c Math 151, Benjamin Aurispa 4.1 Exponential Functions Exponential functions are those of the form f (x) = ax where a > 0, a 6= 1. Case 1: f (x) = ax where a > 1 Case 2: f (x) = ax where 0 < a < 1 Increasing Exponential/Exponential Growth Decreasing Exponential/Exponential Decay Domain: (−∞, ∞) Domain: (−∞, ∞) Range: (0, ∞) Range: (0, ∞) y-intercept: (0, 1) y-intercept: (0, 1) VA: None VA: None HA: y = 0 HA: y = 0 lim f (x) = x→∞ lim f (x) = x→−∞ lim f (x) = x→∞ lim f (x) = x→−∞ Consider exponentials of the form f (x) = a−x . f (x) = 2−x f (x) = −x Consider f (x) = ex where the base is the natural number e. 1 1 3 c Math 151, Benjamin Aurispa Recall the rules of exponents: (1) ax ay = ax+y (2) ax = ax−y ay (3) (ax )y = axy (4) (ab)x = ax bx NOTE: (a + b)x 6= ax + bx – DO NOT DO THIS! Calculate the following limits: lim 0.3−x lim 0.3−x x→∞ lim x→−3+ 3 2 x→−∞ x x+3 = lim x→−3− 3 2 x x+3 = 4 + 3ex x→−∞ 3 + e−x 5 + (0.1)x x→∞ 2 + e−x 3e2x + e−3x x→∞ e2x − 4e−3x 3e2x + e−3x x→−∞ e2x − 4e−3x lim lim lim lim 2 (5) x a b = ax bx c Math 151, Benjamin Aurispa Derivatives of Exponentials: d x e = ex dx d g(x) e = g′ (x)eg(x) dx Calculate the following derivatives: f ′ (x) where f (x) = ex sin x + x2 e3x + f ′ (x) where f (x) = 1 e + cos(ex ) + xe + e−5x 1 + e−2x f (n) (x) where f (x) = xex 3 √ e2x + 1 c Math 151, Benjamin Aurispa √ Find an equation of the tangent line to the curve y = x2 e x when x = 4. Find the slope of the tangent line to the curve 4exy − ex = y at the point (0, 3). For what values of r does the function f (x) = e−rx satisfy the differential equation: 2y ′′ + 3y ′ − 2y = 0. 4 c Math 151, Benjamin Aurispa 4.2 Inverse Functions A function is one-to-one if every element in the domain has a UNIQUE value in the range. In other words, if f (x1 ) = f (x2 ), then it MUST be true that x1 = x2 if the function is one-to-one. Show that the function f (x) = x x−2 is one-to-one. Horizontal Line Test: Graphically, a function is one-to-one if no horizontal line intersects its graph more than once. If a function f is one-to-one, then it has an inverse f −1 defined by: f −1 (y) = x ⇔ f (x) = y If f has domain A and range B, then f −1 has domain B and range A. If (a, b) is on the graph of f , then (b, a) is on the graph of f −1 . 5 c Math 151, Benjamin Aurispa The graph of f −1 is obtained by reflecting the graph of f about the line y = x. If f is a continuous function defined on an interval, then f −1 is also a continuous function. Cancellation Equations: If x is in the domain of f and y is in the range of f , then f −1 (f (x)) = x and f (f −1 (y)) = y Find the inverse of the function f (x) = √ Find the inverse of the function f (x) = 4x + 3 . x−2 2x + 6 and state its domain and range. 6 c Math 151, Benjamin Aurispa If f is a one-to-one differentiable function with inverse g = f −1 , then g is also differentiable and g′ (a) = 1 f ′ (g(a)) provided that f ′ (g(a)) 6= 0. Suppose f (x) = 3x5 + 2x3 − 3. Find g ′ (2) where g is the inverse of f . Suppose f (x) = 4 + 2x + ex . Find g ′ (5) where g is the inverse of f . 7 c Math 151, Benjamin Aurispa 4.3 Logarithmic Functions We’ve dealt with exponential functions and we know that the graph of an exponential function of the form f (x) = ax is one-to-one, which means it must have an inverse. The inverse of the exponential function f (x) = ax is the logarithmic function with base a. loga x = y ⇔ ay = x In words, loga x is the EXPONENT to which a must be raised to get x. Evaluate the following: (1) log2 32 (2) log3 (4)log a 1 1 81 (5) Find x such that log4 x = −3 f (x) = ax , a > 1 f (x) = loga x, a > 1 Domain: (−∞, ∞) Domain: Range: (0, ∞) Range: Asymptotes: y = 0 Asymptotes: Intercepts: (0, 1) Intercepts: lim ax = ∞ x→∞ lim ax = 0 x→−∞ (3) log49 7 lim loga x = x→∞ lim loga x = x→0+ 8 c Math 151, Benjamin Aurispa Cancellation equations: aloga x = x for x > 0 loga (ax ) = x for all x The common logarithm is the logarithmic function with base 10. log10 x = log x The natural logarithm is the logarithmic function with base e. It has special notation. loge x = ln x ln x = y ⇔ ey = x ln e = 1 ln(ex ) = x eln x = x, x > 0 Calculate the following limits: (1) lim+ log3 (x − 5) x→5 (2) limπ ln(sin x) x→ 2 1 ) (3) lim− log( 3−x x→3 Properties of Logarithms: (1) loga (xy) = loga x + loga y (2) loga x y = loga x − loga y (3) loga (xy ) = y loga x IMPORTANT: loga (x + y) 6= loga x + logb y – DO NOT DO THIS Examples: (1) (# 12, 4.4) Evaluate log5 10 + log5 20 − 3 log5 2 9 c Math 151, Benjamin Aurispa (2) Express 1 2 ln x + b ln y − c ln z − ln(x2 + 1) as a single logarithm. (3) Calculate lim [ln(3x2 + x) − ln(2x2 − x)] x→∞ (4) Solve the equation 4log4 6 + ln(4x − 2) = 15 for x. (5) Solve the equation log(x − 7) + log(x + 2) = 1 for x. 10 c Math 151, Benjamin Aurispa (6) Solve the equation 32x−9 − 5 = 0 for x. (7) Find the inverse of the function f (x) = 2e3x−1 1 + e3x−1 (8) Find the domain of y = log(x2 − 4). 11 c Math 151, Benjamin Aurispa ln x ln a Example: Calculate log7 12 correct to 6 decimal places. Change of Base: loga x = 4.4 Derivatives of Logarithmic Functions • d 1 ln x = dx x • d 1 ln |x| = dx x • Chain Rule Version: • d g′ (x) ln(g(x)) = dx g(x) 1 1 1 d loga x = · = dx ln a x x ln a • Chain Rule Version: d g′ (x) loga (g(x)) = dx g(x) ln a Examples: Find the derivatives of the following functions. √ (1) f (x) = ln(3x2 + x) (2) g(x) = log2 (x4 − 5x) (3) h(x) = x ln(cos x) 12 c Math 151, Benjamin Aurispa (4) f (x) = p ln(x + ln x) t2 − 4 t3 − 7t (5) g(t) = log ! Now we have the ability to differentiate exponential functions where the base is not e. • d x a = ax ln a dx • Chain Rule Version: d g(x) a = ag(x) (ln a)g′ (x) dx Examples: Differentiate the following functions. (1) f (x) = x3 5x (2) h(θ) = 4ln(θ 2 −7x 2 +1) 13 c Math 151, Benjamin Aurispa Logarithmic Differentiation: Sometimes it is easier to differentiate a function by first taking the logarithm of both sides, differentiating implicitly and then solving for y ′ . Use this method when: (1) The function is a quotient or product of a lot of terms. – Log. Diff. recommended, but not necessary. (2) The function is of the form y = f (x)g(x) . – Logarithmic Differentiation NECESSARY. √ e2x x5 + 2 ′ . Find f (x) for f (x) = (x − 1)4 (x2 + 9)2 Find f ′ (x) for f (x) = xcos x . Find y ′ for y = (sin x)e . x 14