SOLUBILITY EQUILIBRIA SOLUBILITY Solubility: quantity of a substance that dissolves to form a saturated solution Solubility: g/L Molar solubility: mole/L Precipitation Dissolution When forward rate = backward rate: We have an _______________! Some salts are very soluble (> 0.1 M). Recall solubility rules. Some salts are sparingly soluble (< 0.1 M) sometimes referred to as ‘insoluble’. AgCl(s) Ag+(aq) + Cl!(aq) Precipitation and Solubility of ionic salts and their equilibrium in water MA(s) M+(aq) + A!(aq) The concentration of solid does not change at equilibrium CH112 LRSVDS BUFFERS part II 1 CH112 LRSVDS BUFFERS part II 2 SOLUBILITY CALCULATION SOLUBILITY Calculate [Ca2+] and [F-] for a saturated CaF2 solution. 1) Write the reaction: CaF2 (s) Ca+2 (aq) +2F! (aq) Solubility Product: Ksp AgCl AgBr AgI CdS ZnS Mg(OH)2 Ca(OH)2 CaF2 BaCO3 BaSO4 1.8 x 10-10 5.0 x 10-13 8.3 x 10-17 8.0 x 10-27 1.1 x 10-21 1.8 x 10-11 5.5 x 10-6 3.9 x 10-11 5.1 x 10-9 1.1 x 10-10 2) Make an ice table 3) Write the equilibrium expression Ksp = [Ca2+][F!]2 =3.9 x 10!11 at 25oC 4) What is the solubility? solubility = amount of salt dissociated CH112 LRSVDS BUFFERS part II 3 CH112 LRSVDS BUFFERS part II 4 SOLUBILITY CALCULATION Common Ion Effect Solubility and the COMMON ION EFFECT AgCl(s) What is the solubility of CaF2 in 0.01 M NaF solution? Ksp = 3.9 x 10!11 Ag+(aq) + Cl!(aq) CaF2 solubility = [Ca2+] = x [F!] = 0.01 M I C E CaF2(s) Ca2+(aq) + 2F!(aq) Add [Ag+] to solution at equilibrium Add [Cl!] to solution at equilibrium CH112 LRSVDS BUFFERS part II 5 CH112 LRSVDS BUFFERS part II 6 Effect of pH on Solubility Effect of pH on Solubility What is the solubility of Mg(OH)2 in water? Ksp = 1.8 x 10-11 What is the solubility of Mg(OH)2 in a solution with a pH of 9? Ksp = 1.8 x 10-11 (Buffered to remain at this pH) Mg(OH)2 Mg(OH)2 (s) CH112 LRSVDS BUFFERS part II 7 CH112 LRSVDS BUFFERS part II 8 Demo on Effect of pH on Solubility Demo on Effect of pH on Solubility 1. Milk of Magnesia Mg(OH)2 MgCl2 + 2NaOH " Mg(OH)2(s) + 2NaCl Mg(OH)2 (s) 3. Barium salts (continued) BaCl2 + 2 Na2CO3 " BaCO3(s) + 2NaCl BaCO3(s) Ba+2(aq) + CO32!(aq) CO32!(aq) + H2O HCO3-(aq) + OH-(aq) 2. Barium salts BaCl2 + 2NaOH " Ba(OH)2(s) + 2OH! Ba(OH)2 (s) CH112 LRSVDS BUFFERS part II 9 CH112 LRSVDS BUFFERS part II 10 Demo on Effect of pH on Solubility Effect of pH on common ions If either the anion or the cation is involved in an acid base equilibrium, then it is a common ion problem. Barium salts (continued) BaCl2 + 2 Na2SO4 " BaSO4(s) + 2NaCl Ba+2(aq) BaSO4(s) + SO4 2!(aq) Basic Metal hydroxides Example Mg(OH)2 Does Sulfate anion also react with water? SO42!(aq) + H2O Salts of weakly basic anions Examples: HSO4-(aq) + OH-(aq) ZnCO3 NaF What is a Basic anion? What about SO42-? CH112 LRSVDS BUFFERS part II 11 CH112 LRSVDS BUFFERS part II 12 Precipitation and Dissolution AMPHOTERISM Will Mn(OH)2 precipitate from 0.05 M MnCl2 solution if the pH = 8? Amphoterism is the ability of a molecule to act both as an acid and as a base. This results in metal hydroxides which are soluble in both acids and bases. Ksp = [Mn2+][OH!]2 = 1.9 x 10!13 1) MnCl2 (s) Hydration: Al3+(aq) # Al(H2O)63+ 2) If pH = 8, what is [OH-]? Al(OH)3(s) + 3H2O 3) Are we at equilibrium? In acid: Al(OH)3(OH2)3 + H+ Al(OH)3(OH2)3(s) Al(OH)2(OH2)4+(aq) solubility increases. In base: Al(OH)3(OH2)3 + OH! Al(OH)4(OH2)2!(aq) + H2O solubility increases. CH112 LRSVDS BUFFERS part II 13 CH112 LRSVDS BUFFERS part II 14 AMPHOTERIC METAL HYDROXIDES FORMATION OF COMPLEX IONS Hydration of metal ions There are amphoteric hydroxides of Al3+ Cr3+ Zn2+ Sn2+ Many transition metal ions Cu2+(aq) + 4 H2O(l) " Lewis Acid These involve formation of complex ions, such as: Al(OH)3(OH2)3 Metal Complex Cu2+(aq) # + H+ " Al(OH)2(OH2)4+ + OH! " Al(OH)4(OH2)2! Other Lewis bases react with metal ions to form complexes Amphoteric hydroxides Low and high pH increases solubility Al(OH)3 Cr(OH)3 Zn(OH)3 Sn(OH)2 other transition metal hydroxides CH112 LRSVDS BUFFERS part II + Lewis " Base Cu2+(aq) + 4 NH3(aq) Cu2+(aq) + 4 CN!(aq) Cu2+(aq) + 4 Cl!(aq) 15 CH112 LRSVDS BUFFERS part II 16 Problem Solving: METAL COMPLEX STABILITY Metal Complexes Cu(OH2)42+ + 4NH3 Cu(NH3)42+ + 4H2O [H2O] = constant Keq = Addition of 5 x10-3 total moles of Cu2+ to a 1.0 L solution of NaCN gives a solution of the complex ion [Cu(CN)4]2! (Kf = 1 x 1025). What is the concentration of uncomplexed Cu2+ ion if the concentration of cyanide ion in the final solution is 0.2 M? Keq/[H2O]4 = Kf = Kf VALUES OF METAL COMPLEXES Ag(NH3)2+ 1.7 x 107 Cu(NH3)42+ 5 x 1012 Cu(CN)421 x 1025 Ag(CN)21 x 1021 Ag(S2O3)232.9 x 1013 CH112 LRSVDS BUFFERS part II Cu2+(aq) + 17 CN!(aq) CH112 LRSVDS BUFFERS part II [Cu(CN)4]! (aq) 18 Applications of Complex Ion Formation CuCO3 is a sparingly soluble salt: Selective Precipitation of metal ions Add OH- to the following mixture of ions in solution; 0.05 M Mg2+ Ksp (CuCO3) = 2.3 x 10!10 0.02 M Cu2+ What is the solubility in water? 1) What [OH-] is necessary to begin precipitation of each ion? Ksp (Mg(OH)2) = 1.8 x 10-11 How can I get it to dissolve? Ksp (Cu(OH)2) = 2.2 x 10-20 2) Which ion will precipitate first as OH- is added to the solution? Will it dissolve in ammonia solution? What is Keq for the following reaction? Mg2+ + 2OH- Ksp CuCO3 = 2.3 x 10!10, Kf [Cu(NH3)4]2+ = 5 x 1012 CuCO3(s) + 4NH3(aq) Mg(OH)2(s) CO32!(aq) + [Cu(NH3)4]2+(aq) Cu2+ + 2OH- CH112 LRSVDS BUFFERS part II 19 Cu(OH)2(s) CH112 LRSVDS BUFFERS part II 20