Algebra 2A: Ch. 2 Practice Test
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Name
Standards Covered: 1, 2
Date/Period
1. Find the slope of the line through the pair of points.
a) (5, 2) and (5, -7)
b) (-7, 3) and (-12, 10)
2. Write in standard form an equation of the line passing through the point with the given slope.
Slope = -5 ; (-4, 5)
1
3. For 𝑓(𝑥) = 6𝑥 + 7 find 𝑓(−3) and 𝑓 (3)
4. Find the equation of each line.
a) through (3, 7) and perpendicular to 𝑦 = 3𝑥 − 1
b) through (3, 7) and parallel to 𝑦 = 3𝑥 − 1
c) through (-2, 5) and vertical
d) through (-6, 2) and horizontal
5. Make a mapping diagram of the relation. Determine if the relation is a function (yes or no).
a) {(1,-1),(2,-3),(3,-5),(4,-7)} domain
range
b) {(0,1),(0,-1),(3,4),(3,-4)}
6. Graph each equation.
2
a) 𝑦 = − 3 − 1
b) 𝑦 + 2𝑥 = −2
domain
range
7. Find the slope and intercepts of each line.
a) 𝑦 = 2𝑥 + 50
slope =
x-int. =
y-int. =
b) 3𝑥 + 4𝑦 = 12
slope =
x-int. =
y-int. =
8. Write an equation for the translation from the parent function f ( x)  x .
a) right 3 unit and down 4 units
b) vertical stretch by a factor of 4, right 7 units, and down 1 unit
9. Describe the translation.
1
a) 𝑦 = 2 |𝑥 − 9| + 4
b) 𝑦 = −2|𝑥| − 3
10. Find the vertex of the function 𝑦 = |𝑥 − 3| + 5
11. Graph the absolute value equation. You can make and use a t-chart or use translations.
a) 𝑦 = 4|𝑥| + 1
b) 𝑦 = −|𝑥 + 3|
12. Graph each inequality.
a) 𝑦 ≤ 3𝑥 − 1
b) −3𝑦 < 9 − 6𝑥
13. Graph the absolute value inequality.
14. Write an inequality for the graph below.
a) 𝑦 ≥ |𝑥 + 1| − 4
Answer Key for Chapter 2 Practice Test
Answer Key for Chapter 2 Practice Test
7
b) slope = − 5
1a) slope =undefined
2. 5𝑥 + 𝑦 = −15
2. 5𝑥 + 𝑦 = −15
1
3. 𝑓(−3) = −11
1
4a) 𝑦 = − 3 𝑥 + 8
c) x = -2
3. 𝑓(−3) = −11
b) 𝑦 = 3𝑥 − 2
4a) 𝑦 = − 3 𝑥 + 8
5a) domain:{1, 2, 3, 4} range{-1, -3, -5, =7}; yes
b) domain:{0, 3} range: {1, -1, 4, -4}; no
6a) see graph
3
b) slope = − 4
b) see graph
x-int. = -25
y-int. = 50
x-int. = 4
y-int. = 3
8a) 𝑓(𝑥) = |𝑥 − 3| − 4
1
𝑓 (3) = 9
d) y = 2
7a) slope = 2
7
b) slope = − 5
1a) slope =undefined
b) 𝑓(𝑥) = 4|𝑥 − 7| − 1
9a) Vertical Shrink by 1/2, right 9, up 4
b) reflects across x-axis, vertical stretch by 2, down 3
𝑓 (3) = 9
1
b) 𝑦 = 3𝑥 − 2
c) x = -2
d) y = 2
5a) domain:{1, 2, 3, 4} range{-1, -3, -5, =7}; yes
c) domain:{0, 3} range: {1, -1, 4, -4}; no
6a) see graph
7a) slope = 2
3
b) slope = − 4
b) see graph
x-int. = -25
y-int. = 50
x-int. = 4
y-int. = 3
8a) 𝑓(𝑥) = |𝑥 − 3| − 4
b) 𝑓(𝑥) = 4|𝑥 − 7| − 1
9a) Vertical Shrink by 1/2, right 9, up 4
c) reflects across x-axis, vertical stretch by 2, down 3
10. V: (3, 5)
10. V: (3, 5)
11a) V: (0,1); see graph
11a) V: (0,1); see graph
b) V: (-3, 0); see graph
12a) see graph
b) see graph
b) V: (-3, 0); see graph
12a) see graph
13. see graph
13. see graph
14. 𝑦 ≥ |𝑥 + 2| + 4
14. 𝑦 ≥ |𝑥 + 2| + 4
b) see graph