The Verification of an Inequality Roger W. Barnard, Kent Pearce, G. Brock Williams Texas Tech University Leah Cole Wayland Baptist University Presentation: Pondicherry, India Notation & Definitions D {z :| z | 1} Notation & Definitions D {z :| z | 1} hyperbolic metric 2 | dz | ( z ) | dz | 2 1 | z | Notation & Definitions D {z :| z | 1} Hyberbolic Geodesics Notation & Definitions D {z :| z | 1} Hyberbolic Geodesics Hyberbolically Convex Set Notation & Definitions D {z :| z | 1} Hyberbolic Geodesics Hyberbolically Convex Set Hyberbolically Convex Function Notation & Definitions D {z :| z | 1} Hyberbolic Geodesics Hyberbolically Convex Set Hyberbolically Convex Function Hyberbolic Polygon o Proper Sides Examples k ( z ) 2 z (1 z ) (1 z ) 2 4 2 z k Examples f ( z ) tan where z (1 2 2 1 4 2 cos 2 ) 0 2 , 0 2 K (cos ) f d Schwarz Norm || S f ||D For f A( D) let Sf 2 f 1 f f 2 f and || S f ||D sup{(1 | z | ) | S f ( z) |: z D} 2 2 Extremal Problems for || S f ||D Euclidean Convexity Nehari (1976): f ( D) convex || S f ||D 2 Extremal Problems for || S f ||D Euclidean Convexity Nehari (1976): f ( D) convex || S f ||D 2 Spherical Convexity Mejía, Pommerenke (2000): f ( D) convex || S f ||D 2 Extremal Problems for || S f ||D Euclidean Convexity Nehari (1976): f ( D) convex || S f ||D 2 Spherical Convexity Mejía, Pommerenke (2000): f ( D) convex || S f ||D 2 Hyperbolic Convexity Mejía, Pommerenke Conjecture (2000): f ( D) convex || S f ||D 2.3836 Verification of M/P Conjecture “The Sharp Bound for the Deformation of a Disc under a Hyperbolically Convex Map,” Proceedings of London Mathematical Society (accepted 3 Jan 2006), R.W. Barnard, L. Cole, K. Pearce, G.B. Williams. http://www.math.ttu.edu/~pearce/preprint.shtml Verification of M/P Conjecture Preliminary Facts: Invariance of hyperbolic convexity under disk automorphisms Verification of M/P Conjecture Preliminary Facts: Invariance of hyperbolic convexity under disk automorphisms Invariance of || S f ||D under disk automorphisms For we have , Auto( D) || S f ||D || S f ||D || S f ||D || S f || 1 ( D ) Classes H and Hn H { f A( D) : f ( D) is hyp. convex, f (0) 0, f (0) 0} Classes H and Hn H { f A( D) : f ( D) is hyp. convex, f (0) 0, f (0) 0} H poly { f H : f ( D) is hyp. polygon} Classes H and Hn H { f A( D) : f ( D) is hyp. convex, f (0) 0, f (0) 0} H poly { f H : f ( D) is hyp. polygon} H n { f H poly : f ( D) has at most n proper sides} Reduction to Hn Lemma 1. To determine the extremal value of || S f ||D over H, it suffices to determine the value over each Hn. Moreover, each Hn is pre-compact. Reduction to Hn Lemma 1. To determine the extremal value of || S f ||D over H, it suffices to determine the value over each Hn. Moreover, each Hn is pre-compact. A. Hn {0} is compact Reduction to Hn Lemma 1. To determine the extremal value of || S f ||D over H, it suffices to determine the value over each Hn. Moreover, each Hn is pre-compact. A. Hn {0} is compact B. H n H n Reduction to Hn Lemma 1. To determine the extremal value of || S f ||D over H, it suffices to determine the value over each Hn. Moreover, each Hn is pre-compact. A. Hn {0} is compact B. H n H n C. Schwarz norm is lower semi-continuous Examples k ( z ) 2 z (1 z ) (1 z ) 2 4 2 z k Reduction to Re Sf (0) Lemma 2. For each n > 2, sup || S f ||D max | S f (0) | max Re S f (0) f H n A. B. C. f H n f H n Schwarz Norm || S f ||D For f A( D) let Sf 2 f 1 f f 2 f and || S f ||D sup{(1 | z |2 )2 | S f ( z) |: z D} Reduction to Re Sf (0) Lemma 2. For each n > 2, sup || S f ||D max | S f (0) | max Re S f (0) f H n f H n A. (Nehari) f H n n k 1 n 1 k2 Sg ( z) 2 2 k 1 ( z ak ) k 1 z ak implies lim 4(Im z )2 | S g ( z ) | 2 for w U z w B. C. Reduction to Re Sf (0) Lemma 2. For each n > 2, sup || S f ||D max | S f (0) | max Re S f (0) f H n f H n A. (Nehari) f H n n k 1 n 1 k2 Sg ( z) 2 2 k 1 ( z ak ) k 1 z ak implies lim 4(Im z )2 | S g ( z ) | 2 for w U z w B. There exist f H n for which || S f ||D 2 C. Reduction to Re Sf (0) Lemma 2. For each n > 2, sup || S f ||D max | S f (0) | max Re S f (0) f H n f H n A. (Nehari) f H n n k 1 n 1 k2 Sg ( z) 2 2 k 1 ( z ak ) k 1 z ak implies lim 4(Im z )2 | S g ( z ) | 2 for w U z w B. There exist f H n for which || S f ||D 2 C. Invariance under disk automorphisms Julia Variation Let Ω be a region bounded by a piece-wise analytic curve Γ and φ(w) piece-wise C1 on Γ . Julia Variation (cont) Let Ω be a region bounded by a piece-wise analytic curve Γ and φ(w) piece-wise C1 on Γ . Julia Variation (cont) Let Ω be a region bounded by a piece-wise analytic curve Γ and φ(w) piece-wise C1 on Γ . At each point w on Γ (where Γ is smooth), let n(w) denote the unit outward normal to Γ. For small ε let {w * w ( w)n( w) : w } and let Ωε be the region bounded by Γε. Julia Variation (cont) Let Ω be a region bounded by a piece-wise analytic curve Γ and φ(w) piece-wise C1 on Γ . At each point w on Γ (where Γ is smooth), let n(w) denote the unit outward normal to Γ. For small ε let {w * w ( w)n( w) : w } and let Ωε be the region bounded by Γε. Julia Variation (cont) Theorem. Let f be a conformal map from D on Ω with f (0) = 0 and suppose f has a continuous extension to ∂D. Then, for sufficiently small ε the map fε from D on Ωε with fε (0) = 0 is given by zf ( z ) 1 z f ( z ) f ( z ) d o( ) 2 D 1 z where d ( f ( )) d and ei | f ( ) | Two Variations for Hn Variation #1 Two Variations for Hn Variation #1 Two Variations for Hn Variation #1 Two Variations for Hn Variation #1 f ( z ) f ( z ) o( ) * Barnarnd & Lewis, Subordination theorems for some classes of starlike functions, Pac. J. Math 56 (1975) 333-366. Two Variations for Hn Variation #2 Two Variations for Hn Variation #2 Schwarzian and Julia Variation Lemma 3. If f ( z ) ( z a2 z 2 a3 z 3 ) then S f (0) 6(a3 a22 ) Lemma 4. If f ( z ) ( z a2 z 2 a3 z 3 ) H n and Var. #1 or Var. #2 is applied to a side Γj, then S f (0) 6 a3 2 a2 2 (3a3 4a2 )d j 2 (2a2 2 )d j 2 o( ) Schwarzian and Julia Variation In particular, 6 2 2 Re S f (0) Re 3 a 4 a 2 d 3 2 2 0 j Re K ( j ) d j where 6 2 2 K ( ) 3 a 4 a 2 3 2 2 Reduction to H2 Step #1. Reduction to H4 Reduction to H2 Step #1. Reduction to H4 Step #2. (Step Down Lemma) Reduction to H2 Reduction to H2 Step #1. Reduction to H4 Step #2. (Step Down Lemma) Reduction to H2 Step #3. Compute maximum in H2 Reduction to H2 – Step #1 Suppose f H n is extremal and maps D to a region bounded by more than four sides. Reduction to H2 – Step #1 Suppose f H n is extremal and maps D to a region bounded by more than four sides. Then, pushing Γ5 out using Var. #1, we have Re S f (0) Re K ( 1 ) d 0 0 5 Reduction to H2 – Step #1 Consequently, the image of each side γj under K must intersect imaginary axis Reduction to H2 – Step #1 Consequently, the image of each side γj under K must intersect imaginary axis Reduction to H2 – Step #2 Suppose f H n is extremal and maps D to a region bounded by exactly four sides. Reduction to H2 – Step #2 Suppose f H n is extremal and maps D to a region bounded by exactly four sides. Reduction to H2 – Step #2 Suppose f H n is extremal and maps D to a region bounded by exactly four sides. Reduction to H2 – Step #2 Suppose f H n is extremal and maps D to a region bounded by exactly four sides. Then, pushing in the end of Γ3 , near f (z*), using Var. #2, we have Re S f (0) (1) Re K ( * ) d 0 0 * Reduction to H2 – Step #2 Suppose f H n is extremal and maps D to a region bounded by exactly two sides. Computation in H2 Functions whose ranges are convex domains bounded by one proper side (k ) Functions whose ranges are convex domains bounded by two proper sides which intersect Functions whose ranges are odd symmetric convex domains whose proper sides do not intersect ( f ) Computation in H2 Using an extensive calculus argument which considers several cases (various interval ranges for |z|, arg z, and α) and uses properties of polynomials and K, one can show that this problem can be reduced to computing sup (1 x) 2 | S f ( x) | 0 x 1 Computation in H2 Verified (1 r ) 2 S f ( ) (r ) A. For each fixed that maximized at r = 0 B. The curve S f (0) 2(c 2 ) is unimodal, i.e., there exists a unique * 0.2182 so that S f (0) increases for 0 * and decreases for * 2 . At * , ( ) ( ) Sf ( * ) 2.3836 is Graph of S f ( ) * (0) 2(c ) 2