Yimin Math Centre 4 Unit Math Homework for Year 12 Student Name: Grade: Date: Score: Table of contents 2 Topic 2 — Conics (Part 2) 1 2.1 Parametric Equations for the Ellipse and Hyperbola . . . . . . . . . . . . . . . . . . . 1 2.1.1 Parametric Equations for the Ellipse . . . . . . . . . . . . . . . . . . . . . . . 1 2.1.2 Parametric Equations for Hyperbola . . . . . . . . . . . . . . . . . . . . . . . 2 2.1.3 Further Trigonometry . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4 2.1.4 Equation of a Chord on an Ellipse . . . . . . . . . . . . . . . . . . . . . . . . 5 2.1.5 Equation of a Chord on Hyperbola . . . . . . . . . . . . . . . . . . . . . . . . 7 Past Exam Questions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 14 2.2 This edition was printed on June 17, 2013. Camera ready copy was prepared with the LATEX2e typesetting system. Copyright © 2000 - 2013 Yimin Math Centre (www.yiminmathcentre.com) 4 Unit Math Homework for Year 12 Year 12 Topic 2 Homework 2 Page 1 of 14 Topic 2 — Conics (Part 2) 2.1 2.1.1 Parametric Equations for the Ellipse and Hyperbola Parametric Equations for the Ellipse Definition: Let N be the foot of a perpendicular from a point P on the ellipse to the x-axis. Produce NP to a point Q on the circle x2 + y 2 = a2 . Let OQ make an angle θ with the positive x-axis, π < θ ≤ π. Then Q has coordinates (a cos θ, a sin θ). 2 2 At P, xa2 + yb2 = 1 and x = a cos θ, hence y = b sin θ, where a > b. 2 2 Hence the ellipse with Cartesian equation xa2 + yb2 = 1. has parametric equations x = a cos θ and y = b sin θ, where −π < θ ≤ π. The circle x2 + y 2 = a2 is called the auxiliary circle. Exercise 2.1.1 Find the parametric equations of 1. The ellipse x2 16 + y2 9 = 1. 2. The ellipse x2 + 4y 2 = 4. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework 2.1.2 Page 2 of 14 Parametric Equations for Hyperbola Definition: N the foot of the perpendicular form a point P on the hyperbola to the x-axis. From N, a tangent is drawn to the circle x2 + y 2 = a2 , meeting the circle in Q. If P is on the right-hand branch, choose Q in the same quadrant as P . If P is on the left-hand branch, choose Q in different quadrants as P . Let θ be the angle OQ makes with the positive x-axis. 2 2 At P, x = a sec θ and xa2 − yb2 = 1, hence y = b tan θ For P on the right-hand branch, − π2 < θ < π2 . For P on the left-hand branch, −π < θ < − π2 2 2 The hyperbola xa2 − yb2 = 1 has parametric equations x = a sec θ and y = b tan θ, where −π < θ ≤ π, θ 6= ± π2 . Exercise 2.1.2 Find the parametric equations of 1. The hyperbola x2 16 − y2 25 = 1. 2. The hyperbola x2 − y 2 = 4. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework Exercise 2.1.3 Find the Cartesian equations of: 1. The ellipse x = 3 cos θ, y = 2 sin θ. 2. The ellipse x = 5 cos θ, y = 4 sin θ. 3. The hyperbola x = 3 sec θ, y = 4 tan θ. 4. The hyperbola x = 2 sec θ, y = 5 tan θ. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Page 3 of 14 Year 12 Topic 2 Homework 2.1.3 Page 4 of 14 Further Trigonometry Sums and Differences: sin(θ + φ) = sin θ cos φ + cos θ sin φ sin(θ − φ) = sin θ cos φ − cos θ sin φ cos(θ + φ) = cos θ cos φ − sin θ sin φ cos(θ − φ) = cos θ cos φ + sin θ sin φ tan(θ + φ) = tan θ + tan φ 1 − tan θ tan φ tan(θ − φ) = tan θ − tan φ 1 + tan θ tan φ Double Angle Identities: sin 2θ = 2 sin θ cos θ cos 2θ = cos2 θ − sin2 θ = 1 − 2 sin2 θ = 2 cos2 θ − 1 2 tan θ tan 2θ = 1 − tan2 θ Sums to Products: sin θ + sin φ = 2 sin θ+φ 2 cos θ−φ sin θ − sin φ = 2 cos sin 2 θ+φ θ−φ cos θ + cos φ = 2 cos cos 2 2 θ+φ θ−φ cos θ − cos φ = 2 sin sin 2 2 θ+φ 2 θ−φ 2 The t-Formulae: Let t = tan 2θ , Then: sin θ = 2t , 1 + t2 cos θ = 1 − t2 , 1 + t2 tan θ = 2t 1 − t2 Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework 2.1.4 Page 5 of 14 Equation of a Chord on an Ellipse PQ, PR, PW are chords of the conic. Chord PR through the centre is a diameter, PW through the focus S is a focal chord. Cd is a focal chord which is perpendicular to the major axis. Such a chord is termed a latus rectum of the conic and has equation x = ±ae. The equation of a general chord PQ is best expressed in terms of the parameters θ and φ of the end points P and Q. 2 y2 Definition: Let P (a cos θ, b sin θ) and Q(a cos φ, b sin φ) lie on xa2 + b2 = 1. Then the gradient of PQ is: 2 sin( θ−φ ) cos(θ+φ) cos( θ+φ ) b(sin θ−sin φ) b 2 2 = ab × −2 sin( θ−φ × = − θ+φ a(cos θ−cos φ) a ) sin( ) sin( θ+φ ) 2 cos( θ+φ ) 2 2 2 ∴ y − b sin θ = − ab × sin( θ+φ (x − a cos θ) ) 2 θ+φ y θ+φ θ+φ x cos + sin = cos θ cos + sin θ sin a 2 b 2 2 θ+φ x Then the equation of the chord is: a cos 2 + yb sin θ+φ 2 θ+φ ) 2 = cos( θ−φ . 2 In the special case where PQ is a diameter, (0, 0) lies on the chord and hence |θ − φ| = π Example 2.1.1 P (a cos θ, b sin θ) and Q[a cos(π + θ), b sin(π + θ)] lie on the ellipse Show that P Q passes through (0, 0). 2 2 Solution: The equation of the chord PQ of the ellipse xa2 + yb2 = 1 is: y x + b sin θ+φ = cos θ−φ , where P, Q have parameters θ, φ cos θ+φ a 2 2 2 We have of the chord φ = π+ θ. Hence the equation PQ transforms into: θ+(π+θ) θ+(π+θ) θ−(π+θ) y x cos + b sin = cos . a 2 2 2 x cos 2θ+π + yb sin 2θ+π = cos −π . a 2 2 2 y x Thus − a sin θ + b cos θ = 0. Therefore (0, 0) lies on the chord PQ. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) x2 a2 + y2 b2 = 1. Year 12 Topic 2 Homework Page 6 of 14 Exercise 2.1.4 The point P (a cos θ, b sin θ), and Q(a cos φ, b sin φ) lie on the ellipse 2 and the chord PQ subtends a right angle at (0, 0). Show that tan θ tan φ = − ab2 . x2 a2 + y2 b2 =1 Exercise 2.1.5 The point P (a cos θ, b sin θ) and Q[a cos(−θ), b sin(−θ)] are the extremities of the latus 2 2 rectum x = ae of the ellipse xa2 + yb2 = 1. 1. Show that cos θ = e. 2. Show that PQ has length 2b2 . a Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework 2.1.5 Page 7 of 14 Equation of a Chord on Hyperbola 2 2 Definition: Let P (a sec θ, b tan θ) and Q(a sec φ, b tan φ) lie on xa2 − yb2 = 1. y Then the equation of the chord is: xa cos θ−φ ) = cos( θ+φ − b sin θ+φ . 2 2 2 In the special case where PQ is a diameter, (0, 0) lies on the chord and hence |θ + φ| = π 2 2 Example 2.1.2 The points P (a sec θ, b tan θ) and Q(a sec φ, b tan φ) lie on the hyperbola xa2 − yb2 = 1 2 and the chord PQ subtends a right angle at (0, 0). Show that sin θ sin φ = − ab2 . Solution: P OQ is a right-angled triangle. Therefore OP 2 + OQ2 = P Q2 . a2 sec2 θ + b2 tan2 θ + a2 sec2 φ + b2 tan2 φ = a2 (sec θ − sec φ)2 + b2 (tan θ − tan φ)2 = a2 (sec2 θ − 2 sec θ sec φ + sec2 φ) + b2 (tan2 θ − 2 tan θ tan φ + tan2 φ) Then 0 = −2a2 sec θ sec φ − 2b2 tan θ tan φ, ⇒ ∴ sin θ sin φ = − a2 b2 Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework Exercise 2.1.6 P (a sec θ, b tan θ) lie on the hyperbola S 0 (−ae, 0). Page 8 of 14 x2 a2 − y2 b2 = 1 with foci S(ae, 0) 1. Show that P S = a(e sec θ − 1) and P S 0 = a(e sec θ = 1) 2. Deduce that |P S − P S 0 | = 2a. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) and Year 12 Topic 2 Homework Page 9 of 14 Exercise 2.1.7 The point P (a cos θ, b sin θ) and Q(a cos φ, b sin φ) lie on the ellipse 2 If P Q subtends a right angle at (a, 0) show that tan 2θ tan φ2 = − ab 2 . x2 a2 Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) + y2 b2 = 1. Year 12 Topic 2 Homework Page 10 of 14 Exercise 2.1.8 The points P (a sec θ, b tan θ) and Q(a sec φ, b tan φ) lie on the hyperbola 2 2 x2 − yb2 = 1. If PQ subtends a right angle at (a, 0). Show that tan 2θ tan φ2 = − ab 2 . a2 Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework Page 11 of 14 Exercise 2.1.9 2 2 1. Given that the equation of the chord PQ of the ellipse xa2 + yb2 = 1 is xa cos( θ+φ ) + yb sin( θ+φ )= 2 2 θ−φ θ cos( 2 ), where P, Q have parameters θ, φ, show that if PQ is a focal chord then tan 2 tan φ2 1−e takes one of values − 1+e or 1+e . 1−e 2. PQ is a focal chord of x2 4 + y2 3 = 1, where P has coordinates (1, 32 ). Find the coordinate of Q. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework Page 12 of 14 Exercise 2.1.10 2 2 1. P (a sec θ, b tan θ) and Q(a sec φ, b tan φ), lie on the hyperbola xa2 − yb2 = 1. Use the result that ) − yb sin( θ+φ ) = cos( θ+φ ) to show that if PQ is a focal the chord PQ has equation xa cos( θ−φ 2 2 2 φ θ 1−e 1+e chord, then tan 2 tan 2 takes one of the values 1+e or 1−e . √ √ 2 2 2. P (2 3, 3 3) is one extremity of a focal chord on the hyperbola x3 − y9 = 1. Find the coordinates of the other extremity Q. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework Page 13 of 14 2 2 Exercise 2.1.11 Points P (a cos θ, b sin θ and Q(a cos φ, bsinφ) lie on the ellipse xa2 + yb2 = 1. Find the equation of the chord PQ. Hence show that if PQ subtends a right angle at the point A(a, 0) then PQ passes through a fixed point on the x-axis. Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Year 12 Topic 2 Homework 2.2 Past Exam Questions Copyright © 2000 - 2012 Yimin Math Centre (www.yiminmathcentre.com) Page 14 of 14