Ann. Funct. Anal. 1 (2010), no. 2, 12–27 A nnals of F unctional A nalysis ISSN: 2008-8752 (electronic) URL: www.emis.de/journals/AFA/ LIPSCHITZ ESTIMATES FOR MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS ZHIWEI WANG1 AND LANZHE LIU2∗ Communicated by J. Esterle Abstract. In this paper, we prove the boundedness for some multilinear commutators generated by the pseudo-differential operator and Lipschitz functions. 1. Introduction As the development of singular integral operators, their commutators and multilinear operators have been well studied (see [4, 5, 6, 7, 8, 9, 10]). In [4, 5, 6, 7, 8, 9, 10], the authors prove that the commutators and multilinear operators generated by the singular integral operators and BM O functions are bounded on Lp (Rn ) for 1 < p < ∞; Chanillo (see [2]) proves a similar result when singular integral operators are replaced by the fractional integral operators. In [4, 11, 12, 13, 16], the boundedness for the commutators and multilinear operators generated by the singular integral operators and Lipschitz functions on Triebel– Lizorkin and Lp (Rn )(1 < p < ∞) spaces are obtained. In [14], the weighted boundedness for the commutators generated by the singular integral operators and BM O and Lipschitz functions on Lp (Rn )(1 < p < ∞) spaces are obtained. The purpose of this paper is to prove the weighted boundedness on Lebesgue spaces for some multilinear operators associated to the pseudo-differential operators and the weighted Lipschitz functions. To do this, we first prove a sharp function estimate for the multilinear operators. Our results are new, even in the unweighted cases. Date: Received: 25 July 2010; Accepted: 15 December 2010. ∗ Corresponding author. 2010 Mathematics Subject Classification. Primary 42B20; Secondary 42B25. Key words and phrases. Multilinear commutator, pseudo-differential operator, Lipschitz space, Lebesgue spaces, Triebel–Lizorkin space. 12 MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS 13 The purpose of this paper is to prove the boundedness on Lebesgue spaces for some multilinear commutators generated by the pseudo-differential operator and Lipschitz functions. 2. Notations and Theorems In order to state our results, we begin by introducing the relevant notions and definitions. Throughout this paper, Q will denote a cube of Rn with sides parallel to the axes. R 1 The A1 weight is defined by A1 = {0 < ω ∈ L1loc : supQ3x |Q| ω(y)dy ≤ Q cω(x), a.e.}(see [5]). The Lipschitz space Lipβ (Rn ) with 0 < β < 1 is the space of functions f such that |f (x) − f (y)| ||f ||Lipβ = sup < ∞. |x − y|β x,y∈Rn x6=y For 0 < β < 1, 1 < p < ∞, m > 0, the Triebel–Lizorkin space F̃pmβ,∞ (Rn ) (see [14]) is the space of functions f such that Z mβ ||f ||F̃pmβ,∞ = sup |Q|−1− n |f (x) − fQ |dx < ∞. Q3x̃ Q Lp Given some function bj ∈ Lipβ (Rn ), 1 ≤ j ≤ m, 0 < β < 1, we denote by Cjm the family of all finite subsets γ = {γ(1), · · ·, γ(j)} of j different elements in {1, · · ·, m}, where γ(i) < γ(j) when i < j. For γ ∈ Cjm , we denote γ c = {1, · · ·, m}\γ. For ~b = {b1 , · · ·, bm } and γ = {γ(1), · · ·, γ(j)} ∈ Cjm , we denote b~γ = {bγ(1) , · · ·, bγ(j) }, and bγ = bγ(1) · · · bγ(j) , and ||b~γ ||Lipβ = ||bγ(1) ||Lipβ · · · ||bγ(j) ||Lipβ . m We say δ(x, ξ) ∈ S,σ , if for x, ξ ∈ Rn , α β ∂ ∂ ≤ Cα,β (1 + |ξ|)m−|β|+σ|α| , δ(x, ξ) ∂xα ∂ξ β where α, β are multiindex consisting of n nonnegative integers. m The pseudo-differential operators ψ · d · o· with symbols δ(x, ξ) ∈ S,σ is given by Z T (f )(x) = e2πi(x,ξ) δ(x, ξ)fˆ(ξ)dξ, Rn where f is a Schwartz function and fˆ denotes the Fourier transform of f . The pseudo-differential operators ψ · d · o· also have another expression Z T (f )(x) = K(x, x − y)f (y)dy, Rn where K(x, x − y) = R Rn δ(x, ξ)e2πi(x−y,ξ) dξ. 14 Z. WANG, L. LIU Let bj , 1 ≤ j ≤ m be the fixed locally integrable functions on Rn . The multilinear commutator associated to the pseudo-differential operator is defined by Z m Y T~b (f )(x) = K(x, x − y) (bj (x) − bj (y))f (y)dy. Rn j=1 Now, we state the main results as follows. −na/2 Theorem 2.1. Let T be a ψ ·d·o· with symbol δ(x, ξ) ∈ S1−a,σ , 0 ≤ σ < 1−a, 0 < 1 a < 1, and bj ∈ Lipβ (Rn ) for 1 ≤ j ≤ m, 0 < β < m(1−a) , and 1 < p < ∞. Then T~b is bounded from Lp (Rn ) to F̃pmβ,∞ (Rn ). −na/2 Theorem 2.2. Let T be a ψ · d · o· with symbol δ(x, ξ) ∈ S1−a,σ , 0 ≤ σ < 1 1 − a, 0 < a < 1, and bj ∈ Lipβ (Rn ) for 1 ≤ j ≤ m, 0 < β < m(1−a) , and mβ 1 < p < ∞, 1/q = 1/p − n . Then T~b is bounded from Lp (Rn ) to Lq (Rn ). 3. Preliminary Lemmas Lemma 3.1. (see [14]) For 0 < β < 1, 1 ≤ p ≤ ∞, 1/p Z Z β β −1− n −n −1 p ||b||Lipβ ≈ sup |Q| |b(x)−bQ |dx ≈ sup |Q| |Q| |b(x) − bQ | dx , Q Q Q −1 where bQ = |Q| R Q Q b(x)dx. Lemma 3.2. (see [14]) Let Q1 ⊂ Q2 . Then |bQ1 − bQ2 | ≤ C||b||Lipβ |Q2 |β/n . −na/2 Lemma 3.3. (see [1]) Let δ(x, ξ) ∈ S1−a,σ , 0 ≤ σ < 1 − a, 0 < a < 1, and K(x, w) denote the inverse Fourier transformations in the ξ-variable and in the R distribution sense of δ(x, ξ), that is informally K(x, w) = Rn δ(x, ξ)e2πi(w,ξ) dξ. Then for |x − x0 | ≤ d ≤ 1/2 and N ≥ 0, Z 1/2 2 |K(x, x − y) − K(x0 , x0 − y)| dy (2N d)1−a ≤|y−x0 |≤(2N +1 d)1−a ≤ C|x − x0 |(1−a)(h−n/2) (2N +1 d)−h(1−a) where h is an integer such that n/2 < h < n/2 + 1/(1 − a). 0 Lemma 3.4. (see [1]) Let δ(x, ξ) ∈ S,σ , 0 < < 1, and, as usual, K(x, w) = R 2πi(w,ξ) δ(x, ξ)e dξ. Then for |w| ≥ 1/4 and arbitrarily large M, |K(x, w)| ≤ Rn −2M CM |w| . Lemma 3.5. (see [3]) For 0 < β < 1, 1 < p < ∞, m > 0, we have Z mβ −1− n ||f ||F̃pmβ,∞ ≈ sup |Q| |f (x) − fQ |dx Q3x̃ Q Lp Z mβ −1− n ≈ sup inf |Q| |f (x) − c|dx , Q3x̃ c∈CQ R where fQ = |Q|−1 Q f (x)dx. Q Lp MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS 15 Lemma 3.6. (see [15, Section 1.9 of Chapter 5]) χQ ∈ A1 for any cube Q. −na/2 Lemma 3.7. (see [1]) Let δ(x, ξ) ∈ S1−a,σ , 0 ≤ σ < 1 − a, 0 < a < 1, T (f )(x) = R e2πi(x,ξ) δ(x, ξ)fˆ(ξ)dξ, and ω ∈ Ap/2 with 2 ≤ p < ∞, ||T (f )||p,ω Rn 1 R = Rn |T (f )(x)|p ω(x)dx p . Then ||T (f )||p,ω ≤ Cp ||f ||p,ω for f ∈ C0∞ (Rn ). Lemma 3.8. (see [15, Section 1.1 of Chapter 2]) Suppose 1 < p < ∞, 1 < r < ∞, R r1 1 r Mr (f )(x) = supQ3x |Q| |f (y)| dy . Then Q Z 1/p p Z ≤C Mr (f )(x) dx Rn p |f (x)| dx 1/p . Rn 1/r rmβ R Lemma 3.9. (see [2]) Let Mr,mβ (f )(x) = supx∈Q |Q|−1+ n Q |f (y)|r dy for 1 < r < ∞, β > 0, m > 0, and r < p < mβ/n, 1/q = 1/p − mβ/n. Then ||Mr,mβ (f )(x)||Lq ≤ C||f ||Lp . 4. Proof of Theorem 1 Proof. Fix a cube Q = Q(x̃, d) with the sidelength d. we first prove that there exists some constant C and 1 < r < ∞ such that, for f ∈ Lp (Rn ), Z −1− mβ n sup inf |Q| |T~b (x) − c|dx ≤ C||~b||Lipβ (Mr (T (f ))(x̃) + Mr (f )(x̃)) . Q3x̃ c∈CQ Q We consider the case m = 1 and d ≤ 1. Let f (x) = f1 (x) R + f2 (x) with f1 (x) = f (x)χJ (x) and f2 (x) = f (x)χJ c (x), and let (b1 )J = |J|−1 J b1 (y)dy, where J is a cube concentric with Q of side-length d1−a . Z K(x, x − y)((b1 (x) − (b1 )J ) − (b1 (y) − (b1 )J ))f (y)dy Tb~1 (f )(x) = Rn Z Z = (b1 (x) − (b1 )J ) K(x, x − y)f (y)dy − K(x, x − y)(b1 (y) − (b1 )J )f1 (y)dy Rn Rn Z − K(x, x − y)(b1 (y) − (b1 )J )f2 (y)dy Rn = (b1 (x) − (b1 )J )T (f )(x) − T ((b1 − (b1 )J )f1 )(x) − T ((b1 − (b1 )J )f2 )(x), thus β −1− n Z |Q| |Tb~1 (f )(x) − T (((b1 )J − b1 )f2 )(x̃)|dx Z Z β −1− n |b1 (x) − (b1 )J ||T (f )(x)|dx + |Q| |T ((b1 − (b1 )J )f1 )(x)|dx Q Q Z β −1− n |T ((b1 − (b1 )J )f2 )(x) − T ((b1 − (b1 )J )f2 )(x̃)|dx +|Q| Q β ≤ |Q|−1− n Q = A1,1 + A1,2 + A1,3 . 16 Z. WANG, L. LIU For A1,1 , by Hölder’s inequality with exponent 1/r + 1/r0 = 1 and Lemma 1, we have β −1− n A1,1 ≤ C|Q| −1 Z |Q| |Q| r0 1/r0 |b1 (x) − (b1 )J | dx Z −1 |Q| ≤ C|J| Q Z −1 1/r0 r0 |J| 1/r |T (f )(x)| dx Q β −n r |b1 (x) − (b1 )J | dx −1 Z r |Q| 1/r |T (f )(x)| dx J Q ≤ C||b1 ||Lipβ Mr (T (f ))(x̃). For A1,2 , by Hölder’s inequality with exponent 1/s + 1/s0 = 1 and 1/t + 1/t0 = 1, such that st = r, and Lemma 7, 1, we have β −1− n Z s A1,2 ≤ C|Q| 1/s |T ((b1 − (b1 )J )f1 )(x)| dx |Q|1/s 0 Rn β −1− n Z s ≤ C|Q| s 1/s |b1 (x) − (b1 )J | |f1 (x)| dx |Q|1/s 0 Rn β −1− n Z s s 1/s |b1 (x) − (b1 )J | |f (x)| dx = C|Q| |Q|1/s 0 J β −1− n ≤ C|Q| −1 1/s |Q| Z −1 |J| |f (x)|st dx × |Q| Z st0 1/st0 |b1 (x) − (b1 )J | dx J 1/st |Q|1/s 0 Q β −n ≤ C|J| −1 Z |J| st0 |b1 (x) − (b1 )J | dx J 1/st0 −1 Z |Q| st 1/st |f (x)| dx Q ≤ C||b1 ||Lipβ Mr (f )(x̃). For A1,3 , choose h such that n/2 < h < n/2 + 1/(1 − a) and n/2 − h + β < 0. By Hölder’s inequality with exponent 1/r + 1/s + 1/2 = 1 and Lemma 2,3,1, we have |T ((b1 − (b1 )J )f2 )(x) − T ((b1 − (b1 )J )f2 )(x̃)| Z = (K(x, x − y) − K(x̃, x̃ − y))(b1 (y) − (b1 )J )f2 (y)dy n ZR ≤ |K(x, x − y) − K(x̃, x̃ − y)||b1 (y) − (b1 )J ||f (y)|dy = |y−x0 |>d1−a ∞ XZ N =0 (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a |K(x, x − y) − K(x̃, x̃ − y)||b1 (y) − (b1 )J ||f (y)|dy MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS = ∞ Z X N =0 17 |K(x, x − y) − K(x̃, x̃ − y)| (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a × |b1 (y) − (b1 )2(N +1)(1−a) J ||f (y)|dy ∞ Z X + |K(x, x − y) − K(x̃, x̃ − y)| (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a N =0 × |(b1 )2(N +1)(1−a) J − (b1 )J ||f (y)|dy 1/2 ∞ Z X 2 ≤C |K(x, x − y) − K(x̃, x̃ − y)| dy (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a N =0 Z s × 1/s Z r |b1 (y) − (b1 )2(N +1)(1−a) J | dy |y−x̃|≤(2N +1 d)1−a ∞ Z X +C 1/r |f (y)| dy |y−x̃|≤(2N +1 d)1−a 2 1/2 |K(x, x − y) − K(x̃, x̃ − y)| dy (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a N =0 × ||b~1 ||Lipβ (2 N +1 β(1−a) d) N +1 (2 n(1−a)/s Z r 1/r |f (y)| dy d) |y−x̃|≤(2N +1 d)1−a ∞ X ≤C |x − x̃|(1−a)(h−n/2) (2N +1 d)−h(1−a)+n(1−a)/2 (2N +1 d)β(1−a) N =0 N +1 × (2 −β(1−a) d) N +1 (2 Z −n(1−a) s |b1 (y) − (b1 )2(N +1)(1−a) J | dy d) |y−x̃|≤(2N +1 d)1−a N +1 × (2 −n(1−a) Z 1/r r |f (y)| dy d) |y−x̃|≤(2N +1 d)1−a +C ∞ X |x − x̃|(1−a)(h−n/2) (2N +1 d)−h(1−a)+n(1−a)/2 N =0 N +1 × ||b1 ||Lipβ (2 β(1−a) d) N +1 (2 −n(1−a) Z r 1/r |f (y)| dy d) |y−x̃|≤(2N +1 d)1−a ≤C ∞ X d(1−a)(h−n/2) (2N +1 d)(1−a)(n/2−h) (2N +1 d)β(1−a) ||b1 ||Lipβ Mr (f )(x̃) N =0 +C ≤C ∞ X N =0 ∞ X d(1−a)(h−n/2) (2N +1 d)(1−a)(n/2−h) (2N +1 d)β(1−a) ||b1 ||Lipβ Mr (f )(x̃) 2(N +1)(1−a)(n/2−h+β) dβ(1−a) ||b1 ||Lipβ Mr (f )(x̃) N =0 β ≤ C|J| n ||b1 ||Lipβ Mr (f )(x̃) thus A1,3 ≤ C||b1 ||Lipβ Mr (f )(x̃). 1/s 18 Z. WANG, L. LIU Combining all the estimates, we finish the case m = 1 and d ≤ 1. In case m = 1 and d > 1, we proceeds the case as follows. Let f (x) = f1 (x) + f2R(x) with f1 (x) = f (x)χ2J (x) and f2 (x) = f (x)χ(2Q)c (x), and let (b1 )2Q = |2Q|−1 2Q b1 (y)dy. We have Z K(x, x − y)((b1 (x) − (b1 )2Q ) − (b1 (y) − (b1 )2Q ))f (y)dy Z = (b1 (x) − (b1 )2Q ) K(x, x − y)f (y)dy Rn Z − K(x, x − y)(b1 (y) − (b1 )2Q )f1 (y)dy n ZR − K(x, x − y)(b1 (y) − (b1 )2Q )f2 (y)dy Tb~1 (f )(x) = Rn Rn = (b1 (x) − (b1 )2Q )T (f )(x) − T ((b1 − (b1 )2Q )f1 )(x) − T ((b1 − (b1 )2Q )f2 )(x), thus β −1− n Z |Q| Q β −1− n |Tb~1 (f )(x)|dx Z ≤ |Q| |b1 (x) − (b1 )2Q ||T (f )(x)|dx Q β −1− n Z + |Q| |T ((b1 − (b1 )2Q )f1 )(x)|dx Q β −1− n Z + |Q| |T ((b1 − (b1 )2Q )f2 )(x)|dx Q = A2,1 + A2,2 + A2,3 . Similar to A1,1 , A2,1 ≤ C||b1 ||Lipβ Mr (T (f ))(x̃). Similar to A1,2 , A2,1 ≤ C||b1 ||Lipβ Mr (f )(x̃). For A2,3 , by Hölder’s inequality with exponent 1/r + 1/r0 = 1 and Lemma 4, 2, 1, we have Z |T ((b1 − (b1 )2Q )f2 )(x)| = K(x, x − y)(b1 (y) − (b1 )2Q )f2 (y)dy Rn Z ≤ |K(x, x − y)||b1 (y) − (b1 )2Q ||f (y)|dy |y−x̃|>2d Z ≤C |x − y|−2n |b1 (y) − (b1 )2Q ||f (y)|dy |y−x̃|>2d MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS ≤C ∞ Z X ≤C |x − y|−2n |b1 (y) − (b1 )2N +1 Q ||f (y)|dy 2N d≤|y−x̃|≤2N +1 d N =1 +C ∞ Z X |x − y|−2n |(b1 )2N +1 Q − (b1 )2Q ||f (y)|dy 2N d≤|y−x̃|≤2N +1 d N =1 ∞ X N +1 2 Z −2n+n N +1 β N +1 −β N +1 −n d (2 d) (2 d) (2 d) N +1 × (2 r 1/r |f (y)| dy |y−x̃|≤2N +1 d N =1 19 −n Z r0 1/r0 |b1 (y) − (b1 )2N +1 Q | dy d) |y−x̃|≤2N +1 d +C ≤C ∞ X N =1 ∞ X N +1 2 Z −2n+n N +1 −n (b1 )2N +1 Q − (b1 )2Q (2 d d) r 1/r |f (y)| dy |y−x̃|≤2N +1 d −n N +1 β 2N +1 d (2 d) ||b1 ||Lipβ Mr (f )(x̃) N =1 +C ≤C ≤C ∞ X N =1 ∞ X N =1 ∞ X −n N +1 β 2N +1 d (2 d) ||b1 ||Lipβ Mr (f )(x̃) 2(N +1)(−n+β) d−n+β ||b1 ||Lipβ Mr (f )(x̃) 2(N +1)(−n+β) dβ ||b1 ||Lipβ Mr (f )(x̃) N =1 β ≤ C|Q| n ||b1 ||Lipβ Mr (f )(x̃), thus A2,3 ≤ C||b1 ||Lipβ Mr (f )(x̃). Combining all the estimates, we finish the case m = 1 and d > 1. Now, we consider the case m ≥ 2 and d ≤ 1. Let f (x) = f1 (x) R + f2 (x) with f1 (x) = f (x)χJ (x) and f2 (x) = f (x)χJ c (x), and let (bj )J = |J|−1 J bj (y)dy for 1 ≤ j ≤ m, where J is a cube concentric with Q of side-length d1−a . Z T~b (f )(x) = = m Y K(x, x − y) ((bj (x) − (bj )J ) − (bj (y) − (bj )J ))f (y)dy Rn j=1 m X X j=0 γ∈Cjm m−j (−1) Z (b(x) − bJ )γ K(x, x − y)(b(y) − bJ )γ c f (y)dy Rn 20 Z. WANG, L. LIU Z m Y = (bj (x) − (bj )J ) j=1 + K(x, x − y)f (y)dy Rn m−1 X X m−j (−1) Z (b(x) − bJ )γ m m Y K(x, x − y) (bj (y) − (bj )J )f1 (y)dy Z +(−1) Rn +(−1)m K(x, x − y)(b(y) − bJ )γ c f (y)dy Rn j=1 γ∈Cjm Z K(x, x − y) Rn j=1 m Y (bj (y) − (bj )J )f2 (y)dy j=1 m Y = (bj (x) − (bj )J )T (f )(x) j=1 + m−1 X X j=1 γ∈Cjm (b(x) − bJ )γ T ((b − bJ )γ c f )(x) m Y +(−1)m T ( (bj − (bj )J )f1 )(x) j=1 m Y +(−1)m T ( (bj − (bj )J )f2 )(x), j=1 thus −1− mβ n m Y |T~b (f )(x) − T ( ((bj )J − bj )f2 )(x̃)|dx Z |Q| Q ≤ |Q|−1− mβ n j=1 Z Y m |bj (x) − (bj )J ||T (f )(x)|dx Q j=1 + m−1 X X Z −1− mβ n |Q| |(b(x) − bJ )γ ||T ((b − bJ )γ c f )(x)|dx Q j=1 γ∈Cjm −1− mβ n Z +|Q| Q −1− mβ n Z m Y |T ( (bj − (bj )J )f1 )(x)|dx j=1 m Y m Y (bj − (bj )J )f2 )(x) − T ( (bj − (bj )J )f2 )(x̃)|dx |T ( +|Q| Q j=1 = A3,1 + A3,2 + A3,3 + A3,4 . j=1 MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS 21 For A3,1 , by Hölder’s inequality with exponent 1/r1 + · · · + 1/rm + 1/r = 1 and Lemma 1, we have − mβ n A3,1 ≤ C|Q| m Y Z −1 |J| |bj (x) − (bj )J | dx ≤C ≤C j=1 m Y −β/n |J| −1 Z |Q| rj 1/rj |bj (x) − (bj )J | dx) (|J| 1/r Q Z −1 r |T (f )(x)| dx J j=1 m Y 1/rj rj 1/r Z −1 r |Q| |T (f )(x)| dx J Q ||bj ||Lipβ Mr (T (f ))(x̃) j=1 ≤ C||~b||Lipβ Mr (T (f ))(x̃). For A3,2 , by Hölder’s inequality with exponent 1/s + 1/s0 = 1 and 1/t + 1/t0 = 1, such that st = r, and Lemma 1, 6, 7, we have A3,2 ≤ C m−1 X − mβ n X |Q| −1 Z |J| |(b(x) − bJ )γ | dx J j=1 γ∈Cjm −1 1/s0 s0 Z 1/s s × |Q| |T ((b − bJ )γ c f )(x)| χQ (x)dx Rn ≤ C m−1 X − mβ n X |Q| −1 Z |J| |(b(x) − bJ )γ | dx J j=1 γ∈Cjm −1 1/s0 s0 Z s × |Q| 1/s s |(b(x) − bJ )γ c | |f (x)| χQ (x)dx Rn ≤ C m−1 X X j=1 γ∈Cjm −1 − mβ n |Q| −1 Z s0 |J| 1/s0 |(b(x) − bJ )γ | dx J Z s × |Q| s 1/s |(b(x) − bJ )γ c | |f (x)| dx Q ≤ C m−1 X X − jβ n |J| −1 |J| ×|J| (m−j)β n s0 |(b(x) − bJ )γ | dx −1 Z |J| st0 |(b(x) − bJ )γ c | dx J ≤ C m−1 X X 1/s0 J j=1 γ∈Cjm − Z ||b~γ ||Lipβ ||b~γ c ||Lipβ Mr (f )(x̃) j=1 γ∈Cjm ≤ C||~b||Lipβ Mr (f )(x̃). 1/st0 −1 Z |Q| st |f (x)| dx Q 1/st 22 Z. WANG, L. LIU For A3,3 , by Hölder’s inequality with exponent 1/s + 1/s0 = 1 and 1/t1 + · · · + 1/tm + 1/t = 1, such that st = r, and Lemma 1, 7, we have !1/s Z m Y 0 −1− mβ s n A3,3 ≤ C|Q| |T ( (bj − (bj )J )f1 )(x)| dx |Q|1/s Rn !1/s m Y Z −1− mβ n j=1 ≤ C|Q| |bj (x) − (bj )J |s |f1 (x)|s dx |Q|1/s 0 Rn j=1 Z Y m −1− mβ n ≤ C|Q| !1/s |bj (x) − (bj )J |s |f (x)|s dx |Q|1/s 0 J j=1 −1− mβ n 1/s ≤ C|Q| |Q| m Y −1 |J| −1 Z × |Q| stj 1/stj |bj (x) − (bj )J | dx J j=1 Z 1/st st |f (x)| dx |Q|1/s 0 Q ≤ C m Y β −n |J| −1 Z 1/stj |bj (x) − (bj )J | dx) (|J| J j=1 stj −1 Z × |Q| st 1/st |f (x)| dx Q ≤ C m Y ||bj ||Lipβ Mr (f )(x̃) j=1 ≤ C||~b||Lipβ Mr (f )(x̃). For A3,4 , choose h such that n/2 < h < n/2 + 1/(1 − a) and n/2 − h + mβ < 0. By Hölder’s inequality with exponent 1/s + 1/r + 1/2 = 1 and Lemma 1, 2, 3, we have m m Y Y T ( (bj − (bj )J )f2 )(x) − T ( (bj − (bj )J )f2 )(x̃) j=1 j=1 Z m Y = (K(x, x − y) − K(x̃, x̃ − y)) (bj (y) − (bj )J )f2 (y)dy Rn j=1 Z m Y ≤ |K(x, x − y) − K(x̃, x̃ − y)| |bj (y) − (bj )J ||f (y)|dy |y−x̃|>d1−a ≤ ∞ X j=1 Z |K(x, x − y) − K(x̃, x̃ − y)| N 1−a ≤|y−x̃|≤(2N +1 d)1−a N =0 (2 d) m Y × |bj (y) − (bj )J ||f (y)|dy j=1 MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS ≤ ∞ Z X |K(x, x − y) − K(x̃, x̃ − y)| (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a N =0 m Y × (|bj (y) − (bj )2(N +1)(1−a) J | + |(bj )2(N +1)(1−a) J − (bj )J |) |f (y)|dy j=1 ≤ ∞ X m X X N =0 j=0 |(b2(N +1)(1−a) J − bJ )γ | γ∈Cjm Z |K(x, x − y) − K(x̃, x̃ − y)| × (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a ×|(b(y) − b2(N +1)(1−a) J )γ c ||f (y)|dy ∞ X m X X ≤ C ||b~γ ||Lipβ (2N +1 d)j(1−a)β N =0 j=0 γ∈Cjm Z 1/2 2 × |K(x, x − y) − K(x̃, x̃ − y)| dy (2N d)1−a ≤|y−x̃|≤(2N +1 d)1−a Z 1/s s × |(b(y) − b2(N +1)(1−a) J )γ c | dy |y−x̃|≤(2N +1 d)1−a Z r |f (y)| dy × ≤ C 1/r |y−x̃|≤(2N +1 d)1−a ∞ X m X X ||b~γ ||Lipβ (2N +1 d)j(1−a)β N =0 j=0 γ∈Cjm ×|x − x̃|(1−a)(h−n/2) (2N +1 d)−h(1−a)+n(1−a)/2 (2N +1 d)(m−j)(1−a)β ×(2N +1 d)−(m−j)(1−a)β Z N +1 −n(1−a) × (2 d) s 1/s |(b(y) − b2(N +1)(1−a) J )γ c | dy |y−x̃|≤(2N +1 d)1−a N +1 × (2 −n(1−a) Z r 1/r |f (y)| dy d) |y−x̃|≤(2N +1 d)1−a ≤ C ∞ X m X X ||b~γ ||Lipβ (2N +1 d)j(1−a)β d(1−a)(h−n/2) (2N +1 d)(1−a)(n/2−h) N =0 j=0 γ∈Cjm ×(2N +1 d)(m−j)(1−a)β ||b~γ c ||Lipβ Mr (f )(x̃) ∞ X m X X ≤ C 2(N +1)(1−a)(n/2−h+mβ) dm(1−a)β ||~b||Lipβ Mr (f )(x̃) N =0 j=0 γ∈Cjm ≤ C|J| mβ n ||~b||Lipβ Mr (f )(x̃), thus A3,4 ≤ C||~b||Lipβ Mr (f )(x̃). 23 24 Z. WANG, L. LIU Combining all the estimates, we finish the case m ≥ 2 and d ≤ 1. In case m ≥ 2 and d > 1, we proceeds the case as follows. Let f (x) = f1 (x) + f2R(x), with f1 (x) = f (x)χ2Q (x) and f2 (x) = f (x)χ(2Q)c (x), and let (bj )2Q = |2Q|−1 2Q bj (y)dy for 1 ≤ j ≤ m. m Y (bj (x) − (bj )2Q )T (f )(x) T~b (f )(x) = j=1 + m−1 X X (b(x) − b2Q )γ T ((b − b2Q )γ c f )(x) j=1 γ∈Cjm m Y +(−1) T ( (bj − (bj )2Q )f1 )(x) m j=1 m Y +(−1)m T ( (bj − (bj )2Q )f2 )(x), j=1 thus −1− mβ n Z |Q| |T~b (f )(x)|dx Q −1− mβ n ≤ |Q| Z Y m |bj (x) − (bj )2Q ||T (f )(x)|dx Q j=1 + m−1 X X j=1 γ∈Cjm −1− mβ n |Q| Z Q mβ n |(b(x) − b2Q )γ ||T ((b − b2Q )γ c f )(x)|dx Q +|Q| +|Q|−1− Z −1− mβ n Z m Y |T ( (bj − (bj )2Q )f1 )(x)|dx j=1 m Y |T ( Q (bj − (bj )2Q )f2 )(x)|dx j=1 = A4,1 + A4,2 + A4,3 + A4,4 . Similar to A3,1 , A4,1 ≤ C||~b||Lipβ Mr (T (f ))(x̃). Similar to A3,2 , A4,2 ≤ C||~b||Lipβ Mr (f )(x̃). Similar to A3,3 , A4,3 ≤ C||~b||Lipβ Mr (f )(x̃). For A4,4 , by Hölder’s inequality with exponent 1/r + 1/r0 = 1 and Lemma 1, 2, 4, we have m Y T ( (bj − (bj )2Q )f2 )(x) j=1 MULTILINEAR COMMUTATOR OF PSEUDO-DIFFERENTIAL OPERATORS Z m Y = K(x, x − y) (bj (y) − (bj )2Q )f2 (y)dy Rn j=1 Z m Y ≤ |K(x, x − y)| |bj (y) − (bj )2Q ||f (y)|dy |y−x̃|>2d Z j=1 m Y |x − y|−2n ≤ C |bj (y) − (bj )2Q ||f (y)|dy |y−x̃|>2d ≤ C ≤ C j=1 ∞ Z X N =1 ∞ X −2n |x − y| 2N d≤|y−x̃|≤2N +1 d m Y |bj (y) − (bj )2Q ||f (y)|dy j=1 (2N +1 d)−2n N =1 m Y (|bj (y) − (bj )2N +1 Q | + |(bj )2N +1 Q − (bj )2Q |)|f (y)|dy Z × ≤ C 2N d≤|y−x̃|≤2N +1 d j=1 ∞ X m X X N +1 −2n (2 d) |(b2N +1 Q − b2Q )γ | γ∈Cjm N =1 j=0 Z |(b(y) − b2N +1 Q )γ c ||f (y)|dy × ≤ C |y−x̃|≤2N +1 d ∞ X m X X (2N +1 d)−2n+n ||b~γ ||Lipβ (2N +1 d)jβ (2N +1 d)(m−j)β N =1 j=0 γ∈Cjm N +1 ×(2 −(m−j)β d) N +1 (2 −n Z r0 |(b(y) − b2N +1 Q )γ c | dy d) |y−x̃|≤2N +1 d N +1 × (2 −n Z r 1/r |f (x)| dy d) |y−x̃|≤2N +1 d ≤ C ∞ X m X X (2N +1 d)−n ||b~γ ||Lipβ (2N +1 d)mβ ||b~γ c ||Lipβ Mr (f )(x̃) N =1 j=0 γ∈Cjm ≤ C ∞ X m X X 2(N +1)(−n+mβ) d−n+mβ ||~b||Lipβ Mr (f )(x̃) N =1 j=0 γ∈Cjm ≤ C ∞ X m X X 2(N +1)(−n+mβ) dmβ ||~b||Lipβ Mr (f )(x̃) N =1 j=0 γ∈Cjm ≤ C ∞ X m X X 2(N +1)(−n+mβ) |Q| N =1 j=0 γ∈Cjm ≤ C|Q| mβ n ||~b||Lipβ Mr (f )(x̃), mβ n ||~b||Lipβ Mr (f )(x̃) 1/r0 25 26 Z. WANG, L. LIU thus A4,4 ≤ C||~b||Lipβ Mr (f )(x̃). Combining all the estimates, we finish the case m ≥ 2 and d > 1. So, for any cube Q and c ∈ CQ and 1 < r < ∞ and f ∈ Lp , Z −1− mβ n |Q| |T~b (x) − c|dx ≤ C||~b||Lipβ (Mr (T (f ))(x̃) + Mr (f )(x̃)) , Q thus −1− mβ n Z |T~b (x) − c|dx ≤ C||~b||Lipβ (Mr (T (f ))(x̃) + Mr (f )(x̃)) . sup inf |Q| Q3x̃ c∈CQ Q By Minkowski’s inequality and Lemma 7, 8, we have Z −1− mβ n ||T~b (f )||F̃pmβ,∞ ≈ sup inf |Q| |T~b (f )(x) − c|dx Q3x̃ c∈CQ Q Lp ≤ C||~b||Lipβ (||Mr (T (f ))(x̃)||Lp + C||Mr (f )(x̃)||Lp ) ≤ C||~b||Lip (||T (f )||Lp + ||f ||Lp ) β ≤ C||~b||Lipβ ||f ||Lp . This completes the proof of Theorem 1. 5. Proof of Theorem 2 Proof. Similar to Theorem 1, we can prove that there exists some constant c and 1 < r < ∞, such that for f ∈ Lp , Z −1 |Q| |T~b (x) − c|dx ≤ C||~b||Lipβ (Mr,mβ (T (f ))(x̃) + Mr,mβ (f )(x̃)) . Q Further, we have (T~b (f ))# (x̃) ≤ C||~b||Lipβ (Mr,mβ (T (f ))(x̃) + Mr,mβ (f )(x̃)). 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