Applied Mathematics E-Notes, 12(2012), 44-52 c Available free at mirror sites of http://www.math.nthu.edu.tw/ amen/ ISSN 1607-2510 A Multipoint Iterative Method For Semistable Solutions Steeve Burnet, Célia Jean-Alexis and Alain Pietrusy Received 28 June 2011 Abstract This paper deals with variational inclusions of the form : 0 2 '(z) + F (z) where ' is a single-valued function admitting a second order Fréchet derivative and F is a set-valued map from Rq to the closed subsets of Rq . In order to approximate a solution z of the previous inclusion, we use an iterative scheme based on a multipoint method. We obtain, thanks to some semistability properties of z, local superquadratic or cubic convergent sequences. 1 Introduction This paper is devoted to the study of a multipoint iterative method for approximating a solution of the variational inclusion 0 2 '(z) + F (z); (1) where ' is a single-valued function and F is a set-valued map. Variational inclusions are an abstract model of a wide variety of variational problems including linear and non-linear complementarity problems, systems of non-linear equations, variational inequalities. In the last decade, several iterative methods for solving the inclusion (1) have been introduced. These methods consist in generating an iterative sequence (zn ) obtained by subsequently solving implicit subproblems of the form 0 2 A(zn ; zn+1 ) + F (zn+1 ) where A denotes some approximation of the mapping '. Dontchev [7, 8] associates to (1) a Newton-type method based on a partial linearization. Inspired and motivated by his works, various authors proved the convergence of some methods based on di¤erent techniques such as one or second order Taylor’s expansion, interpolation formula and a multipoint formula given in [23]. For more details on these methods, the reader could refer to [6, 12, 13, 14, 15, 17, 20]. Let us point out that all these methods have been studied when a metric regularity property is satis…ed for the set-valued map (' + F ) 1 or one of its approximation. For more details on this property, the reader could refer to [1, 2, 9, 10, 11, 18, 19, 22]. Mathematics Subject Classi…cations: 49J53, 47H04, 65K10. LAMIA, EA4540, Université des Antilles et de la Guyane, Département de Mathématiques et Informatique, Campus de Fouillole, 97159 Pointe-à-Pitre, France y Laboratoire 44 Burnet et al. 45 In this paper, the function ' is de…ned from Rq to Rq and F is a set-valued map from R to the closed subsets of Rq : Our aim is to study inclusion (1) using an assumption which is directly connected to a solution : the semistability concept. This concept has been introduced by Bonnans [3] for variational inequalities. A solution z of a variational inclusion is said to be semistable if, given a small perturbation on the left-hand side, a solution z of the perturbed variational inclusion that is su¢ ciently close to z is such that the distance of z to z is of the order of the magnitude of the perturbation. Studies using such property has recently been made in [4, 5] for methods based on the second order Fréchet derivative. Following these works, we consider the relation q 0 2 '(zk ) + N X ai Mki (zk+1 zk ) + F (zk+1 ); (2) i=1 where Mki is a q q matrix satisfying some conditions and we prove the convergence of this procedure under the semistability property. We can observe that if Mki = '0 zk + i (zk+1 zk ) , we get the method proposed in [6] and if N = 2; a1 = a2 = 21 ; 1 = 0 and 2 = 1; we obtain the method introduced in [4]. The rest of the paper is organized as follows. In section 2, we collect a number of basic de…nitions regarding semistability of solutions and regularity for set-valued maps that we will need afterwards. Then, in section 3, we study the behaviour of the method (2) and we give a classical problem which could be treated with our method. In this paper, for simplicity reasons, all the norms are denoted by k:k. 2 Background Materials Here, we recall the concept of semistability introduced by Bonnans in [3]. DEFINITION 1. A solution z of (1) is said to be semistable if c1 > 0 and c2 > 0 exist such that, for all (z; ) 2 Rq Rq , solution of 2 '(z) + F (z); and kz zk c1 , then kz zk c2 k k. Note that a su¢ cient condition for semistability is the strong regularity of Robinson [21]. Recently, Izmailov and Solodov in [16] used this concept in order to study the convergence of Inexact Josephy-Newton method for solving generalized equations. We will also need the following Hölder-type property. DEFINITION 2. Let ' : Rq ! Rq be a function. One says that ' satis…es a Hölder-type condition on a neighborhood of z if 9K > 0; Note that when 3 2]0; 1]; k'(x) '(y)k K kx yk ; 8 x; y 2 : = 1, we have the Lipschitz condition for '. Convergence Analysis Our purpose in this section is to provide an iterative procedure for solving (1) and to show how the semistability property can be an e¢ cient tool to estimate the rate of convergence of the method (2). 46 A Multipoint Iterative Method for Semistable Solutions First of all, we consider the approximation (u; v) = '(u) + N X of ' de…ned by ai '0 u + i (v u) (v u) (3) i=1 and then we introduce the algorithm: given any starting point z0 in some neighborhood of z which is a solution of (1), for k = 0; 1; : : :, while zk does not satisfy (1), choose k (:) an approximation of PN (zk ; ) de…ned by k (z) = '(zk ) + i=1 ai Mki (z zk ); compute a solution zk+1 of 02 k (z) + F (z): (4) The main result of this study reads as follows. THEOREM 1. Let z be a semistable solution of (1) and let (zk ) be a sequence computed by (2) which converges towards z. We suppose that '00 is a locally Lipschitz function. Then : (i) if (zk ; zk+1 ) cally. (ii) if (zk ; zk+1 ) 2 then (zk ) converges superquadrati- 3 then (zk ) converges cubically. k (zk+1 ) = o kzk+1 zk k k (zk+1 ) = O kzk+1 zk k To prove Theorem 1, we will need the following lemma: LEMMA 1. Let ' : Rq ! Rq be a function admitting a second order Fréchet derivative which is L-Lipschitz on and let be de…ned by (3). One has the following inequality N L LX 3 + jai j 2i kv uk : (5) k'(v) (u; v)k 6 2 i=1 PROOF. We have k'(v) (u; v)k = '(v) '(u) N X ai '0 u + i (v u) (v u) i=1 = '(v) '(u) 1 + '00 (u)(v 2 '0 (u)(v 2 u) N X u) ai '0 u + '(u) i (v u)2 + '0 (u)(v u) (v i=1 Let A1 = '(v) 1 00 ' (u)(v 2 '0 (u)(v u) 1 00 ' (u)(v 2 u)2 u) : u) Burnet et al. 47 and 1 u) + '00 (u)(v 2 A2 = '0 (u)(v Since '00 is L-Lipschitz on A2 = = N X ai '0 (u) ai Z ai '0 u + L 6 N X u)2 = i = N X ai '0 u + i (v '00 u + i t(v u) i=1 1 u) (v 1 '00 u + jai j 2 i L kv i (v u) (v 1 u) + '00 (u)(v 2 (v i t(v u) (v 0 i=1 N X i Z uk : Moreover, 3 uk 1 L 2 tdt 0 N X i=1 u)2 1 u)dt + '00 (u)(v 2 Z 1 N X u)2 dt + ai i '00 (u)(v u)(v 2 i jai j kv u)2 u)2 dt 0 i=1 Z u) i=1 0 i=1 u) : u) (v 3 kv ai '0 u + i=1 N X i (v i=1 , we obtain A1 1 u) + '00 (u)(v 2 '0 (u)(v N X u)2 3 uk : And then N k'(v) L LX + jai j 6 2 i=1 (u; v)k 2 i kv 3 uk : PROOF of THEOREM 1. We write (4) as rk 2 '(zk+1 ) + F (zk+1 ); (6) with rk := k + (zk+1 ; zk ); where k = (zk ; zk+1 ) (zk+1 ; zk ) = '(zk+1 ) k (zk+1 ) and 2 (5), we get k (zk+1 ; zk )k = o(kzk+1 zk k ): Then krk k = o(kzk+1 Since z is semistable, we get kzk+1 zk = O(krk k): Then kzk+1 zk = o(kzk+1 2 zk + 2 kzk+1 zk kzk zk + kzk (zk ; zk+1 ): Using 2 zk k ): 2 zk ); i.e., 0 = = lim k!1 kzk+1 kzk+1 zk + 2 kzk+1 1 kzk+1 zk + 2 kzk lim k!1 2 zk zk kzk zk + zk + kzk kzk zk2 kzk+1 zk : 2 zk 48 A Multipoint Iterative Method for Semistable Solutions Since zk ! z; the latter relation implies that limk!1 kzk+1 kzk zk2 kzk+1 zk = +1; i.e., 2 zk = o(kzk zk ) which proves (i). Similarly for (ii), with (5), we get 3 krk k = O(kzk+1 zk k ): Thanks to the semistability of z, we obtain kzk+1 3 zk = O(kzk+1 kzk+1 zk k kzk zk Since (zk ) converges superquadratically then kzk+1 zk k ): zk = O(kzk ! 1, and then 3 zk ); which completes the proof. Let us extend this study to the case where the second order Fréchet derivative '00 of the function ' satis…es a Hölder-type condition. LEMMA 2. Let ' : Rq ! Rq be a function admitting a second order Fréchet derivative and let be de…ned by (3). If '00 satis…es a Hölder-type condition with constants and L on , one has, for all u; v 2 , the following inequality k'(v) L L + (1 + )(2 + ) 1 + (u; v)k N X i=1 jai j 1+ i kv uk 2+ : (7) PROOF. The proof is similar to the proof of Lemma 1. We write k'(v) (u; v)k '(u) '0 (u)(v A1 + A2 with A1 = '(v) 1 00 ' (u)(v 2 u) u)2 and A2 = '0 (u)(v 1 u) + '00 (u)(v 2 u)2 N X ai '0 u + i (v Since '00 satis…es a Hölder-type condition with constants A1 u) (v u) : i=1 L kv (1 + )(2 + ) 2+ uk and L on , we obtain : Moreover, A2 N X i=1 jai j 1+ i L kv 2+ uk Z 0 1 t dt L 1+ N X i=1 jai j 1+ i kv uk 2+ : Burnet et al. 49 Then k'(v) L L + (1 + )(2 + ) 1 + (u; v)k N X i=1 jai j 1+ i kv 2+ uk : THEOREM 2. Let z be a semistable solution of (1) and let (zk ) be a sequence computed by (2) which converges towards z. If '00 satis…es a Hölder-type condition with constants and L then : (i) if (zk ; zk+1 ) (ii) if (zk ; zk+1 ) ically. 1+ k (zk+1 ) = o kzk+1 zk k k (zk+1 ) = O kzk+1 zk k then (zk ) converges superlinearly; 2+ then (zk ) converges superquadrat- PROOF. The proof is similar to that of Theorem 1, but using Lemma 2 instead of Lemma 1. As an illustration of our results let us consider the standard following nonlinear programming problem : minimize f (x) (8) subject to gi (x) 0; gj (x) = 0; 8i 2 I 8i 2 J where I; J are a partition of f1; :::; pg; f : Rn ! R is twice continuously di¤erentiable on Rn while the functions gi : R ! R; i = 1; :::; p are di¤erentiable on Rn and are twice di¤erentiable in a neighborhood of a solution x of (8). To problem (8) is associated the …rst order optimality condition (in which 2 Rp ): rf (x) + rg(x) =0 gi (x) 0; 8i 2 I; gj (x) = 0; 8j 2 J; 0; I i gi (x) = 0; 8i 2 I: (9) As observed in [3], we may embed (9) into (2) in putting z = (x; ); '(x; ) = rf (x) + rg(x) g(x) and F (x; ) = N (x; ) = f0g N ( ) where = f 2 Rp ; N ( ) denotes the normal cone to at the point i.e. N ( )= ; if 2 = f 2 Rp ; J = 0; I 0; i = 0 if I i 0; 8i = 1; :::; pg and > 0; 8i 2 Ig : The corresponding variational inequality can be written in the following way: rf (x) + rg(x) g(x) 2 N ( ) =0 : (10) 50 A Multipoint Iterative Method for Semistable Solutions Thanks to a result given in Bonnans [3] and using a similar reasoning, we obtain that the semistability of (10) is equivalent to : 8 = 0; < (y; ) = 0 is the unique solution of H(x; )y + rg(x) y 2 C; I 0 0; = 0 if g (x) < 0; 8i 2 I; (11) i i : 0 rg (x)y = 0; 8i 2 I i i where H(x; ) = r2 f (x) + p X i=1 ir 2 gi (x); I = fi 2 I; gi (x) = 0g; I 0 = fi 2 I; I + = fi 2 I; i i = 0g; > 0g and C = fy 2 Rn ; rgI (x)y 0; rgJ (x)y = 0; rgI + (x)y = 0g: For more details, the reader can refer to [3]. Now, let us apply the method (2) presented in this paper to (10). The subproblem to be solved at the step k is : 8 > k+1 = 0 < rf (xk ) +pH(xk ; k )(xk+1 xk ) + rg(xk ) X k ai rg(xk + i (xk+1 xk ))(xk+1 xk ) 2 N ( k+1 ): > : g(x ) + i=1 As the evaluation of rg(xk ) is already necessary in order to evaluate '(xk ; k ); the only part of the Jacobian that perhaps needs to be approximated is H(xk ; k ): We then obtain the following algorithm: given any starting point (x0 ; if (xk ; (xk+1 ; k) 0) 2 Rn Rp is not solution of (10), choose Mk ; an n solution of n matrix, compute the k+1 ) 8 > k+1 = 0 < rf (xk ) +pMk (xk+1 xk ) + rg(xk ) X ai rg(xk + i (xk+1 xk ))(xk+1 xk ) 2 N ( > : g(xk ) + k+1 ): i=1 When Mk = H(xk ; k ); by applying Theorem 1 and the relation (11),we obtain the convergence of the sequence computed by (2) with Mki = rg(xk + i (xk+1 xk )). Acknowledgment. We would like to thank the referee for valuable suggestions that enabled us to improve the presentation of this paper. 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