Vhigh Vlow q E vd conducting material q battery A battery is connected to a conducting material to produce a potential difference ∆V across the material. The battery “pumps” the positive charges q from the low potential to the high potential side of the conductor. The charges inside the material are moving from high to low potential with an average drift speed vd. J silver copper gold q slope = σ vd J E iron E For many conductors it is found experimentally that the current density J is directly proportional to the electric field E. The proportionality constant is referred to as the conductivity “σ” of the material and its value depends on the conductor’s material. r r J = σE Ohm’s Law 1 Ohm’s Law Applied to a Cylindrical Conductor E A J vd q Vhigh Vlow L The conducting cylinder has a length L and cross sectional area A. The conductivity is assumed to be uniform and the electric field E is related to the potential difference by: ∆V = Vlow − Vhigh = − ∫ Eds = − EL If we now let ∆V be the magnitude of the potential difference across the cylinder we have: E= ∆V L Ohm’s Law Applied to a Cylindrical Conductor E A J q Vhigh vd Vlow L The current density is related to the current and cross sectional area by: J = I A Ohm’s Law applied to the cylinder gives: J = σE ⇒ I ∆V =σ A L L ⇒ ∆V = I σA 2 Ohm’s Law Applied to a Cylindrical Conductor E A J vd q Vhigh Vlow L L ∆V = I σA The electrical resistance, R, of the cylindrical conductor is: R= L ρL = σA A ρ is the reciprocal of σ and is called the resistivity. ∆V = IR Alternate form of Ohm’s Law Summary E A q Vhigh vd Vlow L The field E is in the direction from high to low potential. The charge moves from high to low potential with a constant drift speed. The resistance of the conductor is: The potential difference, current and resistance are related by Ohm’s Law: R= L ρL = σA A ∆V = IR 3