof. Since
p
p −1
d p a· p−1
du p−1
N −1
p
|u| r
r
=
|u|2 2 · 2u · ra· p rN −1
dr
2
dr
p−1
p−1
p
+ |u| a ·
+ N − 1 ra· p −1 rN −1 ,
p
and
p
a≥
(1 − N ),
p−1
we get that
du p−1
d p a· p−1
|u| r p rN −1 ≥ pu|u|p−2 ra· p rN −1
dr
dr
and obtain
Z +∞
du p−1
a· p−1
r p rN −1 |u(r)|p ≤ AN
|u|p−1 S N −1 S a· p dS
dr
r
Z
du p−1
≤ AN |u|p−1 |x|a· p dx
dr
Z
p−1
Z
p1
p
a
p
p
|∇u|
.
≤ AN
|x| |u|
It follows that
p
N −1+a· p−1
|x|
Z
p
|u(x)| ≤ AN
a
p
p−1
Z
p
|x| |u|
p
p1
|∇u|
,
and we have
|x|
a(p−1)
N −1
+
p
p2
Z
|u(x)| ≤ AN
a
p
p−1
Z
2
|x| |u|
p
p
12
|∇u|
p
.
Lemma 2.2. If 1 < p < N, p ≤ r <
Z
r
|u| dx ≤ C
pN
,
N −p
Z
then for any u ∈ W 1,p (RN ), we have that
p
|∇u|
J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp.
N (r−p)
Z
2
p
p
|u|
)
N p+r(p−N
2
p
.
http://jipam.vu.edu.au/
4
H UI -M EI H E AND J IAN -Q ING C HEN
Proof. The proof can be adapted directly from the Gagliardo-Nirenberg inequality.
The following inequality extends the results of [5] to the general equation with the p−Laplacian
operator.
Lemma 2.3. For
1 < p < N,
p<q<
pN
+
N −p
c
N −1
p
+
a(p−1)
p2
a≥
,
p
(1 − N ),
p−1
there exist BN,p,c such that for every u ∈ Dr1,p (RN ), we have
Z
|x|c |u|q dx ≤ BN,p,c
Z
|∇u|p
c
p(N −1)+a(p−1)
+ N2
p
2
cp
q−p− p(N −1)+a(p−1)
.
Proof. Using Lemma 2.1 and Lemma 2.2, we have
Z
|x|c |u|q dx
Z |x|
=
Z
≤
a(p−1)
N −1
+
p
p2
a
p
p−1
2 ·
p
|x| |u|
Z
·
Z
=
|∇u|p
·
|∇u|p
Z
≤ BN,p,c
c
(N −1)/p+a(p−1)p−2
c
(N −1)/p+a(p−1)p−2
N2 (q−p−
p
|x|a |u|p dx
Z
c
c
q−
(N −1)/p+a(p−1)p−2
(N −1)/p+a(p−1)p−2
|u|
|u|
dx
Z
p
c
p(N −1)+a(p−1)
+ N2
p
|u|p
12 ·
p
|∇u|
c
)
(N −1)/p+a(p−1)p−2
c(p−1)
p(N −1)+a(p−1)
Z
|∇u|p
Z
|u|p
N2p + p−N
2
p
N2p + p−N
2
p
2
cp
q−p− p(N −1)+a(p−1)
c
p(N −1)+a(p−1)
+ N2
p
2
c
(N −1)/p+a(p−1)p−2
p
p
2
q−
c
(N −1)/p+a(p−1)p−2
cp
q− p(N −1)+a(p−1)
cp
q−p− p(N −1)+a(p−1)
.
Next, to prove Theorem 1.1, we consider the following minimization problem
Z p
a
p
m = m(a, b, p, q) =
inf
|∇u|
+
|x|
|u|
dx.
1,p
u∈Wr,a (RN )
R
|x|b |u|q dx=1
Theorem 2.4. If a ≥ 0, b ≥ 0, 1 < p < N and
Np
bp
+
,
N −p N −p
(p − 1)(q − p)
pb − a p +
< (q − p)(N − 1),
p
p < q < q̃ =
then m(a, b, p, q) is achieved.
J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp.
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R ADIAL S OLUTION AND N ONRADIAL S OLUTIONS
5
1,p
Proof. Let (un ) ⊂ Wr,a
(RN ) be a minimizing sequence for m = m(a, b, p, q) :
Z
|x|b |un |q dx = 1,
Z
(|∇un |p + |x|a |un |p ) dx → m.
1,p
By going (if necessary) to a subsequence, we can assume that un * u in Wr,a
(RN ). Hence, by
weak lower semicontinuity, we have
Z
(|∇u|p + |x|a |u|p ) dx ≤ m,
Z
|x|b |u|q dx ≤ 1.
If c is defined by q =
pN
N −p
+
Z
pc
,
N −p
then c < b and it follows from Lemma 2.3 that
Z
b
q
b−c
|x| |un | dx ≤ ε
|x|c |un |q dx ≤ Cεb−c .
|x|≤ε
1,p
Since (un ) is bounded in Wr,a
(RN ). We deduce from Lemma 2.1 that
Z
Z
b
q
|x| |un | dx =
|x|b−a |un |q−p |x|a |un |p dx
|x|≥ 1ε
|x|≥ 1ε
b−a−(q−p)( Np−1 + a(p−1)
Z
)
p2
1
≤
C |x|a |u|p dx
ε
≤ Cε
a( q+1
−
p
(q−p)(N −1)
q
)−b+
p
p2
.
So we get that, for every t < 1, there exists ε > 0, such that for every n,
Z
|x|b |un |q dx ≥ t.
ε≤|x|≤ 1ε
By the Rellich theorem and Lemma 2.1,
Z
Z
b
q
1 ≥ |x| |un | dx ≥
|x|b |un |q dx ≥ t.
ε≤|x|≤ 1ε
Finally
R
|x|b |u|q dx = 1 and m = m(a, b, p, q) is achieved at u.
Now we will prove Theorem 1.1.
Proof. By Theorem 2.4, m is achieved. Then by the Lagrange multiplier rule, the symmetric
criticality principle (see e.g. [13]) and the maximum principle, we obtain a solution of

 −∆p υ + |x|a |υ|p−2 υ = λ|x|b |υ|q−2 υ,

υ > 0, υ ∈ W 1,p (RN ).
1
Hence u = λ q−p υ is a radial solution of (1.2), with λ = pq m.
J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp.
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6
H UI -M EI H E AND J IAN -Q ING C HEN
3. N ONRADIAL S OLUTIONS
In this section, we will prove Theorem 1.2. We use the preceding results to construct nonradial solutions of problem (1.2) in the case Ω = B(0, R).
Consider
Z p
a
p
M = M (a, b, p, q) =
inf
|∇u|
+
|x|
|u|
dx.
1,p
N
a (R )
Ru∈W
|x|b |u|q dx=1
It is clear that M ≤ m, and using our previous results, we prove that M is achieved under some
conditions.
Theorem 3.1. If a ≥ 0, b ≥ 0, 1 < p < N and
p < q < q# =
p2 b
pN
−
,
N − p a(N − p)
then M (a, b, p, q) is achieved.
Proof. Let (un ) ⊂ Wa1,p (RN ) be a minimizing sequence for M = M (a, b, p, q) :
Z
|x|b |un |q dx = 1,
Z p
a
p
|∇un | + |x| |un | dx → M.
By going (if necessary) to a subsequence, we can assume that un * u in Wa1,p (RN ). Hence, by
weak lower semicontinuity, we have
Z p
a
p
|∇u| + |x| |u| dx ≤ M,
Z
|x|b |u|q dx ≤ 1.
If c is defined by q =
pN
N −p
−
p2 c
,
a(N −p)
then c > b and
a
r= ,
c
s=
aN p
N −p
aq − pc
are conjugate. It follows from the Hölder and Sobolev inequalities that
b−c Z
Z
1
b
q
|x| |un | dx ≤
|x|c |un |q dx
1
ε
|x|≥ ε
b−c Z
pc
pc
1
=
|x|c |un | a |un |q− a dx
ε
1s
Z
r1 Z
Np
c−b
a
p
|un | N −p dx
≤ε
|x| |un | dx
≤ Cεc−b .
As in Theorem 2.4, for every t < 1, there exists ε > 0 such that, for every n,
Z
|x|b |un |q dx ≥ t.
|x|≤ 1ε
J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp.
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R ADIAL S OLUTION AND N ONRADIAL S OLUTIONS
7
By the compactness of the Sobolev theorem in the bounded domain, for 1 < p < N, p < q <
Np
,
N −p
Z
Z
b
q
|x|b |un |q dx ≥ t.
1 ≥ |x| |u| dx ≥
|x|≤ 1ε
Hence
R
|x|b |u|q dx = 1 and M = M (a, b, p, q) is achieved at u.
Now we will prove Theorem 1.2.
Proof. By Theorem 2.4, m(a, b, p, q) is positive. Since pb > aq, it is easy to verify that
M (a, b, p, q) = 0. Let us define
Z
M (a, b, p, q, R) =
inf
|∇u|p + |x|a |u|p dx,
1,p
R u∈Wa (B(0,R))
b
q
B(0,R) |x| |u| dx=1
B(0,R)
Z
m(a, b, p, q, R) =
inf
1,p
R
u∈Wr,a (B(0,R))
|x|b |u|q dx=1
|∇u|p + |x|a |u|p dx.
B(0,R)
B(0,R)
It is clear that, for every R > 0, M (a, b, p, q, R) and m(a, b, p, q, R) are achieved and
lim M (a, b, p, q, R) = M (a, b, p, q) = 0,
R→∞
lim m(a, b, p, q, R) = m(a, b, p, q) > 0.
R→∞
Then from Theorem 1.1, we know that problem (1.2) with B(0, R) has a radial solution.
On the other hand, by the Lagrange multiplier rule, the symmetric criticality principle (see
e.g.[13]) and the maximum principle, we obtain a solution of

a
p−2
b
q−2

 −∆p υ + |x| |υ| υ = λ|x| |υ| υ in B(0, R)
υ > 0, u ∈ W 1,p (B(0, R)),


υ = 0,
on ∂B(0, R).
1
Hence u = λ q−p υ is a solution of (1.2), with λ = pq M (a, b, p, q, R). Thus, Problem (1.2) has a
nonradial solution.
4. N ECESSARY C ONDITIONS
In this section we obtain a nonexistence result for the solution of problem (1.2) using a
Pohozaev-type identity. The Pohozaev identity has been derived for very general problems by
H. Egnell [3].
Lemma 4.1. Let u ∈ W 1,p (RN ) be a solution of (1.2), then u satisfies
Z
Z
Z
N −p
N +a
N +b
p
a
p
|∇u| dx +
|x| |u| dx −
|x|b |u|q dx = 0.
p
p
q
Theorem 4.2. Suppose that
q̃ =
Np
pb
+
≤q
N −p N −p
or
N +a
N +b
≤
.
p
q
Then there is no solution for problem (1.2).
J. Inequal. Pure and Appl. Math., 10(2) (2009), Art. 59, 8 pp.
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8
H UI -M EI H E AND J IAN -Q ING C HEN
Proof. Multiplying (1.2) by u and integrating, we see that
Z
Z
b
q
|x| |u| dx =
|∇u|p + |x|a |u|p dx.
On the other hand, using Lemma 4.1, we obtain
Z
Z
N +a N +b
N −p N +b
p
−
|∇u| dx +
−
|x|a |u|p dx = 0.
p
q
p
q
So, if u is a solution of problem (1.2), we must have
N −p
N +b
N +a
N +b
<
,
>
.
p
q
p
q
Remark 2. The second assumption of Theorem 2.4,
(q − p)(p − 1)
pb − a p +
< (q − p)(N − 1)
p
implies that
N +b
N +a
<
.
q
p
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