6. Integration 6.2 Substitution

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6. Integration

6.2 Substitution

To learn one of many powerful methods to computing more complicated indefinite integrals. Substitution method will often simplify the calculation.

Example 1.

Getting acquainted: Find the following indefinite integral

Z x

5

( x

6

+ 1)

3 d x

How

Based on the reverse chain rule.

Recall of chain rule:

Let u = g ( x ) = x

6

+ 1. Then, the differential of u d u =

So, d x =

Thus,

Z x

5

( x

6

+ 1)

3 d x

Check (by differentiation as we did in 6.1):

1

What

The Substitution Rule: Let u = g ( x ), we have

Z f ( g ( x )) g

0

( x ) d x =

Z f ( u ) d u, assuming that u = g ( x ) is a continuously differentiable function whose range is an interval on which f is continuous.

Trick

Choosing the right u in the integrand. It depends on the integral. Practice for gaining experience.

SOME PRACTICE. Finding the following indefinite integrals.

Example 2.

Z x ( x

2

+ 1)

2015 d x

Example 3.

Z x

2 + x 2 d x

2

Example 4.

Z x − 7

( x 2 − 14 x ) 2 d x

Example 5.

Z e x e x + 5 d x

Example 6.

Z xe x

2 d x

3

Example 7.

Z (ln x )

2 d x x

Example 8.

Z e x

4

+ e x

(4 x

3

+ e x

) d x,

Example 9.

Z x (1 − x

2

)

3 / 2 d x

4

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