NAME Id. No, Final Examination, Math 304 Fall 2012, Wilkerson Section 508. December 7, 2011 – Two Hours – Blocker 161 No notes, books, calculators, music players, earphones, etc. Show all work. Problem Score 1.(10) 2.(20) 3.(20) 4.(20) 5.(10) 6.(10) 7.(10) 8.(10) 9.(10) 10.(15) Total(150) 1. 10 points Let −1 0 0 B = −3 2 0 . 0 0 1 Find the eigenvalues of B. 1 2. (20 points) Let 1 1 1 2 1 −1 , ~b = . A= 3 1 0 4 1 4 a)(15 points) Write out the normal equations used in solving for the least squares solution to A~x = ~b. Use this to find the least squares solution to Ax = b. b) Find an orthonormal basis of the column space Col(A) .(5 points) 2 4. (20 points) A linear transformation L : V → V is represented by an matrix. Let VE = R3 be with the standard basis E = {e1 , e2 , e3 }. 0 0 1 Let F be the basis of R3 consisting of v1 = 1 1 , v2 = 1 , v3 = 0 . Let VF denote R3 with 1 1 0 1 0 −1 the F -basis. Let AE = 2 1 3 represent the linear transformation L in the E-basis. Write 1 1 0 out the linear transformation L as AF in the F -basis. 3 1 √ √ 5. (10 points) Let S ⊂ R3 have the orthonormal basis u1 = 1/ 3 1 and u2 = 1/ 2 0 . −1 1 T Find the projection of the vector (1, 2, 3) onto S. 1 6. (10 Let P be the plane in R3 which contains the point (2, 3, 5) and is perpendicular points) 1 to N = 5 . 11 a) Write an equation for P . b) Is (0, 0, 0) on P ? Is (1, 1, 1) on P ? 4 7. (10 points) Let A be a symmetric 2 × 2 matrix with eigenvectors (1, 1)T for λ = 2 and (1, −1)T for λ = 3. Using the theorem that AT = DT for suitable T and diagonal D, find T , D, and A. 8. (15 points). 1 1 1 A = 1 1 1 ! 1 1 has eigenvalues 3 and 0. For each eigenvalue λ calculate the subspace Eλ of v with Av = λv , i.e, Null(A − λId). a) For λ = 0. b) For λ = 3. 5 9. 20 points 1 The matrix A = 2 3 a) 10 points. Give a 1 2 0 1 has reduced row echelon form U = 0 0 1 3. 4 1 5 0 0 0 0 6 2 9 basis for the null space of A. 2 1 4 b) 5 points. Give a basis for ColSpace(A). c) 5 points. Does the equation 2 A~x = 3 5 have a soluition ? If so, how many and list them? 6