Hindawi Publishing Corporation International Journal of Mathematics and Mathematical Sciences Volume 2013, Article ID 238490, 6 pages http://dx.doi.org/10.1155/2013/238490 Research Article On Symmetric Left Bi-Derivations in BCI-Algebras G. Muhiuddin,1 Abdullah M. Al-roqi,1 Young Bae Jun,2 and Yilmaz Ceven3 1 Department of Mathematics, University of Tabuk, Tabuk 71491, Saudi Arabia Department of Mathematics Education (and RINS), Gyeongsang National University, Jinju 660-701, Republic of Korea 3 Department of Mathematics, Faculty of Science, Suleyman Demirel University, 32260 Isparta, Turkey 2 Correspondence should be addressed to G. Muhiuddin; chishtygm@gmail.com Received 15 February 2013; Accepted 30 May 2013 Academic Editor: Aloys Krieg Copyright © 2013 G. Muhiuddin et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. The notion of symmetric left bi-derivation of a BCI-algebra X is introduced, and related properties are investigated. Some results on componentwise regular and d-regular symmetric left bi-derivations are obtained. Finally, characterizations of a p-semisimple BCI-algebra are explored, and it is proved that, in a p-semisimple BCI-algebra, F is a symmetric left bi-derivation if and only if it is a symmetric bi-derivation. 1. Introduction BCK-algebras and BCI-algebras are two classes of nonclassical logic algebras which were introduced by Imai and IseΜki in 1966 [1, 2]. They are algebraic formulation of BCK-system and BCI-system in combinatory logic. Later on, the notion of BCI-algebras has been extensively investigated by many researchers (see [3–6], and references therein). The notion of a BCI-algebra generalizes the notion of a BCK-algebra in the sense that every BCK-algebra is a BCI-algebra but not vice versa (see [7]). Hence, most of the algebras related to the π‘-norm-based logic such as MTL [8], BL, hoop, MV [9] (i.e lattice implication algebra), and Boolean algebras are extensions of BCK-algebras (i.e. they are subclasses of BCK-algebras) which have a lot of applications in computer science (see [10]). This shows that BCK-/BCI-algebras are considerably general structures. Throughout our discussion, π will denote a BCI-algebra unless otherwise mentioned. In the year 2004, Jun and Xin [11] applied the notion of derivation in ring and near-ring theory to π΅πΆπΌ-algebras, and as a result they introduced a new concept, called a (regular) derivation, in π΅πΆπΌ-algebras. Using this concept as defined they investigated some of its properties. Using the notion of a regular derivation, they also established characterizations of a π-semisimple π΅πΆπΌalgebra. For a self-map π of a π΅πΆπΌ-algebra, they defined a πinvariant ideal and gave conditions for an ideal to be πinvariant. According to Jun and Xin, a self map π : π → π is called a left-right derivation (briefly (π, π)-derivation) of π if π(π₯ ∗ π¦) = π(π₯) ∗ π¦ ∧ π₯ ∗ π(π¦) holds for all π₯, π¦ ∈ π. Similarly, a self map π : π → π is called a right-left derivation (briefly (π, π)-derivation) of π if π(π₯ ∗ π¦) = π₯ ∗ π(π¦) ∧ π(π₯) ∗ π¦ holds for all π₯, π¦ ∈ π. Moreover, if π is both (π, π)- and (π, π)-derivation, it is a derivation on π. After the work of Jun and Xin [11], many research articles have appeared on the derivations of BCI-algebras and a greater interest has been devoted to the study of derivations in BCIalgebras on various aspects (see [12–17]). Inspired by the notions of π-derivation [18], left derivation [19], and symmetric bi-derivations [20, 21] in rings and near-rings theory, many authors have applied these notions in a similar way to the theory of BCI-algebras (see [12, 13, 17]). For instantce in 2005 [17], Zhan and Liu have given the notion of π-derivation of BCI-algebras as follows: a self map ππ : π → π is said to be a left-right π-derivation or (π, π)-π-derivation of π if it satisfies the identity ππ (π₯ ∗ π¦) = ππ (π₯) ∗ π(π¦) ∧ π(π₯) ∗ ππ (π¦) for all π₯, π¦ ∈ π. Similarly, a self map ππ : π → π is said to be a rightleft π-derivation or (π, π)-π-derivation of π if it satisfies the identity ππ (π₯ ∗ π¦) = π(π₯) ∗ ππ (π¦) ∧ ππ (π₯) ∗ π(π¦) for all π₯, π¦ ∈ π. Moreover, if ππ is both (π, π)- and (π, π)-π-derivation, it is said that ππ is an π-derivation, where π is an endomorphism. In the year 2007, Abujabal and Al-Shehri [12] defined and studied the notion of left derivation of BCIalgebras as follows: a self map π· : π → π is said to be a left 2 International Journal of Mathematics and Mathematical Sciences derivation of π if satisfying π·(π₯∗π¦) = π₯∗π·(π¦)∧π¦∗π·(π₯) for all π₯, π¦ ∈ π. Furthermore, in 2011 [13], Ilbira et al. have introduced the notion of symmetric bi-derivations in BCIalgebras. Following [13], a mapping π·(⋅, ⋅) : π × π → π is said to be symmetric if πΉ(π₯, π¦) = πΉ(π¦, π₯) holds for all pairs π₯, π¦ ∈ π. A symmetric mapping π·(⋅, ⋅) : π × π → π is called left-right symmetric bi-derivation (briefly (π, π)symmetric bi-derivation) if it satisfies the identity π·(π₯ ∗ π¦, π§) = π·(π₯, π§)∗π¦∧π₯∗π·(π¦, π§) for all π₯, π¦, π§ ∈ π. π· is called right-left symmetric bi-derivation (briefly (π, π)-symmetric bi-derivation) if it satisfies the identity π·(π₯ ∗ π¦, π§) = π₯ ∗ π·(π¦, π§) ∧ π·(π₯, π§) ∗ π¦ for all π₯, π¦, π§ ∈ π. Moreover, if π· is both a (π, π)- and a (π, π)-symmetric bi-derivation, it is said that π· is a symmetric bi-derivation on π. Motivated by the notion of symmetric bi-derivations [13] in the theory of π΅πΆπΌ-algebras, in the present analysis, we introduced the notion of symmetric left bi-derivations on π΅πΆπΌ-algebras and investigated related properties. Further, we obtain some results on componentwise regular and πregular symmetric left bi-derivations. Finally, we characterize the notion of π-semisimple BCI-algebra π by using the concept of symmetric left bi-derivation and show that, in a π-semisimple π΅πΆπΌ-algebra π, πΉ is a symmetric left biderivation if and only if it is a symmetric bi-derivation. 2. Preliminaries We begin with the following definitions and properties that will be needed in the sequel. A nonempty set π with a constant 0 and a binary operation ∗ is called a π΅πΆπΌ-algebra if for all π₯, π¦, π§ ∈ π the following conditions hold: (I) ((π₯ ∗ π¦) ∗ (π₯ ∗ π§)) ∗ (π§ ∗ π¦) = 0, (II) (π₯ ∗ (π₯ ∗ π¦)) ∗ π¦ = 0, (III) π₯ ∗ π₯ = 0, (IV) π₯ ∗ π¦ = 0 and π¦ ∗ π₯ = 0 imply π₯ = π¦. Define a binary relation ≤ on π by letting π₯ ∗ π¦ = 0 if and only if π₯ ≤ π¦. Then (π, ≤) is a partially ordered set. A BCI-algebra π satisfying 0 ≤ π₯ for all π₯ ∈ π is called BCKalgebra. A π΅πΆπΌ-algebra π has the following properties for all π₯, π¦, π§ ∈ π. (a1) π₯ ∗ 0 = π₯. (a2) (π₯ ∗ π¦) ∗ π§ = (π₯ ∗ π§) ∗ π¦. (a3) π₯ ≤ π¦ implies π₯ ∗ π§ ≤ π¦ ∗ π§ and π§ ∗ π¦ ≤ π§ ∗ π₯. If π+ = {0}, then π is called a π-semisimple π΅πΆπΌ-algebra. In a π-semisimple π΅πΆπΌ-algebra π, the following hold. (a8) (π₯ ∗ π§) ∗ (π¦ ∗ π§) = π₯ ∗ π¦. (a9) 0 ∗ (0 ∗ π₯) = π₯ for all π₯ ∈ π. (a10) π₯ ∗ (0 ∗ π¦) = π¦ ∗ (0 ∗ π₯). (a11) π₯ ∗ π¦ = 0 implies π₯ = π¦. (a12) π₯ ∗ π = π₯ ∗ π implies π = π. (a13) π ∗ π₯ = π ∗ π₯ implies π = π. (a14) π ∗ (π ∗ π₯) = π₯. (a15) (π₯ ∗ π¦) ∗ (π€ ∗ π§) = (π₯ ∗ π€) ∗ (π¦ ∗ π§). Let π be a π-semisimple π΅πΆπΌ-algebra. We define addition “+” as π₯ + π¦ = π₯ ∗ (0 ∗ π¦) for all π₯, π¦ ∈ π. Then (π, +) is an abelian group with identity 0 and π₯−π¦ = π₯ ∗ π¦. Conversely, let (π, +) be an abelian group with identity 0, and let π₯ ∗ π¦ = π₯ − π¦. Then π is a π-semisimple π΅πΆπΌ-algebra and π₯ + π¦ = π₯ ∗ (0 ∗ π¦) for all π₯, π¦ ∈ π (see [6]). For a π΅πΆπΌ-algebra π, we denote π₯ ∧ π¦ = π¦ ∗ (π¦ ∗ π₯), in particular 0 ∗ (0 ∗ π₯) = ππ₯ , and πΏ π (π) := {π ∈ π | π₯ ∗ π = 0 ⇒ π₯ = π, ∀π₯ ∈ π}. We call the elements of πΏ π (π) the πatoms of π. For any π ∈ π, let π(π) := {π₯ ∈ π | π ∗ π₯ = 0}, which is called the branch of π with respect to π. It follows that π₯ ∗ π¦ ∈ π(π ∗ π) whenever π₯ ∈ π(π) and π¦ ∈ π(π) for all π₯, π¦ ∈ π and all π, π ∈ πΏ π (π). Note that πΏ π (π) = {π₯ ∈ π | ππ₯ = π₯},which is the π-semisimple part of π, and π is a π-semisimple π΅πΆπΌ-algebra if and only if πΏ π (π) = π (see [23, Proposition 3.2]). Note also that ππ₯ ∈ πΏ π (π); that is, 0 ∗ (0∗ππ₯ ) = ππ₯ , which implies that ππ₯ ∗π¦ ∈ πΏ π (π) for all π¦ ∈ π. It is clear that πΊ(π) ⊂ πΏ π (π), and π₯ ∗ (π₯ ∗ π) = π and π ∗ π₯ ∈ πΏ π (π) for all π ∈ πΏ π (π) and all π₯ ∈ π. Let π·(⋅, ⋅) : π × π → π be a symmetric mapping. Then for all π₯ ∈ π, a mapping π : π → π defined by π(π₯) = π·(π₯, π₯) is called trace of π· [13]. For more details, refer to [3, 4, 6, 11, 22, 23]. 3. Symmetric Left Bi-Derivations The following definition introduces the notion of symmetric left bi-derivation for a BCI-algebra π. Definition 1. A symmetric mapping πΉ(⋅, ⋅) : π × π → π is called a symmetric left bi-derivation of π if it satisfies the following identity: (∀π₯, π¦, π§ ∈ π) (πΉ (π₯ ∗ π¦, π§) = (π₯ ∗ πΉ (π¦, π§)) ∧ (π¦ ∗ πΉ (π₯, π§))) . (a4) (π₯ ∗ π§) ∗ (π¦ ∗ π§) ≤ π₯ ∗ π¦. (a5) π₯ ∗ (π₯ ∗ (π₯ ∗ π¦)) = π₯ ∗ π¦. (a6) 0 ∗ (π₯ ∗ π¦) = (0 ∗ π₯) ∗ (0 ∗ π¦). (a7) π₯ ∗ 0 = 0 implies π₯ = 0. For a π΅πΆπΌ-algebra π, denote by π+ (resp., πΊ(π)) the π΅πΆπΎ-part (resp., the π΅πΆπΌ-G part) of π; that is, π+ is the set of all π₯ ∈ π such that 0 ≤ π₯ (resp., πΊ(π) := {π₯ ∈ π | 0 ∗ π₯ = π₯}). Note that πΊ(π) ∩ π+ = {0} (see [22]). (1) Example 2 (see [24]). Consider a π-semisimple π΅πΆπΌ-algebra π = {0, 3, 4, 5} with the following Cayley table: ∗ 0 3 4 5 0 0 3 4 5 3 3 0 5 4 4 4 5 0 3 5 5 4 3 0 (2) International Journal of Mathematics and Mathematical Sciences Define a mapping πΉ(⋅, ⋅) : π × π → π by Using Theorem 3, we have the following corollary. πΉ (0, 0) = πΉ (3, 3) = πΉ (4, 4) = πΉ (5, 5) = 0, Corollary 4. Let πΉ(⋅, ⋅) : π × π → π be a symmetric left bi-derivation and π : π → π be the trace of πΉ. Then πΉ (0, 3) = πΉ (3, 0) = 3, πΉ (0, 4) = πΉ (4, 0) = 4, πΉ (0, 5) = πΉ (5, 0) = 5, (3) πΉ (3, 4) = πΉ (4, 3) = 5, πΉ (4, 5) = πΉ (5, 4) = 3. It is routine to verify that πΉ is a symmetric left biderivation of π. Theorem 3. Let πΉ(⋅, ⋅) : π × π → π be a symmetric left biderivation of π. Then (1) (∀π§ ∈ π) (π ∈ πΊ(π) ⇒ πΉ(π, π§) ∈ πΊ(π)). (2) (∀π§ ∈ π) (π ∈ πΏ π (π) ⇒ πΉ(π, π§) ∈ πΏ π (π)). (3) (∀π§ ∈ π) (π ∈ πΏ π (π) ⇒ πΉ(π, π§) = 0 + πΉ(π, π§)). (4) (∀π§ ∈ π) (π ∈ πΏ π (π) ⇒ πΉ(π, π§) = π ∗ πΉ(0, π§) = π + πΉ(0, π§)). Proof. (1) Let π ∈ πΊ(π). Then 0 ∗ π = π, and so (1) (∀π§ ∈ π) (π, π ∈ πΏ π (π) ⇒ πΉ(π + π, π§) = π + πΉ(π, π§)). (2) (∀π§ ∈ π) (π ∈ πΏ π (π) ⇒ πΉ(π, π§) = π if and only if πΉ(0, π§) = 0). (3) (∀π₯, π¦, π§ ∈ π) (πΉ(π₯ ∗ π¦, π§) ≤ π₯ ∗ πΉ(π¦, π§)). (4) (∀π₯, π¦, π§ ∈ π) (π₯ ∗ πΉ(π₯, π§) = π¦ ∗ πΉ(π¦, π§)). Proof. (1) Let π, π ∈ πΏ π (π). Then πΉ (π + π, π§) = πΉ (π ∗ (0 ∗ π) , π§) = π ∗ πΉ (0 ∗ π, π§) ∧ (0 ∗ π) ∗ πΉ (π, π§) (8) = π ∗ (0 ∗ πΉ (π, π§) ∧ π ∗ πΉ (0, π§)) = (0 ∗ πΉ (π, π§)) ∧ (π ∗ πΉ (0, π§)) = (π ∗ πΉ (0, π§)) ∗ ((π ∗ πΉ (0, π§)) ∗ (0 ∗ πΉ (π, π§))) = 0 ∗ πΉ (π, π§) , (4) since 0 ∗ πΉ(π, π§) ∈ πΏ π (π). Hence πΉ(π, π§) ∈ πΊ(π). (2) For any π ∈ πΏ π (π) implies π = 0 ∗ (0 ∗ π) and so = π ∗ (0 ∗ πΉ (π, π§)) = π + πΉ (π, π§) . (2) Suppose πΉ(π, π§) = π for all π ∈ πΏ π (π), π§ ∈ π. It is clear that, for 0 ∈ πΏ π (π), we have πΉ(0, π§) = 0. Conversely let us assume that πΉ(0, π§) = 0; then by using Theorem 3(4), we have πΉ(π, π§) = π + πΉ(0, π§) = π + 0 = π. (3) For any π₯, π¦, π§ ∈ π, we have πΉ (π₯ ∗ π¦, π§) = (π₯ ∗ πΉ (π¦, π§)) ∧ (π¦ ∗ πΉ (π₯, π§)) πΉ (π, π§) = πΉ (0 ∗ (0 ∗ π) , π§) = (π¦ ∗ πΉ (π₯, π§)) = (0 ∗ πΉ (0 ∗ π, π§)) ∧ ((0 ∗ π) ∗ πΉ (0, π§)) (5) ∗ ((π¦ ∗ πΉ (π₯, π§)) ∗ (π₯ ∗ πΉ (π¦, π§))) (9) ≤ π₯ ∗ πΉ (π¦, π§) . ∗ (((0 ∗ π) ∗ πΉ (0, π§)) ∗ (0 ∗ πΉ (0 ∗ π, π§))) = 0 ∗ πΉ (0 ∗ π, π§) ∈ πΏ π (π) . (4) For any π₯, π§ ∈ π, we have (3) By (2), we have πΉ(π, π§) ∈ πΏ π (π). Then πΉ (0, π§) = πΉ (π₯ ∗ π₯, π§) = (π₯ ∗ πΉ (π₯, π§)) ∧ (π₯ ∗ πΉ (π₯, π§)) (6) (4) For any π ∈ πΏ π (π) and π§ ∈ π, we have = π₯ ∗ πΉ (π₯, π§) . (10) Thus, we can write πΉ(0, π§) = π₯ ∗ πΉ(π₯, π§) = π¦ ∗ πΉ(π¦, π§) for any π¦ ∈ π. This completes the proof. πΉ (π, π§) = πΉ (π ∗ 0, π§) = (π ∗ πΉ (0, π§)) ∧ (0 ∗ πΉ (π, π§)) = (0 ∗ πΉ (π, π§)) ∗ ((0 ∗ πΉ (π, π§)) ∗ (π ∗ πΉ (0, π§))) = π ∗ πΉ (0, π§) = π ∗ (0 ∗ πΉ (0, π§)) = π + πΉ (0, π§) . (7) This completes the proof. (2) (∀π ∈ πΏ π (π)) (π(π) ∈ πΏ π (π)). = π ∗ πΉ (0 ∗ π, π§) πΉ (π, π§) = πΉ (0 ∗ π, π§) πΉ (π, π§) = 0 ∗ (0 ∗ πΉ (π, π§)) = 0 + πΉ (π, π§) . (1) (∀π ∈ πΊ(π)) (π(π) ∈ πΊ(π)). Theorem 5. Let πΉ be a symmetric left bi-derivation of π. Then πΉ (3, 5) = πΉ (5, 3) = 4, = ((0 ∗ π) ∗ πΉ (0, π§)) 3 Definition 6. A symmetric left bi-derivation πΉ(⋅, ⋅) : π×π → π of a π΅πΆπΌ-algebra π is said to be componentwise regular if πΉ(0, π§) = 0 for all π§ ∈ π. In particular, πΉ is called πregular if πΉ(0, 0) = π(0) = 0. Theorem 7. Let πΉ be a symmetric left bi-derivation of π΅πΆπΌalgebra π. Then π is a π΅πΆπΎ-algebra if and only if πΉ is componentwise regular symmetric left bi-derivation. 4 International Journal of Mathematics and Mathematical Sciences Proof. Suppose π is a π΅πΆπΎ-algebra. Then for any π₯, π§ ∈ π, we have πΉ (0, π§) = πΉ (0 ∗ π₯, π§) = (0 ∗ πΉ (π₯, π§)) ∧ (π₯ ∗ πΉ (0, π§)) πΉ (π₯, π§) ∗ π¦ ≤ π₯ ∗ π¦ ≤ π₯ ∗ πΉ (π¦, π§) . (11) = 0 ∧ (π₯ ∗ πΉ (0, π§)) = 0. Hence πΉ is componentwise regular. Conversely, let πΉ be a componentwise regular symmetric left bi-derivation. Let for any π ∈ πΏ π (π) be such that π =ΜΈ 0. Then πΉ (π ∗ 0, 0) = πΉ (π, 0) = 0. (12) (16) This completes the proof. Next, we prove some results in a π-semisimple π΅πΆπΌalgebra. Theorem 9. Let πΉ be a symmetric left bi-derivation of a πsemisimple π΅πΆπΌ-algebra π; one has the following assertions. (1) (∀π₯, π¦, π§ ∈ π) (πΉ(π₯ ∗ π¦, π§) = π₯ ∗ πΉ(π¦, π§)). (2) (∀π₯, π¦, π§ ∈ π) (πΉ(π₯, π§) ∗ π₯ = πΉ(π¦, π§) ∗ π¦). But it is clear that (3) (∀π₯, π¦, π§ ∈ π) (πΉ(π₯, π§) ∗ π₯ = π¦ ∗ πΉ(π¦, π§)). π ∗ πΉ (0, 0) ∧ 0 ∗ πΉ (π, 0) = π ∗ 0 ∧ 0 ∗ 0 = π ∧ 0 = 0 ∗ (0 ∗ π) (13) = π =ΜΈ 0, which is not possible as πΉ is a componentwise regular symmetric left bi-derivation. Thus 0 is the unique π-atom. Assume that for some π ∈ π, we have 0∗π =ΜΈ 0, then π0∗π = 0 ∗ (0 ∗ (0 ∗ π)) = 0, so 0 ∗ π ∈ πΏ π (π), which is a contradiction. Henceforth, for all π ∈ π, we have 0 ∗ π = 0 implying thereby, π is a π΅πΆπΎ-algebra. This completes the proof. Theorem 8. Let πΉ be a componentwise regular symmetric left bi-derivation of a π΅πΆπΌ-algebra π. Then (1) Both π₯ and πΉ(π₯, π§) belong to the same branch for all π₯, π§ ∈ π. (2) (∀π₯, π§ ∈ π) (πΉ(π₯, π§) ≤ π₯). (14) since ππ₯ ∗ πΉ(π₯, π§) ∈ πΏ π (π). Hence ππ₯ ≤ πΉ(π₯, π§), and so πΉ(π₯, π§) ∈ π(ππ₯ ). Obviously, π₯ ∈ π(ππ₯ ). (2) Since πΉ is componentwise regular, πΉ(0, π§) = 0. Then πΉ (π₯, π§) = πΉ (π₯ ∗ 0, π§) = (π₯ ∗ πΉ (0, π§)) ∧ (0 ∗ πΉ (π₯, π§)) = (0 ∗ πΉ (π₯, π§)) ∗ ((0 ∗ πΉ (π₯, π§)) ∗ π₯) (π₯ ∗ π¦) ∗ (π₯ ∗ πΉ (π¦, π§)) ≤ πΉ (π¦, π§) ∗ π¦, (π¦ ∗ π₯) ∗ (π¦ ∗ πΉ (π₯, π§)) ≤ πΉ (π₯, π§) ∗ π₯. (18) These above inequalities can be rewritten as ((π₯ ∗ π¦) ∗ (π₯ ∗ πΉ (π¦, π§))) ∗ (πΉ (π¦, π§) ∗ π¦) = 0, ((π¦ ∗ π₯) ∗ (π¦ ∗ πΉ (π₯, π§))) ∗ (πΉ (π₯, π§) ∗ π₯) = 0. (19) (20) Also, using Theorem 5(4) and (1), we obtain = ππ₯ ∗ πΉ (π₯, π§) , = (π₯ ∗ 0) ∧ (0 ∗ πΉ (π₯, π§)) (2) Let π₯, π¦, π§ ∈ π. Using (I), we have = ((π¦ ∗ π₯) ∗ (π¦ ∗ πΉ (π₯, π§))) ∗ (πΉ (π₯, π§) ∗ π₯) 0 = πΉ (0, π§) = πΉ (ππ₯ ∗ π₯, π§) = (π₯ ∗ πΉ (ππ₯ , π§)) ∗ ((π₯ ∗ πΉ (ππ₯ , π§)) ∗ (ππ₯ ∗ πΉ (π₯, π§))) πΉ (π₯ ∗ π¦, π§) = (π₯ ∗ πΉ (π¦, π§)) ∧ (π¦ ∗ πΉ (π₯, π§)) = π₯ ∗ πΉ (π¦, π§) . (17) ((π₯ ∗ π¦) ∗ (π₯ ∗ πΉ (π¦, π§))) ∗ (πΉ (π¦, π§) ∗ π¦) Proof. (1) For any π₯, π§ ∈ π, we get = (ππ₯ ∗ πΉ (π₯, π§)) ∧ (π₯ ∗ πΉ (ππ₯ , π§)) Proof. (1) Let π be a π-semisimple π΅πΆπΌ-algebra. Then for any π₯, π¦, π§ ∈ π, we have Consequently, we get (3) (∀π₯, π¦, π§ ∈ π) (πΉ(π₯, π§) ∗ π¦ ≤ π₯ ∗ πΉ(π¦, π§)). ≤ π₯. (3) Since πΉ(π₯, π§) ≤ π₯ for all π₯, π§ ∈ π by (2), using (a3) we obtain (15) (π₯ ∗ π¦) ∗ πΉ (π₯ ∗ π¦, π§) = (π¦ ∗ π₯) ∗ πΉ (π¦ ∗ π₯, π§) σ³¨⇒ (π₯ ∗ π¦) ∗ (π₯ ∗ πΉ (π¦, π§)) = (π¦ ∗ π₯) ∗ (π¦ ∗ πΉ (π₯, π§)) . (21) Since π is a π-semisimple π΅πΆπΌ-algebra, hence, by using (21) and (a12), the above (20) yields πΉ(π₯, π§) ∗ π₯ = πΉ(π¦, π§) ∗ π¦. (3) We have πΉ(0, π§) = π₯ ∗ πΉ(π₯, π§) by Theorem 5(4). Further, on letting π₯ = 0, we get that πΉ(0, π§) ∗ 0 = πΉ(π¦, π§) ∗ π¦ implies πΉ(0, π§) = πΉ(π¦, π§) ∗ π¦. Henceforth πΉ(π¦, π§) ∗ π¦ = π₯ ∗ πΉ(π₯, π§), which amounts to say that πΉ(π₯, π§) ∗ π₯ = π¦ ∗ πΉ(π¦, π§). This completes the proof. Theorem 10. Let π be a π-semisimple π΅πΆπΌ-algebra. Then πΉ is a symmetric left bi-derivation if and only if it is a symmetric bi-derivation on π. International Journal of Mathematics and Mathematical Sciences Proof. Suppose that πΉ is a symmetric left bi-derivation on π. First, we show that πΉ is a (r,l)-symmetric bi-derivation on π. Let π₯, π¦, π§ ∈ π. Using Theorem 9(1) and (a14), we have πΉ (π₯ ∗ π¦, π§) = π₯ ∗ πΉ (π¦, π§) = (πΉ (π₯, π§) ∗ π¦) ∗ ((πΉ (π₯, π§) ∗ π¦) ∗ (π₯ ∗ πΉ (π¦, π§))) (22) = (π₯ ∗ πΉ (π¦, π§)) ∧ (πΉ (π₯, π§) ∗ π¦) . Hence πΉ is a (π, π)-symmetric bi-derivation on π. Again, we show that πΉ is a (l,r)-symmetric bi-derivation on π. Let π₯, π¦, π§ ∈ π. Using Theorem 9(1), (3) and (a15), we have πΉ (π₯ ∗ π¦, π§) = π₯ ∗ πΉ (π¦, π§) = (π₯ ∗ 0) ∗ πΉ (π¦, π§) = (π₯ ∗ (πΉ (0, π§) ∗ πΉ (0, π§))) ∗ πΉ (π¦, π§) = (π₯ ∗ ((π₯ ∗ πΉ (π₯, π§)) ∗ (πΉ (π¦, π§) ∗ π¦))) ∗ πΉ (π¦, π§) = (π₯ ∗ πΉ (π¦, π§)) (23) ∗ ((π₯ ∗ πΉ (π₯, π§)) ∗ (πΉ (π¦, π§) ∗ π¦)) = (π₯ ∗ πΉ (π¦, π§)) ∗ ((π₯ ∗ πΉ (π¦, π§)) ∗ (πΉ (π₯, π§) ∗ π¦)) = (πΉ (π₯, π§) ∗ π¦) ∧ (π₯ ∗ πΉ (π¦, π§)) . Conversely, suppose that πΉ is a symmetric bi-derivation of π. As πΉ is a (r,l)-symmetric bi-derivation on π, then for any π₯, π¦, π§ ∈ π and using (a14), we have πΉ (π₯ ∗ π¦, π§) = (π₯ ∗ πΉ (π¦, π§)) ∧ (πΉ (π₯, π§) ∗ π¦) = (πΉ (π₯, π§) ∗ π¦) ∗ ((πΉ (π₯, π§) ∗ π¦) ∗ (π₯ ∗ πΉ (π¦, π§))) = π₯ ∗ πΉ (π¦, π§) (24) = (π¦ ∗ πΉ (π₯, π§)) ∗ ((π¦ ∗ πΉ (π₯, π§)) ∗ (π₯ ∗ πΉ (π¦, π§))) = (π₯ ∗ πΉ (π¦, π§)) ∧ (π¦ ∗ πΉ (π₯, π§)) . Hence πΉ is a symmetric left bi-derivation. This completes the proof. Acknowledgments The authors are grateful to the anonymous referee(s) for a careful checking of the details and for helpful comments that improved the present paper. G. Muhiuddin and Abdullah M. Al-roqi were partially supported by the Deanship of Scientific Research, University of Tabuk, Ministry of Higher Education, Saudi Arabia. 5 References [1] Y. Imai and K. IseΜki, “On axiom systems of propositional calculi. XIV,” Proceedings of the Japan Academy, vol. 42, pp. 19–22, 1966. [2] K. 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