General Mathematics Vol. 15, Nr. 2–3(2007), 108-117 Certain inequalities concerning some complex and positive functionals Emil C. Popa Abstract In this paper we study an inequality for the complex and positive functionals. Some applications for the Carlson0 s inequality and for complex matrices on given. 2000 Mathematical Subject Classification: 26D07, 26D15 Key words and phrases: complex functionals, positive functionals, Carlson0 s inequality, complex matrices. 1 Introduction Let X be a complex algebra and F : X × X → C a complex functional with the following properties i) F (αx1 + βx2 , y) = αF (x1 , y) + βF (x2 , y)for all x1 , x2 , y ∈ X and α, β ∈ C 108 Certain inequalities concerning some complex ... 109 ii) F (x, y) = F (y, x) for all x, y ∈ X iii) F (x, x) ≥ 0 for all x ∈ X. Appling the Cauchy - Schwartz - Buniakowski inequality we have |F (yx, z)|2 ≤ F (yx, yx) · F (z, z) (1) for all x, y, z ∈ X. 1 Let y0 = λw1 + w2 be an element of X where w1 , w2 ∈ X, λ ∈ C, λ Re(λ) 6= 0, Im(λ) 6= 0, |y0 | 6= 0. We have µ (2) ¶ 1 1 F (y0 x, y0 x)= F λw1 x + w2 x, λw1 x + w2 x = λ λ µ ¶ λ 1 2 = |λ| F (w1 x, w1 x) + 2 F (w2 x, w2 x) + 2Re F (w1 x, w2 x) . |λ| λ We can formulate the next lemma Lemma 1. If |F (w1 x, w1 x)|6=0, |F (w2 x, w2 x)| = 6 0 and Re (F (w1 x, w2 x))6=0, there exist a complex number λ = p + qi, such that s F (w2 x, w2 x) (3) |λ|2 = F (w1 x, w1 x) µ (4) (5) Re ¶ λ F (w1 x, w2 x) = 0 λ p2 ≥ q 2 110 Emil C. Popa Proof. We denote F (w1 x, w2 x) = a + bi, a 6= 0 and from (4) we obtain µ ¶2 p p a − 2b − a = 0 q q with b2 + a2 > 0 and x1 x2 = 1 (x1 , x2 roots). Hence |x¯1 | ¯≥ 1 or |x2 | ≥ 1. ¯p¯ Then exists p, q ∈ R, p 6= 0, q 6= 0 such that ¯¯ ¯¯ ≥ 1 or |p| ≥ |q| q satisfying (3), (4), (5). With this λ, from (1) and (2) we obtain p |F (y0 x, z)|2 ≤ 2 F (w1 x, w1 x) · F (w2 x, w2 x) · F (z, z) so |F (y0 x, z)|4 ≤ 4F 2 (z, z) · F (w1 x, w1 x) · F (w2 x, w2 x). (6) We name (6) the Carlson - type inequality for complex and positive functionals, because of (6) we obtain for example the classical Carlson integral inequality. 2 Applications 1. Let X be the complex algebra of the complex and integrable functions defined on [a, ∞), a > 0. We consider Z∞ F (f, g) = f (t)g(t)dt a where f, g ∈ X. F verify the conditions i), ii), iii) of introduction, evidently. Certain inequalities concerning some complex ... 111 Now we consider x(t), y0 (t), z(t) ∈ X, non-nulls, and w1 , w2 : [a, ∞) → (0, ∞) two continuously differentiable functions such that w20 (t)w1 (t) − w2 (t)w10 (t) ≥ m > 0. It is clear that Z∞ w12 (t)|x(t)|2 dt ≥ 0, F (w1 x, w1 x) = a Z∞ w22 (t)|x(t)|2 dt ≥ 0, F (w2 x, w2 x) = a Z∞ w1 (t)w2 (t)|x(t)|2 dt ≥ 0, F (w1 x, w2 x) = a 2 and hence, using (4) we have p = q 2 . Of (6) we obtain ¯4 ¯∞ ¯ ¯Z ¯ ¯ ¯ y0 (t)x(t)z(t)dt¯ ≤ ¯ ¯ ¯ ¯ a 2 ∞ ∞ Z Z∞ Z 2 2 4 z(t)z(t)dt · w1 (t)|x(t)| dt · w22 (t)|x(t)|2 dt. (7) a a Since |y0 (t)| 6= 0 we choose z(t) = (8) a 1 y0 (t) in (7) and we get ¯∞ ¯4 2 ∞ ∞ ¯Z ¯ Z Z∞ Z ¯ ¯ dt ¯ x(t)dt¯ ≤ 4 · w12 (t)|x(t)|2 dt · w22 (t)|x(t)|2 dt. ¯ ¯ 2 |y (t)| 0 ¯ ¯ a a a a Clearly Z dt = |y0 (t)|2 Z dt ¯2 = ¯ ¯ ¯ 1 ¯λw1 (t) + w2 (t)¯ ¯ ¯ λ Z |λ|2 w12 (t) ¯ ¯ dt. ¯ 2 w2 (t) ¯2 ¯λ + ¯ ¯ w1 (t) ¯ 112 Emil C. Popa Since λ = p + qi, p2 = q 2 , we have ¯ ¯ 2 ¯ 2 w2 (t) ¯2 ¯λ + ¯ = |λ|4 + w2 (t) . ¯ w1 (t) ¯ w12 (t) Hence Z dt = |y0 (t)|2 Z µ (9) ≤ 1 m Z 1 |λ|2 w12 (t) µ ¶2 dt ≤ w2 (t) 1+ |λ|2 w1 (t) ¶0 w2 (t) 1 w2 (t) |λ|2 w1 (t) arctg µ ¶2 dt = m |λ|2 w1 (t) w2 (t) 1+ |λ|2 w1 (t) and we have the following result Theorem 1.Let x(t) : [a, ∞) → C, a > 0, an integrable function and w1 (t), w2 (t) : [a, ∞) → (0, ∞) two continuously differentiable functions w2 (t) = ∞. with w20 (t)w1 (t) − w2 (t)w10 (t) ≥ m > 0, lim t→∞ w1 (t) Then ¯∞ ¯4 ¯Z ¯ ¶2 µ ¯ ¯ ¯ x(t)dx¯ ≤ 4 π − 1 arctg w2 (a) · ¯ ¯ 2m m c · w1 (a) ¯ ¯ a (10) Z∞ Z∞ 2 2 · w1 (t)|x(t)| dt · w22 (t)|x(t)|2 dt a where a v u Z∞ u u w2 (t)|x(t)|2 dt u 2 u ua c = c(w1 , w2 ) = u Z∞ u u t w12 (t)|x(t)|2 dt a Certain inequalities concerning some complex ... 113 Z∞ w12 (t)|x(t)|2 dt > 0. and a Proof. Of (8) and (9) we obtain ¯4 ¯∞ ¯ ¯Z µ ¶2 ¯ ¯ π 1 w (a) 2 ¯ x(t)dt¯ ≤ 4 · − arctg ¯ ¯ 2m m |λ|2 w1 (a) ¯ ¯ a Z∞ Z∞ w12 (t)|x(t)|2 dt · · a where w22 (t)|x(t)|2 dt a v u Z∞ u u w2 (t)|x(t)|2 dt u 2 u u |λ|2 = u Za∞ u u t w12 (t)|x(t)|2 dt a in conformity with (3). Remark 1. When w1 (t) = 1, w2 (t) = t then the inequality (10) reduces to (11) ¯∞ ¯4 ¯Z ¯ ¶2 Z∞ µ Z∞ ¯ ¯ a π 2 ¯ x(t)dt¯ ≤ 4 − arctg · |x(t)| dt · t2 |x(t)|2 dt. ¯ ¯ 2 c(1, t) ¯ ¯ a a a When a → 0, inequality (11) reduces to the well known Carlson0 s integral inequality (12) ¯4 ¯∞ ¯ ¯Z Z∞ Z∞ ¯ ¯ 2 2 ¯ x(t)dt¯ ≤ π |x(t)| dt · t2 |x(t)|2 dt ¯ ¯ ¯ ¯ 0 (see [7]). 0 0 114 Emil C. Popa Hence (10) and (11) are an improvement of (12). 2. We consider now the complex algebra of square matrices with complex elements X = Mn (C). If A is a n × n matrix, we write tr A to denote the trace of A. If a11 a12 ... a1n a21 a22 ... a2n A= ... ... ... ... an1 an2 ... ann we denote , a11 a21 ... an1 a12 a22 ... an2 ∗ A = ... ... ... ... a1n a2n ... ann aij ∈ C . Let F be a complex functional defined by F (x, y) = tr(y ∗ x) , F :X ×X →C which verify i), ii), iii), evidently. Using (6) we get (13) |tr(z ∗ y0 x)|4 ≤ 4tr2 (z ∗ z) · tr(x∗ w1∗ w1 x) · tr(x∗ w2∗ w2 x) 1 where x, z, w1 , w2 ∈ X and y0 = λw1 + w2 , y0 ∈ X, with λ of (3), (4), (5). λ If y0∗ y0 = In then choosing in (13) z = y0 we obtain (14) |trx|4 ≤ 4tr2 (y0∗ y0 ) · tr(x∗ w1∗ w1 x) · tr(x∗ w2∗ w2 x) and we have the next Certain inequalities concerning some complex ... 115 Theorem 2. Let x, w1 , w2 be some matrices of Mn (C). If µ ¶∗ µ ¶ 1 1 λw1 + w2 λw1 + w2 = In λ λ with λ complex number which verify s tr(x∗ w2∗ w2 x) (15) |λ|2 = tr(x∗ w1∗ w1 x) µ (16) Re ¶ λ ∗ ∗ · tr(x w2 w1 x) = 0 λ (Re(λ))2 ≥ (Im(λ))2 , (17) then we have the following inequality of Carlson0 s type |tr x|4 ≤ 4n2 · tr(x∗ w1∗ w1 x) · tr(x∗ w2∗ w2 x). (18) Proof. Using the inequality (14) and (3), (4), (5) we get (15), evidently. Remark 1. For w1 = w2 = µ 1 λw1 + w2 λ ¶∗ µ 1 w, where p = Re(λ) and w∗ w = In , we obtain 2p 1 λw1 + w2 λ ¶ 2 1 (λ2 + 1)(λ + 1) ∗ = 2 w w= 4p λλ 2 1 (λ2 + 1)(λ + 1) = 2 In . 4p λλ Since (15), (16), (17) we have |λ|2 = 1 and (Re(λ))2 = (In(λ))2 . Hence |λ|2 = 2p2 = 1 and µ 1 λw1 + w2 λ ¶∗ µ 1 λw1 + w2 λ ¶ = In . 116 Emil C. Popa Therefore from (18) it follows that |trx|4 ≤ n2 2 ∗ tr (x x). 4p4 This implies |trx|2 ≤ n · tr(x∗ x). (19) Remark 2.We observe the fact that from (19) we get the well known inequality |a1 + a2 + ... + an |2 ≤ n(|a1 |2 + |a2 |2 + ... + |an |2 ) for ai ∈ C, i = 1, 2. References [1] Barza S., Pečarić J., Persson L. E., Carlson type inequalities, J. Inequal. Appl. 2, 2 (1998), 121-135. [2] Barza S., Popa E. C., Inequalities related with Carlson0 s inequality, Tamkang J. Math., 29, 1 (1998), 59-64. [3] Barza C., Popa E. C., Weighted multiplicative integral inequalities, Y.I.P.A.M., Vol 7(5), Art. 169, 2006. [4] Carlson F., Une inégalité, Ark. Mat. Astr. Fysik 26B, 1 (1934). [5] Hardy G. H., A note on two inequalities, J. London Math. Soc. 11 (1936), 167-170. Certain inequalities concerning some complex ... 117 [6] Hardy G. H., Littlewood J. E., Pólya G., Inequalities, Cambridge, University Press, 1952, 2d ed.. [7] Larsson L., Maligranda L., Peěcarić J., Persson L. E., Multiplicative Inequalities of Carlson Type and Interpolation, World Scientific, 2006. Emil C. Popa Department of Mathematics Faculty of Science University ”Lucian Blaga” of Sibiu Str. I. Ratiu, no. 5-7, 550012 - Sibiu, Romania Email address: emil.popa@ulbsibiu.ro ecpopa2002@yahoo.com