Page 1 Math 151-copyright Joe Kahlig, 09B 1. (6 points) Given m = h2, 7i and n = h1, 10i. Find the vector projection of n onto m 2. (6 points) Find a vector equation of the line thru the points (1, 7) and (3, 12) 3. (15 points) A pilot wishes to set a course so that his ground speed is northeast(N45o E) at 180 mph. the wind is blowing in the direction of S30o E at 40 mph. What course (speed and bearing) should the pilot set in order to achieve his desired ground speed? Check the back of the page for more problems. Page 2 Math 151-copyright Joe Kahlig, 09B 4. (16 points) Find the derivatives for the following. Assume that g(x) is a differentiable function. DO NOT SIMPLIFY YOUR ANSWER. √ 1 5 (a) f (x) = x2 x2 + 4 5x (b) h(x) = (x4 + 3x + 7)g(x) 5. (9 points) Find the equation of the tangent line at x = 2 for the function f (x) = x3 + 1 . x+8 6. (8 points) Determine the values of x where the function is not continuous. For each of these numbers state whether f is continuous from the right, or from the left, or neither. 6 5 4 3 2 1 −7 −6 −5 −4 −3 −2 −1 −1 1 2 3 4 5 6 7 8 9 10 11 12 −2 −3 −4 Check the back of the page for more problems. Page 3 Math 151-copyright Joe Kahlig, 09B 7. (8 points) Let r(t) =< t3 + t + 1, t2 − 9 >. Find a tangent vector(s) at the point (11, −5). 8. (20 points) Find the exact values of the following limits. (continued on the next page) 2x2 − 7x + 3 = x→3 x2 − 9 (a) lim (b) x4 + 3x = x→−∞ 4 − x2 lim √ x + 2x2 + 1 (c) lim = x→−∞ 4x + 1 Check the back of the page for more problems. Page 4 Math 151-copyright Joe Kahlig, 09B (d) lim x→2 1 4 − 2 x−2 x −4 = 9. (6 points) For what value(s) of c and m that will make the function f (x) be differentiable everywhere. If this can not be done, then explain why. Fully justify your answers. x2 for x < 3 f (x) = cx + m for x ≥ 3 Check the back of the page for more problems. Page 5 Math 151-copyright Joe Kahlig, 09B 10. (6 points) Use the definition of the derivative to show that the derivative of f (x) = x2 + 5x is f ′ (x) = 2x + 5. Check the back of the page for more problems.