Internat. J. Math. & Math. Sci. Vol. 22, No. 4 (1999) 817–822 S 0161-17129922817-7 © Electronic Publishing House CHARACTERIZATION ON SOME ABSOLUTE SUMMABILITY FACTORS OF INFINITE SERIES W. T. SULAIMAN (Received 12 June 1998) Abstract. A general theorem concerning some absolute summability factors of infinite series is proved. This theorem characterizes as well as generalizes our previous result [4]. Other results are also deduced. Keywords and phrases. Summability, series, sequences. 1991 Mathematics Subject Classification. 40D15, 40F15, 40F05. 1. Introduction. Let an be an infinite series with partial sum sn . Let σnδ and ηδn denote the nth Cesàro mean of order δ(δ > −1) of the sequences {sn } and {nan }, respectively. The series an is said to be summable |C, δ|k , k ≥ 1, if ∞ n=1 k δ < ∞, nk−1 σnδ − σn−1 (1.1) or, equivalently, ∞ k n−1 ηn < ∞. (1.2) n=1 Let {pn } be a sequence of positive real constants such that Pn = n pv → ∞ as n → ∞. (1.3) v=0 The series an is said to be summable N, pn k , k ≥ 1, if (Bor [1]) k−1 ∞ Pn Tn − Tn−1 k < ∞, pn n=1 (1.4) where Tn = Pn−1 n pv sv . (1.5) v=0 For pn = 1, N, pn k summability is equivalent to C, 1k summability. In general, the two summabilities are not comparable. Let {ϕn } be any sequence of positive real constants. The series an is said to be summable N, pn , ϕn k , k ≥ 1, if (Sulaiman [4]) ∞ n=1 k k−1 ϕn Tn − Tn−1 < ∞. (1.6) 818 W. T. SULAIMAN Clearly, N, pn , Pn = N, pn , k pn k N, 1, n = C, 1 . k k (1.7) Theorem 1.1 (Sulaiman [4]). Let {pn }, {qn }, and {ϕn } be sequences of real positive constants. Let tn denote the (N, pn )-mean of the series an . If ∞ n=1 k Pn pn ∞ n=1 ∞ n=1 Pn pn qn Qn k k k k−1 ϕn n ∆tn−1 < ∞, k k k−1 ϕn n ∆tn−1 < ∞, k (1.8) k k k−1 ϕn ∆n ∆tn−1 < ∞, then the series an n is summable N, qn , ϕn k , k ≥ 1, where ∆fn = fn −fn+1 for any sequence {fn } and Qn = n qv → ∞ as n → ∞ q−1 = Q−1 = 0 . (1.9) v=0 2. Lemmas Lemma 2.1 (Bor [1]). Let k > 1 and A = (anv ) be an infinite matrix. In order that A ∈ (k ; k ), it is necessary that anv = O(1) (all n, v). (2.1) Lemma 2.2. Suppose that n = O(fn gn ), fn , gn ≥ 0, {n /fn gn } monotonic, ∆gn = O(1), and ∆fn = O(fn /gn+1 ). Then ∆n = O(fn ). Proof. Let kn = (n /fn gn ) = O(1). If (kn ) is nondecreasing, then ∆n = kn fn gn − kn+1 fn+1 gn+1 ≤ kn fn gn − kn fn+1 gn+1 = kn ∆ fn gn = kn fn ∆gn + gn+1 ∆fn , ∆n = O fn ∆gn + O gn+1 ∆fn = O f n + O fn = O f n . (2.2) If (kn ) is nonincreasing, write ∇fn = fn+1 − fn , ∇n = kn+1 fn+1 gn+1 − kn fn gn ≤ kn ∇ fn gn = kn fn ∇gn + gn+1 ∇fn , ∆n = ∇n = O fn ∇gn + O gn+1 ∇fn = O fn ∆gn + O gn+1 ∆fn = O f n + O fn = O f n . (2.3) CHARACTERIZATION ON SOME ABSOLUTE SUMMABILITY FACTORS . . . 819 3. Main Result. We state and prove the following theorem: Theorem 3.1. Let {pn }, {qn }, {αn }, and {βn } be sequences of positive real numbers such that βn qn is nonincreasing; (3.1) Qn pn Qn = O Pn qn ; (3.2) 1−(1/k) P q βn n n n is monotonic; (3.3) pn Qn αn Qn = O(1); (3.4) ∆ qn 1−(1/k) 1−(1/k) p p q αn αn n n n+1 ∆ =O . (3.5) P n βn Pn Qn+1 βn Then the necessary and sufficient conditions that an n be summable N, qn , βn k , whenever an is summable N, pn , αn k , k ≥ 1, are pn Qn αn 1−(1/k) , (3.6) n = O Pn qn βn 1−(1/k) p αn n . (3.7) ∆n = Pn−1 βn Proof. Write n qn Qv−1 av v , Qn Qn−1 v=1 n pn 1−(1/k) tn = αn Pv−1 av , Pn Pn−1 v=1 1−(1/k) Tn = βn Tn = 1−(1/k) βn 1−(1/k) = βn 1−(1/k) = βn qn Qn Qn−1 qn Qn Qn−1 qn Qn Qn−1 n Pv−1 av v=1 n−1 v (3.8) Qv−1 v Pv−1 n Qn−1 Qv−1 n + Pr −1 ar Pv−1 v Pn−1 r =1 pv Qv v Qv −qv α(1/k)−1 t + + ∆ v v v v Pv−1 Pv−1 Pv Pv Pr −1 ar ∆ v=1 r =1 n−1 Pv Pv−1 v=1 pv Pn Pn−1 qn Qn−1 tn α(1/k)−1 n n Qn Qn−1 pn Pn−1 n−1 −qv qn 1−(1/k) = βn Pv α(1/k)−1 tv v v Qn Qn−1 v=1 pv Pv Qv (1/k)−1 (1/k)−1 + αv Qv tv v + αv tv ∆v pv Pn qn (1/k)−1 1−(1/k) + α βn tn n . pn Qn n 1−(1/k) + βn Let us denote the above form of Tn by Tn,1 + Tn,2 + Tn,3 + Tn,4 . (3.9) 820 W. T. SULAIMAN By Minkowski’s inequality, in order to prove the sufficiency, it is sufficient to show ∞ that n=1 |Tn,r |k < ∞, r = 1, 2, 3, 4. Applying Hölder’s inequality, m+1 n=2 |Tn,1 |k = m+1 k n−1 −qv 1−(1/k) qn β Pv α(1/k)−1 t v v n v Qn Qn−1 v=1 pv n=2 k−1 k k n−1 n−1 qv q P 1 k k n v k−1 ≤ βn qv αv1−k tv v Qn Qn−1 v=1 pv Qn−1 n=2 v=1 k k m k k m+1 1 Pv qn k−1 ≤ O(1) qv αv1−k tv v βn p Q Q v n n−1 v=1 n=v+1 k k−1 m+1 m k Pv qv qn 1−k k = O(1) qv αv tv v βv p Q Q Qn−1 v v n v=1 n=v+1 k k−1 m k k βv qv Pv tv v , = O(1) p Q α v v v v=1 m+1 k n−1 m+1 1−(1/k) qn β Tn,2 k = α(1/k)−1 Qv tv v n v Q Q n n−1 v=1 n=2 n=2 m+1 m+1 k 1 n−1 Qv qv k k−1 qv k k n−1 qv tv v Qn−1 α1−k Qn−1 v=1 v v=1 k k m m+1 k k Qv qn 1 k−1 ≤ O(1) αv1−k qv tv v βn q Q Q v n n−1 v=1 n=v+1 k k−1 m+1 m k k qv qn 1−k Qv = O(1) αv qv tv v βv q Q Q Qn−1 v v n v=1 n=v+1 m k−1 βv k k tv v = O(1) α v v=1 k k k−1 m k k Pv qv βv tv v , = O(1) p Q α v v v v=1 = n=2 k−1 βn qn Qn k n−1 m+1 Pv−1 1−(1/k) qn (1/k)−1 β Tn,3 k = Q α t ∆ v v v v n Q Q p n n−1 v n=2 n=2 v=1 k k k n−1 m+1 qn Pv−1 Qv 1 k−1 ≤ βn qv αv1−k Qn Qn−1 v=1 pv qv n=2 k−1 qv k k n−1 × tv ∆v Qn−1 v=1 k k k m k m+1 Pv−1 Qv qn 1 1−k k k−1 = O(1) qv αv βn tv ∆v pv qv Qn Qn−1 v=1 n=v+1 k k k−1 m k Qv qv Pv−1 qv 1−k k tv ∆v = O(1) αv βv Qv pv qv Qv v=1 m+1 CHARACTERIZATION ON SOME ABSOLUTE SUMMABILITY FACTORS . . . = O(1) m v=1 m+1 m Tn,4 k = O(1) n=2 n=1 Pv−1 pv k qn Pn pn Qn βv αv k k−1 βn αn 821 k tv ∆v k , k−1 k k tn n . (3.10) Sufficiency of (3.6) and (3.7) follows. Necessity of (3.6). Using the result of Bor in [2], the transformation from (tn ) into (Tn ) maps k into k and, hence by Lemma 2.1 the diagonal elements of this transformation are bounded and so (3.6) is necessary. Necessity of (3.7). This follows from Lemma 2.2 and the necessity of (3.6) by taking fn = pn Pn αn βn 1−(1/k) , gn = Qn . qn (3.11) 4. Applications Corollary 4.1. Suppose that the conditions (3.1) and (3.2) are satisfied. Then the necessary and sufficient condition that an be summable |N, qn , βn |k , whenever it is summable |N, pn , αn |k , k ≥ 1, is α 1−(1/k) P n qn n =O . (4.1) βn pn Qn Proof. The proof follows from Theorem 3.1 by putting n = 1 and noticing that we do not need the conditions (3.3), (3.4), and (3.5) as ∆n = 0 for n = 1. Corollary 4.2. Suppose that (3.2) and (3.4) are satisfied, {(Pn qn /pn Qn )(1/k) n } is monotonic, and 1−(1/k) 1−(1/k) p p q Pn qn Pn qn n n n+1 ∆ =O . (4.2) Pn pn Qn Pn Qn+1 pn Qn Then the necessary and sufficient conditions that an n be summable |N, qn |k when ever an is summable |N, pn |k , k ≥ 1, are 1/k 1−(1/k) p pn Qn Pn qn n n = O . (4.3) , ∆n = Pn q n Pn−1 pn Qn Proof. The proof follows from Theorem 3.1 by putting αn = Pn /pn , βn = Qn /qn . Corollary 4.3 (Bor and Thorpe [3]). Suppose that pn Qn = O(Pn qn ) and Pn qn = O(pn Qn ). Then, the series an is summable |N, qn |k if and only if it is summable |N, pn |k , k ≥ 1. Proof. The proof follows from the sufficient part of Corollary 4.1. 822 W. T. SULAIMAN Remark. It may be noticed that (3.4) can be replaced by Qn ∆qn = O qn qn+1 , as Qn Qn Qn+1 qn+1 Qn − qn (Qn + qn+1 ) ∆ = = − qn qn qn+1 qn qn+1 Q ∆q n n = + 1 qn qn+1 ≤ 1+ (4.4) (4.5) Qn |∆qn | . qn qn+1 References [1] [2] [3] [4] H. Bor, On two summability methods, Math. Proc. Cambridge Philos. Soc. 97 (1985), no. 1, 147–149. MR 86d:40004. Zbl 554.40008. , On the relative strength of two absolute summability methods, Proc. Amer. Math. Soc. 113 (1991), no. 4, 1009–1012. MR 92c:40006. Zbl 743.40007. H. Bor and B. Thorpe, On some absolute summability methods, Analysis 7 (1987), no. 2, 145–152. MR 88j:40012. Zbl 639.40005. W. T. Sulaiman, On some summability factors of infinite series, Proc. Amer. Math. Soc. 115 (1992), no. 2, 313–317. MR 92i:40009. Zbl 756.40006. Sulaiman: College of Education, Ajman University, P. O. Box 346, Ajman, United Arab Emirates