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A New Perspective on the Poisson-Boltzmann

Equation and some Related Results

Ping Sheng

Department of Physics

Hong Kong University of Science and Technology

Controlled Structural Formation of Soft Matter

Beijing, China

August 12, 2015

Phys. Rev. X 4 (1), 011042

1

Collaborators

Li WAN Shixin XU Maijia LIAO Chun LIU

2

Introduction to electrokinetics

• Charge separation at the fluid-solid interface (e.g. silica-water interface) leads to an electrical double layer, which is the basis of electro-kinetics .

Si

O

H

-

+

+

-

-

+

Electrical double layer

0

Distance from the interface

ζ : Zeta potential

λ

D

: Debye length

3

Poisson-Boltzmann equation

const .

Boundary of the PB equation

 2

 

1

 2

D sinh

  

0 a

Fluid

Integral of the right hand side of the PB equation yields the net charge in the Debye layer.

---- Counter-balanced by the surface charge.

Surface charge

• Hence, the PB equation divides the electrical double layer into two halves.

---- They can be problems when the fluid channel width is smaller then twice the Debye length.

---- Is a holistic treatment possible?

4

Treating electrical double layer as an integral entity

Fluid const .

Boundary of PB equation

Present Boundary

• The computational domain must be overall neutral.

a

• A constant potential boundary condition would only yields a constant potential solution.

 

0

• From the Gauss Theorem, the only compatible Neumann boundary condition is zero normal electric field.

Surface charge

• Uniform boundary condition is not possible to describe the physical situation!

--- Go back to the charge separation process!

5

Surface potential trap model

2

( )

0.

( r

 a )

, for a for r a

0 r a .

Height of the potential trap is approximated by the hydrogen bond strength

Introduces an asymmetry to the positive and negative ions

--Attributes an energy cost to interfacial charge separation process.

Functional form of f(r) can not be arbitrary.

1

 

 r

 f r

 r 

 c

C should yield zero(no net charge brought by the potential trap).

• The potential trap is only for H

+

 and ions.

6

Outline of the mathematical approach

Derive a charge-conserved PB(CCPB) equation whose right hand side must integrate to zero.

Total ion density must be written as: n

O

 n

2

 a

----

 

• Definition of a global chemical potential that is derived from the condition of overall charge neutrality.

---- Different from the local electrochemical potential component such as ion concentration and local electrical potential.

7

Poisson-Nernst-Planck equations and their static limit

PB equation

J n

J n

 n

 n

Assume

 exp exp

0

 e

 e

/ k T

/

 n





J

/

/ n  n n t t 

 

 u u

D

(

(

B

 

B e e n n

 n

) n

 

 e

 n

J

 n  n

 

0,

0.

, k T n

 J n 

 

D

 n

 2    e

 n

(

 n

 dr

)

 

,

,

0,

0,

CCPB equation n

 n

J n

J n

0

 

   f ) / k T exp

 e (

  f ) / k T

 f ) / k T ]

 n V

   dr exp[

 e (

  f ) / k T ]

 2

 

1

 2

D sinh

D  2

 k T

B

2 e n

  e

  k T

1

 

 r

 r 

2

 o

 a

0

 a

0 exp e (

 r exp e (

 r exp

 e (

  f ) /

B f ) /

B exp

 e (

  f ) /

B f ) /

B

8

.

Global chemical potential

Reformulate the CCPB with a definition of chemical potential

(Salt addition considered)

1

  r r  r

 r 

 e

{ n

OH

 n

H

 exp[

 e (

  f ) /

B

]

 n

Cl

) /

B

] f ) /

B

]

 n

Na

 exp[

 e (

 

) /

B

]}

R.H.S.

+ and – ion densities separately integrates to zero:

  k T

B

2 e ln

 a

0

{ n

OH

 e

 a

0

{ n

H

 exp[

 e (

 

 f ) / k T

B

]

 n

Cl

 f ) / k T

B

]

 n

Na exp[ e

/ k T

B

]} rdr exp[

 e

/ k T

B

]} rdr

 n

    

OH

 n

Cl

 n

Na

 n

H

 n n

O

 n

2

 a

9

Solution process (I)

1

  r

 

 r

 e

{ n

OH

 n

H

 exp[

 e (

  f ) /

B

]

 n

Cl

) / f ) /

B

]

 n

Na

 exp[

 e (

 

) /

]

]}

  k T

B

2 e ln

 a

 a

0 n

{

OH

 e

{ n

H

 exp[

 e (

 

) / ]

B

 f k T n

Cl

 f ) / k T

B

]

 n

Na

 exp[ e

/ k T

B

]} rdr exp[

 e

/ k T

B

]} rdr

0 n

(1) Solve (1) and (2) simultaneously, with as the inputs,

(3) From one can obtain the a

2

2

 a

0

{ n

OH

 surface dissociation charge density f ) /

B

]

 n

Cl

) /

B

]} rdr

 as :

2 a

2 a

0

{ n

H

 exp[

 e (

 

 n

O  n

2

 a f ) /

B

]

 n

Na

 exp[

 e (

 

) /

B

]} rdr

(1)

(2)

10

Solution process (II)

(4) Surface charge densities s can be obtained by integrating the net charge densities inside the surface potential trap.

NOTE:

(a) In the inputs , the law of mass action must be obeyed. That is, n

H

 n

( M )

 n

OH

( M )

10

14 ( M 2 )

(b) In the presence of salt, acid, or alkaline additions, there will be ions

 other than and . These ions do not interact with the solid surface. That is, they should not be allowed to enter the surface potential trap. A mathematical implementation of this constraint is described below .

(c) Since the only interaction between the different types of ions is electrical, hence besides the interaction with the solid surface, all often positive and negative ions are treated equally.

11

Surface-specific potential trap model

 o

 

 

 x o | a



 

 x f f

| a



 o

Na + , H + ,

Cl , OH -

Potential trap

 f

H + , OH -

Interfacial

Potential trap intended to model the interfacial charge separation energy

2

( )

0.

( r

 a )

, for a for r a

0 r a .

Potential trap height

12 r

Re-derivation of the PB equation from the

CCPB equation

Charge conserved PB equation with a definition of chemical potential (salt addition considered)

1

1 n

OH

 r r

1

 n

Cl

 r r o

1 f

 r

 n

Na

 e r

 e r n o

{ n

Cl

 e

Na

{

 r n

 n

 o

OH

H

 e

2

 e

 n n

 e e

(

 e n

2

 exp[

 o

Na

 f

(

Cl

PB

(

(

)

)

H n

/

(

 k T

PB

1

OH

) f

B e

2

D

)

) sinh

)

( PB )

(

]

]

/

/

--Arising from charge neutrality condition :

)

B k T

 n e

B

 

OH

 e

H

( PB

B

]

( exp[

( PB  )

) n

H

/

/

 e (

B exp[ e

 o

 o

 

) /

( PB )

]

]} (

 f

) /

/

 k T

B

]

 f ) / k

B

T ]} n

H

( M )

 n

OH

M

 

14

M

2

( ) 10 ( )

 

2 e ln

0

0 a



{

 n

OH

 exp( e

 o

/ k T

B

)

 n

Cl

 a



{ n

H

 exp(

 e

 o

/ k T

B

)

 n

Na

 exp( e

 o

/ k T

B

)} rdr exp(

 e

 o

/ k T

B

)} rdr

 a

 a

 a

 a



 n

OH

 n

H

 f exp[

 e (

 f

 f ) / k T rdr

B

] f ) / k T rdr

B

13

]

.

Charge-regulation phenomenon

Charge regulation phenomenon denotes the fact that the surface charge can not remain constant as the fluid channel width decreases.

Usually surface site density, equilibrium constants pK, Stern layer capacitance parameters are needed for explaining the data.

No Salt , pH=8.2 NaOH

s contains some ions captured from the bulk. However, when the radius decreases below , s is seen to approach . .

In the large channel width limit, our reformulation yields the same results as the traditional

PB equation.

Zeta potential

Zeta potential

-the basis of the EK effects that arises from charge separation and its associated potential variation

Average velocity: u z

2 r u a

1

2

2 z

 a

2

0 a

2 r

2

2 r

 a

 r

2 z

2

[(

(

2 z

PB

)

1

1 r

 

1

 r

2

  z

E

( PB ) r

 r

 1

E

( PB ) z 1

0

]

  z

P z

  rdr

2 

 r

(

 

(

E z a

)

2

( PB )

2

1

 

 r a   r

0

( PB ) a d r a

 

E z

No Salt , pH=8.2 NaOH

-Zeta potential has the same value as the negative of the chemical potential in large fluid channel down to 10 μm but the two deviate from each other as the fluid channel width diminishes. In particular, the zeta potential, or EK effect, diminishes in small channels.

15

Isoelectric point and dipole inversion

Potential trap height γ=510mV

Outside

Potential Trap

Isoelectric point is pH2.5, in good agreement with experimental data.

• Consistent with experiment: Net polar orientation of interfacial water molecules was observed to flip close to pH4.

16

Net electronic charge per μm y

Donnan potential

pH=7 No Salt

Fluid

Net Charge Distribution:

R=0.7μm a

SiO

2

Nanochannel h a=0.2μm h/2=0.2μm

0 2 4 × 10 4

/

 m

3 a: channel radius

17

Comparison with force measurements

F

 k T

B

A

 d x

 n

Na

 n n

Na

 n o

 n

H

 n n

H

 n o

 n

OH

 n n

OH

 n o

 n

Cl

 n n n

Cl

 

 o 2 k T

B

|

 

|

2  efN

Mixing entropy

Electrical interaction energy

CCPB predicts both the range and the magnitude of the force as a function of

18 pH and salt concentration.

Thanks for your attention!

19

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