Math 251-copyright Joe Kahlig, 15C Page 1 Section 13.3: Double Integrals over General Regions Example: Evaluate the integral where D = {(x, y) ∈ <2 |x2 + y 2 ≤ 16}. ZZ p 16 − x2 − y 2 dA D Definition: A plane region D is said to be of Type I if it lies between two continuous functions of x, that is D = {(x, y)|a ≤ x ≤ b, B(x) ≤ y ≤ T (x)} Let D = {(x, y)|a ≤ x ≤ b, B(x) ≤ y ≤ T (x)} be a domain of type I and f is continuous on D. Choose a rectangle region R = [a, b] × [c, d] containing D and Define a new function G(x, y) on R by ( f (x, y) if (x, y) is in D G(x, y) = 0 if (x, y) is in R but not in D Definition: We define the integral of f (x, y) over D to be ZZ ZZ f (x, y)dA = G(x, y)dA D R provided the integral over the region R exists. Note: G is likely to have discontinuities on the boundary of D. However, it can be shown that if f is continuous on D and the boundary of D is ”well behaved”, then G is integrable over over R. Page 2 Math 251-copyright Joe Kahlig, 15C By Fubini’s Theorem we get: ZZ Zb ZZ f (x, y)dA = G(x, y)dA = D Zd G(x, y)dy dx a R c Recall that G(x, y) = 0 if y < B(x) or if y > T (x). Therefor, B(x) Z Zd G(x, y)dy = G(x, y)dy + c c Zd B(x) Z Zd G(x, y)dy + B(x) c c Zd T Z(x) G(x, y)dy = Zd f (x, y)dy + B(x) G(x, y)dy T (x) T Z(x) 0dy + G(x, y)dy = c T Z(x) 0dy T (x) f (x, y)dy B(x) Thus Theorem: If f is continuous on a type I region D such that D = {(x, y)|a ≤ x ≤ b, B(x) ≤ y ≤ T (x)} then ZZ Zb TZ(x) f (x, y)dA = f (x, y)dydx D a B(x) Definition: A plane region D is said to be of Type II if it lies between two continuous functions of y, that is D = {(x, y)|c ≤ y ≤ d, L(y) ≤ x ≤ R(y)} Theorem: If f is continuous on a type II region D such that D = {(x, y)|c ≤ y ≤ d, L(y) ≤ x ≤ R(y)}then ZZ Zd R(y) Z f (x, y)dA = f (x, y)dxdy D c L(y) Math 251-copyright Joe Kahlig, 15C Example: If D is the region bounded by y = 4x and y = x2 evaluate ZZ x + y dA D Example: Evaluate the double integral of f (x, y) = x over the region D = {(x, y)|0 ≤ x ≤ π, 0 ≤ y ≤ sin(x)}. Page 3 Math 251-copyright Joe Kahlig, 15C Page 4 Example: Set up the double integral that would evaluate the function f (x, y) = x + y over the region bounded by the lines y = 6x, y = 2x, and y = −2x + 16 Example Find the volume of the solid bounded by the cylinder x2 + z 2 = 9, the planes x = 0, y = 0, z = 0, x + 2y = 2 in the first octant. Page 5 Math 251-copyright Joe Kahlig, 15C Z1 Z2 Example: Evaluate the integral by changing the order of integration cos(y 2 )dydx 0 2x Properties of Double Integrals: • If a and b are real numbers then ZZ ZZ (af (x, y) + bg(x, y))dA = a D ZZ f (x, y)dA + b D g(x, y)dA D • If D = D1 ∪ D2 , where D1 and D2 do not overlap except perhaps on their boundaries then ZZ ZZ f (x, y)dA = D ZZ f (x, y)dA + D1 f (x, y)dA D2 ZZ • If we integrate f (x, y) = 1 over a region D, then dA = the area of D. D