Math 152 – Spring 2016 Section 10.2 1 of 8 Section 10.2 – Series Definition. If we add the terms of an infinite sequence {an }∞ n=1 , then we get an infinite series a1 + a2 + a3 + · · · + an + · · · . We use the notation ∞ X an or X an n=1 Question. How do we add infinitely many things? Consider the following two series: 1. ∞ X n We can define partial sums – sums of the first i terms denoted si : n=1 s1 = 1 s2 = 1 + 2 = 3 s3 = 1 + 2 + 3 = 6 s4 = 1 + 2 + 3 + 4 = 10 .. . sn = 1 + 2 + · · · + n = n(n + 1) 2 .. . This series clearly has an infinite sum – as we add more and more terms the sum approaches infinity. We say the series is divergent. 2. ∞ X 1 . 2n n=1 The partial sums si are 1 2 1 3 1 s2 = + 2 = 2 2 4 1 1 1 7 s3 = + 2 + 3 = 2 2 2 8 1 1 1 1 15 s4 = + 2 + 3 + 4 = 2 2 2 2 16 .. . 1 1 1 1 sn = + 2 + · · · + n = 1 − n 2 2 2 2 .. . s1 = As n → ∞ the partial sums approach 1. Therefore, ∞ X 1 = 1. 2n n=1 Math 152 – Spring 2016 Definition. Given a series Section 10.2 ∞ X 2 of 8 ai = a1 + a2 + a3 + · · · , let sn denote its nth partial i=1 sum: sn = a1 + a2 + · · · an = n X ai i=1 If the sequence {sn } is convergent and lim sn = s exists as a real number, then the series ∞ X n→∞ ai is called convergent and we write i=1 a1 + a2 + a3 + · · · = s or ∞ X an = s n=1 The number s is called the sum of the series. If the sequence {sn } does not converge, then the series is called divergent. Note. In the previous definition, it is easy to confuse what is a series and what is a sequence. • Series – the infinite sum ∞ X an n=1 • Sequence – the partial sums {sn } form a sequence where each sn = n X ai . i=1 The definition tells us that (provided the limit exists) the infinite series equals the limit of the partial sums: ∞ n X X ai = lim ai = lim sn i=1 n→∞ i=1 n→∞ Example 1. Determine if the following sequences converge or diverge. If they converge, find the sum. (a) ∞ X n n=1 (b) ∞ X 1 2n n=1 Math 152 – Spring 2016 Section 10.2 3 of 8 Geometric Series. A geometric series is a series of the form a + ar + ar2 + ar3 + · · · + arn + · · · = ∞ X arn−1 r 6= 0 n=1 where a and r 6= 0 are constants. Question. For what values of r does a geometric series converge? Theorem. The geometric series ∞ X arn−1 = a + ar + ar2 + ar3 + · · · + arn + · · · n=1 is convergent if |r| < 1 and its sum is ∞ X n=1 arn−1 = a 1−r for |r| < 1. If |r| ≥ 1, the geometric series is divergent. Example 2. Determine if the series is convergent or divergent. If it is convergent, find its sum. (a) ∞ X n=1 2−3n 5n+2 Math 152 – Spring 2016 (b) ∞ X Section 10.2 sinn x, where −π/2 < x < π/2 n=1 (c) ∞ X 1 n(n + 1) n=1 (d) 2 − 7 3 + 49 18 − 343 108 + ··· Example 3. Write the number 2.15 as a fraction. 4 of 8 Math 152 – Spring 2016 Section 10.2 5 of 8 Harmonic Series. The harmonic series is the series ∞ X 1 1 1 1 1 = 1 + + + + ··· + + ··· n 2 3 4 n n=1 Show that the harmonic series is divergent. n Terms: an Partial Sums: sn 1 a1 = 1 s1 = 1 2 a2 = 1 2 s2 = 1.5 3 a3 = 1 3 s3 = 1.83 4 a4 = 1 4 s4 = 2.08 5 a5 = 1 5 s5 = 2.28 6 a6 = 1 6 s6 = 2.45 7 a7 = 1 7 s7 = 2.59 8 a8 = 1 8 s8 = 2.72 9 a9 = 1 9 s9 = 2.83 1 10 s10 = 2.93 10 a10 = Theorem. If the series ∞ X n=1 Sketch of proof: an is convergent, then lim an = 0. n→∞ Math 152 – Spring 2016 Section 10.2 6 of 8 Test for Divergence. If lim an does not exist or lim an 6= 0, then the series n→∞ n→∞ ∞ X an n=1 is divergent. Note 1: For ∞ X an we have the following sequences and series: n=1 • Series – the infinite sum ∞ X an n=1 • Sequence – the partial sums {sn } form a sequence where each sn = n X ai . i=1 • Sequence – the terms of the sum form a sequence {an } (this is the sequence {a1 , a2 , a3 , . . .} used in the Test for Divergence and the terms are NOT being added.) Note 2: If lim an = 0, then the series might be convergent or it might be divergent n→∞ – the test for divergence DOES NOT tell us ANYTHING in this case. Recall the har∞ X 1 1 = 0, but is divergent. monic series: lim n→∞ n n n=1 Example 4. Determine if the following series are convergent or divergent. If a series is convergent, find its sum. (a) ∞ X n=1 (b) √ 3n n2 + 3 ∞ X n ln n n=1 Math 152 – Spring 2016 Theorem. If ∞ X Section 10.2 an and n=1 ∞ X 7 of 8 bn are convergent series, then the following series are n=1 convergent and equal to what is listed below: • ∞ X can = c n=1 • ∞ X ∞ X (an + bn ) = n=1 • ∞ X an n=1 ∞ X an + n=1 (an − bn ) = n=1 ∞ X n=1 ∞ X bn n=1 an − ∞ X bn n=1 Example 5. Determine if the following series are convergent or divergent. If the series is convergent, find its sum. ∞ X 1 2−3n 5n+2 − n (a) 2 i=1 (b) ∞ X 3 n(n + 1) n=2 Math 152 – Spring 2016 (c) ∞ X ln n − ln(n2 − 3) n=1 (d) ∞ X e−n − e−n+1 n=1 n ∞ X π 1 7 − n+1 (e) 32n 2 n=1 Section 10.2 8 of 8