c Dr Oksana Shatalov, Fall 2012 1 Fall 2012 Math 152 Week in Review 6 courtesy: Oksana Shatalov (covering Section 9.3, 9.4 &10.1 ) 9.3: Arc Length Key Points Z • Arc length of curve C: Z • Z β s ds = α Z • Z dx dt s b ds = 2 1+ a Z • Z d s 1+ ds = c ds + dy dx 2 dx dy 2 dy dt 2 dt when C is given by x = x(t), y = y(t), α ≤ t ≤ β; dx when C is given by y = y(x), a ≤ x ≤ b; dy when C is given by x = x(y), c ≤ x ≤ d. Examples 1. Find the length of the curve x = cos3 t, y = sin3 t, 0 ≤ t ≤ π/2. 2. Find the length of the curve x = 41 ln y − 12 y 2 from y = 1 to y = e. 3. A wire hanging between two poles (at x = −10 and x = 10) takes the shape of a catenary with equation y = 2(ex/4 + e−x/4 ). Find the length of the wire. 9.4: Area of a Surface of Revolution Key Points Z • SA = 2π (radius)ds • about the x-axis: radius = y • about the y-axis: radius = x c Dr Oksana Shatalov, Fall 2012 2 Examples 4. The curve y = x2 , 0 ≤ x ≤ 1, is rotated about the y-axis. Find the area of the resulting surface. 5. The curve x = 1 − cos(2t), y = 2t + sin(2t), 0 ≤ t ≤ π/4 is rotated about the x-axis. Find the area of the resulting surface. 6. Set up (but don’t evaluate) the integral that gives the surface area obtaine by rotating the curve x = sin(πy 2 /8), 1 ≤ y ≤ 2, (a) about the x-axis (b) about the y-axis π is rotated about the x-axis (here a is an 7. The curve x = sin(at), y = cos(at), 0 ≤ t ≤ 2a arbitrary positive constant). Find the area of the resulting surface. 10.1: Sequences Key Points • If lim an exists and finite then we say that the sequence {an } converges. Otherwise, we n→∞ say the sequence diverges. (Recall all techniques for finding limits at infinity.) • The Squeeze Theorem for Sequences: If an ≤ bn ≤ cn for all n and the sequences {an } and {cn } have a common limit L as n → ∞, then lim bn = L. n→∞ • If lim |an | = 0, then lim an = 0. n→∞ n→∞ • {an } increasing: show that an+1 − an > 0, or f 0 (x) > 0 (where f (n) = an ); or (provided an > 0 for all n.) Note: reverse signs for {an } decreasing. an + 1 >1 an Examples 8. Define the n-th term of the sequence 1 2 3 4 5 , , , , , . . . and find its limit. 2 3 4 5 6 9. Determine if the given sequence converges or diverges. If it converges, find the limit. 3n5 − 12n3 + 2012 2012 − 12n4 − 4n4 − 9n5 3n5 − 12n3 + 2012 (b) bn = 2012 − 12n4 − 4n4 − 9n5 + 11n6 (a) an = c Dr Oksana Shatalov, Fall 2012 (c) cn = 3 12n7 + 2012 2012 − 12n4 − 4n5 − 9n6 10. Determine if the sequence with the given general term (n ≥ 1) converges or diverges. If it converges, find the limit. (a) an = ln(n2 + 3) − ln(7n2 − 5) 1 1 (b) zn = 4 sin( 5 ) n n n (−1) (c) yn = n3 (−1)n n (d) xn = 3n + 33 (arctan n)7 (e) an = n5 11. Assuming that the sequence defined recursively by an = 1, an+1 = find its limit. 12. Determine whether the given seqence is increasing or decreasing. (a) {arctan(n)}∞ n=1 (b) {n − 2n }∞ n=1 n ∞ 10 (c) n! n=1 1 2 an + 9 an is convergent,