Chapter 30 Magnetic Induction Magnetic Induction • Magnetic Flux • Induced EMF & Faraday’s Law • Lenz’s Law • Motional EMF • Generators & Motors • Eddy Currents • Inductance • Magnetic Energy • RL Circuits MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 2 Magnetic Induction A changing magnetic field that causes the magnetic flux to change through a surface, bounded by a closed stationary loop of wire, induces a current in that wire. Since there is a flow of current there must be a source of this current and it is attributed to an induced emf which causes the induced current. The process is called induction If the flux stops changing then the induced emf goes to zero. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 3 Magnetic Induction The induced emf is distributed over space and is the primary effect of the changing magnetic flux. It doesn’t need a circuit. The induced emf will be there even if there is no wire. The purpose of the wire coil is to allow us to measure the effect of the induced emf and demonstrate its presence. Most important thing to remember The induced emf tries to maintain the existing magnetic flux and opposes any changes in the flux. No changes in magnetic flux ==> No induced emf MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 4 Magnetic Flux MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 5 Magnetic Flux ˆ = ∫ Bn dA φm = ∫ B ⋅ ndA S S The units of magnetic flux are Webers (W). 1 Wb = 1 Tm2 B is proportional to the number of field lines per unit area. B can be thought of as a flux density in Webers/m2 MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 6 Magnetic Flux Example Assume a flat surface area S ˆ = BAcosθ = Bn A φm = B ⋅ nA φm = NBAcosθ In the simplest case MFMcGraw-PHY 2426 φm = NBA with nˆ B Chap30a-Magnetic Induction-Revised: 10/04/2012 7 Induced Emf and Faraday’s Law Stationary Wire Coil - Moving Magnet Emf = ∫ E NC ⋅ dL C The induced emf is the result of the nonconservative electric field, Enc. For a conservative electric field this integral would be zero. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 8 The induced emf is such that it produces an induced current whose magnetic flux opposes the change that caused the emf. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 9 Induced Emf and Faraday’s Law d ˆ Emf = - ∫ B ⋅ ndA dt S Faraday’s Law d d ˆ = - φm Emf = ∫ Enc idL = - ∫ B indA dt S dt C This is where we finally have to get the direction of C correlated with the direction of unit vector normal to S. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 10 Faraday’s Law Farther away The right hand rule determines the direction of the normal to S based on the direction around C. Closer MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 11 Induced Nonconservative E-Field Calculate the magnitude and direction of the ENC field both inside and outside of the ring. Uniform magnetic field directed into the page everywhere inside r < R. Conductive ring of radius R MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 12 Induced ENC-Field - Problem Setup Contour C is traversed in a clockwise direction. Whatever direction we pick will be referred to as the positive tangential direction. This means that the corresponding normal to the surface S, enclosed by C, points into the page. Our goal is to align this normal of S with the direction of B. At this point we haven’t totally determined the problem to be solved so we do not know the final direction of ENC. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 13 Induced ENC-Field - Problem Setup The direction of B will remain fixed and its value will remain zero outside the wire. We will change the flux by letting the magnitude of B change with time. Therefore dB/dt is not zero ε dφm = ∫ E NC ⋅ dl = C dt C E NC ⋅ dl = E NC ∫ dl = E NC ( 2πr ) MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 ∫ C 14 Induced ENC-Field ε ∫ dφm = ∫ E NC ⋅ dl = C dt E NC ⋅ dl = E NC ( 2πr ) C φm = ∫ S B⋅ˆ ndA = ∫ Bn dA = Bn ∫ dA = Bπr 2 dφm ∫C ENC ⋅ dl = - dt MFMcGraw-PHY 2426 S S d E NC ( 2πr ) = Bπr 2 dt 1 1 dB 2 dB E NC = πr = r 2πr dt 2 dt ( Chap30a-Magnetic Induction-Revised: 10/04/2012 ) 15 Induced ENC-Field E NC 1 dB =r 2 dt The positive direction on C was chosen to be clockwise. Therefore the minus sign on ENC indicates its points in a counter clockwise direction. Trace the result intuitively. B increases into the page. This induces a B field out of the page. This induced field requires a counter clockwise current The current is driven by a counterclockwise pointing ENC. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 16 Induced ENC-Field for r > R dφm = ∫ E NC ⋅ dl = C dt ∫ E NC ⋅ dl = ENC ( 2πr ) Same as before φm = ∫ Bn dA = Bn ∫ dA = BπR 2 No B-field past r = R ε C S dφm ∫C ENC ⋅ dl = - dt MFMcGraw-PHY 2426 S d E NC ( 2πr ) = BπR 2 dt 2 1 dB R dB 2 E NC = πR =2πr dt 2r dt ( Chap30a-Magnetic Induction-Revised: 10/04/2012 ) 17 Induced ENC-Field for r > R E NC R 2 dB =2r dt The positive direction on C was chosen to be clockwise. Therefore the minus sign on ENC indicates its points in a counter clockwise direction. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 18 Lenz’s Law MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 19 Lenz’s Law “The induced emf is in such a direction as to oppose, or tend to oppose, the change that produces it.” Alternatively: “When the magnetic flux through a surface changes, the magnetic field due to any induced current produces a flux of its own through the same surface and opposite in sign to the initial change in flux. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 20 Lenz’s Law It is as if the induced emf is producing a virtual bar magnet to oppose the motion of the bar magnet that is causing the inital changes. Motion of the magnet increases the flux through the loop pointing to the right. The induced current creates a B-field pointing to the left, i.e. a North pole, to decrease the increased flux. It is as if the original bar magnet sees an “image” of itself opposing it. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 21 The Same Motion in More Detail The B-field increases to the right MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 22 The Same Motion in More Detail The ring opposes the increasing field with a field to the left (B2 ). MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 23 The Same Motion in More Detail The field B2 requires a counter-clockwise current (I). MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 24 The Motion is Relative Motion of the loop decreases the flux through the loop pointing to the right. The induced current creates a B-field pointing to the right, i.e. a South pole, to increase the previously decreased flux. It is as if the original bar magnet sees an “inverted image” of itself replacing the decreased flux. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 25 Coupled Induced Current Switch Open The piece of iron, around which the wires are wrapped, enhances the coupling of the magnetic flux between the two circuits. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 26 Coupled Induced Current Switch Closed MFMcGraw-PHY 2426 Switch Open Chap30a-Magnetic Induction-Revised: 10/04/2012 27 Motional EMF MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 28 Flip Coil Magnetic Field Measurement Current Integrator MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 29 Flip Coil Magnetic Field Measurement dφ ε = - dt εdt = -dφ m m dQ IRdt = R dt = -dφm dt R ∫ dQ = - ∫ dφm = -(φmf - φmi ) N ˆ f - B ⋅ nˆi A Q=B⋅n R N 2NBA Q = - ( B(-1) - B(1)) A = R R QR B= 2NA ( MFMcGraw-PHY 2426 ) Chap30a-Magnetic Induction-Revised: 10/04/2012 30 Induced Emf - Changing Flux Area Surface area for calculating magnetic flux. Unit normal vector parallel to field. Therefore our contour C’s positive direction is clockwise Frictionless, conductive rod Stationary conductive rails Uniform magnetic field directed into the page MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 31 Induced Emf - Changing Flux Area As the bar moves to the right the area increases. The flux crossing the surface S increases, pointing into the page. A current is induced in the blue loop such that it produces a magnetic field out of the page to oppose the flux increase. This current is counter clockwise. φm = Blx ; ε MFMcGraw-PHY 2426 dφm dx = Bl = Blv dt dt dφm == -Blv dt Chap30a-Magnetic Induction-Revised: 10/04/2012 32 Motional Emf Although the bar appears after the example of the moving rod on the rails this rod is all by itself. The conductive bar is originally neutral. The conventional positive charges in the conductor are moving through a uniform magnetic field. They experience an upward Lorentz force due to the bar’s motion through the magnetic field. Since there is not a complete circuit the positive charges pile up at the top and the bottom is effectively negative. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 33 Motional Emf An electric field builds up parallel to the rod due to the separated charge called E This field increases until it balances the Lorentz force on the charges qE = qvB E = vB ∆V = El = vBl MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 34 Magnetic Drag ε Blv I= = R R Blv B 2l 2 v dv F = -IlB = lB = =m R R dt MFMcGraw-PHY 2426 dv B 2l 2 =dt v mR v f dv B 2l 2 t f ∫vo v = - mR ∫0 dt vf B 2l 2 ln = tf vo mR mR -tτ v(t) = vo e ; τ = 2 2 Bl Chap30a-Magnetic Induction-Revised: 10/04/2012 35 Generators and Motors MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 36 Generators Motion supplied MFMcGraw-PHY 2426 Voltage output Chap30a-Magnetic Induction-Revised: 10/04/2012 37 DC AC MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 38 Motors Motion Output Voltage Input MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 39 Eddy Currents MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 40 Eddy Currents The changing flux inside the conductor induces an emf which gives rise to an induced current that flows in the direction shown below. This current flow resembles the eddies seen in the water and hence the name Leaving the field region, the flux is decreasing therefore the induced flux will oppose it and will be into the page. Sometimes these eddy currents are desired and sometimes they are not wanted. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 41 Dissipating Eddy Currents If the eddy currents are not wanted they can be reduced by breaking up the pathway of the current flow as shown below. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 42 Eddy Currents - Damping Force Sometimes the eddy currents are wanted! MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 43 Electromagnetic Brake MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 44 Eddy Current Demo from Carleton Physics http://www.youtube.com/watch?v=OJvEOXsSuaQ http://www.hscphysics.edu.au/resource/EddyCurrents.flv MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 45 Self Inductance MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 46 Self Inductance A current carrying wire, wrapped into the shape of a coil is subject to self inductance. The magnetic field lines from one part of the coil pass through other coils of the same wire. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 47 Self Inductance of a Long Solenoid Although the geometry might be difficult since B is proportional to I then the flux through the coil should also be proportional to I Units: 1 Henry (H) = 1 Wb/A= 1Tm2/A φm = LI ( ) φm = NBA = N µ0 nI A = µo N 2 IA l = µo N 2 IA l 2 l φm = µo n 2 IAl φm L= = µ on 2 Al I MFMcGraw-PHY 2426 Factors only depend on geometry Chap30a-Magnetic Induction-Revised: 10/04/2012 48 Mutual Inductance MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 49 Mutual Inductance When circuits are physically close enough and/or the currents are large enough the magnetic flux from one circuit may pass through or couple into the second circuit. This is referred to as mutual inductance. Sometimes it is desirable and other times it is NOT. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 50 Mutual Inductance We can write the flux of circuit 1 through circuit 2 as φm12 φm12 = M 12 I 1 We can write the flux of circuit 2 through circuit 1 as φm21 φm21 = M 21 I 2 M12 and M21 are the mutual inductances between the two circuits. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 51 Mutual Inductance φm12 = M 12 I 1 φm21 = M 21 I 2 The mutual inductances M12 and M21 depend on the geometrical arrangement of the circuits. For the mutual inductance to be useful the circuit geometry must stay fixed. For arbitrary circuits it is difficult to calculate the mutual inductance. Our old friend the solenoid is one of the easier cases. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 52 Mutual Inductance Calculating the mutual inductance is really an exercise in calculating the flux φ =M I m12 ( ) 12 1 ( ) ( ) φm12 = N 2 B1 πr12 = n2 lB1 πr12 = n2l ( µo n1 I 1 ) πr12 φm12 = µo n1n2lπr12 I 1 φm12 M 12 = = µ on1n 2lπr12 I1 It can be shown that φm21 M 21 = = µ on 2n1 lπr12 I2 MFMcGraw-PHY 2426 Therefore M 21 = M 21 = M Chap30a-Magnetic Induction-Revised: 10/04/2012 53 Tesla Coil: Low Voltage to High Voltage Outer coil has few loosely spaced loops. The high voltage from the inner coil breaks down the Argon gas in the light bulb and causes the streaming arcs of current. The inner coil has many closely spaced loops. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 54 Commercial Handheld Tesla Coil Tesla coils turn low voltage into relatively high voltage Technical Details • High-frequency transformer can step up ordinary 110-volt electricity to thousands of volts • Creates impressive 3-inch sparks • Adjustable from 10,000 to 50,000 volts • Has momentary on/off switch in its Bakelite handle MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 55 Simple Tesla Coil Circuits MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 56 DIY DC Handheld Tesla Coil http://www.rmcybernetics.com/projects/DIY_Devices/plasma-gun.htm MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 57 Handheld Tesla Coil http://www.rmcybernetics.com/projects/DIY_Devices/plasma-gun.htm MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 58 Extreme DIY Tesla Coil http://tesladownunder.com/ MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 59 Extreme DIY Tesla Coil Circuit http://tesladownunder.com/ MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 60 Magnetic Energy MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 61 Stored Energy A capacitor stores electrical energy in its electric field An inductor stores magnetic energy in its magnetic field. These components are referred to as reactive components because they store energy instead of dissipating it like a resistor. Inductors and capacitors tend to slow down the speed of a circuit because it takes time to build up their fields and to let their fields decay back to zero. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 62 Magnetic Energy The voltage on L is proportional to the derivative of the current with time. dI VL = L dt A simple RL series circuit MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 63 Magnetic Energy dI Vi = Vo - IR - L = 0 ∑ dt Loop Use Kirchhoff’s Loop Rule on this circuit. dI dt Now multiply each term by I to turn each term into a power. Vo = IR + L Power stored in L dI Vo I = I R + LI dt 2 Power from battery MFMcGraw-PHY 2426 Power dissipated in R Chap30a-Magnetic Induction-Revised: 10/04/2012 64 Magnetic Energy Stored in L dI Vo I = I R + LI dt 2 Now power is the time rate of change of energy Magnetic Energy in Inductor L MFMcGraw-PHY 2426 dU m dI d 1 = LI = LI 2 dt dt dt 2 1 2 U m = LI 2 Chap30a-Magnetic Induction-Revised: 10/04/2012 65 Magnetic Energy Stored in a Solenoid Bz = µ 0nI L = µ 0n 2 AL 1 2 U m = LI 2 Solenoid Magnetic Energy Magnetic Energy Density MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 66 RL Circuits MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 67 RL Circuits When S is in position e the current in R is building up to steady state. When S is in position f the current in R is decaying to zero. Make before break switch MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 68 Switches Break-before-make Open circuit MFMcGraw-PHY 2426 Make-before-break Closed circuit Chap30a-Magnetic Induction-Revised: 10/04/2012 69 Transient Current in RL Circuit If = ε o R1 + R The presence of the inductor slows the circuit down. It takes a time equal to about 3-4 time constants to achieve full steady state current after the switch is moved to position e MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 70 Transient Current in RL Circuit I(t) = I o e -tτ The presence of the inductor slows the circuit down. It takes a time equal to about 3-4 time constants for the current to go back to zero after the circuit is moved to position f. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 71 Initial Currents & Final Currents We want to examine the operation of this LR circuit at very short times - transient response and at very long times steady state response. MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 72 Transient Response Note: This is not a series circuit as in the previous example. Rule 1: The presence of the inductor prevents the current from changing abruptly. Therefore since the current is zero just before the switch is closed then it is also zero right after the switch is closed. In the transient response it is as if the L isn’t there I3 = 0 MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 73 Transient Response V = IR1 + IR2 V I= R1 + R2 MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 74 Steady State Response When the current reaches its constant steady state level di/dt is zero and the voltage across L is zero. This effectively reduces L to a wire and that shorts out R2. V = IR1 V I= R1 MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 75 Extra Slides MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 76 MFMcGraw-PHY 2426 Chap30a-Magnetic Induction-Revised: 10/04/2012 77