128 (2003) MATHEMATICA BOHEMICA No. 3, 309–317 OSCILLATION OF A NONLINEAR DIFFERENCE EQUATION WITH SEVERAL DELAYS , , , Xiangtan (Received June 10, 2002) Abstract. In this paper we consider the nonlinear difference equation with several delays (axn+1 + bxn )k − (cxn )k + m pi (n)xkn−σi = 0 i=1 where a, b, c ∈ (0, ∞), k = q/r, q, r are positive odd integers, m, σi are positive integers, {pi (n)}, i = 1, 2, . . . , m, is a real sequence with pi (n) > 0 for all large n, and lim inf pi (n) = n→∞ pi < ∞, i = 1, 2, . . . , m. Some sufficient conditions for the oscillation of all solutions of the above equation are obtained. Keywords: nonlinear difference equtions, oscillation, eventually positive solutions, characteristic equation MSC 2000 : 39A10 1. Introduction Consider the nonlinear difference equation (1) (axn+1 + bxn )k − (cxn )k + m X pi (n)xkn−σi = 0 i=1 where a, b, c ∈ (0, ∞), c > b, k = q/r, q, r are positive odd integers, m, σi are positive integers, {pi (n)} are real sequences with pi (n) > 0 for all large n, and lim inf pi (n) = n→∞ Project supported by Hunan Provincial Natural Science Foundation of China (02JJY2003) and Research Fund of Hunan Provincial Education Department (01B003). 309 pi < ∞, i = 1, 2, . . . , m. It is easy to see that if c < b then (1) cannot have an eventually positive solution. The corresponding “limiting” equation of (1) is k (2) k (axn+1 + bxn ) − (cxn ) + m X pi xkn−σi = 0 i=1 with the characteristic equation k (3) k (aλ + b) − c + m X pi λ−kσi = 0. i=1 For the special case where k = a = 1, c = b + 1, equation (1) reduces to the linear difference equation m X xn+1 − xn + pi (n)xn−σi = 0. i=1 There have been a lot of activities concerning the oscillation of solutions of linear difference equations. But there have been few results for the oscillation of solutions of the nonlinear equation (1). Under the condition that 0 < c−b a 6 1, a sufficient condition of nonexistence of eventually positive solutions for (1) was obtained in [5], [6]. In this paper we obtain several new sufficient conditions for oscillation of all solutions of (1) by removing the condition c−b a 6 1. A sufficient and necessary condition for oscillation of all solutions of (2) is obtained as well. A solution {xn } of equation (1) is said to oscillate about zero or simply to oscillate if the terms xn of the sequence {xn } are neither eventually all positive nor eventually all negative. Otherwise, the solution is called nonoscillatory. 2. Main results Lemma 1 [3]. If x, y are positive numbers and x 6= y, then rxr−1 (x − y) > xr − y r > ry r−1 (x − y) for r > 1. Theorem 1. If (3) has no positive roots, then every solution of (1) oscillates. . By way of contradiction, assume that {xn } is an eventually positive solution of (1). By (1) we have (4) 310 xn+1 a +b xn k m X xn−σi −c + pi (n) xn i=1 k k = 0. For sufficiently large n, set xn+1 xn = βn . Then eventually 0 < βn 6 c−b , a and (4) yields k (5) k (aβn + b) − c + m X pi (n) Y σi −1 βn−j j=1 i=1 k = 0. Set lim sup βn = β. n→∞ It follows from (5) that 0 < β 6 c−b a . We also claim that (aβ + b)k − ck + m X pi β −kσi 6 0. i=1 Indeed, by virtue of lim inf pi (n) = pi < ∞, for every ε ∈ (0, 1) there exists an nε > 0 n→∞ such that pi (n) > (1 − ε)pi for i = 1, 2, . . . , m and n > nε . Therefore, (aβn + b)k − ck + (1 − ε) m X pi i=1 Y σi j=1 −1 βn−j k 6 0 for n > nε . Let Nε > nε be such that βn < (1 + ε)β for n > Nε . Then (aβn + b)k − ck + (1 − ε) m X pi (1 + ε)−kσi β −kσi 6 0 for n > Nε + σi , i=1 i.e., (aβn + b)k 6 ck − (1 − ε) m X pi (1 + ε)−kσi β −kσi , i=1 which implies (aβ + b)k 6 ck − (1 − ε) m X pi (1 + ε)−kσi β −kσi . i=1 311 As this is true for every ε ∈ (0, 1), it follows that (aβ + b)k 6 ck − (6) m X pi β −kσi , i=1 which proves our claim. Set F (λ) = (aλ + b)k − ck + (7) m X pi λ−kσi . i=1 Then F (0+) = +∞ and F (β) 6 0. It follows that (3) has a positive root. This contradiction completes the proof. Corollary 1. Every solution of (2) oscillates if and only if (3) has no positive roots. . Sufficiency can be directly derived from Theorem 1. So it suffices to prove Necessity. Suppose that (3) has a positive root λ. Let xn = λn , n = 1, 2, . . . . Then we have (axn+1 + bxn )k − (cxn )k + m X i=1 m X pi xkn−σi = λkn (aλ + b)k − ck + pi λ−kσi = 0. i=1 Hence, {xn } is an eventually positive solution of (2). This contradiction completes the proof. Corollary 2. Assume that lim inf pi (n) = pi < ∞, i = 1, 2, . . . , m, k > 1, and n→∞ that m X pi akσi (kσi + 1)kσi +1 > 1. kck−1 (c − b)kσi +1 (kσi )kσi i=1 Then every solution of (1) oscillates. . Let F (λ) = (aλ + b)k − ck + m X pi λ−kσi . i=1 Then F (λ) > 0 for λ > 312 c−b . a For λ < c−b a , by Lemma 1, we have k k F (λ) > {c − (aλ + b) } − 1 + Since min 0<λ< c−b a m X i=1 λ−kσi k−1 kc (c − aλ − b) = pi λ−kσi . kck−1 (c − aλ − b) akσi (kσi + 1)kσi +1 , − b)kσi +1 (kσ i )kσi kck−1 (c by the condition of Corollary 2 we get k k F (λ) > {c −(aλ+b) } −1+ m X i=1 pi akσi (kσi + 1)kσi +1 kck−1 (c − b)kσi +1 (kσ i )kσi > 0 for λ < c−b . a By Theorem 1, every solution of (1) oscillates. The proof is completed. Define a sequence {λl } by (8) 1 c−b , λl+1 = a a λ1 = ck − m X i pi λ−kσ l i=1 k1 − b , l = 1, 2, . . . Lemma 2. Suppose that {λl } is defined by (8). Then 0 < λ∗ 6 λl 6 lim λl = λ∗ , where λ∗ is the largest root of equation (3) on (0, c−b a ]. c−b a and l→∞ . First, we prove the sequence {λl } is nonincreasing. Since λ2 = 1 a ck − m X i pi λ−kσ 1 i=1 k1 c−b −b < = λ1 , a hence, by induction, supposing that λl 6 λl−1 , we have λl+1 1 = a k c − m X i pi λ−kσ l i=1 k1 1 −b 6 a k c − m X i pi λ−kσ l−1 i=1 k1 − b = λl . Hence, the sequence {λl } is nonincreasing. From (3) it is obvious that λ1 > λ∗ , and by induction λl+1 1 = a k c − m X i=1 i pi λ−kσ l k1 1 −b > a k c − m X i pi λ−kσ ∗ i=1 k1 − b = λ∗ . Hence, {λl } is nonincreasing and bounded. Therefore, lim λl exists. Letting l → ∞ l→∞ in (8) and noting that λ∗ is the largest root of (3), we conclude lim λl = λ∗ . The proof is completed. l→∞ 313 Theorem 2. Assume that (3) has positive roots, λ∗ is the largest root of (3) and (9) lim sup n→∞ a 1 k k X m m X 1 k(1−σi ) −kσi > ck . p (n + 1)λ p (n)λ + b + i ∗ i ∗ ck − bk i=1 i=1 Then every solution of (1) oscillates. . Suppose that {xn } is an eventually positive solution of (1). Then there exists n1 > 0 such that xn > 0 and xn−σi > 0, i = 1, 2, . . . , m, for n > n1 . From (1) we have m X (axn+1 + bxn )k − (cxn )k = − pi (n)xkn−σi 6 0, i=1 i.e., (axn+1 + bxn )k 6 (cxn )k . Since k = q/r, q, r are positive odd integers, we have (10) where θ = xn+1 6 θxn c−b a . for n > n1 , By virtue of lim inf pi (n) = pi < ∞, for every ε ∈ (0, 1) there exists n→∞ an nε > n1 such that (11) pi (n) > (1 − ε)pi for i = 1, 2, . . . , m and n > nε . Define a sequence {µl (ε)} by 1 µ1 (ε) = θ, µl+1 (ε) = a k c − (1 − ε) m X pi (µl (ε)) −kσi i=1 k1 − b , l = 1, 2, . . . . From (10) we get xkn−σi > (µ1 (ε))−kσi xkn (12) for n > nε + σi . From (1), (11), and (12) we have (axn+1 + bxn )k 6 (cxn )k − (1 − ε) m X pi (µ1 (ε))−kσi xkn , i=1 i.e., xn+1 314 1 6 a k c − (1 − ε) m X i=1 pi (µ1 (ε)) −kσi k1 − b xn . That is xn+1 6 µ2 (ε)xn , n > nε + σi , which gives xn 6 µ2 (ε)xn−1 6 (µ2 (ε))2 xn−2 6 . . . 6 (µ2 (ε))σi xn−σi , n > nε + 2σi , i.e., xn−σi > (µ2 (ε))−σi xn . Repeating the above process, we obtain xn+1 6 1 a ck − m X pi (µl−1 (ε))−kσi i=1 k1 − b xn , i.e., (13) xn+1 6 µl (ε)xn , n > nε + (l − 1)σi . Since lim µl (ε) = λl and lim λl = λ∗ , for a sequence {εl } with εl > 0 and εl → 0 as ε→0 l→∞ l → ∞, by (13) there exists a sequence {nl } such that nl → ∞ as l → ∞ and (14) xn+1 6 (λ∗ + εl )xn , n > nl , and (15) xn−σi > (λ∗ + εl )−σi xn , n > nl + σi . On the other hand, from (1) we have (bk − ck )xkn + m X pi (n)xkn−σi 6 0, i=1 i.e., (16) (ck − bk )xkn > m X pi (n)xkn−σi . i=1 From (15) and (16) we obtain (ck − bk )xkn > m X pi (n)(λ∗ + εl )k(1−σi ) xkn−1 , i=1 315 i.e., k1 m X xn 1 k(1−σi ) p (n)(λ + ε ) , n > n l + σi . > k i ∗ l xn−1 c − bk i=1 (17) From (1) we have ck = (18) axn+1 + bxn xn k + m X i=1 pi (n) xkn−σi . xkn From (15), (17) and (18) we obtain c > a k (19) 1 k k m X 1 k(1−σi ) p (n + 1)(λ + ε ) + b i ∗ l ck − bk i=1 m X + pi (n)(λ∗ + εl )−kσi . i=1 Let l → ∞, then (19) implies lim sup a n→∞ 1 k k X m m X 1 k(1−σi ) −kσi pi (n)λ∗ 6 ck , +b + pi (n + 1)λ∗ ck − bk i=1 i=1 which contradicts (9) and completes the proof. "! 1. Theorems 1 and 2 extend the results on linear difference equations in [2], [9]. # $%'&)(* 1. Consider equation (1). Let 4 3 , p1 (1) = , p1 (n + 2) = p1 (n) for n = 0, 1, 2, . . . , 3 4 3 1 p2 (0) = , p2 (1) = , p2 (n + 2) = p2 (n) for n = 0, 1, 2, . . . , 4 2 k = 3, a = 1, b = 1, c = 2, σ1 = 1, σ2 = 2, m = 2. p1 (0) = Then lim inf p1 (n) = n→∞ and 2 X i=1 3 1 , lim inf p2 (n) = , n→∞ 4 2 pi akσi (kσi + 1)kσi +1 = 1.32 . . . > 1. kck−1 (c − b)kσi +1 (kσi )kσi Thus according to Corollary 2, every solution of (1) oscillates. 316 # $%'&)(* 2. Consider equation (1). Let p1 (0) = 1, p1 (1) = 7, p1 (n + 2) = p1 (n) for n = 0, 1, 2, . . . , k = 3, a = 1, b = 1, c = 2, σ1 = 1, m = 1. Then lim inf p1 (n) = 1. n→∞ Hence, the characteristic equation (3) has the largest root λ∗ = 0.8586. Therefore, lim sup a n→∞ 1 k X k m m X 1 k(1−σi ) −kσi + b + p (n)λ = 9.5799 > 8. p (n + 1)λ i i ∗ ∗ ck − bk i=1 i=1 Thus according to Theorem 2, every solution of (1) oscillates. +-, .)0/1(*02"3'.4 . The authors thank the referee for useful comments and suggestions. References [1] R. P. Agarwal, P. J. Y. 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