c Applied Mathematics E-Notes, 10(2010), 210-234 Available free at mirror sites of http://www.math.nthu.edu.tw/∼amen/ ISSN 1607-2510 A Survey On D-Semiclassical Orthogonal Polynomials∗ Abdallah Ghressi†, Lotfi Khériji‡§ Received 17 June 2009 Abstract In this paper, a survey of the most basic results on characterizations, methods of classification and processes of construction of D-semiclassical orthogonal polynomials is presented. In particular, the standard perturbation, the symmetrization process are revisited and some examples are carefully analyzed. Symmetrization after perturbation is studied and some examples are given. 1 Introduction and Preliminaries By D-classical monic orthogonal polynomials sequences: (MOPS), we refer to Hermite, Laguerre, Bessel and Jacobi polynomials where D is the derivative operator. The orthogonality considered here is related to a form (regular linear form) [6,30] not only to an inner product. Since 1939, a natural generalization of the D-classical character is the D-semiclassical one introduced by J. A. Shohat in [41]. From 1985, this theory has been developed, from an algebraic aspect and a distributional one, by P. Maroni and extensively studied by P. Maroni and coworkers in the last decade [1,12,16,30,34,36]. A form u is called D-semiclassical when it is regular and satisfies the Pearson equation D(Φu) + Ψu = 0 (1) where (Φ, Ψ) are two polynomials , Φ monic with deg Φ ≥ 0 and deg Ψ ≥ 1. The corresponding (MOPS) {Bn }n≥0 is called D-semiclassical. Moreover, if u is D-semiclassical, the class of u, denoted s is defined by s := min max(deg Φ − 2, deg Ψ − 1) (2) where the minimum is taken over all pairs (Φ, Ψ) satisfying (1). In particular, the class s is greater to 0 and when s = 0 the D-classical case is recovered [34]. In 1985, M. Bachene [3, page 87] gave the system fulfilled by the coefficients of the threeterm recurrence relation of a D-semiclassical (MOPS) of class 1 using the structure ∗ Mathematics Subject Classifications: 42C05, 33C45. des Sciences de Gabès Route de Mednine 6029-Gabès, Tunisia. ‡ Institut Supérieur des Sciences Appliquées et de Technologie de Gabès Rue Omar Ibn El Khattab 6072-Gabès, Tunisia. § The second author is pleased to dedicate this work to Professor Pascal Maroni founder of the research group in orthogonal polynomials at Gabès, Tunisia. † Faculté 210 A. Ghressi and L. Khériji 211 relation (see (26) below). In 1992, S. Belmehdi [4,page 272] gave the same system (in a more simple way) using the Pearson equation (1). This system is not linear and it is very difficult to solve. As a consequence, D-semiclassical forms of class 1 are classified by S. Belmehdi in [4] through a distributional study by taking into account (1) and by giving an integral representation for any canonical case except the case of Bessel kind. In 1996, J. Alaya and P. Maroni have established the linear system fulfilled by the coefficients of the three-term recurrence relation of a symmetric D-Laguerre-Hahn (MOPS) of class 1 [1] that is to say the (MOPS) associated with a regular form u satisfying the functional equation D(Φu) + Ψu + B x−1 u2 = 0 where Φ, Ψ, B are three polynomials with Φ monic and max deg Ψ − 1, max(deg Φ, deg B) − 2 = 1. Consequently, the authors give the classification of symmetric D-semiclassical forms of class 1 as a particular case (B ≡ 0). There are three canonical situations: • The generalized Hermite form H(µ) (µ 6= 0 , µ 6= −n− 12 , n ≥ 0) and its (MOPS) satisfying ( βn = 0 , γn+1 = 12 (n + 1 + µ(1 + (−1)n )) , n ≥ 0, (3) D(xH(µ)) + {2x2 − (2µ + 1)}H(µ) = 0. • The generalized Gegenbauer G(α, β) (α 6= −n−1 , β 6= −n−1 , β 6= − 12 , α+β 6= −n − 1 , n ≥ 0) and its (MOPS) satisfying βn = 0 , n ≥ 0, (n+β+1)(n+α+β+1) γ2n+1 = (2n+α+β+1)(2n+α+β+2) , n ≥ 0, (n+1)(n+α+1) γ2n+2 = (2n+α+β+2)(2n+α+β+3) , n ≥ 0, n o D x(x2 − 1)G(α, β) + − 2(α + β + 2)x2 + 2(β + 1) G(α, β) = 0. (4) For further properties of the generalized Hermite polynomials, the generalized Gegenbauer polynomials and their orthogonality relations see [1,4,6,14,40]. • The form B[ν] of Bessel kind (ν 6= −n − 1 , n ≥ 0) and its (MOPS) satisfying 1 βn = 0 , γ1 = − 4(ν+1) , n+1 γ2n+2 = 41 (2n+ν+1)(2n+ν+2) , n ≥ 0, (5) 1 n+1+ν γ2n+3 = − 4 (2n+ν+2)(2n+ν+3) , n ≥ 0, n o D x3 B[ν] − 2(ν + 1)x2 + 1 B[ν] = 0. 2 212 D-Semiclassical Orthogonal Polynomials For an integral representation of B[ν] and some additional features of the associated (MOPS) see [13,39]. Other families of D-semiclassical orthogonal polynomials of class greater to 1 were revealed by solving functional equations of the type P (x)e u = Q(x)u (6) where P, Q are two polynomials cunningly chosen and u, e u two forms. In fact, the product of a form by a polynomial is one of the old construction process of forms; in 1858, Christoffel proved that the product of a positive definite form by a positive polynomial is still a positive definite form [7]. This result has been generalized by J. Dini and P. Maroni in [9] since 1989 where it was proved that, under certain regularity conditions, the product of a regular form u e by a polynomial P is a regular form. In that work, the D-semiclassical character is studied. It is also interesting to consider the inverse problem, which consists of the determination of all regular form u e satisfying (6) where Q(x) = −λ ∈ C − {0} and u is a given regular form. P. Maroni has considered the case P (x) = x − τ , τ ∈ C in 1990 [31], the case P (x) = x2 in 1996 [35] and the case P (x) = x3 in 2003 [36]. In 1992, F. Marcellan and P. Maroni have considered the case P (x) = Q(x) = x − τ , where u is a given regular D-semiclassical form [23]. For other published papers concerning the problem (6) see [12,15,17,21,22,43]. Symmetric D-semiclassical forms of class 2 satisfying (1) with Φ(0) = 0 are well described in [39] by M. Sghaier and J. Alaya (in 2006) through there an original characterization by taking into account (6). In 2007, symmetric D-semiclassical forms of class 2 are also classified by a distributional study likewise in [4], by A. M. Delgado and F. Marcellan [8] but it seems that integral representations are given only in the positive definite cases (see Remark 4.2. below). For other relevant research work on the subject from other points of view and with perhaps other operators see [2,5,20,38]. The aim of this survey is threefold. First, to present an overview about the characterizations and processes of construction of D-semiclassical orthogonal polynomials ( see section 1 and section 2). Then, to revise the standard perturbation (see (6) for deg P = 1 and deg Q = 0) by taking into account the framework [31] and the limiting case (q → 1) in [12] and to analyze the symmetrization process according to [2,33] by adding some complementary results (see section 3 and section 4). Finally, to highlight some examples of D-semiclassical orthogonal polynomials of class greater to 1 by using [37] ( see section 2), by applying the standard perturbation ( see section 3) and by combining the processes of symmetrization and perturbation (see section 4). Now, we are going to introduce the material concerning orthogonal polynomials and regular forms that find their origin in the book of T. S. Chihara (1978) [6] and developed by P. Maroni since 1981 [24,25,29,30]. Let P be the vector space of polynomials with coefficients in C and let P 0 be its topological dual. We denote by hu, fi the effect of u ∈ P 0 on f ∈ P. In particular, we denote by (u)n := hu, xn i , n ≥ 0 the moments of u. Moreover, a form u is called symmetric if (u)2n+1 = 0, n ≥ 0. For any form u, any polynomial g , let gu , be the form defined by duality hgu, fi := hu, gfi , f ∈ P. (7) 213 A. Ghressi and L. Khériji For f ∈ P and u ∈ P 0 , the product uf is the polynomial xf (x) − ζf (ζ) (uf) (x) := u, . x−ζ (8) The derivative u0 = Du of the form u is defined by hu0 , fi := − hu, f 0 i , f ∈ P. (9) (fu)0 = f 0 u + fu0 , u ∈ P 0 , f ∈ P . (10) We have [30] 0 The formal Stieltjes function of u ∈ P is defined by S (u) (z) := − X (u) n . z n+1 (11) n≥0 Similarly, with the definitions hha u, fi := hu, hafi = hu, f (ax)i , u ∈ P 0 , f ∈ P , a ∈ C − {0} , (12) hτb u, fi := hu, τ−b fi = hu, f (x + b)i , u ∈ P 0 , f ∈ P , b ∈ C (13) hδc , fi := f(c) , f ∈ P , c ∈ C. (14) hu, PmPn i = rn δn,m , n, m ≥ 0 ; rn 6= 0 , n ≥ 0. (15) and The form u is called regular if we can associate with it a polynomial sequence {Pn }n≥0 , deg Pn = n, such that The polynomial sequence {Pn }n≥0 is then said orthogonal with respect to u. Necessarily, {Pn }n≥0 is an (OPS) where every polynomial can be supposed monic and it fulfils the three-term recurrence relation P0 (x) = 1 , P1 (x) = x − β0 , (16) Pn+2 (x) = (x − βn+1 ) Pn+1 (x) − γn+1 Pn (x) , n ≥ 0 hu,xP 2 i hu,P 2 i 6= 0, n ≥ 0. Moreover, the regular form u, with βn = hu,P 2ni and γn+1 = hu,Pn+1 2 n ni associated to the (MOPS) {Pn }n≥0 satisfying (16), is said to be positive definite if and only if βn ∈ R and γn+1 > 0 for all n ≥ 0. The form u is said to be normalized if (u)0 = 1. In this paper, we suppose that any form will be normalized. p(x)−p(c) From the linear application p 7→ (θc p) (x) = , p ∈ P , c ∈ C , we define x−c −1 (x − c) u by D E (x − c)−1 u, p := hu, θcpi (17) and we have [30,33] (x − c) (x − c)−1 u = u ; (x − c)−1 (x − c)u = u − (u)0 δc , u ∈ P 0 , c ∈ C. (18) 214 D-Semiclassical Orthogonal Polynomials Finally, we introduce the operator σ : P −→ P defined by (σf)(x) := f(x2 ) for all f ∈ P. Consequently, we define σu by duality hσu, fi := hu, σfi , f ∈ P , u ∈ P 0 (19) and we have for f ∈ P , u ∈ P 0 [33] f(x)σu = σ(f(x2 )u) ; 2 σu0 = 2(σ(xu))0 . (20) Overview about D-Semiclassical Forms Now, we will expose the D-semiclassical character according to P. Maroni [26,27,28,30]. Let Φ monic and Ψ be two polynomials , deg Φ = t , deg Ψ = p ≥ 1. We suppose that the pair (Φ, Ψ) is admissible , i.e. when p = t − 1 , writing Ψ (x) = ap xp + ..., then ap 6= n + 1 , n ∈ N. DEFINITION 2.1. A form u is called D-semiclassical when it is regular and satisfies the functional equation (Φu)0 + Ψu = 0 (21) where the pair (Φ, Ψ) is admissible. The corresponding orthogonal sequence {Pn }n≥0 is called D-semiclassical. REMARKS 2.1. 1. The D-semiclassical character is kept by shifting( see [30]). In fact, let −n a (ha ◦ τ−b Pn ) n≥0 , a 6= 0 , b ∈ C; when u satisfies (21), then ha−1 ◦ τ−b u fulfils the equation a−t Φ (ax + b) ha−1 ◦ τ−b u 01−t Ψ (ax + b) ha−1 ◦ τ−b u = 0. (22) 2. The D-semiclassical form u is said to be of class s = max(p − 1, t − 2) ≥ 0 if and only if Y n o (23) Ψ(c) + Φ0 (c) + u, θcΨ + θc2 Φ > 0, c∈ZΦ where ZΦ is the set of zeros of Φ. The corresponding orthogonal sequence {Pn }n≥0 will be known as of class s [30]. 3. When s = 0, the form u is usually called D-classical Hermite, Laguerre, Bessel, and Jacobi [34]. We can state characterizations of D-semiclassical orthogonal sequences. {Pn }n≥0 is D-semiclassical of class s, if and only if one of the following statements holds (see [31] and q = 1 in section 2. of [12]) (1). The formal Stieltjes function of u satisfies a non homogeneous first order linear differential equation Φ(z)S 0 (u) (z) = C0 (z) S (u) (z) + D0 (z) , (24) 215 A. Ghressi and L. Khériji where C0 (z) = −Ψ(z) − Φ0 (z), D0 (z) = −(uθ0 Φ)0 (z) − (uθ0 Ψ)(z). (25) Φ and Ψ are the same polynomials as in (21). (2). {Pn }n≥0 satisfies the following structure relation 0 Φ (x) Pn+1 (x) = 1 (Cn+1 (x) − C0 (x)) Pn+1 (x) − γn+1 Dn+1 (x) Pn (x) , n ≥ 0, (26) 2 where Cn+1 (x) = −Cn (x) + 2 (x − βn ) Dn (x) , n ≥ 0 (27) γn+1 Dn+1 (x) = −Φ (x) + γn Dn−1 (x) 2 + (x − βn ) Dn (x) − (x − βn ) Cn (x) , n ≥ 0, (28) Φ, Ψ, C0, D0 are the same parameters introduced in (1); βn , γn are the coefficients of the three term recurrence relation (16). Notice that D−1 (x) := 0, deg Cn ≤ s + 1 and deg Dn ≤ s, n ≥ 0. (3). Each polynomial Pn+1 , n ≥ 0 satisfies a second order linear differential equation 0 00 (x) + K (x, n) Pn+1 (x) + L (x, n) Pn+1 (x) = 0 , n ≥ 0, (29) J (x, n) Pn+1 with and J (x, n) = Φ (x) Dn+1(x) , 0 (x) Φ (x) , K (x, n) = Dn+1 (x) Φ0 (x) + C0 (x) − Dn+1 0 (x) − n) = 12 Cn+1 (x) − C0 (x) Dn+1 L (x, 1 0 0 − Cn+1 − C0 (x) Dn+1 (x) − Dn+1 (x) Σn (x) , n ≥ 0. 2 Σn (x) := n X k=0 Dk (x) , n ≥ 0. (30) (31) Φ, Cn , Dn are the same in the previous characterization. Notice that deg J(., n) ≤ 2s + 2 , deg K(., n) ≤ 2s + 1 and deg L(., n) ≤ 2s. In particular, when s = 0 that is to say the D-classical case, the coefficients of the structure relation (26) become C (x)−C (x) n+1 0 = 12 Φ00 (0)((n + 1)x − Sn )+ 2 (32) +(Ψ0 (0) − Φ00 (0)(n + 1))βn+1 + (Ψ(0) − Φ0 (0)(n + 1)), Dn+1 (x) = 12 Φ00 (0)(2n + 1) − Ψ0 (0), n ≥ 0, with Sn = Pn k=0 βk , n ≥ 0. Also we get for (30) J(x, n) = Φ(x) , K(x, n) = −Ψ(x) , L(x, n) = (n + 1)(Ψ0 (0) − 12 Φ00 (0)n) , n ≥ 0. (33) 216 D-Semiclassical Orthogonal Polynomials In 1990, P. Maroni gives the following result about order of zero of a D-semiclassical polynomial Pn+1 of class s [31]. REMARK 2.2. Taking into account the structure relation (26), the polynomial sequence {Dn+1 }n≥0 gives us some information about zeros of the polynomial Pn+1 . In fact, if c is a zero of order η of Pn+1 , n ≥ 1 with η ≥ 2, then η ≤ s + 1 and c is a zero of order η − 1 of Dn+1 . In 1996, J. Alaya and P. Maroni give the following result to a symmetric D-LaguerreHahn form [1] which remains valid in the symmetric D-semiclassical case PROPOSITION 2.1. Let u be a symmetric D-semiclassical form of class s satisfying (21). The following statements hold i) When s is odd then the polynomial Φ is odd and Ψ is even. ii) When s is even then the polynomial Φ is even and Ψ is odd. Finally, about integral representation (P. Maroni [32] in 1995), let u be a Dsemiclassical form satisfying (21). We are looking for an integral representation of u and consider Z +∞ hu, fi = −∞ U (x)f(x)dx , f ∈ P, (34) where we suppose the function U to be absolutely continuous on R, and is decaying as fast as its derivative U 0 . From (21) we get Z +∞ −∞ +∞ (ΦU )0 + ΨU f(x)dx − Φ(x)U (x)f(x) −∞ = 0 , f ∈ P. Hence, from the assumptions on U , the following conditions hold Z +∞ Φ(x)U (x)f(x) −∞ = 0 , f ∈ P, +∞ −∞ Condition (36) implies (ΦU )0 + ΨU f(x)dx = 0 , f ∈ P. (ΦU )0 + ΨU = ωg, (35) (36) (37) where ω 6= 0 arbitrary and g is a locally integrable function with rapid decay representing the null-form Z +∞ xn g(x)dx = 0 , n ≥ 0. (38) −∞ Conversely, if U is a solution of (37) verifying the hypothesis above and the condition Z +∞ −∞ U (x)dx 6= 0, then (35)-(36) are fulfilled and (34) defines a form u which is a solution of (21). (39) 217 A. Ghressi and L. Khériji In particular, from (Φu)0 + Ψu Φ(x) = t X n = 0, n ≥ 0, writing ck x k ; Ψ(x) = k=0 p X ak x k k=0 and by taking into account (9), we have for the moments of u (u)0 = 1 ; p X k=0 ak (u)k = 0; p+1 X k=1 ak−1 (u)n+k − (n + 1) t X k=0 ck (u)n+k = 0, n ≥ 0. (40) In [37], P. Maroni and M. Ihsen Tounsi (2004) have described all (MOPS) which are identical to their second associated sequence that is to say those satisfying (16) with βn+2 = βn ; γn+3 = γn+1 , n ≥ 0. The resulting polynomials are D-semiclassical of class s ≤ 3. In fact there are five canonical situations itemized (a)-...-(e) (see Proposition 3.5 in [37]). The characteristic elements of the structure relation (26) and the second-order differential equation (29) are given explicitly by using the quadratic decomposition [33]. Integral representations of the corresponding forms are also given by an other process which consists of representing the corresponding Stieljes function (11). So, our interest in the following example is to describe the canonical situation (d) in that work but with processes exposed in this section. EXAMPLE 2.1. Let’s consider the D-semiclassical form u of class 1 and its (MOPS) {Pn }n≥0 . We have [37] 1 n βn = (−1) , γn+1 = − 4 , n ≥ 0 , 02 (41) + x + 2)u = 0. x(x2 − 1))u For the moments of u, from (40)-(41) we get ( (u)0 = 1, (u)1 = 1 , −(n + 4)(u)n+2 + (u)n+1 + (n + 2)(u)n = 0 , n ≥ 0. (42) Consequently, it is easy to prove by induction that (u)2n+1 = (u)2n , n ≥ 0. (43) Now, taking n ← 2n in the second equality in (42) and by virtue of (43) we get (u)2n+2 = 2n + 3 (u)2n , n ≥ 0 2n + 4 from which we derive the following (u)2n+1 = (u)2n = 1 (2n + 1)! , n ≥ 0. n + 1 22n (n!)2 (44) 218 D-Semiclassical Orthogonal Polynomials For an integral representation of u of type (34), equation (37) with ω = 0 and hypothesis becomes 1 1 1 0 2 2 U (x) + − + − U (x) = 0. (45) x x−1 x+1 A possible solution of (45) is the function 0 , x ≤ −1, q 1+x U (x) = ρ x 1−x , −1 < x < 1, 0 , x ≥ 1. (46) First, condition (35) is fulfilled because 2 r n x(x − 1)x ρ x Second, with the change of variable t = −1 ρ = Z 1 −1 x r Z 1+x dx = 1−x where Jk = Z 1+x 1−x q +∞ 0 +∞ 0 1+x 1−x +1 −1 = 0 , n ≥ 0. the normalization constant ρ satisfies 4t2 (t2 − 1) dt = 4J1 − 12J2 + 8J3 (t2 + 1)3 dt , k ≥ 1. (t2 + 1)k But, upon integration by parts we get Jk+1 = In particular, J1 = π2 , J2 = integral representation π 4 2 hu, fi = π 2k − 1 Jk , k ≥ 1. 2k and J3 = Z 1 −1 x r 3π 16 . Thus, ρ−1 = π 2 and u has the following 1+x f(x) dx , f ∈ P. 1−x (47) For the structure relation (26), we may write it as follows 1 0 x(x2 − 1)Pn+1 (x) = (n + 1)x2 + bn x + cn Pn+1 (x) + dn x + en Pn (x) , n ≥ 0. (48) 4 The problem is then to determine the coefficients bn , cn , dn , en , n ≥ 0. Taking x = 0, x = 1, x = −1 respectively in (48) we get 1 cn Pn+1 (0) + 4 en Pn (0) = 0 (n + 1) + bn + cn Pn+1 (1) + 41 (dn + en )Pn (1) = 0 , n ≥ 0. (49) (n + 1) − bn + cn Pn+1 (−1) + 14 (−dn + en )Pn (−1) = 0 219 A. Ghressi and L. Khériji Moreover, from (41) and (48), the formulas in (25)-(26) become ( Cn (x) = (2n + 1)x2 + (2bn−1 − 1)x + 2cn−1 − 1 Dn (x) = dn−1x + en−1 ,n ≥ 0 (50) where b−1 := 0, c−1 := 0, d−1 := 2, e−1 := 2. Consequently, replacing in (27)-(28) we get after identification dn = 2(n + 2) n 2b n + 2bn−1 − 2en−1 = 2 1 − 2(−1) (n + 1) 2c + 2c n n n−1 + 2(−1) en−1 = 2 , n ≥ 0. (51) 2bn−1 + en−1 = 1 + (−1)n (−2n + 1) −2(−1)n bn−1 + 2cn−1 − 2(−1)n en−1 = 2n + 12 − (−1)n −2(−1)n cn−1 + 41 en + 34 en−1 + = (−1)n+1 On the other hand, regarding (49) we are going to compute Pn (0), Pn (1), Pn (−1) for any n ≥ 0. For Pn (0), taking x = 0 in (16) and on account of (41) we obtain 1 Pn+2 (0) = −(−1)n+1 Pn+1 (0) + Pn (0), n ≥ 0 ; P0 (0) = 1 ; P1 (0) = −1. 4 Thus, Pn+2 (0) + (−1)n+1 Pn+1 (0) 2 = (−1)n 2 Pn+1 (0) + (−1)n Pn (0) 2 P1 (0) + 12 P0 (0) = − 12 . , n ≥ 0, Therefore, (n−1)n (−1)n (−1) 2 Pn+1 (0) = − Pn (0) − 2 2n+1 from which we deduce that Pn (0) = , n≥0 n(n+1) n+1 (−1) 2 , n ≥ 0. 2n (52) For Pn (1), taking x = 1 in (16) and on account of (41) we obtain 1 Pn+2 (1) = (1 − (−1)n+1 )Pn+1 (1) + Pn (1), n ≥ 0 ; P0 (1) = 1 ; P1 (1) = 0. 4 (53) With n ← 2n and n ← 2n − 1 successively in (53) we deduce ( P2n+2 (1) = 2P2n+1(1) + 14 P2n (1), n ≥ 0 P2n+1 (1) = 14 P2n−1 (1), n ≥ 1 which gives P2n+1 (1) = 0, n ≥ 0 ; P2n (1) = 1 , n ≥ 0. 22n (54) 220 D-Semiclassical Orthogonal Polynomials For Pn (−1), taking x = −1 in (16) and on account of (41) we obtain ( Pn+2 (−1) = −(1 + (−1)n+1 )Pn+1 (−1) + 41 Pn (−1) , n ≥ 0, P0 (−1) = 1 ; P1 (−1) = −2. (55) With n ← 2n and n ← 2n − 1 successively in (55) we deduce ( P2n+2 (−1) = 14 P2n (−1), n ≥ 0 P2n+1 (−1) = 14 P2n−1(−1) − 1 22n−1 , n≥1 which gives P2n(−1) = 1 , n≥0 ; 22n P2n+1 (−1) = − n+1 n ≥ 0. 22n−1 (56) Now, replacing the numbers in (52), (54), (56) in the system (49) and by taking into account the second system (51) we obtain b2n = 1 ; b2n+1 = 0 c2n = −(2n + 1) ; c2n+1 = −2(n + 1) , n ≥ 0. (57) dn = 2(n + 2) e = −4(n + 1) ; e 2n 2n+1 = 2(2n + 3) So, it is quite straightforward to get the expressions in (26) and (30) for the structure relation and the second order linear differential equation. 3 3.1 The Standard Perturbation Revisited On the standard perturbation Let u be a regular form. Denoting by {Pn }n≥0 its (MOPS) satisfying (16). Let u e ∈ P0 satisfying (x − τ )e u = λu , τ ∈ C, λ ∈ C − {0}. (58) According to (18) relation (58) is equivalent to u e = δτ + λ(x − τ )−1 u with constraints (e u)0 = 1, (u)0 = 1 and λ + τ = (e u)1 . e Suppose u e regular and let {Pn }n≥0 be its (MOPS) Pe0 (x) = 1 , Pe1 (x) = x − βe0 , e Pn+2 (x) = (x − βen+1 )Pen+1 (x) − e γn+1 Pen (x) , n ≥ 0. The connection between Pen and Pn is (see [31]) Pe0 (x) = 1 , Pen+1 (x) = Pn+1 (x) + an Pn (x) , n ≥ 0, (59) (60) (61) 221 A. Ghressi and L. Khériji with (1) an = − where Pn(1)(x) := Pn+1 (τ ) + λPn (τ ) (1) Pn (τ ) + λPn−1 (τ ) 6= 0 , n ≥ 0, Pn+1 (x) − Pn+1 (ξ) u, x−ξ (62) , n ≥ −1. We have [30] (1) Pn+1 (x)Pn+1 (x) − Pn+2 (x)Pn(1)(x) = n Y k=0 γk+1 , n ≥ 0. (63) Denoting λn = − Pn (τ ) (1) Pn−1 (τ ) , n ≥ 1 , λ0 = 0. (64) Let us recall the fundamental result owing to P. Maroni (1990) [31] PROPOSITION 3.1. Let u be a regular form. The following statements are equivalent i) The form u e = δτ + λ(x − τ )−1 u is regular. ii) λ 6= λn , n ≥ 0. We may write γn+1 + an+1 − βn+1 = −τ , n ≥ 0, an (65) βe0 = β0 −a0 = τ +λ , βen+1 = βn+1 +an −an+1 , γen+1 = −an (an −βn +τ ) , n ≥ 0, (66) (x − τ )Pn (x) = Pen+1 (x) + (βn − an − τ )Pen (x) , n ≥ 0 , (67) (x − τ )Pn+1 (x) = (x − an − τ )Pen+1 (x) + an (an − βn + τ )Pen (x) , n ≥ 0. In particular, if the regular form u is symmetric then the form u e = δ0 +λx−1 u is regular for any λ 6= 0 and we have (γ0 := 1 ; γ−1 := 1) ** n Q γ2k a2n = −λ γ2k−1 , n ≥ 0, k=0 (68) n Q γ 2k+1 1 a2n+1 = λ γ2k , n ≥ 0. k=0 3.2 The D-semiclassical case Suppose u be a D-semiclassical form of class s satisfying (21). Multiplying (21) by λ and on account of (58) we get 0 e u + Ψe e u = 0, Φe (69) 222 D-Semiclassical Orthogonal Polynomials with e (x) = (x − τ )Φ (x) , Ψ e (x) = (x − τ )Ψ (x) . Φ (70) Φ(τ ) 6= 0 , λ 6= λn , n ≥ 0 or Φ(τ ) = 0 , λ 6= λn , n ≥ −1, (71) Now, taking q = 1 in section 3.1 of [12], we recover the following result concerning the class of u e [31] THEOREM 3.1. If the D-semiclassical form u is of class s then the form u e is D-semiclassical of class se = s + 1 for where λ−1 = − Ψ(τ ) + Φ0 (τ ) . hu, θτ Ψ + θτ2 Φi (72) REMARK 3.1. Also, taking q = 1 in section 3.2 n ofo [12], we recover again the results in [31] concerning the structure relation of Pen and the second order n≥0 linear differential equation satisfied by Pen+1 , n ≥ 0. Finally, if we suppose that the form u has the following integral representation: Z +∞ Z +∞ hu, fi = U (x) f (x) dx , f ∈ P ; U (x) dx = 1 −∞ −∞ where U is a locally integrable function with rapid decay and continuous at the point x = τ then in view of (59) we may write Z +∞ Z +∞ U (x) U (x) he u, fi = 1 − λP dx f (0) + λP f (x) dx , f ∈ P , (73) −∞ x − τ −∞ x − τ where P Z +∞ −∞ U (x) dx := lim x−τ ε 0+ Z τ−ε −∞ U (x) dx + x−τ Z +∞ τ+ε U (x) dx . x−τ (74) In particular, taking q = 1 in (5) of the document [12], the moments of u e are given by (e u)0 = 1 ; (e u)n = τ n + λ n X k=1 τ n−k (u)k−1 , n ≥ 1. (75) EXAMPLE 3.1. Let us consider u the D-semiclassical form of class 1 studied in Example 2.1. and u e = δ−1 + λ(x + 1)−1 u be its standard perturbed (τ = −1). Taking x = −1 in (63), by virtue of (41) and the fact that Pn (−1) 6= 0, n ≥ 0 ( see (56)) we get Pn+2 (−1) (1) (−1)n+1 (1) Pn+1 (−1) = Pn (−1) + 2n+2 , n≥0 Pn+1 (−1) 2 Pn+1 (−1) which gives (1) Pn+1 (−1) = n n k Y X Y Pk+2 (−1) (−1)k+1 Pl+1 (−1) 1+ , n ≥ 0. Pk+1 (−1) 22k+2 Pk+1 (−1) Pl+2 (−1) k=0 k=0 l=0 223 A. Ghressi and L. Khériji Consequently, in accordance with (56) it follows (1) P2n+1 (−1) = 0 1 , n ≥ 0. 22n (76) 1 , n≥0 4(2n + 2 − λ) (77) (1) ; P2n (−1) = Thus, (62) and (64) can be written as a2n = 2n + 2 − λ ; a2n+1 = λ2n+1 = 2(n + 1) , n ≥ 0. (78) −1 By virtue of Proposition 3.1., The form u e = δ−1 + λ(x + 1) u is regular if and only if λ 6= 2(n + 1), n ≥ −1. In particular, from (41) and (77), the relations in (66) become βe0 = λ − 1 1 βe2n+1 = 2n + 1 − λ − 4(2n+2−λ) , n ≥ 0. (79) 1 − 2n − 3 + λ βe2n+2 = 4(2n+2−λ) γe 1 = −(2n + 2 − λ)(2n − λ) ; e γ =− 2n+1 2n+2 16(2n+2−λ)2 In accordance with Theorem 3.1. u e is D-semiclassical of class 2 for any λ 6= 2(n + 1), n ≥ −1 satisfying the functional equation 02 2 x(x − 1)(x + 1) )e u + x + 2)e u = 0. (80) For the moments of u e, with (44) and (75) we get (e u)2n = 1 ; (e u)2n+1 = λ − 1 , n ≥ 0. (81) For an integral representation of u e, in view of (47) and (73) and by the fact that R1 √ x dx = 0 we may write −1 1−x2 he u, fi = f(−1) + λ 3.3 Z 1 −1 √ x f(x) dx , f ∈ P. 1 − x2 (82) The study of δ0 + λx−1 B(α) Consider u = B(α), α 6= − n2 , n ≥ 0 the D-classical Bessel form. we have [32] 1−α , n ≥ 0, β0 = − α1 , βn+1 = (n+α)(n+α+1) (n+1)(n+2α−1) γn+1 = − (2n+2α−1)(n+α)2(2n+2α+1) , n ≥ 0, 0 x2 B(α) − 2(αx + 1)B(α) = 0, and for α ≥ 6 2 4 ,f π ∈P hB(α), fi = Tα−1 Z 0 +∞ 1 x2 Z x +∞ x 2α t 2 2 exp − s(t)dtf(x)dx, t x (83) (84) 224 D-Semiclassical Orthogonal Polynomials with Z +∞ 2α 1 x 2 2 Tα = exp − s(t)dtdx, x2 x t t x 0 x ≤ 0, 0, s(x) = 1 1 exp(−x 4 ) sin x 4 , x > 0. Z +∞ (85) (86) where s represents the null-form and given in 1895 by T. J. Stieljes [42]. The integral representation (84) of the D-classical Bessel form is given by P. Maroni (1995) in [32]. In fact, the history of the Bessel form is more tortured than that other D-classical forms and the reason is certainly that the Bessel form is not positive definite for any value of the parameter α. For others representations through a function, a distribution or through an ultra-distribution see A. J. Duran (1993) [10], A. M. Krall (1981)[19] and W. D. Evans et al. (1992)[11], S. S. Kim et al. (1991) [18] respectively. Taking into account the functional equation in (83), it is easy to see that the moments of B(α) are (B(α))n = (−1)n 2n Γ(2α) , n ≥ 0, Γ(n + 2α) (87) where Γ is the Gamma function. Putting x = 0 in (26) and by virtue of (83) and (32) we get Pn (0) = 2n Γ(n + 2α − 1) , n ≥ 0. Γ(2n + 2α − 1) (88) Also, taking x = 0 in (63) and in accordance with(88) and (83) we obtain the recurrence relation (1) Pn+1 (0) = n + 2α Γ(2α) P (1)(0) + (−1)n+1 2n+1 , n ≥ 0. (2n + 2α + 1)(n + α + 1) n Γ(2n + 2α + 2) Therefore, an easy computation yields the equality n Pn(1)(0) = 2n+1 Γ(2α)Γ(n + 2α) X (−1)k k!(k + α) , n ≥ 0. Γ(2n + 2α + 1) Γ(k + 2α) k=0 By induction, we can easily prove that n X (−1)k k!(k + α) k=0 Γ(k + 2α) = 1 2α − 1 1 (n + 1)! + (−1)n , n ≥ 0, 2 Γ(2α) 2 Γ(n + 2α) which gives (compare with [31]) Pn(1)(0) = 2n (2α − 1)Γ(n + 2α) + (−1)n (n + 1)!Γ(2α) , n ≥ 0. Γ(2n + 2α + 1) Thus, for (62) and (64) we get for n ≥ 0 an = −2 Γ(2n + 2α − 1) Γ(2n + 2α + 1) (89) 225 A. Ghressi and L. Khériji 2Γ(n + 2α) + λ (2α − 1)Γ(n + 2α) + (−1)n (n + 1)!Γ(2α) , × 2Γ(n + 2α − 1) + λ (2α − 1)Γ(n + 2α − 1) + (−1)n−1 n!Γ(2α) and λn = −2 Γ(n + 2α − 1) , n ≥ 1. (2α − 1)Γ(n + 2α − 1) + (−1)n−1 n!Γ(2α) (90) (91) Consequently, in accordance with theorem 3.1. and (69)-(72) the form u e = δ0 + 2 λx−1 B(α) is D-semiclassical of class e s = 1 for any λ 6= λn , n ≥ −1 with λ−1 = 1−2α and fulfils the functional equation (69) with e Φ(x) = x3 , e Ψ(x) = −2x(αx + 1). (92) Also, the recurrence coefficients of {Pen }n≥0 are given by (66) with the above results (88) and (83). From (75) and (87), the moments of u e are (e u)n = λ(−1)n−1 2n−1 Γ(2α) , n ≥ 1 , (e u)0 = 1. Γ(n + 2α − 1) (93) When α ≥ 6( π2 )4 and on account of (73)-(74), (84)-(86) let us consider the function 1 e U(x) = 3 x Z +∞ x 2α ξ x We have for n ≥ 0, n x U e (x) ≤ ≤ = exp 2 2 s(ξ)dξ , x > 0. x 2 x Z +∞ ξ −2α exp ne x U (x) = Θn (x) + O x n+2α−3 2 exp − x Z 1 2 2 Θn (x) = xn+2α−3 exp − ξ −2α exp s(ξ)dξ. x ξ x Hence, Z 0 (94) 2 1 exp −ξ 4 dξ ξ x Z +∞ 2 1 1 2 1 1 xn+2α−3 exp(− ) exp(− x 4 ) ξ −2α exp exp − ξ 4 dξ x 2 ξ 2 x 1 1 o xn+2α−3 exp − x 4 . 2 xn+2α−3 exp − For 0 < x ≤ 1 and n ≥ 0 with ξ − 1 |Θn (x)|dx ≤ Z 0 1 ξ −2α exp 2 ξ |s(ξ)| Z 0 ξ x n+2α−3 exp 2 − dx dξ. x 226 D-Semiclassical Orthogonal Polynomials Moreover, upon integration by parts we have Z = ≤ and hence ξ 2 dx x 0 Z ξ 1 n+2α−1 2 1 2 ξ exp − − (n + 2α − 1) xn+2α−2 exp − dx 2 ξ 2 x 0 Z ξ 2 1 2 1 n+2α−1 ξ exp − + (n + 2α − 1)ξ xn+2α−3 exp − dx, 2 ξ 2 x 0 xn+2α−3 exp − Z ξ x n+2α−3 0 for all 0 ≤ ξ ≤ It results in 2 n+2α−1 n+2α−1 exp − 2ξ 2 1 ξ exp − dx ≤ x 2 1 − 21 (n + 2α − 1)ξ , n ≥ 0. Z 1 |Θn (x)|dx < +∞. 0 Consequently, we get the natural integral representation of u e: for α ≥ 6( π2 )4 and f ∈ P +λTα−1 Z with 4 4.1 Teα = +∞ 0 Z 0 he u, fi = (1 − λTα−1 Teα )f(0) 1 x3 +∞ Z 1 x3 +∞ x 2α t x Z +∞ x exp x 2α t 2 exp t − 2 t 2 s(t)dtf(x)dx, x − 2 s(t)dtdx. x (95) (96) The Symmetrization Process Revisited On the symmetrization process Let u b be a symmetric regular form and {Pbn }n≥0 be its (MOPS). They satisfy a three term recurrence relation Pb0 (x) = 1, Pb1 (x) = x , (97) b b b Pn+2 (x) = xPn+1 (x) − γbn+1 Pn (x) , n ≥ 0. It is very well known (see T.S. Chihara [6] and P. Maroni [33]) that Pb2n (x) = Pen (x2 ), Pb2n+1(x) = xPn (x2 ) , n ≥ 0, (98) where {Pen }n≥0 and {Pn }n≥0 are the two (MOPS) related to regular forms u e and xe u, respectively, with u e = σb u. (99) 227 A. Ghressi and L. Khériji The form u b is said to be the symmetrized of the form u e. In fact [6,33] u b is regular ⇐⇒ u e and xe u are regular. u b is positive definite ⇐⇒ u e and xe u are positive definite. Furthermore, taking into account the three term recurrence relations for {Pen }n≥0 and {Pn }n≥0 which are (60) and (16) respectively, we get [6,33] e γ1 , β0 = b βen+1 = b γ2n+2 + γb2n+3 , n ≥ 0, γn+1 = b e γ2n+1 b γ2n+2 , n ≥ 0. and ( Consequently, b γ1 = βe0 , 4.2 (100) βn = b γ2n+1 + γb2n+2 , n ≥ 0, γn+1 = b γ2n+2 γb2n+3 , n ≥ 0. γ2 = b Qn γ1 e e0 , β γ b γ2n+1 = βe0 Qnk=1 eγkk , k=1 The D-semiclassical case γ2n+2 = b Qn+1 γk 1 Qk=1 e , n e β0 k=1 γk (101) n ≥ 1. (102) Regarding section two in [2], a study of the D-semiclassical character and the class of u b is done by J. Arvesú, M. J. Atia and F. Marcellán (in 2002) after determination of the non homogeneous first order linear differential equation satisfied by the formal Stieltjes function of u b which derived from that of u e. In the following theorem, we are going to resume these results in terms of the polynomials coefficients in the Pearson equation of u e. THEOREM 4.1. Let u e be a regular form and {Pen }n≥0 its (MOPS) such that Pen+1 (0) 6= 0, n ≥ 0. Then its symmetrized form u b is regular. If u e is D-semiclassical of class e s satisfying the functional equation e u)0 + Ψe eu = 0 (Φe (103) b u)0 + Ψb bu = 0 (Φb (104) then u b is D-semiclassical of class sb satisfying the functional equation with i) if b e 2) Φ(x) = (θ0 Φ)(x , e Φ(0) =0 b e 2 ) + 2(θ0 Ψ)(x e 2) Ψ(x) = x (θ02 Φ)(x , e 0 (0) + 2Ψ(0) e Φ = 0, (105) (106) 228 D-Semiclassical Orthogonal Polynomials and b s = 2e s for (105). ii) if b e 2) Φ(x) = x(θ0 Φ)(x e Φ(0) =0 and b s = 2e s + 1 for (107). iii) b e 2) Φ(x) = xΦ(x , , if , b e 2) Ψ(x) = 2Ψ(x e 0 (0) + 2Ψ(0) e Φ 6= 0, b e 2 ) + x2 Ψ(x e 2) Ψ(x) = 2 − Φ(x e Φ(0) 6= 0, and b s = 2e s + 3 for (109). (107) (108) (109) (110) REMARK 4.1. Some calculation allows to give the structure relation of {Pbn }n≥0 by taking into account the results of the components {Pen }n≥0, {Pn }n≥0 and Theorem 4.1. Finally, let us suppose that the form u e has the following integral representation: Z +∞ Z +∞ e (x) f (x) dx , f ∈ P; e (x) dx = 1 he u, fi = U U (111) 0 0 e is a locally integrable function with rapid decay. Consider now f ∈ P and let where U us split it up into its even and odd parts f(x) = f e (x2 ) + xf o (x2 ). From the symmetric character of the form u b, (99) and (112) we get hb u, fi = hb u, σf e i = hσb u, f e i = he u, f e i. (112) (113) In view of (111) and (113), with the fact that √ √ f( x) + f(− x) f e (x) = , x ≥ 0, 2 and after a change of variables, we obtain the following integral representation of u b Z +∞ e 2 )f(x)dx , f ∈ P hb u, fi = |x|U(x (114) −∞ since Z 0 +∞ 1 e (x)dx < +∞ , n ≥ 0. xn+ 2 U In particular, the moments of u b are (b u)0 = 1 ; (b u)2n+1 = 0 , (b u)2n+2 = (e u)n+1 , n ≥ 0. (115) (116) 229 A. Ghressi and L. Khériji 4.3 The symmetrized of δ0 + λx−1 B(α) Let u e = δ0 + λx−1 B(α) and its associated (MOPS) {Pen }n≥0 the D-semiclassical of 2 and λn , n ≥ 0are given by (91), class se = 1 for any λ 6= λn , n ≥ −1 with λ−1 = 1−2α taking x = 0 in the first equality of (67) we get Pen+1 (0) = (an − βn )Pen (0), n ≥ 0. Consequently, Pen+1 (0) 6= 0, n ≥ 0, which implies that the form u b, symmetrized of u e, is regular. On the other hand, from (92) and (106) we have e e 0 (0) + 2Ψ(0) e Φ(0) =0 , Φ = 0. Then with (106) the form u b is symmetric D-semiclassical of class 2 satisfying the functional equation (104) with b b Φ(x) = x4 , Ψ(x) = −x (4α − 1)x2 + 4 . (117) Taking into account (102) and (65)-(66), the recurrence coefficients of {Pbn }n≥0 are γb1 = λ , b γ2 = a0 , b γ2n+1 = a0 an−1 γn , b γ2n+2 = an , n ≥ 1, a0 (118) where γn , n ≥ 1 and an , n ≥ 0 are given by (83) and (90) respectively. The moments of u b are (b u)2n+1 = 0 , (b u)2n+2 = λ(−1)n 2n Γ(2α) , n ≥ 0 , (b u)0 = 1. Γ(n + 2α) Regarding the natural integral representation (95) of u e, for α ≥ 6 4 2 π − (119) 1 4 the con- dition (115) is fulfilled and from (114) we obtain the following representation of u b, for f∈P hb u, fi = (1 − λTα−1 Teα )f(0) Z +∞ Z 2 +∞ −2α 2 +λTα−1 |x|4α−5 exp − 2 t exp s(t)dtf(x)dx. (120) x t −∞ x2 REMARK 4.2. The representation (120) doesn’t exist in [8] which proves that the list of integral representations given in [8] is not complete. Another integral representation analogous to (120) is given in [39]. 4.4 Symmetrization after Perturbation when u is a Symmetric D-Semiclassical Form Let us suppose u to be a symmetric D-semiclassical form of class s satisfying the Pearson equation (21) and u e = δ0 + λx−1 u or equivalently xe u = λu. It has been shown in section 3 that u e is D-semiclassical satisfying the equation (69) with (70) and u e is of 230 D-Semiclassical Orthogonal Polynomials class se = s + 1 when (71)-(72) are valid. If u b is the symmetrized of (e u) then u e = σb u and from (58)-(59) we get ( σb u = δ0 + λx−1 u xσb u = λu. (121) Thus, σb u and xσb u are well known. Now, we are able to give γbn+1 , n ≥ 0. From (102) and by virtue of (65)-(66) we obtain γ4n+1 = −a2n , γb4n+2 = a2n , γb4n+3 = −a2n+1 , b b γ4n+4 = a2n+1 , n ≥ 0. From (11), (121) and the fact that u is symmetric, the moments of u b are (b u)0 = 1 ; (b u)4n+1 = (b u)4n+3 = (b u)4n+4 = 0 , (b u)4n+2 = λ(u)2n , n ≥ 0. (122) (123) On the other hand, in accordance with (70) we have Therefore, e Φ(x) = xΦ(x) e Φ(0) =0 , e Ψ(x) = xΨ(x). , e 0 (0) + 2Ψ(0) e Φ = Φ(0). Consequently, with Theorem 4.1., two cases arise i) b b Φ(x) = Φ(x2 ), Ψ(x) = x (θ0 Φ)(x2 ) + 2Ψ(x2 ) (124) if Φ(0) = 0, and b s = 2e s = 2s + 2 Or ii) if (125) for (124). b Φ(x) = xΦ(x2 ), b Ψ(x) = 2x2 Ψ(x2 ) Φ(0) 6= 0, (126) (127) and b s = 2e s + 1 = 2s + 3 for (126). EXAMPLE 4.1. Let u be the symmetric D-semiclassical form of class 1 of generalb of δ0 +λx−1 u ized Hermite H(µ) (µ 6= 0 , µ 6= −n− 12 , n ≥ 0), then the symmetrized u is of class sb = 4 satisfying 0 x2 u b + x 4x4 − (4µ + 1) u b = 0. (128) In this case (122) becomes Γ(µ+ 1 ) γb4n+1 = λ Γ(n+µ+2 1 ) n! 2 Γ(µ+ 1 ) γb4n+2 = −λ Γ(n+µ+2 1 ) n! 2 Γ(n+µ+ 3 ) 1 γb4n+3 = − λ1 Γ(µ+ 1 )2 n! 2 3 γb4n+4 = 1 Γ(n+µ+1 2 ) 1 λ Γ(µ+ ) n! 2 , n ≥ 0. (129) 231 A. Ghressi and L. Khériji The moments are (b u)0 = 1 (b u)4n+1 = (b u)4n+3 = (b u)4n+4 = 0 , n ≥ 0. λ Γ(µ+1)Γ(2n+2µ+1) (b u)4n+2 = 22n Γ(2µ+1)Γ(n+µ+1) (130) EXAMPLE 4.2. Let u be the symmetric D-semiclassical form of class 1 of generalized Gegenbauer G(α, β) (α 6= −n−1 , β 6= −n−1 , β 6= − 12 , α+β 6= −n−1 , n ≥ 0), then the symmetrized u b of δ0 + λx−1 u is of class b s = 4 satisfying 0 x2 (x4 − 1)b u + x −(4α + 4β + 7)x4 + 4β + 3 u b = 0. (131) In this case (122) becomes Γ(n+α+1)Γ(α+β+1)Γ(β+1) λn! γ4n+1 = 2n+α+β+1 b Γ(α+1)Γ(n+α+β+1)Γ(n+β+1) Γ(n+α+1)Γ(α+β+1)Γ(β+1) λn! b γ4n+2 = − 2n+α+β+1 Γ(α+1)Γ(n+α+β+1)Γ(n+β+1) Γ(α+1)Γ(n+α+β+2)Γ(n+β+2) 1 b4n+3 = − λn!(2n+α+β+2) γ Γ(n+α+1)Γ(α+β+2)Γ(β+1) Γ(α+1)Γ(n+α+β+2)Γ(n+β+2) b 1 γ4n+4 = λn!(2n+α+β+2) Γ(n+α+1)Γ(α+β+2)Γ(β+1) , n ≥ 0. (132) The moments are (b u)0 = 1 (b u)4n+1 = (b u)4n+3 = (b u)4n+4 = 0 , n ≥ 0. Γ(α+β+2)Γ(n+β+1) (b u)4n+2 = λ Γ(β+1)Γ(n+α+β+2) (133) EXAMPLE 4.3. Let u be the symmetric D-semiclassical form of class 1 of Bessel kind B[ν] (ν 6= −n − 1 , n ≥ 0), then the symmetrized u b of δ0 + λx−1 u is of class sb = 4 with 0 x6 u b − x (4ν + 3)x4 + 1 u b = 0. (134) In this case (122) becomes n n! Γ(ν+1) γ4n+1 = λ (−1) b (2n+ν) Γ(n+ν) (−1)n n! Γ(ν+1) b γ4n+2 = −λ (2n+ν) Γ(n+ν) The moments are (−1)n Γ(n+ν+1) 1 b4n+3 = 4λ γ (2n+ν+1)n! Γ(ν+1) n (−1) Γ(n+ν+1) b 1 γ4n+4 = − 4λ (2n+ν+1)n! Γ(ν+1) , n ≥ 0. (b u)0 = 1 (b u)4n+1 = (b u)4n+3 = (b u)4n+4 = 0 , n ≥ 0. 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