EE143 S06 Semiconductor Tutorial 2 -Electron Energy Band - Fermi Level -Electrostatics of device charges Professor N Cheung, U.C. Berkeley 1 EE143 S06 Semiconductor Tutorial 2 The Simplified Electron Energy Band Diagram Professor N Cheung, U.C. Berkeley 2 EE143 S06 Semiconductor Tutorial 2 Energy Band Diagram with E-field Electron Electron Energy Energy E-field + 2 1 Electric potential φ(2) < φ(1) + EC 2 EV x E-field - 1 EC EV Electric potential φ(2) > φ(1) x Electron concentration n qφ ( 2 ) / kT n( 2) e q[ φ ( 2 ) − φ ( 1 )] / kT = qφ( 1) / kT = e n(1) e Professor N Cheung, U.C. Berkeley 3 EE143 S06 Semiconductor Tutorial 2 The Fermi-Dirac Distribution (Fermi Function) Probability of available states at energy E being occupied f(E) = 1/ [ 1+ exp (E- Ef) / kT] where Ef is the Fermi energy and k = Boltzmann constant=8.617 ∗ 10-5 eV/K f(E) T=0K 0.5 E -Ef Professor N Cheung, U.C. Berkeley 4 EE143 S06 Semiconductor Tutorial 2 Properties of the Fermi-Dirac Distribution Probability of electron state at energy E will be occupied (1) f(E) ≅ exp [- (E- Ef) / kT] for (E- Ef) > 3kT •This approximation is called Boltzmann approximation Note: At 300K, kT= 0.026eV (2) Probability of available states at energy E NOT being occupied 1- f(E) = 1/ [ 1+ exp (Ef -E) / kT] Professor N Cheung, U.C. Berkeley 5 EE143 S06 Semiconductor Tutorial 2 How to find Ef when n(or p) is known Ec q|ΦF| Ef (n-type) Ei Ev Ef (p-type) n = ni exp [(Ef - Ei)/kT] Let qΦF ≡ Ef - Ei ∴n = ni exp [qΦF /kT] Professor N Cheung, U.C. Berkeley 6 EE143 S06 Semiconductor Tutorial 2 Dependence of Fermi Level with Doping Concentration Ei ≡ (EC+EV)/2 Middle of energy gap When Si is undoped, Ef = Ei ; also n =p = ni Professor N Cheung, U.C. Berkeley 7 EE143 S06 Semiconductor Tutorial 2 The Fermi Energy at thermal equilibrium At thermal equilibrium ( i.e., no external perturbation), The Fermi Energy must be constant for all positions Electron energy Material A Material B Material C Material D EF Position x Professor N Cheung, U.C. Berkeley 8 EE143 S06 Semiconductor Tutorial 2 Electron Transfer during contact formation System 1 Before contact formation EF1 EF System 2 Net negative charge E Professor N Cheung, U.C. Berkeley EF2 e EF2 + Net positive + charge + - System 2 System 1 e System 1 After contact formation System 2 EF1 System 2 System 1 - EF + + + E 9 EE143 S06 Semiconductor Tutorial 2 Applied Bias and Fermi Level Fermi level of the side which has a relatively higher electric potential will have a relatively lower electron energy ( Potential Energy = -q • electric potential.) Only difference of the E 's at both sides are important, not the absolute position of the Fermi levels. q Va E f1 Side 2 Side 1 + Va > 0 - Ef 2 E f1 q| Va | Ef 2 Side 2 Side 1 + Va < 0 - Potential difference across depletion region = Vbi - Va Professor N Cheung, U.C. Berkeley 10 EE143 S06 Semiconductor Tutorial 2 PN junctions Thermal Equilibrium NA - and E-field p ρ(x) is 0 ND+ and n Depletion region Quasi-neutral region -- ++ -- ++ p-Si NA- only ρ(x) is - ρ(x) is 0 Quasi-neutral region n-Si ND+ only ρ(x) is + Complete Depletion Approximation used for charges inside depletion region r(x) ≈ ND+(x) – NA-(x) http://jas.eng.buffalo.edu/education/pn/pnformation2/pnformation2.html Professor N Cheung, U.C. Berkeley 11 EE143 S06 Semiconductor Tutorial 2 Electrostatics of Device Charges 1) Summation of all charges = 0 ρ2 • xd2 = ρ1 • xd1 2) E-field =0 outside depletion regions ρ (x) p-type Semiconductor n-type Semiconductor ρ2 - xd1 - ρ1 E=0 Professor N Cheung, U.C. Berkeley x xd2 x=0 E ≠0 E=0 12 EE143 S06 Semiconductor Tutorial 2 3) Relationship between E-field and charge density ρ(x) d [ε E(x)] /dx = ρ(x) “Gauss Law” 4) Relationship between E-field and potential φ E(x) = - dφ(x)/dx Professor N Cheung, U.C. Berkeley 13 EE143 S06 Semiconductor Tutorial 2 Example Analysis : n+/ p-Si junction ρ (x) +Q' Emax =qNaxd/εs p-Si n+ Si x x Depletion region Depletion region -qNa is very thin and is approximated as E (x) d x=0 3) ⇒ Slope = qNa/εs xd 2) ⇒ E = 0 a thin sheet charge 1) ⇒ Q’ = qNaxd Professor N Cheung, U.C. Berkeley 4) ⇒ Area under E-field curve = voltage across depletion region = qNaxd2/2εs 14 EE143 S06 Semiconductor Tutorial 2 Superposition Principle ρ(x) If ρ1(x) ⇒ E1(x) and V1(x) ρ2(x) ⇒ E2(x) and V2(x) then ρ1(x) + ρ2(x) ⇒ E1(x) + E2(x) and V1(x) + V2(x) +qND -xp x -qN- A +xn x=0 ρ2(x) ρ1(x) +qND Q=+qNAxp -xp x -qNA x +xn Q=-qNAxp x=0 Professor N Cheung, U.C. Berkeley + x=0 15 EE143 S06 Semiconductor Tutorial 2 ρ1(x) -xp ρ2(x) +qND Q=+qNAxp x x +xn -qNA Q=-qNAxp x=0 x=0 E1(x) E2(x) -xp +xn x Slope = - qNA/εs x - - Professor N Cheung, U.C. Berkeley + x=0 Slope = + qND/εs x=0 16 EE143 S06 Semiconductor Tutorial 2 Sketch of E(x) E(x) = E1(x)+ E2(x) -xp x=0 Slope = - qNA/εs +xn x Slope = + qND/εs - Emax = - qNA xp /εs = - qND xn /εs Professor N Cheung, U.C. Berkeley 17 EE143 S06 Semiconductor Tutorial 2 Depletion Mode :Charge and Electric Field Distributions by Superposition Principle of Electrostatics ρ (x) Q' Metal ρ (x) Q' Oxide Semiconductor x=xo + x d x Metal ρ (x) Q' Oxide x=0 E(x) Metal Oxide Semiconductor Metal E(x) Oxide x=xo Professor N Cheung, U.C. Berkeley x=0 x=xo Semiconductor = Metal x x=x + x o d x=xo + x d x=0 −ρ - Q' x=xo x Semiconductor x=xo + x d x Oxide x −ρ x=0 Metal Semiconductor x=0 x=x o E(x) Oxide x=xo Semiconductor + x x=x o + x x=0 x=x d o 18 EE143 S06 Semiconductor Tutorial 2 Why xdmax ~ constant beyond onset of strong inversion ? VG = VFB + VOX + VSi Higher than VT Picks up all the changes in VG Justification: If surface electron density changes by ∆n Ei Ef δ δ ∝ ln (∆ n ∆n ∝ e Professor N Cheung, U.C. Berkeley Approximation assumes VSi does not change much δ ∆VOX ) ∆n ∝ COX but the change of VSi changes only by kT/q [ ln (∆n)] – small! kT 19 EE143 S06 Semiconductor Tutorial 2 N (surface) = n (bulk) • exp [ qVSi/kT] p-Si Na=1016/cm3 n-bulk = 2.1 • 104/cm3 n-surface qVSi Ei 0.35eV Ef Onset of strong inversion (at VT) Professor N Cheung, U.C. Berkeley VSi 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 n-surface 2.10E+04 9.84E+05 4.61E+07 2.16E+09 1.01E+11 4.73E+12 2.21E+14 1.04E+16 4.85E+17 2.27E+19 20