The fractional transport equation: an analytical solution and a spectral approximation by Chebyshev polynomials Abdelouahab Kadem Abstract. In this paper, we show that the fractional transport equation can be reduced to a fractional linear differential equation system by using Chebyshev polynomials. We give the analytical solution of this system followed by the spectral approximation. M.S.C. 2000: 65D32, 82D75, 40A10, 41A50. Key words: Linear transport equation, isotropic scattering, Chebyshev spectral method, discrete-ordinates method. 1 Introduction The fractional derivatives technique has been widely employed for solving linear differential and integral equations, among them is cited the diffusion problems in curvilinear coordinates [7, 12]. In our recent work we have presented a new method for solving a steady fractional transport equation in two dimensional case using the orthogonal properties of Chebyshev polynomials and Walsh functions, in ordinary case a new approximation for solving the one dimensional transport equation analytically, have been reported where we are using the Chebyshev polynomials combined with the Sumudu transform [4]. The approach is based on expansion of the angular flux in a truncated series of Chebyshev polynomials in the angular variable. By replacing this development in the transport equation, this which will result a first-order linear differential system is solved for the spatial function coefficients by application of the Sumudu transform technique [11]. The inversion of the transformed coefficients is obtained using Trzaska’s method [10] and the Heaviside expansion technique. In order to obtain a new rule for the calculate the matrix exponential which arises in the formal solution of algebraic systems of differential equation without using the Sumudu transform and Trzaska’s method for solving the first-order fractional linear differential system, we fractionalize the one dimensional integro-differential equation and we try to convert it into a system of fractional differential equation (FDE). The main characteristic of using this technique is that reduces this problems to those of Applied Sciences, Vol.11, 2009, pp. 78-90. c Balkan Society of Geometers, Geometry Balkan Press 2009. ° The fractional transport equation 79 solving a system of algebraic equations, thus greatly simplifying the problem and making it computational plausible on the other hand that permit us to solve some of the particular cases and then we can check that the solution is close to the dynamics of some anomalous processes, the other aspect of this technique, it allows us to establish a fractional derivative which performs the same mapping of a given linear operator, it becomes to use the Riemann-Liouville definition for fractional derivatives and considerate the ordinary model and look that in the limit of some situations where the ordinary model do not work fine it is necessary to introduce such fractional operators in the model so we solve the problem. The paper has been organized as follows. Section 2 contains preliminaries, and Section 3 describes how to convert a transport equation into FDE in Section 4 we report a specification application of the method. Let us consider the following mono-energetic 3 − D transport equation: Z 1 (1.1) Ω.∇(r, Ω) + σt Ψ(r, Ω) = σs (Ω, Ω0 )Ψ(r, Ω0 )dΩ0 + Q(r) 4π 4π Ω = (η, ξ) (1.2) angular variable, and (1.3) σs (µ0 ) = ∞ X 2k + 1 k=0 4π σsk Pk (µ0 ) differential cattering cross section with µ0 = Ω.Ω0 and Pk = the k th Legendre polynomial. 2 Preliminaries We enlist some definitions and basic results [5, 6, 9] Definition 2.1. A real function f (x), x > 0 is said to be in the space Cα,α∈R if there exists a real number p(> α), such that f (x) = xp f1 (x) where f1 (x) = C [0, ∞) . Clearly Cα ⊂ Cβ if β ≤ α. Definition 2.2. A function f (x), x > 0 is said to be in space Cαm , m ∈ N ∪ {0} , if f(m) ∈ Cα . Definition 2.3. The (left sided) Riemann-Liouville fractional integral of order µ > 0, of a function f ∈ Cα , α ≥ 1 is defined as: Z t 1 µ (2.1) I f (t) = (t − τ )µ−1 f (τ )dτ, µ > 0, t > 0, Γ(µ) 0 I 0 f (t) = f (t) Definition 2.4. The (left sided) Riemann-Liouville fractional derivative m of f, f ∈ C−1 , m ∈ N ∪ {0} of order α > 0, is defined as: (2.2) Dµ f (t) = dm m−µ I f (t), m − 1 < µ ≤ m, m ∈ N. dtm 80 Abdelouahab Kadem Definition 2.5. The (left sided) Caputo fractional derivative of f, m f ∈ C−1 , m ∈ N ∪ {0} of order α > 0, is defined as: ½ £ m−µ (m) ¤ I f (t) , m − 1 < µ ≤ m, m ∈ N, (2.3) Dcµ f (t) = dm µ = m. dtm f (t) Note that (i) I µ tγ = Γ(γ+1) γ+µ , Γ(γ+µ+1) t P µ > 0, γ > −1, t > 0. k m−1 (k) (ii) I Dcµ f (t) = f (t) f (0+ ) tk! , m´− ³ − k=0 Pm−1 k (iii) Dcµ f (t) = Dµ f (t) − k=0 f (k) (0+ ) tk! , α−β µ 1 < µ ≤ m, m ∈ N. m − 1 < µ ≤ m, m ∈ N. f (t) if α > β, f (t) if α = β, β−α D f (t) if α < β, (v) Dcα Dm f (t) = Dα+m f (t), m = 0, 1, 2, ..., n − 1 < α < n. From here on, we will use Cγ ([a, b]) (γ ∈ R) to denote the Banach space © ª (2.4) Cγ ([a, b]) = g(x) ∈ C((a, b]) :k g kCγ =k (x − a)γ g(x) kC < ∞ . (iv) Dβ I α f (t) = I In particular, C0 ([a, b]) represents the space of continuous functions in [a, b], that is, C([a, b]). 3 Planar Geometry We consider a planar-geometry problem with spatial variation only in the x−direction: (3.1) Q(r) = q(x), (3.2) Ψ(r, Ω) = 1 Ψ(x, µ) 2π equation (1) simplifies to (3.3) ∂Ψ (x, µ) + σt Ψ(x, µ) = µ ∂x Z 1 σs (µ, µ0 )Ψ(x, µ0 )dµ0 + −1 q(x) , 2 with (3.4) σs (µ, µ0 ) = ∞ X 2k + 1 k=0 2 σsk Pk (µ)Pk (µ0 ). So we consider equation (3.3) with 0 ≤ x ≤ a and −1 ≤ µ ≤ 1, and subject to the boundary conditions (3.5) Ψ(x = 0, −µ) = f (µ), and (3.6) Ψ(x = a, µ) = 0, The fractional transport equation 81 where f (µ) is the prescribed incident flux at x = 0; Ψ(x, µ) is the angular flux in the µ direction; σt is the total cross section; σsl , with l = 0, 1, ..., L are the components of the differential scattering cross section, and Pk (µ) are the Legendre polynomials of degree k. Now we fractionalize the equation (3.3) with the same boundary conditions (3.5) and (3.6) (3.7) µ ∂β Ψ (x, µ) + σt Ψ(x, µ) = ∂xβ Z 1 σs (µ, µ0 )Ψ(x, µ0 )dµ0 + −1 q(x) , 2 with 0 < β ≤ 1. Theorem 3.1. Consider the integro−dif f erential equation (3.7) subject to the boundary conditions (3.5) and (3.6), then the f unction Ψ(x, µ) satisf y the f ollow f irst − order linear dif f erential equation system f or the spatial component Yn (x) N X n=0 1 αn,m Yn(β) (x) + L N X X σt π 2l + 1 q(x) 2 3 σsl αm,l αn,l Yn (x) + Ym (x) = 2 − δm,0 2 2 n=0 l=0 where Z 1 αn,m 1 Tm (µ) µTn (µ) p dµ, 1 − µ2 −1 Z 1 := Tn (µ)Pl (µ)dµ, := 2 αn,l Z 3 := αn,l −1 1 −1 Tn (µ)Pl (µ) p dµ, 1 − µ2 and Ym (x) are the coef f icients of the expansion of the Ψ(x, µ). To prepare for the proof of the theorem we need the following result Proposition 3.2. Let Tn+1 (x) − 2xTn (x) + Tn−1 (x) = 0 and Pl+1 (x) = 2xPl (x) − Pl−1 (x) − [xPl (x) − Pl−1 (x)] /(l + 1) the recurrence relations f or the Chebyshev and the Legendre polynomials respectively we have f or l > 2 and k = 2, 3 k αn,l+1 := ¤ 2l + 1 £ k l k αk αn+1,l + αn−1,l − 2l + 2 l + 1 n,j−1 3 2 assume the and αn,l Hence, in particular f or l = 0 and 1 the coef f icients αn,l values ½ 0 if n + l odd, 2 αn,l = 2 if n + l even, 2 2 (1+l) −n and 3 αn,l = πδn,l 2 − δl,0 82 Abdelouahab Kadem P roof . It easy to see that 1 αn,m = πδ|n−m| 2(2 − δn+m,1 ) For k = 2 by the multiplication of the Chebyshev and the Legendre recurrence formulas we have l 2l + 1 [Pl (µ)Tn+1 (µ) + Pl (µ)Tn−1 (µ)] − Pl−1 (µ) [Tn+1 (µ) + Tn−1 (µ)] 2l + 2 2µ (l + 1) it is known that Tn+1 (µ) + Tn−1 (µ) = 2µTn (µ) after doing some algebraic manipulations and integrating over µ ∈ [−1, 1] on the resulting equation we get 2 αn,l+1 = ¤ 2l + 1 £ 2 l 2 αn+1,l + αn−1,l − α2 2l + 2 l + 1 n,j−1 The case k = 3 is treated similarly but in this case we multiply the resulting expression by √ 1 2 and integrate over µ ∈ [−1, 1] we get the desired result. 1−µ Now we give a proof of Theorem 3.1. P roof . Expanding the angular flux in the µ variable in terms of the Chebyshev PN (x)Tn (µ) polynomials leads to Ψ(x, µ) = n=0 Yn√ with 2 1−µ N = 0, 2, 4, ..., where the expansions coefficients Yn (x) should be determined. Here Tn (µ) are the well known Chebyshev polynomials of order √ n which are orthogonal in the interval [−1, 1] with respect to the weight w(t) = 1/ 1 − t2 . After replacing this ansatz into equation (3.7) it turns out N n o T (µ) X n µYn(β) (x) + σt Yn (x) p = 1 − µ2 n=0 L X 2l + 1 (3.8) l=0 2 σsl Pl (µ) N X Z Yn (x) n=0 1 Tn (µ0 ) q(x) Pl (µ0 ) p dµ0 + 02 2 1−µ −1 using the orthogonality of the Chebyshev polynomials, multiply the equation (3.8) by Tm (µ), considering m = 0, 1, ..., N, and integrated in the µ variable in the interval [−1, 1] . Thus we get the following first-order linear differential equation system for the spatial component Yn (x) (3.9) N X n=0 1 αn,m Yn(β) (x) + L N X X 2l + 1 σt π q(x) 2 3 Ym (x) = σsl αm,l αn,l Yn (x) + 2 − δm,0 2 2 n=0 l=0 where Z (3.10) 1 αn,m = 1 Tm (µ) µTn (µ) p dµ, 1 − µ2 −1 The fractional transport equation 83 Z 2 αn,l (3.11) Tn (µ)Pl (µ)dµ, −1 Z 3 αn,l = (3.12) 1 = 1 −1 Tn (µ)Pl (µ) p dµ, 1 − µ2 2 3 with δn,m denoting the delta of Kronecker. Here the coefficients αn,l and αn,l are evaluated by the multiplication of the Chebyshev and Legendre recurrence formulas and integration of the resulting equation (See proposition 3.2). In the next step we solve the β-order linear differential equation system (3.9), we rewrite this equation in matrix form A.Y (β) (x) + BY (x) = C(x) (3.13) where Y (β) is the Caputo fractional derivative of order β, with 0 < β ≤ 1, Y (x) = Col. [Y0 (x), Y1 (x), ..., YN (x)] and A is a real square matrix of order N + 1, that is A ∈ MN +1 (R), and B ∈ C1−β ((0, x]), with the components 1 , (A)i,j = αi−1,j−1 (3.14) (3.15) (B)i,j = N L X X πσt 2l + 1 3 2 αj−1,l δi,j − σsl αi−1,l 2 − δ1,j 2 n=0 l=0 where each component of B belongs to space C1−β ((0, x]), and q(x) = Col. [C0 (x), C1 (x), ..., CN (x)] . 2 We rewrite the expression (3.14) as (3.16) C(x) = Y (β) (x) + A−1 BY (x) = A−1 C(x) (3.17) We notice that the general solution to (3.18) where A−1 B ∈ MN +1 (R), and A C ∈ C1−β ((0, x]), is given by [1] Z x A−1 B(x−ξ) −1 A−1 Bx (3.18) Y (x) = eβ H+ eβ A C(ξ)dξ, −1 0 where H is an arbitrary constant matrix, and the β-exponential function eA β defined by eβA (3.19) −1 Bx = xβ−1 ∞ X (A−1 B)k k=0 −1 −1 Bx is xkβ Γ [(k + 1)β] Moreover, it is easy to see that the function eβA B satisfies the following properties [1]: (i) If k A−1 B k= maxi,j | Ai,j Bi,j |, where Ai,j and Bi,j are the components of matrix A and B respectively then P∞ (k+1)β−1 −1 B k eA k ≤ k=0 k A−1 B kk xΓ[(k+1)β] (x > 0), β −1 Bx Kx eβ −1 Bx D β eA β (ii) eA β (A−1 B+K)x 6= eβ −1 (β 6= 1), Bx (iii) = (A−1 B)eA , β where A, B, K ∈ Mn (R) and β ∈ (0, 1] . 84 Abdelouahab Kadem 4 Specific application of the method Consider the two-dimensional linear steady state transport equation given by µ p ∂β ∂β Ψ(x, µ, φ) + 1 − µ2 cos φ β Ψ(x, µ, φ) + σt Ψ(x, µ, φ) β ∂x ∂y Z (4.1) Z 1 2π = 0 0 0 0 0 0 σs (µ , φ → µ, φ)Ψ(x, µ , φ )dφ dµ + S(x, µ, φ) −1 0 in the rectangular domain Ω = {x := (x, y): − 1 ≤ x ≤ 1, −1 ≤ y ≤ 1} , 0 < β ≤ 1, and the direction in D = {(µ, θ) : −1 ≤ µ ≤ 1, 0 ≤ θ ≤ 2π}. Here Ψ(x, µ, φ) is the angular flux, 0 0 σt and σs denote the total and the differential cross section, respectively, σs (µ , φ → 0 0 µ, φ) describes the scattering from an assumed pre-collision angular coordinates (µ , θ ) to a post-collision coordinates (µ, θ) and S is the source term. Given the functions f1 (y, µ, φ) and f2 (x, µ, φ), describing the incident flux, we seek for a solution of (4.1) subject to the following boundary conditions: For 0 ≤ θ ≤ 2π, let ( f1 (y, µ, φ), x = −1, 0 < µ ≤ 1, (4.2) Ψ(x = ±1, y, µ, θ) = 0, x = 1, −1 ≤ µ < 0. For −1 < µ < 1, let ( (4.3) Ψ(x, y = ±1, µ, θ) = f2 (y, µ, φ), y = −1, 0 < cos θ ≤ 1, 0, y = 1, −1 ≤ cos θ < 0. Theorem 4.1. Consider the integro − dif f erential equation (4.1) under the boundary conditions (4.2) and (4.3), then the f unction Ψ(x, µ, θ) satisf ies the f ollowing f irst − order f ractional linear dif f erential equation f or the spatial component Ψi (x) ∂β µ β Ψk (x, µ, θ) + σt Ψk (x, µ, θ) ∂x Z 1 Z 2π 0 0 0 0 0 0 σs (µ , φ → µ, φ)Ψk (x, µ , φ )dθ dµ + Gk (x, µ, θ) −1 0 P roof . Expanding the angular flux Ψ(x, µ, θ) in terms of the Chebyshev polynomials in the y variable, leads to (4.4) Ψ(x, µ, θ) = I X Ψi (x, µ, θ)Ti (y). i=0 Below we determine the first component, i.e., Ψ0 (x, µ, θ) explicitly, whereas the other components, Ψi (x, µ, θ), i = 1, ...I, will appear as the unknowns in I one dimensional The fractional transport equation 85 transport equations. We start to determine Ψ0 (x, µ, θ), by inserting (4.4) into the boundary conditions (4.3) at y = ±1, to find that: (4.5) Ψ0 (x, µ, θ) = f2 (x, µ, φ) − I X (−1)i Ψi (x, µ, θ), 0 < cos θ ≤ 1, i=1 (4.6) Ψ0 (x, µ, θ) = − I X Ψi (x, µ, θ), −1 ≤ cos θ < 0. i=1 where −1 ≤ x ≤ 1, −1 < µ < 1, and we have used the fact that for the Chebyshev polynomials T0 (x) ≡ 0, Ti (1) ≡ 1 and Ti (−1) ≡ (−1)i . If we now insert Ψ from (4.4) into (4.1), multiply the resulting equation by √Tk (y)2 , 1−y k = 1, ..., I, and integrate over y we find that the components Ψk (x, µ, θ), k = 1, ..., I, satisfy the following I one-dimensional equations: µ Z Z 1 (4.7) 2π ∂β Ψk (x, µ, θ) + σt Ψk (x, µ, θ) ∂xβ 0 0 0 0 0 0 σs (µ , φ → µ, φ)Ψk (x, µ , φ )dθ dµ + Gk (x, µ, θ) −1 0 The same procedure with the boundary condition (4.2) at x = −1, and (4.4) yields (4.8) Ψ(−1, y, µ, θ) = f1 (y, µ, φ) = I X Ψi (−1, µ, θ)Ti (y). i=0 Now multiply (4.8) by √Tk (y)2 , k = 1, ..., I, and integrate over y we find that 1−y (4.9) Ψk (−1, µ, θ) = 2 π Z 1 Tk (y) dy. f1 (y; µ, θ) p 1 − y2 −1 Similarly, (note the sign of µ below), the boundary condition at x = 1 is written as (4.10) I X Ψi (1, −µ, θ)Ti (y) = 0 0 < µ ≤ 1. i=0 Multiplying (4.10) by √Tk (y)2 , k = 1, ..., I and integrating over y, we get 1−y (4.11) Ψk (1, −µ, θ) = 0, 0 < µ ≤ 1, 0 ≤ θ ≤ 2π. We can easily check that Gk in (4.7) is written as (4.12) Gk (x, µ, θ) = Sk (x, µ, θ) − p 1 − µ2 cos θ I X i=k+1 Aki Ψk (x, µ, θ) 86 Abdelouahab Kadem where Aki (4.13) 2 = π Z 1 d Tk (y) (Ti (y)) p dy dy 1 − y2 −1 and (4.14) 2 Sk (x, µ, θ) = π Z 1 Tk (y) S(x, y, µ, θ) p dy. 1 − y2 −1 Note that the solutions to the one-dimensional problems given through the equation (4.7)-(4.14) define the components Ψk (x, µ, θ), for k = 1, ..., I, in this decreasing order to avoid the coupling of the equations. Once this is done, the angular PIflux given by (4.4) is completely determined. Here we have used the convention i=I+1 ... = 0. Hence the starting GI (x, µ, θ) ≡ SI (x, µ, θ). Note also that although the solution, developed in here, rely on specific boundary conditions the procedure is quite general in the sense that the expression for the first component, Ψ0 (x, µ, θ), keeps the information from the boundary conditions in the y variable, while the other components are derived based on the boundary conditions in x. Now consider the corresponding discrete ordinates equation [3] µm (4.15) ∂ β Ψα (x, µm , φm ) + σt Ψα (x, µm , φm ) = ∂β x M X ωn Ψα (x, µm , φm ) + Gk (x; µm , φm ) n=1 Theorem 4.2. Let 0 < β ≤ 1, Consider the f ractional integro − dif f erential equation (4.15), then the f unction Ψα (x, µm , φm ) satisf ies the f ollowing f irst − order f ractional linear dif f erential equation f or the spatial component χk I J M p X X X ∂ β χm µm Aα Bjα sin φm χm 1 − µ2m + σt − i cos φm − ∂xβ m=0 i=α+1 j=α+1 π = 2 Z 1 Sα (x, µm , φm )Tl (µm )dµm . −1 Here χk are the coef f icients of the expansion of the Ψα (x, µm , φm ). P roof . We expand Ψα (x, µm , φm ) in a truncated series of Chebyshev polynomials i.e. (4.16) Ψα (x, µm , φm ) = M X χk (x, φm )Tk (µm ) p 1 − µ2m k=0 bringing the equation (4.16) in equation (4.15) to get "M # "M # X χk (x, φm )Tk (µm ) ∂ β X χk (x, φm )Tk (µm ) p p µm β + σt = ∂x 1 − µ2m 1 − µ2m k=0 k=0 The fractional transport equation M X (4.17) " ωn n=1 87 # M X χk (x, φm )Tk (µm ) p + Gα (x; µm , ηm ) 1 − µ2m k=0 with Gα (x; µm , ηm ) = Sα (x, µ, φ) − (4.18) p 1 − µ2 M J M X X X χk (x, φm )Tk (µm ) χk (x, φm )Tk (µm ) p p × cos φ Aα + sin φ , Bjα i 2 1 − µ 1 − µ2m m α=i+1 α=j+1 k=0 k=0 I X multiply the equation (4.17) par Tl (µm ) and integrate over µm ∈ [−1, 1] we find µm Z 1 Z 1 M M X ∂β X Tk (µm )Tl (µm ) Tk (µm )Tl (µm ) p p χ (x, φ ) dµ +σ χ (x, φ ) dµm = k m m t k m 2 ∂xβ 1 − µ 1 − µ2m −1 −1 m k=0 k=0 (4.19) M X ωn n=0 M X Z 1 Tk (µm )Tl (µm ) p dµm + 1 − µ2m χk (x, φm ) −1 k=0 Z 1 Gα (x; µm , ηm )Tl (µm )dµm −1 with Z Z 1 1 Gα (x; µm , ηm )Tl (µm )dµm = Sα (x, µm , φm )Tl (µm )dµm −cos φm −1 −1 × M X Z 1 Ck (x, φm ) −1 k=0 (4.20) × M X p 1 − µ2m i=α+1 J X p Tk (µm )Tl (µm ) p Bjα dµm + sin φm 1 − µ2m 1 − µ2m j=α+1 Z 1 χk (x, φm ) −1 k=0 Tk (µm )Tl (µm ) p dµm 1 − µ2m where Aα i (4.21) 2 = π Bjα = (4.22) 2 π Z 1 −1 Z 1 −1 Z 1 −1 Z 1 −1 Ti (y) d (Tα (y)) p Tl (µm )dydµm dy 1 − y2 Tj (z) d (Tα (z)) √ Tl (µm )dzdµm dz 1 − z2 by using the properties of Chebyshev polynomials to equation (4.20) to get Z 1 Gα (x; µm , ηm )Tl (µm )dµm = −1 Z 1 Sα (x, µm , φm )Tl (µm )dµm − −1 I X hπp 2 i 1 − µ2m χk (x, φm ) Aα i 88 Abdelouahab Kadem × (4.23) I X J X Aα i cos φm + i=α+1 Bjα sin φm j=α+1 then the equation (4.15) becomes M I J X X X p ∂ β χm µm + σt − 1 − µ2m Aα Bjα sin φm χm i cos φm − ∂xβ m=0 i=α+1 j=α+1 (4.24) = π 2 Z 1 Sα (x, µm , φm )Tl (µm )dµm . −1 after written in vector and matrix notation and regrouping the coefficients χm together in equation (4.24), we can derive the following differential equation ∂ β χm + DCm = Em ∂xβ (4.25) where Dm = 1 µm Bm (4.26) and Em = Am := π 2 1 µm Am Z with 1 Sα (x, µm , φm )Tl (µm )dµm −1 J I M X X X p Bjα sin φm Aα := σt − 1 − µ2m i cos φm − (4.27) Bm m=0 i=α+1 j=α+1 the solution of differential equation for the vector χm is thus constructed as follows [1] Z x −(x−ξ)D (4.28) χm (x) = e−Dx χ (0) + eβ Em (ξ)dξ m β 0 where (4.29) β−1 eDx β =x ∞ X Dk k=0 xkβ Γ [(k + 1)β] equation (4.28) depend on vector χm (0). Having established an analytical formulation for the exponential appearing in equation (4.29), the unknown components of vector χm (0) for the boundary problem (4.1) can be readily obtained applying the boundary conditions (4.2), (4.3) and (4.4). 5 Study of the spectral approximation Now we expand (5.1) Ψα,N (x, φm ) = (N ) X m=0 ) χ(N m cos(mφm ) The fractional transport equation 89 (N ) where χm is the approximation to the coefficient χm by the consideration of the truncated series Ψα,N . From spectral analysis, we know that when a function is infinitely smooth and all its derivatives exist, then the coefficients appearing in its sine or cosine series go to zero faster than 1/n. Moreover, if the function and all its derivatives are periodic, then the decay is faster than any power of 1/n. However, as indicated by Canuto. (1988) [2], in practice this decay cannot be observed before enough coefficients that represent the essential structures of the function are considered. In the calculation, one can test the convergence of the cosine truncated series defined in equation (5.1) by evaluating · ¸ | ΨN +1 (k) − ΨN (k) | (5.2) sup ≤² ΨN (k) k where ² is the required precision. In general, the few first coefficients of the series are enough to generate the angular flux. If N is the chosen value, we can write ) χ(N m =0 (5.3) for all n > N, Combining therefore equations (5.3) and (4.28) we shall now describe the necessary (N ) algorithm to obtain all the cosine coefficients χm Step 0: N = 0; for n = N = 0 Z x (0) −D(x−s) −Dx (0) (5.4) χ0 (x) = eβ χ0 (0) − eβ A0 (x)dx, 0 with Z (5.5) 1 A0 := π Sα (x, µ0 , φ0 )Tl (µ0 )dµ0 −1 (0) which is well known, and thus χ0 (x) is completely determined. To finish the step, we apply equation (5.1) to obtain the first approximation to the angular flux, i.e., Ψ0 . Step 1: N = 1; for n = 0, Z x (1) (1) (0) − (5.6) χ0 (x) = e−Dx C e−D(x−s) A1 (x)dx, 0 β 0 with (5.7) A1 := π 2 Z 1 Sα (x, µ1 , φ1 )Tl (µ1 )dµ1 −1 Step 2: for n = 1 Z (5.8) (1) (1) χ1 (x) = e−Dx χ1 (0) − β 0 x D(x−s) eβ A1 (x)dx, with (5.9) A1 := π 2 Z 1 Sα (x, µ1 , φ1 )Tl (µ1 )dµ1 −1 90 Abdelouahab Kadem (0) Bringing the approximated solution for χ0 obtained at step 0 inside equation (5.8) and iterating with equation (5.4), we obtain immediately the approximated coeffi(1) (1) cients χ0 and χ1 . To finish the step, we evaluate through equation (5.1) the new approximation Ψ1 and perform the precision condition defined in equation (5.2). If equation is verified, the calculation is stopped; if not, we go to step 2 and to likewise until the convergence condition in equation (5.2) is fulfilled. 6 Conclusions and future work In this paper, we have shown that we can reduce a fractional transport equation. 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Author’s address: Abdelouahab Kadem L.M.F.N Mathematics Department, University of Setif, Algeria. E-mail: abdelouahabk@yahoo.fr