Chapter 5
Graphing and
Optimization
Section 1
First Derivative and Graphs
Objectives for Section 5.1
First Derivative and Graphs
β
Part 1:
β
Use the first derivative to determine when functions are increasing or decreasing.
β
Part II:
β
Use the first derivative to determine the local extrema of a function.
Barnett/Ziegler/Byleen Business Calculus 12e 2
Increasing/Decreasing Intervals
From a Graph f(x) is increasing on the interval (a, b) π ′ π ′ π₯ > 0 π₯ = 0 on the interval (a, b) when x = b f(x) is decreasing on the interval (b, c) π ′ π₯ < 0 on the interval (b, c)
Barnett/Ziegler/Byleen Business Calculus 12e 3
Derivatives on a Graph π π ′
′ π₯ = 0: π₯ > 0: π₯ = π
1, π
2
, π
3
, π
5 π
2
, π
3
∪ π
4
, π
5 π ′ π₯ < 0: −∞, π
1 π ′ π₯ = π’ππππππππ:
∪ π
1
, π π₯ = π
2
4,
∪ (π π
6
5
, π
6
∪ π
, π
7
3
)
, π
4
∪ π
6
, ∞
Barnett/Ziegler/Byleen Business Calculus 12e 4
Partition Points
ο§
Partition points are locations where there’s the potential for the derivative to change sign.
ο§
Partition points occur when the derivative is zero or undefined.
Barnett/Ziegler/Byleen Business Calculus 12e 5
Increasing/Decreasing Intervals
Using Calculus
1. Set π
′ π₯ = 0 πππ π πππ£π πππ π₯
•
These x values are called partition points
2. Identify values of x that make π ′ π₯ = π’ππππππππ
• These are also partition points
3. Plot partition points on a sign chart.
4. Plug in test numbers into π ′ π₯ .
5. These will indicate intervals where π(π₯) is increasing/decreasing.
6. Write your answer using interval notation.
Barnett/Ziegler/Byleen Business Calculus 12e 6
Example 1 π f ( x ) = x 2 + 6 x + 7 Find the intervals on which f(x) is increasing/decreasing.
′ π₯ = 2π₯ + 6 π ′ π₯ ππ πππ£ππ π’ππππππππ.
0 = 2π₯ + 6 π₯ = −3 π′(π₯) − − −
0 π(π₯) πππππππ πππ −3
−∞, −3
+ + + πππππππ πππ
−3, ∞
Barnett/Ziegler/Byleen Business Calculus 12e 7
Example 2 f ( x ) = (1 – x ) 1/3 Find the intervals on which f(x) is increasing/decreasing.
π ′ π₯ =
−1
3 1−π₯
−1
0 =
3 1 − π₯ 2 3 ππ π πππ’π‘πππ π₯ ≠ 1 π′(π₯) − − − ππ· − − −
1 π(π₯) πππππππ πππ: −∞, 1 ∪ (1, ∞)
Barnett/Ziegler/Byleen Business Calculus 12e 8
Example 3 π π₯ = 8 ln π₯ − π₯ 2
Find the intervals on which f(x) is incr/decr. (Note: x > 0 because can’t take ln of a negative #) π′(π₯) =
=
8 π₯
8 π₯−
− 2π₯
2π₯
2 π₯
=
2(2−π₯)(2+π₯) π₯
=
=
8−2π₯
2 π₯
2(4−π₯
2
) π₯
0 =
2(2−π₯)(2+π₯) π₯ π₯ = 2, −2 π₯ ≠ 0 π′(π₯) ππ· π(π₯)
0 2
πΌπππ: 0,2 π·πππ: (2, ∞)
Barnett/Ziegler/Byleen Business Calculus 12e 9
Example 4 π₯
2 π π₯ = π₯+4
Find the intervals on which f(x) is incr/decr.
π′ π₯ =
πΏπ»
′
−π»πΏ
′
πΏ 2 π₯ + 4 2π₯ − π₯ 2 (1) π′(π₯) = π ′ π₯ = π₯ + 4 2 π₯ 2 + 8π₯ π₯ + 4 2
= π₯(π₯ + 8) π₯ + 4 2 π₯(π₯ + 8)
0 = π₯ + 4 2
0 = π₯(π₯ + 8 ) π₯ = 0, −8 x
οΉ
-4 π′(π₯) + + 0 − − ππ· − − 0 + +
−8 −4 0 π(π₯) πΌπππ: −∞, −8 ∪ 0, ∞ π·πππ: −8, −4 ∪ (−4,0)
Barnett/Ziegler/Byleen Business Calculus 12e 10
Example 5
Match each graph with it’s sign chart.
π΄
π·
π΅
πΈ
Barnett/Ziegler/Byleen Business Calculus 12e
πΆ
πΉ
11
Homework
Find increasing/decreasing intervals only!
Barnett/Ziegler/Byleen Business Calculus 12e 12
Objectives for Section 5.1
First Derivative and Graphs
β
Part 1:
β
Use the first derivative to determine when functions are increasing or decreasing.
β
Part II:
β
Use the first derivative to determine the local extrema of a function.
Barnett/Ziegler/Byleen Business Calculus 12e 13
Critical Values
In the first part of the lesson, you learned how to find partition points . These points were used to determine intervals for which the graph of f(x) is increasing/decreasing.
Critical values are the partition points where local extrema
(maxima/minima) might be located.
Barnett/Ziegler/Byleen Business Calculus 12e 14
Local Extrema
When the graph of a continuous function changes from rising to falling, a high point or local maximum occurs.
When the graph of a continuous function changes from falling to rising, a low point or local minimum occurs.
Theorem.
If f is continuous on the interval ( a , b ), c is a number in ( a , b), and f ( c ) is a local extremum, then c is a critical value.
Barnett/Ziegler/Byleen Business Calculus 12e 15
First Derivative Test
Let c be a critical value of f . That is, f ( c ) is defined, and either f
ο’
( c ) = 0 or f
ο’
( c ) is not defined. Construct a sign chart for f
ο’
( x ) close to and on either side of c .
f (x) left of c f (x) right of c f (c)
Decreasing
Increasing
Decreasing
Increasing
Increasing local minimum at c
Decreasing local maximum at c
Decreasing not an extremum
Increasing not an extremum
Barnett/Ziegler/Byleen Business Calculus 12e 16
Graphs & Local Extrema
ο§ Let’s first look at some examples of graphs with local extrema…
Barnett/Ziegler/Byleen Business Calculus 12e 17
First Derivative Test f
ο’
( c ) = 0: Horizontal Tangent
Barnett/Ziegler/Byleen Business Calculus 12e 18
First Derivative Test f
ο’
( c ) = 0: Horizontal Tangent
Barnett/Ziegler/Byleen Business Calculus 12e 19
First Derivative Test f
ο’
( c ) is not defined but f ( c ) is defined
Barnett/Ziegler/Byleen Business Calculus 12e 20
First Derivative Test f
ο’
( c ) is not defined but f ( c ) is defined
Barnett/Ziegler/Byleen Business Calculus 12e 21
Finding Local Extrema
Using Calculus
ο§
Step 1: Find the partition points i.
Set π
′ ii.
π₯ = 0 πππ π πππ£π πππ π₯
Identify values of x that make π ′ π₯ = π’ππππππππ iii. Use the partition points to make a sign chart for π
′ π₯
ο§
Step 2: Identify critical values . (These are the partition points where f(x) has a value.)
ο§
Step 3: If there is a change in sign on the left and right of the critical point, then a local extrema exists.
Barnett/Ziegler/Byleen Business Calculus 12e 22
Example 1 π π₯ = −2π₯ 3 + 3π₯ 2 + 120π₯ Find the partition points, critical points, & local extrema.
π ′ π₯ = −6π₯ 2
0 = −6 π₯ 2
+ 6π₯ + 120
− π₯ − 20
0 = −6 π₯ − 5 π₯ + 4 π₯ = −4, 5 π′(π₯) − −
0
+ +
0
−4 5
Partition points: x = -4, 5 f(-4)=-304 f(5) =425
Critical values: x = -4, 5
− − f(-4)=-304 is a local min. f(5) =425 is a local max.
Barnett/Ziegler/Byleen Business Calculus 12e 23
Barnett/Ziegler/Byleen Business Calculus 12e
Example 2 π π₯ =
6
Find the partition points, critical points, & local π₯+2 extrema.
π π₯ = 6 π₯ + 2 −1
−2 π′(π₯) = −6 π₯ + 2
−6
0 = π₯ + 2 2 π₯ = ππ π πππ’π‘πππ π₯ ≠ −2
Partition point: x = -2
Critical values: none, f(-2) = undefined
No extrema
Barnett/Ziegler/Byleen Business Calculus 12e 25
Barnett/Ziegler/Byleen Business Calculus 12e
Example 3 π π₯ = π₯ 3 − 6π₯ 2 + 9π₯ + 1 Find the partition points, critical points, local extrema, & sketch the graph.
π ′ π₯ = 3π₯ 2
0 = 3 π₯ 2
− 12π₯ + 9
− 4π₯ + 3
0 = 3 π₯ − 1 π₯ − 3 π₯ = 1, 3
Partition points: x = 1, 3 π′(π₯) + +
0
− −
0
+ + f(1)=5 f(3) =1
1 3
Critical values: x = 1, 3 f(1)=5 is a local max. f(3) =1 is a local min.
Barnett/Ziegler/Byleen Business Calculus 12e 27
Barnett/Ziegler/Byleen Business Calculus 12e
Example 4
ο§
Use the information below to sketch a graph of f. Assume f(x) is continuous on (-
ο₯
,
ο₯
).
y x
Barnett/Ziegler/Byleen Business Calculus 12e 29
Example 5
ο§
Use the information to sketch a graph of f. Assume f(x) is continuous on (-
ο₯
,
ο₯
).
y x
Barnett/Ziegler/Byleen Business Calculus 12e 30
Comparing the Graphs of π and π′ π π₯ = π₯ 3 − 6π₯ 2 + 9π₯ + 1 π ′ π₯ = 3π₯ 2 − 12π₯ + 9 f’(x) > 0: (ο₯
, 1) f’(x) = 0: x = 1 f ’(x) < 0: (1, 3) f’(x) = 0: x = 3 f’(x) > 0: (3, ο₯
)
Barnett/Ziegler/Byleen Business Calculus 12e f’(x) > 0: (ο₯
, 1) f’(x) = 0: x = 1 f ’(x) < 0: (1, 3) f’(x) = 0: x = 3 f’(x) > 0: (3, ο₯
)
31
Example 6
ο§
The graph of π ′ is shown below. Match it with the correct graph of π .
f’(x) < 0: (ο₯
, -2) f’(x) = 0: x = -2 f ’(x) > 0: (-2, 2) f’(x) = 0: x = 2 f’(x) < 0: (2, ο₯
)
Barnett/Ziegler/Byleen Business Calculus 12e 32
Homework
Barnett/Ziegler/Byleen Business Calculus 12e 33