Math 152 – Spring 2016 Section 10.3 1 of 6 Section 10.3 – The Integral and Comparison Tests, Estimating Sums Example 1. Use the integral of the corresponding function to determine if the following series are convergent or divergent. (a) ∞ X 1 2 n n=1 (b) ∞ X 1 √ n n=1 The Integral Test. Suppose that f is a function on [1, ∞) and let an = f (n). If f is • continuous, • positive, and • decreasing, then Z ∞ 1. If f (x) dx is convergent, then 1 Z 2. If an is convergent. n=1 ∞ f (x) dx is divergent, then 1 ∞ X ∞ X an is divergent. n=1 Note. • The Integral Test still works if the series starts at something other than n = 1. If the series starts at n = 2, then start the integral at 2 as well. • We must make sure the function f satisfies all three requirements or the integral test does not apply. However, it is not necessary that f is always decreasing, just that f is only decreasing after some point (i.e., there is some N such that f is decreasing for all x > N ). Math 152 – Spring 2016 Section 10.3 Example 2. Determine whether the series ∞ X ln n is convergent or divergent. n2 n=1 Example 3. For what values of p is the series P-Series: The p-series 2 of 6 ∞ X 1 convergent? np n=1 ∞ X 1 is convergent if p > 1 and divergent if p ≤ 1. p n n=1 Note: It is easy to confuse p-series and geometric series: ∞ X 1 : the index n is part of the base n1 and p is the power (or exponent). p n n=1 The series converges based on how big the exponent p is: converges if p > 1, diverges if p ≤ 1. • p-series, • Geometric series, ∞ X arn−1 . The index n is part of the exponent, and the con- n=1 vergence of the series depends on the base r. Converges if |r| < 1, and diverges if |r| ≥ 1. Math 152 – Spring 2016 Example 4. Determine if the series Section 10.3 ∞ X 3 of 6 3n−3 is convergent or divergent. n=1 P P The Comparison Test. Suppose that an and bn are series with positive terms (i.e., an > 0 and bn > 0 for all n). X P bn is convergent and an ≤ bn for all n, then an is convergent. • If • If X bn is divergent and an ≥ bn for all n, then P an is divergent. Example 5. Determine if the following series are convergent or divergent. (a) ∞ X 8n + 3 4n2 − 3n n=1 (b) ∞ X 5n − 4 32n + 2n n=1 Math 152 – Spring 2016 Section 10.3 4 of 6 P P The Limit Comparison Test: Suppose that an and bn are series with positve terms. If an lim =c n→∞ bn where c is a finite number and c > 0, then either both series converge or both diverge. Example 6. Determine if the following series are convergent or divergent. (a) ∞ X 8n − 3 4n2 + 3n n=1 ∞ X 1 (b) sin n n=1 Hint: lim x→0 sin x = 1 (use L’Hospital or see p.181) x Math 152 – Spring 2016 Section 10.3 5 of 6 Question. Suppose we know that a series converges by the integral test, but we can not calculate its sum. How do we approximate the sum and give a margin of error for our approximation? Remainer Estimate for the Integral Test: If and Rn = s − sn , then Z ∞ Z f (x) dx ≤ Rn ≤ n+1 P an converges by the Integral Test ∞ f (x) dx n Example 7. (a) Approximate the sum of the series ∞ X 1 by using the sum of the n3 n=1 first 10 terms. (b) How many terms for the previous series are required to ensure that the sum is accurate to within 0.0005? Math 152 – Spring 2016 Section 10.3 Example 8. How many terms of the series 6 of 6 ∞ X 1 n=1 n(1 + ln n) 5 would you need to find the sum is accurate to within 0.001? Question. Does the previous theorem on remainders give a better estimate of the sum? What if we add sn to the above inequality? Theorem. If P an converges by the Integral Test, Rn = s − sn , and Z ∞ Z ∞ sn + f (x) dx ≤ s ≤ sn + f (x) dx n+1 P an = s, then n Example 9. Use this theorem with n = 10 to estimate the sum of the series ∞ X 1 . 3 n n=1