INTEGRAL MEAN ESTIMATES FOR POLYNOMIALS WHOSE ZEROS ARE WITHIN A CIRCLE K.K. DEWAN, N. SINGH, B. CHANAM Department of Mathematics Faculty of Natural Sciences, Jamia Millia Islamia (Central University) New Delhi-110025, India Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page EMail: nareshkuntal@yahoo.co.in ABDULLAH MIR Post Graduate Department of Mathematics University of Kashmir Hazratbal, Srinagar-190006, India Contents JJ II J I Page 1 of 15 Received: 17 October, 2007 Accepted: 19 December, 2008 Communicated by: G.V. Milovanović 2000 AMS Sub. Class.: 30A10, 30C10, 30D15 Key words: Polynomials, Zeros of order m, Inequalities, Polar derivatives. Go Back Full Screen Close Abstract: Let p(z) be a polynomial of degree n. Zygmund [11] has shown that for s≥1 Z 0 2π |p0 (eiθ )|s dθ 1/s Z ≤n 2π |p(eiθ )|s dθ 1/s . 0 In this paper, we have obtained inequalities in the reverse direction for the polynomials having a zero of order m at the origin. We also consider a n P an−ν z n−ν not problem for the class of polynomials p(z) = an z n + ν=µ vanishing outside the disk |z| < k, k ≤ 1 and obtain a result which, besides yielding some interesting results as corollaries, includes a result due to Aziz and Shah [Indian J. Pure Appl. Math., 28 (1997), 1413–1419] as a special case. Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page Contents Acknowledgment: The work of second author is supported by Council of Scientific and Industrial Research, New Delhi, under grant F.No.9/466(78)/2004-EMR-I. JJ II J I Page 2 of 15 Go Back Full Screen Close Contents 1 Introduction and Statement of Results 4 2 Lemmas 9 3 Proofs of The Theorems 10 Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page Contents JJ II J I Page 3 of 15 Go Back Full Screen Close 1. Introduction and Statement of Results Let p(z) be a polynomial of degree n and p0 (z) its derivative. It was shown by Turán [10] that if p(z) has all its zeros in |z| ≤ 1, then n max |p(z)| . 2 |z|=1 max |p0 (z)| ≥ (1.1) |z|=1 More generally, if the polynomial p(z) has all its zeros in |z| ≤ k, k ≤ 1, it was proved by Malik [5] that the inequality (1.1) can be replaced by n (1.2) max |p0 (z)| ≥ max |p(z)| . |z|=1 1 + k |z|=1 Malik [6] obtained a Lp analogue of (1.1) by proving that if p(z) has all its zeros in |z| ≤ 1, then for each r > 0 (1.3) r1 2π Z iθ r |p(e )| dθ n 2π Z iθ r ≤ r1 |1 + e | dθ 0 max |p0 (z)|. |z|=1 0 As an extension of (1.3) and a generalization of (1.2), Aziz [1] proved that if p(z) has all its zeros in |z| ≤ k, k ≤ 1, then for each r > 0 2π Z (1.4) |p(eiθ )|r dθ n 0 r1 Z ≤ 2π |1 + keiθ |r dθ 0 r1 max |p0 (z)|. |z|=1 If we let r → ∞ in (1.3) and (1.4) and make use of the well known fact from analysis (see for example [8, p. 73] or [9, p. 91]) that Z 2π r1 → max p(eiθ ) as r → ∞ , (1.5) |p(eiθ )|r dθ 0 0≤θ<2π Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page Contents JJ II J I Page 4 of 15 Go Back Full Screen Close we get inequalities (1.1) and (1.2) respectively. In this paper, we will first obtain a Zygmund [11] type integral inequality, but in the reverse direction, for polynomials having a zero of order m at the origin. More precisely, we prove P j Theorem 1.1. Let p(z) = z m n−m j=0 aj z be a polynomial of degree n, having all its zeros in |z| ≤ k, k ≤ 1, with a zero of order m at z = 0. Then for β with |β| < k n−m and s ≥ 1 Z 2π (1.6) 0 s 1s 0 0 iθ mm i(m−1)θ p (e ) + dθ β̄e n k ≥ n − (n − m)Cs(k) vol. 10, iss. 1, art. 23, 2009 Z 2π 0 s 1s 0 iθ m imθ p(e ) + dθ , β̄e kn where m0 = min |p(z)|, |z|=k Cs(k) = 1 2π Z 2π |Sc + eiθ |s dθ − 1s and 0 an−m−1 an−m + 1 . Sc = an−m−1 1 k 2 + n−m an−m 1 n−m Corollary 1.2. If p(z) is a polynomial of degree n, having all its zeros in |z| ≤ 1, with a zero of order m at z = 0, then for s ≥ 1 2π iθ s |p(e )| dθ (1.7) 0 1s ≥ n − (n − m)Cs(1) Title Page Contents JJ II J I Page 5 of 15 Go Back Full Screen By taking k = 1 and β = 0 in Theorem 1.1, we obtain: Z Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir Z 2π iθ s |p(e )| dθ 0 1s , Close where Cs(1) = 1 1 R 2π |1 + eiθ |s dθ 2π 0 1s . By letting s → ∞ in Theorem 1.1, we obtain P j Corollary 1.3. Let p(z) = z m n−m j=0 aj z be a polynomial of degree n, having all its zeros in |z| ≤ k, k ≤ 1, with a zero of order m at z = 0. Then for β with |β| < k n−m Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 0 0 0 m + nS m mm c max p (z) + n β̄z m−1 ≥ max p(z) + n β̄z m , |z|=1 |z|=1 k 1 + Sc k (1.8) Title Page 0 where m and Sc are as defined in Theorem 1.1. By choosing the argument of β suitably and letting |β| → k n−m in Corollary 1.3, we obtain the following result. P j Corollary 1.4. Let p(z) = z m n−m j=0 aj z be a polynomial of degree n, having all its zeros in |z| ≤ k, k ≤ 1, with a zero of order m at z = 0. Then m + nSc (n − m)Sc m0 0 (1.9) max |p (z)| ≥ max |p(z)| + , |z|=1 |z|=1 1 + Sc 1 + Sc k m where m0 and Sc are as defined in Theorem 1.1. Let Dα p(z) denote the polar derivative of the polynomial p(z) of degree n with respect to the point α. Then Dα p(z) = np(z) + (α − z)p0 (z) . Contents JJ II J I Page 6 of 15 Go Back Full Screen Close The polynomial Dα p(z) is of degree at most (n − 1) and it generalizes the ordinary derivative in the sense that Dα p(z) = p0 (z) . α→∞ α lim (1.10) Our next result generalizes as well as improving upon the inequality (1.4), which in turns, gives a generalization as well as improvements of inequalities (1.3), (1.2) and (1.1) in terms of the polar derivatives of Lp inequalities. P Theorem 1.5. If p(z) = an z n + nj=µ an−j z n−j , 1 ≤ µ ≤ n, is a polynomial of degree n, having all its zeros in |z| ≤ k, k ≤ 1, then for every real or complex numbers α and β with |α| ≥ k µ and |β| ≤ 1 and for each r > 0 Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page (1.11) max |Dα p(z)| Contents |z|=1 ≥ R n(|α| − k µ ) 2π 0 |1 + k µ eiθ |r dθ Z 1 r 0 2π r r1 0 iθ n βm i(n−1)θ p(e ) + + n−µ m0 , e dθ n−µ k k JJ II J I Page 7 of 15 0 where m = min |p(z)|. |z|=k Dividing both sides of (1.11) by |α|, letting |α| → ∞ and noting that (1.10), we obtain P Corollary 1.6. If p(z) = an z n + nj=µ an−j z n−j , 1 ≤ µ ≤ n, is a polynomial of degree n, having all its zeros in |z| ≤ k, k ≤ 1, then for every real or complex Go Back Full Screen Close number β with |β| ≤ 1, for each r > 0 (1.12) max |p0 (z)| |z|=1 ≥ R 2π 0 Z n |1 + k µ eiθ |r dθ r1 0 2π r r1 0 iθ βm i(n−1)θ dθ , p(e ) + e k n−µ where m0 = min |p(z)|. |z|=k Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Remark 1. Letting r → ∞ in (1.12) and Pchoosing the argument of β suitably with |β| = 1, it follows that, if p(z) = an z n + nj=µ an−j z n−j , 1 ≤ µ ≤ n, is a polynomial of degree n, having all its zeros in |z| ≤ k, k ≤ 1, then n 1 0 (1.13) max |p (z)| ≥ max |p(z)| + n−µ min |p(z)| . |z|=k |z|=1 (1 + k µ ) |z|=1 k JJ II Inequality (1.13) was already proved by Aziz and Shah [2]. J I Title Page Contents Page 8 of 15 Go Back Full Screen Close 2. Lemmas For the proofs of these theorems we need the following lemmas. P Lemma 2.1. Let p(z) = nj=0 aj z j be a polynomial of degree n having no zeros in |z| < k, k ≥ 1. Then for s ≥ 1 Z 2π 0 iθ s 1s |p (e )| dθ (2.1) Z ≤ nSs 2π iθ s |p(e )| dθ 0 1s , 0 vol. 10, iss. 1, art. 23, 2009 where Ss = 1 2π Z 2π |Sc0 + eiθ |s dθ 1s h i 1 a1 + 1 n a0 Sc0 = . 1 a1 2 1 + n a0 k k2 and 0 The above lemma is due to Dewan, Bhat and Pukhta [3]. The following lemma is due to Rather [7]. P Lemma 2.2. Let p(z) = an z n + nj=µ an−j z n−j , 1 ≤ µ ≤ n, be a polynomial of degree n having all its zero in |z| ≤ k, k ≤ 1. Then (2.2) Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir k µ |p0 (z)| ≥ |q 0 (z)| + n k n−µ min |p(z)| for |z| = 1, |z|=k Title Page Contents JJ II J I Page 9 of 15 Go Back Full Screen Close where q(z) = z n p 1 z̄ . 3. Proofs of The Theorems Proof of Theorem 1.1. Let p(z) = z m n−m X aj z j = z m φ(z), (say) j=0 where φ(z) is a polynomial of degree n − m, with the property that φ(0) 6= 0 . Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Then 1 1 n−m q(z) = z p =z φ z̄ z̄ n Title Page is also a polynomial of degree n − m and has no zeros in |z| < k1 , k1 ≥ 1. Now if m0 1 1 n m0 = min1 |q(z)| = min1 z p = n min |p(z)| = n , z̄ k |z|=k k |z|= k |z|= k JJ II J I then, by Rouche’s theorem, the polynomial Page 10 of 15 q(z) + m0 βz n−m , Contents |β| < k n−m , Go Back 1 1 , k k Full Screen of degree n − m, will also have no zeros in |z| < ≥ 1. Hence, by Lemma 2.1, we have for s ≥ 1 and |β| < k n−m s 1s Z 2π 0 0 iθ q (e ) + m βei(n−m−1)θ (n − m) dθ n k 0 s 1s Z 2π 0 iθ m (k) i(n−m)θ dθ , q(e ) + ≤ (n − m)Cs βe kn 0 Close which implies 2π Z (3.1) 0 s 1s 0 m imθ iθ iθ 0 iθ np(e ) − e p (e ) + β̄ (n − m)e dθ kn s 1s Z 2π 0 m imθ p(eiθ ) + ≤ (n − m)Cs(k) β̄e dθ . kn 0 Now by Minkowski’s inequality, we have for s ≥ 1 and |β| < k n−m Z 2π n 0 s 1s 0 iθ p(e ) + m β̄eimθ dθ n k s 1s Z 2π 0 m imθ iθ 0 iθ iθ np(e ) + dθ ≤ β̄(n − m)e − e p (e ) kn 0 s 1s Z 2π 0 iθ 0 iθ mm imθ e p (e ) + + β̄e dθ , kn 0 which implies, by using inequality (3.1) Z n 0 2π s 1s 0 iθ m imθ p(e ) + dθ β̄e kn Z (k) ≤ (n − m)Cs s 1s 2π 0 p(eiθ ) + m β̄eimθ dθ n k 0 s 1s Z 2π 0 0 iθ m i(m−1)θ dθ , p (e ) + m β̄e + kn 0 and the Theorem 1.1 follows. Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page Contents JJ II J I Page 11 of 15 Go Back Full Screen Close Proof of Theorem 1.5. Since q(z) = z n p z̄1 so that p(z) = z n q have 1 1 0 n−1 n−2 0 (3.2) p (z) = nz q −z q , z̄ z̄ 1 z̄ , therefore, we which implies (3.3) |p0 (z)| = |nq(z) − zq 0 (z)| for |z| = 1 . Using (3.2) in (2.2), we get for 1 ≤ µ ≤ n |q 0 (z)| + vol. 10, iss. 1, art. 23, 2009 0 mn ≤ k µ |nq(z) − zq 0 (z)| for |z| = 1 . k n−µ Now, from the above inequality, for every complex β with |β| ≤ 1, we get, for |z| = 1 0 0 0 m n q (z) + β̄ ≤ |q 0 (z)| + m n k n−µ k n−µ (3.4) ≤ k µ |nq(z) − zq 0 (z)| . For every real or complex number α with |α| ≥ k µ , we have |Dα p(z)| = |np(z) + (α − z)p0 (z)| ≥ |α| |p0 (z)| − |np(z) − zp0 (z)|, which gives by interchanging the roles of p(z) and q(z) in (3.3) for |z| = 1 |Dα p(z)| ≥ |α||p0 (z)| − |q 0 (z)| (3.5) Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir ≥ |α||p0 (z)| − k µ |p0 (z)| + m0 n k n−µ (using (2.2)). Title Page Contents JJ II J I Page 12 of 15 Go Back Full Screen Close Since p(z) has all its zeros in |z| ≤ k ≤ 1, by the Gauss-Lucas theorem, all the zeros of p0 (z) also lie in |z| ≤ 1. This implies that the polynomial 1 n−1 0 z p = nq(z) − zq 0 (z) z̄ has all its zeros in |z| ≥ 1 k ≥ 1. Therefore, it follows from (3.4) that the function m0 n zq (z) + β̄ n−µ z k w(z) = µ k (nq(z) − zq 0 (z)) 0 (3.6) is analytic for |z| ≤ 1 and |w(z)| ≤ 1 for |z| ≤ 1. Furthermore w(0) = 0. Thus the function 1 + k µ w(z) is a subordinate to the function 1 + k µ z in |z| ≤ 1. Hence by a well-known property of subordination [4], we have for r > 0 and for 0 ≤ θ < 2π, Z 2π Z 2π µ iθ r (3.7) |1 + k w(e )| dθ ≤ |1 + k µ eiθ |r dθ . 0 0 Also from (3.6), we have m0 n nq(z) + β̄ n−µ z k 1 + k µ w(z) = , nq(z) − zq 0 (z) or 0 nq(z) + β̄ m n z = |1 + k µ w(z)||p0 (z)| for |z| = 1, n−µ k which implies 0 m (3.8) n p(z) + β n−µ z n−1 = |1 + k µ w(z)||p0 (z)| for |z| = 1. k Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page Contents JJ II J I Page 13 of 15 Go Back Full Screen Close Now combining (3.7) and (3.8), we get r Z 2π Z 2π 0 iθ m r i(n−1)θ n |1 + k µ eiθ |r |p0 (eiθ )|r dθ . p(e ) + β k n−µ e dθ ≤ 0 0 Using (3.5) in the above inequality, we obtain r Z 2π iθ m0 i(n−1)θ r µ r n (|α| − k ) dθ p(e ) + β k n−µ e 0 r Z 2π nm0 µ iθ r ≤ |1 + k e | dθ max |Dα p(z)| − n−µ , |z|=1 k 0 from which we obtain the required result. Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page Contents JJ II J I Page 14 of 15 Go Back Full Screen Close References [1] A. AZIZ, Integral mean estimate for polynomials with restricted zeros, J. Approx. Theory, 55 (1988), 232–239. [2] A. AZIZ AND W.M. SHAH, An integral mean estimate for polynomials, Indian J. Pure Appl. Math., 28(10) (1997), 1413–1419. [3] K.K. DEWAN, A. BHAT AND M.S. PUKHTA, Inequalities concerning the Lp norm of a polynomial, J. Math. Anal. Appl., 224 (1998), 14–21. [4] E. HILLE, Analytic Function Theory, Vol. II, Ginn and Company, New York, Toronto, 1962. [5] M.A. MALIK, On the derivative of a polynomial, J. London Math. Soc., 1 (1969), 57–60. [6] M.A. MALIK, An integral mean estimate for polynomials, Proc. Amer. Math. Soc., 91 (1984), 281–284. [7] N.A. RATHER, Extremal properties and location of the zeros of polynomials, Ph.D. Thesis submitted to the University of Kashmir, 1998. [8] W. RUDIN, Real and Complex Analysis, Tata McGraw-Hill Pub. Co., 1977. [9] A.E. TAYLOR, Introduction to Functional Analysis, John Wiley and Sons Inc., New York, 1958. [10] P. TURÁN, Über die Ableitung von Polynomen, Compositio Math., 7 (1939), 89–95. [11] A. ZYGMUND, A remark on conjugate series, Proc. London Math. Soc., 34(2) (1932), 392–400. Integral Mean Estimates K.K. Dewan, N. Singh, B. Chanam and A. Mir vol. 10, iss. 1, art. 23, 2009 Title Page Contents JJ II J I Page 15 of 15 Go Back Full Screen Close