LAST NAME : FIRST NAME : QUIZ 4, Version A, MATH 251, Section 505 last name : . . . . . . . . first name : . . . . . . . . GRADE : . . . . . . . . ”An Aggie does not lie, cheat or steal, or tolerate those who do” signature : . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Write up your result, detail your calculations if necessary and BOX your final answer 1. [50pts] Evaluate the work of the force F (x, y) = h2xy, y 2 i along the parabola y = x2 + 1 from (−1, 2) to (1, 2). 2. [50pts] Compute the line integral R C x2 yds where C is the first quadrant of the circle x2 + y 2 = 2. R 1. The work of F along the part of the parabola denoted, C is C F.dr. Let’s parametrize C, r(t) =< t, t2 + 1 > for increasing t from −1 to 1. Z Z 1 1 F (r(t)).r (t)dt = F.dr = C Z 0 < 2t(t2 + 1), (t2 + 1)2 > . < 1, 2t > dt, −1 −1 Z 1 (t2 + 1)3 (t2 + 1)2 = 2t(t + 1) + 2t(t + 1) dt = + 3 2 −1 2 2 2 1 , −1 = 0. 2. It’s with respect the arc length. The part of √ √ an integral √ the circle C is parametrized by r(t) =< π 0 2 cos t, 2 sin t >, 0 ≤ t ≤ 2 . We have ds = |r (t)|dt = 2dt, Z Z 2 y xds = C π 2 0 = 4 . 3 cos3 t 2.2 cos t sin tdt = 4 − 3 2 π2 , 0