Well-posed Solutions of the Third Order Benjamin–Ono Equation in Weighted Sobolev Spaces Xueshang Feng∗ Abstract Here we continue the study of the initial value problem for the third order T Benjamin-Ono equation in the weighted Sobolev spaces Hγs = H s L2γ , where s > 3, γ ≥ 0. The result is the proof of well-posedness of the afore mentioned problem in Hγs , s > 3, γ ∈ [0, 1]. The proof involves the use of parabolic regularization, the Riesz-Thorin interpolation theorem and the construction technique of auxiliary functions. 1 Introduction In recent years, the initial value problem for Benjamin-Ono(BO) equation of deep water, ∂tu + ∂x (2Hux + u2 ) = 0 has been investigated by many authors [1, 4, 5, 7, 8]. Iorio[5] established the wellposedness of the above BO equation in Hγ2 , where γ ∈ [0, 1], by using Kato’s theory of linear evolution equations of “hyperbolic type”. Ponce [7] proved the global wellposedness of the BO equation in H s , s ≥ 3/2. In [3], the authors obtained the ∗ Supported by National Natural Science Foundation of China Received by the editors May 1996. Communicated by J. Mawhin. 1991 Mathematics Subject Classification : 35Q20, 35G25, 35D99. Key words and phrases : The third order BO equation; Initial value problem; Weighted Sobolev spaces; Global well-posedness. Bull. Belg. Math. Soc. 4 (1997), 525–537 526 X. Feng global existence and uniqueness both in the usual Sobolev space H s and weighted Sobolev spaces Hγs for the third order BO equation ∂tu = −∂x(u3 + 3uHux + 3H(uux ) − 4∂x2u), t > 0, x ∈ R (1.1) u(x, 0) = φ(x) (1.2) which can be considered as the high order approximation of the BO equation. Here ∂k u = u(x, t) is real valued, ∂xk = ∂x k and the subscripts appended to u stand for partial differentiations, and H denotes the Hilbert transform Z (Hf)(x) = P.V. In this paper, Hγs = H s T f(y) dy π(y − x) L2γ with the following norm ||u||2γ,s = ||f||2s + |ωγ f|22 , ωγ (x) = (1 + x2 )γ where || • ||s and | • |2 are the usual norms of the Sobolev spaces H s (R) and Lebesgue space L2 (R), respectively. Throughout the paper, | • |p will denote the usual norm of the Lebesgue spaces Lp (R), p ∈ [1, ∞]. If X and Y are Banach spaces we denote the set of all bounded operators from X to Y by B(X, Y ). If X = Y we write B(X) instead of B(X, Y ). As usual [A, B] will indicate the commutator of two linear operators(not necessarily continuous). The BO equation arises in the study of unidirectional propagation of nonlinear dispersive waves or long nonlinear sausage-wave propagation in a magnetic slab in an incompressible plasma of the solar atmosphere, and presents the interesting fact that operrators modelling the dispersive effect in the BO equation or the effect of derivative nonlinearity in (1.1) are nonlocal. In [3, 5], the authors have shown that u ∈ C([0, T ]; H 43 ) or u ∈ C([0, T ]; H24) solves equation (1.1) or the BO equation 2 if and only if u ≡ 0, and pointed out in [3] that this phenomena are caused by the nonlocal terms modelling the equations. The papers [1, 7] are devoted to the proof of the well-posedness of the global solutions to the initial value problem of the BO equation in H s , for s ≥ 32 . Many physicists such as Ruderman (see [8] and references therein) have used this equation to study the wave propagation in a magnetically structured atmosphere and found its solutions in the form of periodic waves of permanent shape numerically. As the high order approximation of the BO equation, the third order BO equation (1.1) is interesting in its own rights and therefore it is of importance to study its well-posedness whether mathematically or physically considered. I would here like to apologize if I miss citing other papers on the BO equation. Our aim here is to investigate the global well-posedness of problem (1.1), (1.2) in the weighted Sobolev spaces Hγs as done in [5] for the BO equation. Our main result is as follows: Theorem 1.1. Let φ ∈ Hγs , s ≥ 4 and γ ∈ [0, 1]. Then for all fixed µ ≥ 0 there exists a unique uµ ∈ C([0, T ]; H s) for any given T > 0 such that ∂tuµ ∈ C([0, T ]; H s−4) and ωγ0 ∂xk uµ ∈ C([0, T ]; L2) for k ≤ s/2 and the following (2.6), (2.7) are satisfied. Moreover, |ωγ0 ∂xk u|2 ≤ C(γ)||u||γ,s Third Order Benjamin–Ono Equation in Weighted Sobolev Spaces 527 Furthermore, the map φ 7→ uµ is continuous in the sense that if φn → φ in Hγs−2 and unγ , uµ are the corresponding solutions then lim sup[0,T ]||unµ (t) − uµ (t)||γ,s−2 = 0 n→∞ where s ≥ 6. In fact, we shall show that the map φ 7→ u is globally Lipschitz. In our cases, it is difficult to apply Kato’s theory of linear evolution equations of “hyperbolic type” because of the appearance of the derivative nonlinear nonsmooth terms. The proof in this paper is very technical and long. In the following two sections we shall finish the proof of Theorem 1.1 by presenting a series of statements. 2 Preliminary results In this part, a series of lemmas are given for the purpose of proving Theorem 1.1. The lemmas below are established following the same lines as those of [5]. Lemma 2.1. Suppose n a(x) isodefined on R and |a(x)−a(y)| ≤ M|x−y|, x, y ∈ R R. Let T (f) = |x−y|≥ a(x)−a(y) f(y)dy. Then (x−y)2 |T (f)|p ≤ Ap |f|p , for all f ∈ Lp (R) with Ap independent of , 1 < p < ∞. For details and further results of this kind see Calderon [2] and P.238 of Stein [9]. The following well-known Gagliardo-Nirenberg’s inequality will be unexplainedly used throughout the paper. Lemma 2.2. For f ∈ H m (R) and p ≥ 2, then we have |∂xd f|p ≤ 2 (p−2) 2p |∂xk u|λ2 |u|1−λ (2.1) S where d, m, k ∈ N {0}, λ = (d + 12 − 1p )/k, and 0 ≤ d < k ≤ m. More precisely, for f ∈ H d+1 (R) we have 1 2d+1 |∂xd f|∞ ≤ |f|22(d+1) |∂xd+1f|22(d+1) (2.2) Proof. (2.1) has been well-known. To prove (2.2), noting that |f(x)| = 2 Z 2 |f(x)| = −2 x −∞ Z 2 ffx dx ≤ 2 ∞ x Z ffx dx ≤ 2 x −∞ Z |ffx |dx ∞ x |ffx |dx We get by using the Cauchy-Schwartz inequality |f|2∞ ≤ Z |ffx |dx ≤ |f|2 |fx |2 (2.3) which gives (2.2) for the case d=0. By using (2.1) and (2.3) we get 2d+1 1 |∂xdu|2∞ ≤ |∂xdu|2|∂xd+1 u|2 ≤ |∂xd+1u|2d+1 |u|2d+1 528 X. Feng which finishes the proof of (2.2). It should be pointed out that inequality (2.2) can be used to improve the uniqueness result for the smallness case of the initial data in [3]. Lemma 2.3. Let λ ∈ [0, ∞), γ ∈ [0, 1], µ > 0, and Qµ = −µ∂x4 + 4∂x3 . Then Sµ (t) = exp(tQµ ) ∈ B(Hγs , Hγs+λ ) for all t > 0, s ≥ 0 and satisfies the estimate ||Sµ (t)φ||γ,s ≤ G(t, µ, λ, γ)||φ||γ,s (2.4) for all φ ∈ Hγs , where G(t, µ, λ, γ) is locally integrable with respect to t. Moreover the map t ∈ (0, ∞) 7→ Sµ (t)φ is continuous with respect to the topology of Hγs+λ . Proof. Due to [3], where the Lemma is established in the case of H0s = H s , s ∈ R, it suffices to examine Sµ (t) as an operator from Hγs into Hγ0 = L2γ . If γ = 0 we obtain T H00 = L2 so that ||Sµ (t)φ||0,0 ≤ ||φ||0,0. Next, if γ = 1 and φ ∈ H1s = H s L21 we have (ω1 Sµ (t)φ)∧(ξ) = Eµ (ξ, t)(1 − ∂ξ2)φ̂ − (∂ξ2Eµ (ξ, t))φ̂ − 2(∂ξ Eµ (ξ, t))∂ξ φ̂ (2.5) where Eµ (ξ, t) = exp[−(µξ 4 + 4iξ 3 )t]. The result then follows by combining (2.5) with the formulas ∂ξ Eµ (ξ, t) = −(4µξ 3 + 12iξ 2 )tEµ (ξ, t) ∂ξ2Eµ (ξ, t) = −12t(µξ 2 + 2iξ)Eµ (ξ, t) + 16t2 ξ 4 (µξ + 3i)Eµ (ξ, t) and the estimate λ 0 ≤ ξ 2λ exp(−µtξ 4 ) ≤ λλ exp( )(2µt)−λ/2 2 The statement in the Lemma is now an easy consequence of the Riesz-Thorin interpolation theorem. We are now in position to establish a local existence for the following parabolic regularized problem ∂tuµ = −µ∂x4uµ − ∂x (u3µ + 3uµ H∂x uµ + 3H(uµ ∂x uµ ) − 4∂x2uµ ) (2.6) uµ (x, 0) = φ(x) (2.7) in Hγs , γ ∈ [0, 1] and µ > 0. Let T be a positive number and consider the set n Xγ,s (T ) = f ∈ C([0, T ]; Hγs); ||f(t) − Sµ (t)φ||γ,s ≤ ||φ||γ,s , t ∈ [0, T ] o which becomes a complete metric space when provided with the distance obtained from the sup norm. Note that if f ∈ Xγ,s (T ), then by Lemma 2.3 it is not difficult to show that one can choose T > 0 such that the map (Af)(t) = Sµ (t)φ − Z 0 t Sµ (t − τ )∂x f 3 + 3fHfx + 3H(ffx ) dτ defines a contraction in Xγ,s (T ). In view of the uniqueness and regularity results established in [3] we have Corollary 2.4. Let φ ∈ Hγs , s ≥ 4, γ ∈ [0, 1], µ > 0. Then there exist a T > 0 and a unique uµ ∈ C([0, T ]; Hγs) such that ∂t uµ ∈ C([0, T ]; H s−4) satisfies problem (2.6), (2.7). Moreover, uµ ∈ C((0, T ]; Hγq ) for all q ∈ R. Third Order Benjamin–Ono Equation in Weighted Sobolev Spaces 529 Let µ > 0 be fixed. From now on, unless otherwise specifed, we write u = uµ for simplicity. The next step is to establish global existence in Hγs , s ≥ 4 and γ ∈ [0, 1]. This has already been done in [3] in the cases γ = 0 and γ = 1 (the result for γ = 1 will be re-obtained below from a slightly different point of view). In order to obtain global estimates for the Hγs norm of the solution it suffices to study what happens in L2γ since the H s result was proved in [3]. Now, by Corollary 2.4 and integration by parts, at least formally we have ∂t ||u(t)||2γ,0 = −4µ −8 Z Z ωγ2 u∂x (u3) Z ωγ2 u22x dx + 2µ 0 uu2xωγ ωγ00dx Z t − 4µ dx − 3 Z +2 (ωγ2 )000u2 dx − 24 Z Z uu2x(ωγ0 )2 dx − 8µ Z Z ωγ2 u2 H(∂x2u)dx +6 ωγ ωγ0 uu2x dx − 3 Z ux u2xωγ ωγ00 dx ωγ ωγ0 u2 Hux dx Z ωγ2 uH(∂x2(u2))dx (2.8) In order to extend the local solution to the whole time interval [0, T ], for any fixed T > 0 we must estimate the right-hand side of (2.8). For this purpose we need the following Lemmas. Lemma 2.5. Let u ∈ Hγ4 , γ ∈ [0, 1]. Then ωγ/2 u2x ∈ L2 and satisfies 1 1 |ω γ2 u2x |2 ≤ C||u||42 |ωγ u|22 ≤ C||u||γ,4 (2.9) where C is a generic constant. Proof. By definition, for u ∈ S(R)(the Schwartz space) we have |ω γ 2 u2x|22 Z = Z ωγ u22xdx = ωγ00 uu2x Z dx + 2 ωγ0 uu3xdx Z + ωγ uu4xdx ≤ |ωγ00u|2|u2x |2 + 2|ωγ0 u|2|u3x |2 + |ωγ u|2|u4x|2 ≤ C||u||4|ωγ u|2 (2.10) which combines a limiting argument to yield the result. Lemma 2.6. Let f ∈ Hγs , γ ∈ [0, 1]. Then x(1 + x2 )γ ∂xk f ∈ L2 and |x(1 + x2)(r−1) ∂xk f|2 ≤ C(r)||f||γ,s , 2k ≤ s (2.11) where C(γ) is a constant depending only on γ. The same results are true if x(x2 + 1)γ−1 is replaced by ωγ0 (x). Proof. A simple limiting argument shows that it suffices to prove (2.11) for f ∈ S(R). Assume therefore that this is the case and integrate by parts to obtain for k = 1 |x(1 + x2)γ−1 fx |22 = − 3 X Ij j=1 where Z I1 = 2 (1 + x2)γ f(x)[x(1 + x2)γ−2 ]fxdx I2 = 2(2γ − 2) Z (1 + x2)γ f(x)[x3(1 + x2)γ−3 ]fx dx 530 X. Feng Z I3 = (1 + x3)γ f(x)[x2(1 + x2)γ−2 ]∂x2f(x)dx It is easy to verify that the expressions inside the square brackets in all the three ingegrals are bounded of x. By this remark and the Cauchy-Schwartz inequality we obtain |I1| ≤ 2|fx |2|ωγ |2, |I2| ≤ |4γ − 4||fx |2 |ωγ f|2 , |I3| ≤ |∂x2f|2 |ωγ f|2 Now, we have |x(1 + x2)γ−1 fx |2 ≤ {(2 + |4γ − 4|)|fx |2 + |f2x|2 } |ωγ f|2 ≤ C(γ)||f||2|ωγ f|2 which finishes the proof. For the general case, a similar argument yields |x(1 + x2)γ−1 ∂xk f|22 = 2k Z X (1 + x2 )γ f(x)pj (x)∂xj f(x)dx j=k where pj (x) is bounded in x. So the result follows. Corollary 2.7. Let f ∈ Hγ4 , γ ∈ [0, 1]. Then ω γ2 fx ∈ L2 , ω γ2 fx ∈ L∞ and satisfy the estimates 1 1 |ω γ2 fx |2 ≤ C(γ)||f||22 |ωγ f|22 (2.12) 1 1 |ω γ2 fx |∞ ≤ C(γ)||f||44 |ωγ f|22 (2.13) where C(γ) > 0 depends only on γ. Proof. Similar to the proof of (2.9), it suffices to prove (2.12) for f ∈ S(R). If this is the case, then we have |ω γ2 fx |22 = Z ωγ fx fx dx = − Z ωγ ff2xdx − Z ωγ0 ffx dx ≤ |fx |2|ωγ0 f|2 + |f2x|2 |ωγ f|2 ≤ C(γ)||f||2|ωγ f|2 which gives (2.12). By (2.2), (2.9), (2.11) and (2.12) we obtain |ω γ2 fx |2∞ ≤ |ω γ2 fx |2|ω 0γ fx + ω γ2 f2x|2 ≤ C(γ)||f||4|ωγ f|2 2 This finishes (2.13). Lemma 2.8. Let f ∈ Hγs , γ ∈ [0, 1]. Then [ω γ2 , H∂x ]f ∈ L2 and |[ω γ2 , H∂x ]f|2 ≤ C(γ)|f|2 (2.14) where C(γ) depends only on γ. Proof. First observe that it suffices to prove (2.14) in case of f ∈ S(R). Now [ω γ2 , H∂x ]f = [ω γ2 , H]∂x f − H[∂x , ω γ2 ]f (2.15) For the second commutator in (2.15) we have H[∂x, ω γ2 ]f = H(ω 0γ f) 2 (2.16) Third Order Benjamin–Ono Equation in Weighted Sobolev Spaces 531 For the first commutator in (2.15) we integrate by parts once to obtain [ω γ2 , H]∂xf = P.V. 1 π Z ω γ (x) − ω γ (y) 2 2 (x − y)2 f(y)dy − H(ω 0γ f) (2.17) f(y)dy − 2H(ω 0γ f) (2.18) 2 From (2.15)-(2.17) we know that [ω γ2 , H∂x ]f = P.V. 1 π Z ω γ (x) − ω γ (y) 2 2 (x − y)2 2 Since ω 0γ is bounded and ω γ2 is Lipschitz, by Lemma 2.1 and the fact that H ∈ B(L2 ) 2 it follows from (2.18) that |[ωγ , H∂x2]f|2 ≤ C(γ)|f|2 which finishes the proof. From the proof above we see that (2.14) holds for all f ∈ L2 . Lemma 2.9. Let f ∈ Hγ2 , γ ∈ [0, 1]. Then [ωγ , H∂x2 ]f ∈ L2 and |[ωγ , H∂x2]f|2 ≤ C(γ)||f||γ,2 (2.19) where C(γ) ≥ 0 depends only on γ. Proof. First note that it suffices to prove (2.19) for f ∈ S(R). Evidently [ωγ , H∂x2]f = [ωγ , H]∂x2f − H[∂x2, ωγ ]f (2.20) So it suffices to establish (2.19) with [ωγ , H∂x2]f replaced by H[∂x2, ωγ ]f and [ωγ , H]∂x2f. The result then follows for the first of these functions by combining the formula H[∂x2, ωγ ]f = H(ωγ00f + 2ωγ0 ∂xf) (2.21) with Lemma 2.6 and the facts that ωγ00 ∈ L∞ and H ∈ B(L2). In order to handle [ωγ , H]∂x2f we integrate by parts once to obtain [ωγ , H]∂x2f = H(ωγ0 ∂x f) 1 − P.V. π Z ωγ (x) − ωγ (y) f(y)dy (x − y)2 (2.22) In view of Lemma 2.6 the first term on the right-hand side of (2.22) satisfies |H(ωγ0 ∂xf)|2 ≤ C(γ)||f||γ,2, so it remains to bound the second. Since ωγ0 is bounded if and only if γ ∈ [0, 12 ], in this case ωγ is Lipschitz. Hence, by Lemma 2.1 we have Z 1 ωγ (x) − ωγ (y) P.V. ≤ A|f|2 f(y)dy π (x − y)2 (2.23) where A > 0 is a generic constant, γ ∈ [0, 12 ]. In the case of γ ∈ ( 12 , 1] we integrate by parts once in (2.22) to get [ωγ , H]∂x2f = −P.V. 1 π Z K(x, y)g(y)dy (2.24) 532 X. Feng 2(ωγ (x) − ωγ (y)) − 2ωγ0 (y)(x − y) − ωγ00(y)(x − y)2 (x − y)3(1 + y 2 )γ K(x, y) = (2.25) where g(y) = (1 + y 2)γ f(y) ∈ L2 . If γ ∈ ( 12 , 1], it is not difficult to verify that K(x, y) is a Hilbert-Schmidt kernel. Thus 1Z P.V. K(x, y)ωγ (y)f(y)dy ≤ C|ωγ f|2 (2.26) π where C > 0 is a generic constant, γ ∈ ( 12 , 1]. Now the result of the lemma follows from (2.20)-(2.26). Now we are in position to estimate each term in the right-hand side of (2.8) as follows: Z µ µ 00 R1 ) 4µ uu2xωγ ωγ dx ≤ |ωγ u2x|22 + Cµ|ωγ00u|2 ≤ |ωγ u2x |22 + Cµ|u|22 3 3 Z µ 0 2 R2 ) 4µ uu2x (ωγ ) dx ≤ |ωγ u2x|22 + Cµ|ωγ u|22 3 Z µ R3 ) 8µ ux u2xωγ ωγ00dx ≤ |ωγ u2x |22 + Cµ|ux |22 3 Z R4 ) 8 (ωγ )2u∂x (u3)dx ≤ C(||u||2)|ωγ u|22 Z 2 2 2 R5 ) 3 (ωγ ) u H(∂x u)dx ≤ C(||u||3)|ωγ u|22 Z 0 2 R6 ) 6 ωγ ωγ u Hux dx ≤ C(||u||2)|ωγ u|22 Z 000 2 R7 ) 2 (ωγ ) u dx ≤ |ωγ u|22 Z 0 R8 ) 24 ωγ ωγ uu2xdx ≤ 24|ωγ u|2|ωγ0 u2x |2 ≤ C|ωγ u|2|ω γ2 u2x|2 ≤ C(||u||4)|ωγ u|22 Z Z Z (ωγ )2uH∂x2 (u2)dx = R9 ) Z = Z ωγ u[ωγ , H∂x2]u2 dx + ωγ u[ωγ , H∂x2]u2dx + ωγ uH∂x2(ωγ u2 )dx ωγ uH[ωγ00u2 + 2ωγ0 uux + 2ωγ u2x + 2ωγ uu2x)dx n ≤ C|ωγ u|2 |[ωγ , H∂x2 ]u2|2 + |ωγ00u2 |2|ωγ0 uux|2 + |ωγ u2x |2 + |ωγ uu2x|2 n o ≤ C(γ)|ωγ u|2 ||u2||γ,2 + |u2|2 + |ωγ0 uux |2 + |ω γ2 ux |∞ |ω γ2 ux |2 + |u2x|∞ |ωγ u|2 o ≤ C(γ, ||u||4)|ωγ u|2 Considering R1 –R9 ) and (2.8) we obtain Z d ||u(t)||2γ,0 + µ (ωγ )2 u22xdx ≤ C(µ, γ, ||u||4)|ωγ u|22 (2.8)0 dt By [3] we know that ||u(t)||s is bounded uniformly for t in any fixed interval [0, T ] and µ varying in any bounded interval. That is, ||u(t)||s ≤ C(µ, ||φ||s ), t ∈ [0, T ] (2.27) Third Order Benjamin–Ono Equation in Weighted Sobolev Spaces 533 where C(µ, ||φ||s) > 0 depends in an nondecreasing way on µ and ||φ||s , respectively. If µ remains in a bounded set [0, µ0], one can choose C(µ, ||φ||s) depending only on ||φ||s. With this remark in mind, apply Gronwall’s inequality to (2.8)0 to obtain ||u(t)||γ,0 ≤ C(µ, γ, T, ||φ||γ,4), t ∈ [0, T ] (2.28) where C(µ, γ, T, ||φ||γ,4) has the same property as that of (2.27). Now we return to the global existence result. If µ > 0, the global existence result follows from (2.27) and (2.28).The existence result in the case µ = 0 can be proved by the standard limiting argument. Proof of uniqueness. Here the proof is reproduced from [3]. Let u, v be two solutions to problem (2.6), (2.7) with the initial data φ(x), ψ(x) ∈ H s , respectively. Putting w = u − v, then w satisfies the following equation wt = −µ∂x4w 4∂x3 w + − ∂x 3 (u − v ) + 3wHux + 3vHwx + H∂x (u2 − v 2) 2 3 3 w(x, 0) = φ(x) − ψ(x) (2.29) (2.30) For µ > 0 fixed, the uniqueness result follows from the standard energy estimate. So in the following we only give the proof for µ = 0. From (2.29), a direct calculation of (2.29) and use of Lemma 2.2 yield d dt Z Z w2 dx = 2 1 − w2 (u2 + uv + v 2)x + 3wwx Hux + 3vwx Hwx 2 3 3 − (u + v)wxHwx − (ux + vx )wHwx dx 2 2 Now it is not difficult to find that |w|22 ≤ |w(0)|2 + C(||φ||2, ||ψ||2) Z 0 t ||w(t)||21dt (2.31) (2.32) Since s ≥ 4, we know that |ut |L∞ ([0,T ]×R), |vt|L∞ ([0,T ]×R), |∂xk u(x, t)|L∞([0,T ]×R) and |∂xk v(x, t)|L∞([0,T ]×R) are bounded for 0 ≤ k ≤ s − 1. Multiply equation (2.29) by K4 (u) − K4 (v) to know Z wt (K4 (u) − K4 (v)) dx = 0 (2.33) where K4 (u) = u3 + 3uHux + 3H(uux ) − 4u2x . The bound for the term in the right-hand side of (2.33) is carried out as follows. Z t Z 1) 0 1 = 2 Z wt(u3 − v 3)dxdt t Z Z 1 t w (u + uv + v )dx − w2 (u2 + uv + v 2)tdxdt 2 2 2 0 ≤ C(|w(t)|22 + |w(0)|22 + Z 2 0 t 0 |w(τ )|22dτ ) (2.34) 534 X. Feng Z t Z 2) 0 3 = 2 Z 3 wt [3uHwx + 3wHvx + H(u2 − v 2)x ]dxdt 2 t Z uwHwx dx − 3 Z 2 w Hvx dx + 3 0 t Z ut [wHwx + H(wwx )]dxdt 0 Z ≤ δ|wx|22 + C(δ)|w|22 + C||w(0)||21 + C 3) − 4 Z t 0 Z 0 t ||w(τ )||21dτ (2.35) wt w2x dxdt = 2|wx |22 − 2|wx (0)|22 (2.36) Adjusting the value of δ, from (2.32)-(2.36) we derive ||w(t)||21 ≤ C(||φ||1, ||ψ||1)||w(0)||21 + C(||φ||4, ||ψ||4) Z 0 t ||w(τ )||21dτ (2.37) Applying Gronwall’s inequality to (2.37) to yield ||w(t)||21 ≤ C(T, ||φ||4, ||ψ||4)||w(0)||21 , t ∈ [0, T ] (2.38) which implies the uniqueness. Up to now we have proved the following Corollary 2.10. Let φ ∈ Hγs , s ≥ 4 and γ ∈ [0, 1]. Then for all fixed µ ≥ 0 there exists a unique uµ ∈ C([0, T ]; Hγs) for any given T > 0 such that ∂tuµ ∈ C([0, T ]; H s−4) and ωγ0 ∂xk uµ ∈ C([0, T ]; L2) for 2k ≤ s and (2.6), (2.7) are satisfied. 3 Proof of Theorem 1.1 Continued In this section we continue the proof of Theorem 1.1. Lemma 3.1. Let φ, ψ ∈ Hγs , s ≥ 4 and γ ∈ [0, 1], µ ≥ 0. Let uµ , vµ be the solutions(obtained in Corollary 2.10) to (2.6) with φ, ψ as the initial data, respectively. Suppose w = uµ − vµ . Then we have ||w(t)||2γ,0 ≤ ||w(0)||2γ,4 + C(µ, T, ||φ||γ,4, ||ψ||γ,4) Z t 0 ||w(t)||2γ,4dt, t ∈ [0, T ] (3.1) where C depends in an nondecreasing way on its arguments. Proof. By the assumptions of the Lemma we know that w satisfies problem (2.29), (2.30). Multiply (2.29) by ωγ2 w and integrate by parts to obtain Z d Z 2 2 ωγ w dx + 2µ ωγ2 (∂x2w)2 dx dt = −4µ + −8 Z Z + −3 ww2x ωγ ωγ00 dx − 4µ Z ww2x (ωγ0 )2dx − 8µ Z Z ωγ2 w∂x (u3 − v 3)dx + 2 (ωγ2 )000w2 dx − 24 Z Z ωγ2 w2 Hv2xdx + 3 (ωγ2 )0 w2 Hvxdx − 6 wx w2xωγ ωγ00dx Z ωγ ωγ0 ww2xdx Z ωγ2 wuHw2xdx Third Order Benjamin–Ono Equation in Weighted Sobolev Spaces −6 Z ωγ2 wux Hwx dx − 3 Z ωγ2 wH∂x2 (u2 − v 2)dx ≡ 7 X Bj 535 (3.2) j=1 The estimate for each Bj is as follows. By using (2.9), (2.11), (2.12), (2.13) and (2.14), we obtain |B1 | ≤ µ|ωγ w2x|22 + µC|ωγ w|22 , |B2 | ≤ C(||φ||2, ||ψ||2)|ωγ w|22 Z 0 |B3 | ≤ 24 ωγ ωγ ww2x dx ≤ 24|ωγ w|2 |ωγ0 w2x|2 ≤ C|ωγ w|2 |ω γ2 w2x|2 ≤ C||w||2γ,4 |B4| ≤ C(T, ||φ||3, ||ψ||3)|ωγ w|22 , |B5 | ≤ C|ωγ u|2||w||2γ,2 Z B6 = 6 Z ωγ2 wux Hwx dx = 6 Z ωγ wω γ2 ux[ω γ2 , H∂x ]wdx + 6 ωγ wω γ2 ux H∂x (ω γ2 w)dx ≤ 6|ω γ2 ux |∞ |ωγ w|2|[ω γ2 , H∂x ]w|2 + |ωγ w|2|∂x (ω γ2 w)|2 ≤ C(||u||γ,4)||w||2γ,4 Z B7 = 3 Z =3 ωγ2 wH∂x2 (u2 − v 2)dx ωγ w[ωγ , H∂x2 ](u2 − v 2)dx + 3 Z ωγ wH∂x2(ωγ w(u + v))dx ≤ C|ωγ w|2 ||u2 − v 2||γ,2 + |∂x2(ωγ (u + v)w)|2 ≤ C(T, ||φ||γ,4, ||ψ||γ,4)||w||2γ,4 Considering (3.1) and (3.2) we know that Z d |ωγ w|22 + µ (ωγ )2(∂x2 w)2 dx ≤ C(µ, T, ||φ||γ,4, ||ψ||γ,4)||w||2γ,4 dt (3.3) Integrate (3.3) with respect to t to yield the result. Lemma 3.2. Let the assumptions in Lemma 3.1 be satisfied and s ≥ 6. Then we have Z d 2s − 3 s−1 2 s−2 s−2 |∂x w|2 + (u + v)∂x wH∂x wdx dt 4 ≤ C(µ, T, ||φ||s, ||ψ||s)||w(t)||2s−2, t ∈ [0, T ] (3.4) where C depends in an increasing way on its arguments and remains bounded whenever its arguments stay in a bounded set. Proof. The proof of (3.4) for µ > 0 is simple and is omitted. But the proof for µ = 0 is technical. For s = 6, a complicated calculation yields Z d s−2 2 |∂ w|2 ≤ −27 (u + v)x∂x4wH∂x5 wdx + C(T, ||φ||6, ||ψ||6)||w(t)||24 dt x and d dt Z (u + v)∂xs−3wH∂xs−2 wdx ≤ 12 Z (u + v)x∂x4wH∂x5 wdx + C(T, ||φ||6, ||ψ||6)||w(t)||24 These two inequalities mean that the derivative term in the left hand side equals the first term in the right hand side plus a term less than the second term in the 536 X. Feng right hand side. Hence, (3.4) holds for s = 6. For general s we can prove (3.4) by induction on s. The details are omitted. The Completion of Proof of Theorem 1.1. By Lemma 2.2 we have Z 2s − 3 s−3 s−2 s−3 s−2 (u + v)∂x wH∂x wdx ≤ C(|φ|2 , |ψ|2 )|∂x w|∞ |∂x w|2 4 1 ≤ |∂xs−2 w|22 + C|w|22 2 From (2.38), (3.4) and (3.5) there appears that 1 2s−5 ≤ C|w| 2(s−2) |∂xs−2 w|22(s−2) +1 |∂xs−2 w|22 ≤ C||w(0)||2s−2 + C Z 0 t ||w(t)||2s−2 dt (3.5) (3.6) Combining (2.38), (3.1), (3.6) with Gronwall’s inequality we can obtain ||w(t)||2γ,s−2 ≤ C(T, ||φ||γ,s, ||ψ||γ,s)||w(0)||2γ,s−2 , t ∈ [0, T ] which implies the last statement of Theorem 1.1. References [1] Abdelouhab L. et al., Nonlocal models for nonlinear, dispersive waves, Physica D, 40(1989), 360-392 [2] Calderon A. P., Commutators of singular integral operators, Proc. Nat. Acad. Sci., 53(1965), 1092-1099 [3] Feng X., Han X., On the Cauchy problem for the third order Benjamin-Ono equation, J. London Math. Soc., 53(1996), 512-528 [4] Iorio R. J., On the Cauchy problem for the Benjamin-Ono equations, Comm. PDEs, 11(1986), 1031-1086 [5] Iorio R. J., The Benjamin-Ono equation in weighted Sobolev spaces, J. 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