General Mathematics Vol. 14, No. 1 (2006), 55–64 On a subclass of n-uniformly close to convex functions 1 Mugur Acu Abstract In this paper we define a subclass on n-uniformly close to convex functions and we obtain some properties regarding this class. 2000 Mathematical Subject Classification: 30C45. Key words and phrases: Uniformly close to convex functions, Libera-Pascu integral operator, Briot-Bouquet differential subordination 1 Introduction Let H(U ) be the set of functions which are regular in the unit disc U = {z ∈ C : |z| < 1}, A = {f ∈ H(U ) : f (0) = f 0 (0) − 1 = 0} and S = {f ∈ A : f is univalent in U }. We recall here the definition of the well - known class of starlike functions: zf 0 (z) ∗ S = f ∈ A : Re >0, z∈U , f (z) Let Dn be the Sălăgean differential operator (see [5]) Dn : A → A, n ∈ N, defined as: D0 f (z) = f (z) 1 Received January 10, 2006 Accepted for publication (in revised form) February 2, 2006 55 56 M. Acu D1 f (z) = Df (z) = zf 0 (z) Dn f (z) = D(Dn−1 f (z)) Remark 1.1. If f ∈ S , f (z) = z + ∞ P aj z j , z ∈ U then j=2 n D f (z) = z + ∞ X j n aj z j . j=2 Let consider the Libera-Pascu integral operator La : A → A defined as: (1) 1+a f (z) = La F (z) = za Zz F (t) · ta−1 dt , a∈C, Re a ≥ 0. 0 For a = 1 we obtain the Libera integral operator, for a = 0 we obtain the Alexander integral operator and in the case a = 1, 2, 3, ... we obtain the Bernardi integral operator. The purpose of this note is to define, using the Sălăgean differential operator, a subclass on n-uniformly close to convex functions and to obtain some properties regarding this class. 2 Preliminary results Let k ∈ [0, ∞), n ∈ N∗ . We define the class (k, n) − S ∗ (see the definition of the class (k, n) − ST in [1]) by f ∈ S ∗ and n n D f (z) D f (z) Re > k − 1 , z ∈ U . f (z) f (z) Remark 2.1. (for more details see [1]) We denote by pk , k ∈ [0, ∞) the function which maps the unit disk conformally onto the region Ωk , such that 1 ∈ Ωk and ∂Ωk = u + iv : u2 = k 2 (u − 1)2 + k 2 v 2 . The domain Ωk is elliptic for k > 1, hyperbolic when 0 < k < 1, parabolic for k = 1, and a right half-plane when k = 0. In this conditions, a function On a subclass of n-uniformly close to convex functions 57 Dn f (z) Dn f (z) ≺ pk or take all f (z) f (z) values in the domain Ωk . Because the domain Ωk is convex, as an immediate consequence of the well known Rogosinski result for subordinate functions, we obtain for p ≺ pk , p(z) = 1 + p1 z + p2 z 2 + ... , z ∈ U , 8(arccos k)2 , 0 ≤ k < 1, π 2 (1 − k 2 ) 8 |pn | ≤ |P1 | := P1 (k) = , k = 1, π2 2 π √ 2 , k > 1. 4 κ(k − 1)K 2 (κ)(1 + κ) f is in the class (k, n) − S ∗ if and only if for n = 1, 2, ... , where K(κ) is Legendre, s complete elliptic integral of the first kind, κ is chosen such that k = cosh[πK 0 (κ)]/[4K(κ)] and K 0 (κ) is complementary integral of K(κ) . With the notations from Remark 2.1 we have: Theorem 2.1. [1] Let k ∈ [0, ∞) and f (z) = z + ∞ P aj z j belongs to the j=2 P1 class (k, n) − S ∗ . Then |a2 | ≤ n and 2 −1 j−1 P1 Y P1 |aj | ≤ n 1+ n , j = 3, 4, ... , n ∈ N∗ . j − 1 s=2 s −1 The next theorem is result of the so called ”admissible functions method” introduced by P.T. Mocanu and S.S. Miller (see [2], [3], [4]). Theorem 2.2. Let q be convex in U and j : U → C with Re[j(z)] > 0, z ∈ U . If p ∈ H(U ) and satisfied p(z)+j(z)·zp0 (z) ≺ q(z), then p(z) ≺ q(z). 3 Main results Definition 3.1. Let f ∈ A, k ∈ [0, ∞) and n ∈ N∗ . We say that the function f is in the class (k, n) − CC with respect to the function g ∈ (k, n) − S ∗ if n n D f (z) D f (z) Re − 1 , z ∈ U . > k · g(z) g(z) 58 M. Acu Remark 3.1. Geometric interpretation: f ∈ (k, n) − CC with respect to Dn f (z) ≺ pk (see Remark 2.1) the function g ∈ (k, n) − S ∗ if and only if g(z) Dn f (z) or take all values in the domain Ωk (see Remark 2.1). g(z) Remark 3.2. From the geometric properties of the domains Ωk we have that (k1 , n) − CC ⊂ (k2 , n) − CC, where k1 ≥ k2 . Theorem 3.1. If F (z) ∈ (k, n) − S ∗ , with k ∈ [0, ∞) and n ∈ N∗ , then f (z) = La F (z) ∈ (k, n) − S ∗ , where La is the integral operator defined by (1). Proof. By differentiating (1) we obtain (2) (1 + a)F (z) = af (z) + zf 0 (z) . By means of the application of the linear operator Dn we have (3) (1 + a)Dn F (z) = aDn f (z) + Dn+1 f (z) . From (2) and (3) we obtain Dn f (z) Dn+1 f (z) f (z) a + (1 + a)Dn F (z) aDn f (z) + Dn+1 f (z) f (z) f (z) = = 0 0 zf (z) (1 + a)F (z) af (z) + zf (z) f (z) a + f (z) or Dn f (z) Dn+1 f (z) + Dn F (z) f (z) f (z) . = 0 zf (z) F (z) a+ f (z) a (4) With notation p(z) = zp0 (z) = z Dn f (z) , where p(0) = 1, we obtain f (z) (Dn f (z))0 f (z) − (Dn f (z)) f 0 (z) = f 2 (z) On a subclass of n-uniformly close to convex functions = or 59 z (Dn f (z))0 Dn f (z) zf 0 (z) Dn+1 f (z) zf 0 (z) − · = − p(z) · f (z) f (z) f (z) f (z) f (z) Dn+1 f (z) zf 0 (z) = zp0 (z) + p(z) · . f (z) f (z) (5) From (4) and (5) we have zf 0 (z) + zp0 (z) p(z) a + Dn F (z) f (z) = zf 0 (z) F (z) a+ f (z) or Dn F (z) = p(z) + F (z) (6) 1 · zp0 (z) zf 0 (z) a+ f (z) Dn F (z) ≺ pk (z), where pk maps the unit disk F (z) conformally onto the convex domain Ωk (see Remark 2.1). 1 Using (6) we obtain p(z) + · zp0 (z) ≺ pk (z). 0 zf (z) a+ f (z) Using the hypothesis, from Theorem 2.2, we have p(z) ≺ pk (z) or Dn f (z) take all values in the domain Ωk . This means that f (z) ∈ (k, n)−S ∗ . f (z) From hypothesis we have Theorem 3.2. If F (z) ∈ (k, n) − CC, k ∈ [0, ∞), n ∈ N∗ , with respect to the function G(z) ∈ (k, n) − S ∗ , and f (z) = La F (z), g(z) = La G(z), where La is the integral operator defined by (1), then f (z) ∈ (k, n) − CC, k ∈ [0, ∞), n ∈ N∗ , with respect to the function g(z) ∈ (k, n) − S ∗ . Proof. Using (1) and the linear operator Dn we obtain (1 + a)Dn F (z) = aDn f (z) + Dn+1 f (z) and (1 + a)G(z) = ag(z) + zg 0 (z) . 60 M. Acu From the above we have (1 + a)Dn F (z) aDn f (z) + Dn+1 f (z) = (1 + a)G(z) ag(z) + zg 0 (z) or Dn f (z) Dn+1 f (z) + a Dn F (z) g(z) g(z) = 0 zg (z) G(z) a+ g(z) n D f (z) If we denote p(z) = , with p(0) = 1, we have g(z) n D F (z) = G(z) (7) Dn+1 f (z) g(z) 0 zg (z) a+ g(z) ap(z) + With simple calculations we obtain z (Dn f (z))0 Dn f (z) zg 0 (z) Dn+1 f (z) zg 0 (z) zp (z) = − · = − p(z) · g(z) g(z) g(z) g(z) g(z) 0 and thus (8) (9) Dn+1 f (z) zg 0 (z) = zp0 (z) + p(z) · g(z) g(z) From (7) and (8) we obtain Dn F (z) = p(z) + G(z) 1 · zp0 (z) = p(z) + j(z) · zp0 (z) , zg 0 (z) a+ g(z) where from the hypothesis and the Theorem 3.1 we have Re j(z) > 0 z∈U. From F (z) ∈ (k, n)−CC with respect to the function G(z) ∈ (k, n)−S ∗ , using Remark 3.1, we obtain p(z) + j(z) · zp0 (z) ≺ pk (z), where pk maps the unit disk conformally onto the convex domain Ωk (see Remark 2.1). Dn f (z) From Theorem 2.2, we have p(z) ≺ pk (z) or take all values in g(z) the domain Ωk . This means that f (z) ∈ (k, n) − CC with respect to the function g(z) ∈ (k, n) − S ∗ . On a subclass of n-uniformly close to convex functions Theorem 3.3. If f (z) = z + ∞ X 61 aj z j belong to the class (k, n) − CC, with j=2 ∗ respect to the function g(z) ∈ (k, n) − S , g(z) = z + ∞ X bj z j , where j=2 ∗ k ∈ [0, ∞), n ∈ N , then |a2 | ≤ P1 P1 (P1 − 1 + 2n ) ; |a | ≤ ; 3 2n − 1 (2n − 1) (3n − 1) j−1 Y P1 P 1 − 1 + tn |aj | ≤ n · , j ≥ 4, j − 1 t=2 tn − 1 where P1 is given in Remark 2.1. Dn f (z) ≺ pk (z), g(z) where pk (U ) = Ωk (see Remark 3.1). Let h(z) = 1 + c1 z + c2 z 2 + · · · , z ∈ U . Taking account the Rogosinski subordination theorem, we have |cj | ≤ P1 , j ≥ 1 . Using the hypothesis and the Remark 1.1 we have Proof. We have f (z) ∈ (k, n) − CC if and only if h(z) = z+ ∞ X j n aj z j j=2 ∞ X z+ = 1 + c1 z + c2 z 2 + · · · . bj z j j=2 From the equality of the powers coefficients we obtain 2n a2 = c1 + b2 ; 3n a3 = c2 + b3 + c1 b2 and (10) j n aj = cj−1 + c1 bj−1 + c2 bj−2 + c3 bj−3 + · · · cj−2 b2 + bj , j ≥ 4 . Using |cj | ≤ P1 , j ≥ 1 , 2n a2 = c1 + b2 and Theorem 2.1 we have P1 2n 2 |a2 | ≤ P1 + n = n · P1 2 −1 2 −1 n 62 M. Acu and thus |a2 | ≤ P1 . −1 2n P1 (P1 − 1 + 2n ) In a similarly way we obtain |a3 | ≤ n . (2 − 1) (3n − 1) Using |cj | ≤ P1 , j ≥ 1 and Theorem 2.1 we obtain from (10) the estimations " ( #) j−1 l−1 X Y P P1 P P 1 1 1 + n + · · j n |aj | ≤ P1 1 + n 1+ n n 2 − 1 l=3 l − 1 s=2 s −1 j −1 · j−1 Y t=2 P1 1+ n t −1 . By mathematical induction for j ≥ 4 we have " # Y j−1 j−1 l−1 X Y P1 P1 P1 P1 − 1 + tn 1+ n + · 1+ n = 2 − 1 l=3 ln − 1 s=2 s −1 tn − 1 t=2 and thus we obtain n j |aj | ≤ P1 · j−1 Y P1 − 1 + tn tn − 1 t=2 or j−1 Y P1 P1 + n · 1+ n j − 1 t=2 t −1 j−1 Y P1 P1 − 1 + tn j |aj | ≤ j n · , j ≥ 4. j − 1 t=2 tn − 1 n Thus n j−1 Y P1 P 1 − 1 + tn |aj | ≤ n · , j ≥ 4, j − 1 t=2 tn − 1 Theorem 3.4. Let a ∈ C, Re a ≥ 0, n ∈ N∗ and k ∈ [0, ∞). If ∞ X F (z) ∈ (k, n) − CC, F (z) = z + aj z j , and f (z) = La F (z), f (z) = z + ∞ X j=2 bj z j ,where La is the integral operator defined by (1), then j=2 a + 1 P1 (P1 − 1 + 2n ) a + 1 P1 ; |b3 | ≤ ; |b2 | ≤ a + 2 2n − 1 a + 3 (2n − 1) (3n − 1) On a subclass of n-uniformly close to convex functions 63 j−1 Y a + 1 P1 P1 − 1 + tn |bj | ≤ · , j ≥ 4, a + j j n − 1 t=2 tn − 1 where P1 is given in Remark 2.1. Proof. From f (z) = La F (z) we have (1 + a)F (z) = af (z) + zf 0 (z) . Using the above series expansions we obtain (1 + a)z + ∞ X (1 + a)aj z j = az + j=2 ∞ X j=2 abj z j + z + ∞ X jbj z j j=2 and thus bj (a + j) = (1 + a)aj j ≥ 2 . a + 1 · |aj | , j ≥ 2 . Using the estimations From the above we have bj ≤ a + j from Theorem 3.3 we obtain the needed results. For a = 1, when the integral operator La become the Libera integral operator, we obtain from the above theorem: Corollary 3.1.Let n ∈ N∗ and k ∈ [0, ∞). If F (z) ∈ (k, n) − CC, ∞ ∞ X X F (z) = z + aj z j , and f (z) = L(F (z)), f (z) = z + bj z j ,where L is j=2 Z j=2 2 z F (t)dt, then the Libera integral operator defined by L(F (z)) = z 0 |b2 | ≤ 2 P1 1 P1 (P1 − 1 + 2n ) ; |b | ≤ ; 3 3 2n − 1 2 (2n − 1) (3n − 1) j−1 Y 2 P 1 − 1 + tn P1 |bj | ≤ · , j ≥ 4, j + 1 j n − 1 t=2 tn − 1 where P1 is given in Remark 2.1. Remark 3.3. Similarly results with the results from the Corollary 3.1 are easy to obtain from Theorem 3.4 by taking a = 0, respectively a = 1, 2, 3, · · · . 64 M. Acu References [1] S. Kanas, T. Yaguchi, Subclasses of k-uniformly convex and strlike functions defined by generalized derivate I, Indian J. Pure and Appl. Math. 32, 9(2001), 1275-1282. [2] S. S. Miller and P. T. Mocanu, Differential subordonations and univalent functions, Mich. Math. 28 (1981), 157 - 171. [3] S. S. Miller and P. T. Mocanu, Univalent solution of Briot-Bouquet differential equations, J. Differential Equations 56 (1985), 297 - 308. [4] S. S. Miller and P. T. Mocanu, On some classes of first-order differential subordinations, Mich. Math. 32(1985), 185 - 195. [5] Gr. Sălăgean, Subclasses of univalent functions, Complex Analysis. Fifth Roumanian-Finnish Seminar, Lectures Notes in Mathematics, 1013, Springer-Verlag, 1983, 362-372. ”Lucian Blaga” University of Sibiu, Department of Mathematics, Str. Dr. I. Rat.iu, No. 5-7, 550012 - Sibiu, Romania E-mail: acu mugur@yahoo.com